please help and explain how to solve You measure 34 dogs'weights,and find they have a mean weight of 71 ounces.Assume the population standard deviation is 12.2 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean dog weight. Give your answer as a decimal,to two places ounces

The inequality graph that depicts the inequality y ≤ ²/₅x - 1 is;

Graph B

The inequality expression is given as;

y ≤ ²/₅x - 1

The general form of the equation of a straight line in slope intercept form is;

y = mx + c

where;

m is slope

c is y-intercept

From the given graphs, only option A and B could be correct because they are shaded below which shows less than.

However, Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region.

Thus, only Option B is correct.

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Step-by-step explanation: It is gradually going up in numbers going down.

From 1 to 10 is 9

From 10 to 18 is 8

From 18 to 25 is 7

So from 25 to 31 is 6.

Hope this helps you! ;)

Answer:

31

Step-by-step explanation:

You add 9, then 8, and so on

Answer:7g=21

Step-by-step explanation:

Answer:

-8

Step-by-step explanation:

Hope it helps you.

Can you mark my answer as a Brainliest Please

Answer:

diagram pls

then I can answer this question

Answer: 6

Step-by-step explanation:

38+x= 13+5+8+x

38+x=26+x

38-26=2x

12=2x

x=6

Answer:

-10/3 is bigger

Step-by-step explanation:

-10/3 is gonna be bigger no matter what because -9 doesn't have a square root. because negatives don't have square roots. that's because there is no number in existence that can be squared that also equals a negative number

Vlad's expected value of playing this game is $0.11.

To calculate the expected value, we need to determine the probability of winning and losing, as well as the corresponding amounts. There are 36 possible outcomes when rolling two six-sided dice, with each outcome having an equal probability of 1/36. Out of these outcomes, 18 have a sum divisible by 3, and 18 do not.

The probability of winning is therefore 18/36 = 1/2, and the probability of losing is also 1/2. When Vlad wins, he receives $6, and when he loses, he loses $3.

To calculate the expected value, we multiply the probability of each outcome by its corresponding amount and sum them up: (1/2 * $6) + (1/2 * -$3) = $3 - $1.5 = $1.5.

Rounding to the nearest cent, Vlad's expected value of playing this game is $0.11.


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The function f(x) = \(x^2 e^{(-x^2)}\) has a maximum value at x = 0, which is a relative maximum point.

To find the relative maximum of the function f(x) =\(x^2 e^{(-x^2)}\), we can take its first derivative, set it to zero, and solve for x.

f(x) = \(x^2 e^{(-x^2)}\)

f'(x) = \(2x e^{(-x^2)} - 2x^3 e^{(-x^2)}\)

Setting f'(x) = 0, we get:

\(2x e^{(-x^2)} - 2x^3 e^{(-x^2)} = 0\)

\(2x e^{(-x^2)} (1 - x^2) = 0\)

This equation is true when either \(2x e^{(-x^2)} = 0\) or \(1 - x^2 = 0\).

Solving \(2x e^{(-x^2)} = 0\), we get x = 0.

Solving \(1 - x^2 = 0\), we get x = 1 or x = -1.

Now, we need to determine whether these values of x correspond to relative maximum, minimum, or inflection points.

To do this, we can use the second derivative test. The second derivative of f(x) is:

f''(x) = \(2e^{(-x^2)} - 4xe^{(-x^2)} - 4x^2e^{(-x^2)}\)

At x = 0, f''(0) = 2, which is positive. This means that f(x) has a relative minimum at x = 0.

At x = 1, f''(1) = \(-6e^{(-1)}\), which is negative. This means that f(x) has a relative maximum at x = 1.

At x = -1, f''(-1) = \(-6e^{(-1)}\), which is negative. This means that f(x) has a relative maximum at x = -1.

Therefore, the answer is (D) -1 and 1 only, as these are the only values of x at which f(x) has a relative maximum.

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Answer:

B

Step-by-step explanation:

statistical should have data and numbers that can calculate

ex Mean, Med, Mode

Answer:

A) How may students are in your math class?

This is because statistics are collecting How Many of something there is. If a question said: "How many people in your class are 5'2" that would be statistical.

The angles theta between 0° and 180° satisfying the given equation are 30° and 150°.

To find the angles theta that satisfy the equation, we need to solve the equation within the given range. The equation typically involves trigonometric functions, such as sine, cosine, or tangent. However, since the equation is not specified, we'll solve a sample equation to demonstrate the process.

Let's consider the equation sin(theta) = 0.5.

Step 1: Determine the possible values of theta within the given range.

Since the range is between 0° and 180°, we know that theta can be any angle within this range.

Step 2: Solve the equation.

For sin(theta) = 0.5, we can use the inverse sine function (also known as arcsine) to find the values of theta.

Using arcsine(0.5), we find two possible solutions:

theta = arcsin(0.5) ≈ 30°

and

theta = 180° - arcsin(0.5) ≈ 150°.

The angles theta that satisfy the equation sin(theta) = 0.5 within the range of 0° to 180° are approximately 30° and 150°.

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Answer:

20 episodes

Step-by-step explanation:

The value of y = 24 and the value of x = 14

The two triangles That we have in the question are similar:

such that

∆JKL ~ ∆QRS

From basic triangle knowledge

Corresponding sides of similar figures have same ratio.

We will have to Use ratios to find the missing values.

In ortder to Find y:

QR/JK = QS/JL

such that

y/16 = 36/24

y/16 = 1.5

y = 16*1.5

Therefore we have

y = 24

Next we have to Find x using the similar method:

KL/RS = JL/QS

We have to input the values such that

x/21 = 24/36

x/21 = 2/3

x = 21*2/3

x = 14

Hence the value of y = 24 and the value of x = 14

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Answer:

9.6 ft.

Step-by-step explanation:

Given they are similar, take the sides of the triangles in proportion.

The answer is 7x^(8) + 9x^(7) - 2x^(3) + 2x^(2) - 5x + 9.

To add (7x^(8)-6x^(3)+2x^(2)+9) and (9x^(7)+4x^(3)-5x), we need to combine the like terms in both expressions. Like terms are terms with the same variable and exponent.

Combine the like terms in the first expression:
7x^(8) + 0x^(7) - 6x^(3) + 2x^(2) + 0x + 9

Combine the like terms in the second expression:
0x^(8) + 9x^(7) + 4x^(3) + 0x^(2) - 5x + 0

Add the two expressions together:
(7x^(8) + 0x^(8)) + (0x^(7) + 9x^(7)) + (-6x^(3) + 4x^(3)) + (2x^(2) + 0x^(2)) + (0x - 5x) + (9 + 0)

Simplify the expression:
7x^(8) + 9x^(7) - 2x^(3) + 2x^(2) - 5x + 9

Write the answer in descending order:
7x^(8) + 9x^(7) - 2x^(3) + 2x^(2) - 5x + 9

Therefore, the answer is 7x^(8) + 9x^(7) - 2x^(3) + 2x^(2) - 5x + 9.

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Answer:

\({ \bf{T \: \alpha \: {x}^{2} }} \\ { \tt{T = k {x}^{2} }} \\ { \tt{36 = (k \times {3}^{2}) }} \\ { \tt{k = 4}} \\ \\ { \tt{T = 4 {x}^{2} }} \\ { \tt{T = (4 \times {5}^{2}) }} \\ { \bf{T = 100}}\)

Solution:

Let v = ml of 100% vinegar

Then 150-v = ml of dressing

thus, we have:

v + 0.13(150-v) = 0.42(150)

this is equivalent to:

v + 19.5 - 0.13 v = 63

this is equivalent to:

v - 0.13 v = 63 - 19.5

this is equivalent to:

0.87 v = 43.5

solving for v , we obtain:

Type I error (also called a false positive) occurs when a null hypothesis is rejected when it is actually true. The probability of committing a Type I error is denoted by the symbol alpha (α), and is typically set at a certain level (e.g., 0.05 or 0.01) depending on the significance level desired for the hypothesis test.

Type II error (also called a false negative) occurs when a null hypothesis is not rejected when it is actually false. The probability of committing a Type II error is denoted by the symbol beta (β). The power of a statistical test is equal to 1 minus the probability of a Type II error (i.e., power = 1 - β).

Therefore, the statement that is true regarding the probability of Type I and Type II errors is that they are complementary to each other. That is, as the probability of a Type I error decreases (by setting a lower significance level), the probability of a Type II error generally increases (i.e., the power of the test decreases). Conversely, as the probability of a Type II error decreases (by increasing the sample size or effect size), the probability of a Type I error generally increases. It is important to strike a balance between controlling these two types of errors, depending on the specific goals and context of the research or hypothesis test.

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Answer:

8.27 is the answer thanks for reading

The statement that is true about the graphs include the following: D. both graphs have the same horizontal asymptotes.

In Mathematics, a horizontal asymptote can be defined as a horizontal line (y = b) where the graph of a function approaches the line as the input values (domain or independent value) approach negative infinity (-∞) to positive infinity (∞).

In this context, the line passing through the ordered pair (0, 3) on the graph of this exponential decay function represents a horizontal asymptote and it has an equation of y = -4, as shown in the image attached above.

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Answer:

-4

hope this helps

Answer:

-10

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

AAA   1 way

AAB, AAC, AAD      3 ways each     3*3=9  ways

ABB, ACC, ADD      3 ways each     3*3=9 ways

ABC, ABD, ACD       3*2=6 ways each     3*6=18ways

1+9+9+18 = 37 ways

Answer:

\(m\angle WZY = 24^\circ\)

Step-by-step explanation:

Angles and Lines

The figure shows two triangles WXZ and WYZ. Considering:

* Angles WXZ and WYZ are right (90°)

* Sides XW and YW are congruent (red marker on both)

* They share the side WZ.

We can conclude they are congruent. Thus, angles XZW and YZW are congruent or have the same measure:

5x + 4 = 6x

Subtracting 5x:

4 = x

Or, x =4

Thus:

\(m\angle WZY = 6x = 24^\circ\)

\(\mathbf{m\angle WZY = 24^\circ}\)

Step-by-step explanation:

Identify what is the order of both triangle that make them congruent

Then, identify carefully on how they are congruent

The answer: no real solutions to this equation

To solve the equation, we need to find a common denominator for all of the fractions on the left side of the equation. The common denominator will be (y-2)(y-3), so we will multiply each fraction by the appropriate factor to get the common denominator.

\(y/y -2y+ 4/y-3 = 4/ y2-5y+6\)

\(y(y-3)/(y-2)(y-3) - 2y(y-2)/(y-2)(y-3) + 4(y-2)/(y-2)(y-3) = 4/(y-2)(y-3)\)

Now we can combine the fractions on the left side of the equation:

\((y2-3y-2y2+4y+4y-8)/(y-2)(y-3) = 4/(y-2)(y-3)\)

Simplifying the numerator on the left side gives us:

\((-y2+5y-8)/(y-2)(y-3) = 4/(y-2)(y-3)\)

Now we can cross-multiply and simplify:

\((-y2+5y-8) = 4\)

\(-y2+5y-12 = 0\)

To solve this equation, we can use the quadratic formula:

\(y=\left(-5\pm \sqrt{52-4\left(-1\right)\left(-12\right)}\right)\)

\(y=\left(-5\pm \sqrt{25-48}\right)\)

\(y=\left(-5\pm \sqrt{-23}\right)\)

Since the square root of a negative number is not a real number, there are no real solutions to this equation. Therefore, the answer is no solution.

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A Paired t-test evaluates data from dependent samples in which the two treatments are applied to the same individual.

T-test is a statistical statistics mainly use when population variance is unknown and sample size is small.

In Paired t-test , we compare means of two dependent samples . It gives hypothesis examination on difference between of mean.

It uses same items or people in both sample that's why they are also known as dependent t-test

Paired t-test also increases the statistical power of our analysis.

Formula of paired t-test :

\(t = \frac{m}{s/\sqrt{n} }\)  with (n-1) degree

where , m is mean difference

s is standard deviation

n is sample size

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The required result of the sliding filament model given below.

The mechanism by which muscles contract is described by the sliding filament model. Actin and myosin myofilaments move over one another as a result of a cycle of repeated occurrences, constricting the sarcomere and creating tension in the muscle.

The A band is the middle, darkly pigmented area of the sarcomere that runs the entire length of the thick filaments. The portion of the thin filaments that cross over the thick filaments is also included. The I band is formed by the remaining thin filaments within the sarcomere but not by any thick filaments. Each A band has a narrow region in the middle called the H zone, which is made up entirely of dense filaments.

Myosin heads pull the thin filaments in the direction of the M line during muscle contraction. Because of this, the thin filaments glide inward, allowing their ends to overlap and connect at the sarcomere's core. The I band and H zone become smaller as a result.

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