the relative velocity of two cars is 10 m/s what does it mean​

The impact speed of the mouse is 23.3 m/s as per the data given in the question.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

To solve for the impact speed, we can use the following equation:

\(v^2 = u^2 + 2as\)

Where:

v = impact speed,

u = initial speed (which is the horizontal speed of the owl),

a = acceleration due to gravity (9.8 m/\(s^2\)), and

s = vertical distance fallen (15.0 m).

Substituting the known values, we get:

\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)

\(v^2\) = 256 + 294

\(v^2\) = 550

v = sqrt(550 )

v = 23.3 m/s

Thus, the impact speed of the mouse is 23.3 m/s.

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The expression; R vector=A vector - B vector shows that R² = A² + B² - 2ABcosθ.

Start by expanding the square of R:

R² = (A - B)²

Use the difference of squares factorization to expand this:

R² = (A - B)(A + B)

Now distribute the terms on the right-hand side:

R² = A² + AB - AB - B²

Combine like terms on the right-hand side:

R² = A² + B² - 2AB

Finally, use the cosine rule to express the magnitude of R in terms of the magnitudes of A and B and the angle between them:

R² = A² + B² - 2ABcosθ

Therefore, it is shown that R² = A² + B² - 2ABcosθ.

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The angular deceleration of the ball is -0.42 rad/s².

Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.

We can use the formula for angular acceleration:

α = (ωf - ωi) / t

where

α is the angular acceleration

ωi is the initial angular velocity

ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)

t is the time it takes for the ball to come to a stop

To find the initial and final angular positions, we can use the formula:

θf - θi = ωi * t + (1/2) * α * t²

where

θi is the initial angular position (0 in this case)

θf is the final angular position (90 radians in this case)

Substtuting the given values, we have:

θf - θi = ωi * t + (1/2) * α * t²

90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²

Simplifying and solving for α, we get:

α = -0.42 rad/s²

Therefore, the angular deceleration of the ball is -0.42 rad/s².

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A 165 mh inductor was attached right after that. The frequency of the oscillation is f=7957.74 Hz.

Periodic or oscillatory motion is defined as a motion that repeats itself. A restoring force or torque causes the object in this motion to oscillate about its equilibrium position.

Oscillation is a revolving motion between two states or locations. The side-to-side swing of a pendulum or the up-and-down motion of a spring with a weight are two examples of periodic motions that repeat themselves in a regular cycle and are considered oscillations.

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Answer:

4 secs

Explanation:

The first step is to calculate the velocity

V= frequency × wavelength

= 500× 0.2

= 100

Therefore the time can be calculated as follows

= distance/velocity

= 400/100

= 4 secs

The correct answer is Self-critical.

Why is self-improvement?

Self-critical:

Self-critical causes them to always strive for self-improvement and never to see accomplishing a goal as good enough.

The characteristic of a turbulent person causes them to always strive for self-improvement and to never see accomplishing a goal as good enough is Self-critical.

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Answer:

15 cm

Explanation:

Hooke's law says force is proportional to change in length.

force = kΔx

There is a restoring force F when stretched to a length of 13 cm.

F = k (13 − 12)

F = k

When the restoring force is 3F:

3F = (F) (x − 12)

3 = x − 12

x = 15

500 miles/hr West

Because it has magnitude and direction

Answer:

a)  T_alcohol = 123.2ºC , b) T_alcohol = -67.2ºC  and c)  r_alcohol =√5,6 r_mercury  

Explanation:

We can solve this problem using the thermal expansion equation

            ΔV = β Vo ΔT

indicates that alcohol has a coefficient of expansion 5 times that of mercury

           β_alcohol = 5 β_mercury

the amount of alcohol used from a correct reading at zero degrees, let's substitute in the equation for alcohol

           ΔV = β_ alcohol ΔT

           ΔV = 5.6 β_mercury ΔT

we see that the expansion is 5 times the expansion of mercury

           T_alcohol = 5.6 T_mercury

           T_alcohol = 5.6 22

           T_alcohol = 123.2ºC

b) in the case of T = -12ºC

          T_alcohol = 5.6 (-12)

          T_alcohol = -67.2ºC

c) In this case we want the division to give the same value for the two thermometers

let's use the volume ratio

          V = A L

where A is the area of ​​the circle and L the length that the alcohol travels

We know that the volume of alcohol is 5.6 times the volume of mercury

        V_alcohol = 5.6 V_mercury

        A_alcohol V = 5.6 A_mercury L

        A_alcohol = 5.6 A_mercury

if the area of ​​a plum is A = π r², when substituting in this equation

         π r_alcohol² = 5.6 π r_mercury²

           r_alcohol =√5,6 r_mercury

the consequence the radius of the alcohol thermometer must be √5.6 times the radius of the Mercury thermometer; the correct answer is 2

Answer:

Row D ; 280 Nm

Explanation:

Workdone is the product of the force applied and the distance moved. This means :

Workdone = Force * distance

For each of rows A to D:

Row A :

Workdone = 20 N * 20m = 400 Nm

Row B :

Workdone = 40 N * 10m = 400 Nm

Row C :

Workdone = 50 N * 6m = 300 Nm

Row D :

Workdone = 70 N *4m = 280 Nm

From the result obtained above, the smallest amount of workdone on the trolley is given in Row D ; which is 280Nm

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Answer:

velocity is a hell of a drug treatment classes in the position you are offering to help you with your medical needs and your needs and your needs and your needs and your needs for the future and to be getting your son in a better place for the better of the richest of his family and his life in the world.

Explanation:

no exceptions

The equation for finding speed is given by v = (x₂ - x₁) / (t₂ - t₁), where x is the displacement and t is the corresponding interval. The speed of the walking dude remains constant at 2 m/s.

To find the speed of Walking Dude, using  v = (x₂ - x₁) / (t₂ - t₁), insert the values for x and t.

For t = 0 and 2 seconds, the displacement is x = 0 and 4 meters respectively. So,

v = (4 - 0) / (2 - 0) = 4 m/s

For t = 2 and 4 seconds, the displacement is x = 4 and 8 meters respectively. So,

v = (8 - 4) / (4 - 2) = 2 m/s

For t = 4 and 6 seconds, the displacement is x = 8 and 12 meters respectively. So,

v = (12 - 8) / (6 - 4) = 2 m/s

For t = 6 and 8 seconds, the displacement is x = 12 and 16 meters respectively. So,

v = (16 - 12) / (8 - 6) = 2 m/s

Thus, the speed of Walking Dude remains constant at 2 m/s during the entire time period.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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Explanation:

x-component:

Vx = Vcos(theta)

= (92.5 m)cos(32.0)

= 78.4 m

Answer:

-78.4

Explanation:

For acellus students

Answer:

B.-80.35 J

i dont know the calculation

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

Answer:

Explanation:

the lose and gain of electron makes the atom an ion it is a charged because it has different number of electron and proton the number of electron differs from the number of proton

250 BC by Aristarchus is the answer ot the question

Data supporting the theory of a round earth was collected as early as _____.

1570 AD by Galileo

1500 AD by Copernicus

250 BC by Aristarchus

1640 AD by Kepler

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Answer:

D. 60

Explanation:

Divide 300 miles by 5

Answer:

The velocity is  \(v  = 796 \  m/s \)

Explanation:

From the question we are told that

   The mass of the bullet is  \(m_b  =  5.00\  g =  0.005 \ g\)

   The mass of the hand gun is  \(m_g  =  1.00 \ kg\)

    The speed of the gun is  \(v_b  =  8.00 * 10^{2} \  m/s\)

Generally from the law of momentum conservation

     \(m_b *  u_b  +  m_g *  u_g  =  m_b*  v_b +  m_g *  - v_g\)

here \(u_g\  and \   u_b\) are zero given that before the bullet was shot the gun was at rest

\(v_g\) is negative given because from Newtons third law action and reaction is equal and opposite so if the bullet is moving forward the gun will be moving backward

So

   \( 0.005 *  0  +  1* 0=  0.005 * 8.00 * 10^{2}  -   1.00*  v_g\)      

=>  \( v_g  =  4 \  m/s \)    

Hence the velocity of the bullet with respect to the loose gun is  

     \(v  =  v_b  -  v_g\)

=>   \(v  =  8.00 * 10^{2}   - 4\)

=>   \(v  = 796 \  m/s \)

In a simple machine the direction changes by using the pulley. By applying the force on the pulley, by pushing down and the object moves up.

The simple machine allows to change the direction is a pulley. The pulley machine acts as a direction changer and is also used to change the direction of the force. When the wheel rotates, the cord can move in either direction.

The pulley has a wheel and hook. By attaching the hook to the cord, the wheel rotates making the object move up or down much easier when the force is applied to the pulley. These machines use pivot points to balance.

Hence, the simple machine called a pulley, is used to change the direction of force and makes the object moves up.

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S = displacement

V = final velocity

U = initial velocity

Answer:

pls find the attached image for solution

Answer:

The ball would be traveling fastest at point (C).

Point (D) appears to be the same height as point (C) but the ball would probably have lost some speed on rebounding,