in the analysis of stability and control, we work with partial derivatives. if C_L,t = Aα^2_T + Bδ^3_e, calculate dC_L,t/dα_e and dC_L,t/dδ_e.

Answer:

False

Explanation:

Fusion doesn't produce more.

Explanation:

cuboid; rectangular prism):V=l×w×hwhere: l−long; w−wide; h−high−−−−−−−−−−−−−−−−−−−−−−−−−−−−−l=5cm; w=4cm; h=6cmthereforeV=5×4×6=120 (cm3)

therefore

<4×6= 120(cm³)

Given data

*The given height of the building h = 56 m

*The distance from the base is d = 45 m

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The formula for the time taken by the lemming is given as

Substitute the known values in the above expression as

The formula for the lemming's initial speed is given as

Substitute the known values in the above expression as

Hence, the lemming's initial speed is v = 13.3 m/s

According to the question the rotational kinetic energy of a 12-kg motorcycle wheel is 809.14 J

The SI unit for rotational kinetic energy is the joule (J). The rotating kinetic energy formula has a similar structure to a translational kinetic energy equation. Kinetic energy is created by spinning objects around an axis. This type of energy is influenced by the object's mass, weight, and center of mass angle with respect to the axis.

Given data -

Mass = 12-kg

Angular velocity (ω) -120rad/s

inner radius = 0.280 m

outer radius = 0.330 m.

By using the formula

I = ½*M (r1² + r2²)

I = ½ *(12) * (0.2802 + 0.3302)

I = 1.1238 Kgm2

K.E = ½*Iω2

K.E = ½ * (1.1238)*(120)2

K.E = 809.14 J

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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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Answer:

E' = Qa/4πε[√(a² + z²)]³

Explanation:

Since the non-conducting plate is symmetric, a small charge element dq generates an electric field dE at a distance R from itself and a distance z above the center of the plate. Since the plate is symmetric, we only have the vertical component of the electric field acting at the center so dE' = dEcosθ where θ is the angle between R and the plate.

So, dE' = dEcosθ = dqcosθ/4πεR²

Let σ represent the surface charge density of the plate. So, for a small elemental area dA, dq = σdA.

Substituting this into dE' we have

dE' = σdAcosθ/4πεR²

Also cosθ = a/R where a is half the length of side of the plate of side length, 2a.

So, dE' = σdAa/4πεR³

Also R² = a² + z²

R = √(a² + z²)

So,  dE' = σdAa/4πε[√(a² + z²)]³

Now, dA = dxdy

dE' = σadxdy/4πε[√(a² + z²)]³

So, the total electric field at z is obtain by integrating dE'

E' = ∫dE' = ∫σadxdy/4πε[√(a² + z²)]³ = σa∫dxdy/4πε[√(a² + z²)]³

We integrate dx and dy from -a to a.

So,

E' = σa[2a][2a]/4πε[√(a² + z²)]³

E' = σa³/πε[√(a² + z²)]³

Since the total chare Q = σA where A is the are of the plate. A = (2a)² = 4a²

Q = σA = 4σa²

σ = Q/4a²

substituting σ into E', we have

E' = (Q/4a²)a³/πε[√(a² + z²)]³

E' = Qa/4πε[√(a² + z²)]³

Answer:

Explanation:

Magnetic field = permeability x turn density x current

Magnetic field = 0.22T

turn density = 4150 /1.6 = 2593.75 t/m

permeability : µ = k µ°

µ°= 4 π 10^-7

k = 1

I = 0.22 / 4 π 10^-7 * 2593.75 = 0.22 10^7 /32594 = 67.497 A

The oscillator loses 0.156% of its mechanical energy during each cycle. As the system continues to oscillate, the amplitude will continue to decrease, and the percentage of energy lost in each cycle will increase.

The amplitude of a lightly damped oscillator decreases by 3.08% during each cycle, indicating that the system is losing energy with each oscillation. The percentage of mechanical energy lost in each cycle can be calculated using the following formula:

Percentage of energy lost = \($(1 - e^{-\zeta \pi})$\)

Where ζ is the damping ratio, and e is the mathematical constant approximately equal to 2.71828. The damping ratio is a dimensionless parameter that characterizes the system's response to damping. For a lightly damped oscillator, the damping ratio is small, typically less than 1.

Given that the amplitude of the oscillator decreases by 3.08% during each cycle, we can calculate the damping ratio as follows:

\($\zeta = \frac{\ln(1 - 0.0308)}{-\pi}$\)

ζ = 0.005

Substituting this value of ζ into the formula above gives us:

Percentage of energy lost = \($(1 - e^{-0.005\pi}) \times 100%$\)

Percentage of energy lost = 0.156%

Therefore, it is essential to minimize damping in mechanical systems to reduce energy loss and increase efficiency.

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Answer:

The total kinetic energy of the car can be divided into two parts: translational kinetic energy, due to the car's motion as a whole, and rotational kinetic energy, due to the rotation of the wheels about their axles.

The translational kinetic energy of the car is given by:

KE_translational = (1/2)mv^2

where m is the mass of the car and v is its speed.

The rotational kinetic energy of each wheel can be calculated as:

KE_rotational = (1/2)Iω^2

where I is the moment of inertia of a wheel and ω is its angular velocity.

The moment of inertia of a uniform disk is given by:

I = (1/2)mr^2

where m is the mass of the disk and r is its radius.

The mass of each wheel is given as 12 kg, so the moment of inertia of each wheel is:

I = (1/2)(12 kg)(0.5 m)^2 = 1.5 kg·m^2

Assuming that the wheels are rolling without slipping, the angular velocity of each wheel can be related to the speed of the car by:

v = rω

where r is the radius of the wheel.

Solving for ω, we get:

ω = v/r

Substituting this expression into the equation for KE_rotational, we get:

KE_rotational = (1/2)(1.5 kg·m^2)(v/r)^2

Simplifying, we get:

KE_rotational = (3/8)mv^2

So the rotational kinetic energy of each wheel is (3/8) of the translational kinetic energy of the car.

The total rotational kinetic energy of all four wheels is therefore:

KE_total_rotational = 4 KE_rotational = (3/2)mv^2

The total kinetic energy of the car is:

KE_total = KE_translational + KE_total_rotational = (5/2)mv^2

So the fraction of the total kinetic energy of the car that is due to the rotation of the wheels about their axles is:

KE_total_rotational / KE_total = (3/5) = 0.6

Therefore, 60% of the car's total kinetic energy is due to the rotation of the wheels about their axles.

When a below glide slope indication is shown by a pulsating approach slope indicator, it means that the aircraft is below the desired glide slope. The pulsating approach slope indicator is a system of lights that can be used to help pilots maintain the correct descent rate while landing on an instrument approach.

This is accomplished by using a series of red and white lights that are arranged in a horizontal line. The aircraft is on the correct glide slope when the pilot sees two white lights and two red lights. When the aircraft is above the desired glide slope, the pilot will see more white lights than red lights. When the aircraft is below the desired glide slope, the pilot will see more red lights than white lights. In the event that the pilot sees a below glide slope indication from a pulsating approach slope indicator, they must adjust their descent rate to increase the aircraft's altitude and bring it back up to the desired glide slope.

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Answer: 1.44m/s West

Explanation:

Given the following :

Mass of skater = 60kg

Average force = 240N east

Time of = 0.360 seconds

The Velocity after 0.360seconds

Recall the relation:.

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)

Ft = mV

240 × 0.360 = 60 × V

60 × V = 86.4

V = 86.4 / 60

V = 1.44m/s

According to Newton's third law, to every action, there is an equal and opposite reaction.

The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force

Therefore, velocity is 1.44ms West

The force exerted by the pillow on the bowling ball was 0 N.

The force exerted by the pillow on the bowling ball was equal to the mass of the bowling ball multiplied by the acceleration of the bowling ball due to the pillow's force.

This force is equal to the rate of change of momentum of the bowling ball, which is equal to the mass times the acceleration, or F=ma.

To calculate the acceleration, we can use the equation a = (vf-vi)/t, where vf is the final velocity of the bowling ball, vi is the initial velocity of the bowling ball, and t is the amount of time it took for the bowling ball to come to rest. For this problem, the final velocity is 0 m/s, the initial velocity is unknown, and the time is 0.67 seconds, so we can solve for the acceleration: a = 0 / 0.67 = 0 m/s^2.

Finally, we can solve for the force by multiplying the mass of the bowling ball (500 kg) by the acceleration (0 m/s^2): \(F = 500kg * 0 m/s^2 = 0 N.\)

Therefore, the force exerted by the pillow on the bowling ball was 0 N.

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Answer:

There is 18

Explanation:

Answer:

females

Explanation:

The ova(egg) starts meiosis as a foetus but doesn't complete it until puberty. This is when the menstrual cycle will start to occur indicating the gametes( egg) is maturing and if not fertilized will be removed.

After getting the acceleration of the object, the calculated velocity is 8 m/s

Velocity is the distance travelled by an object in a specific direction. It is a vector quantity. And it is measured m/s

Given that a force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg, before we calculate its velocity, we need to calculate its acceleration by using the formula

F = ma

Where

Substitute the parameters into the formula

80 = 10a

a = 80/10

a = 8 m/s

To calculate its velocity, use the formula

v² = u² + 2as

where u = 0

v² = 0 + 2 × 8 x 4

v² = 64

v = √64

v = 8 m/s

Therefore, the velocity of the object is 8 m/s

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Answer:

6.76875 • 10 ^-10 F

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 3.61 • 10^-4

D = 4.72 • 10 ^-6

So:

C = (8.85 • 10^-12)(3.61 • 10^-4)/4.72 • 10 ^-6 = 6.76875 • 10 ^-10 F

Good Luck!  :)

Answer:

Therefore, the magnitude of the acceleration of the particle at the instant when its velocity is zero is approximately 18.258 m/s².

Explanation:

To find the magnitude of acceleration at the instant when velocity is zero, we need to differentiate the given velocity equation with respect to time (t) to obtain the acceleration equation.

Given:

Velocity equation: v(t) = 22 - 3.8t^2

Differentiating the velocity equation with respect to time, we get:

a(t) = d(v(t))/dt = -2 * 3.8t

To find the magnitude of acceleration at the instant when velocity is zero, we need to solve for t when v(t) = 0.

0 = 22 - 3.8t^2

3.8t^2 = 22

t^2 = 22/3.8

t^2 ≈ 5.789

Taking the square root of both sides, we find:

t ≈ √(5.789)

t ≈ 2.403

Now we can substitute this value of t into the acceleration equation to find the magnitude of acceleration at that instant:

a(t) = -2 * 3.8 * 2.403

a(t) ≈ -18.258

Therefore, the magnitude of the acceleration of the particle at the instant when its velocity is zero is approximately 18.258 m/s².

Answer:

But if you place a clear container filled with hydrogen gas between the flashlight and the prism, gaps appear in the smooth rainbow of colors, places where the light literally goes missing. The dark absorption lines of a star at rest (left) get shifted towards red if the star is moving away from Earth (right)

Explanation:

The required wavelength for the photon necessary to induce the given transition is calculated to be 5.163 × 10⁻³¹ m.

The energy difference between the ground state and an excited electronic state is 3.85 × 10⁵ j/mol.

ΔE = 3.85 × 10⁵ j/mol

We know that,

Planck's constant h = 6.626 × 10⁻³⁴ Js

Speed of light c = 3 × 10⁸ m/s

The formula for ΔE is known as, ΔE = E₂ - E₁ = h c/λ

where, λ is the wavelength

Making λ as subject in the above formula, we have,

ΔE = h c/λ

λ = h c/ΔE

λ = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(3.85 × 10⁵) = 5.163 × 10⁻³¹ m

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Answer:

Explanation:

F = ma

F = 4*4 = 16

A permanent bar magnet with the south pole pointing downward is dropped through a Solenoid, as shown in the illustration.

The direction of the induced current that would be measured in the ammeter as the magnet falls completely through the solenoid is given by the left-hand rule.

According to this rule, if the thumb of the left hand points in the direction of the force on a positive charge, then the fingers will point in the direction of the magnetic field that is generating the force, and the palm will face in the direction of the motion of the charge.

The magnetic field in the solenoid is perpendicular to the direction of motion of the magnet, and the force generated is towards the center of the solenoid. Therefore, the induced current that would be measured in the ammeter as the magnet falls completely through the solenoid is in a clockwise direction.

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Answer: chemical

Explanation: To change from hydrogen to oxygen is a chemical change because if you change hydrogen to oxygen, it is still a chemical. The answer is chemical.

Answer:

chemical possibly

Explanation:

fact

The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

The switch that adjusts the magnetic field to be either nearly uniform or have a strong gradient will affect the current in the two coils differently.

When the magnetic field is nearly uniform at the center, the current in both coils will remain relatively unchanged. The uniform field will not induce any significant voltage in the coils, so the current will flow through them as usual.

However, when the magnetic field has a strong gradient, the current in the two coils will be affected differently. The rapidly changing field will induce a voltage in the coils according to Faraday's law of electromagnetic induction. This induced voltage will result in a change in the current flowing through the coils. The magnitude and direction of the induced current will depend on the specific characteristics of the coils and the magnetic field gradient.

In summary, the switch that changes the magnetic field from uniform to having a strong gradient will induce a change in the current flowing through the coils due to the induced voltage.

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The Earth's blackbody temperature would be approximately 303 K (or 30 degrees Celsius) in this scenario, assuming the Earth's albedo remains the same.

This can be calculated using the Stefan-Boltzmann law, which states that the amount of radiation emitted by a blackbody is proportional to its fourth power temperature. Since the Sun's luminosity is 10 times greater, the Earth would receive 10 times more energy and therefore its temperature would increase. Specifically, the temperature would increase by the fourth root of 10 (since the energy received by the Earth is proportional to the square of the distance from the Sun). This calculation results in a temperature increase of about 1.8 times, or approximately 48 degrees Celsius. Therefore, adding this to the Earth's current blackbody temperature of 255 K gives a new temperature of approximately 303 K.

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The blackbody temperature of the Earth would be 255 K x 1.78 = 453.9 K.

According to the Stefan-Boltzmann law, the temperature of a blackbody is directly proportional to the fourth root of its luminosity. Therefore, if the Sun had exactly 10 times its current luminosity, the Earth's blackbody temperature would increase by the fourth root of 10, which is approximately 1.78. So, the new blackbody temperature of the Earth would be 255 K x 1.78 = 453.9 K.

This is significantly higher than the current blackbody temperature of the Earth, and would likely result in a much warmer planet. It is important to note that this calculation assumes that the Earth's albedo remains the same, even though an increase in temperature could potentially lead to changes in the Earth's albedo.

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Answer:

Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.

Explanation:

Answer:

Explanation:

Cosmologists refer to a "surface of last scattering" when the CMB photons last hit matter; after that, the universe was too big. So when we map the CMB, we are looking back in time to 380,000 years after the Big Bang, just after the universe was opaque to radiation. But the CMB was first found by accident.

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Answer:

48.93km = distance        22km = displacement

Explanation

to find distance add all of them up

21.2 + 18.23 + 9.5 = 48.93km

distance is just the total amount traveled, displacement on the other hand is how far away you are from the starting place.

To find displacement you want to basically create a triangle. Lets say you have x and y (vertical) axis. you got 21.2 along x and -9.5 along x so that is a total of 11.7 along x axis.

then you move 18.23 along the y axis. Draw a triangle using 11.7 and 18.23 and find the hypotenuse.

to do this use Pythagorean theorem which is c^2 = a^2 + b^2

so 11.7^2+18.23^2 = 469.2229, then take the square root of that and you get 21.661km or 22km with sig figs.

hope this makes sense!

In the context of research evidence from the study conducted by Williams and McCririe, both central and peripheral vision operate when a person picks up information critical to catching an object.

What is vision?

Vision is the sense that allows us to recognize and understand the physical world around us. Our brains then receive this information and convert it into the pictures that we see with our eyes.

Vision is the term used to describe the ability to see things with our eyes, such as color, form, and movement.

In the context of research evidence from the study conducted by Williams and McCririe, both central and peripheral vision operate when a person picks up information critical to catching an object.

Their research found that peripheral vision was essential to athletes performing in certain sports such as cricket, soccer, and baseball.

Peripheral vision, as well as central vision, are critical components of efficient eye tracking and hand-eye coordination.

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