Answer the next filter is FIR, IIR or other case.
y(n)=x(n)-2*x(n-2)+x(n-3)
a. FIR
b. IIR
c. other case

Answer:

composition: the action of putting things together; formation or construction. Alternatively, a creative work, especially a poem or piece of music. Or, in chemistry terms, the chemical composition of engineering material indicates the elements which are combined together to form that material.

synthesis: the combination of components or elements to form a connected whole. Often contrasted with analysis.

microstructure: Microstructure is the very small scale structure of a material,  which can be made visible and examined with a microscope.

Explanation:

If you need further explanation, let me know!

Answer:

The golfer is at greater risk.

Explanation:

The golfer is holding a metal club. Metal is a good conductor for electricity (lightning), meaning electrons can pass through easily. Her caddy is at lesser risk because she is holding a plastic handled umbrella. Plastic is an insulator, which does not easily allow the movement of electrons to pass.

Answer:

Velocity of ball B after impact is \(0.6364v_0\) and ball A is \(0.711v_0\)

Explanation:

\(v_0\) = Initial velocity of ball A

\(v_A=v_0\cos45^{\circ}\)

\(v_B\) = Initial velocity of ball B = 0

\((v_A)_n'\) = Final velocity of ball A

\(v_B'\) = Final velocity of ball B

\(e\) = Coefficient of restitution = 0.8

From the conservation of momentum along the normal we have

\(mv_A+mv_B=m(v_A)_n'+mv_B'\\\Rightarrow v_0\cos45^{\circ}+0=(v_A)_n'+v_B'\\\Rightarrow (v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0\)

Coefficient of restitution is given by

\(e=\dfrac{v_B'-(v_A)_n'}{v_A-v_B}\\\Rightarrow 0.8=\dfrac{v_B'-(v_A)_n'}{v_0\cos45^{\circ}}\\\Rightarrow v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0\)

\((v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0\)

\(v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0\)

Adding the above two equations we get

\(2v_B'=\dfrac{1.8}{\sqrt{2}}v_0\\\Rightarrow v_B'=\dfrac{0.9}{\sqrt{2}}v_0\)

\(\boldsymbol{\therefore v_B'=0.6364v_0}\)

\((v_A)_n'=\dfrac{1}{\sqrt{2}}v_0-0.6364v_0\\\Rightarrow (v_A)_n'=0.07071v_0\)

From the conservation of momentum along the plane of contact we have

\((v_A)_t'=(v_A)_t=v_0\sin45^{\circ}\\\Rightarrow (v_A)_t'=\dfrac{v_0}{\sqrt{2}}\)

\(v_A'=\sqrt{(v_A)_t'^2+(v_A)_n'^2}\\\Rightarrow v_A'=\sqrt{(\dfrac{v_0}{\sqrt{2}})^2+(0.07071v_0)^2}\\\Rightarrow \boldsymbol{v_A'=0.711v_0}\)

Velocity of ball B after impact is \(0.6364v_0\) and ball A is \(0.711v_0\).

Answer: 8.33333333 or 6.1989778

Explanation:

Polymers is the referred to the class of material which is generally considered to be the weakest at room temperature, offering the lowest elastic moduli and tensile strengths and is denoted as option B.

This refers to a type of compound which are long chained and are formed from smaller repeating chemical units known as monomers through the process which is referred to as polymerization

They are usually in the form of plastics or resins and have features such as lowest elastic moduli and tensile strengths thereby making it the most appropriate choice.

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The options incliude:

A.Metal

B.Polymer

C.Ceramics

D.Composites

Answer:

No, they need to be somewhat flexible so that forces such as turbulance don't shear the wing off.

Answer:

gdyc ddxtfvytg4dgtfxdwcftcd3rcby

If the crankshaft end play is out of specifications, check for:

Thrust Bearings

Main Bearings

Crankshaft

Crankshaft Thrust Washers

Engine Block

To understand the crankshaft when it is out of specifications, check for:

Thrust Bearings: Check the condition of the thrust bearings, which are located at the front and/or rear of the engine block. Excessive wear or damage to the thrust bearings can contribute to increased crankshaft end play.

Main Bearings: Inspect the main bearings, which support the crankshaft within the engine block. Worn or damaged main bearings can cause excessive movement of the crankshaft.

Crankshaft: Check the crankshaft itself for any signs of damage, such as scoring or bending. A damaged crankshaft may not sit properly within the bearings, leading to increased end play.

Crankshaft Thrust Washers: Some engines use thrust washers to control the end play of the crankshaft. Inspect these washers for wear, damage, or improper installation.

Engine Block: Check the engine block for any signs of damage or distortion that may affect the alignment and support of the crankshaft.

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A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis

D. CNC machines.

In Engineering the following items are basically needed for and during test/Analysis

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Answer:

True

Explanation:

in a single-stream, steady flow system, the mass flow rates for the inlet and outlet must be the same is true

Answer:

A pointer is spun on a fair wheel of chance having its periphery labeled Trom 0 to 100. (a) Whhat is the sample space for this experiment? (b)What is the probability that the pointer will stop between 20 and 35? (c) What is the probability that the wheel will stop on 58?

​

Explanation:

thats all you said

Answer:

hii my name is RAGHAV what is your name

Explanation:

this question is which chapter

Answer:

DNA profiling

Explanation:

took the test

To solve trusses like this, you need to use the method of joints. This means that you calculate the forces at each joint in the truss and then use the equations of equilibrium to solve for the unknown forces.

Equilibrium is a state of balance or a steady state in which opposing forces or influences are balanced. In economics, it is a situation in which all economic forces are balanced and in the absence of external influences the values of economic variables will not change. Equilibrium is the result of market forces of supply and demand being equal; where the quantity of a good or service that suppliers are willing to provide is equal to the quantity that consumers are willing and able to purchase. It is a state of no change where all economic variables such as price and quantity remain constant.

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Answer:

C - oil filters.

Explanation:

You must crush or drain oil filters for a minimum of 12 hours for recycling because used motor oil is hazardous waste and can affect the environment if disposed of properly so the government has created strict rules for proper disposal.

Answer:

25,000 mph or around 40,000 kph

Explanation:

all depends on the altitude and weather conditions but this is average

84.874023 in binary is 1010100.111111. To convert 25.84375 to binary with a maximum of six places to the right of the binary point:

First, convert the whole number part:

25 in binary is 11001.

Next, convert the fractional part:

0.84375 × 2 = 1.6875

0.6875 × 2 = 1.375

0.375 × 2 = 0.75

0.75 × 2 = 1.5

0.5 × 2 = 1.0

Combine the whole number and fractional parts:

25.84375 in binary is 11001.1101.

b. To convert 57.55 to binary with a maximum of six places to the right of the binary point:

Whole number part:

57 in binary is 111001.

Fractional part:

0.55 × 2 = 1.10

0.10 × 2 = 0.20

0.20 × 2 = 0.40

0.40 × 2 = 0.80

0.80 × 2 = 1.60 (discard the integer part)

0.60 × 2 = 1.20 (discard the integer part)

Combine the whole number and fractional parts:

57.55 in binary is 111001.100011.

c. To convert 80.90625 to binary with a maximum of six places to the right of the binary point:

Whole number part:

80 in binary is 1010000.

Fractional part:

0.90625 × 2 = 1.8125 (discard the integer part)

0.8125 × 2 = 1.625 (discard the integer part)

0.625 × 2 = 1.25 (discard the integer part)

0.25 × 2 = 0.50

0.50 × 2 = 1.00

Combine the whole number and fractional parts:

80.90625 in binary is 1010000.11101.

d. To convert 84.874023 to binary with a maximum of six places to the right of the binary point:

Whole number part:

84 in binary is 1010100.

Fractional part:

0.874023 × 2 = 1.748046 (discard the integer part)

0.748046 × 2 = 1.496092 (discard the integer part)

0.496092 × 2 = 0.992184 (discard the integer part)

0.992184 × 2 = 1.984368 (discard the integer part)

0.984368 × 2 = 1.968736 (discard the integer part)

0.968736 × 2 = 1.937472 (discard the integer part)

Combine the whole number and fractional parts:

84.874023 in binary is 1010100.111111.

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Answer:

Finding stuff you need ( D )

Explanation:

Once an idea is narrowed down and divided into categories, The next line of action would be to create smaller groups that will be brainstorm solutions towards resolving the problem/ implement the idea faced by the team.

The phase of the design process that the smaller teams created will be focused on is to model and build a prototype ( finding stuff you need ) that would help implement the ideas

Answer:

  12 volts

Explanation:

The voltage ratio is equal to the turns ratio.

  secondary/primary = 20/200 = v2/120

  v2 = 120(20/200) = 12

The secondary winding voltage is 12 volts.

The new power dissipation, with the increased activity factor and decreased switching frequency, is approximately 43.04 W.

To calculate the new power dissipation, we can use the formula:

Power = Activity Factor × Switching Frequency × Capacitance × Voltage²

Given:

Transistors = 10 billion (10e9)

Old Power Dissipation = 40W

Old Activity Factor = 20% = 0.2

Old Switching Frequency = 5 MHz = 5e6 Hz

Gate Capacitance = 1 fF = 1e-15 F

First, let's calculate the voltage based on the old power dissipation:

Power = Activity Factor × Switching Frequency × Capacitance × Voltage²

Rearranging the formula, we get:

Voltage = sqrt(Power / (Activity Factor × Switching Frequency × Capacitance))

Plugging in the values:

Voltage = sqrt(40 / (0.2 × 5e6 × 1e-15))

Voltage ≈ 8944.27 V

Now, let's calculate the new power dissipation using the same formula with the new values:

New Activity Factor = 60% = 0.6

New Switching Frequency = 2 MHz = 2e6 Hz

New Power = New Activity Factor × New Switching Frequency × Capacitance × Voltage²

Plugging in the values:

New Power = 0.6 × 2e6 × 1e-15 × (8944.27)²

New Power ≈ 43.04 W

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Answer:

search up factors of 2450 and divide by two

The number of ways 2450 can be written as a product of 2 factors is 9 ways

Factors of 2,450 = 1, 2, 5, 7, 10, 14, 25, 35, 49, 50, 70, 98, 175, 245, 350, 490, 1225, 2450

The number of ways 2450 can be written as a product of 2 factors = number of factors / 2

= 18/2

= 9 wats

This means, taking the product of two factors such as;

1 × 2450

2 × 1225

5 × 490

7 × 350

10 × 245

14 × 175

25 × 98

35 × 70

50 × 98

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Both Technicians A and B are correct that driveline binding can result from uneven tire circumferences and that uneven tire circumferences can be corrected by shaving the tires.

Employed in almost every industry, technicians are skilled professionals. Different systems and pieces of equipment are serviced, repaired, installed, and replaced by them. The ability to read instructions and communicate clearly is a requirement for technicians, who frequently collaborate with other skilled workers. If a four-wheel vehicle is driven on dry highways for a significant amount of time, you can expect to experience drivetrain binding. Transmission windup can also happen because the front and rear driveshafts don't rotate at the proper frequency or speed, which is affected by the direction you're driving. On these vehicles, the drivetrain rotates more quickly at the front than the rear. Many part-time 4 wheel drive transfer cases lack a center differential, which causes them to jam. Like all-wheel drive and contemporary automatic 4WD vehicles, a center differential balances out the differences in axle speeds.

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Answer: It takes the form of heat or thermal power.

Explanation: I got it right on the test.

Answer:

B. It takes the form of heat or thermal power.

Explanation:

edg21

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

One cycle for a sine wave is 360o or 2 radians. a) A sine wave with maximum amplitude at time t=0. The amplitude of a sine wave is maximum at the peak of the wave. Case 1: assuming that the wave is starting its cycle at t=0 then there is no phase shift for the wave at time t=0 without considering the amplitude...

Determine the minimal distance if the collar at B is smooth and solely applies a horizontal force to the pipe, and the coefficient of static friction at A is.

The ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient.Typically, it is represented by the Greek letter mu (). F is the frictional force and N is the normal force, and mathematically, = F/N.

The things that are creating friction determine the coefficient of static friction's value. Its value typically ranges from 0 to 1, however it can be higher.

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The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.

The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes  While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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The transfer function of an integrator circuit is:$$\frac{V_{out}(s)}{V_{in}(s)}=-\frac{1}{RCs}$$ For a transfer function with an absolute value of 2 at a frequency of 3 kHz

$$\left| \frac{V_{out}(j\omega)}{V_{in}(j\omega)} \right| = 2$$If we consider only the magnitude, we get:$$\frac{V_{out}(j\omega)}{V_{in}(j\omega)} = -2$$Using the expression for the transfer function, we get:$$-\frac{1}{RCj\omega}=-2$$Solving for the product RC, we get:$$RC=\frac{1}{2\cdot 3\cdot 10^3}=-\frac{1}{6\cdot 10^3}$$Since we have only one constraint equation, we can choose any value for R or C, but to make the design simpler, let's choose R = 1 kOhm. Thus, we get:$$C = -\frac{1}{6\cdot 10^6}$$The input impedance of the circuit is equal to the magnitude of the impedance of the capacitor, which is given by:$$\left| Z_2 \right| = \frac{1}{\omega C}=2\cdot 10^3$$Substituting the values of C and solving for R, we get:$$R = \frac{1}{2\cdot 10^3 \cdot C}=\frac{1}{4} kOhm$$Long answer: a) Design of an integrator circuit.

Thus, we get:$$C = -\frac{1}{6\cdot 10^6}$$The input impedance of the circuit is equal to the magnitude of the impedance of the capacitor, which is given by:$$\left| Z_2 \right| = \frac{1}{\omega C}=2\cdot 10^3$$Substituting the values of C and solving for R, we get:$$R = \frac{1}{2\cdot 10^3 \cdot C}=\frac{1}{4} kOhm$$Thus, the design of the integrator circuit is complete.b) Calculation of the transfer function at f = 10 kHzAt f = 10 kHz, the transfer function of the integrator circuit is given by:$$\frac{V_{out}(j\omega)}{V_{in}(j\omega)}=-\frac{1}{RCj\omega}=-\frac{1}{\frac{1}{4}k\Omega\cdot -\frac{j}{6\cdot 10^6} \cdot 2\pi \cdot 10^4}=-\frac{10^6}{3j}$$Thus, the value of the complex transfer function at f = 10 kHz is given by:-\frac{10^6}{3j} = -\frac{10^6}{3}\cdot \frac{-j}{j^2}=\frac{10^6}{3} \cdot \frac{1}{j}=-\frac{10^6}{3}j

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When using a raising stake to form a deep bowl,  start the raising operation using forming blocks. Option A

These blocks give bolster and shape to the metal because it is slowly pounded over the stake.

Strengthening operations, in spite of the fact that not particularly specified, are still pivotal amid the raising handle, indeed in the event that hardwood stakes are utilized (B).

Toughening makes a difference to relax the metal and anticipate breaking or mutilation. As the edges of the piece are raised, a hammer is utilized to shape and form the metal, requiring the piece to be picked up different times (C).

At last, after trimming any overabundance fabric, the shaped piece is  cleaned for a smooth and refined wrap up (D).

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