To determine the required cross-sectional area of the fasteners for infinite life, we can use the endurance limit or fatigue strength of the material.
Unfortunately, the specific endurance limit for the EQ21A-T6 Mg alloy is not provided in the information given. The endurance limit is the maximum stress level that the material can sustain indefinitely without failure.
Without the endurance limit, it is not possible to calculate the cross-sectional area required for infinite life. The endurance limit is crucial in determining the stress range the material can withstand without experiencing fatigue failure over an infinite number of cycles.
To design the fasteners for infinite life, you would need to consult the material specifications or conduct fatigue testing to determine the endurance limit of the EQ21A-T6 Mg alloy. With the endurance limit, you can calculate the required cross-sectional area using the stress range and the alternating load values provided.
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2-design a set of simple test programs to determine the type compatibility rules of a c compiler to which you have access. Write a report of your findings
When designing a set of simple test programs to determine the type compatibility rules of a C compiler to which you have access, it is important to consider the different data types that are used in C programming. An example of a set of test programs that can be used to determine the type compatibility rules of a C compiler:
Integer Test the compatibility of the C compiler with integer data types. It declares two variables of type int, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with integer data types.
Floating-Point Test the compatibility of the C compiler with floating-point data types. It declares two variables of type float, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with floating-point data types.
By running the set of simple test programs described above, you can determine the type compatibility rules of a C compiler to which you have access. If any of the programs do not compile or run without errors, then you can determine which data types are not compatible with the C compiler and adjust your code accordingly.
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In a hydroelectric power plant, water enters the turbine nozzles at 800 kPa absolute with a low velocity. If the nozzle outlets are exposed to atmospheric pressure of 100 kPa, determine the maximum velocity (m/s) to which water can be accelerated by the nozzles before striking the turbine blades.
Answer:
The answer is VN =37.416 m/s
Explanation:
Recall that:
Pressure (atmospheric) = 100 kPa
So. we solve for the maximum velocity (m/s) to which water can be accelerated by the nozzles
Now,
Pabs =Patm + Pgauge = 800 KN/m²
Thus
PT/9.81 + VT²/2g =PN/9.81 + VN²/2g
Here
Acceleration due to gravity = 9.81 m/s
800/9.81 + 0
= 100/9.81 + VN²/19.62
Here,
9.81 * 2= 19.62
Thus,
VN²/19.62 = 700/9.81
So,
VN² =1400
VN =37.416 m/s
Note: (800 - 100) = 700
Answer:
\(V2 = 37.417ms^{-1}\)
Explanation:
Given the following data;
Water enters the turbine nozzles (inlet) = 800kPa = 800000pa.
Nozzle outlets = 100kPa = 100000pa.
Density of water = 1000kg/m³.
We would apply, the Bernoulli equation between the inlet and outlet;
\(\frac{P_{1} }{d}+\frac{V1^{2} }{2} +gz_{1} = \frac{P_{2} }{d}+\frac{V2^{2} }{2} +gz_{2}\)
Where, V1 is approximately equal to zero(0).
Z\(z_{1} = z_{2}\)
Therefore, to find the maximum velocity, V2;
\(V2 = \sqrt{2(\frac{P_{1} }{d}-\frac{P_{2} }{d}) }\)
\(V2 = \sqrt{2(\frac{800000}{1000}-\frac{100000}{1000}) }\)
\(V2 = \sqrt{2(800-100)}\)
\(V2 = \sqrt{2(700)}\)
\(V2 = \sqrt{1400}\)
\(V2 = 37.417ms^{-1}\)
Hence, the maximum velocity, V2 is 37.417m/s
Varying the frequency of the control signal does not affect the output voltage level of a buck chopper.
a. True
b. False
The statement "Varying the frequency of the control signal does not affect the output voltage level of a buck chopper" is false.
What is a buck chopper? A buck chopper is also known as a step-down chopper, which means it lowers the output voltage level to a level below the input voltage level. In comparison to other choppers, buck choppers are more commonly utilized. The key working principle of buck chopper is that the input DC voltage is switched using an electronic switch ON and OFF.The output voltage is provided to the load through a filter after the chopper has switched off. The filter assists in the reduction of the DC voltage to the load. The value of the output voltage is determined by the length of the switch ON time compared to the switch OFF time. This time ratio is known as the duty cycle. So, the output voltage is determined by the ratio of ON time to OFF time. It means that the output voltage can be controlled by changing the duty cycle. Therefore, the statement "Varying the frequency of the control signal does not affect the output voltage level of a buck chopper" is false.
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read each of the following descriptions. match each description to one of the zone control system types listed. provides cooling only and the air handlers are not constantly operating at full capacity. answer 1 choose... provides temperature and humidity control for multiple zones and includes a cooling coil at the air handling unit and then a heating coil is located in each zone to provide the required temperature for that zone. answer 2 choose... serves very large buildings with many zones and is flexible to allow for easy expansion. answer 3 choose... warmed and cooled air flows through separate duct systems and mixes the warmed and cooled air together in a terminal located in a space. answer 4 choose... a system that uses refrigerant coils and does not need ductwork. answer 5 choose...
The correct answer is: 1, 2, 4. provides cooling only and the air handlers are not constantly operating at full capacity.
What is capacity?
Capacity refers to your capacity or the volume that something can hold. If your bird cage is already full, adding another bird won't prevent the bird from developing claustrophobia. "Breadth" and "capacity" are the meanings of the Latin word capacitatem. A room's capacity to hold a certain number of people, a law's ability to reduce crime rates, or your capacity to learn new languages are all examples of capacity as a noun, which simply means "ability" or "capability." You may hear about factories operating at "full capacity," which refers to operating at maximum speed and output.
Serves very large structures with numerous zones and is adaptable to facilitate simple expansion. warmed and cooled air flows through separate duct systems and mixes the warmed and cooled air together in a terminal located in a space.
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Problem 2: Array Util (10 points) Part 2: Array Resize (Data Structure algorithms) ArrayList is a class in the java.util package that provides much more functionality than standard arrays. One powerful feature of ArrayList is that they can dynamically resize themselves, whereas a basic array has a fixed length determined during its initialization. ArrayList resize by creating a new Array twice the size of their original array and then copy their values to the new bigger array. Implement a resize method within your ArrayUtil class as specified in the API below Array Util Method API: Modifier and Type Method and Description static resize(String[] array) String[] Returns new array with the same elements as original but that's twice the length Facts . Implement this method in the same ArrayUtil dass as Problems 1,2,3,4 5,6 A return is required because a new array is created in memory Your ArrayUtil class implementation should not have a main method. NO Scanner for input & Ng System.out for output! . . Input The ArrayUtil class will be accessed by an extemal Java Application within Autolab. This Java app will send data in as arguments into each of the methods parameters, Output The ArrayUtil class should return the correct data calculations back to the invoking client code
The final ArrayUtil class should look like this:
```java
public class ArrayUtil {
public static String[] resize(String[] array) {
String[] resizedArray = new String[array.length * 2];
for (int i = 0; i < array.length; i++) {
resizedArray[i] = array[i];
}
return resizedArray;
}
}
```
The Step-by-step explanation for implementing a resize method in your ArrayUtil class for resizing an array of Strings:
1. Create a new class called ArrayUtil, if it's not already created.
2. Add the following method signature to the class:
```java
public static String[] resize(String[] array)
```
3. Inside the resize method, determine the length of the original array by using the `array.length` property.
4. Create a new array, called `resizedArray`, with double the length of the original array:
```java
String[] resizedArray = new String[array.length * 2];
```
5. Copy the elements from the original array to the new resized array using a loop:
```java
for (int i = 0; i < array.length; i++) {
resizedArray[i] = array[i];
}
```
6. Return the resized array:
```java
return resizedArray;
```
Note that there is no main method or input/output handling in the ArrayUtil class, as the instructions specified that it will be accessed by an external Java application. The class simply contains the resize method for resizing an array of Strings.
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dentify the recommended practices when putting a tip on a micropipette. Select one or more: Gently push the micropipette into the tip and tap lightly to load the tip. Hold the micropipette at a 45 degree angle to the tip rack. Use the tip size designed for the micropipette size in use. Remove the tip from the rack and place it on micropipette by hand.
Answer:
Gently push the micropipette into the tip box and tag tightly to load the tip.
Explanation:
The recommended practice when putting a tip on a micropipette is ; Gently push the micropipette into the tip box and tag tightly to load the tip.
Given that it is not advisable to remove tip from rack so as not to contaminate it, if we want to put a tip on a micropipette we should gently push the micropipette into the tip box.
how do you know when an equation is (In)
design a one-input, one-output sequence detector, which produces an output 1 every time the sequence 1111 is detected, and an output 0 at all other times. the circuit is also required to recognize overlapping sequences, as can be seen in the output string z that results from the following input string x. use jk flip-flops. use the following input string as part of your simulation. input string x: 1101111111010 output string z: 0000001111000 the following format will be used for lab reports:
To design a one-input, one-output sequence detector for detecting the sequence "1111" using JK flip-flops, we can use the following state diagram:
Sequence Detector State DiagramIn this state diagram, S0, S1, S2, and S3 are the four possible states of the detector. The output of the detector is 1 when it reaches state S3 and remains in that state until the next clock pulse. The output is 0 for all other states.
The state transition table for the detector is:
Present State Input
S0 0 S0 0
S0 1 S1 0
S1 0 S0 0
S1 1 S2 0
S2 0 S0 0
S2 1 S3 0
S3 0 S0 1
S3 1 S1 0
To implement this state diagram using JK flip-flops, we can use the following circuit:Sequence Detector Circuit DiagramIn this circuit, J and K inputs of each flip-flop are set based on the state transition table. The Q output of each flip-flop is connected to the corresponding input of the next flip-flop. The output of the detector is taken from the Q output of the last flip-flop (Q3).To test the circuit, we can use the given input string x = 1101111111010 and verify that the output string z = 0000001111000 is produced. The simulation waveform of the circuit is shown below:
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A 1.5 m x1.5 m square footing is supported by a soil deposit that contains a 16.5 m thick saturated clay layer followed by the bedrock. The clay has μs = 0.50 and Es = 5,000 kN/m2 . The footing base is at 1.5 m below the ground surface. Determine the maximum vertical central column load so that the elastic settlement of the footing will not exceed 50.0 mm. If the square footing is replaced by a 1.2 m wide wall footing with all other conditions remaining the same.
Required:
What will be the elastic settlement under the same footing pressure?
Answer:
somewhere around 34.2223 meters thick but that's what I am estimating.
Which characteristic would atoms of a ferromagnetic material have?A. A lack of electrons B. North and south poles C. A temporary magnetic field D. The ability to attract nonmagnetic materials
Answer:
Option B
Explanation:
Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.
Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.
Hence, option B is correct
By how many orders of magnitude (powers of ten, approximately) does density vary for metals? 0.13 1.3 13 130
B) For metals, the variation in density is about 1.3 orders of magnitude (powers of ten).
What does density variation mean?The graph in figure displays the fluctuation in density () with temperature (T) of an ideal gas with molecular mass (M) at constant pressure. At state P, the gas is under RT2KM of pressure. K has a value of.
Does a metal's density change as it becomes hotter?Although materials do expand when heated, the size change is relatively modest, hence temperature changes have little effect on a material's density.
What factors affect a metal's density?A substance's density is based on the mass, size, and arrangement of its atoms. Density (D) is defined as the substance's mass divided by its volume. Densities differ between objects with the same volume but differing masses.
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If 4000 is invested now, 7000 four years from now, and 5000 six years from now at an interest rate of 6% compounded annually, what will be the total amount in 9
Explanation:
To solve this problem, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = the final amount
P = the principal amount (the initial investment)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time (in years)
Let's start with the first investment of $4000:
A1 = 4000(1 + 0.06/1)^(1*9)
= 4000(1.06)^9
= $6,542.51
Now, let's move on to the second investment of $7000, made four years from now:
A2 = 7000(1 + 0.06/1)^(1*5)
= 7000(1.06)^5
= $9,381.81
Finally, let's calculate the third investment of $5000, made six years from now:
A3 = 5000(1 + 0.06/1)^(1*3)
= 5000(1.06)^3
= $5,674.32
The total amount after 9 years will be the sum of these three amounts:
Total = A1 + A2 + A3
= $6,542.51 + $9,381.81 + $5,674.32
= $21,598.64
Therefore, the total amount after 9 years will be $21,598.64.
how do we find percentage error in measuring voltage across a resistor
Answer:
use the percentage error relation
Explanation:
The percentage error in anything is computed from ...
%error = ((measured value)/(accurate value) -1) × 100%
__
The difficulty with voltage measurements is that the "accurate value" may be hard to determine. It can be computed from the nominal values of circuit components, but there is no guarantee that the components actually have those values.
Likewise, the measuring device may have errors. It may or may not be calibrated against some standard, but even measurement standards have some range of possible error.
Answer:
use the percentage error relation
An intake manifold gasket has been replaced due to a vacuum leak. Which of the following steps uses a scan tool to complete the job? O A. Torquing the manifold bolts B. Idle relearn O C. Refilling the cooling system O D. Air cleaner check
Answer: B.Idle relearn
Explanation:
When replacing an intake manifold gasket due to a vacuum leak, using a scan tool for idle relearn is a crucial step to complete the job. The Option B.
How does a scan tool help complete the job when replacing an intake manifold gasket?The scan tool is used to reset the idle control system and allow the engine's computer to relearn the correct idle speed and air/fuel mixture. This is important because the replacement of the intake manifold gasket can affect the engine's idle characteristics.
By using the scan tool to perform an idle relearn procedure, the engine management system can recalibrate and optimize the idle control parameters, ensuring smooth and stable idle operation. This step helps to restore the engine's performance and maintain proper combustion efficiency after the intake manifold gasket replacement.
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covers and guardrails are required in all of the following areas except: open pits ditches loading docks vats
The covers and guardrails are required in all of the following areas except ditches.
Do open pits require covers and guardrails?
Yes, they do need a covers and/or guardrails and it is one that is known or shall be provided to help in the protection of personnel from the hazards that pertains to open pits, tanks, vats and others.
Note that they are often needed that is covers and/or guardrails need to be provided to help to protect personnel.
Therefore, The covers and guardrails are required in all of the following areas except ditches.
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a map sensor is being tested. technician a says that many map sensors also act as a barometric pressure sensor when the ignition switch is first turned on. technician b says on many map sensors the signal voltage should increase when the vacuum at the sensor decreases. which technician is correct?
Technician b is correct many map sensors the signal voltage should increase when the vacuum at the sensor decreases.
An area devoid of matter is called a vacuum. The adjective vacuus, which means "empty" or "void," is the source of the word. A region with a gaseous pressure significantly below atmospheric pressure might be thought of as an approximate representation of such a vacuum. vacuum, space where there is no matter present or where the pressure is so low that any particles present have no impact on any processes occurring there. It is measured in units of pressure and is a state that is significantly lower than the average atmospheric pressure. Even though the finest vacuum is in space, scientists have created vacuum chambers and vacuum pumps to imitate this environment. A vacuum chamber is a small enclosure with no air inside of it.
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A 1300 kg car is involved in an accident and is being towed by a truck. Determine the power required by the truck
a. For a constant velocity on a level road
b. For a constant velocity of 60 km/h on a 35° uphill road
c. Toaccelerateonalevelroadfromrestto80km/hin10s.
Answer:
Explanation:
a. When the car is being towed by the truck at a constant velocity on a level road, the net force acting on the car is zero. This means that the power required by the truck to maintain this velocity is equal to the power dissipated by frictional forces, which is given by:
Power = Force × Velocity
The force of friction can be calculated using the coefficient of rolling resistance and the weight of the car:
Force = coefficient of rolling resistance × weight
= 0.01 × 1300 kg × 9.81 m/s^2
= 127.53 N
The velocity of the car is not given, so we cannot calculate the power required by the truck.
b. When the car is being towed by the truck at a constant velocity of 60 km/h on a 35° uphill road, the power required by the truck can be calculated as follows:
Power = Force × Velocity
The force required to maintain this velocity can be resolved into two components: the force due to gravity acting downhill and the force due to friction acting uphill. The force due to gravity can be calculated using the weight of the car and the angle of the slope:
Force due to gravity = weight × sin(35°)
= 1300 kg × 9.81 m/s^2 × sin(35°)
= 7113.95 N
The force due to friction can be calculated using the coefficient of rolling resistance and the weight of the car:
Force due to friction = coefficient of rolling resistance × weight
= 0.01 × 1300 kg × 9.81 m/s^2
= 127.53 N
The net force required to maintain a constant velocity can be calculated as the vector sum of these two forces:
Net force = Force due to gravity - Force due to friction
= 7113.95 N - 127.53 N
= 6986.42 N
The velocity of the car can be converted to meters per second:
Velocity = 60 km/h × 1000 m/km / 3600 s/h
= 16.67 m/s
Now we can calculate the power required by the truck:
Power = Net force × Velocity
= 6986.42 N × 16.67 m/s
= 116,419.1 W
≈ 116.42 kW
Therefore, the power required by the truck to maintain a constant velocity of 60 km/h on a 35° uphill road is approximately 116.42 kW.
c. When the truck is accelerating the car on a level road from rest to 80 km/h in 10 seconds, the average power required can be calculated as follows:
First, we need to convert the final velocity to meters per second:
Final velocity = 80 km/h × 1000 m/km / 3600 s/h
= 22.22 m/s
The acceleration of the car can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time
= (22.22 m/s - 0 m/s) / 10 s
= 2.22 m/s^2
The force required to accelerate the car can be calculated using Newton's second law:
Force = mass × acceleration
= 1300 kg × 2.22 m/s^2
= 2892 N
The power required to accelerate the car can be calculated using the formula:
Power = Force × Velocity
= 2892 N × (80 km/h × 1000 m/km / 3600 s/h)
= 226,595.6 W
The net force acting on the car is zero when it is being towed by the truck at constant speed along a flat road.
What is Power?The power dissipated by frictional forces, which is determined by the following equation, is equal to the power needed by the vehicle to maintain this velocity.
Force and velocity are the components of power. Using the coefficient of rolling resistance and the vehicle's weight, one can get the force of friction.
Weight Force = Coefficient of rolling resistance = 0.01 × 1300 kg × 9.81 m/s^2 = 127.53 N
Therefore, The net force acting on the car is zero when it is being towed by the truck at constant speed along a flat road.
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Determine the NPW, AW, FW and IRR of the following engineering project. • Initial Cost ($400,000) • The Study Period 15 years Salvage (Market) Value of the project 15% of the initial cost Operating Costs in the first year ($9,000) • Cost Increase 3% per year • Benefits in the first year $40,000 Benefit Increase 9% per year • MARR 8% per year Is the Project acceptable? WHY?
The CEO of PT ABC asked the project manager to use PW, AW, and FW to prioritize the project while also adding the expected reject rate between each alternative.
Thus, This implies that the anticipated revenue will vary depending on the choice. The three projects are prioritized by the project manager. The CEO will assess which option will be more profitable than the others.
The quantity of money that is accessible for investment, as well as where and how much it cost (for example, whether it came from equity funds or borrowed funds).
The quantity of worthwhile projects that are open to investment and their objective (i.e., whether they maintain current operations and serve a necessary purpose or whether they enlarge current operations and serve a discretionary purpose) and PW.
Thus, The CEO of PT ABC asked the project manager to use PW, AW, and FW to prioritize the project while also adding the expected reject rate between each alternative.
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consider this single-tank liquid level system. which of the following is the output mass flow rate of this system? please submit your hand calculations into the dropbox.
•R2:Linear resistance of valve •h :Height of liquid •qi =inlet volume flow rate •A=cross sectional area of the tank (constant) •P:density of liquid=constant •P, pump: pump pressure •P pump: pump pressure Apply the law of conservation of mass to the E.O.M. Assuming h> h1 > h2 Which of the following is the output mass flow rate of this system? Please submit your hand calculations into the dropbox.
The output mass flow rate of the system can be determined using the law of conservation of mass.
According to the law of conservation of mass, the mass flow rate into the system must be equal to the mass flow rate out of the system. Therefore, we can equate the mass flow rate at the inlet (qi) to the mass flow rate at the outlet (qo).
Using the Bernoulli's equation, we can express the outlet mass flow rate (qo) in terms of the system variables:
qo = A * sqrt(2 * (P - P_pump) / P) * sqrt(2 * (h1 - h2 + R2 * qo^2 / A^2))
Simplifying this equation by assuming that the term R2 * qo^2 / A^2 is small compared to the other terms, we get:
qo = A * sqrt(2 * (P - P_pump) / P) * sqrt(2 * (h1 - h2))
Therefore, the output mass flow rate (qo) can be calculated as:
qo = A * sqrt(2 * (P - P_pump) / P) * sqrt(2 * (h1 - h2))
The output mass flow rate of the single-tank liquid level system is given by the equation qo = A * sqrt(2 * (P - P_pump) / P) * sqrt(2 * (h1 - h2)).
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The XYZ Company is planning a new product line and a new factory to produce the parts and assemble the final products. The product line will include 13 different models. Annual production of each model is expected to be 1,000 units. Each product will be assembled of 250 components, but 65% of these will be purchased parts (not made in the new factory). There is an average of 8 processing operations required to produce each component, and each processing step takes 30 sec (including an allowance for setup time and part handling). Each final unit of product takes 48 min to assemble. All processing operations are performed at work cells that include a production machine and a human worker. Products are assembled at single workstations consisting of one worker each plus assembly fixtures and tooling. Each work cell and each workstation require 25 m2 of floor space and an additional allowance of 45% must be added to the total production area for aisles, work-in-process storage, shipping and receiving, rest rooms, and other utility space. The factory will operate one shift (the day shift, 2,000 hr/yr). Determine: (a) how many processing and assembly operations, (b) how many workers (direct labor only), and (c) how much total floor space will be required in the plant.
The plant will need to perform 9,100,000 processing and assembly procedures altogether.
What fundamental processing tasks are carried out in a manufacturing facility?Shape operations, property-enhancing operations, and surface processing operations are the three distinct categories of processing operations. By using mechanical force, heat, or other forms and combinations of energy, shaping operations change the work material's geometry.
There are 250 components in each product.
Parts purchased as a percentage equal 65%.
250 - (65% x 250) = 87.5 is the number of components that will be produced in the new facility.
Eight processing steps are needed to manufacture each component.
The new factory's processing procedures per component totaled 8 x 87.5, or 700.
13 x 1000 x (700 + 1) = 9,100,000 is the total number of processing and assembly procedures needed for the 13 different models.
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In a 1-phase UPS, Vd = 350 V, vo(t) = 170 sin(2π * 60t) V, and io(t) = 10 sin(2π * 60t - 30ᴼ) A.Calculate and plot da(t), db(t), vaN(t), vbN(t), Id, id2(t) and id(t). Switching frequency fs = 20 kHz.
Answer: provided in the explanation section
Explanation:
The question says;
In a 1-phase UPS, Vd = 350 V, vo(t) = 170 sin(2π * 60t) V, and io(t) = 10 sin(2π * 60t - 30ᴼ) A.Calculate and plot da(t), db(t), vaN(t), vbN(t), Id, id2(t) and id(t). Switching frequency fs = 20 kHz.
Answer
From this we have come to this;
da = Ṽan/Vd = 0.5 + (0.5 * 0.4857) sin w,t
db = Ṽbn/Vd = 0.5 - (0.5 * 0.4857) sin w,t
Ṽan(t) = da * 350 V
Ṽbn(t) = db * 350 V
Id = 0.5 * Ṽo/ Vd * Îo cosΦ1 = 0.5 * (170/350) * 10 * cos 30ᴼ = 2.429 A
Id2 = -0.5 * 170/350 * 10 * sin(2 w,t - 30ᴼ) = -2.429 sin(2 w,t - 30ᴼ)
īd = Id + id2 = 2.429 A + -2.429 sin(2 w,t - 30ᴼ).
Note: Attached is a copy of an image showing and explaining thr plots.
cheers i hope this has been helpful !!!!
A liquid of specific heat 3000J/kgk rise from 15°c to 65°c in 1 min when an electric heater is used. If the heater generate 63000J, calculate the mass of the water
Answer:
0.42 kg
Explanation:
Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.
\(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)
The mass of the liquid is about 0.42 kg.
NEED A CHEN NOTATION DIAGRAM OF THE FOLLOWING INFORMATION
***** This is a Chen Notation ER Diagramming Assignment. Only Chen Notation Diagrams will be accepted. *****
During peak periods, the Temporary Employment Corporation (TEC) places temporary workers in companies. TEC’s manager gives you the following description and business rules of the business:
TEC has a file of candidates who are willing to work. They would like to put this Candidate File Information into a Database.
If the candidate has worked before, that candidate has a specific job history. (Naturally, no job history exists if the candidate has never worked.) Each time the candidate works temporarily for an outside company, one additional job history record is created. TEC wants the candidate's Job History in a database.
Each candidate has earned several qualifications. Each qualification may be earned by more than one candidate. (For example, it is possible for more than one candidate to have earned a BBA degree or a Microsoft Network Certification. And clearly, a candidate may have earned both a BBA and a Microsoft Network Certification.) TEC wants to store all existing and future types of Qualifications in a database.
TEC offers courses to help candidates improve their qualifications. This is done by offering training courses so that candidates can earn qualifications. TEC wants to keep store all courses that they offer for qualifications in a Database
Every course develops one specific qualification; however, TEC does not offer a course for every qualification. Some qualifications have multiple courses that develop that qualification.
Some courses cover advanced topics that require specific qualifications as prerequisites. Some courses cover basic topics that do not require any prerequisite qualifications. A course can have several prerequisites. A qualification can be a prerequisite for more than one course.
TEC also has a list of companies that request temporary employees.
Each time a company requests a temporary employee, TEC makes an entry in the Openings folder. That folder contains an opening number, a company name, required qualifications, a starting date, and anticipated ending date, and hourly pay. TEC wants to store all company requests for temporary jobs in a database.
When a candidate matches the qualification, the job is assigned, and an entry is made in the Placement Record folder. That folder contains an opening number, a candidate number, the total hours worked, etc. In addition, an entry is made in the job history for the candidate.
An opening can be filled by many candidates, and a candidate can fill many openings.
Summary Information that has to be Maintained
Client Company Information. These are companies that need Temporary Workers.
Job Opening Information, a Company offers one or more Temporary Job-Opening Positions
Qualification or Skills of the Candidates in (TEC). A Candidate can have one or more Qualifications
Candidate or Temporary Worker Information. A Candidate is a Temporary Worker seeking a position
Candidate JOB_HISTORY Information. This is a Temporary Workers Work History.
Placement Information. This is the Record of all Temporary Workers Placed in a Temporary Job
Training Courses that are being offered to (TEC) Candidates.
Training Courses that Candidates have taken
Given that information, do the following:
Draw the Chen ERDs for this enterprise
Identify all Entities
Identify all Attributes for the Entities
Identify all possible relationships
Identify the Cardinality for each relationship
Resolve all 1: N relationships
Resolve all M: N relationships
Identify Primary Keys and map the Foreign Keys based on the described Cardinality
The ER diagram for the Temporary Employment Corporation (TEC) based on the business rules given is given below: Attributes for Entities:
(One-to-Many)One candidate can have many job histories. (One-to-Many)One job history can belong to only one candidate. (One-to-One)One placement can belong to only one candidate. (One-to-One)One job opening can be placed by many placements. (One-to-Many)One candidate can have many placements.
In the given diagram below, all the relationships and primary keys are labeled correctly and the ER diagram is resolved for all M:N relationships and 1:N relationships. If you want to add more attributes to each entity, you can do it accordingly:
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Write a short summary, at least 5 paragraphs regarding the areas that you think Fluid Mechanics is the governing science to describe the phenomena and explain in details your understanding of means of applicability.
Answer:
Fluid mechanics has great application in important branches of science such as acoustics and aeroelasticity.
Explanation:
Acoustics studies the speed of transmission, propagation, storage and reproduction of sound. In industries, knowing how sound is transmitted and the speed in the different activities that are carried out, allow control programs and adjustments to be carried out to avoid damages to the employees.
Aeroelasticity comprises the study of three important forces; inertial forces, elastic forces, and aerodynamic forces.
This field of action of fluid mechanics is important because it allows space engineering to study or design new systems or aircraft that are stable in or outside the atmosphere.
Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determine the percentage of total unit cell volume that is occupied in (a) simple cubic lattice and (b) a diamond lattice. For each case, write down smallest distance, unit volume, number of atoms per unit cell, equation for density or packing fraction. Show your calculation and check your unit.
Answer:
The classification of the concern is listed in the interpretation segment below.
Explanation:
(a)...
Simple cubic lattice
\(a=2r\)
Now,
The unit cell volume will be:
\(=a^3\)
\(=(2r)^3\)
\(=8r^3\)
At one atom per cell, atom volume will be:
\(=(1)\times (\frac{4 \pi r^3}{3})\)
Then the ratio will be:
\(Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent\)
\(=52.4 \ percent\)
(b)...
Diamond lattice
The body diagonal will be:
\(d=8r=a\sqrt{3}\)
\(a=\frac{8}{\sqrt{3}}r\)
The unit cell volume will be:
\(=a^1\)
\(=(\frac{8r}{\sqrt{3}})^1\)
At eight atom per cell, the atom volume will be:
\(=8(\frac{4 \pi r^1}{3})\)
Then the Ratio will be:
\(Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent\)
\(=34 \ percent\)
Note: percent = %
Calculate the tensile modulus of elasticity for a laminated composite consisting of 62 percent by volume of unidirectional carbon fibers and an epoxy matrix under isostress conditions. The tensile modulus of elasticity of the carbon fibers is 340 GPa and that of the epoxy is 4.50 103 MPa.
Answer:
4.30 gp
Explanation:
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4. a. A family purchased a 3 acre piece of land in Limuru for Kshs.30,000,000.00 fifteen years ago. They planted trees at a cost of Kshs.250,000.00 per acre. Each year they have been spending on average Kshs.25,000.00 per acre per month to take care of the trees and also to secure the property. They are now considering selling it. What is the minimum amount they should accept so as not to incur a loss bearing in mind that comparable properties have been yielding a rate of 6.5% interest per annum? (8 marks)
b. “Compulsory acquisition is the power of government to acquire private rights in land for public good without the willing consent of the owner but; in exchange for compensation”. Discuss this statement with special reference to the main considerations that ought to be made in conducting a valuation for compulsory acquisition. (12 marks)
The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.
Why should they accept this amount and why?To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.
Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.
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CAN I GET ANSWERS PLEASE, I TRY THE FORMULA AND MY TEACHER HAS A FAMILY EMERGENCY SO HE CANT RESPOND BACK SO PLEASE HELP ME
Explanation:
I won't answer each of these, but will give you an explaination of how to solve for each.
You'll need to use Ohm's Law and Kirchhoff's Voltage Law.
Remember Ohm's Law as \(V = IR\).
Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.
\(E_T = E_1 + E_2 + E_3\)
A couple of other helpful notes:
These three resistors are in series which means that the current flowing through them is equal.
So it is easy to see that... \(V = IR \rightarrow E_1 = 4*2 = 8 V\)
Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).
What is code in Arduino to turn led on and off
here's your answer..
what is the role of product design?
Answer:
Product designers are in charge of the entire product creation process. They are ultimately responsible for discovering and defining a problem, and then empathically designing a solution. The skills that a product designer must have range from technical to human-centered design.
Explanation: