y=8x-x^2
y=2x
step by step solution and fast please !

The answer is 3 ft-lb.

Beyond its natural length:

Work done to strech the spring to a lentgh x = 0.5 * k * x^2

Now;

12  = 0.5 * k * 9

k = 8/3 = 2.667

9 in = 1.5 ft

Work needed to stretch it 9 in. beyond its natural length = 0.5 * 2.667 * 1.5*1.5 = 3 ft-lb

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Answer:

16 shirts.

Step-by-step explanation:

You can make a system of equations

x + y = 26

5.50x + 12y = 208

You can solve this in many ways, however  chose to graph using desmos. I got that x = 16, and y = 10.

The number of degrees that the direction of the boat change when it made its first turn is 39°.

From the information given, we would use the cosine function to solve the information.

This will be:

18² = 28² + 25² - 2(28)(25)(cos x)

324 = 784 + 625 - 1400cosx

x = 39.19

Therefore, the value is 39°.

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The probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

Probability defines the likelihood of occurrence of an event. There are many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur. Probability generally has great applications in games, in business to make probability-based predictions, and also probability has extensive applications in this new area of artificial intelligence.

The probability of an event can be calculated by probability formula by simply dividing the favorable number of outcomes by the total number of possible outcomes. The value of the probability of an event to happen can lie between 0 and 1 because the favorable number of outcomes can never cross the total number of outcomes. Also, the favorable number of outcomes cannot be negative.

\(P(50.5 < = X < = 51.25) =\frac{51.25-50.5}{54-49 } = \frac{0.75}{5} = 0.15\)

P = 0.15 means that the probability is 15%.

Thus, the probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

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Answer:

144

Step-by-step explanation:

An angle of a regular pentagon is of 180(5-2)/5=108°

and that all the sides are equal so angle MNL=108/3=36

then MNK=180-MNL=180-36=144

I don't know if you understand this but it's hard to work without more points :)

D. No, because the probability of being left-handed is greater, x must count the number of left-handed adults.

The binomial probability formula can be used to calculate the probability of a certain number of successes (or left-handed individuals) in a given number of trials (100 adults). In order for the binomial probability formula to be used, the trials must be independent, meaning that the selection of one person does not affect the selection of the next one. Since the probability of being left-handed is greater, the binomial probability formula cannot be used in this case and x must count the number of left-handed adults.

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The value of x, y and z are 2/3, 1, and 3/2 if the system of equations 3⁢x+y+2⁢z=6 6⁢x−2⁢y=2 3⁢x+y−2⁢z=0

It is defined as the relation between three variables, if we plot the graph of the linear equation we will get a plane.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The linear equations are:

3⁢x+y+2⁢z=6

6⁢x−2⁢y=2

3⁢x+y−2⁢z=0

From equation (I) and (III)

6x + 2y = 6

From the above equation and equation (II)

12x = 8

x = 8/12 = 2/3

y = 1

z = 3/2

Thus, the value of x, y and z are 2/3, 1, and 3/2 if the system of equations 3⁢x+y+2⁢z=6 6⁢x−2⁢y=2 3⁢x+y−2⁢z=0

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Answer:

The smaller integer is greater than 1

Step-by-step explanation:

The integers are x and x+1

\(x + x + 1 < 3x \\ 2x + 1 < 3x \\ 2x - 2x + 1< 3x - 2x \\ 1< x \)

Answer:

59.65

Step-by-step explanation:

2 decimal places is to the hundredths place.

Answer: 59.65

Step-by-step explanation: When rounding a number to a given place, look at the next place y o the right. If that digit is 5 or more, "round up" by adding one to the given place.

If the number to the right is 4 or less, leave the given place "as is"

In this example, the hundredths place is 4, the place to the right has an 8. So you round up the 4 to a 5. You end up with 59.65

To show that E(Xn) = Ek=p-k, we can use the concept of conditional expectation and the law of total expectation.

Let's define X as the number of flips required to obtain a run of n consecutive heads.

We can express X as the sum of two random variables: the number of flips required to obtain the first head (H) and the number of additional flips required to obtain a run of n-1 consecutive heads (Xn-1).

We can write the equation as:

X = H + Xn-1

Taking the expectation on both sides, we have:

E(X) = E(H + Xn-1)

Using the linearity of expectation, we can rewrite this as:

E(X) = E(H) + E(Xn-1)

The expected number of flips required to obtain the first head is simply the reciprocal of the probability of getting heads on a single flip, which is 1/p.

So, E(H) = 1/p.

Next, let's consider the expectation of Xn-1. Since Xn-1 represents the number of additional flips required to obtain a run of n-1 consecutive heads, it is equivalent to Xn but with a reduced value of n.

Using the law of total expectation, we can express E(Xn-1) as a conditional expectation:

E(Xn-1) = E(E(Xn-1 | Xn-1 > 1))

In other words, the expected value of Xn-1 can be obtained by conditioning on the event that the first flip is not a head.

Since the first flip is not a head, we need to start over and obtain a new run of n consecutive heads.

Therefore, the expectation of Xn-1 conditioned on Xn-1 > 1 is equal to E(Xn).

Putting it all together, we have:

E(X) = E(H) + E(Xn-1)

    = 1/p + E(Xn)

Simplifying further, we get:

E(X) = 1/p + E(Xn)

Now, notice that E(X) is equal to E(Xn) when n = 1.

Therefore, we can write:

E(X) = 1/p + E(X)  (since E(X1) = E(X))

Solving for E(X), we find:

E(X) = 1/p

Finally, let's substitute k = n-1 into the expression:

E(Xn) = 1/p

Since k = n-1, we have:

E(Xn) = 1/p = Ek=p-k

Therefore, we have shown that E(Xn) = Ek=p-k.

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Answer:

10N as the SI u it for net force is N

Step-by-step explanation:

The answer is:

F=MA

=2Kg×5m/s

=10N

1% growth has a multiplier 1+0.01=1.01

What is exponential growth function ?

A process called exponential growth sees a rise in quantity over time. When a quantity's derivative, or instantaneous rate of change with respect to time, is proportionate to the quantity itself, this phenomenon takes place.

The exponential function which models the exponential growth has a form

\(y= C(1+r)^x\)

where C is initial amount, y is final amount, x is time, r is rate (the percent written as a decimal) and 1+r is a multiplier.

The exponential function which models the exponential decay has a form

\(y= C(1-r)^x\)

where C is initial amount, y is final amount, x is time, r is rate (the percent written as a decimal) and 1-r is a multiplier.

Thus,

1. 1% growth has a multiplier 1+0.01=1.01;

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As asked by the question, the value of K for a given equation of a line is equal to the slope of the line.

A line has length but no breadth, making it a one-dimensional figure. A line is made up of a collection of points that may be stretched indefinitely in opposing directions. Two points in a two-dimensional plane determine it.

A line's steepness may be determined by looking at its slope. Slope is computed mathematically as "rise over run" (change in y divided by change in x).

The value of K for a given line is equal to the slope of the line. Since lines are generally expressed in the form of y = mx +b , where m is the slope of the line and b is the y-intercept of the line. Here , the value of K will be equal to the slope m of the line.

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The answer to the question is 334 kittens.

Given that a cat gave birth to 333 kittens who each had a different mass between 147 g and 159 g. Then the cat gave birth to a 4th kitten with a mass of 57 g.

First of all, we will find out the range of the mass of kittens. The range is given as follows;Range = Maximum Value - Minimum Value Range = 159 g - 147 g Range = 12 g

Now, the cat gave birth to a 4th kitten with a mass of 57 g, we can say that the minimum value of kitten's mass is 57 g.So, the maximum value of kitten's mass can be calculated as follows;Maximum Value = 57 g + Range Maximum Value = 57 g + 12 g Maximum Value = 69 g Now, we can say that all kittens with a mass of 69 g or less would be born because the minimum value of kitten's mass is 57 g and the range of mass is 12 g.

Therefore, the answer to the question is 334 kittens.

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The sample indicates that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

This given test is a test for single sample proportion

The test hypothesis are:

\(H_{o} :p=0.20\), null hypothesis

\(H_{1} :p\neq 0.20\), alternative hypothesis

The test statistic fallows a standard normal distribution and is given by:

\(Z=\frac{x-p}{{\sqrt{p(1-p)/n} } }\)

p=0.20

X=47 plants

Sample size, n=500

x, is the sample mean:

x=X/n=47/500

x=0.094

So, test statistic is calculated as:

\(Z=\frac{0.094-0.20}{\sqrt{0.20(1-0.20)/500} }\)

Z=-5.93

From the z-table, the p-value associated with Z=-5.93 is approximately 0

The decision rule based on p-vale, is to reject the null hypothesis if p-value is less than confidence level

In this case, the p-value is very small and less than confidence level of 0.20, we therefore reject the null hypothesis or the claim

So we conclude that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

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Answer:

there is no number for that,there is infinite stars in the universe

Answer:

TUNNEL:

f(x) = -2/4.9  \(x^{2}\)  + 9.8

TRUCK:

Width (m) < 9.8

Height (m) <  -2/4.9 ( \(Width^{2}\) /4 - \(4.9^{2}\) )

Step-by-step explanation:

Please see attachment

If the maximum height of the tunnel is the same as its maximum width, 9.8 meters, The quadratic model to represent the tunnel will be f(x)= (-2/4.9)x²+9.8.

Any function of the form\(\rm f(x) =ax^2+bx+c\) where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic function.

It is given that, If the maximum height of the tunnel is the same as its maximum width, 9.8 meters.

We have to determine a quadratic model to represent the tunnel.

The quadratic function is formed as,

f(x) =K(x-x₁)(x-x₂)

x₁=width/2

x₁=9.8/2 = 4.9

x₂= -x₁ = -4.9

Substitute the obtained value as,

f(x) = K(x-4.9)(x-(-4.9))

f(x) =K(x²-4.9²)

f(0)=9.8

The value of K is obtained as a result,

K=-2×4.9/(4.9)²

K= -2/4.9

Substitute the value of K as,

f(x) = -2/4.9(x²-4.9²)

f(x) = (-2/4.9)x²+2×4.9

f(x)= (-2/4.9)x²+9.8

Thus, if the maximum height of the tunnel is the same as its maximum width, 9.8 meters, The quadratic model to represent the tunnel will be f(x)= (-2/4.9)x²+9.8.

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The latest possible time that Lyle could leave home in order to arrive at his friend’s house on time is 8:30 a.m

Given that Lyle is driving from home to his friend’s house, a distance of 720 km. He plans to drive at an average speed of 80 km per hour, take an hour for lunch, and take two 15- minute breaks and He must arrive at his friend’s house by 7:00 p.m.

The time it takes Lyle to drive to his friend's house is given by t = d/v where

Given that Lyle is driving from home to his friend’s house, a distance of 720 km. He plans to drive at an average speed of 80 km per hour, we have that

Substituting the values of the variables into t, we have

t = d/v

= 720 km/80 km/h

= 9 h

So, it takes Lyle 9 hours to drive.

Now, since Lyle takes an hour for Lunch and two 15 minutes breakes, this extra time is t' = 1 h + 2 × 15 min

= 1 h + 30 min

= 1 h + 30 min/60 min × 1h

= 1 h + 0.5 h

= 1.5 h

So, the total time Lyle takes to reach his friend's house is T = t + t'

= 9 h + 1.5 h

= 10.5 h

Since Lyle must reach his friend's place no later than 7:00 pm, 10.5 hrs from 7:00 pm is 8:30 am.

So, Lyle must leave no later than 8:30 a.m

So, the latest possible time that Lyle could leave home in order to arrive at his friend’s house on time is 8:30 a.m

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Answer:

4/6 and 8/12

Step-by-step explanation:

Answer:

do u need help with any thing?

Answer:12

Step-by-step explanation:

36:3=12

Percentage of data within 2 population standard deviations of the mean is 68%.

To calculate the percentage of data within two population standard deviations of the mean, we need to first find the mean and standard deviation of the data set.

The mean can be found by summing all the values and dividing by the total number of values:

Mean = (20*2 + 22*8 + 28*9 + 34*13 + 38*16 + 39*11 + 41*7 + 48*0)/(2+8+9+13+16+11+7) = 32.68

To calculate standard deviation, we need to calculate the variance first. Variance is the average of the squared differences from the mean.

Variance = [(20-32.68)^2*2 + (22-32.68)^2*8 + (28-32.68)^2*9 + (34-32.68)^2*13 + (38-32.68)^2*16 + (39-32.68)^2*11 + (41-32.68)^2*7]/(2+8+9+13+16+11+7-1) = 139.98

Standard Deviation = sqrt(139.98) = 11.83

Now we can calculate the range within two population standard deviations of the mean. Two population standard deviations of the mean can be found by multiplying the standard deviation by 2.

Range = 2*11.83 = 23.66

The minimum value within two population standard deviations of the mean can be found by subtracting the range from the mean and the maximum value can be found by adding the range to the mean:

Minimum Value = 32.68 - 23.66 = 9.02 Maximum Value = 32.68 + 23.66 = 56.34

Now we can count the number of data points within this range, which are 45 out of 66 data points. To find the percentage, we divide 45 by 66 and multiply by 100:

Percentage of data within 2 population standard deviations of the mean = (45/66)*100 = 68% (rounded to the nearest percent).

Therefore, approximately 68% of the data falls within two population standard deviations of the mean.

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Answer:

2 11/22

Step-by-step explanation:

35/4 -35/6

35/12

2 11/12

We can use the trigonometric tangent identity, this is:

Where z = 60°

opposite side = x

adjacente side = 50ft

Then:

And the tower height is:

Answer: 93.6 ft

The  diameter of the rod required to limit the total elongation to 0.10 inches is approximately 1-1/2 inches (or 1.441 inches to be more precise). Hence, the correct answer is option (A) with an elongation of 0.2358 inches and using a 1-1/2" diameter rod.

(a) To compute the total elongation, we can use the formula:

Elongation = (P * L) / (A * E)

where P is the axial tensile load, L is the length of the rod, A is the cross-sectional area of the rod, and E is the modulus of elasticity for the material.

Given:
P = 30,000 lb
L = 20 ft = 240 in
Diameter of the rod = 1-1/2 in

First, we need to calculate the cross-sectional area:

Area = π * (diameter/2)^2
Area = π * (1.5/2)^2
Area ≈ 1.767 in^2

Next, we need to determine the modulus of elasticity for the material. Assuming it's a standard structural steel, we can use a typical value of 29,000,000 psi.

Now we can plug the values into the formula:

Elongation = (30,000 * 240) / (1.767 * 29,000,000)
Elongation ≈ 0.2358 in

Therefore, the total elongation is approximately 0.2358 inches.

(b) If the total elongation must not exceed 0.10 inches, we need to determine the diameter of the rod that satisfies this requirement.

We can rearrange the formula for elongation to solve for the cross-sectional area:

A = (P * L) / (E * Elongation)

Using the given values:

A = (30,000 * 240) / (29,000,000 * 0.10)
A ≈ 2.069 in^2

To find the corresponding diameter, we use the formula:

Diameter = √(4 * A / π)

Diameter = √(4 * 2.069 / π)
Diameter ≈ 1.441 in

Therefore, the diameter of the rod required to limit the total elongation to 0.10 inches is approximately 1-1/2 inches (or 1.441 inches to be more precise). Hence, the correct answer is option (A) with an elongation of 0.2358 inches and using a 1-1/2" diameter rod.

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If new data will be collected (i.e., primary data collection), the researcher can easily recruit an adequate number of participants is false.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Given,

We need to check whether if new data will be collected (i.e., primary data collection), the researcher can easily recruit an adequate number of participants is true or false.

The given statement is false because Primary data collection is a process of collecting original data, directly from the source.

Hence, if new data will be collected (i.e., primary data collection), the researcher can easily recruit an adequate number of participants is false.

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Answer:28

Step-by-step explanation:

Break it up! 6x3 is 18. Then 18 + 10 is 28 :P

Hope this helps :D

Given:

Solution in Exact Form:

Hope this helps!

The general solution of the differential equation y''(x) + y(x) = sec(x) tan(x) is y(x) = c₁cos(x) + c₂sin(x) + (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x); here c₁ and c₂ are constants.

To solve the differential equation y''(x) + y(x) = sec(x) tan(x) using variation of parameters, we first need to find the solutions to the homogeneous equation y''(x) + y(x) = 0.

The auxiliary equation for the homogeneous equation is r² + 1 = 0, which has complex roots r = ±i.

The corresponding solutions to the homogeneous equation are y₁(x) = cos(x) and y₂(x) = sin(x).

Next, we need to find the particular solution using the method of variation of parameters. Let's assume the particular solution has the form y_p(x) = u(x)cos(x) + v(x)sin(x).

Now, we need to find u(x) and v(x) by substituting this form into the original differential equation and solving for u'(x) and v'(x).

Differentiating y_p(x), we get y_p'(x) = u'(x)cos(x) - u(x)sin(x) + v'(x)sin(x) + v(x)cos(x).

Taking the second derivative, y_p''(x) = -u(x)cos(x) - u'(x)sin(x) + v(x)sin(x) + v'(x)cos(x).

Substituting these derivatives into the original differential equation, we have:

(-u(x)cos(x) - u'(x)sin(x) + v(x)sin(x) + v'(x)cos(x)) + (u(x)cos(x) + v(x)sin(x)) = sec(x)tan(x).

Simplifying, we get:

u'(x)sin(x) + v'(x)cos(x) = sec(x)tan(x).

To find u'(x) and v'(x), we solve the following system of equations:

u'(x)sin(x) + v'(x)cos(x) = sec(x)tan(x),

u(x)cos(x) + v(x)sin(x) = 0.

We can solve this system using various methods such as substitution or elimination.

Solving the system, we find:

u'(x) = sin(x)sec(x),

v'(x) = -cos(x)sec(x).

Integrating these expressions, we obtain:

u(x) = -ln|sec(x) + tan(x)| + C₁,

v(x) = -ln|sec(x) + tan(x)| + C₂.

Finally, the particular solution is given by:

y_p(x) = (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x).

The general solution to the differential equation is the sum of the homogeneous and particular solutions:

y(x) = c₁cos(x) + c₂sin(x) + (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x).

Here, c₁ and c₂ are constants.

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