Mercury at 25°c flows over a 3-m-long and 2-m-wide flat plate maintained at 75°c with a velocity of 0. 01 m/s. Determine the rate of heat transfer from the entire plate?
Answers
The rate of heat transfer from the entire plate is 710.8 kW
The properties of mercury at the film temperature of (75+25)/2= 50°C
k = 8.83632 W/m °C
v = 1.056 × \(10^-^7\) m²/s
Pr = 0.0223
The local Nusselt number relation for liquid metals is given by
\(N_u =\frac{h_sx}{k} = 0.565 9Re_x Pr)^\frac{1}{2}\)
The average heat transfer coefficient for the entire surface can be determined from
\(h = \frac{1}{L} \int\limits^1_0 {h_x} \, dx\)
Substituting the local Nusselt number relation into the above equation and performing the integration we obtain
\(N_u = 1.13 (Re_s Pr)^\frac{1}{2}\)
The Reynolds number is
\(Re_L = \frac{VL}{v} = \frac{(0.01)(3m)}{1.056 * 10^-^7 m^2/s} = 0.028 * 10^7\)
Using the relation for the Nusselt number, the average heat transfer coefficient and the heat transfer rate are determined to be
Q = 710.8 kW
Therefore, the rate of heat transfer from the entire plate is 710.8 kW
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Related Questions
can somebody explain it to me please?
Answers
Range be R and height be h
\(\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}\)
\(\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}\)
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
\(\\ \sf\longmapsto R=2h\)
\(\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}\)
Cancelling required ones
\(\\ \sf\longmapsto sin^2\theta=sin2\theta\)
sin2O=2sinOcosO
\(\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta \)
\(\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2\)
\(\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2\)
\(\\ \sf\longmapsto tan\theta=2\)
\(\\ \sf\longmapsto \theta=tan^{-1}(2)\)
\(\\ \sf\longmapsto \theta=63.4°\)
Done
Option B is correct
2. How did Isabella discover capoeira?
O Her friend was trying it.
O She saw it in a movie.
O Her father is a coach.
o It was a club offered at her school.
Answers
Answer:
she saw it in a movie
Explanation:
she said her mom and her saw it in Step up 3 and fell in love
Fiona followed these steps for a scientific investigation: 1. Collect baking soda and vinegar 2. Pour baking soda into a bowl. 3. Pour vinegar into the bowl. 4. Record observations Choose the statement which shows what Fiona is most likely investigating. This mixture will cause a physical and chemical change to the bowl. Mixing baking soda and vinegar will cause a physical and chemical change. Combining baking soda and vinegar will cause a chemical change. Combining baking soda and vinegar will cause a physical change.
Answers
Answer: The correct statement is combining baking soda and vinegar will cause a chemical change.
Explanation:
A chemical reaction is defined as the reaction in which two or more chemical substances react to form two or more different chemical substances
A new substance (product) is formed in a chemical reaction when the bonds between the reactants are broken so that the new bonds between the products can be formed.
A physical process is defined as the process in which the physical state of matter takes place. Like, in the process of vaporization, a liquid state changes to the gaseous state without changing the composition of species.
When baking soda (Sodium bicarbonate) is reacted with vinegar (acetic acid), it leads to the formation of sodium acetate, water, and carbon dioxide.
A new compound is getting formed in this process which is denoted by the chemical equation:
\(NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2O+CO_2\)
Hence, the correct statement is combining baking soda and vinegar will cause a chemical change.
The orbit of Venus around the sun is more sharply curved than the orbit of Mars. Use one of Newton's laws to explain this
Answers
Answer:
gravity it's what keeping it to rotate and keeping it looping
a light spring is attached to a heavier spring at one end. a pulse traveling along the light spring is incident on the boundary with the heavier spring. at this boundary, the pulse will be
Answers
When a pulse traveling along a light spring reaches the boundary with a heavier spring, some of the pulse energy will be reflected back into the light spring, and some will be transmitted into the heavier spring. The amount of energy reflected and transmitted depends on the properties of the two springs and the angle of incidence of the pulse.
In general, if the two springs have different spring constants, the pulse will experience a change in velocity and amplitude at the boundary. The pulse will slow down when it enters the heavier spring, because the heavier spring will offer more resistance to deformation than the lighter spring. As a result, the wavelength of the pulse will decrease, and its amplitude will increase.
Whether the pulse is inverted or not at the boundary depends on the relative phase of the reflected and transmitted waves. If the boundary conditions are such that the reflected wave is in phase with the incident wave, the pulse will be inverted. If the reflected wave is out of phase with the incident wave, the pulse will not be inverted.
The exact behavior of the pulse at the boundary between the two springs depends on the specific properties of the springs, such as their spring constants and densities.
However, in general, the pulse will undergo a change in velocity, wavelength, and amplitude at the boundary, and may or may not be inverted depending on the relative phase of the reflected and transmitted waves.
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What happens to the gravitational force between two objects as the objects move closer together?
Answers
Answer:
The Gravity gets stronger
Explanation:
Newtons laws of motion.
Example 1-2. Figure 1-8a shows a ferromagnetic core whose mean path length is 40 cm. There is a small gap of 0.05 cm in the structure of the otherwise whole core. The cross-sectional area of the core is 12 cm^2
, the relative permeability of the core is 4000 , and the coil of wire on the core has 400 turns. Assume that fringing in the air gap increases the effective cross-sectional area of the air gap by 5 percent. Given this information, find (a) the total reluctance of the flux path (iron plus air gap) and (b) the current required to produce a flux density of 0.5 T in the air gap.
Answers
The total reluctance is the sum of the reluctances of the iron core and the air gap is 33.773 H⁻. The current required to produce a flux density of 0.5 T in the air gap is approximately 0.0497 A.
The reluctance (R) of a magnetic material is given by R = l / (μ₀μrA), where l is the length, μ₀ is the permeability of free space (4π x 10^-7 H/m), μr is the relative permeability, and A is the cross-sectional area. The mean path length of the core is given as 40 cm, and the cross-sectional area is 12 cm².
\(R_{iron} = l_{iron\) / (μ₀μr_\(ironA_{iron\)).
\(R_{iron\)= (40 cm) / (4π x 10^-7 H/m * 4000 * 12 cm²)
\(R_{iron\)= 0.02653 H⁻¹
The length of the air gap is given as 0.05 cm. We need to consider the effective cross-sectional area of the air gap, which is increased by 5 percent due to fringing. The actual cross-sectional area of the air gap is 0.05 cm * 12 cm². Therefore, the effective cross-sectional area is 1.05 * (0.05 cm * 12 cm²).
\(R_{air_{gap\)= (0.05 cm) / (4π x 10^-7 H/m * 1 * 1.05 * (0.05 cm * 12 cm²))
= 33.747 H⁻¹
The total reluctance is the sum of the reluctances of the iron core and the air gap:
\(R_{total} = R_{iron }+ R_{air_{gap\)
≈ 33.773 H⁻¹
(b) The magnetic field intensity (H) is related to the current (I) and the number of turns (N) by H = (N * I) / l. The magnetic flux density (B) is related to the magnetic field intensity and the relative permeability (μr) by B = μ₀μrH.
To achieve a flux density of 0.5 T in the air gap, we can rearrange the equation B = μ₀μrH to solve for H:
H = B / (μ₀μr) = 0.5 T / (4π x 10^-7 H/m * 1)
H = 397.887 A/m
Now, we can solve for the current (I) using the formula H = (N * I) / l:
397.887 A/m = (400 turns * I) / 0.05 m
I = (397.887 A/m * 0.05 m) / 400 turns
I ≈ 0.0497 A
Therefore, the current required to produce a flux density of 0.5 T in the air gap is approximately 0.0497 A.
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, Explain why a decrease in CFC emissions did not result in an immediate increase in the concentration of stratospheric ozone?
11, Predict how levels of stratospheric ozone are expected to change in the coming decades. Justify your response with evidence and reasoning?
Answers
Explanation why a decrease in CFC emissions did not result in an immediate increase in the concentration of stratospheric ozone CFC (chlorofluorocarbon) is a stable chemical compound that remains in the atmosphere for a long period of time. Therefore, even if the production of CFC were to be stopped, the concentration of the compound in the atmosphere would continue to exist for years.
The halogenated chemicals that damage the ozone layer are known to have long atmospheric lifetimes; they remain in the atmosphere for several years to decades. Therefore, even if humans stopped producing all ozone-depleting chemicals tomorrow, the stratospheric ozone layer would continue to be affected for many years. Predicting how the levels of stratospheric ozone are expected to change in the coming decades CFCs (chlorofluorocarbons) are synthetic organic chemicals made of carbon, chlorine, and fluorine. They are used in various applications such as refrigeration, air conditioning, and aerosols. If current trends continue, CFC levels are expected to decrease in the coming decades, and stratospheric ozone concentrations are expected to increase.
However, other factors, such as climate change, can also impact the concentration of ozone in the stratosphere. Greenhouse gases such as CO2, CH4, and N2O emitted into the atmosphere as a result of human activities can increase temperatures in the troposphere and decrease temperatures in the stratosphere. The temperature drop in the stratosphere is a result of the greenhouse gases trapped in the atmosphere, which in turn increases the concentration of polar stratospheric clouds. These clouds can act as surfaces for chemical reactions, which deplete the ozone layer. As a result, even if CFC levels decrease, stratospheric ozone concentrations may not increase if these other factors are not addressed.
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Describe how reactivity changes as you go down Group 1A.
Answers
Answer:
it is a the answer is a btw
Explanation:
Using the "nielsen form" determine the equation of motion for a mass m connected to a spring of constant k
Answers
By applying Newton's second law of motion, it is possible to establish an equation of motion for a mass attached to a spring. The traditional form of the equation of motion of a spring–mass system is called the "Nielsen form" in this context.
Provides the following motion equation:
m * d²x/dt² + k * x = 0
Where:
m is the mass of the object connected to the spring
x is the displacement of the object from its equilibrium position
t is time
k is the spring constant, which represents the stiffness of the spring
The inertial force (m * d²x/dt²) and the spring force (k * x) acting on the mass are balanced by this equation. The spring force is said to be in the opposite direction to the displacement when its sign is negative, which acts as a restoring force to move the mass back to its equilibrium position.
We can calculate the momentum of the mass-spring system with time by solving this second-order ordinary differential equation. The initial conditions, such as the initial displacement and velocity of the mass, affect the solution.
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Do any of the force pairs suggested in Question 5 not produce an acceleration? If so which one(s).
A. A skier uses her ski poles to start moving downhill
B. A boat propeller spins rapidly in the water
C. A baseball player hits a pitched ball with a bat
D. A party balloon contains rapidly moving helium atoms
Answers
All of the given options produce an acceleration that are force pairs suggested in Question 5.
When a skier uses her ski poles to start moving downhill then the ski poles exert a backward force on the ground while the ground exerts a forward force on poles and produces acceleration.
Similarly in case B. when a boat propeller spins rapidly in the water the propeller exert a backward force on the water while the water exerts a forward force on propeller and produces acceleration.
In case C. when a baseball player hits a pitched ball with a bat the bat exert a backward force on the ball while the ball exerts a force away from bat and produces acceleration.
In case D. when a party balloon contains rapidly moving helium atoms the helium atoms exert an outward force on the balloon while the balloon exerts an inward force on helium atoms and produces acceleration.
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What are the factors that change the pattern observed on a screen during Young’s double-slit experiment?
Answers
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:
1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.
2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.
3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.
4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.
5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.
When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.
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A spring is compressed 7.0 cm. How far must you compress a spring with twice the spring constant to store the same amount of energy
Answers
you must compress the new spring by 0.07 meters (or 7.0 cm) to store the same amount of energy.
To find how far you must compress a spring
with twice the spring constant to store the same amount of energy, you can use the formula for the potential energy stored in a spring:
PE = (1/2)kx^2
Where PE is the potential energy, k is the spring constant, and x is the displacement of the spring.
Given that the initial spring is compressed by 7.0 cm, we can calculate the potential energy stored using the formula:
PE1 = (1/2)k1(0.07)^2
Now, we want to find the displacement of the new spring,
let's call it x2. Since the new spring has twice the spring constant, we can write:
PE1 = PE2
(1/2)k1(0.07)^2 = (1/2)k2x2^2
Since k2 is twice k1, we can substitute 2k1 for k2:
(1/2)k1(0.07)^2 = (1/2)(2k1)x2^2
Simplifying the equation, we get:
(0.07)^2 = x2^2
Taking the square root of both sides, we have:
0.07 = x
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To store the same amount of energy, you would need to compress the spring with twice the spring constant to approximately 4.95 cm.
To find out how far you must compress a spring with twice the spring constant to store the same amount of energy, let's first understand the relationship between the compression of a spring and the stored energy.
The potential energy stored in a compressed spring is given by the equation:
PE = (1/2)kx^2
where PE is the potential energy, k is the spring constant, and x is the compression of the spring.
In this case, the initial compression of the spring is given as 7.0 cm, and we want to find the new compression for the spring with twice the spring constant.
Let's assume the original spring constant is k1 and the new spring constant is k2 (which is twice k1). The potential energy for both springs should be equal:
(1/2)k1x1^2 = (1/2)k2x2^2
Since we want to find x2, we can rearrange the equation as follows:
k1x1^2 = k2x2^2
Since k2 = 2k1, we can substitute 2k1 for k2:
k1x1^2 = (2k1)x2^2
Simplifying further:
x1^2 = 2x2^2
Taking the square root of both sides, we get:
x1 = sqrt(2) * x2
To find x2, we divide both sides of the equation by sqrt(2):
x2 = x1 / sqrt(2)
Substituting the value of x1 (7.0 cm), we have:
x2 = 7.0 cm / sqrt(2)
Calculating this value, we get:
x2 ≈ 4.95 cm
Therefore, to store the same amount of energy, you would need to compress the spring with twice the spring constant to approximately 4.95 cm.
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What is the voltage drop across the 30 ohm resistor?
Answers
The voltage drop across the 30Ω resistor in the given circuit is 60V which is described below.
Ohm's Law:According to the circuit given in the question, all the resistors are connected in series with the battery.
The equivalent resistance R in the circuit is:
R = 10Ω + 20Ω + 30Ω
R = 60Ω
The battery has a voltage of V = 120V
From Ohm's Law:
V = IR
where I is the current in the circuit
120 = I × 60
I = 2A
So, the same current flows through all the resistors as they are connected in series.
The voltage drop across 30Ω resistor is:
V₃₀ = 2×30
V₃₀ = 60 V
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3. A current of 6.0 amperes flows through a light bulb when the voltage
difference between the ends of the filament are 110 volts. What is the
resistance?
Answers
Answer:
18.3Ω
Explanation:
Resistance can be found using the formula:
Resistance = \(\frac{Voltage}{Current }\)
Voltage = 110 volts
Current = 6.0 amperes
∴ Resistance = \(\frac{110}{6}\)
= 18.3 Ω ( to nearest 3 significant figures)
what is the molar solubility of la(io3)3 in pure water? ksp = 1.0 × 10−11 for la(io3)3.
Answers
The molar solubility of La(IO₃)₃ in pure water is approximately 1.0 × 10⁻⁴ mol/L.
The molar solubility of a compound refers to the maximum amount of the compound that can dissolve in a given solvent at a specific temperature, typically expressed in moles per liter (mol/L). To determine the molar solubility of La(IO₃)₃ in pure water, we can use the given value of the solubility product constant (Ksp) for La(IO₃)₃, which is 1.0 × 10⁻¹¹.
La(IO₃)₃ dissociates into La³⁺ and IO₃⁻ ions in water. Let's assume x mol/L represents the molar solubility of La(IO₃)₃. According to the balanced chemical equation, one mole of La(IO₃)₃ produces one mole of La³⁺ ions and three moles of IO₃⁻ ions.
Therefore, the solubility product expression for La(IO₃)₃ is:
Ksp = [La³⁺][IO₃⁻]³
Since the concentration of La³⁺ ions is equal to the molar solubility (x) and the concentration of IO₃⁻ ions is three times the molar solubility (3x), we can substitute these values into the Ksp expression:
Ksp = (x)(3x)³
1.0 × 10⁻¹¹ = 27x⁴
Solving for x, we find:
x ≈ 1.0 × 10⁻⁴ mol/L
Therefore, the molar solubility of La(IO₃)₃ in pure water is approximately 1.0 × 10⁻⁴ mol/L.
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A spring with a force constant of 5500 N/m and a rest length of 2.8 m is used in a catapult. When compressed to 1.0 m, it is used to launch a 54 kg rock. However, there is an error in the release mechanism, so the rock gets launched almost straight up. How high does it go (in m)
Answers
The rock goes to a height of approximately 13 m when launched by the compressed spring using the catapult.
Considering that the rock moves only in the vertical direction (due to a straight launch) with an initial velocity of 0 m/s, then the final velocity of the rock can be calculated using conservation of energy.
Thus the potential energy of the compressed spring gets converted to potential energy of the rock when the spring is released. i.e.,
Potential Energy of the compressed spring = PE of the rock at maximum height
The potential energy of the spring is given by the formula:
PEspring= 0.5 k (x2 - x1)2
where k is the force constant of the spring, x1 is the uncompressed length of the spring, and x2 is the length of the spring when compressed.
The initial compression of the spring x1 = 2.8 m and the compression x2 = 1.0 m
Therefore, PEspring = 0.5 × 5500 × (2.8 − 1)2 = 7193.75 J
The potential energy of the rock at maximum height is given by: PErock= mgh
where m is the mass of the rock, g is the acceleration due to gravity (9.8 m/s²), and h is the maximum height achieved by the rock.
Substituting the values of m, g and PErock, we get: 7193.75 J = (54 kg) (9.8 m/s²) (h)
h = 7193.75 / (54 × 9.8) ≈ 13 m
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
Answers
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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An elevator, mass 4750kg, is designed so that the maximum acceleration is 0.50m/s2. What are themaximum and minimum forces the motor exerts on the cable?
Answers
The free body diagram of the elevator can be shown as,
According to free body diagram, the net force acting on the elevator is,
\(F_n=T_{\max }-mg\)According to Newton's law,
\(F_n=ma\)Plug in the known expression,
\(\begin{gathered} ma=T_{\max }-mg \\ T_{\max }=ma+mg \\ =m(a+g) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\max }=(4750kg)(0.50m/s^2+9.8m/s^2) \\ =(4750\text{ kg)(}10.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =48925\text{ N} \end{gathered}\)Thus, the maximum force exerted on the cable is 48925 N.
For minimum, tension the net force can be expressed as,
\(F_n=mg-T_{\min }\)Plug in the known expression,
\(\begin{gathered} ma=mg-T_{\min } \\ T_{\min }=mg-ma \\ =m(g-a) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\min }=(4750kg)(9.8m/s^2-0.5m/s^2) \\ =(4750\text{ kg)(}9.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =44175\text{ N} \end{gathered}\)Thus, the minimum force exerted on the cable is 44175 N.
Please help will give brainiest!!!
Answers
Given the fact that the arrow is in motion, it the follows that the arrow possesses kinetic energy.
What is the kinetic energy?The kinetic energy is the energy that is possessed by a body by virtue of its motion. This is different form the potential energy of the body which is the energy that the body possesses as a result of the fact that the object is located at a particular position. These are actually the two kinds of mechanical energy that we have in the study of physics.
If we consider this matter closely, we would see that the arrow as shown is in motion. The arrow does posses a velocity and such the arrow is in motion. As long as we can see that the arrow is in motion, it the follows that the arrow as we can see does and in fact possesses the kinetic energy.
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Degeneracy pressure stops the crush of gravity in all the following except:_____.A) a brown dwarf.
B) a white dwarf.
C) a neutron star.
D) a very massive main-sequence star.
E) the central core of the Sun after hydrogen fusion ceases but before helium fusion begins.
Answers
Degeneracy pressure stops the crush of gravity in all the following except a brown dwarf. The correct option is a.
What is Degeneracy pressure?Electron degeneracy pressure is a subset of the broader phenomenon of quantum degeneracy pressure.
The Pauli exclusion principle prevents two identical half-integer spin particles from occupying the same quantum state at the same time.
Electron degeneracy pressure, in particular, is what protects white dwarfs from gravitational collapse, as well as the Chandrasekhar limit (the maximum mass a white dwarf can attain) arises naturally as a result of electron degeneracy physics.
Thus, the correct option is a.
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True or False? Index Fossils are used to help constrain the relative age of the rocks in an area?
Answers
it is important to know the difference between atoms
Answers
Answer:
yes
hope this will help you
what force is needed to move a 2 kg mass with an acceleration of 5 m/s²?
force = mass X acceleration
a, 10 N
b, 25 N
c,3 N
d, 15 N
help please :(
Answers
F = m.a
F = 2 x 5 = 10 N
Answer:
a, 10 N
Explanation:
5 x 2 = 10 or 5 m/s^2 * 2kg
A horizontal force of 20 N is applied to the object.
Draw a free body diagram with the forces to scale.
Determine the force of friction.
Determine the acceleration of the object.
Answers
The acceleration of the object with a horizontal force of 20N is 4.4 m/s².
How to Determine Horizontal Acceleration in Frictional Systems
Here, the angle of repose
a = tan⁻¹ (45)
a = tan⁻¹(1/5)
a = 11.3°
The angle of inclination is greater than the angle of repose.
The friction force on the block will act in an upward direction.
For the acceleration of the block:
MgsinΘ - μN = Ma
a = gsinΘ - μg cosΘ
a = g (sinΘ - u cosΘ)
a = 10 (sin37 - μ cos37)
a = 10 (0.6 - 0.2 * 4/5)
a = 10 ( 0.6 -0.16)
a = 4.4 m/s²
Thus the acceleration of the object is 4.4 m/s².
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The part of the atom where the electrons cannot be found is the.
Answers
Answer:
Nucleus :)
Explanation:
An electron will only react with a proton in the nucleus via electron capture if there are too many protons in the nucleus.
I also learned this in freshman year in high school for biology.
Answer:
Nucleus
Explanation:
The Heisenberg Uncertainty Principle explains why electrons do not fall into the nucleus of an atom. The principle specially states that the product of the uncertainty of position and the uncertainty of momentum is greater than or equal to Planck's reduced constant divided by two.
please help asap!!!!
Answers
Answer:
D. 100% Chance of having a child with dimple
four children stand at edge of a circular horizontal platform that is free to rotate about a vertical axis. each child has a mass of 35 kg and are at positions that are a quarter circle from each other. the platform has a moment of inertia equal to 500 kg*m2 and a radius of 2.0 m. the system is initially rotating at 6.0 rev/min. the children walk toward the center of the platform until they are 0.50 m from the center. (a) what is the rotational speed of the platform when the children are at the 0.50 m positions? (b) what is the change in rotational kinetic energy of the system? {-116 j}
Answers
a)1060 kg/m2.
b) 525
What exactly is inertia?
a quality of matter that allows it to remain in its current state of rest or uniform motion in a straight line until modified by an external force.
What is the definition of moment of inertia?
In physics, a moment of inertia is a quantitative measure of a body's rotational inertia—that is, the resistance that the body shows to having its speed of rotation along an axis altered by the application of a torque (turning force). The axis might be internal or exterior, and it can be fixed or not.
A rigid body's moment of inertia, also known as its mass moment of inertia, angular mass, second moment of mass, or, more precisely, rotational inertia, is a quantity that determines the torque required for a desired angular acceleration about a rotational axis, similarly to how mass determines the force required for a desired acceleration. A typical mechanical quantity is the moment of inertia.
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Inertia is a property of matter that causes it to resist changes in velocity (speed and/or direction). According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.
What exactly is inertia?
A quality of matter that allows it to remain in its current state of rest or uniform motion in a straight line until modified by an external force.
What is the definition of moment of inertia?
In physics, a moment of inertia is a quantitative measure of a body's rotational inertia—that is, the resistance that the body shows to having its speed of rotation along an axis altered by the application of a torque (turning force). The axis might be internal or exterior, and it can be fixed or not.
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Consider the circled elements in the periodic table. Based on their location, we could infer that most of them are
A) very reactive gases.
B) gases at room temperature.
C) do not react readily with metals.
D) nonreactive solids at room temperature.
Answers
Based on the circled elements in the periodic table’s location, we could infer that most of the circled elements are gases at room temperature. The correct answer is B.
What elements are gasses at room temperature?There are 11 elements that are in gaseous state at room temperature. They are Hydrogen (H), Helium (He), Neon (N), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn), Fluorine (F), Chlorine (Cl), Nitrogen (N) and Oxygen (O).
Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and also are found as diatomic molecules (H2, N2, O2, F2, Cl2).
Although part of your question is missing, you might be referring to this full question: Consider the circled elements in the periodic table as seen on attached image. Based on their location, we could infer that most of them are:
A) very reactive gases.
B) gases at room temperature.
C) do not react readily with metals.
D) nonreactive solids at room temperature.
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what difference will you get from the flying or air filled balloon and the hydrogen filled balloon.
Answers
Answer:Since most of air is made of nitrogen and oxygen, which have heavier molecular weights than hydrogen, air is denser than the hydrogen-filled balloon (the atmosphere is denser than the hydrogen-filled balloon). This results in the balloon floating in the air!
Explanation: