gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated naoh(aq). calculate the amount of ga(s) that can be deposited from a ga(iii) solution using a current of 0.560 a that flows for 70.0 min. mass:

The major product of the reaction depends on the specific reactants involved. Without knowing the specific reactants, it is impossible to determine the major product(s) formed. The reaction Br2 (heat) represents a thermal decomposition of bromine.

When bromine is heated, it undergoes homolytic cleavage to form two bromine free radicals (Br·). The major product(s) of this reaction depends on the conditions under which the reaction occurs.If the reaction occurs in the absence of other reactants, the bromine free radicals will react with each other to form a stable Br2 molecule. Thus, the major product of the reaction would be Br2.However, if the reaction occurs in the presence of other reactants, the bromine free radicals may react with those instead of each other, leading to different products.

For example, if the reaction occurs in the presence of methane (CH4), the bromine free radicals can abstract a hydrogen atom from methane to form HBr and a methyl radical (CH3·). The methyl radical can then react with another bromine molecule to form CH3Br and Br2. In this case, the major product(s) of the reaction would be HBr, CH3Br, and Br2.

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sunlight gives energy to living things

Explanation:

sun is the main energy for the earth

Answer:The yellow crystalline substance is a compound. The green gas and red powder are elements.

Explanation

Elements and compounds are considered pure substances. Elements are made up of a single type of atom while compounds are composed of two or more elements. One example of a compound is the table salt (NaCl) which is made up of one atom of sodium and one atom of chlorine. The elements in the compound are combined chemically and there is a definite ratio of these elements. They are formed by a chemical reaction where chemical bonds are formed. Furthermore, the components of the compound can be separated through several means such as extraction, distillation, etc. The process of heating the yellow crystalline substance resulted in the separation of its components namely, the green gas and red powder.

Answer:

0.1498 g of O2.

Explanation:

The Behavior of Gases => Ideal Gas Law.

The ideal gas law is a single equation that relates the pressure, volume, temperature, and the number of moles of an ideal gas, which is:

where P is pressure in atm, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.082 L*atm/mol*K), and T is the temperature in the Kelvin scale.

So we have to convert pressure from 700.0 mmHg to atm, volume from 120.0 mL to L, and 15 °C to K.

Let's convert pressure taking into account that 1 atm equals 760 mmHg, like this:

Remember that 1 L equals 1000 mL, so 120.0 mL would be equal:

And the conversion from °C to K is just sum °C with 273, so 15 °C in K is:

Finally, we can use the ideal gas formula, solving for 'n' (number of moles) and replacing the data that we have, as follows:

Now, the final step is to convert 4.680 x 10⁻³ moles of O2 to grams using the molar mass of O2 that can be calculated using the periodic table, which is 32 g/mol. The conversion will look like this:

The answer would be that there are 0.1498 g of O2.

we use the formula

pV=nRT

we convert Kilo Pascals to mmHg

253.25 KPa=253250 pascals

1mmHg is equal to 133.322 pascals

xmmHg are equal to 253250pascals

x=253250/133.322=1900mmHg

now we convert mmHg to atmospheres

1 atmosphere is equal to 760mmHg

x atmospheres are equatl to 1900mmHg

x=1900/760=2.5 atmospheres

in the formula:

pV=nRT

p-pressure

V-volume

n-number of moles

R-ideal constant of gases

T-temperature

the only missing variable is temperature since we know that  R=0.082

250ml=0.25L

0.25*2.5=0.1*0.082T

T=0.625/0.0082=76.219K

Answer:

false

Explanation:

fission is lots of energy

Answer:

the third one

Explanation:

When you breathe in, you inhale oxygen and exhale carbon dioxide

Answer:

3.4g

Explanation:

Given parameters:

Mass of ethanol  = 2.911g

Unknown:

Mass of water vapor = ?

Solution:

To solve this problem, let us write the balanced reaction equation first;

             C₂H₅OH  + 3O₂  → 2CO₂  + 3H₂O

Now find the number of moles of ethanol;

  Number of moles  = \(\frac{mass}{molar mass}\)

    Molar mass of ethanol = 2(12) + 5(1) + 16 + 1 = 46g/mol

  Number of moles  = \(\frac{2.911}{46}\)   = 0.06mole

  So;

       1 mole of ethanol will produce 3 moles of water vapor

      0.06mole of ethanol will produce 0.06 x 3  = 0.19moles of water vapor

 Mass of water vapor  = number of moles x molar mass

   Molar mass of H₂O  = 2(1) + 16  = 18g/mol

  Mass of water vapor  = 0.19 x 18  = 3.4g

Decanting, filtration, sublimation and distillation are the separation techniques.

Decanting is a process in which a liquid is carefully poured out, leaving the solid behind in the container.

A solid is caught on paper or a membrane while the liquid passes through, this process is called Filtration.

Sublimation is a process in which a solid mixture is heated in which one component transitions directly between solid and gas.

A solvent is added to dissolve only one mixture component and then the liquids are separated, this process is known as distillation.

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The physical separation techniques used are :

Physical Separation techniques are procedures applied for the separation of a mixture of two different states pf matter based on their physical properties. usually solid and liquid mixtures. When a mixture of liquid and solid is separated by carefully pouring out the liquid while leaving the solid behind that separation technique is known as decanting.

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If hydrochloric acid is added to a solution of HF, it will react with the HF to form H3O+ and F- ions. This reaction is a type of acid-base reaction, where the hydrochloric acid acts as the stronger acid and donates a proton to the HF, which acts as the weaker base.

The addition of hydrochloric acid will increase the concentration of H3O+ ions in the solution. This increase in the concentration of H3O+ ions will shift the equilibrium of the HF ionization reaction to the left, leading to a decrease in the percent ionization of HF. This is because the increased concentration of H3O+ ions will make it more difficult for the HF molecules to ionize and release H+ ions into the solution.

Therefore, the correct answer is that the percent ionization of HF will decrease. The Ka for HF will not change, as it is a constant value for a given temperature and is independent of the concentration of H3O+ ions in the solution.

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The concentration of hydroxide ions in the solution at 25°C, with a pOH of 12.40, is approximately 3.98 x 10^(-13) mol/L.

To determine the concentration of hydroxide ions in a solution at 25°C with a pOH of 12.40, we can use the relationship between pOH and hydroxide ion concentration. The pOH is defined as the negative logarithm (base 10) of the hydroxide ion concentration. Mathematically, it can be expressed as pOH = -log[OH-].

Given that pOH = 12.40, we can calculate the hydroxide ion concentration by taking the antilogarithm (10 raised to the power of the negative pOH value). So, [OH-] = 10^(-pOH).

Substituting the given value into the equation, we have [OH-] = 10^(-12.40). Evaluating this expression, we find that the concentration of hydroxide ions in the solution is approximately 3.98 x 10^(-13) mol/L.

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Answer:

Increasing the temperature

Increasing particle size

Explanation:

Increasing the temperature allows for particles and molecules to move faster (because there is an increase in energy) and allows for more collisions.

∴ Increasing the temperature would be an answer.

Increasing the particle size allows for more surface area and a greater chance for particles to collide with each other.

∴ Increasing particle size would be an answer.

Topic: AP Chemistry

Unit: Kinetics

The concentration of Li+ ions in 4.57 L of a 2.35 M Li3P solution is 7.05 M.

To find the concentration of lithium ions (Li+) in the 2.35 M Li3P solution in 4.57 L, you first need to calculate the number of moles of Li+ in the solution.

Li3P dissociates into 3 Li+ ions and 1 P3- ion, so for every mole of Li3P, you get 3 moles of Li+ ions.

To find the number of moles of Li3P in 4.57 L of the solution, you can use the formula:

moles = concentration (M) x volume (L)

moles of Li3P = 2.35 M x 4.57 L = 10.75 moles

Since there are 3 moles of Li+ ions for every mole of Li3P, you can calculate the number of moles of Li+ ions in the solution by multiplying the number of moles of Li3P by 3:

moles of Li+ ions = 10.75 moles Li3P x 3 = 32.25 moles Li+

Finally, to find the concentration of Li+ ions in the solution, divide the number of moles of Li+ ions by the volume of the solution:

concentration (m) = moles of Li+ ions / volume of solution

concentration (m) = 32.25 moles / 4.57 L = 7.05 M

Therefore, the concentration of Li+ ions in 4.57 L of a 2.35 M Li3P solution is 7.05 M.

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The formation of solid magnesium chloride (MgCl₂) by the reaction between chlorine gas (Cl₂) and magnesium metal (Mg) at high temperatures is classified as a synthesis reaction or a combination reaction.

Synthesis reactions involve the combination of two or more substances to form a single product. In this case, chlorine gas and magnesium metal combine to produce magnesium chloride as the sole product.

The balanced chemical equation for this synthesis reaction is:

Mg + Cl₂ ⇒ MgCl₂

Hence, the reaction between chlorine gas and magnesium metal to form solid magnesium chloride indicates a synthesis reaction, as the elements combine to form a compound.

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The molar concentration of Al(OH)₃ in the solution is 1.61 M.

we need to calculate the number of moles of Al(OH)3 in the solution:

Number of moles of Al(OH)₃ = mass of Al(OH)3 / molar mass of Al(OH)3

Molar mass of Al(OH)₃ = (1 x atomic mass of Al) + (3 x atomic mass of O) + (3 x atomic mass of H)

Molar mass of Al(OH)₃ = (1 x 26.98 g/mol) + (3 x 16.00 g/mol) + (3 x 1.01 g/mol) = 78.00 g/mol

Number of moles of Al(OH)₃ = 62.7 g / 78.00 g/mol = 0.804 moles

Next, we need to calculate the volume of the solution in liters:

Volume of solution = 500.0 mL = 500.0 mL x (1 L/1000 mL) = 0.500 L

Finally, we can calculate the molar concentration of Al(OH)₃

Molarity = moles of solute/volume of solution in liters

Molarity = 0.804 moles / 0.500 L = 1.61 M

Therefore, the molar concentration of Al(OH)₃ in the solution is 1.61 M.

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Taking in excessive amounts of water without sufficient electrolytes can result in a condition called hyponatremia--- True.

Hyponatremia occurs when the concentration of sodium in the blood becomes abnormally low. Sodium is an essential electrolyte responsible for maintaining proper fluid balance in the body. When there is an imbalance between water intake and electrolyte levels, such as low sodium, it can disrupt the osmotic balance and lead to hyponatremia.

This condition can be potentially dangerous and may cause symptoms such as nausea, headache, confusion, seizures, and in severe cases, it can be life-threatening. It is important to maintain a proper balance of water and electrolytes for overall health and well-being.

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The molar concentration of the weak acid solution is 0.09308 M.

To determine the molar concentration of the weak acid solution, we need to use the balanced chemical equation for the reaction between the weak acid and the strong base NaOH:

HA + NaOH → NaA + H2O

where HA is the weak monoprotic acid and NaA is its corresponding sodium salt.

At the stoichiometric point of the titration, all of the weak acid has reacted with the strong base, and the number of moles of NaOH used is equal to the number of moles of weak acid present in the original solution:

n(HA) = n(NaOH)

We can use the molarity and volume of NaOH used to calculate the number of moles of NaOH used:

n(NaOH) = M(NaOH) × V(NaOH)

= 0.0981 mol/L × 23.74 mL / 1000 mL/L

= 0.002327 moles

Since the molar ratio of HA to NaOH in the balanced equation is 1:1, the number of moles of HA in the original solution is also 0.002327 moles.

To calculate the molar concentration of the weak acid solution, we divide the number of moles of HA by the volume of the original solution used in the titration:

M(HA) = n(HA) / V(HA)

= 0.002327 moles / 25.0 mL / 1000 mL/L

= 0.09308 mol/L

Therefore, the molar concentration of the weak acid solution is 0.09308 M.

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Answer:

125 cubic meters

Explanation:

Subtract 375-250=125 cubic meters

answer:

yes!

explanation:

hope this helped <3 also if wouldn't mind could you pls give me brainliest? (im trying to level up) thanks! :)

Answer:

yes it is

Explanation:

The approximate mass of \(KHC_8H_4O_4\) for the standardization of a NaOH solution is 160.16 g.  

The approximate mass of \(KHC_8H_4O_4\)  (sodium hydrogen carbonate) for the standardization of a NaOH solution can be calculated using the molar mass of the compound.

The molar mass of \(KHC_8H_4O_4\) is 160.16 g/mol, and the mole ratio of KHC8H4O4 to NaOH in the standardization solution is 1:1. Therefore, the mass of NaOH required to react completely with the KHC8H4O4 can be calculated as follows:

mass of NaOH = moles of NaOH x molar mass of NaOH

mass of NaOH = 1 x 58.44 g/mol

mass of NaOH = 58.44 g

The approximate mass of  \(KHC_8H_4O_4\) required for the standardization of a NaOH solution can be calculated as follows:

mass of \(KHC_8H_4O_4\) = moles of  \(KHC_8H_4O_4\) x molar mass of  \(KHC_8H_4O_4\)

mass of  \(KHC_8H_4O_4\) = 1 x 160.16 g/mol

mass of  \(KHC_8H_4O_4\) = 160.16 g

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The amount of heat needed to vaporize 10.00 grams of water at 100.0°C is 2,259 J. Main Calculation Here, we are given that: Mass of water = 10.00 grams Latent heat of vaporization of water = 2,259 J/g

Latent Heat of Vaporization The latent heat of vaporization is the amount of heat that is absorbed per unit mass of a given material, which is undergoing a change of state from liquid to gas, at a constant temperature and pressure. It is expressed in units of energy per mass.

The SI unit of latent heat of vaporization is joules per kilogram (J/kg), while the older, less common unit is calories per gram (cal/g).Specific Latent Heat of Vaporization The specific latent heat of vaporization is the amount of heat that is required to vaporize one unit of mass of a substance, under specific conditions of temperature and pressure.

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Answer:

Explanation:

A chemical formula is the combination of atomic symbols that designate a particular chemical compound, or a substance with two or more different elements.  The formula shows which type and how many of each element makes up that specific compound

Answer:

I believe the answer is A

Explanation:

Work and energy are related because when you work, you cause displacement in the object you are exerting upon. While this happens, you transfer energy between the systems. Both work and energy share the same SI unit, called the joule.

The required additional moles of helium gas must be added to the sample to obtain a volume of 6.4L is 0.293 moles.

Required moles of the final volume will be calculated by using the below equation as:

n₁/V₁ = n₂/V₂, where

n₁ & V₁ are the moles and volume of initial solution.

n₂ & V₂ are the moles and volume of final solution.

On putting values from the question to the equation, we get

n₂ = (0.22)(6.4) / (4.8) = 0.293 moles.

Hence required moles of helium gas is 0.293.

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The amount of manganese oxide that should be added is 0.869 moles.

The balanced equation of the reaction is,

\(MnO _{2} (s) + 4HCl → MnCl _{2}(aq) + 2 H _{2} O + Cl _{2}(g)\)

The volume of hydrochloric acid that has to be obtained is V.

V = 275 ml

The temperature is T.

T = 5° C = (273+ 5) K = 278 K

The pressure is P.

P = 650 mm of Hg = 0.85 atm

The gas constant is R.

R = 0.0821 L atm/ K mol

The number of moles of chlorine gas that will be produced is,

PV = nRT

\( n = \frac{ PV}{ RT }\)

\( n = \frac{0.85 \times 0.275}{0.0821 \times 278} \)

n = 0.01 moles

The 0.01 moles of chlorine gas will be produced.

The amount of manganese oxide that should be added to hydrochloric acid to produce 275 ml of fluorine gas is,

\(0.01 \: mol \: of \: Cl× \frac{ 1 mmol \: of \: MnO }{mol \: of \: Cl } = 0.01 \: moles \: of \: MnO _{2} \: needed.

\)

\(0.01 \: mol \: of \: MnO _{2} = \frac{86.9}{ mol \: of \: MnO _{ 2}}=0.869 \: moles

\)

Therefore, the amount of manganese oxide that should be added to hydrochloric acid to produce 275 ml of fluorine gas is 0.869 moles.

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To calculate the number of millimoles of phenyl bromide present, we need to first convert the given quantity of phenyl bromide (1.4555 g) into moles by dividing it by its molar mass.

The molar mass of phenyl bromide is the sum of the molar masses of its constituent atoms, which is 157.01 g/mol.

Therefore, the number of moles of phenyl bromide present is:

1.4555 g / 157.01 g/mol = 0.0092711 mol

To convert this into millimoles, we need to multiply it by 1000:

0.0092711 mol x 1000 = 9.2711 mmol

Therefore, there are 9.2711 millimoles of phenyl bromide present in the Grignard reaction. It is important to accurately measure the amount of reactants involved in a reaction to determine the stoichiometry and yield of the reaction.

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Answer:C - 3.115 g

Explanation:Correct

why helium is inactive