Can someone make an example of this problem in regular C code. Thank You.
Write a program that tells what coins to give out for any amount of change from 1 cent to 99 cents.
For example, if the amount is 86 cents, the output would be something like the following:
86 cents can be given as 3 quarter(s) 1 dime(s) and 1 penny(pennies)
Use coin denominations of 25 cents (quarters), 10 cents (dimes), and 1 cent (pennies). Do not use nickel
and half-dollar coins.
Use functions like computeCoins. Note: Use integer division and the % operator to implement this
function

Answer:

Increase efficiency

Explanation:

I come from a family of electricians

Explanation:

A business man who really focus on victory achieved through a right procedure will focus on long-term planning.

Let us understand what a short-term and long-term planning is.

Short-term will plan only for two-three years. But a long-term plan will look for future five years income projection, plan of expansion, bigger goals, etc.

A business man is the person who take risks and achieve more. A victory can be achieved in many ways one is taking bigger risks, next is focusing on long-term plans

If this is wrong, give me the answer choices so I know what's right or wrong. I'll edit the question if given to me.

Answer:

To determine the fluid gage pressure that must be maintained in the hydraulic lift, you need to use the equation for force, which is:

Pressure = Force / Area

Where:

Pressure is in units of kPa (kilopascals)

Force is in units of N (newtons) and is equal to the weight of the car (1620 kg) multiplied by the acceleration due to gravity (9.81 m/s^2)

Area is in units of m^2 (square meters) and is equal to the output diameter of the lift (22.8 cm) converted to meters (0.228 m)

So the pressure that must be maintained is:

Pressure = (1620 kg * 9.81 m/s^2) / (0.228 m^2)

Pressure = (15,847.2 N) / (0.228 m^2)

Pressure = 69,844 kPa

So the fluid gage pressure that must be maintained is 69,844 kPa.

Answer: I believe the answer is 963.75 if I am reading the question right.

Explanation:

ACH=60L/V

ACH=2.25

V=25,700

25,700*2.25=57,825

57,825/60=963.75

L=963.75

60(963.75)/25,700=2.25

The maximum amount of air leakage that would result in an ACH of no more than 2.25 would be approximately 956.25 cfm (cubic feet per minute).

Given that ACH of a house is a measure of its​ air-tightness and the formula for ACH is ACH = 60L/V. It means that ACH is inversely proportional to air-tightness or leakage. Therefore, the lower the air leakage the higher the ACH and vice versa.Mathematically, it is represented as:ACH ∝ 1/L or L ∝ 1/ACH

We can solve the question as follows:ACH = 2.25 (since the maximum ACH is 2.25)The volume of the house, V = 25,700 cubic feet.Substituting in the formula,2.25 = 60L/25,700Dividing both sides by 2.25 gives us,L = (2.25 * 25,700)/60L = 956.25 cubic feet per minute (cfm)

Therefore, the maximum amount of air leakage that would result in an ACH of no more than 2.25 is approximately 956.25 cfm (cubic feet per minute).

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A circuit breaker serves the same purpose as a fuse.  The main answer is: Option B - Fuse.

A fuse is a safety device that protects electrical circuits from overcurrent conditions by breaking the circuit when an excessive current flows through it. Similarly, a circuit breaker is designed to automatically interrupt the electrical circuit when it detects an overload or short circuit. Both the fuse and circuit breaker act as protective devices to prevent damage to the electrical system and equipment. Therefore, the correct option is B - Fuse.

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\(f = force\)

\(m = mass \: of \: an \: object\)

\(a = acceleration\)

Newton's second law is one of the most important in all of physics. For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration) are both vector quantities. If a body has a net force acting on it, it is accelerated in accordance with the equation

In tree data structures, a node with no children is known as a leaf node. When deleting a leaf node, it's essential to address the pointer that previously referenced the deleted node.

When a node in a tree with no children (leaf node) is deleted, the pointer to the deleted node in its parent node is set to null (or none, depending on the language being used). This ensures that the parent node no longer has a reference to the deleted node, and the tree structure remains consistent.

Step-by-step:
1. Identify the leaf node to be deleted.
2. Locate its parent node.
3. Set the pointer in the parent node that was pointing to the deleted node to null (or none).
4. The deleted node is now disconnected from the tree.

After deleting a leaf node in a tree, the pointer to the deleted node in its parent node is replaced by null (or none), effectively disconnecting the deleted node from the tree structure.

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A Ni-H battery of 600mAh is used for 1 hour. 28 volts and 2.4 amps are the desired values for the string and the parallel connection. The formula we'll need is the following:Ns x Np = (V / Vbatt) x (I / Ibatt),

where Ns represents the number of batteries in a string, Np is the number of strings in parallel, V is the desired voltage, Vbatt is the voltage of the individual battery, I is the desired current, and Ibatt is the current of the individual battery. First, we need to calculate the current of the battery.600mAh equals 0.6Ah. Dividing it by 1 hour, we get 0.6A for the current. So, Ibatt is 0.6A.Ns x Np = (V / Vbatt) x (I / Ibatt)Now,

let's use the given values.28 volts and 2.4 amps are the desired values. The voltage of the individual battery (Vbatt) is 1.2 volts.Ns x Np = (28 / 1.2) x (2.4 / 0.6)Ns x Np = 58Therefore, we need 58 batteries in total. This could be achieved with 2 strings of 29 batteries each, or with 4 strings of 14 batteries each. If you go with the 4-string setup, you'll connect two sets of two strings in parallel (each containing 14 batteries). You will need 2.4 amps per battery,

therefore a total of 1392mA will be drawn from the parallel connection of each battery.What this means is that one string will provide 1392mA, while four strings will provide 5568mA (4 x 1392). Since 600mAh equals 600mA, it implies that one string will last for 2 minutes (600mA / 1392mA), whereas four strings will last for 8 minutes (2400mA / 1392mA).

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Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Under NFPA 70E, the appropriate PPE for arc flash can be determined by conducting an arc flash hazard analysis which takes into consideration factors such as the incident energy level, working distance, and equipment ratings. This analysis helps to determine the appropriate level of protection needed for workers and ensures that they are equipped with the appropriate PPE, such as flame-resistant clothing, face shields, and gloves, to protect them from the potential hazards of arc flash.

The key factors considered in determining the appropriate PPE for arc flash include:

1. Incident Energy Analysis: This involves calculating the potential thermal energy released during an arc flash event at various locations within the electrical system. The incident energy is typically measured in calories per square centimeter (cal/cm²).

2. Arc Flash Boundary: The arc flash boundary is the distance from the arc source within which a worker could receive a second-degree burn (1.2 cal/cm²). It helps define the safe working distance and determines the level of PPE required for workers within that boundary.

3. PPE Categories: NFPA 70E defines PPE categories (ranging from 1 to 4) based on the incident energy level at a specific location. Each category specifies the minimum arc rating (expressed in cal/cm²) required for the PPE ensemble to protect against arc flash hazards.

By conducting the arc flash risk assessment and determining the incident energy levels at various locations within the electrical system, employers can identify the appropriate PPE category and select the corresponding PPE ensemble to provide adequate protection for workers against arc flash hazards. It is important to follow the guidelines and recommendations provided by NFPA 70E and consult with qualified electrical safety professionals to ensure compliance and worker safety.

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The rate of energy loss through a 1.5 square meter window with the worst R-value (0.9) is 936.7 Btu/hour and the rate of energy loss through the best R-value (11.1) is 75.95 Btu/hour. In order to calculate how much can be saved by replacing all the windows with the highest R-value, relative to the lowest R-value windows, we need to consider the energy loss of all the windows.

We have 18 windows in the house, therefore the amount of energy lost with the lowest R-value windows will be:18 * 936.7 = 16,860.6 Btu/hourOn the other hand, the amount of energy lost with the highest R-value windows will be:18 * 75.95 = 1,367.1 Btu/hour The difference between the two will be the amount of energy that will be saved if we use the highest R-value windows:16,860.6 - 1,367.1 = 15,493.5 Btu/hourNow, we need to consider the duration of the winter, which is 4 months or 120 days, assuming that the house is heated for the entire duration of winter. Therefore, the total amount of energy that can be saved in 4 months or 120 days will be:15,493.5 * 120 = 1,859,220 Btu (rounded off to the nearest whole number).This means that we can save 1,859,220 Btu of energy if we replace all the windows with the highest R-value, relative to the lowest R-value windows over the course of a 4-month winter year.

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Answer:

Answer to the following is as follows;

Explanation:

A request for proposal is a documentation that invites prospective contractors to submit business opportunities to an agency or corporation interested in procuring a commodities, product, or valuable resource through a bid procedure.

A request for proposal (RFP) is a commercial document that introduces a project, defines it, and invites eligible contractors to compete on its completion.

The correct answer is B.Investigate the drive right away by browsing it on the suspect's computer, just in case there are time files .

The following stages may be included in many (or all) inquiry efforts: Data collection, digital search, and . Examining involves using methods to locate and retrieve data. Utilizing resources and data for analysis to support a claim. In order to establish facts and offer correct and in court or other proceedings, an investigation procedure known as "computer " is used. Any system that you believe has been or is somehow connected to an event should have its data collected. It can also provide you with enough details to decide if a subset needs a thorough analysis.

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The mass balance equation for the sewage lagoon can be expressed as:

Qin x Cin = Qout x Cout + V x R

Where:

Qin = influent flow rate = 8,640 m^3/d

Cin = influent concentration of biodegradable contaminant = 100 mg/L

Qout = effluent flow rate = Qin (since there are no losses or gains of water)

Cout = effluent concentration of biodegradable contaminant = 20 mg/L (maximum allowable concentration)

V = volume of lagoon = 10 ha x 10,000 m^2/ha x 1 m = 100,000 m^3

R = biodegradation reaction rate (kg/m^3/d) x density of water = k x Cin

Assuming a first-order reaction, the biodegradation rate can be expressed as:

R = k x Cin

Substituting the values in the mass balance equation and rearranging:

k = (Qin x (Cin - Cout)) / (V x Cin)

k = (8,640 m^3/d x (100 mg/L - 20 mg/L)) / (100,000 m^3 x 100 mg/L)

k = 0.0691 d^-1

Therefore, the biodegradation reaction rate coefficient that must be achieved for a first-order reaction is 0.0691 d^-1.

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i cant solve this but good question

The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:

a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.

From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.

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Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

Answer:

Explanation:

Temperature of atmospheric air To = 25°C = 298 K

Free  stream velocity of air Vo = 25 m/s

Length and width of plate = 1m

Temperature of plate Tp = 125°C = 398 K

We know for air, Prandtl number Pr = 1

And for air, thermal conductivity K = 24.1×10?³ W/mK

Here, charectorestic dimension D = 1m

Given value of Reynolds number Re = 105

For laminar boundary layer flow over flat plate

= 3.402

Therefore, hx = 0.08199 W/m²K

So, heat transfer rate q = hx×A×(Tp – To)

                                          = 0.08199×1×(398 – 298)

The drag per unit span on the model can be calculated using a control volume approach as follows:

Where ρ is the density of the fluid, V is the velocity of the fluid, and z is the distance from the top of the test section to the bottom. The integral can be calculated by summing up the velocity of the fluid at each point from the top to the bottom of the test section. This can be expressed as:

Where Vz is the velocity of the fluid at each point in the test section.

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Answer:

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Explanation:

From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation (\(\dot Q\)), measured in BTU per hour, is represented by this formula:

\(\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4})\) (1)

Where:

\(\epsilon\) - Emissivity, dimensionless.

\(A\) - Surface area of the student, measured in square feet.

\(\sigma\) - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.

\(T_{s}\) - Temperature of the student, measured in Rankine.

\(T_{b}\) - Temperature of the bus, measured in Rankine.

If we know that \(\epsilon = 0.90\), \(A = 16.188\,ft^{2}\), \(\sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}\), \(T_{s} = 554.07\,R\) and \(T_{b} = 527.67\,R\), then the heat transfer rate due to electromagnetic radiation is:

\(\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]\)

\(\dot Q = 417.492\,\frac{BTU}{h}\)

Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:

\(Q = \dot Q \cdot \Delta t\) (2)

Where \(\Delta t\) is the heat transfer time, measured in hours.

If we know that \(\dot Q = 417.492\,\frac{BTU}{h}\) and \(\Delta t = \frac{1}{3}\,h\), then the net energy transfer is:

\(Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)\)

\(Q = 139.164\,BTU\)

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Answer:

A =41 .....

......

......

....C=21

Answer:

Purpose of review papers

They carefully identify and synthesize relevant literature to evaluate a specific research question, substantive domain, theoretical approach, or methodology and thereby provide readers with a state-of-the-art understanding of the research topic.

Translucent plastic brake fluid reservoirs eliminates any need to remove the fluid caps during a complete brake system inspection. (False)

The hydraulic braking systems that use brake fluid convert force into pressure when the brake pedal is depressed, bringing the car to a complete stop. Modern braking systems necessitate routine flushing and brake fluid replacement at predetermined intervals, just like your engine.

All that stands between you and what you're approaching is the braking system of your car. In addition, your car won't stop if it doesn't have the right brake fluid. The safety of not only you and any passengers in your vehicle, but also of other motorists and pedestrians with whom you share the road, is precisely why routine brake maintenance is so crucial.

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At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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Answer:

Scalability

Explanation:

just took a test and it was right.