how many liters of the standardized naoh in question 2 will be needed to neutralize a water solution with 0.1453 g oxalic acid dissolved?

Answers

Answer 1

To neutralize the water solution containing 0.1453 g of oxalic acid, 0.16 liters of the standardized NaOH in question 2 must be used.

In order to determine the amount of standardized NaOH needed to neutralize a water solution with 0.1453 g of oxalic acid dissolved, we must first calculate the moles of oxalic acid in the solution. To do so, we divide the grams of oxalic acid (0.1453 g) by its molar mass (90.04 g/mol), which gives us 0.016 mol of oxalic acid.

We can use the given molarity of the NaOH (0.1 M) to calculate the amount of moles of NaOH needed to neutralize this amount of oxalic acid. To do this we first multiply the molarity of NaOH by the volume of the solution (1 liter); this gives us 0.1 mol of NaOH. We then divide the moles of oxalic acid (0.016 mol) by the moles of NaOH (0.1 mol) which yields 0.16 L of standardized NaOH needed to neutralize the water solution.

This means that 0.16 liters of the standardized NaOH from question 2 is needed to neutralize the water solution with 0.1453 g oxalic acid dissolved.

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Related Questions

How did they get the limiting reactant as O2???

How did they get the limiting reactant as O2???

Answers

better picture? you ksksmskakakaoa

The goodyear blimp is filled with nearly 203,000 cubic feet of what gas?

Answers

The goodyear blimp is filled with nearly 203,000 cubic feet of Helium gas.

The helium inside the Goodyear blimp is considered to be an ideal gas.

The ideal gas law relates the pressure, volume, number of moles, and temperature to each other for an ideal gas, which is a reasonable assumption for the noble gases.

In such a case, all gases obey an equation of state known as the ideal gas law: PV = nRT, where n is the number of moles of the gas and R is the universal (or perfect) gas constant, 8.3144626 joules per kelvin per mole.

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Is C6H1206 an element or compound

Answers

C6H1206 is a compound (of glucose).

Suppose that you were given a block of gold 27cm long, 11cm wide, and 2. 0 cm thick

Answers

The mass of the gold block is 11,464.2 grams (or approximately 11.5 kg).

If we are given a block of gold with dimensions 27 cm (length), 11 cm (width), and 2.0 cm (thickness), we can calculate the volume and mass of the gold block.

The volume (V) of the gold block can be calculated using the formula:

V = length x width x thickness

Given values:

Length = 27 cm

Width = 11 cm

Thickness = 2.0 cm

Substituting the values into the formula:

V = 27 cm x 11 cm x 2.0 cm

V = 594 cm³

The volume of the gold block is 594 cm³.

To calculate the mass of the gold block, we need to know the density of gold. The density of gold is approximately 19.3 g/cm³.

The mass (m) of the gold block can be calculated using the formula:

m = density x volume

Given:

Density of gold = 19.3 g/cm³

Volume of the gold block = 594 cm³

Substituting the values into the formula:

m = 19.3 g/cm³ x 594 cm³

m = 11,464.2 g

The mass of the gold block is 11,464.2 grams (or approximately 11.5 kg).

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The lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group (red). in this representation, each y atom needs 1 electron(s) to complete its octet, and gains these electrons by forming 1 bond(s) with atoms of h . there are 1 unshared electron pair(s) and 1 bonding electron pair(s) in the product molecule. the bonds in the product are .

Answers

The question is incomplete, the complete question is;

The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group______ (red).

In this representation, each Y atom needs ______ electron(s) to complete its octet, and gains these electrons by forming______ bond(s) with atoms of H .

There are ______ unshared electron pair(s) and _______bonding electron pair(s) in the product molecule.

The bonds in the product are _________ (Ionic or Covalent)

Answer:

1) 16

2) 2 electrons

3) 2 bonds

4) 2 unshared pairs of electrons

5) 2 bonding pairs of electrons

6) The bonds in the product are covalent

Explanation:

Group sixteen elements have six electrons on their outermost shell. These include two unshared pairs of electrons and two unpaired electrons. These two unpaired electrons can now be covalently bonded to two hydrogen atoms to give H2Y. The compound H2Y has two lone pairs and two bond pairs of electrons.

H2Y can be a general formula for all hydrides of group 16. They are all very similar in structure but gradually differ in physical and chemical properties according to the graduated variation observed down the group.

The molecule has been \(\rm H_2Y\), where the two bonds have been formed for the sharing of 2 electrons pair between the H and Y atom.

The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group ______ (red).

The main group element that has the ability to form \(\rm H_2Y\) type of structure has been Group 16.

In this representation, each Y atom needs ______ electron(s) to complete its octet, and gains these electrons by forming______ bond(s) with atoms of H .

The atom required 2 electrons to complete its octet, and in order to gain two electrons, the atom form 2 bonds with the H, resulting in \(\rm H_2Y\).

There are ______ unshared electron pair(s) and _______ bonding electron pair(s) in the product molecule.

The atom forms bond with the two H atoms, thus there has been the presence of two unshared electrons pair. The bonding electrons pair are also two in the molecule.

The bonds in the product are _________ (Ionic or Covalent)

The bond has been formed with the sharing of the electron pair. Thus it has been a covalent bond.

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Mia put one liter of a substance into a 5 liter container. After 5 minutes she checked and the substances had expanded to take up the entire container. What substance did she use?
Group of answer choices

liquid

ice cubes

solid

gas

Answers

Answer:

Solid

Explanation:

Solid matter is composed of tightly packed particles. A solid will retain its shape; the particles are not free to move around. ... It will take the shape of its container. Particles can move about within a liquid, but they are packed densely enough that volume is maintained.

The irreversible gas phase reaction of ethylene (A) with hydrogen (B) to produce ethane (C) is carried out in a Ni-catalyzed packed-bed reactor: A + B =C , the rate constant for this reaction at 400°K is K= 0.2 L2 /mol s Kg cat, If the feed stream contains an equimolar amount of A and B and enters a temperature of 400°K and a pressure of 5 atm with a total volumetric flow rate of 8 L/s, what is the mass of catalyst required for a 70% conversion, considers it to be

Answers

Main answer:In order to find the mass of catalyst required for a 70% conversion, the following explanation can be followed:Explanation:Given the irreversible gas phase reaction of ethylene (A) with hydrogen (B) to produce ethane (C) is carried out in a Ni-catalyzed packed-bed reactor: A + B =CThe rate constant for this reaction at 400°K is K= 0.2 L2 /mol s Kg catThe feed stream contains an equimolar amount of A and B and enters a temperature of 400°K and a pressure of 5 atm with a total volumetric flow rate of 8 L/sTo find the mass of catalyst required for a 70% conversion, the following equation can be used:Plug the given values in the equation:To convert L/s into mol/s, the following formula can be used:Total volumetric flow rate (Q) = 8 L/sThe molar volume of the reactants can be calculated as follows:Therefore, the number of moles entering the reactor per second:To find the number of moles of A converted to C per second, the conversion can be used as follows:Therefore, the number of moles of A that will react per second:The mass of the catalyst that will be required can be calculated as follows:Therefore, the mass of catalyst required for a 70% conversion is 9.64 Kg.

Approximately 0.36 kg of catalyst is required for a 70% conversion in the given Ni-catalyzed packed-bed reactor, assuming a surface area of 10 m².

Given:

Rate constant (k) = 0.2 L²/mol s Kg cat

Total volumetric flow rate (Q) = 8 L/s

Conversion (X) = 70%

To calculate the mass of catalyst required, we need the surface area of the catalyst. Since the surface area (S) is not provided, let's assume a value of 10 m² for demonstration purposes.

Substituting the values into the equation:

Catalyst mass = (k * 0.3² * Fa₀ * Fb₀) / (Rate constant * Surface area of catalyst)

Catalyst mass = (0.2 L²/mol s Kg cat * (0.3)² * 4 L/s * 4 L/s) / (0.2 L²/mol s Kg cat * 10 m²)

Catalyst mass = (0.2 * 0.09 * 4 * 4) / (0.2 * 10)

Catalyst mass = 0.72 / 2

Catalyst mass = 0.36 kg

Therefore, approximately 0.36 kg of catalyst is required for a 70% conversion in the given Ni-catalyzed packed-bed reactor, assuming a surface area of 10 m².

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Helga has a box. She wants to determine how much the box can hold. Which measurement should she calculate?

A) Length
B) Area
C) Volume
D) Perimeter

Answers

C) volume

Explanation:

hope it helps !

Answer:

Volume. "How much the box can hold" means how much matter can fit into the box

PLEASEEEE HELPPPPP!!!


A reaction occurs, and you know that NaOH has a concentration of 0. 001 M NaOH. What will the concentration of HCl be?



A) 13. 999 M HCl


B) 3 M HCl


C) 0. 001 M HCl


D) 1 x 10-11 M HCl

Answers

The correct answer is None of the above.

To determine the concentration of HCl, we need to know the balanced chemical equation and the stoichiometry of the reaction. Assuming that the reaction is a neutralization reaction between NaOH and HCl, the balanced chemical equation is:

NaOH + HCl → NaCl + H2O

The stoichiometry of the reaction is 1:1, meaning that for every 1 mole of NaOH reacted, 1 mole of HCl is consumed. Since the concentration of NaOH is 0.001 M, we can calculate the number of moles of NaOH as:

moles of NaOH = concentration × volume (in liters) = 0.001 × volume

However, we don't know the volume of NaOH used, so we cannot determine the number of moles of HCl consumed. Therefore, we cannot determine the concentration of HCl.

Therefore, the correct answer is None of the above.

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3-8 find the exact value of each expression.
5. (b) \(\log _{10} 0.0001\)

Answers

the exact value of the expression \(\log _{10} 0.0001\) is -4.

The expression given is \(\log _{10} 0.0001\).
We know that \(\log _{10} 0.0001\) is the power to which 10 must be raised to get 0.0001.
We can write 0.0001 as 1/10,000 or in exponential form, 10^-4.
Therefore, \(\log _{10} 0.0001 = \log _{10} 10^{-4}\).
Using the property of logarithms, \(\log _{a}a^{b}=b\), we get
\(\log _{10} 10^{-4} = -4\).
So, the exact value of the expression \(\log _{10} 0.0001\) is -4.
the exact value of the given expression is -
Expression: \(\log _{10} 0.0001\)
Recall that the logarithm is the inverse of exponentiation. In this case, we want to find the exponent to which 10 must be raised to obtain 0.0001.
Since 0.0001 = 10^(-4), the expression simplifies as follows:
\(\log _{10} 0.0001 = \log _{10} 10^{-4}\)
By the property of logarithms, the exponent can be directly extracted when the base of the logarithm matches the base of the exponent:
\(\log _{10} 10^{-4} = -4\)
So the exact value of the expression is -4.

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Can someone Help please List the methods you think is used to treat water for contaminants before it gets to your
faucet.

Answers

The distillation system is a method also dioxide and ozone.

A car is moving with the a speed of 25m/s.Calculate the distance travelled the car in 30seconds​

Answers

Answer:

750 m

Explanation:

Hi there!

We're given that:

⇒ The speed of the car is 25 meters/second

⇒ The car travelled a certain distance in 30 seconds

To calculate distance, use the formula:

Distance = Speed × Time

Distance = 25 × 30

Distance = 750

Therefore, the car travelled a distance of 750 m in 30 seconds.

I hope this helps!

Answer:

\(\boxed {\boxed {\sf 750 \ meters}}\)

Explanation:

We are asked to find the distance a car traveled. Distance is the product of speed and time.

\(d= s \times t\)

The speed of the car is 25 meters per second. The time is 30 seconds.

s= 25 m/s t= 30 s

\(d= 25 \ m/s * 30 \ s\)

The units of seconds cancel each other out.

\(d= 25 \ m * 30\)

\(d= 750 \ m\)

The car traveled 750 meters in 30 seconds at a speed of 25 meters per second.

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of phosphoric acid and potassium hydroxide

Answers

The net ionic equation for the overall reaction that occurs when aqueous solutions of phosphoric acid and potassium hydroxide are H₃PO₄ + 3 KOH → K₃PO₄ + 3 H₂OH⁺ + OH⁻ → H₂O.

To find the net ionic equation for the reaction between aqueous solutions of phosphoric acid and potassium hydroxide, we must write the balanced chemical equation for the reaction, which is:

H₃PO₄ + 3 KOH → K₃PO₄ + 3 H₂O

After writing the balanced chemical equation, you need to separate out the spectator ions that do not take part in the reaction. Here, the spectator ions are K⁺ and PO₄³⁻.

The net ionic equation only includes the species that take part in the reaction and they are:

H⁺ + OH⁻ → H₂O

Thus, the net ionic equation for the overall reaction is:

H₃PO₄ + 3 KOH → K₃PO₄ + 3 H₂OH⁺ + OH⁻ → H₂O

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The Dutch scientist Johannes van der Waals developed a useful equation to predict the behavior of real gases. In the van der Waals equation, what are the constants a and b, respectively?
a. a is a measure of how strongly the gas molecules attract one another, and b is a measure of the finite volume occupied by the molecules.
b. a is a measure of the random motion of gas molecules, and b is a measure of the volume of the container.
c. a is a measure of the finite volume occupied by the molecules, and b is a measure of how strongly the gas molecules attract one another.
d. a is a measure of the molecular mass of the gas molecules, and b is a measure of the finite volume occupied by the molecules.

Answers

Answer:

Explanation:

The higher the value of a, the greater the attraction between molecules and the more easily the gas will compress.

The b term represents the excluded volume of the gas or the volume occupied by the gas particles.

When an object is acted on by unbalanced forces, the object will -

Answers

Answer:

hope it helps and thank you for the points

When an object is acted on by unbalanced forces, the object will -

Which compound is the most soluble in water?
Medium
A Chloroethane
B Ethanol
C Ethanal
D Ethylene glycol

Answers

Answer: B) ethanol

Explanation:

Due to its strong attraction with water molecules.

5) When rain falls to the earth, it just doesn't sit there. Instead, the rain water starts moving. Some of the precipitation seeps into the ground to replenishing groundwater. However, most of
it flows downhill as runoff. Runoff is important in filling rivers and lakes, but it also changes the landscape by erosion and can be a powerful mover. Flowing water is a powerful force,
capable of moving boulders and carving out canyons. Runoff has an impact on streams and rivers, but it also has an impact on the ocean system. What can you infer about the impact of
runoff on Ocean life? Choose ALL that apply.
A) Runoff drops a lot of sediment in the ocean, decreasing salinity.
B) Runoff builds up the coastline, depositing sediment, disrupting habitats of marine wildlife.
Runoff can lead to overgrowth of algae that can cause oxygen deprivation and create a dead zone.
D) Runoff carries pollutants into the ocean, causing illness and death of vulnerable marine populations.
) Runoff can carry bacteria, viruses and other pathogens from pet and livestock waste that can harm shellfish and other marine organisms.

Answers

Answer: Rain evaporates and this same process happens over and over again.

Explanation:

the compound lead nitrate is a strong electrolyte. write the transformation that occurs when solid lead nitrate dissolves in water.

Answers

The lead nitrate \(PB (NO_{3})_{2}\) is soluble in water. It will dissociate into \(Pb^{2+}\) (aq) ion and \(NO_{3}^{-}\) ion.

Reaction

\(Pb(NO_{3})_{2} (s) + H_{2}O (l) - > Pb^{2+} (aq) + 2NO_{3}^{-} (aq)\)

Lead(II) nitrate is an inorganic compound with the chemical formula Pb(NO₃)₂. It commonly occurs as a colorless crystal or white powder and, unlike most other lead(II) salts, is soluble in water.

What is lead nitrate used for?

Lead Nitrate is a white or colorless, sand-like solid. It is used in making matches and special explosives, in the dye and photography industries, and in process engraving. List because it is cited by OSHA, ACGIH, DOT, NIOSH, NTP, DEP, IARC and EPA.

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What effect does the concentration of reactants have on the rate of a
reaction?
A. Changing the concentration has no effect on the reaction rate.
B. Increasing the concentration decreases the rate of the reaction.
O C. Increasing the concentration increases the rate of the reaction.
O D. The effect of concentration on rate varies within the reaction.

Answers

Answer:

C

Explanation:

The answer is C as concentration is a major factor affecting the rate of reaction and it has a direct relationship with the rate of reaction.

The effect that the concentration of reactants has on the rate of a reaction is increasing the concentration increases the rate of the reaction. The correct option is C.

What is a reactant?

A reactant is a part of a reaction that is the first part of the reaction. Reactant can be more than one in the reaction. The different reactant reacts, and form a totally different product.

H2 + O2 = H2O

The hydrogen and oxygen are the reactants of the reaction.

Thus, the correct option is C. Increasing the concentration increases the rate of the reaction, as concentration plays a significant role in determining the rate of reaction and is directly related to it.

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How do plants support the Earth's ecosystem and food web?

Answers

Answer:

It provides the energy for all life on Earth and thus all Earth's ecosystems. Plants convert sunlight to make their own food, which they use to support their own lives. When animals eat plants, they eat this "ready-made" food, formed from energy originally provided by the sun.

Explanation:

What is the pH of a 7.5 × 10-3 M Ba(OH)2 solution at 25°C?
a. 0.015
b. 1.82
c. 12.18
d. 11.88

Answers

A 7.5 10-3 M Ba(OH)2 solutions at 25°C has a pH of 1.82. (option b).

What exactly is a solution exemplar?

A homogenous solution of two or more ingredients with particles smaller than one nm is referred to as a solution. Solutions come in many forms, such as soda water, salt and sugar solutions, etc. In a solution, every element appears as a single phase.

What is the ideal definition of a solution?

In chemistry, a solution is a homogeneous mix of two or more molecules in relative proportions that can be constantly changed up to what is known as the limit of solubility. Although the term "solution" is frequently used to refer to the liquid state of matter, solutions of gases and solids are also possible.

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3. A man rode on his motorcycle for 162 miles. His average speed was 45 miles per hour. How long did his trip take?​

Answers

Explanation:



Answer : 3.6 hours

Look at the image shown.
H-H
What does this image represent?
Linear molecule with one domain
Linear molecule with two domains
Tetrahedral molecule with four domains
O
Trigonal planar molecule with three domains

Answers

The lone pairs are perfectly balance out and will not cause distortion of the central carbon atom..

Therefore answer is,

b) linear molecule with two domains

Mark me Brainly

equation of bhr and h2o

Answers

HBr + H2O = H3O + Br2

Which is the IUPAC name for NO?

Answers

Answer:

Nitrogen (ii) oxide

Explanation:

To know the IUPAC name for NO, we shall determine the oxidation number of N in NO.

NOTE: The oxidation number of oxygen (O) is always – 2.

Thus the oxidation number of N in NO can be obtained as follow:

N + O = 0 (ground state)

N + (– 2) = 0

N – 2 = 0

Collect like terms

N = 0 + 2

N = +2

Thus, the oxidation number of Nitrogen (N) in NO is +2.

Therefore, the IUPAC name for NO is Nitrogen (ii) oxide

Answer:

nitrogen monoxide

Explanation:

for those taking quiz on edge

The progress with time of a reaction system is depicted in the figure below. Red spheres represent the molar concentration of substance A and blue spheres represent the molar concentration of substance B. Does the system reach equilibrium? In which direction is equilibrium attained?

Answers

The concentration of red spheres diminishes with time as the concentration of blurry spheres grows. In box C, the system reaches equilibrium. The proper equilibrium is attained.

Let's begin by formulating the reaction equation A ⇔ B.

Hence, the equilibrium constant, KC, is written as

KC = [B]eq / [A]eq.

Now count the red and blue spheres in the upper right corner of the picture. There are 16 red and 24 blue spheres. (A) (B). Its value is 24/16, or 1.5.

We must first confirm that the system in the rightmost frame has reached equilibrium before continuing. We must first determine the B to A ratio in the previous frame in order to execute it (second from the right). It features the same 24 blue and 16 red spheres as the previous picture. The system reached equilibrium when the ratio stayed constant.

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Complete Question:

The progress with time of a reaction system is depicted in the figure below. Red spheres represent the molar concentration of substance A and blue spheres represent the molar concentration of substance B. Does the system reach equilibrium? In which direction is equilibrium attained?

 The progress with time of a reaction system is depicted in the figure below. Red spheres represent the

When calcium reacts with chlorine, the reaction involves:

a. a transfer of electrons from Ca to Cl

b. the sharing of electrons between Ca and Cl

c. a creation of electrons

d. a transfer of electrons from Cl to Ca

Answers

When calcium reacts with chlorine, the reaction involves: a transfer of electrons from Ca to Cl. The correct option is (a).

In the reaction between calcium (Ca) and chlorine (Cl), the electrons are transferred from calcium to chlorine. This is indicated by the formation of calcium ions (Ca²⁺) and chloride ions (Cl⁻).

Calcium has two valence electrons in its outer shell, and chlorine has seven valence electrons. Calcium tends to lose its two electrons to achieve a stable configuration, while chlorine tends to gain one electron to achieve a stable configuration of eight valence electrons.

As a result, calcium loses two electrons, which are gained by chlorine. This transfer of electrons leads to the formation of calcium ions with a +2 charge and chloride ions with a -1 charge.

The option "a. a transfer of electrons from Ca to Cl" correctly describes the electron transfer that occurs during the reaction between calcium and chlorine.

This type of reaction, involving the transfer of electrons, is known as an ionic reaction and is characteristic of the formation of ionic compounds.

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2. When liquid water freezes, it tends to

Answers

expand…
hope this helps

What is the difference between a divide and a drainage basin?

Answers

Answer:

Drainage basin, also called catchment area, or (in North America) watershed, area from which all precipitation flows to a single stream or set of streams. ... The boundary between drainage basins is a drainage divide: all the precipitation on opposite sides of a drainage divide will flow into different drainage basins.

Explanation:

just looked it up

Drainage basin, also called catchment area, or (in North America) watershed, area from which all precipitation flows to a single stream or set of streams. ... The boundary between drainage basins is a drainage divide: all the precipitation on opposite sides of a drainage divide will flow into different drainage basins.

calculate the frequency of light associated with the transition from n=2 to n=3

Answers

The frequency of light associated with the transition from n=2 to n=3 is approximately 5/36 times the Rydberg constant.The frequency of light associated with the transition from one energy level to another can be calculated using the Rydberg formula, which is given by:

ν = R * (1/n₁² - 1/n₂²)

where ν is the frequency of light, R is the Rydberg constant (approximately 3.29 x 10^15 Hz), n₁ is the initial energy level, and n₂ is the final energy level.

Given that the transition is from n=2 to n=3, we can substitute these values into the formula and calculate the frequency:

ν = R * (1/2² - 1/3²)

ν = R * (1/4 - 1/9)

ν = R * (9/36 - 4/36)

ν = R * (5/36)

The frequency of light associated with the transition from n=2 to n=3 is approximately 5/36 times the Rydberg constant.

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