n=60,σ=8,α=1−0.1=0.9,Z 2
α
​ =Z 0.45
​ =1.645 (Round to the nearest hundredth) Find E=Z 0.45
​ n
​ σ
​ = Find 3.3+E= Find 3.3−

Step-by-step explanation:

Refer to pics...............

Answer:

one side = 110 inches

second side = 66 inches

third side = 264 inches

Step-by-step explanation:

10 + 6 + 24 = 40

one side of Δ = 10/40 x 440 = 110

second side of Δ = 6/40 x 440 = 66

third side of Δ = 24/40 x 440 = 264

For the given problem:

Let the number = x

Two less than the quotient of a number and 8 is 1/4

so, we can write the following expression:

Now, solve the equation to find (x)

Multiplying by (8) to eliminate the denominators:

Add (6) to both sides:

So, the answer will be the number is 18

The measure of angle A and B is 30° and 60° respectively.

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin(tetha) = opp/hyp

cos(tetha) = adj/hyp

tan(tetha) = opp/adj

16 is hypotenuse and 8 is opposite

therefore, sin(tetha) = 8/16

sin(tetha) = 0.5

tetha = sin^-1 ( 0.5)

= 30°

The sum of angle in a triangle is 180°. Therefore ,

angle B = 180-(90+30)

= 180-120 = 60°

therefore the measure of angle A and B is 30° and 60° respectively.

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Perimeter 2l + 2w. Using this we can find your inequality equation.

32 = 2(5.5) + 2w

32 = 11 + 2w

21 = 2w

w = 10.5

This means that when the perimeter is 32 in, the width is 10.5 in. We want to know when perimeter is 32 in or greater so we can simply do:

w > 10.5 because anything above 10.5 will increase the perimeter.

The statement that correctly explains the association in the scatter plot is; A. Since the y-values decrease as the x-values increase, the scatter plot shows a negative association.

When it comes to interpretation of scatterplots, we can say that two variables are deemed to possess a negative association when the values of one variable tends to decrease as the values of the other variable increases.

Similarly, we can say that two variables are deemed to possess a positive association when the values of one variable tends to increase as the values of the other variable increases.

In this given scatterplot, we see that the y-value is decreasing as the x-axis is increasing and as such this is a negative association.

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Answer: A. Since the y-values decrease as the x-values increase, the scatter plot shows a negative association.

Step-by-step explanation: And if you know the answer to your own question then why ask bro

a) the probability of drawing a face card is 3/13. b) , the probability of not drawing a black face card is 1/2. c) the probability of drawing a heart or a queen is 4/13.

A) To find the probability of drawing a face card (a jack, queen, or king), we need to determine the number of favorable outcomes (face cards) and divide it by the total number of possible outcomes (52 cards in a deck).

Number of favorable outcomes = 12 (4 jacks + 4 queens + 4 kings)

Total number of possible outcomes = 52

Probability of drawing a face card = Number of favorable outcomes / Total number of possible outcomes

                               = 12 / 52

                               = 3 / 13

Therefore, the probability of drawing a face card is 3/13.

B) To find the probability of not drawing a black face card, we need to determine the number of favorable outcomes (non-black face cards) and divide it by the total number of possible outcomes (52 cards in a deck).

Number of favorable outcomes = 12 (4 jacks + 4 queens + 4 kings)

Total number of possible outcomes = 52

Since there are 26 black cards in the deck, the number of non-black cards is 52 - 26 = 26.

Probability of not drawing a black face card = Number of favorable outcomes / Total number of possible outcomes

                                          = 26 / 52

                                          = 1 / 2

Therefore, the probability of not drawing a black face card is 1/2.

C) To find the probability of drawing a heart or a queen, we need to determine the number of favorable outcomes (hearts + queens) and divide it by the total number of possible outcomes (52 cards in a deck).

Number of favorable outcomes = 16 (13 hearts + 3 other queens)

Total number of possible outcomes = 52

Probability of drawing a heart or a queen = Number of favorable outcomes / Total number of possible outcomes

                                       = 16 / 52

                                       = 4 / 13

Therefore, the probability of drawing a heart or a queen is 4/13.

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Answer:

45

Step-by-step explanation:

Total score = 35 + (-10) + (-15) + 20 + 5

Total score = 35 - 10 - 15 + 20 + 5

Total score = 60 - 25

Total score = 45

The check for independence in a one- sample is

The population size is further than 10 times the sample size.

The Correct option is D.

What is Z- test?

A Z- test is a statistical thesis test used to determine whether a sample mean significantly differs from a given population mean when the population standard divagation is known.

For a one- sample z- test for a population proportion, the sample is named without relief from a finite population.

In order for the test to be valid, it's necessary to insure that the sample is small relative to the population size.

still, it can be considered large enough to satisfy the independence supposition, If the population size is further than 10 times the sample size. This supposition is necessary for the validity of statistical conclusion in this environment.

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Answer:

x= - 9

Step-by-step explanation:

x = 27 / - 3

x = -9

Hope this helps

Answer:

x=9

Step-by-step explanation:

-3x=27

or, x=27/-3

or, x= -9

To find the integer value of n that results in exactly 560 lattice points strictly in the interior of the triangle, use the equation: n = (560 + 2)/8.

This equation is derived by counting the lattice points on each side of the triangle, starting with the side between points (1,1) and (9,1). This side has a length of 8, so it contains 8 lattice points, including the two endpoints. The remaining sides have lengths of 8 + n and 8 + n, which combined have 8 + 2n lattice points. The total number of lattice points in the triangle is then 8 + 8 + 2n = 16 + 2n.  

Solving for n when the total number of lattice points is 560 gives us n = (560 + 2)/8. Therefore, the integer value of n is 70.

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Answer:

The answer is explained below

Step-by-step explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:

\(z=\frac{x-\mu}{\sigma}, where\ x\ is\ the \ raw\ score\)

To find the Probability that x < 8.8, we first find the z score using:

\(z = \frac{x-\mu}{\sigma}=\frac{8.8-7}{1.5}=1.2\)

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%

Answer:

$11.78

Step-by-step explanation:

14.89+9.33=24.22

36-24.22=11.78

Answer and Step-by-step explanation:

For the first one, x is equal to 61 (180 - 63 - 56 = 61)

and y = 4

51 = 12y + 3

48 = 12y

y = 4

For the second one,

x = 11

11x - 4 = 117

11x = 121

x = 11

y = 5

17y - 8 = 12 + 13y

4y = 20

y = 5

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Answer:

7/12 for white sock. 5/12 black sock. 1/4 navy

Step-by-step explanation:

(white) 24-10=14 so then 14/24=7/12

(black) 10/24=5/12

(navy) 6/24=1/4

Answer:

I JUST LOVE GETTING POINTS

Step-by-step explanation:

Answer:

£700 000

Step-by-step explanation:

The value £749 000 is the value with 7% increase

That is 100% + 7% = 107%

To find the original value , that is 100%

Divide by 107 to find 1% and multiply by 100

\(\frac{749000}{107}\) × 100 = £700 000

A city with m districts has m robberies in a particular week.

Assume the robberies are located randomly, with all possibilities for which robbery occurred where equally likely. What is the probability that exactly one district had no robberies?The number of ways in which m robberies can be distributed in m districts is (m + m − 1 C m−1 ) by stars and bars principle, where m + m − 1 is the total number of objects, namely, m robberies and m − 1 bars separating the m districts.

Thus, there are (2m − 1 C m−1 ) ways to distribute the m robberies .The number of ways in which exactly one district has no robberies is m( m−1 C m−2 ). There are m ways to choose the district with no robberies, and m − 1 ways to choose one of the remaining districts to have two robberies.

The remaining m − 2 robberies can be distributed arbitrarily among the remaining m − 2 districts. Thus, there are m( m−1 C m−2 ) ways to distribute the m robberies with exactly one district having no robberies.

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Answer:

Step-by-step explanation:

Isolate the term of r, from one side of the equation.

First, multiply by 2 from both sides.

2*3/2r=2(-1)

Solve.

3r=-2

Then, you divide by 3 from both sides.

3r/3=-2/3

Solve.

Divide the numbers from left to right.

r=-2/3

-2/3=-0.66

\(\Longrightarrow: \boxed{\sf{r=-\dfrac{2}{3}}}\)

I hope this helps! Let me know if you have any questions.

Answer:

\({ \qquad{ {{ \tt{ - \frac{2}{3} }}}}} \\ \\\)

Given equation,

\( \\ { \longrightarrow \qquad{ {{ \tt{ \frac{3}{2} \: r = -1 }}}}} \\ \\\)

Multiplying both sides by \( \sf \dfrac{1}{3}\) we get :

\( \\ { \longrightarrow \qquad{ {{ \tt{ \frac{1}{3} \times \frac{3}{2}r = \frac{1}{3} \times -1 }}}}} \\ \\\)

\( { \longrightarrow \qquad{ {{ \tt{ \frac{1}{ \cancel3} \times \frac{ \cancel3}{2}r = - \frac{ 1}{ 3} }}}}} \\ \\\)

\( { \longrightarrow \qquad{ {{ \tt{ \frac{1}{2}r = - \frac{1}{3} }}}}} \\ \\\)

Now, Multiplying both sides by 2 we get :

\( \\ { \longrightarrow \qquad{ {{ \tt{ 2 \times \frac{1}{2}r = 2 \times - \frac{1}{3} }}}}} \\ \\\)

\({ \longrightarrow \qquad{ {{ \tt{ \cancel2 \times \frac{1}{ \cancel2}r = - \frac{2}{3} }}}}} \\ \\\)

\({ \longrightarrow \qquad{ {{ \tt{ {1}r = - \frac{2}{3} }}}}} \\ \\\)

\({ \longrightarrow \qquad{ \frak {{ \pmb{ r = - \frac{2}{3} }}}}} \\ \\\)

When a point falls outside of control limits in statistical process control, the probability is quite high that the process is experiencing special cause variation.

In statistical process control (SPC), control limits are used to define the range within which a process is expected to operate under normal or common cause variation. Common cause variation refers to the inherent variability of a process that is predictable and expected.

On the other hand, special cause variation, also known as assignable cause variation, refers to factors or events that are not part of the normal process variation. These are typically sporadic, non-random events that have a significant impact on the process, leading to points falling outside of control limits.

When a point falls outside of control limits, it indicates that the process is exhibiting a level of variation that cannot be attributed to common causes alone. Instead, it suggests the presence of specific, identifiable causes that are influencing the process. These causes may include equipment malfunctions, operator errors, material defects, or other significant factors that introduce variability into the process.

Therefore, when a point falls outside of control limits in statistical process control, it is highly likely that the process is experiencing special cause variation, which requires investigation and corrective action to identify and address the underlying factors responsible for the out-of-control situation.

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Answer:324234

Step-by-step explanation:

Answer:

The mean of the data set is 7.

2 + 9 + 10 + 6 + 8

= 35

35 ÷ 5

= 7

Step-by-step explanation:

You're welcome

Two crucial tasks inherent in the initial stage of group therapy are orientation and establishing group norms.Ambiguity and lack of a structured approach in groups often lead to confusion, inefficiency, and potential challenges.

Orientation involves providing essential information to group members about the purpose, goals, and guidelines of the therapy group.

It helps individuals understand what to expect, builds trust, and creates a sense of safety and predictability within the group. Orientation may include discussing confidentiality, group rules, expectations, and addressing any questions or concerns.

Establishing group norms involves collaboratively developing shared guidelines and expectations that govern the behavior and interactions within the group. This process allows group members to contribute to the creation of a supportive and respectful group climate. Group norms help set boundaries, encourage open communication, and foster a sense of cohesion among members.

Without clear structure and guidance, group members may struggle to understand their roles, goals, or the process of the group therapy. Ambiguity can hinder progress, create frustration, and impede meaningful communication.

Lack of structure may also result in difficulty managing conflicts, decision-making, or time management within the group. It can lead to unequal participation, power struggles, and a lack of accountability.

To address these issues, it is important for group therapy to provide a clear framework, establish ground rules, and facilitate structured activities or interventions that promote clarity, engagement, and progress. A structured approach helps create a supportive environment, enhances group dynamics, and maximizes the therapeutic benefits of the group process.

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Answer:

proportional

Step-by-step explanation:

Answer:

I'm 99% sure it's Non-Proportional

Step-by-step explanation:

If you were to convert each of them into fractions and simplified them, they wouldn't be equivalent.

Answer: The equation \(x-7/8=-3/2\) has a different value of x than the others. The value of x here is -0.625, while in all the other equations, the value of x is 0.625.

Step-by-step explanation: Simplifying the equation \(x+9/8=7/4\), we get:

\(x=7/4-9/8\)

\(x=0.625\)

Simplifying the equation \(x-7/8=-3/2\),  we get:

\(x=-3/2+7/8\)

\(x=-0.625\)

Simplifying the equation \(x+0.875=1.5\), we get:

\(x=1.5-0.875\)

\(x=0.625\)

Simplifying the equation \(x-0.025=0.6\), we get:

\(x=0.6+0.025\)

\(x=0.625\)

Therefore, \(x+9/8=7/4\) has a different value of x than the others.

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It will take 84 school days before all four tutors are working.

In this situation, Beatrice works every sixth school day, and Chi works every seventh school day. Today they are all working in the math lab.

To find the least common multiple of 3, 4, 6, and 7, we can first find the prime factorization of each number.

3 = 3

4 = 2^2

6 = 2 * 3

7 = 7

The least common multiple is then 2^2 * 3 * 7, or 84. This means that it will take 84 school days before all four tutors are working in the math lab again.

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We need to first identify the center of the circle.

We see that the coordinate point of the center of the circle is (-1, -2).

The equation of a circle is given with the equation

where h is x, k is y, and r is the radius of the circle.

Therefore, we can plug in the coordinates first to find the h and k of the equation.

Then, we need to determine r.

The circle intersects points (-6, -2) and (4, -2). We can simply subtract the x-coordinates from each other to find the diameter of the circle.

Finally, we know the radius is half of the diameter:

We can plug in the radius into the equation.

Therefore, our final equation is Choice D:

Answer:

  10.97 seconds

Step-by-step explanation:

You want to know when a rocket will hit the ground if its height is given by y = -16x² +170x +61, where x is seconds after launch.

The formula for the solutions of a quadratic equation is ...

  \(\text{for }ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

When we apply this to the equation y=0, we have ...

  \(x=\dfrac{-170\pm\sqrt{170^2-4(-16)(61)}}{2(-16)}=\dfrac{170\pm\sqrt{32804}}{32}\\\\x\approx 10.97\quad\text{seconds}\)

The rocket will hit the ground after about 10.97 seconds.

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