rue/false: the glass transition temperature is always above the melting temperature of an amorphous material.

For  question B, 2. the reaction is delayed until just before the balloon pops

For question  C, 1.the reaction can start right away

Based on the fact that the hydrogen-only swell contains immaculate hydrogen gas, whereas the blended swell contains both hydrogen and oxygen gasses.

When the fire is added, the hydrogen in both inflatables will burn, but within the hydrogen-only balloon, the response will take longer to reach unstable levels since there's no oxygen display to respond with the hydrogen.

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Answer:

8.1×10^-8 mols-1

Explanation:

Now we have the mass of copper sulphate produced after three days. Recall that the rate of reaction is given as;

Rate= change in the concentration of product/time

At the beginning of the reaction, there was 0 moles of copper sulphate

After 72 hours or 259200 seconds, there was 3.4g/160gmol-1 = 0.021 moles of copper sulphate.

Note that 160gmol-1 is the molar mass of copper sulphate.

Hence;

Rate of reaction= 0.021 moles /259200 seconds

Hence, the rate of reaction is 8.1×10^-8 mols-1

Rate of reaction= 8.1×10^-8 mols-1

The value of ΔH for the reaction CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g) is -1272 kJ.

To calculate the enthalpy change (ΔH) for the given reaction, we can use Hess's law, which states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of the individual reactions involved.

Given the enthalpy changes:

1. 2 C(s) + O₂(g) → 2 CO(g)... ∆H = -222 kJ

2. C(s) + O₂(g) → CO₂(g)... ∆H = -394 kJ

3. 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

We need to manipulate these reactions to obtain the desired reaction:

1. Reverse reaction 2: CO₂(g) → C(s) + O₂(g)... ∆H = +394 kJ

2. Multiply reaction 2 by 2 to balance carbon atoms: 2 CO₂(g) → 2 C(s) + 2 O₂(g)... ∆H = -788 kJ

3. Leave reaction 3 unchanged: 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

By adding reactions 2 and 3, we obtain the desired reaction:

CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g)... ∆H = -788 kJ + (-484 kJ) = -1272 kJ

Therefore, the value of ΔH for the given reaction is -1272 kJ.

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Answer:

Caffeine, lead, Copper(ii) chloride, Sodium chloride, silver and tungsten

The partial pressure of helium in the tank is 1700torr.

First, let's calculate the partial pressure of oxygen (O2) and nitrogen (N2) in the tank:

Partial pressure of O2 = (Percentage of O2/100) * Total pressure
Partial pressure of O2 = (1300torr/7000torr) * 7000torr
Partial pressure of O2 = 1300torr

Partial pressure of N2 = (Percentage of N2/100) * Total pressure
Partial pressure of N2 = (4000torr/7000torr) * 7000torr
Partial pressure of N2 = 4000torr

Now, we can find the partial pressure of helium by subtracting the partial pressures of O2 and N2 from the total pressure:

Partial pressure of He = Total pressure - Partial pressure of O2 - Partial pressure of N2
Partial pressure of He = 7000torr - 1300torr - 4000torr
Partial pressure of He = 1700torr

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The mass % of the solution if the density of the solution is 1.06 g/ml is 10.51%

The mass of NaI = 99.7 g

Volume of the solution = 895 ml

Density of the solution = 1.06 g/ml

To calculate the mass % of the solution, we have to calculate the mass of the solution first.

Step-by-step explanation:

The formula for density is given by:

Density = Mass/Volume

Or,

Mass = Density × Volume

Now, we will calculate the mass of the solution.

Mass = Density × Volume

        = 1.06 × 895= 948.7 g

Now, we will calculate the mass % of the solution.

Mass % = (Mass of solute/Total mass of solution) × 100

Mass of solute = 99.7 g

Total mass of solution = 948.7 g

Mass % = (99.7/948.7) × 100

             = 10.51%

Therefore, the mass % of the solution is 10.51%.

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Answer:

a

Explanation:

Answer:

Explanation:

Example for Endothermic include melting ice cubes, cooking eggs, or baking breads.

Example for Exothermic include Burning candles, lighting match, or hot packs

Wegener suggested that the deserts of Africa were once covered in ice and that the striations were formed by the movement of the ice across the desert floor.

Glacier striations are grooves or scratches in the bedrock that have been created by a glacier sliding over the surface. They are typically found in areas where the ice has melted away, revealing the bedrock beneath.

Wegener suggested that the deserts were once wetter and lusher. He proposed that the climate has gradually changed over time, making the deserts arider. This is supported by evidence of ancient riverbeds and lakes in the Sahara Desert.

Glacier striations can be used to help researchers learn about the history of a particular glacier and the climate in the area where it is located. For example, the direction of the striations can indicate the direction the glacier was moving and the depth of the striations can give clues about how deep the glacier was.

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Answer:Yes. Adding or losing neutrons will change the atomic mass without forming a different element.

Explanation: Brainly

Answer:

1 mole H2O has 6.02 × 10^23 molecules

Explanation:

Answer: A catalyst is a substance that speeds up the rate of a chemical reaction without being used up and remains chemically unchanged itself .

Explanation: For a reaction to take place the particles must collide with enough energy for bonds to break and reaction to occur .

BUT when a catalyst is present the reactants are able to react in a way that requires less energy ,leading to more successful collision so the reaction speeds up without the chemical composition of the catalyst being affected

NOTE: the catalyst must be chosen to suit the particular reaction

HOPE THIS HELPS IF YOU NEED MORE EXAMPLES FEEL FREE TO COMMENT IN THE COMMENT SECTION

Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J

Answer:When you immerse an ionic compound in water, the ions are attracted to the water molecules, each of which carries a polar charge. If the attraction between the ions and the water molecules is great enough to break the bonds holding the ions together, the compound dissolves.

Explanation:

I apologize, but without any specific cleaning and disinfection guidelines mentioned, it is impossible to determine if any statement is true or false.

It is important to refer to reliable sources and follow appropriate cleaning and disinfection protocols for different types of brushes, including fan brushes. Generally, fan brushes can be cleaned with mild soap and water, and disinfected with a solution of 70% alcohol or a disinfectant spray. It is important to thoroughly rinse and air-dry the brushes after cleaning and disinfection to prevent any residue from affecting the quality of the brush or causing skin irritation.

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Answer:

\( \boxed{\sf \lambda \: = 1.282 \times {10}^{ 3} nm}\)

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

\( \frac{1}{ \lambda} = R_H {Z}^{2} \big(\frac{1}{{n_f^2}} - \frac{1}{{n_i^2}} \big)\)

Where,

109690 Cm-¹ in Puri Sharma Pathania standard book of physical chemistry &

109737 Cm-¹ according to Wikipedia

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

\( \frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{3^2}} - \frac{1}{{5^2}} \big)\)

\( \frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{9}} - \frac{1}{{25}} \big)\)

\( \frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{25 - 9}{25 \times 9} \)

\(\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{16}{225} \)

\( \frac{1}{ \lambda} = 7800.18 \: \: cm ^{ - 1} \)

\( \lambda = 1.282 \times {10}^{ - 4} cm\)

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

\( \lambda \: = 1.282 \times {10}^{ - 4} \times {10}^{7} \)

\(\lambda \: = 1.282 \times {10}^{ - 4 + 7} \)

\( \sf \lambda \: = 1.282 \times {10}^{ 3} nm\)

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The law of conservation of  mass is obeyed by a balanced chemical equation. The number of moles of KCl produced from 4K is 4KCl.

An equation in which the amount of the reactants and products on both sides of the reaction are equal is defined as the balanced chemical equation. In a balanced equation the number of atoms of each element is same on both sides.

According to the law of conservation of mass, mass can neither be created nor be destroyed. All the balanced chemical equation satisfies this law.

Here when 4K is used the amount of KCl produced is given as:

4K + 2Cl₂ → 4KCl

Here there are 4 'K' atoms and 4 'Cl' atoms. Hence the number of the respective atoms are equal on both sides of the equation.

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To prepare 2-butanol using a carbonyl compound and a Grignard reagent, you could use acetone as the carbonyl compound and 2-bromobutane as the Grignard reagent. The reaction between acetone and 2-bromobutane in the presence of a strong base, such as lithium diisopropylamide (LDA), would yield 2-butanol as the main product.

2-Butanol, also known as sec-butyl alcohol, is a secondary alcohol with the chemical formula C4H10O. It is a clear, colorless liquid with a slightly pungent, fruity odor. It is used as a solvent, a fuel additive, and in the production of chemicals such as butyl acetates, glycol ethers, and alkyd resins. It is also found in small amounts in some fruits and fermented foods. 2-Butanol is not as toxic as primary alcohols like methanol or ethanol, it is still considered a poison if ingested or inhaled in large amounts.

Thus, to prepare 2-butanol, acetone as the carbonyl compound and 2-bromobutane as the Grignard reagent could be used.

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What is the subscript charge?

Answer:

Lose 3

Explanation:

Aluminum has a full outer shall, ergo, when it forms an ion it can only lose.

Based on the tabulated data, compound B represents B) a metallic compound. Hence, option B) a metallic compound is the correct answer.

Characteristics of metals are:

Because electrons are mobile in metallic solids , they are good conductors of heat and electricity. Metallic solids are also malleable and ductile due to the ability of the metal nuclei to move past each other without disrupting the bonding.

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Answer:an ionic compound

Explanation:

The molar mass of FeCl3 is 162.2 g/mol.

To find the molar mass of FeCl3 (iron(III) chloride), you need to determine the atomic masses of the elements in the compound and add them up according to the number of atoms of each element in the formula.

The molar mass is expressed in grams per mole (g/mol).

The atomic masses of the elements in FeCl3 are:

Iron (Fe) = 55.85 g/mol

Chlorine (Cl) = 35.45 g/mol (the atomic mass of chlorine is based on its most abundant isotope, which has a mass number of 35)

The formula for iron(III) chloride is FeCl3, which indicates that there is one atom of iron and three atoms of chlorine in each molecule of the compound. Therefore, to calculate the molar mass of FeCl3, you can add up the atomic masses of one iron atom and three chlorine atoms:

Molar mass of FeCl3 = (1 x 55.85 g/mol) + (3 x 35.45 g/mol)

= 162.2 g/mol

Therefore, the molar mass of FeCl3 is 162.2 g/mol.

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The cleavage yields a carbonyl cation or "acylium" ion, which has a high abundance because it is resonance stabilized.

The ion that is formed as a result of alpha-fragmentation in a ketone or aldehyde mass spectrum is called the acylium ion. This ion is stabilized by resonance, which is why it is typically observed as the base peak in the mass spectrum. The acylium ion is a cationic species that contains a positive charge on the carbonyl carbon and a lone pair of electrons on the oxygen atom. This charge distribution allows for resonance stabilization, as the positive charge can be delocalized across the carbonyl carbon and the adjacent carbon atom. The acylium ion is also a reactive intermediate that can undergo further fragmentation or reactions with other molecules. Overall, the observation of the acylium ion as the base peak in a ketone or aldehyde mass spectrum provides valuable information about the structure and stability of these compounds.

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According to the question the maximum amount of phosphate remaining in solution is 5.6016 mol.

Phosphate is an inorganic chemical compound that contains phosphorus, oxygen and other elements. It is a key component of DNA and RNA, and serves as an important energy source for cells and organisms.

To calculate the maximum amount of phosphate remaining in solution, we need to first determine the amount of barium iodide needed to reach the desired concentration of barium ion.
Using the equation:
Concentration of Barium Ion = Amount of Barium Iodide/Volume of Solution
We can calculate that the amount of barium iodide required is 0.0576 mol.
Next, we need to calculate the amount of phosphate that is consumed when the barium iodide is added. According to the solubility product of barium phosphate, the amount of phosphate that is consumed is equal to the amount of barium iodide added, 0.0576 mol.

Therefore, the maximum amount of phosphate remaining in solution is
125 ml x 0.0463 mol/L - 0.0576 mol
= 5.6016 mol.

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The spectator ions of when k2s and mgcl2 are combined are 1. Cl- (aq) and 2. K (aq)

the balance equation of MgCl2 and  K2S is as follows:

MgCl2(aq) + K2S(aq) ------> MgS(s) + 2KCl(aq)

the net ionic equation is as follows:

Mg 2+ (aq) + 2 Cl- (aq) + 2K (aq) + S 2- (aq) = MgS(s) +2 Cl- (aq) + 2K (aq)

The overall reaction is as follows:

Mg 2+ (aq) + S 2- (aq) = MgS(s)

Thus the spectator ions are the following:

Cl- (aq)

K (aq)

If we compare the solutions before and after the reaction, sodium and nitrate ions are present in both the solutions. They do not undergo any chemical exchange at all. These ions are called spectator ions since they don't participate in the chemical reaction at all (they simply "watch").

Compare the reactant and product sides of the rewritten reaction and cross out the spectator ions. Any dissolved ions that appear in the same form on both sides are spectator ions.

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Multivalent ions are located in the right hand side of periodic table in a zig-zag order.

Multivalent ions are defined as the elements with more than one stable ion. Generally, Ionic compounds containing multivalent elements must have Roman numerals in their names in order to indicate which ions is forming that compound. Basically, the roman numeral is written in brackets after the element to indicate the charge

The Five Multivalent Metals present in the modern periodic table are copper. Cu 1+ copper(I) Cu 2+ copper(II) iron. Fe 2+ iron(II) Fe 3+ iron(III) mercury. Hg2 2+ mercury(I) Hg 2+ mercury(II) lead. Pb 2+ lead(II) Pb 4+ lead(IV) tin. Sn 2+ tin(II) sn 4+ tin(IV).

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Answer:

Yeah

Explanation:

Propylene glycol can be dehydrated to propionaldehyde which can in turn be reductively aminated to propylamine.

Propionaldehyde can be converted to n-propyl amine in two steps.

Conversion of propionaldehyde to oxime

Propionaldehyde is treated with hydroxyl amine in weakly acidic medium to form imine product known as propionaldoxime.

CH₃CH₂CHO+NH₂OH->CH₃CH₂CH=N-OH+H₂O

Reduction of imine to form amine

In this step,propionaldoxime is reduced by proper reducing agent like Na in ethanol to form n-propyl amine.

CH₃CH₂CH=NO-Na-C₂H5OH-> CH₃CH₂CH₂NH₂

Answer:

Matter

Explanation:

Solids, liquids, and gases are the three types of matter that can be found in the world around us today. In solids, all of the particles are close together. They move more in liquids, but they are spread out in gas.

Answer:

1. Solid

2. atom

3. faster and farther apart

4.more freely moving than a solid

5.The amount of matte in an object

Explanation:

Answer:

1. Solid

2. Atom

3. Faster and farther apart

4. More freely moving than a solid

5. The amount of matter in an object.

Answer:

The reference point is the ground.

Explanation:

•Moves slow that you don't notice hope this helps you :) god loves you :)

To get the number of neutrons use the formula i.e. No. of neutrons=mass number-atomic number. Therefore , 28–14 = 14neutrons.

Silicon-28 atom is the stable isotope of silicon with relative atomic mass 27.9769265.

By multiplying the proton and neutron counts of the exact isotope that interests you, you may always find the relative mass of an element. For instance, an atom of carbon-12 has a relative atomic mass of 12 due to its composition of 6 protons and 6 neutrons.

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