How do you work it out A, B & C lie on a straight line. D, B & E lie on a different straight line. ∠ CBE =62°. Work out the angle marked x .

Answer:

forgot how to do this

Step-by-step explanation:

150√374 283727273737272727272

The probability that the mean of a sample of 70 computers would differ from the population mean by less than 1.9 months is 0.1217.

In this problem, we have to find the probability that the mean of a sample of 70 computers would differ from the population mean by less than 1.9 months, given that the quality control manager believes that the mean life of a computer is 105 months, with a variance of 81.

To solve this problem, we can use the Central Limit Theorem, which states that the sample mean of a sufficiently large sample size, drawn from any population, will be approximately normally distributed with mean μ and variance σ²/n, where μ is the population mean, σ² is the population variance, and n is the sample size.

In this case, we know that the population mean is μ = 105 months and the population variance is σ² = 81. Since we are interested in the mean of a sample of 70 computers, we can use the formula for the standard error of the mean, which is σ/√n, to calculate the standard deviation of the sampling distribution of the mean.

The standard deviation of the sampling distribution of the mean is given by σ/√n = √(81/70) ≈ 1.226.

Now, we want to find the probability that the mean of a sample of 70 computers would differ from the population mean by less than 1.9 months. We can standardize this difference using the formula

z = (x' - μ)/(σ/√n), where x' is the sample mean.

Substituting the values, we get z = (x' - 105)/(1.226), and we want to find the probability that |z| < 1.9/1.226 ≈ 1.550.

Using a standard normal distribution table, we can find that the probability of |z| < 1.550 is approximately 0.1217.

Therefore, the probability that the mean of a sample of 70 computers would differ from the population mean by less than 1.9 months is 0.1217.

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Answer:

The answer is 7b+14.

Step-by-step explanation:

z-z +2b+5b + 18-4

The periodic solutions of the system are:

(0, 0),

(±√2, ±√2).

These points represent periodic orbits in the phase space of the system.

To determine the periodic solutions, if any, of the system:

ẋ = yx^p(x^2y^2 - 2),

ẏ = -xy^p(x^2y^2 - 2),

we need to find values of x and y for which the derivatives ẋ and ẏ are equal to zero simultaneously. These points represent potential periodic solutions.Setting ẋ = 0 and ẏ = 0, we have:

0 = yx^p(x^2y^2 - 2),

0 = -xy^p(x^2y^2 - 2).

From the first equation, we can see that either y = 0 or x^2y^2 - 2 = 0.

If y = 0, then the second equation implies that x = 0. Therefore, (0, 0) is a solution.

If x^2y^2 - 2 = 0, then x^2y^2 = 2.

Taking the square root of both sides, we get xy = ±√2.Considering the second equation, we have -xy^p(x^2y^2 - 2) = 0.

Substituting xy = ±√2, we find that this equation holds true.

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Answer:

The answer p= - 1/4 so C

Step-by-step explanation:

Answer:

p=-1/4

Step-by-step explanation:

Answer:

Explanation:

Let's refer to 1st the handle as A and the 2nd handle

Answer:  D. YZV

Step-by-step explanation:

D is the answer because it’s literally the same angle as XYW, but the line segments are on a larger scale. So for example, if they asked you to find the congruent angle of WXY, it’d be VXY for the same reason I just explained. This pretty much works for any two shapes, as long as they are exactly the same.

Hope this helps :D

Answer: 24.7

cos 54° = x/42

⇔ x = 42. cos 54°

⇔ x ≈ 24.7

Step-by-step explanation:

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

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Answer:

C. 48 m

Step-by-step explanation:

The two vertical sides add up to be (8*2) m = 16m.

The two horizontal sides can be added up to (14*2) m = 28m.

(The top horizontal side can be found by pushing the line in the middle up to the level of the other two portions of the same side.)

Finally, add the leftover two sides (2*2) m = 4m.

16+28+4 = 48.

Hope this helped!

Answer:

C-48

Step-by-step explanation:

hi , you need to fill in the blanks and then add them all together

The value that would complete the table to make the relationship between the two quantity proportional is 4.

When two quantities are proportional, their relationship is constant for all values and as one quantity rises, the other rises as well.

A proportional relationship exists between two quantities if they can be written in the general form y = kx, where k is the proportionality constant. In other words, the ratio between these amounts never changes. In other words, no matter which pair of the two numbers you divide, you always obtain the same number k.

The value that would complete the table to make the relationship between the two quantity proportional is 4.

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Answer: sorry i don't know the answer :(

Step-by-step explanation:

The best choice would be to use positive reinforcement techniques, such as clicker training or rewards, to encourage the cat to associate pulling the rope with a desirable outcome and reinforce the desired behavior.

To help the cat learn to pull a rope, the best technique to use would be positive reinforcement.

Positive reinforcement is a behavior modification technique that involves providing a reward or positive consequence immediately after the desired behavior occurs.

In this case, when the cat pulls the rope, it should be rewarded with something it finds valuable or enjoyable, such as a treat, praise, or playtime.

By associating the act of pulling the rope with a positive outcome, the cat is more likely to repeat the behavior in the future.

The low probability of the cat naturally pulling the rope indicates that the behavior needs to be trained and reinforced.

Positive reinforcement creates a positive association between the desired behavior and the reward, making it more likely for the cat to engage in the behavior voluntarily.

It is important to note that the rewards should be given consistently and immediately after the cat pulls the rope to reinforce the behavior effectively.

Gradually, the cat will learn to associate pulling the rope with the positive reinforcement and increase the likelihood of performing the behavior.

Using positive reinforcement not only helps the cat learn the desired behavior but also creates a positive and cooperative environment for training.

It encourages the cat to actively participate and engage in the training process, making it more effective and enjoyable for both the cat and the trainer.

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Answer:

Follows are the responses to this question:

Step-by-step explanation:

In this question, if both quadratic trinomials include opposite \(x^2\) terms of signs, it's indeed possible that's also possible, which is why the quadratic \(x^2+2x +1 \ and \ -x^2 + 4x -5\) cancels the  \(x^2 \ to\ 6x- 4\), which would be a linear binomial.  that's why this statement is true that the "two quadratic trinomials have \(x^2\) -terms in signs opposite".

The coefficients of the terms whose exponents are two, should be added to zero to get the linear binomial.

The general form of a quadratic equation is given as ax^2 + bx + c = 0.

Here, a ≠ 0 and b and c are integers.

The degree of a quadratic equation is 2.

Suppose the two quadratic trinomials are given as follows,

p(x) = a₁x² + b₁x + c₁

And, q(x) = a₂x² + b₂x + c₂.

The sum of these trinomials are given as,

p(x) + q(x) =  a₁x² + b₁x + c₁ + a₂x² + b₂x + c₂.

⇒ p(x) + q(x) = (a₁ + a₂)x² + (b₁ + b₂)x + (c₁ + c₂)

In order of the sum to be a linear binomial, the coefficient of x² should be zero.

Then, it can be written as,

a₁ + a₂ = 0

⇒ a₁ = -a₂

Hence, the required result can be obtained when the sum of the coefficients of x² is zero.

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Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

Answer:

9

Step-by-step explanation:

a) the population cannot be negative, the limiting population is 4300.

b)the population is increasing when 0 < p < 4300 and decreases when p > 4300.

c)the equilibrium solutions are p = 0 and p = 4300.

(a) To determine when the population is increasing or decreasing, we need to look at the sign of dp/dt.

\(\frac{dp}{dt} = 1.2p(1 - \frac{p}{4300})\)

For dp/dt to be positive (i.e. population is increasing),

we need\(1 - \frac{p}{4300} > 0, or \ p < 4300.\)

For dp/dt to be negative (i.e. population is decreasing),

we need\(1 - \frac{p}{4300} < 0, or p > 4300.\)

Therefore, the population is increasing when 0 < p < 4300 and decreases when p > 4300.

(b) To find the limiting population, we need to find the value of p as t approaches infinity.

As t approaches infinity,\(\frac{dp}{dt}\)approaches 0. Therefore, we can set \(\frac{dp}{dt}\) = 0 and solve for p.

0 = 1.2p(1 - p/4300)

Simplifying, we get:

0 = p(1 - p/4300)

So, either p = 0 or 1 - p/4300 = 0.

Solving for p, we get:

p = 0 or p = 4300.

Since the population cannot be negative, the limiting population is 4300.

(c) Equilibrium solutions occur when\(dp/dt = 0.\)We already found the equilibrium solutions in part (b): p = 0 and p = 4300.

Therefore, the equilibrium solutions are p = 0 and p = 4300.

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a)  The population is increasing when 0 < p < 4300, and  decreasing when p > 4300.

b)  The population cannot be negative, the limiting population is 4300.

c)  these are the equilibrium solutions.  At p = 0, the population is not

increasing or decreasing, and at p = 4300,  the population is decreasing

but not changing in size.

(a) To determine when the population is increasing or decreasing, we

need to find the sign of dp/dt. We have:

dp/dt = 1.2p(1 - p/4300)

This expression is positive when 1 - p/4300 > 0, i.e., when p < 4300, and

negative when 1 - p/4300 < 0, i.e., when p > 4300.

Therefore, the population is increasing when 0 < p < 4300, and

decreasing when p > 4300.

(b) To find the limiting population, we need to solve for p as t approaches infinity. To do this, we set dp/dt = 0 and solve for p:

1.2p(1 - p/4300) = 0

This equation has two solutions: p = 0 and p = 4300. Since the population cannot be negative, the limiting population is 4300.

(c) To find the equilibrium solutions, we need to solve for p when dp/dt = 0. We already found that the only solutions to dp/dt = 0 are p = 0 and

p = 4300.

Therefore, these are the equilibrium solutions.

At p = 0, the population is not increasing or decreasing, and at p = 4300,

the population is decreasing but not changing in size.

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Answer:

-47

Step-by-step explanation:

we insert the given values in the equation to calculate the required values

m(x) = 5² - 3

= 25 - 3

= 22

R(X) = 7x 9 + 6

= 69

Thus m (5) - r (9) = 22 - 69

= -47

Answer:

26⁰, 64⁰, 90⁰

Step-by-step explanation:

this is simple perhaps

90⁰+x⁰+(3x-14)=180⁰. (sum of angles in a triangle)

90⁰ + x+3x-14=180⁰

90⁰+4x-14=180⁰

4x + 76= 180⁰

4x= 180-76

4x=104

x=104/4

x=26

(3x-14)= 3(26) -14= 78 -14 = 64⁰

Answer:

26, 64, 90

Step-by-step explanation:

(3x-14) + 90 + x = 180

            -90          -90

_________________

(3x-14) + x = 90

Now, combine the like terms. 3x and x are like terms

4x -14 = 90

    +14   +14

____________

4x = 104

/4  =  /4

x = 26

Input 26 in the equation to find the angle. The place where there is a box, it signifies that this is a right angle triangle and so we automatically know  that area is 90 degrees.

Answer:

Every year, a pet food company sells its food to stores across the nation. ... In the first month of the new year, the Midwest region secured sales orders from ... Suppose the strategy of the pet food company is to increase the proportion of ... Do you think additional field training is necessary for all of the sales representatives?

Step-by-step explanation:

Answer:

9d

Step-by-step explanation:

(4+5)d

Answer:

9d

Step-by-step explanation:

Answer:

equilateral triangle ANP inscribed in circle C

regular hexagon AMNBPQ inscribed in circle C

Step-by-step explanation:

By looking through our choices, we can eliminate which choices could be wrong and which choices could be right.

Δ MNQ does form a triangle, however, it DOES NOT form a equilateral triangle.

Δ ANP does form a triangle and it is ALSO an equilateral triangle.

Hexagon AMNBPQ does form a hexagon and it is ALSO a regular polygon as we can see all the sides and angles within the polygon are congruent to one another.

MNPQ does form a quadrilateral, however, it DOES NOT form a square. It is instead a rectangle.

ANBQ does form a quadrilateral, however, it DOES NOT form a square. It is instead a rectangle.

By looking through our observations, we can conclude that Δ ANP and hexagon AMNBPQ are the correct choices.

- 2022 Edmentum

The equilateral triangle ANP inscribed in circle C  and the regular hexagon AMNBPQ inscribed in circle C. Then the correct options are B and C.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Brian set his compass equal to the radius of circle C and drew two circles centered at points A and B on circle C.

He labeled the points of intersection of the two circles as shown.

The equilateral triangle ANP inscribed in circle C  and the regular hexagon AMNBPQ inscribed in circle C.

Then the correct options are B and C.

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The given series, cos(na) 7/8ⁿ  n = 1 n a., diverges.

The given series is Σ(cos(na) × 7/8ⁿ) with n = 1 to infinity. To test for convergence or divergence, we can use the Ratio Test.

Let's examine the limit as n approaches infinity of the absolute value of the ratio between consecutive terms:

L = lim (n→∞) |((cos((n+1)a) × 7/8⁽ⁿ⁺¹⁾) / (cos(na) × 7/8ⁿ))|

This simplifies to:

L = lim (n→∞) (|cos(na) × 7/8ⁿ| / |cos((n+1)a) × 7/8⁽ⁿ⁺¹⁾|)

The 7/8 terms will cancel out:

L = lim (n→∞) (|cos(na)| / |cos((n+1)a)|) × (8/7)

Since the cosine function oscillates between -1 and 1, the limit does not exist, and we can't draw any conclusion about convergence or divergence using the Ratio Test.

However, note that the series is the product of the sequence cos(na) and the geometric sequence 7/8ⁿ. The geometric sequence converges (because its common ratio 7/8 is between -1 and 1), but cos(na) oscillates between -1 and 1. The product of these sequences does not converge to a single value, so the series diverges.

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Answer:

\(\frac{-x^{2}+5x-1}{2x^{2} -x-1}\)

Step-by-step explanation:

The provided function's definite integral from 0 to 10 is closest to 4.

The area of each zone that the function, the x-axis, and the two vertical lines at x = 0 and x = 10 bounds is added to form the definite integral of the function. The definite integral that results from adding up each of these areas is the one that is closest to 4. The area of the region above the x-axis is larger than the area of the region below the x-axis, which explains this. The area of the region above the x-axis is higher than the area below the x-axis because the function is rising across the interval. The overall area is closer to 4 since the area of the region below the x-axis is negative. As a result, 4 is the closest value for the definite integral of the 0–10 function.

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I need to see some picture or whatever the problem is

You can travel 11 kilometers per litre of petrol.

You can calculate the number of kilometers per litre by dividing the distance travelled by the amount of petrol used. In this case, you would divide 220km by 20Lt to get the number of kilometers per litre.

Here is the step-by-step calculation:

1. Distance travelled = 220km

2. Amount of petrol used = 20Lt

3. Kilometers per litre = Distance travelled / Amount of petrol used

4. Kilometers per litre = 220km / 20Lt

5. Kilometers per litre = 11km/Lt

Therefore, you can travel 11 kilometers per litre of petrol.

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Answer:

11

Step-by-step explanation:

6*6=36

-25+36=11