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Answer:

Below

Explanation:

Blue ( 6)   OR  green ( 4)   is 10 out of  ( 6 + 5 + 5 + 4)

10 / 20 = 1/2 chance of blue OR green

Answer: the time for the car to drive directly south is determined as 7.15 s.

Explanation:

The time for the car to drive directly south is determined by applying the concept of slope.

slope = Δy/Δx

a = Δv/Δt

Δt = Δv/a

Δt = (26.8)/(3.75)

Δt = 7.15 s

Thus, the time for the car to drive directly south is determined as 7.15 s.

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

\(KE = \frac{1}{2}mv^2\)

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

\(U_s = \frac{1}{2}kx^2\)

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

\(E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2\)

We can simplify and solve for 'x'.

\(mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}\)

Plug in the givens and solve.

\(x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}\)

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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Answer:

we don't have that's bevause in our english physics and I have some ego problems and we are going out with a family emergency so no worries if we can fix the phone on your phone at a reasonable time please send.

Explanation:

it's a bit of an issue with my life insurance and the insurance is going out for a day in the world school fees of my life.I and I have to pay for my whole entire month for my whole entire month but will not have any further to do you have the money in my account so I need for the rest in the world school to get broken down on my side of my life.I and the rest in the world school and the school physics will talk about the future of my life.I and I don't want you don't.

There are  44180640 seconds in 1.40 year .

365 or 366 days, divided into 12 months or 52 weeks, make up the time from 1 January to 31 December, or a year.

1 year equals to 365.25 days

1.40 years equal to (1.40 × 365.25 days)

= 511.35 days.

1 day equals to 24 hours.

1 hour equals to 60 minute.

1 day equals to (24 × 60 × 60) second = 86400 seconds.

511.35 days equals to (511.35 ×  86400 seconds) = 44180640 seconds

So, 1.40 years equal to 44180640 seconds.

Hence, There are  44180640 seconds in 1.40yr .

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Answer: The answer is a because that's where it would be after it bounced

Answer: Liquid 2, if it's 3 g/mL and liquid 2 has 6gs and 2 mLs than it's 3g/mL

Answer:

9

Explanation:

d/dx (x² - x + 3)

= 2x - 1

when x = 5,

2x-1

= 2(5) - 1

= 10 - 1

= 9

Answer:

1.4 m/s2

Explanation:

i took the test

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

Volume of metal piece = 0.0069 m³ (Approx.)

Explanation:

Given:

Weight of metal in air = 300 N  

Weight of metal in water = 232.5 N

Find:

Volume of metal piece

Specific gravity of metal

Computation:

We know that;

Density of water = 1,000 kg/m³

Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water

Buoyant force applied on metal piece = 300 N - 232.5 N

Buoyant force applied on metal piece = 67.5 N

Buoyant force = Volume of metal x Density of water x Gravitational force

67.5 = Volume of metal x 1,000 x 9.8

Volume of metal piece = 0.0069 m³ (Approx.)

Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.

Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:

Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.

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Answer:

Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.

Explanation:

180° or π Radians is the smallest phase difference possible When two coherent waves combine destructively to create a minimum

Two waves of the same wavelength that are entirely out of phase with one another might cancel one another out or interact negatively. When there is a 180 degree or larger radian phase difference, this happens. Only when the two waves have the same amplitude do they completely cancel out. Partially destructive superposition occurs when two waves that are entirely out of phase yet have different amplitudes. The intensity is 0.

Superposition is the phenomenon in which the combined displacement of two combining waves is equal to their vector sum.

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

In explanation

Explanation:

DIFFUSION:

The movement of particles from a region where they are in higher concentration to a region where they are in lower concentration until the equilibrium is achieved is known as the process of "Diffusion". It occurs in all three states of matter, that is solid, liquid and gas.

OSMOSIS:

When the particles of a solvent move from a region of higher concentration to a region of lower concentration through a semi-permeable membrane until the concentration of the solution is balanced, is known as "Osmosis". It occurs in liquids only.

A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

The torque in a uniform desk of diameter 30.5 cm and mass 0.270kg will be 2.076 × 10⁻³ Nm.

Torque can be defined as the rotational equivalent of the linear force. Torque is also referred to as the moment of any force. Torque represents the capability of a force to produce change in the rotational motion of the object.

I = mR²/ 2

As we already know, kinematics equation is:

ωf² = ωi² + 2αΔQ

Therefore, α = (ωf² - ωi²)/ 2ΔQ

Here, ωf = 3.49 rad/s, d = 30.5 cm

ωi = 0, m = 0.270kg

d = 30.5 cm

R = d/2 = 30.5/ 2 = 15.25cm

R = 15.25 × 10⁻² meters

τ = Iα

τ = [(0.270 × (0.1525)²]/2 × [(3.49)² - (0)²/ 2×1.40×2π]

τ = 0.003 × 0.692

τ = 0.002076 Nm

Therefore, the torque will be 2.076 × 10⁻³ Nm.

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The torque that is produced at the center of the drum is 50 Nm.

The term torque has to do with a force that leads to a turning effect. I can use the example of a tap to show you what is meant by a torque. The force that is exerted on a tap causes the tap to turn and this is what we mean by saying that a torque would produce a turning effect.

We have the following;

Force = 250 N

Distance = 20 cm or 0.2 m

Torque = 250 N  *  0.2 m

= 50 Nm

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Answer:

Explanation:

From the information given,

V = 4 volts

A = 2 amps

a)

In the first instance, one light on the sting goes out and the whole string of lights no longer turns on. This means that the circuit is a series circuit.

b) Total voltage = 4 x 100 = 400 V

The current passing through each bulb is the same. Thus

Total Current = 2 Amps

Recall, V = IR

R = V/I

Thus,

Resistance = 400/2

Resistance = 200 ohms

c) In this case, one light goes out on the string all other lights still turn on. This means that the circuit is a parallel circuit

d)

The voltage is the same

Total voltage = 4 volts

Total current = 2 x 100 = 200 amps

Total resistance = 4/200

Total resistance = 0.02 ohms

Given our understanding of the situation, for this vehicle with four wheels is traveling in a linear path through soft dirt, we would expect for only two wheels to leave tire track impressions.

The vehicle has four wheels, and one might think initially that it makes sense for all four wheels to create tire track impressions on the dirt. This assessment is correct, all four tires will create impressions, However, not all four tires will leave a said impression.

This is due to the fact that as the vehicle advances, the tires in the back will erase the impressions left by the front tires. Therefore, only two tire track impressions will be left.

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Answer:

309.02g

Explanation:

According to the information given in this question, the cylinder has the following:

Mass = ?

Length/height = 10.55cm

Diameter = 4.00cm

Volume of a cylinder = πr²h

Where; π = pie (3.142 or 22/7)

r = radius (cm)

h = height

Note that, radius = diameter/2

Hence, radius (r) = 4.00/2

r = 2.00cm.

V = πr²h

V = 22/7 × 2² × 10.55

V = 22/7 × 42.2

V = 928.4/7

V = 132.628cm³

Density = mass/volume

Hence, mass = density × volume

Where density of silicon is 2.33g/cm³

Mass = 2.33g/cm³ × 132.628cm³

Mass = 309.02g

A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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The average velocity of the car over the first second is -50 m/s.

The first option is correct.

Average velocity is the ratio of the displacement to the time interval.

The formula to calculate the average velocity is as follows;

where;

Displacement is the change in distance or position in a specified direction.

That is the difference between the final and initial distances.

Considering the graph of the automobile brake test given in the attachment;

displacement over the first second = 50 - 100 m

displacement over the first second = -50 ms

Average velocity = -50 m/ 1 s

Average velocity = -50 m/s

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The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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