Using Riemann sums with four subdivisions in each direction, find upper and lower bounds for the volume under the graph of f(x,y)=8+3xy above the rectangle R with 0≤x≤3,0≤y≤5. upper bound = lower bound =

Answer:

Step-by-step explanation:

If M is the midpoint of the segment AB, then AM+MB = AB. Given the following parameters;

AM=9x-5 and MB=15-x

Required parameter

segemnt AB

Substituting the given parameters into the given formula to get AB we will have;

AB = AM+MB

AB = 9x-5+15-x

collect like terms

AB = 9x-x-5+15

AB = 8x+10

Hence the length of segment AB is 8x+10

Hai!

You would make 110$

Brainliest maybe?

The given equation's answer is \($z+5=55\left(5^z\right):$\) \($z=-\frac{W_{-1}\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}$\), \($z=-\frac{\mathrm{W}_0\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}$\)

\($z+5=55\left(5^z\right):$\) \($z=-\frac{W_{-1}\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}$\), \($z=-\frac{\mathrm{W}_0\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}$\)

\((Decimal: $z=-1.75934 \ldots, z=-4.98187 \ldots$ )\)

\($$z+5=55\left(5^z\right)$$\)

Prepare \($z+5=55\left(5^z\right)$\) Lambert form: \($(z+5) e^{-\ln (5) z}=55$\)

the equation once more using \($(-z-5) \ln (5)=u$\) and \(z=-\frac{u+5 \ln (5)}{\ln (5)}$\)

\($$\left(\left(-\frac{u+5 \ln (5)}{\ln (5)}\right)+5\right) e^{-\ln (5)\left(-\frac{u+5 \ln (5)}{\ln (5)}\right)}=55$$\)

\($$e^{u+5 \ln (5)}\left(-\frac{u+5 \ln (5)}{\ln (5)}+5\right)=55$$\)

Rewrite \($e^{u+5 \ln (5)}\left(-\frac{u+5 \ln (5)}{\ln (5)}+5\right)=55$\)in Lambert form: \($e^u u=-\frac{11 \ln (5)}{625}$\)

Solve \($e^u u=-\frac{11 \ln (5)}{625}: \quad u=\mathrm{W}_{-1}\left(-\frac{11 \ln (5)}{625}\right), u=\mathrm{W}_0\left(-\frac{11 \ln (5)}{625}\right)$$$u=\mathrm{W}_{-1}\left(-\frac{11 \ln (5)}{625}\right), u=\mathrm{w}_0\left(-\frac{11 \ln (5)}{625}\right)$$\)

Substitute back \($u=(-z-5) \ln (5)$\) , solve for z

\($$\begin{aligned}& \text { Solve }(-z-5) \ln (5)=W_{-1}\left(-\frac{11 \ln (5)}{625}\right): \quad z=-\frac{W_{-1}\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)} \\& \text { Solve }(-z-5) \ln (5)=W_0\left(-\frac{11 \ln (5)}{625}\right): z=-\frac{W_0\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)} \\& z=-\frac{W_{-1}\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}, z=-\frac{W_0\left(-\frac{11 \ln (5)}{625}\right)+5 \ln (5)}{\ln (5)}\end{aligned}$$\)

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Incomplete question. I inferred you want to know the properties of parallel and perpendicular lines. Which I provided below.

Explanation:

In geometry, parallel lines are two lines that are always drawn at the same distance apart and never touch each other. Parallel lines are usually denoted by the symbol ∥.

Here are some of their properties;

When a transversal intersects two parallel lines:

Perpendicular lines are two lines that meet at a right angle (90 degrees) to each other.

Properties: two lines that meet, implies all four angles are right angles.

The critical value for the 0.05 level of significance is k = 21.

To find the critical value, we can use the binomial distribution. The binomial distribution models the number of successes in n independent Bernoulli trials, each with probability p of success. In this case, the number of successes is the number of dog owners who say Woof Chow is their regular brand, and the number of trials is n = 100. The null hypothesis is that the true market share of Woof Chow is 25%, and the alternative hypothesis is that it is not 25%.

We can use the binomial cumulative distribution function (CDF) to find the critical value. The CDF gives the probability of getting k or fewer successes in n trials, given a probability of success p. The critical value is the smallest value of k such that the CDF at k is greater than or equal to 1 - alpha, where alpha is the level of significance. In this case, alpha = 0.05.

So, we want to find the smallest k such that:

P(X <= k) >= 1 - 0.05

where X is a random variable representing the number of dog owners who say Woof Chow is their regular brand. We can use a binomial calculator or a software package to calculate the binomial CDF, or we can use a table of critical values for the binomial distribution.

The critical value for the 0.05 level of significance is k = 21. This means that if the true market share of Woof Chow is 25%, then the probability of getting 23 or more dog owners who say Woof Chow is their regular brand is less than 0.05. Since the observed number of dog owners who say Woof Chow is their regular brand is 23, which is greater than 21, we can reject the null hypothesis that the true market share is 25%.

This means that based on the survey results, we cannot conclude that Woof Chow has a market share of 25%. The survey results suggest that Woof Chow may have a market share that is greater than 25%.

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Answer:

142.75

Step-by-step explanation:

Answer: It would take the bug 26min to clime the pole

Step-by-step explanation: For me I drew a pole and labeled it like a number line.

1. use or make a number line and plot 0-10 on it.

2. jump 2 points from 0 on the number line

3. Jump backwards once to make the equation accurate

4. plot the times it takes along the way to find the answer until you get to 10

I hope

Answer:

thank you for points....

The numerical expressions represent the final depth of the diver will be the negative 200 + 12 1/3 (4.5). Then the correct option is C.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

A diver begins at sea level and dives down 200 feet.

He ascends at a steady rate of 12 1/3 for 4.5 minutes.

Then the numerical expressions represents the final depth of the diver will be

Let the negative sign for the downward and the positive sign for upward.

Then we have

⇒ - 200 + 12 1/3 (4.5)

Then the correct option is C.

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Selling price = $6.37 .

Selling price = $6.94

Selling price = $346.80

1)

Sales revenue = 6,000

Less:-Variable costs ($1.5 per unit 1,000) = 1,500

Less:- Fixed costs = (1,700)

Operating Income = 2,800

Variable costs and Fixed costs have increased.

Hence, in order to maintain the same Operating Income, the selling price should be higher than the current selling price .

Thus to maintain same operating income the selling price should be $6.37 .

2)

The computation is given below:

Sales price = ( Total sales revenue ÷ packages sold)

Total sales revenue = ( Total Cost + Operating income )

Total Cost = ( Variable Cost + Fixed cost)

Now

Variable cost = 1,000 packages × $1.90 per unit

= $1,900

Fixed cost = $1,700 × 120%

= $2040

Total cost = $1,900 + $2,040

= $3,940

Now  

Total sales revenue is

= $3,940 + $3,000

= $6,940

Now  

Sales price = $6,540 ÷ 1,000 packages

= $6.94

3)

-Fruit Computer Company has variable costs of $220 per unit and fixed costs of $32,000 per month.

- The company currently sells 500 units per month at a sales price of $300.

Net margin = $8000

- The company wants to increase its operating income by 30%.

- If the company upgrades the computer quality, the variable cost per unit will increase to $240 and the fixed costs will rise by 50%.

Thus the selling price per unit will be  $346.80 per unit.

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To answer your question, let's consider the set U = {2, 4, 5, 6, 7, 3, 5}, and let W be the set of all x in R³ such that U * x = 0. The theorem in Chapter 4 that can be used to show that W is a subspace of R³ is the "Subspace Theorem."

The Subspace Theorem states that a subset W of a vector space V is a subspace if it satisfies the following three conditions:
1. The zero vector of V is in W.
2. If u and v are in W, then their sum (u+v) is in W.
3. If u is in W and c is a scalar, then the product (cu) is in W.

To describe W in geometric language, W would be a plane or a line that passes through the origin in R³, which is orthogonal (perpendicular) to the given vector U. This is because all the vectors x in W have a dot product of 0 with U, indicating that they are orthogonal to U.

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The curve joining the points P1, P2, P3, and so on is called the involute of a circle.

To construct the locus of the free end of the coir for unwinding through an angle of 360 degrees, as well as the normal and tangent at any point on the curve.

Here are the steps for construction:

1. Draw a line PQ that is tangent to the circle and is equal to the circumference of the circle. This line represents the coir being unwound.

2. Divide both the circle and the tangent line into the same number of equal parts. Label these divisions on the circle as 1, 2, 3, and so on. Similarly, label the divisions on the tangent line as 1', 2', 3', and so on.

3. Draw tangents at points 1, 2, 3, and so on on the circle. Mark the points where these tangents intersect the tangent line as P1, P2, P3, and so on.

The distance from each point Pi to the corresponding point i' on the tangent line should be the same as the distance from the center of the circle to the point i on the circle.

4. The curve joining the points P1, P2, P3, and so on is called the involute of a circle. This curve represents the locus of the free end of the coir as it unwinds.

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The process involves creating an initial circle that represents the drum, then using this to draw a horizontal line that's the same length as your first circle's circumference. Divide both into segments and draw lines (tangents) from one set of segments to the other. Points along these lines represent an unwound thread and create the involute when joined up. Tangents and normals can also be drawn onto this curve.

This question pertains to the mathematical concept of a curve locus, specifically the spiral curve produced by unwinding a coir from a drum. To draw this spiral curve (or 'involute'), start by sketching a circle representing the drum (with diameter 30mm). Next, calculate the circumference of this circle and draw a horizontal line of equivalent length. Then, divide this line and the circumference of your circle into the same number of equal sections. For each section in your circle, draw a line from the point of division to an equivalent point on your horizontal line. These lines are your tangents. Mark points on these lines which correspond to the distances covered by the unwound thread. Finally, join these points to create the involute of the circle.

For the part about drawing a normal and a tangent at any point on the curve: Pick a point on the curve. Remember that the tangent at a point on an involute is perpendicular to the line from the point to the centre of the original circle. A normal at any point on a curve is simply a line drawn perpendicular to the tangent at that point.

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Answer:

To calculate the approximate sample mean for student applications, in thousands, you can sum up the total number of student applications for the 12 semesters and then divide by 12.

Add up the total number of student applications for the 12 semesters:

106 + 137 + 285 + 120 + 202 + 195 + 327 + 139 + 307 + 318 + 212 + 217 = 2,563

Divide the sum by 12 to get the sample mean:

2,563 / 12 ≈ 213.6

So, the approximate sample mean for student applications, in thousands, is approximately 213.6.

Answer: D. 214

Step-by-step explanation:

Answer:

Area of the shaded region = 51 cm²

Step-by-step explanation:

Area of the smaller pentagon ABKHG = 17 cm²

Since, B is the midpoint of side AC,

Scale factor used to enlarge the sides = \(\frac{\text{Measure of side AC}}{\text{Measure of side AB}}\)

                                                                = \(\frac{AC}{\frac{AC}{2}}\)

                                                                = 2

Therefore, area scale factor of both the pentagons = (Dimensional scale factor)²

2² = \(\frac{\text{Area of AFEDC}}{\text{Area of ABKHG}}\)

4 = \(\frac{\text{Area of AFEDC}}{17}\)

Area of bigger pentagon AFEDC = 4 × 17

= 68 cm²

Area of the shaded region = Area of the bigger pentagon - Area of the smaller pentagon

= 68 - 17

= 51 cm²

The probability that, in any hour, less than 2 customers will arrive is 0.0087 ( round to four decimal places).

The Poisson distribution is a discrete probability distribution that helps to calculate the probability of an event occurring within a given time interval. The average (mean) rate of occurrence within a given time interval ( in hour, day etc) is well known, but exact timing is unknown. The occured events are independent from each other.

We have , at the fidelity credit union

Mean , m = 6.8

let X be random variable for the customers arrive hourly at the drive-through window.

We have to calculate the probability that, in any hour, less than 2 customers will arrive, P(X< 2) .

Using Poisson probability distribution formula

P(X= x ) = e⁻ᵐ ( ᵐ )ˣ/ x!

Where:

here, x <2 , m = 6.8

P(X< 2) = P(X = 0 ) + P(X = 1 )

Now, P(X< 2) = e⁻⁶·⁸(6.8)⁰/ 0! + e⁻⁶·⁸(6.8)/ 1!

= e⁻⁶·⁸ + e⁻⁶·⁸(6.8) = e⁻⁶·⁸( 7.8)

= 0.00868744615

Hence, required probability is 0.0086.

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Answer:

-12.5333333333

Step-by-step explanation:

her3e

Answer:

130°

Step-by-step explanation:

Angle 3 and Angle 7 are corresponding angles, therefore they are congruent or equivalent (assuming the lines are parallel).

∠3=∠7

130°=∠7

Answer:

x + 4x = 5x

Step-by-step explanation:

An identity is a mathematical equation that is always true (here - for all possible x's).

a). x + 4x = 5x; this is true, because for any possible x

x+4x = (1 + 4)x = 5x; there's not much to add.

b). 6x=18; evaluates to

x = 3; so it only works for one x, not all possible xs.

c). 2x + 1 = 7

2x = 6

x = 3; so it only forks for one x

d). 7x + 9 = x

6x + 9 = 0; we could compute the exact x it works for from here, but suffice to say this doesn't work for x = 0.

In between these given equations, x + 4x = 5x is the correct identity here.

"An identity is an equality relating one mathematical expression A to another mathematical expression B, such that A and B produce the same value for all values of the variables within a certain range of validity."

Given equations are:

1. x + 4x = 5x

⇒ 5x = 5x

This equation is true for all values of 'x'.

Hence, this is a correct identity.

2. 6x = 18

⇒ x = 3

This equation is true when x = 3.

3. 2x + 1 = 7

⇒ 2x = 6

⇒ x = 3

This equation is true when x = 3.

4. 7x + 9 = x

⇒ 6x = - 9

⇒ x = - 9/6

⇒ x = - 3/2

This equation is true when x = - 3/2.

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Answer:

7/2

Step-by-step explanation:

Answer:

Guess I'll agree with the other person.

Step-by-step explanation:

Answer:

$7910.3

Step-by-step explanation:

Given data

P=$3572

n=4

T=16 years

R= 5%

The compound interest is expressed as

A= P(1+r/n)^nt

Substitute

A=3572(1+0.05/4)^16*4

A=3572(1+0.0125)^64

A=3572(1.0125)^64

A=3572*2.21453241061

A=$7910.3

The Laplace transform of the integral of a function is equal to the ratio of the Laplace transform of the function to the Laplace transform parameter (s).

This can be seen by integrating by parts, which states that ∫b u dv/dt dt = uv|b - ∫b v du/dt.dt. In this equation, u is the function to be integrated, and v is its antiderivative.

By substituting the Laplace transform of each term into this equation, we get L[∫t f(T)dT] = 1/s F(s). This is because the Laplace transform of an antiderivative is equal to the Laplace transform of the function divided by the Laplace transform parameter (s).

In summary, the Laplace transform of the integral of a function is equal to the ratio of the Laplace transform of the function to the Laplace transform parameter (s). This can be seen by integrating by parts, which states that ∫b u dv/dt dt = uv|b - ∫b v du/dt.dt.

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More than 50% of the bottles meet the specifications.

To determine the proportion of bottles that meet the specifications, we need to calculate the process capability index (Cpk).

The formula for Cpk is:

Cpk = min((USL - X) / (3* σ), (X - LSL) / (3 * σ))

Given:

USL = 3 + 0.150 = 3.150 ounces

X = 3.042 ounces

σ = 0.034 ounce

So, Cpk = min((3.150 - 3.042) / (3 * 0.034), (3.042 - 2.850) / (3 * 0.034))

   = min(0.108 / 0.102, 0.192 / 0.102)

   = min(1.059, 1.882)

   = 1.059

To determine the proportion of bottles that meet the specifications, we can use the following table:

Cpk Value       Proportion within Specifications

-----------------------------------------------

< 1.00          Poor

1.00 - 1.33     Fair

1.33 - 1.67     Good

> 1.67          Excellent

Since the Cpk value is 1.059, it falls within the range of 1.00 - 1.33, which corresponds to a "Fair" proportion within specifications.

Therefore, slightly more than 50% of the bottles meet the specifications.

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The number of hours it will take to burn 4 1/4 inches of candle is 8.5 hours in decimal.

Using ratio to solve, find the ratio of candle length to the time taken to burn down

let

4 1/2 : 9 = 4 1/4 : x

9/2 ÷ 9 = 17/4 ÷ x

9/2 × 1/9 = 17/4 × 1/x

1/2 = 17/4x

1 × 4x = 2 × 17

4x = 34

x = 34/4

x = 8.5 hours

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In order to determine how much does Allison pay for her utilitites, it is only necessary to calculate the percentage associated to utilities, given in the table (2.3%) of the Allison's earns ($6,500).

For calculating the 2.3% of 6,500, you simply multiply (2.3/100) by 6,500, just as follow:

(2.3/100)(6,500) = 149.5

Then, the 2.3% of $6,500 is $149.5. Hence, Allison pay $149 for her utilities

True. The variance and standard deviation both quantify how far spaced apart a set of data is from the mean. They cannot be used to calculate the dispersion around the median or mode, or any other center-of-mass metric.

The variance and standard deviation both quantify how far spaced apart a set of data is from the mean. They can therefore be used to calculate the difference between the highest and lowest values in a data set. The standard deviation, which is the square root of the variance, is used to calculate how far away from the mean each result is on average. The average of the squared deviations between each data point and the mean is the variance. The variance and standard deviation cannot be used to quantify the dispersion of data around other measures of center, such as the median or mode, because they only measure the dispersion of data around the mean.

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When a cone with a volume of 5000 m³ is dilated by a scale factor of 15, the volume of the resulting cone is 3375000 m³.

The volume of a cone is given by the formula V = (1/3)πr²h, where r is the radius of the base and h is the height. Since the scale factor of 15 applies to all dimensions of the cone, the new radius and height will be 15 times the original values. Let's assume the original cone has radius r and height h.

After dilation, the new cone will have a radius of 15r and a height of 15h. Plugging these values into the volume formula, we get

V' = (1/3)π(15r)²(15h) = (1/3)π(15²)(r²)(h) = 3375V.

Given that the original cone has a volume of 5000 m³, we can calculate the volume of the resulting cone by multiplying 5000 by 3375:

V' = 5000× 3375 = 3375000 m³.

Therefore, the volume of the resulting cone, after being dilated by a scale factor of 15, is 3375000 m³.

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Answer:

-7 + 3 = -4

-5 + 1 = -4

-3 + (-1) = -4

Step-by-step explanation: