2. What are the angle measures of the triangle?

The type of test being conducted is c. a one-tailed test to the right.

To determine the type of test being conducted, we need to examine the alternative hypothesis.

If the alternative hypothesis is formulated as  μ>150, indicating that we are specifically interested in testing if the population mean is greater than 150, then it is a one-tailed test to the right. The critical region for rejection is in the right tail of the distribution.

On the other hand, if the alternative hypothesis is 150, indicating that we are interested in testing if the population mean is different from 150 (either greater or less than), then it is a two-tailed test. The critical region for rejection is split between both tails of the distribution.

In this case, since the alternative hypothesis is not provided, we assume a one-tailed test to the right based on the given null hypothesis μ=150.

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y = 4/7x - 3

hope this helps

Answer:4/7-3

Step-by-step explanation:

Yep

Answer:

Her utility bill decreased

Step-by-step explanation:

$-9.66 is closer to 0 but before her bill was -$25.66 so that's farther away so her bill decreased.

Nancy’s balance increased: -9.66 > -25.66.

Answer:

18.84m

Step-by-step explanation:

The diameter=12m

To get the radius, the diameter has to be divided by 2

Radius=diameter/2

Radius=12/2=6m

Perimeter=3.14 x 6

=18.84m

We need to know about inequality to solve this problem. The solution of the inequality is x>-4/3.

Inequality represents the comparison between two unequal expressions. Two expressions can be related to each other as greater than, less than,greater than or equal to or less than or equal to. While solving inequality we always have to keep in mind the change of sign and corresponding change of the comparison. Here in the question we have an inequality of the variable x, we have to get a solution for x by solving this inequality.

6x+4>-3x-8

6x+3x>-8-4

9x>-12

x>-4/3

Therefore the solution set that we get from the inequality 6x+4>-3x-8 is x>-4/3.

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Answer:

3.49 inches

Step-by-step explanation:

circumference = 2(2)(π) = 12.56 inches

(100/360)(12.56) = 3.49 inches

Answer:

ok

Step-by-step explanation:

The integral is ∫(10 |x − 5| dx) from 0 to 10.

This expression can be interpreted in terms of areas as the area between the function y = 10 |x − 5| and the x-axis from x = 0 to x = 10.

Notice that the graph of |x - 5| is a V-shaped graph with its vertex at (5, 0), so the graph is symmetric about the line x = 5. Therefore, we can split the integral into two parts, from 0 to 5 and from 5 to 10.

When x is between 0 and 5, |x - 5| = 5 - x, so the integral becomes:

∫(10(5 - x) dx) from 0 to 5

= [10(5x - (x^2)/2)] from 0 to 5

= (125 - 125/2) - 0

= 62.5

When x is between 5 and 10, |x - 5| = x - 5, so the integral becomes:

∫(10(x - 5) dx) from 5 to 10

= [10((x^2)/2 - 5x)] from 5 to 10

= 0 - (125 - 125/2)

= -62.5

Therefore, the area between the function and the x-axis from x = 0 to x = 10 is:

62.5 + (-62.5) = 0

So, ∫(10 |x − 5| dx) from 0 to 10 = 0.

Hence, the distance between Hawkes Meadow and Brunswick Street is roughly 11.1 kilometres (km).

Distance is a unit used to express the distances between two objects or positions. This is a scalar value that is typically stated in length units like feet, metres, kilometres, or miles. Distance between two things is a physical concept that specifies their separation; it is frequently used to estimate how much space there is between them. The shortest distance, also referred to as "as the crow flies," can be calculated either along a horizontal path or a curved path. Displacement, or the shift in an object's position from its original location to its end position, is a notion in physics that is closely connected to distance.

given

Using the data from the timetable and the calculation, we can determine how many kilometres the bus travels between Hawkes Meadow and Brunswick Street:

Distance is determined by multiplying time and speed.

According to the timetable, the bus travels from Hawkes Meadow to Othello Avenue in 15 minutes (from 14:25 to 14:32), and from Othello Avenue to Brunswick Street in 8 more minutes (i.e., from 14:32 to 14:40). Hence, it takes 15 + 8 = 23 minutes to get from Hawkes Meadow to Brunswick Street.

Also, we are informed that the bus travels at an average speed of 29 km/h between Hawkes Meadow and Brunswick Street.

To utilise the calculation, we must first divide the time in minutes by 60 to convert it to hours:

23, divided by 60 hours, or 0.3833 hours (rounded to 4 decimal places)

Hence, we can compute the distance using the following formula:

11.12 kilometres is equal to 29 km/h times 0.3833 hours (rounded to 2 decimal places)

Hence, the distance between Hawkes Meadow and Brunswick Street is roughly 11.1 kilometres (km).

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Answer:

they are equivalent

Step-by-step explanation:

8/6

Divide the top and bottom by 2

4/3

16/12

Divide the top and bottom by 4

4/3

They are  the same so they are equivalent

Answer:

5x² + 10

Step-by-step explanation:

5(x² + 2)

= 5x² + 10

The point that the graphs of f and g have in common are (1,0)

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0).

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Answer:

y+2=1/2(x+3)

Why?

Point slope form is written as (y-y1) = m(x-x1) with y1 being the value of y at a certain point, x1 being the value of x at a certain point, and m being slope. y1 and x1 are given to us by the point (-3, -2) letting us know that y1=-2 and x1=-3. The only thing left to find is slope. Parallel lines have the same slope. If the line we are trying to find is parallel to the one given in the question, we just need to find the slope of the equation given. That equation is given in slope-intercept form which is y = mx + b. m is still slope so we can see that the slope is 1/2. Now we can plug m, x1 and y1 into the point slope form equation to get y + 2 = 1/2(x + 3)

The standard deviation is equal to the square root of the variance, which is √(1/8) ≈ 0.353.

To find the variance and standard deviation of X with the given density function, we need to calculate the expected value (E(X)) and the expected value of X squared (E(X^2)). Then, we can use the formula Var(X) = E(X^2) - [E(X)]^2 to find the variance.

First, let's calculate E(X):

E(X) = ∫(x * f(x)) dx

     = ∫(x * 2(1 - x)) dx

     = 2∫(x - x^2) dx

     = 2[x^2/2 - x^3/3] + C

     = x^2 - (2/3)x^3 + C

Next, let's calculate E(X^2):

E(X^2) = ∫(x^2 * f(x)) dx

        = ∫(x^2 * 2(1 - x)) dx

        = 2∫(x^2 - x^3) dx

        = 2[x^3/3 - x^4/4] + C

        = (2/3)x^3 - (1/2)x^4 + C

Now, we can find the variance:

Var(X) = E(X^2) - [E(X)]^2

      = [(2/3)x^3 - (1/2)x^4 + C] - [x^2 - (2/3)x^3 + C]^2

      = [(2/3)x^3 - (1/2)x^4] - [x^2 - (2/3)x^3]^2

The standard deviation can be calculated as the square root of the variance.

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Complete Question

For a laboratory assignment, if the equipment is working, the density function of the observed outcome X is

f(x) = 2 ( 1 - x ), 0 < x < 1

0 otherwise

(1) Find the Variance and Standard deviation of X.

Some information that someone might use to solve problems related to a circle design is the Tangent Arc theorem.

The tangent arc theorem states that if an angle is formed by two secants, one secant, one tangent, or two tangents, and also intersects in a space outside of the circle, then the value obtained will be equal to the difference of the values of the intercepted arcs divided by one and a half.

Also, note that angles outside a circle are those whose vertex or arc is pointed outwards and their sides are either secants or tangents. With this information, it will be possible to solve problems related to tangent lines and arc measures.

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Answer:  x = 7

Step-by-step explanation:  All the angles of a parallelogram add to 360°

Any two of the consecutive angles add to 180°

Using that information, we can create an equation with the angle measurements given:

(7x + 33) + (11x + 21) = 180 . Combine like terms:

7x + 11x + 33 + 21 =180

18x + 54 = 180 .  Subtract 54 from both sides

18x = 126   Divide both sides by 18

x = 7

Answer:

x∈R

Step-by-step explanation:

\(y=2^{x}\)

2>0

The domain is all real numbers.

x∈R

The lengths of a,b,c, and d have been derived and expressed in terms of trigonometric ratios below.

As we can see from the figure itself, the value of a = sin θ

This can be written as such because = sin θ = Perpendicular / Hypotenuse

Here, the perpendicular = a and hypotenuse = radius = 1

= sin θ = a

The value of b = tan θ

This is because tan θ = perpendicular/base

Here, the base = radius = 1

= tan θ = b  

The value of c = sec θ

This is because sec θ = Hypotenuse / Base

= sec θ = c

The value of d = cos θ

This is because cos θ = Base / Hypotenuse

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Comparing a census of a large population to a sample drawn from it, we expect that the sample is usually a more practical method of obtaining the desired information.

This is because a census involves collecting data from every individual in the population, which can be time-consuming, expensive, and logistically challenging, especially for large populations. In contrast, a sample is a smaller, more manageable subset of the population, making it easier to gather and analyze data.

However, it's essential to note that the accuracy of the observations in the census is generally higher than in the sample, as the census covers the entire population, eliminating any sampling error. In comparison, a sample may be subject to various biases or inaccuracies, depending on the sampling technique used and the sample size.

To ensure that the sample accurately represents the population, it is crucial to select a sample that is both random and of an appropriate size. While the sample doesn't need to be a large fraction of the population, it should be sufficiently large to provide reliable estimates and minimize sampling error. Overall, sampling is a practical and efficient approach to obtaining information about a population when properly conducted, balancing the need for accuracy with resource constraints.

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Answer:

Option: A is the correct answer A.

Begin with a line segment on the paper and fold the paper so that the segment's endpoints lie on top of each other.

Step-by-step explanation:

We know that a perpendicular line segment is formed with the help of paper folding in following steps: Draw a line segment on a paper. Fold the paper so that the endpoints of the line segment are on each other. The crease that is formed on the paper and pass through the line segment is the perpendicular line to the given line segment. The point on the line segment is the mid point of the line segment. Hence, option: A is the correct answer.

Option: B is the correct answer i.e. "Begin with a line segment on the paper and fold the paper so that the segment's endpoints lie on top of each other."

Thus, Option: B is the correct answer i.e. "Begin with a line segment on the paper and fold the paper so that the segment's endpoints lie on top of each other."

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The y-intercept represents a. the maximum weight allowed in a shipment.

Given: The graph is between the Amount of allowed weight remaining Vs the Number of boxes included.

What is a graph?

A graph is a diagram or the representation of variations between two or more variables with respect to each other.

A graph consists of dependent and independent variables. We usually plot the response of the dependent variable with the change in the value of the independent variable.

What is y-intercept?

The y-intercept is the point on the y-axis that a given equation of line or a curve passes through when the value of x = 0. It can denote either the minimum value for a function is the function is increasing the the initial point is the y intercept or the maximum value for a decreasing function if the y-intercept is the initial point.

Let's solve the question:

It is given in the question that the graph is of  Amount of allowed weight remaining Vs the Number of boxes.

As it is "Amount of weight remaining", so we can interpret that it is a decreasing curve with the increase in the number of boxes or in simple words the value of y will keep decreasing with the increasing number of x value.

Therefore, for this graph the y-intercept will show the maximum weight remaining or as it is the y-intercept that is x = 0, which means when there are no boxes the maximum weight remaining is y-intercept. So it the maximum weight allowed in the shipment.

Hence the answer is a. the maximum weight allowed in a shipment.

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Disclaimer: The given question is incomplete. The complete question is mentioned below:

One manufacturer boxes screws so that each box weighs the same no matter what size the screws are. The graph shows the amount of allowed weight remaining in a given shipment depending on the number of boxes of screws already included. What does the y-intercept represent in this situation?

a. the maximum weight allowed in a shipment.

b. the minimum weight of a single box of screws.

c. the minimum number of screws in a single box.

d. the maximum number of single boxes for a shipment.

Answer:

We conclude that:

Step-by-step explanation:

Given

We know that the diagonals of a parallelogram bisect each other.

so

\(RT = TP\)

Given

so substituting RT = x, and TP = 5x-28

\(RT = TP\)

\(x = 5x-28\)

\(5x = x+28\)

\(5x-x = 28\)

\(4x = 28\)

divide both sides by 4

\(4x/4 = 28/4\)

\(x = 7\)

Therefore, the value of x:

Similarly,

\(QT = TS\)

Given

so substituting QT = 5y, and TS = 2y+12

\(QT = TS\)

\(5y = 2y+12\)

\(5y-2y = 12\)

\(3y = 12\)

divide both sides by 3

\(3y/3 = 12/3\)

\(y = 4\)

Therefore, the value of y:

y = 4

Therefore, we conclude that:

Answer:

m any number becuase you subract 7 from both sides

Step-by-step explanation:

Answer:

i cant answer this because of my school computer but its simple

Step-by-step explanation:

Answer: x & y

              0 & -3

              1  & 5

slope : 8

y intercept : -3

The general solution of the damped spring-mass system with the given parameters is y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)]. By applying the initial conditions y(0) = 1 and y'(0) = 0, the specific solution can be obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t).

The equation for the damped spring-mass system can be expressed as my'' + cy' + ky = 0, where m is the mass, c is the damping coefficient, and k is the spring constant. In this case, m = 1 kg, c = 3 kg/s, and k = 2 kg/\(s^2\).

To find the general solution, we assume a solution of the form y(t) = e^(rt). By substituting this into the equation and solving for r, we get \(r^2\) + 3r + 2 = 0. Solving this quadratic equation gives us the roots r1 = -2 and r2 = -1.

The general solution is then given by y(t) = c1e^(-2t) + c2e^(-t). However, since we have a damped system, the general solution can be rewritten as y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)], where √7/2 = √(3/4).

By applying the initial conditions y(0) = 1 and y'(0) = 0, we can solve for the coefficients c1 and c2. The specific solution is obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t). This satisfies the given initial value problem.

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Given the division of polynomials

Separate the numerators.

which equals x - 3.

So, the division of the given polynomial gives x - 3.

the ratio of zinc to copper is 3 to 14, that menas that for each 3 grams of zinc there are 14 grams of copper, so we can made a rule of three to find

The natural breaks, quantile, and equal interval classification schemes are methods used to categorize data for the purpose of creating thematic maps. Each scheme has its own approach and considerations: Natural Breaks, Quantile, Equal Interval.

Natural Breaks (Jenks): This classification scheme aims to identify natural groupings or breakpoints in the data. It seeks to minimize the variance within each group while maximizing the variance between groups. Natural breaks are determined by analyzing the distribution of the data and identifying points where significant gaps or changes occur. This method is useful for data that exhibits distinct clusters or patterns.

Quantile (Equal Count): The quantile classification scheme divides the data into equal-sized classes based on the number of data values. It ensures that an equal number of observations fall into each class. This approach is beneficial when the goal is to have an equal representation of data points in each category. Quantiles are useful for data that is evenly distributed and when maintaining an equal sample size in each class is important.

Equal Interval: In the equal interval classification scheme, the range of the data is divided into equal intervals, and data values are assigned to the corresponding interval. This method is straightforward and creates classes of equal width. It is useful when the range of values is important to represent accurately. However, it may not account for data distribution or variations in density.

In summary, the natural breaks scheme focuses on identifying natural groupings, the quantile scheme ensures an equal representation of data in each class, and the equal interval scheme creates classes of equal width based on the range of values. The choice of classification scheme depends on the nature of the data and the desired representation in the thematic map.

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