How much energy does it take to raise the temperature of 80g of aluminium 15 degree Celsius

The value of the equilibrium constant (\(K_{eq}\)) for the reaction at 10°C, based on the given initial concentrations, is 1.08. The units of \(K_{eq}\) depend on the units of the concentrations used in the calculation.

The chemical equation for the reaction between nitrogen dioxide (\(NO_2\)) and dinitrogen tetroxide (\(N_2O_4\)) is:

\(N_2O_4(g) = 2NO_2(g)\)

At a certain temperature, the equilibrium constant expression for this reaction is given by:

\(K_{eq} = [NO_2]^2 / [N_2O_4]\)

We can use the given initial amounts of \(N_2O_4\) and \(NO_2\) to calculate the equilibrium concentrations. Since we know the total volume of the container is 1.0 L, we can also calculate the initial and final partial pressures using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

At the beginning of the reaction, we have:

n(\(N_2O_4\)) = 0.0045 mol

n(\(NO_2\)) = 0.30 mol

n(total) = 0.0045 mol + 0.30 mol = 0.3045 mol

The total pressure is:

P(total) = n(total)RT/V = \((0.3045 mol)(0.0821 L atm mol^{-1} K^{-1})(283 K)/(1.0 L) = 7.52 atm\)

The partial pressures of \(N_2O_4\) and \(NO_2\) are:

P(\(N_2O_4\)) = n(\(N_2O_4\))RT/V = \((0.0045 mol)(0.0821 L atm mol^{-1} K^{-1})(283 K)/(1.0 L) = 0.101 atm\)

P(\(NO_2\)) = n(\(NO_2\))RT/V = \((0.30 mol)(0.0821 L atm mol^{-1} K^{-1})(283 K)/(1.0 L) = 6.42 atm\)

At equilibrium, let the concentration of \(N_2O_4\) be x mol/L, and the concentration of \(NO_2\) be 2x mol/L (because the stoichiometric coefficient of \(NO_2\) is 2 in the balanced chemical equation). The equilibrium expression becomes:

\(K_{eq} = ([NO_2]^2) / [N_2O_4]\\= (2x)^2 / x\\= 4x\)

At equilibrium, the partial pressure of \(N_2O_4\)is P(\(N_2O_4\)) = x(RT/V), and the partial pressure of \(NO_2\) is P(\(NO_2\)) = 2x(RT/V). Since the total pressure is 7.52 atm, we have:

P(total) = P(\(N_2O_4\)) + P(\(NO_2\))

= x(RT/V) + 2x(RT/V)

= 3x(RT/V)

Therefore, \(x = P(N_2O_4) / (3(RT/V)) and 2x = P(NO_2) / (3(RT/V)).\)

Substituting these expressions for x and 2x into the equilibrium constant expression, we get:

\(K_{eq} = 4x\\= 4(P(NO_2) / (3(RT/V)))= (4/3)(P(NO_2) / P(total))\\= (4/3)(6.42 atm / 7.52 atm)\\= 1.08\)

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Answer:

unit formula??

Explanation:

When basket ball is dropped from a height, its potential energy decreases and its kinetic energy increases till it reaches the ground. The highest kinetic energy is at ground level.

The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

A ball drops from the top of a building and picks up speed as it descends. Its speed is increasing by 10 m/s every second. What we refer to as motion with constant acceleration is, for example, a ball falling due to gravity.

Thus, The highest kinetic energy is at ground level.

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The graphs of the change of phase of the solid crystalline substance on cooling and on heating are found in the attachment.

Change of phase refers to the physical changes that occur when matter transitions from one state to another.

The three common states of matter are solid, liquid, and gas. The changes of phase between these states are:

Melting: The change of phase from solid to liquid. This occurs when heat is added to a solid, causing its particles to vibrate faster and break apart from their fixed positions, resulting in a liquid.

Freezing: The change of phase from liquid to solid. This occurs when heat is removed from a liquid i.e cooling of the liquid, causing its particles to slow down and come together in a more organized structure, resulting in a solid.

Vaporization: The change of phase from liquid to gas. This can occur in two ways:

a. Evaporation: The process by which a liquid changes to a gas at the surface of the liquid, due to the absorption of heat.

b. Boiling: The process by which a liquid changes to a gas throughout the liquid, due to the absorption of heat.

Condensation: The change of phase from gas to liquid. This occurs when heat is removed from a gas, causing its particles to slow down and come together to form a liquid.

Sublimation: The change of phase from solid directly to gas, without passing through the liquid phase. This occurs when heat is added to a solid, causing its particles to vibrate so fast that they escape directly into the gas phase.

Deposition: The change of phase from gas directly to solid, without passing through the liquid phase. This occurs when heat is removed from a gas, causing its particles to come together to form a solid.

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the theoretical yield of sodium chloride when 36.0 g Na reacts with 75.2 g Cl2  is 91.5g of NaCl.

Molar mass of Na= 22.99

Molar mass of Cl= 35.45

So we have 36/22.99 moles of sodium and 75.3/35.45 moles of chlorine which makes 1.566 moles of Sodium and 2.124 moles of Chlorine. To form sodium chloride, one atom of sodium reacts with one atom of chlorine, so 1.566 moles of sodium will react with 1.566 moles of chlorine. Excess chlorine is 2.124 - 1.566 moles or 0.558 moles. Therefore, all 1.566 moles or 36 grams of sodium will react with 1.566 times 35.45 grams of chlorine or 55.515 to produce 91.51 grams of NaCl.

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Answer:

Plants consume carbon dioxide and release oxygen.

Answer: Photosynthesis

Animals consume oxygen and release carbon dioxide.

Answer: Respiration

Answer:

The answer is C

Explanation:

Answer:

c

Explanation:

The IR spectrum of Acetylferrocene will differ from that of Ferrocene because of the carbonyl stretching and bending modes that appear in the Acetylferrocene.

The IR spectrum of Acetylferrocene will differ from that of Ferrocene due to the carbonyl stretching and bending modes that appear in the Acetylferrocene.

Ferrocene and Acetylferrocene have similar IR spectra since they both have the Fe-Cp stretching and bending modes. The acetyl group of Acetylferrocene is reflected by an intense band in the 1700-1750 cm-1 range, which is due to carbonyl stretching.

                                     In Acetylferrocene, the IR spectra are dominated by the presence of the acetyl group's vibration, resulting in a change in the frequency of stretching vibration from 200 to 220 cm−1. Another change in the IR spectra of Acetylferrocene is the presence of two bands due to C-O stretching at 1230-1260 cm-1 in addition to the appearance of a strong band due to C-H bending vibrations in the 1410-1450 cm-1 region.

                           Ferrocene does not have a carbonyl group, which is why it will not display the carbonyl stretching and bending vibrations in the IR spectra. This is the most significant difference between the two IR spectra. So, we can conclude that the IR spectrum of Acetylferrocene will differ from that of Ferrocene due to the presence of the carbonyl group.

Therefore,  The IR spectrum of Acetylferrocene will differ from that of Ferrocene because of the carbonyl stretching and bending modes that appear in the Acetylferrocene.

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Approximately 200.18 grams of gallium oxide will be produced when 150 grams of gallium reacts with excess oxygen.

To determine the mass of gallium oxide produced when 150 g of gallium reacts with excess oxygen, we need to understand the balanced chemical equation for the reaction between gallium and oxygen.

The balanced equation for the reaction is:

4 Ga + 3 O2 → 2 Ga2O3

From the balanced equation, we can see that 4 moles of gallium react with 3 moles of oxygen to produce 2 moles of gallium oxide (Ga2O3).

To calculate the mass of gallium oxide produced, we need to follow these steps:

Convert the mass of gallium (150 g) to moles.

The molar mass of gallium (Ga) is 69.72 g/mol. Therefore, the number of moles of gallium is:

Moles of gallium = Mass of gallium / Molar mass of gallium

= 150 g / 69.72 g/mol

≈ 2.15 moles

Determine the mole ratio between gallium and gallium oxide.

From the balanced equation, we know that 4 moles of gallium react to form 2 moles of gallium oxide. Therefore, the mole ratio is 4:2, which simplifies to 2:1.

Calculate the moles of gallium oxide produced.

Since the mole ratio is 2:1, the number of moles of gallium oxide produced is half the number of moles of gallium:

Moles of gallium oxide = 2.15 moles / 2

≈ 1.07 moles

Convert moles of gallium oxide to mass.

The molar mass of gallium oxide (Ga2O3) is 187.44 g/mol. Therefore, the mass of gallium oxide produced is:

Mass of gallium oxide = Moles of gallium oxide * Molar mass of gallium oxide

= 1.07 moles * 187.44 g/mol

≈ 200.18 g

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The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.

The following example illustrates single replacement reaction:

A + BC -> AC + B

From the above reaction, we can see that A has replace/displace B to from AC.

With the above information, we can determine the equation that represents single replacement reaction. Details below:

Equation from the questions:

From the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.

Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

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Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

The drying agent will stick to the sides of the container is the visual indicator that enough of a drying agent, such as anhydrous \(\rm MgSO_4\) or \(\rm CaCl_2\), has been added to properly dry an organic solution.

Water can interfere with a variety of organic reactions and change the properties of organic solvents, thus drying agents are used to get rid of it. The fact that anhydrous \(\rm MgSO_4\)and \(\rm CaCl_2\) have a significant affinity for water and may efficiently remove water molecules from the organic solution makes them popular drying agents.

The drying agent will initially interact with any water in the organic solution and generate hydrated salts when it is introduced. The solution may contain clumps or tiny particles of these hydrated salts, giving the impression that it is murky or hazy. However, the cloudiness should progressively go away as the drying agent keeps drying the solution by reacting with the water.

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The addition of orthophosphate ions (PO43-) decreases the solubility of Pb2+ ions by forming insoluble lead orthophosphate (Pb3(PO4)2). This reduces the concentration of free Pb2+ ions in solution. Without orthophosphate, Pb2+ ions remain more soluble and are present as free ions in higher concentrations.

When orthophosphate (PO43-) is added to a solution containing lead ions (Pb2+), it forms an insoluble compound called lead orthophosphate (Pb3(PO4)2). The addition of orthophosphate affects the solubility of lead ions, leading to key differences in the solubility equilibrium and the concentration of free Pb2+.

Without orthophosphate:

In the absence of orthophosphate, the solubility equilibrium of lead compounds, such as lead chloride (PbCl2) or lead nitrate (Pb(NO3)2), can be represented as follows:

PbX2 (s) ⇌ Pb2+ (aq) + 2X- (aq)

The solubility product constant (Ksp) expression for this equilibrium is given by:

Ksp = [Pb2+] [X-]^2

Where [Pb2+] represents the concentration of free lead ions and [X-] represents the concentration of the anion derived from the lead compound.

With orthophosphate:

Upon adding orthophosphate (PO43-), the following reaction occurs between lead ions and orthophosphate ions:

Pb2+ (aq) + 2PO43- (aq) ⇌ Pb3(PO4)2 (s)

Lead orthophosphate (Pb3(PO4)2) is insoluble and precipitates out of the solution. This removal of lead ions from the aqueous phase effectively reduces the concentration of free Pb2+ in the solution.

As a result, the concentration of free Pb2+ decreases in the presence of orthophosphate compared to the situation without orthophosphate. This reduction is due to the formation of the insoluble lead orthophosphate compound, which removes lead ions from the solution and decreases their availability for complexation or further reactions.

Overall, the addition of orthophosphate shifts the equilibrium towards the formation of lead orthophosphate, reducing the concentration of free Pb2+ ions in the solution.

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Answer:

7NH

Explanation:

Using the given mass of the compound (0.520 g) and the calculated moles, we can determine the molar mass of the compound.

To find the molar mass of the compound, we can use the formula:

ΔT = Kf * m

where ΔT is the freezing point depression, Kf is the cryoscopic constant (in this case, 3.90 °C/m), and m is the molality of the solution.

First, we need to calculate the molality (m) of the solution:

m = moles of solute / mass of solvent (in kg)

The mass of the solvent (lauric acid) is given as 4.62 g. Since the unknown compound is a solute, we need to convert its mass to moles:

moles = mass / molar mass

Given that the mass of the unknown compound is 0.520 g, we can now calculate the moles of the compound.

Next, we convert the mass of the solvent to kg by dividing by 1000:

mass of solvent (lauric acid) = 4.62 g / 1000 = 0.00462 kg

Now we can calculate the molality:

m = moles of solute / mass of solvent = (moles of the compound) / (mass of solvent)

Finally, we can use the freezing point depression formula to find the molar mass of the compound:

ΔT = Kf * m

Substituting the given values:

4.20 °C = 3.90 °C/m * m

Now solve for m:

m = (4.20 °C) / (3.90 °C/m)

Once we have the molality, we can calculate the moles of the compound:

moles = molality * mass of solvent (in kg)

Finally, we calculate the molar mass:

molar mass = mass of solute / moles of solute

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Answer:

how many protons, electrons, and nuetrons are being added

Explanation:

Answer:

(a) Mercury

Explanation:

Mercury with chemical symbol (Hg) is also regarded as " quicksilver". It is heavy and silvery in nature and belongs to d-block of the periodic table, it is metallic element and it is liquid at standard conditions of (temperature and pressure). It has Boiling point of about 356.7 °C with Atomic number of 80. It can molten above the temperature of ( −38.8 °C)

The concentration of the solution is 6.56 M.

The concentration of a solution is typically expressed in units of moles per liter (M) or grams per liter (g/L). To determine the concentration of this solution, we need to first calculate the number of moles of NH₃ present in the solution:

Molar mass of NH₃ = 14.01 g/mol + 1.01 g/mol

                                = 17.02 g/mol

Number of moles of NH₃ = 55.82 g / 17.02 g/mol

                                           = 3.28 mol

We need to convert the volume of the solution from milliliters to liters:

500 mL = 0.5 L

Finally, we can calculate the concentration of the solution in units of M:

Concentration = Number of moles / Volume in liters

Concentration = 3.28 mol / 0.5 L = 6.56 M

As a result, the solution concentration is 6.56 M.

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However, I can provide you with a general idea of what happens during hydrolysis. Hydrolysis is a chemical reaction that involves the splitting of a molecule into two or more smaller molecules by adding water.

The water molecule breaks down into a hydrogen ion (H+) and a hydroxide ion (OH-). The hydrogen ion attaches to one part of the molecule, and the hydroxide ion attaches to the other part, causing the bond between them to break. This reaction usually occurs in acidic or basic environments, where the hydrogen ion or hydroxide ion is abundant.
The products formed during hydrolysis depend on the substance being hydrolyzed. For example, when carbohydrates undergo hydrolysis, they break down into simple sugars such as glucose, fructose, and galactose. Proteins break down into amino acids, while fats break down into fatty acids and glycerol.
In conclusion, without knowing the specific substance, it is difficult to provide a detailed answer. However, the process of hydrolysis involves breaking down a substance by adding water and can result in the formation of smaller molecules or ions, depending on the substance being hydrolyzed.

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The molar mass of the gaseous compound is determined to be 140 g/mol. To find the molar mass of the gas, we can use the ideal gas law equation.

Ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15 to it. So, 27 Celsius is equal to 27 + 273.15 = 300.15 Kelvin. Next, we convert the given volume from milliliters to liters by dividing it by 1000. Therefore, 1,200 mL is equal to 1.2 liters.

Now we can plug in the values into the ideal gas law equation: (740 mmHg)(1.2 L) = n(0.0821 L·atm/mol·K)(300.15 K). Solving for n, we get n = 0.0449 mol.

To calculate the molar mass, we divide the given mass (6.6 g) by the number of moles (0.0449 mol): molar mass = 6.6 g / 0.0449 mol =146.99 g/mol, which rounds to 140 g/mol.

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Answer:

3CaSO₄  + 2AlCl₃ →  Al₂(SO₄)₃   +   3CaCl₂

Explanation:

The reaction expression is given as:

        _CaSO₄  + _AlCl₃ →  _Al₂(SO₄)₃   +   _CaCl₂

To balance the reaction above, let us a mathematical approach;

         assign coefficients a, b, c and d to the species;

       aCaSO₄  + bAlCl₃ →  cAl₂(SO₄)₃   +   dCaCl₂

Conserving Ca : a  = d  

                     S:  a = 3c

                     O:  4a  = 12c

                     Al:    b = 2c

                     Cl:   3b = 2d

So;

 let a = 1, d = 1, c   = \(\frac{1}{3}\) , b  = \(\frac{2}{3}\)  

  Multiply by 3 through;

 a = 3, b  = 2, c  = 1 and d  = 3

  3CaSO₄  + 2AlCl₃ →  Al₂(SO₄)₃   +   3CaCl₂

MgO > CaO > NaF > KCl are the following compounds with decreasing order of lattice energy.

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Any orderly configuration of points and objects over a region or in space, such as the geometric configuration of the atoms within a crystal. Fissionable material is arranged geometrically in a nuclear reactor and is also referred to as a "space lattice."

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Answer:

A saturated solution may not be a concentrated solution IF the solute is only sparingly or slightly soluble in the solution.

At STP, 22.4 liters of nitrogen gas (N2) will have a mass of 28 grams.

At STP (Standard Temperature and Pressure), which is defined as a temperature of 0°C (273.15 K) and a pressure of 1 atmosphere (atm), 22.4 liters of any gas will contain one mole of the gas.

This is based on Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain the same number of particles, regardless of their chemical nature and physical properties.

To find the mass of 22.4 liters of nitrogen gas (N2) at STP, you first need to determine the molar mass of nitrogen gas. Nitrogen has an atomic mass of approximately 14 atomic mass units (amu). Since N2 is a diatomic molecule, meaning it consists of two nitrogen atoms, the molar mass of N2 is 2 * 14 amu = 28 grams per mole.

Now that you have the molar mass, you can determine the mass of 22.4 liters of nitrogen gas at STP. Since there is one mole of N2 in 22.4 liters at STP and the molar mass of N2 is 28 grams per mole, the mass of 22.4 liters of nitrogen gas at STP is:

1 mole * 28 grams per mole = 28 grams

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The total number of oxygen atoms in the mixture is 3.49 x \(10^{23\) atoms.

To determine the number of oxygen atoms in the given mixture, we need to first calculate the number of oxygen atoms in each compound and then add them up.

So, 3.49x10^23 molecules of H2O will contain:

3.49x10^23 x 1 oxygen atom = 3.49x10^23 oxygen atoms

Number of oxygen atoms in 78.1g of CH3OH:

To find the number of moles of CH3OH, we can use its molar mass:

Therefore, 78.1 g of CH3OH will contain:

2.44 mol x 1 oxygen atom = 2.44 oxygen atoms

The molecular formula of CO2 is CO2, which contains 2 oxygen atoms.

To find the number of moles of CO2, we can use the ideal gas law:

Assuming standard temperature and pressure (STP), which is 1 atm and 0°C (273 K), we have:

n = (1 atm x 14.2 L) / (0.0821 L·atm/mol·K x 273 K) = 0.58 mol

Therefore, 14.2 L of CO2 will contain:

0.58 mol x 2 oxygen atoms = 1.16 oxygen atoms

Now we can add up the number of oxygen atoms in each compound to find the total number of oxygen atoms in the mixture:

3.49x10^23 + 2.44 + 1.16 = 3.49x10^23 + 3.6 = 3.49 x \(10^{23\)

Therefore, the mixture contains 3.49 x \(10^{23\) oxygen atoms.

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The polar and neutral, non-polar, positively and negative charged amino acids are as follows -

Gln is polar.

C4H6O4N, aspartate, glutamate, is negatively charged, C9H7O3N, arginine, lysine, is positively charged,

hydrophobic amino acids, leucine and C3H7O2N are non polar amino acids.

Amino acids are the compounds having carboxyl and amino terminal at each end. They fold together to form secondary structures such as alpha helix, beta sheets and others. Upon more folding and turning they acquire three and four dimensional structure which imparts functional activity to the proteins.

Amino acids can be polar, non-polar, postively or negatively charged. The net ionic charge decides their postively or negatively charge. Also, aliphatic groups make the amino acids non-polar while presence of oxygen, sulphur, nitrogen gives polar character.

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The complete question is attached in figure.

When you touch a hot potato with your finger, energy flows. Touch is a sense that is associated with the detection of pressure, temperature, and pain. In the scenario presented the touch of the hot potato by the finger results in the transfer of heat energy from the potato to the finger.

When the finger comes into contact with the hot potato, the energy from the potato flows to the finger. The hot potato has more energy, which is transferred to the finger, making the finger feel hotter. This heat energy transfer is caused by a difference in temperature between the two objects. The flow of energy from the hot potato to the finger occurs until both objects reach thermal equilibrium (the same temperature). In this case, the transfer of energy continues until the finger and the potato have reached the same temperature. The rate of energy transfer depends on the temperature difference between the two objects. The greater the temperature difference, the greater the rate of energy transfer.In conclusion, when you touch a hot potato with your finger, energy flows from the hot potato to the finger, resulting in the transfer of heat energy.

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