Solve for indicated side. Round to the nearest hundredth.
Z=

From the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two systems of the equation:

y = log (−5.6x + 1.3)

y  = −1 − x

After plotting the above equation on the graph we will see two intersections point:

(-2.12, 1.12) and (0.221, -1.221)

So the least value is x = -2.12 ≈ -2.1

The greatest value is x = 0.221 ≈ 0.2

Thus, from the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

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Answer:

11 but specifically it is 11.428571

Answer: 11

Step-by-step explanation: 100 divided by 8 3/4

If you want specific answer it's 11.4285714286

Let g be the integral function defined by g(x) = ∫x-1 (-1/2 * cos (t³ / 2t)) dt for x = 0, g is g(x) = -1/2(x-1 * sin(t³/2t) - x-1 * cos(t³/2t)).

To solve this integral, we need to use the substitution method. We will let u = t/2t, du = 3t/2 dt.

Thus, the integral becomes:

g(x) = -1/2 * ∫x-1 cos(u) du

Using integration by parts, we get:

g(x) = -1/2(x-1 * sin(u) + ∫x-1 sin(u) du).

After integrating the second part, we obtain the final result:

g(x) = -1/2(x-1 * sin(u) - x-1 * cos(u))./2t

we subtitute the value of u to get:

g(x) = -1/2(x-1 * sin(t³/2t) - x-1 * cos(t³/2t)).

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Answer:

A = 12

Step-by-step explanation:

We can define ratio a to b as 12:3. If we are finding the value of A when B is 3, we go to the ratio. The ratio says that when B is 3, A is 12. Therefore, A is 12.

Answer:

A = 12

Explanation:

Given:

A ∝ B

set "k" constant

A = k(B)

Find "k"

12 = k(3)

k = 4

Then find A when B = 3

A = k(B)

insert values found

A = 4(3)

A = 12

Answer:

x2+2x−132x2+16

Step-by-step explanation:

First, let's simplify the expression by combining like terms:

x - 7x^2 + 8 - x^2 - x + 6x^2 + 8

= -7x^2 + 5x^2 - x^2 + x + 16

= -x^2 + 2x + 16

Now we need to factor the quadratic expression -x^2 + 2x + 16. We can use the quadratic formula or complete the square to find the roots, but it turns out that the expression doesn't factor nicely. However, we can rewrite it as -(x^2 - 2x - 16) and then use the quadratic formula to find the roots of the expression inside the parentheses:

x = (-(-2) ± sqrt((-2)^2 - 4(-16)))/(2(1))

x = (2 ± sqrt(68))/2

x = 1 ± 2sqrt(17)/2

x = 1 ± sqrt(17)

So we have:

-x^2 + 2x + 16 = -(x - (1 + sqrt(17)))(x - (1 - sqrt(17)))

Therefore, the expression is equal to -x^2 + 2x + 16, which corresponds to the option:

x^2 + 2x - 13 / 2x^2 + 16

Answer:

19.2 lbs of dog food in 5 weeks

Step-by-step explanation:

12 divided by 5 is 2.4

So that means each week the dog consumes 2.4 lbs of food each week.

If we want to see how much he eats in 8 weeks, we'd multiply 2.4 by 8, giving us 19.2

Answer:

allie saw 68 near sighted patients

sam saw 59 near sighted patients

Step-by-step explanation:

40% of 170 = 68

0.4 × 170 = 68

25% of 236 = 59

0.25 × 236 = 59

the distance between the chord is 23 cm

It is given that AB = 30cm and CD = 16cm

Join the lines OA and OC

We know that AO = 17cm and CO = 17cm

Construct OM ⊥ CD and OL ⊥ AB

The perpendicular from the centre of a circle to a chord bisects the chord

We know that

AL = ½ × AB

By substituting the values

AL = ½ × 30

So we get

AL = 15cm

We know that

CM = ½ × CD

By substituting the values

CM = ½ × 16

So we get

CM = 8cm

Consider △ ALO

Using the Pythagoras theorem it can be written as

AO^2 = OL^2 + AL^2

By substituting the values

17^2 = OL^2 + 15^2

So we get

OL^2 = 17^2 - 15^2

On further calculation

OL^2 = 289 – 225

By subtraction

OL^2 = 64

By taking the square root

OL = √64

OL = 8cm

Consider △ CMO

Using the Pythagoras theorem it can be written as

CO^2 = CM^2 + OM^2

By substituting the values

17^2 = 82 + OM^2

So we get

OM^2 = 17^2 - 8^2

On further calculation

OM^2 = 289 – 64

By subtraction

OM^2 = 225

By taking the square root

OM = √225

OM = 15cm

So the distance between the chords = OM + OL

By substituting the values

Distance between the chords = 8 + 15 = 23cm

Therefore, the distance between the chords is 23 cm.

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Answer:

the length of the square is (2x+3)

Step-by-step explanation:

hope it helps<333

Answer:

let length be b+5 and breadth be b

given,

perimeter of rectangle=150

or, 2(l+b) =150

or, 2(b+5+b)=150

or, 2b+5=150/2

or, 2b+5=75

or, 2b=70

therefore, b=35m

l=b+5

=35+5

=40m

The bar showing the spending for the chamber of commerce makes comparisons with the other groups more difficult.

The structured presentation is a well known visual device for showing information and making correlations between various classifications or gatherings. Nonetheless, certain elements of the information can utilize a visual chart less supportive for correlations. For this situation, the bar showing the spending for the office of trade makes correlations with different gatherings more troublesome on the grounds that it is altogether bigger than different bars, which can make it harder to analyze the general sizes of different bars precisely.

Furthermore, the information would preferable fit a flat rather over an upward show, as this would consider a more clear representation of the information and more precise correlations between the various classifications.

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Answer:

It will take them 7.89 days

The median is usually appropriate to use when summarizing data for distributions with skewed or asymmetric shapes.

The median is the value in the middle of a data set, meaning that 50% of data points have a value smaller or equal to the median and 50% of data points have a value higher or equal to the median.

These distributions include the positively skewed (right-skewed) distribution and the negatively skewed (left-skewed) distribution. In such cases, the median provides a more robust measure of central tendency than the mean, which may be influenced by extreme values in the tails of the distribution.

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Answer: 81,000

Step-by-step explanation:

We can solve this by using the formula given.

If f(1)=1000x3^1, then 1,000x3=3,000

If f(2)=1000x3^2, then 3^2=9 and 1000x9=9000,

and so on,

Now, f(4) will equal 1000x3^4, and 3^4 is 3x3x3x3, which is 9x9 or 9^2, which would be equal to 81, and 81x1000=81,000

To complete the table of values for the exponential function f(x) = 1000*3^x, we can evaluate the function for x = 0, 1, 2, 3, and 4, since we are interested in the number of bacteria on the phone after 4 hours.

x f(x)

0 1000

1 3000

2 9000

3 27,000

4 81,000

Therefore, after 4 hours, there will be 81,000 bacteria on the surface of the phone, assuming the number of bacteria triples every hour and can be described by the exponential function f(x) = 1000*3^x.

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Answer:

80

Step-by-step explanation:

8(3+7)=80

Answer:

(x+3)(x+4)

Step-by-step explanation:

Given:

→x² + 3x + 4x + 12​

Take common from x² + 3x and 4x + 12​

Now,

\(\hookrightarrow x(x+3)+4(x+3)\\\)

Here,

(x+3) can be written as one.

Then,

\(\hookrightarrow (x+3)(x+4)\\\)

And it is our answer.

Answer:

\(\displaystyle [x + 3][x + 4]\)

Explanation:

Find two quantities that when summed to 7, they also multiply to 12. Those will be 4 and 3. Sinse the entire expression is positive, the quantities STAY positive. Moreover, there is not much wourk to be done here BECAUSE the leading coefficient is one. This is all you can do:

\(\displaystyle x^2 + 7x + 12 \\ \\ \boxed{[x + 3][x + 4]}\)

I am joyous to assist you at any time.

Answer:

Yes, it is 24%

Step-by-step explanation:

For the first limit lim x→−2  x + 2x^³  + 8, the answer is -2.
For the second limit, the answer is -18.
For the third limit, the answer is does not exist.
For the fourth limit, the answer is 3.

For the first limit:

lim x→−2

x + 2x³ + 8

We can directly substitute x = -2 and get:

(-2) + 2(-2)³ + 8 = -2

Therefore, the limit is -2.

For the second limit:

lim h → 0

(−9 + h)² − 81h

Expanding the square and simplifying, we get:

((h²) - 18h)/h

Factoring out h, we get:

h(h - 18)/h

Canceling the h terms, we get:

h - 18

Substituting h = 0, we get:

-18

Therefore, the limit is -18.

For the third limit:

lim x → 4

x² − 4x + 3

x − 4

We can factor the numerator and cancel common factors with the denominator to get:

lim x → 4

(x - 1)(x - 3)

x - 4

Substituting x = 4 gives an indeterminate form of 0/0. We can factor the numerator further:

(x - 1)(x - 3) = (x - 4 + 3)(x - 4 + 1) = ((x - 4)^2 - 1)

So the limit becomes:

lim x → 4

((x - 4)² - 1)

x - 4

Canceling the (x - 4) terms, we get:

lim x → 4

(x - 4 + 1/x - 4)

Substituting x = 4 gives:

1/0

Therefore, the limit does not exist.

For the fourth limit:

lim x → 5

x² − 7x + 10

x − 5

We can factor the numerator and cancel common factors with the denominator to get:

lim x → 5

(x - 5)(x - 2)

x - 5

Canceling the (x - 5) terms, we get:

lim x → 5

x - 2

Substituting x = 5 gives:

3

Therefore, the limit is 3.

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Answer:

C. The set of prime numbers.

Thank you ☺️

The equilibrium tuition price is approximately $5,749.

The total social gain at the equilibrium price is approximately $37,275,050.

Consumer's surplus = $23,177,073

Producer's surplus ≈ $14,097,977

To find the equilibrium tuition price, we need to set the demand and supply equations equal to each other:

Demand: q = 20,000 - 2p

Supply: q = p - 3,000 + 0.9q

Setting them equal, we have:

20,000 - 2p = p - 3,000 + 0.9q

Simplifying the equation:

20,000 + 3,000 = 1.1q + 2p

23,000 = 1.1q + 2p

Since we are looking for the equilibrium, we know that the quantity demanded equals the quantity supplied. Therefore, q = q.

Setting the coefficients of p equal to each other:

2p = 1.1q

Simplifying:

p = 0.55q

Substituting this expression for p into the equation:

23,000 = 1.1q + 2(0.55q)

23,000 = 1.1q + 1.1q

23,000 = 2.2q

q = 23,000 / 2.2

q = 10,454

The equilibrium tuition price is given by p = 0.55q:

p = 0.55 * 10,454

p ≈ $5,749

Therefore, the equilibrium tuition price is approximately $5,749.

To find the total social gain at the equilibrium price, we need to calculate the consumer's surplus and the producer's surplus.

Consumer's surplus:

The consumer's surplus is the difference between the maximum price a consumer is willing to pay and the equilibrium price. In this case, the maximum price a consumer is willing to pay is the price at which the demand equation equals zero (q = 0). Substituting q = 0 into the demand equation:

0 = 20,000 - 2p

2p = 20,000

p = 10,000

Consumer's surplus = (1/2) * (10,000 - 5,749) * 10,454

Consumer's surplus = $23,177,073

Producer's surplus:

The producer's surplus is the difference between the equilibrium price and the minimum price at which a producer is willing to supply (q = 0). In this case, the minimum price at which the producer is willing to supply is $3,000.

Producer's surplus = (1/2) * (5,749 - 3,000) * 10,454

Producer's surplus ≈ $14,097,977

Total social gain = Consumer's surplus + Producer's surplus

Total social gain ≈ $23,177,073 + $14,097,977

Total social gain ≈ $37,275,050

Therefore, the total social gain at the equilibrium price is approximately $37,275,050.

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Answer:

least common multiple is 180

Leah may utilize gg, or the amount of gigabytes of data she can consume while keeping under her spending limit, by solving the equation 4g + 42= 48.80, where g has a value of 1.7.

She is known to pay a fixed fee of 42, therefore that number will serve as our constant. We may use 4g to symbolize the $4 per gigabyte utilized that she pays. 4g + 42 = 48.80 will be our equation.

To isolate g is what we want. We can do that by taking 42 off of both sides. The result is 4g = 6.8. Next, multiply each side by four. Thus, we have g = 1.7.

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Answer:

52b+43

Step-by-step explanation:

-7(10b+4)-3(-6b+ 5)

then -70b-28+18b-15

then -70b+18b-28-15

lastly 52b+43

Let's consider the function \(\(f(x) = x^2 + 2x - 1\)\). We will evaluate the given expressions and limits using this function:

1. \(\(f(-4)\): Substituting \(x = -4\) into \(f(x)\), we get: \(f(-4) = (-4)^2 + 2(-4) - 1 = 16 - 8 - 1 = 7\)\)

2. \(\(\lim_{{x \to 1-}} f(x)\): As \(x\) approaches 1 from the left side, we substitute \(x = 1\) into \(f(x)\):\)

  \(\(\lim_{{x \to 1-}} f(x) = f(1) = 1^2 + 2(1) - 1 = 2\)\)

3. \(\(\lim_{{x \to 1+}} f(x)\): As \(x\) approaches 1 from the right side, we substitute \(x = 1\) into \(f(x)\):\)

\(\(\lim_{{x \to 1+}} f(x) = f(1) = 1^2 + 2(1) - 1 = 2\)\)

4. \(\(\lim_{{x \to 1}} f(x)\): As \(x\) approaches 1, we substitute \(x = 1\) into \(f(x)\):\)

\(\(\lim_{{x \to 1}} f(x) = f(1) = 1^2 + 2(1) - 1 = 2\)\)

5. \(\(f(1)\): Substituting \(x = 1\) into \(f(x)\), we get: \(f(1) = 1^2 + 2(1) - 1 = 2\)\)

6. \(\(\lim_{{x \to 6-}} f(x)\): As \(x\) approaches 6 from the left side, we substitute \(x = 6\) into \(f(x)\):\)

\(\(\lim_{{x \to 6-}} f(x) = f(6) = 6^2 + 2(6) - 1 = 47\)\)

7. \(\(\lim_{{x \to 6+}} f(x)\): As \(x\) approaches 6 from the right side, we substitute \(x = 6\) into \(f(x)\):\)

 \(\(\lim_{{x \to 6+}} f(x) = f(6) = 6^2 + 2(6) - 1 = 47\)\)

By solving these expressions and limits using the function \(\(f(x) = x^2 + 2x - 1\),\) we have obtained the corresponding values.

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The value of probability P(A) and P(B) and P(C) is 2/5 and 9/10 and 1/6.

According to the statement

we have given that the an urn contains five balls labeled 1 through 5. And   Three balls are removed from the urn one by one randomly.

And we have to find that the probability of the given conditions.

So, For this purpose, we know that the

On the first given condition

A. Since there is no information on the first draw, this probability simply equals:

P(A)=2/5

Alternatively, you could distinguish between drawing a 4 or 5 in the first turn or not. We can then calculate P(A) as:

P(A) = 2/5*1/4+3/5*2/4

P(A) = 8/20

P(A) = 2/5.

And on the second given condition:

B. The probability of drawing 1 or 2 or both is 1 minus the probability of drawing none:

P(B) = 1−3/5*2/4*1/3

P(B) = 1−1/10

P(B) = 9/10

And the third given condition is :

C. There are (5/3)=10 ways to choose the three numbers, and only one correct way to draw them.

We thus find:

P(C) = (5/3)/5*4*3

P(C) = 10/60

P(C) = 1/6

So, The value of probability P(A) and P(B) and P(C) is 2/5 and 9/10 and 1/6.

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Question:

An urn contains five balls labeled 1 through 5. Three balls are removed from the urn one by one randomly, and their numbers recorded in order. No balls are put back in the urn. Assume that all outcomes of the experiment are equally likely.

(i) Let A be the event that the second ball drawn is ball 4 or 5. Find P(A).

(ii) Let B be the event that the sample of three balls contains ball 1 or ball 2 or both. Find P(B).

(iii) Let C be the event that the three recorded numbers come in increasing order. Find  P(C).

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Answer:

B

Step-by-step explanation:

If the numerator is one, the denominator is going to be the same value as a normal positve interger.

Answer:

A

Step-by-step explanation:

If z = 10, y = 9, and x = 8, it would fit the fact that z > y and y > x.

If we divide 1 by the variables, then it would be 1/10, 1/9, and 1/8. Imagine this as a pie. 1/8 would be the biggest slice then because it is cut into less pieces. 1/9 would be the second biggest slice because it is cut into less pieces than 1/10. Therefore, A is the correct answer.

I hope this helps and please mark this as brainliest!

Okay, here we have this:

Considering the provided graph we are going to identify the requested vertex and decide whether it is a maximum point or a minimum , so we obtain the following:

Let us remember that the lowest or highest point is the vertex of the parabola. In this case we can see that the highest point is (-1, 9). So the vertex is (-1, 9), and since it is the highest, then it will be a maximum.

In the image you can see the vertex drawn in blue.