The standard deviation of both the data are the same which is 3.67 and adding the same constant c to each data value results in the standard deviation remaining the same.
What is the standard deviation?It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.
We have a data set:
8, 16, 14, 8, 16
As we know the formula for standard deviation is:
\(\rm \sigma = \sqrt{\dfrac{ \sum (x_i-X)}{n}\)
Here σ is the standard deviation
xi is each value from the data set
X is the mean of the data set
n is the number of observation in data set.
X = (8+16+14+8+16)/5 = 12.4
n = 5
After calculating the standard deviation will be:
σ = 3.67
Add 8 to each data value to get the new data set 16, 24, 22, 16, 24.
New standard deviation:
σ(new) = 3.67
The standard deviation of both the data are same we can say the standard deviation does not change when we add a constant to each data value.
Adding the same constant c to each data value results in the standard deviation remaining the same.
Thus, the standard deviation of both the data are the same which is 3.67 and adding the same constant c to each data value results in the standard deviation remaining the same.
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A real estate office handles an apartment complex with 60 units. When the rent per unit is $98 per month, all 60 units are occupied. However, when the rent is $630 per month, the average number of occupied units drops to 46. Assume that the relationship between the monthly rent p and the demand x is linear.
Select the equation of the line giving the demand x in terms of the rent p.
Charlie's Chocolate Factory purchases a taffy-pulling machine for $885. The machine has a useful life of 5 years after which time another one will have to be purchased. Assume depreciation of the machine is linear. Write a linear equation giving the value V of the taffy-pulling machine during the 5 years it will be in use.
For the demand of apartments in terms of rent: The equation of the line giving the demand x in terms of the rent p is x = -0.0263p + $62.5764.
For the value of the taffy-pulling machine during its useful life: The equation of the line giving the value V of the taffy-pulling machine during the 5 years it will be in use is V = -$177t + $885.
For the first scenario:
We are given two data points: when the rent is $98 per month, all 60 units are occupied, and when the rent is $630 per month, the average number of occupied units drops to 46.
Let's assign the rent as p and the demand (number of occupied units) as x. We are told that the relationship between the monthly rent p and the demand x is linear.
We can find the equation of the line using the slope-intercept form:
y = mx + b
where y represents the demand x, m represents the slope, and b represents the y-intercept.
Using the given data points, we can calculate the slope:
Slope (m) = (change in y) / (change in x)
Slope (m) = (46 - 60) / ($630 - $98)
= -14 / $532
= -0.0263 (rounded to four decimal places)
Now, we can use one of the data points (let's use p = $98, x = 60) to find the y-intercept:
60 = -0.0263($98) + b
Solving for b:
60 = -$2.5764 + b
b = 60 + $2.5764
b = $62.5764 (rounded to four decimal places)
Therefore, the equation of the line giving the demand x in terms of the rent p is:
x = -0.0263p + $62.5764
For the second scenario:
We are given that the taffy-pulling machine is purchased for $885 and has a useful life of 5 years. The depreciation of the machine is assumed to be linear.
Let's assign the value of the machine as V and the number of years since purchase as t. We want to find the linear equation that gives the value of the taffy-pulling machine during the 5 years it will be in use.
Since the useful life of the machine is 5 years, the initial value is $885, and the final value is $0 (since it will have to be replaced after 5 years), we can use the slope-intercept form to find the equation:
y = mx + b
where y represents the value V, m represents the slope, t represents the number of years since purchase, and b represents the initial value.
Using the given data points, we can calculate the slope:
Slope (m) = (change in y) / (change in x)
Slope (m) = ($0 - $885) / (5 - 0)
= -$177
Now, we can use one of the data points (let's use t = 0, V = $885) to find the initial value:
$885 = -$177(0) + b
Solving for b:
$885 = b
Therefore, the equation of the line giving the value V of the taffy-pulling machine during the 5 years it will be in use is:
V = -$177t + $885
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Please help me with this geometry question
(1 point) find the function g(x) satisfying the two conditions: 1. g′(x)=−512−x3 2. the maximum value of g(x) is 3.
The function g(x) that satisfies the given conditions is \(g(x) = -256 - x^4 + 3x.\)It has a derivative of \(g'(x) = -512 - x^3\) and its maximum value is 3.
To find the function g(x) that satisfies the given conditions, we start by integrating the derivative \(g'(x) = -512 - x^3.\) The integral of -512 gives -512x, and the integral of \(-x^3\) gives\(-(1/4)x^4\). Adding these terms together, we have the general antiderivative of g(x) as \(-512x - (1/4)x^4 + C\), where C is a constant of integration.
Next, we apply the condition that the maximum value of g(x) is 3. To find this maximum value, we take the derivative of g(x) and set it equal to 0, since the maximum occurs at a critical point. Taking the derivative of g(x) = \(-512x - (1/4)x^4 + C\), we get g'(x) = \(-512 - x^3\).
Setting g'(x) = \(-512 - x^3 = 0\), we solve for x to find the critical point. By solving this equation, we find x = -8. Substituting this value back into g(x), we have g(-8) =\(-256 - (-8)^4 + 3(-8) = 3\). Thus, the function g(x) = \(-256 - x^4 + 3x\) satisfies the given conditions, with a derivative of g'(x) = -\(512 - x^3\) and a maximum value of 3.
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in a research study, if the obtained mean of the observations is close to the population parameter, then in one sense the sample is considered representative of the target population. group of answer choices true false
The given statement is True because If the sample mean is close to the population parameter, it suggests representative sampling regarding the variable of interest, although other factors should be considered too.
When the sample mean closely approximates the population parameter, it indicates that the sample is capturing the central tendency of the population. The mean is a measure of central tendency that reflects the average value of the variable of interest in the population.
If the sample mean is similar to the population mean, it suggests that the sample is a good representation of the population in terms of that particular variable.
However, it is important to note that representativeness is a relative concept. A sample may be considered representative in one sense but not necessarily in all aspects. Other factors, such as the sampling method, sample size, and sampling bias, also influence the representativeness of a sample.
In summary, when the obtained mean of the observations in a research study is close to the population parameter, it provides evidence that the sample is representative of the target population to some degree, indicating that the sample captures the central tendency of the population for the variable under investigation.
However, representativeness should be assessed in consideration of other factors as well.
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What is the mathematical equation to equal 24 when using each of the numbers 3 4 6 and 7 only once?
The equation that can be formed from the given set of numbers
1) (3 + 4) * 6 + 7 = 24
2) 3 + 4 * (6 + 7) = 24
3) 3 + 4 + 6 + 7 = 20, so (3 + 4 + 6 + 7) * 1 = 24
4) 3 * 4 * 6 * 7 = 168, so 168 / 7 = 24
Mathematical Operations :
The mathematical “operation” refers to calculating a value using operands and a math operator. The symbol of the math operator has predefined rules to be applied to the given operands or numbers.
Mathematical Equations :
An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used.
BODMAS
According to the BODMAS rule, mathematical equations containing numerous operators must be resolved in the order of BODMAS, starting from the left.
Keep in mind that the order in which you perform the operations will affect the result. Parentheses are used to indicate the order in which operations should be performed.
In the first example above, the operation inside the parentheses (3 + 4) is done first, and then that result is multiplied by 6 and added to 7.
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In the year 2000, in an African game park it was estimated that there were approximately 700 wildebeest and that
their population was increasing at 3% per year. At the same time, in the park there were approximately 1850 zebras
and their population was decreasing at the rate of 4% per year. Use a calculator to plot the graphs of both functions.
a. After how many years was the number of wildebeest greater than the number of zebras?
b. It is also estimated that there were 1000 antelope and their numbers were increasing by 50 per year. After how
many years was the number of antelope greater than the number of zebras?
Answer:
14;8
Step-by-step explanation:
a、700*(1+3%)^n>1850*(1-4%)^n ,n is the minimum :14;
b、1000+50n>1850*(1-4%)^n,n is the minimum :8
a. After approximately 24.89 years, the wildebeest population will be greater than the zebra population.
b. After approximately 57.77 years, the antelope population will be greater than the zebra population.
To find the exact answers for the time when the wildebeest population surpasses the zebra population and when the antelope population surpasses the zebra population, we need to solve the equations:
a) For the wildebeest and zebra populations:
\(700 * (1.03)^t = 1850 * (0.96)^t\)
To solve this equation, we can isolate the exponential terms and solve for t:
\((1.03)^t / (0.96)^t = 1850 / 700\)
Now, take the natural logarithm (ln) of both sides:
\(ln[(1.03)^t / (0.96)^t] = ln(1850 / 700)\)
Using the properties of logarithms, we can simplify the equation:
\(t * ln(1.03) - t * ln(0.96) = ln(1850 / 700)\)
Factor out t:
\(t * [ln(1.03) - ln(0.96)] = ln(1850 / 700)\)
Now, solve for t:
\(t = ln(1850 / 700) / [ln(1.03) - ln(0.96)]\)
we get: \(t \approx 24.89 years\)
So, after approximately 24.89 years, the wildebeest population will be greater than the zebra population.
b) For the antelope and zebra populations:
\(1000 + 50t = 1850 * (0.96)^t\)
We can solve this equation similarly:
\(1000 + 50t = 1850 / (0.96)^t\\\\t * 50 = ln(1850 / 1000) / ln(0.96)\\\\t = ln(1850 / 1000) / ln(0.96) / 50\)
we get: \(t \approx 57.77 years\)
So, after approximately 57.77 years, the antelope population will be greater than the zebra population.
Keep in mind that these are approximate values, and the actual year may need to be rounded to the nearest whole number, as populations cannot be fractional. Therefore, the final answers are: a) After 25 years, the wildebeest population will be greater than the zebra population.
b) After 58 years, the antelope population will be greater than the zebra population.
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What is the slope of line p
please guys or girls I really need help for this question im failing math
Answer:
Yes it is proportional (Equation: y=3.5x)
Step-by-step explanation:
Notice that there is a constant change in y and a constant change in x. But by how much? Given the last point (13,45.5) we can see that 13-12=1 and 45.5-42=3.5 so that means as x increases by 1, y always increases by 3.5, making the relationship proportional. You can also write the equation y=3.5x to show this
Dropped 1. 50 inches raising the seasonal total to 26. 42 inches what was the seasonal total prior to the recent storm?
The seasonal total prior to the recent storm was 76.42 inches.
To calculate the seasonal total prior to the recent storm, we need to subtract the rainfall from the recent storm (50 inches) from the updated seasonal total (26.42 inches).
Let's assume that the seasonal total prior to the recent storm is represented by "x" inches.
So, we can set up the equation:
x - 50 = 26.42
To solve for x, we can add 50 to both sides of the equation:
x - 50 + 50 = 26.42 + 50
This simplifies to:
x = 76.42
Therefore, the seasonal total prior to the recent storm was 76.42 inches.
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solve (3x-2) (4x+1)
Answer:
12x^2-5x-2
Step-by-step explanation:
HELP PLEASE IM ALREADY FAILING MATH AND I DONT UNDERSTAND HOW TO DO THIS!! STEPS HAVE TO BE SHOWN OR I GET A 0!!!
Answer:
I put down my steps in the comment section. If you still don't understand just comment to me.
Step-by-step explanation:
Answer: I answered 6-11
Step-by-step explanation:
the radius of a sphere is increasing at a rate of 2 mm/s. how fast is the volume increasing when the diameter is 60 mm? evaluate your answer numerically.
When diameter is 60 mm, the volume increases at a rate of 22,620 mm³/s.
Define the term rate of volume change?The indication that demonstrates not whether a volume trend is occurring in an up or down direction is the volume rate of change.Step 1: Create an equation that connects a sphere's volume to radius as the first step.
V = 4/3*π*r³
Step 2: Calculate each side's derivative in respect to time (Let the time be "t").
(d/dt)V = (d/dt)(4/3*π*r³)
dV/dt = 4πr²*dr/dt
Step 3: The problem description informs us that the diameter is 600 m, hence r must be 30 mm.
Additionally, it is stated that now the radius of a sphere is expanding at a rate of 2 mm/s; as a result, dr/dt must equal 2 mm/s.
We are interested in dV/dt, or the rate of change of the sphere's volume.
dV/dt = 4π(30mm)²*(2mm/s)
dV/dt = 22,620 mm³/s
So, when diameter is 60 mm, the volume increases at a rate of 22,620 mm³/s.
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Help ASAP PLEASEEEEEeEEeeEeEe
Answer:
C
Step-by-step explanation:
So to do this problem, first find the area of the figure before you apply the scale factor, and then multiply that by 49. The reason you multiply it by 49 and not 7 is because you're multiplying both the length and the width of the figure by 7, so you have 7 * 7 = 49.
The area of the figure to start is 10 (you can find this by simply counting the blocks).
Then, 10 * 49 = C. 490 units squared.
hope that makes sense!
question 4 while verifying cleaned data, a data analyst encounters a misspelled name. which function can they use to determine if the error is repeated throughout the dataset?
The function can they use to determine if the error is repeated throughout the dataset is " COUNTA ".
The given condition needs the following function;
Data Integration Error:
Data from a single source, obtained and entered in the same way across time is unusual to be present in a database of significant size and age. A database frequently comprises data that has been gathered over time from various sources using various ways. As an illustration, consider how the meaning of "affected" is evolving or changing as the crisis progresses and the number of people affected is tracked over time. In addition, many databases evolve in practice by joining together different pre-existing databases. Almost always, the databases involved in this merging effort include discrepancies involving various data units, measurement intervals, formats, etc. Any process that combines data from various sources has the potential to make mistakes. When two or more databases are combined, errors will be found where there are discrepancies between the databases as well as new errors will be produced (i.e. duplicate records). A few potential origins and types of errors in a big assessment are shown in Table 1 below, at three fundamental levels: after completing the survey, when adding information to the database, and when conducting the analysis.
So, we use " COUNTA "
The function can they use to determine if the error is repeated throughout the dataset is " COUNTA ".
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3base and 7 power answers
Answer:
2187
Step-by-step explanation:
Multiply 3 seven times in your calcultor to check this answer or look it up on google
What is the lowest common multiple of 12 and 15?
Answer:
60
Step-by-step explanation:
LCM of 12 and 15
First Method: Listing the multiples
First, write the common multiples of all three numbers.
Common Multiples of 12: 12,24,36,48,60,72,….
Common Multiples of 15: 15, 30, 45, 60, 75,…
Hence, the Least common multiple of 12 and 15 is 60.
Second method: By prime factorisation
Let us write the prime factors of the two numbers individually.
12 = 2 x 2 x 3
15= 3 x 5
Multiply each factor the maximum number of times it occurs in either number
= 2 X 2 X 3 X 5
= 60
LCM of 12 and 15= 60
Answer
LCM of 12 and 15= 60
Hope this helps :)
Answer:
60
Step-by-step explanation:
we have to use prime factorisation method to obtain the answer.
12 and 15 have LCM 60.
suppose that scores on a recent statistics exam were normally distributed, that students in the 80th percentile of scores earned 85 points, and that students in the 30th percentile of scores earned 65 points. what was the mean of all exam scores in the class?
The mean of all exam scores in the class is found as 71.
What is definition of the term normally distributed?Beginning statisticians observed the same shape recurring in different distributions and named this the normal distribution. Normal distributions are distinguished by their symmetric bell shape. The mean and median are the same; they are both in the middle of the distribution.For the given question;
The z-score is found by;
z = (x - μ)/σ
x = sample mean
μ = mean score
σ = standard deviation
Now, from this,
x = zσ + μ
For p = 80th percentile= 0.8, see z value from z score table.
z = 0.85
x = 85 points
85 = 0.85σ + μ .....eq 1
For p = 30% = 0.3, see z value from z score table.
z = -0.3802
x = 65
65 = -0.3802σ + μ .....eq 2
Solving eq 1 and 2.
σ = 16.25
Put in eq 1
μ = 71.19
μ = 71
Thus, the mean of all exam scores in the class is found as 71.
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B = 18, c = 30 a = ?
What is true as the spread of scores around the arithmetic mean gets smaller? A. The coefficient of variation gets smaller B. The interquartile range gets smaller. C. The standard deviation gets smaller D. All of the above
The correct answer is D. All of the above. When the spread of scores around the arithmetic mean gets smaller, it means that the data points are closer to the mean.
This has several implications:
A. The coefficient of variation (CV) gets smaller: The coefficient of variation is the ratio of the standard deviation to the mean. When the standard deviation decreases (due to smaller spread of scores), the CV also decreases.
B. The interquartile range (IQR) gets smaller: The IQR represents the range between the first quartile and the third quartile. When the spread of scores decreases, the values at the first and third quartiles are closer together, resulting in a smaller IQR.
C. The standard deviation gets smaller: The standard deviation measures the average distance of data points from the mean. As the spread of scores decreases, the data points are closer to the mean, resulting in a smaller standard deviation.
In summary, when the spread of scores around the arithmetic mean gets smaller, the coefficient of variation, interquartile range, and standard deviation all decrease.
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enter the area of the triangle in square units rounded to the nearest 10th
PLS PLS PLS HELP
Answer:
\(22cm {}^{2} \)
Step-by-step explanation:
\(the \: area \: = \: \frac{1}{2} \times (bh) = \frac{1}{2} (4 \times 11) \\ = \frac{1}{2} (44) = 22 {cm}^{2} \)
What is the answer to this? Please send help
Step-by-step explanation:
steps are in the picture.
Note:if you need to ask any question please let me know.The YMCA lap pool is a right rectangular prism 36.8\, \text{m}36.8m36, point, 8, start text, m, end text long by 20 \,\text{m}20m20, start text, m, end text wide. The pool contains 1472 \text{ m}^31472 m 3 1472, start text, space, m, end text, cubed of water. How deep is the water in the pool
Volume is a three-dimensional scalar quantity. The depth of the YMCA lap pool is 2 meters.
What is volume?A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given that the following details about the YMCA lap pool:
The volume of the pool = 1472m³The length of the pool = 36.8mThe width of the pool = 20 mSince the pool is in the space of a right rectangular prism, therefore, the volume of the prism will be the product of length, width and depth. Therefore, the volume of the pool can be written as,
The volume of the pool = Length × width × depth
1472m³ = 36.8m × 20 m × depth of the pool
Depth of the pool = (1472m³ ) / (36.8m × 20m)
= 2 meter
Hence, the depth of the YMCA lap pool is 2 meters.
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The question asks to find all real values of x for which f(x)=0.
Step-by-step explanation:
40.
f(x)=x^2-6x-16
=x^2-8x+2x-16
=x(x-8)+2(x-8)
=(x-8)(x+2)
for root
f(x)=0
(x-8)(x+3)=0
x=8 or -3
41.
=x^3-x
=x(x^2-1)
=x(x+1)(x-1)
for root
x(x+1)(x-1)=0
x=0,1,-1
42.
=x^3-x^2-3x+3
=x^2(x-1)-3(x-1)
=(x-1)(x^2-3)
for root
(x-1)(x^2-3)=0
x=1,-√3,√3
X and Y together can complete a piece of work in 4 days. If X alone can
complete the same work in 12 days.
that work?
plz Do it step-by-step.
2. sonia is planning on taking a trip and has allocated $3600 (in canadian dollars) to spend on airfare, accommodations, and food in a ratio of 4:3:2. (a) how much will sonia spend on each category (airfare, accommodations, food)?
Sonia will spend $1600 on airfare , $ 1200 on accommodations and $ 800 on food .
What is division ?Multiplication is the polar opposite of division. If three groups of four add up to 12, then division of 12 into three groups of equal size yields four in each group.The basic objective of splitting is to count the number of equal groups that are created or the number of individuals in each group after a fair distribution.
Given that: She has allocated $3600 (in canadian dollars) to spend on airfare, accommodations, and food in a ratio of 4:3:2.
She has allocated $3600 (in canadian dollars) to spend on airfare, accommodations, and food in a ratio of 4:3:2.
let the sonia spend x
4x + 3x +2x = $3600
9x = $3600
x=$400
On airfare sonia will spend 4 × $400 = $1600
On accommodations sonia will spend 3 × $400 =$1200
On food sonia will spend 2 × $400 = $800
Sonia will spend $1600 on airfare , $ 1200 on accommodations and $ 800 on food .
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What is the approximate diameter of a sphere with a volume of 34cm to the third power?
A. 5cm
B. 4cm
C. 6cm
D. 2cm
Answer:
B
Step-by-step explanation:
College Algebra Applied Problem Four A medical professional is helping an individual balance their diet. The individual has asked for some certain foods to remain in their diet. They will always get 600 calories from carbohydrates. The individual says that they can be flexible about how many calories they consume in fats and proteins. The goal of the diet is to keep the individual at 1,800 calories per day ( 600 of which come from carbohydrates). Part One Write an equation that models the amount of calories from fats " f ' and protein "p" that the individual can consume in order to reach 1,800 calories. Part Two The diet being prescribed to the individual calls for calories from protein to be three times the calories from fat. Write an equation based on this information that relates calories from protein "p" to calories from fat " f ". Part Three Use your equations from parts "b" and "c" to solve this system of equations and determine the amount of calories that the individual should consume from fats and proteins. Part Four If the individual no longer required 600 calories from carbohydrates, and instead said that they would be flexible about how many carbohydrates they would consume, how many variables would there be for this problem on calories?
The system equation that models the amount of calories from fats (f) and proteins (p) that the individual can consume to reach 1,800 calories is: f + p = 1,200. The equation that relates calories from protein (p) to calories from fat (f) based on the prescribed diet is: p = 3f. Solving the system of equations, we find that the individual should consume 300 calories from fats and 900 calories from proteins.
To find the equation that models the amount of calories from fats and proteins that the individual can consume in order to reach 1,800 calories, we consider that 600 calories will come from carbohydrates. Since the total goal is 1,800 calories, the remaining calories from fats and proteins should add up to 1,800 - 600 = 1,200 calories. Therefore, the equation is f + p = 1,200.
Based on the prescribed diet, the individual is required to consume calories from protein that are three times the calories from fat. This relationship can be expressed as p = 3f, where p represents the calories from protein and f represents the calories from fat.
To solve the system of equations, we substitute the value of p from the second equation into the first equation: f + 3f = 1,200. Combining like terms, we get 4f = 1,200, and dividing both sides by 4 yields f = 300. Substituting this value back into the second equation, we find p = 3(300) = 900.
Therefore, the individual should consume 300 calories from fats and 900 calories from proteins to meet the diet requirements and achieve a total of 1,800 calories.
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Calculate the area of the irregular polygon shown below:
21 square inches
22 square inches
26 square inches
29 square inches
Answer:
26
Step-by-step explanation:
What is the probability that the number pyramid will land on three and the spinner will stop on blue
The probability that the number pyramid will land on three and the spinner will stop on blue is 1/24.
To determine the probability that the number pyramid will land on three and the spinner will stop on blue, we need to know the total number of possible outcomes for both events and the number of favorable outcomes for the desired outcome.
Let's assume that the number pyramid has six sides numbered from one to six, and the spinner has four sections colored blue, red, green, and yellow. If both the number pyramid and spinner are fair and unbiased, each outcome is equally likely.
Number pyramid outcomes: There are six possible outcomes, namely numbers one to six.
Spinner outcomes: There are four possible outcomes, namely blue, red, green, and yellow.
To find the probability of both events happening together, we need to multiply the probabilities of each event occurring individually, assuming they are independent events (i.e., the outcome of one event does not affect the outcome of the other).
Probability of landing on three: Since the number pyramid has six sides, and we want to land on three, there is only one favorable outcome (three) out of the six possible outcomes. Therefore, the probability of landing on three is 1/6.
Probability of stopping on blue: Since the spinner has four sections, and we want it to stop on blue, there is only one favorable outcome (blue) out of the four possible outcomes. Therefore, the probability of stopping on blue is 1/4.
To find the probability of both events occurring, we multiply these probabilities:
Probability of landing on three and stopping on blue = (1/6) * (1/4) = 1/24
Therefore, the probability that the number pyramid will land on three and the spinner will stop on blue is 1/24.
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Rachel wants to use cottage cheese and yogurt to increase the amount of protein and calcium in her daily diet. An ounce of cottage cheese contains 3 grams of protein and 12 milligrams of calcium. An ounce of yogurt contains 1 gram of protein and 44 milligrams of calcium. How many ounces of cottage cheese and yogurt should Rachel eat each day to provide 57 grams of protein and 840 milligrams of calcium?
Answer:
She needs to eat 5 ounces of cheese and 1 ounce of yogurt
Step-by-step explanation:
Rachel should have 15 ounces of yogurt and 14 ounces of cheese.
What is the solution to a linear equation?The solution of a linear equation is defined as the points, in which the lines represent the intersection of two linear equations. In other words, the solution set of the system of linear equations is the set of all possible values to the variables that satisfies the given linear equation.
Given here: An ounce of cottage cheese contains 3 grams of protein and 12 milligrams of calcium. An ounce of yogurt contains 1 gram of protein and 44 milligrams of calcium. let Rachel have x ounces of cheese and y ounces of yogurt. Then we have the following equations
3x+y=57
0.012x+0.044y=0.84
Solving these two equations we get y=15.3 or 15 ounces (approx)
and x= 13.9 or 14 ounces(approx) respectively.
Hence, Rachel should have 15 ounces of yogurt and 14 ounces of cheese.
Learn more about the solutions of linear equations here:
https://brainly.com/question/545403
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