The false statement concerning permanent magnets is (e) The north pole of a compass point toward the north pole of a permanent magnet. In reality, the north pole of a compass points towards the south pole of a permanent magnet because opposite poles attract each other.
The magnetic field surrounding a magnet is directed away from the north pole and into the south pole, meaning that the north pole of a compass is attracted to the south pole of a permanent magnet, rather than the north pole.
The other statements provided in the student question are true, including the fact that there is a magnetic field surrounding a magnet, the magnetic field is directed away from a north pole and into a south pole, magnets can exert forces on each other, and a north pole attracts a south pole.
The complete question is:
Which one of the following statements concerning permanent magnets is false?
(A) There is a magnetic field surrounding a magnet.
(B) The magnetic field is directed away from a north pole and into a south pole.
(C) Magnets can exert forces on each other.
(D) A north pole attracts a south pole.
(E) The north pole of a compass points toward the north pole of a permanent magnet.
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In scientific notation, 0.00074m can be written as 1- 0.74×10‐³m 2- 7.4×10-⁴m 3- 74×10‐⁵m 4- 740×10‐⁶m
Answer:
\(0.00074m\) \(=\) \(7.4*10^{-4}m\)
Explanation:
Given
\(0.00074m\)
Required
Express as scientific notation
The scientific notation of a number is: \(a * 10^{b}\)
Where \(1 \le a \le 9\)
This implies that:
\(0.00074m = 7.4 * 10^b\)
Next, is to determine the value of b.
Count the number of point to move from the current point location to 7.4.
If the point moves backward, b will be negative, else b will be positive.
So:
\(0.00074m\) \(b=-4\)
Hence:
\(0.00074m\) \(=\) \(7.4*10^{-4}m\)
Describe the relationship between speed and thinking distance. Physics Paper 2
While there is no direct relationship between speed and thinking distance, higher speeds can result in longer thinking distances due to the increased reaction time needed by the driver.
The relationship between speed and thinking distance is not a direct one, as thinking distance is primarily influenced by the driver's reaction time rather than the actual speed of the vehicle. Thinking distance refers to the distance traveled by a vehicle during the driver's reaction time after perceiving a hazard.
However, there is an indirect relationship between speed and thinking distance in the sense that higher speeds generally result in longer thinking distances. When a vehicle is traveling at a higher speed, the driver needs more time to process information, make decisions, and react to potential hazards. Therefore, a higher speed can lead to a longer thinking distance.
It is important to note that thinking distance is just one component of the total stopping distance, which also includes braking distance. Braking distance is directly influenced by the speed of the vehicle. Higher speeds require longer braking distances to bring the vehicle to a stop.
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Why can videos be streamed from one computer to another with excellent
quality?
A. They are received using both analog and digital signals.
B. They are transmitted using analog signals.
C. They are received using either analog or digital signals.
D. They are transmitted using digital signals.
SUBMIT
The gravitational field on the surface of the earth is stronger than that on the surface of the moon. If a rock is transported from the moon to the earth, which propertie of the rock change? a. mass only b. weight only c. both mass and weight d. neither mass nor weight
When a rock is transported from the moon to the earth, both mass and weight are changed.
Explanation:
The reason why both mass and weight are changed when a rock is transported from the moon to the earth is that the gravitational field on the surface of the earth is stronger than that on the surface of the moon.
This means that the rock's mass, which is the measure of the amount of matter that an object contains, will remain the same.
However, the rock's weight, which is the force with which an object is attracted to the earth due to gravity, will be different since the gravitational pull on the moon is much weaker than that on the earth. This implies that when the rock is transported from the moon to the earth, it will experience a higher gravitational force which will cause it to weigh more compared to when it was on the moon.
Therefore, both mass and weight will change when a rock is transported from the moon to the earth.
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Name:
9. A ball is thrown vertically in the air from rest and soars for 4.2 seconds.
If the acceleration due to gravity is 9.8 m/s², what is the final velocity
of the ball when it is caught?
The final velocity of the ball when it is caught is 20.58 m/s
What is velocity?Velocity is the rate of change of displacement.
To calculate the final velocity of the ball when it is caught, we use the formula below.
Formula:
v = u+gt............ Equation 1Where:
v = Final velocityu = Initial velocityg = Acceleration due to gravityt = TimeFrom the question,
Given:
u = 0 m/sg = 9.8 m/s²t = 4.2/2 = 2.1sSUbstitute these values into equation 1
v = 0+9.8×2.1v = 20.58 m/sHence, the final velocity of the ball when it is caught is 20.58 m/s
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PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was tripled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?
Answer:
The new force of attraction would be 36 units
Explanation:
Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
This statement can be expressed with the formula:
\(\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\)
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: \(6.67\cdot 10^{-11}~Nw*m^2/Kg^2\)
Now suppose two given objects attract with a force of F=16 units, thus:
\(\displaystyle G{\frac {m_{1}m_{2}}{r^{2}}}=16\)
And now the masses of both objects is tripled, i.e., m1'=3m1, m2'=3m2, and the distance between them is doubled, r'=2r. The new force is:
\(\displaystyle F'=G{\frac {3m_{1}3m_{2}}{(2r)^{2}}}\)
Operating:
\(\displaystyle F'=G{\frac {9m_{1}m_{2}}{4r^{2}}}\)
\(\displaystyle F'=\frac{9}{4}G{\frac {m_{1}m_{2}}{r^{2}}}\)
Substituting the value of the initial force:
\(\displaystyle F'=\frac{9}{4}\cdot 16\)
\(F'=36\ units\)
The new force of attraction would be 36 units
Einstein's theory of general relativity is currently the best explanation of gravity. what is likely to happen to this theory in the future?
a. it will remain the best explanation, because no one has come up with a better one yet.
b. it will remain the best explanation, because einstein's name is so well-known.
c. it will be replaced by a new theory if popular opinion changes.
d. it will be replaced by a new theory if enough evidence is collected.
Answer:
d. it will be replaced by a new theory if enough evidence is collected.
Explanation:
i think
if the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, what is the internal resistance of the battery?
If the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, the internal resistance of the battery can be calculated using Ohm's law. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The proportionality constant is called the resistance of the conductor, which is expressed mathematically as V = IR, where V is the voltage, I is the current, and R is the resistance.
The power dissipated by the internal resistance of a battery is given by P = I2R, where P is the power, I is the current, and R is the internal resistance. The rate of internal energy dissipation in the battery is given as 1.0 watt, and the current produced by the battery is given as 0.50 amps.
Using Ohm's law, we can calculate the voltage across the battery as V = IR = 0.50 x R. Therefore, the power dissipated by the internal resistance of the battery is P = I2R = (0.50)2 x R = 0.25R.
Equating the power dissipated by the internal resistance of the battery to the rate of internal energy dissipation, we get:
0.25R = 1.0
Solving for R, we get:
R = 1.0/0.25 = 4 ohms.
Therefore, the internal resistance of the battery is 4 ohms.
Internal energy dissipation is the energy that is lost due to friction or resistance in a system. In the case of a battery, internal energy dissipation refers to the energy that is lost due to the internal resistance of the battery. The internal resistance of a battery is a measure of how much energy is lost due to the resistance of the battery's internal components. The higher the internal resistance of the battery, the more energy is lost as heat, which reduces the battery's efficiency.
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Which of the following is a real-life example of a rotation?
a ceiling fan
a butterfly's wings
O going down a slide
opening a sliding glass patio door
None of the other answers are correct
Answer:
a ceiling fan a ceiling fan
A person throws a rock straight up into the air. At the moment it leaves the person's hand it is going 80 mph. When the rock reaches its peak, how fast is it going and what is the magnitude and direction of its acceleration? Ignore air drag. Express your answer using appropriate mks units.
a) The velocity at the peak is zero m/s
b) The direction of the acceleration of the motion is negative.
What is the acceleration?We should know that the acceleration would have to do with the change in the speed of a body and in the case of the question that we have here we are told that the object has been thrown straight up.
At the maximum height, the object would cease to move and as such the velocity of the object at at the peak of the motion would be seen to be zero. The acceleration in this case would be negative.
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A rolling rock with a velocity of 20 m/s has a momentum of 5000 kg m/s. What is the rock’s mass
Answer:
250 kgExplanation:
The mass of the rock can be found by using the formula
\(m = \frac{p}{v} \\ \)
p is the momentum
v is the velocity
From the question we have
\(m = \frac{5000}{20} = \frac{500}{2} = 250 \\ \)
We have the final answer as
250 kgHope this helps you
An engineering team has come to the stage in the engineering design process in which it is iterating to improve the solution. hat is one thing the team might be doing ?
When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:
Prototyping: This involves building a physical or digital prototype that can be tested and refined based on feedback from stakeholders. The team can then use this prototype to identify any design flaws and make the necessary changes.Simulation: Simulation involves creating a virtual model of the solution and testing it under various conditions. The team can use simulation to identify potential problems with the solution before it is built.User testing: User testing involves testing the solution with real users to get feedback on how well it works and how it can be improved. The team can use this feedback to make changes to the design and improve the user experience.Feedback analysis: This involves analyzing feedback from stakeholders, including users, customers, and other members of the team. The team can use this feedback to identify areas for improvement and make changes to the design.The key to iterating to improve the solution is to be open to feedback and willing to make changes. By continuously testing and refining the design, the engineering team can create a solution that meets the needs of stakeholders and achieves the desired outcomes.For such more question on stakeholders
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Swamp coolers are effective because _____.
A. the water is colder than the air.
B. the water pulls heat from the room to undergo a phase change.
C. the thermal energy of the water is decreasing.
D. the water's latent heat of vaporization is being pulled from the air.
Answer:
D. the water's latent heat of vaporization is being pulled from the air.
Explanation:
A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.
In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.
Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.
The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.
The swamp coolers are typically made up of the following essential components, these are;
1. Float.
2. Blower.
3. Pump.
4. Evaporative pad.
5. Water supply valve.
Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.
Answer:
B and D
Explanation:
List two things you should not do when encountering a funeral procession?
party and being happy..........
Question 25 of 30
Three circuit diagrams are shown. Which statement about the circuit
diagrams is accurate?
Circuit A
Circuit B
Circuit C
V
VE
VE
R
A. Circuit A is a series circuit, and circuits B and C are parallel
circuits
B. Circuits A and B are series circuits, and circuit C is a parallel
circuit
OC. Circuits A and C are series circuits, and circuit B is a parallel
circuit.
O D. Circuits A, B, and C are all series circuits.
Answer:
it's B. circuit a and b are series circuit while c is parallel
What are waveform conversion circuits? 2. Where are waveform conversion circuits typically used
Waveform conversion circuits, also known as signal conversion circuits, are electronic circuits designed to convert one form of an electrical waveform into another form. Waveform conversion circuits find application in a wide range of fields where the modification, conditioning, or transformation of electrical waveforms is necessary to achieve specific objectives.
These circuits modify the characteristics of an input signal to achieve a desired output waveform. The conversion can involve changing the amplitude, frequency, phase, or shape of the waveform.
Waveform conversion circuits are used in various applications where it is necessary to transform signals to match specific requirements. Here are some common areas where waveform conversion circuits are typically used:
Audio Processing: In audio applications, waveform conversion circuits are used to modify audio signals for various purposes. This includes amplifying, filtering, equalizing, or modulating audio waveforms to enhance sound quality, remove noise, or achieve specific audio effects.
Power Electronics: Waveform conversion circuits are extensively employed in power electronics systems for converting and conditioning electrical power. These circuits are used in devices such as inverters, converters, rectifiers, and voltage regulators to transform power waveforms, adjust voltage or current levels, and ensure efficient power transfer.
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A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/s velocity. The car uniformly accelerates to the velocity 35m/s in 20 seconds, the moves at a constant speed for 5 seconds. How long will it take for the car to catch up to the truck.
Answer:
At \(t = (70 / 3) \; {\rm s}\) (approximately \(23.3 \; {\rm s}\).)
Explanation:
Note that the acceleration of the car between \(t = 0\; {\rm s}\) and \(t = 20\; {\rm s}\) (\(\Delta t = 20\; {\rm s}\)) is constant. Initial velocity of the car was \(v_{0} = 0\; {\rm m\cdot s^{-1}}\), whereas \(v_{1} = 35\; {\rm m\cdot s^{-1}}\) at \(t = 20\; {\rm s}\!\). Hence, at \(t = 20\; {\rm s}\!\!\), this car would have travelled a distance of:
\(\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}\).
At \(t = 20\; {\rm s}\), the truck would have travelled a distance of \(x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}\).
In other words, at \(t = 20\; {\rm s}\), the truck was \(400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}\) ahead of the car. The velocity of the car is greater than that of the truck by \(35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}\). It would take another \((50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}\) before the car catches up with the truck.
Hence, the car would catch up with the truck at \(t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}\).
15. A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.00 s?
The answer is 0.389 kg but please show your work.
Let's look at relationship
\(\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}\)
\(\\ \rm\rightarrowtail T\propto \sqrt{m}\)
Hence
\(\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}\)
\(\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}\)
\(\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}\)
\(\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}\)
\(\\ \rm\rightarrowtail m_2=0.889\)
Hence
Mass needs to added =0.889-0.500=0.389kgAnswer
Mass needs to added =0.889-0.500=0.389kg
Explanation:
14. The average speed of a car was 60 m/s by the time it reached the finish line. The car moved in a straight line and traveled from the starting
line to the finish line in 8.0 sec. How far was the finish line?
The radius of the sun is 695,700 km and the mass of the sun is 2x1030 kg. What would the force of gravity be on a 60 kg person "standing" on the surface of the sun? What is the acceleration of gravity at the surface of the sun?
a) The gravitational force is 1.7 * 10^4 N.
b) The acceleration due to gravity is 277 m/s^2.
What is the gravitational force?We know that the gravitational force is the force of attraction that acts in the universe between any two masses that are close to each other. We can see that we have the following information;
Mass of the sun = 2 x 10^30 kg
Mass of the person = 60 kg
Radius of the sun = 695,700 km or 695,700000 m
Force of gravity = Gm1m2/r^2
G = gravitational constant
m1 = mass of the sun
m2 = mass of the person
r = radius of the sun
Hence;
F = 6.67 x 10^-11 * 2 x 10^30 * 60/( 695,700000)^2
F = 8 * 10^21 /4.8 * 10^17
F = 1.7 * 10^4 N
The acceleration due to gravity is gotten from;
g = Gm/r^2
g = 6.67 x 10^-11 * 2 x 10^30/( 695,700000)^2
g = 1.33 * 10^20/4.8 * 10^17
g = 277 m/s^2
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PLEASE HELP ME!!!! In your own words, what does Newton's first law mean to you?
Answer:
His first law states that unless it is forced to change its state through external force, every object will remain stationary or move in a straight line at a constant speed. It is usually taken as the definition of inertia.
Explanation:
From earth in which constellation might you find the planet saturn.
Answer:
the Virgo consentellation
Explanation:
The angular velocity of a flywheel obeys the equation ?z(t)=A+Bt2, where t is in seconds and A and B are constants having numerical values 2.30 (for A) and 1.60 (for B ).A) What is the angular acceleration of the wheel at t = 0.00?B) What is the angular acceleration of the wheel at t = 6.50s ?C) Through what angle does the flywheel turn during the first 1.50s ?D) What are the units of A if ? is in rad/s?E) What are the units of B if ? is in rad/s?
A) To find the angular acceleration at t = 0.00, we need to differentiate the equation ?z(t) = A + Bt^2 with respect to time (t):
?z(t) = A + Bt^2
Differentiating both sides with respect to t:
d?z(t)/dt = d(A + Bt^2)/dt
The derivative of A with respect to t is 0 since it is a constant. The derivative of Bt^2 with respect to t is 2Bt:
d?z(t)/dt = 2Bt
Plugging in t = 0.00 into the equation, we get:
Angular acceleration at t = 0.00: ?z(0.00) = 2B(0.00) = 0
Therefore, the angular acceleration of the wheel at t = 0.00 is 0.
B) To find the angular acceleration at t = 6.50s, we can use the same equation:
?z(t) = A + Bt^2
Differentiating both sides with respect to t:
d?z(t)/dt = d(A + Bt^2)/dt
The derivative of A with respect to t is 0 since it is a constant. The derivative of Bt^2 with respect to t is 2Bt:
d?z(t)/dt = 2Bt
Plugging in t = 6.50 into the equation, we get:
Angular acceleration at t = 6.50s: ?z(6.50) = 2B(6.50) = 2(1.60)(6.50) = 20.80 rad/s^2
Therefore, the angular acceleration of the wheel at t = 6.50s is 20.80 rad/s^2.
C) To find the angle through which the flywheel turns during the first 1.50s, we need to integrate the angular velocity equation over the time interval [0, 1.50]:
Δθ = ∫ ?z(t) dt (from 0 to 1.50)
Substituting ?z(t) = A + Bt^2:
Δθ = ∫ (A + Bt^2) dt (from 0 to 1.50)
Δθ = A*t + (B/3)*t^3 (from 0 to 1.50)
Plugging in the values A = 2.30 and B = 1.60:
Δθ = 2.30*t + (1.60/3)*t^3 (from 0 to 1.50)
Δθ = 2.30*(1.50) + (1.60/3)*(1.50)^3 - (2.30*(0) + (1.60/3)*(0)^3)
Δθ = 3.45 + (1.60/3)*(3.375) = 3.45 + 1.80 = 5.25 radians
Therefore, the flywheel turns through an angle of 5.25 radians during the first 1.50 seconds.
D) The units of A in the given equation ?z(t) = A + Bt^2 are in rad/s since it represents angular velocity. Therefore, the units of A are rad/s.
E) Similarly, the units of B in the given equation ?z(t) = A + Bt^2 are in rad/s/s^2 since it represents angular acceleration. Therefore, the units of B are rad/s/s^2.
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According to the Law of Reflection, a light ray strikes a mirror ________________________________.
moves into the mirror at a slightly different angle.
continues moving through the mirror in the same direction.
bounces off the mirror towards the direction it came from.
bounces off the mirror at the same angle it hits the solid surface.
Answer:
bounces off the mirror at the same angle it hits the solid surface.
Explanation:
According to the Law of Reflection, a light ray strikes a mirror at the point of incidence bounces off the mirror at the same angle it hits the solid surface.
The incident ray and the reflected ray lie in the same plane
The angle of incidence is equal to the angle of reflection as a ray of light reflects off a solid surface.
So,
correct answer is ''bounces off the mirror at the same angle it hits the solid surface.''
a rock stays in the same position without moving, which law is it ?
Answer:This is also known as the law of inertia. EXPLANATION: Inertia is the tendency of an object to remain at rest or remain in motion.
calcula el potencial electrico de un punto B que se encuentra a 75cm de una varga positica q=9×10-6c
Answer:
V = 72000 volts
Explanation:
calculates the electric potential of a point B that is 75cm from a positive charge q = 9 × 10-6c
Given that,
Electric charge, \(q=9\times 10^{-6}\ C\)
We need to find the electric potential of a point B that is 75 cm from this charge. The formula for the electric potential is given by :
\(V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6\times 10^{-6}}{0.75}\\\\V=72000\ V\)
So, the electric potential is equal to 72000 Volts.
WILL GIVE BRAINLIST a HELP PLEASE
pleaseeee
Answer:
Concave mirror
Explanation:
Because as we move the object far away from the mirror, the image gets inverted.
Answer:
Concave mirror
Explanation:
Cool air tends to...
A. Be less dense and flow over warm air.
B. Be lifted up by more dense warm air.
C. Be more dense and flow under warm air.
D. Mix easily with warm air masses.
Answer: C. Be more dense and flow under warm air.
Explanation:
think of a supermarket selling dairy products and when you open the fridge to get the milk, outside the supermarket is hot and inside the fridge is cold ice.
in moment of intertia equations, does the velocity need to take into account the weight of the connecting mass to the pivot?
In the moment of inertia equations, the velocity does not need to take into account the weight of the connecting mass to the pivot.
The moment of inertia of an object depends on its mass and also depends on the distribution of that mass relative to the axis of rotation (r).
I=mr²
Hence, in moment of inertia equations, the velocity and the weight of the connecting mass to the pivot do not need to take into account.
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