Becquerel’s experiment consisted of four steps.

1. Get a sample of a uranium salt.
2. Expose the salt to sunlight.
3. Expose photographic plates to the salt.
4. Develop the plates.

A change in which step led to Becquerel’s discovery of radioactivity?
1
2
3
4

Answer:

A

Explanation:

The cells split up into two to repair the damaged cell

Answer:

I am sure it is D or C. have a nice day

A radioactive substance decreases by 65% each hour. Find the hourly decay factor. The hourly decay factor is 0.35.

Chemicals in the class of radionuclides (also known as radioactive materials) have unstable atomic nuclei. They become stable by undergoing modifications in the nucleus (spontaneous fission, alpha particle emission, neutron conversion to protons, or the opposite).

A radioactive atom will naturally emit radiation in the form of energy or particles in order to transition into a more stable state. The difference between radioactive material and the radiation it emits must be made.

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According to the chemical formula of water the volume of hydrogen collected on electrolysis of water will be double of water thus volume of hydrogen is 40 cm.

Chemical  formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called empirical formula.

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Answer:

a. 3.00 mol Al = 3.00 x 27.0 g/mol = 81.0 g

b. 2.56 × 10^24 atoms Li = 2.56 × 10^24 x 6.939 g/mol = 17.75 g

c. 1.38 mol N = 1.38 x 28.0 g/mol = 38.64 g

d. 4.86 × 10^24 atoms Au = 4.86 × 10^24 x 197.0 g/mol = 961.3 g

e. 6.50 mol Cu = 6.50 x 63.5 g/mol = 410.75 g

f. 2.57 × 10^8 mol S = 2.57 × 10^8 x 32.1 g/mol = 82,567,600 g

g. 1.05 × 10^18 atoms Hg = 1.05 × 10^18 x 200.6 g/mol = 210,000 g

Answer:

Geothermal energy.

Explanation:

The vapor pressure of the solution at 25°C is 72.46 mmHg.

To calculate the vapor pressure of the solution, we can use Raoult's law, which states that the vapor pressure of a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.

The mole fraction of the solvent, benzene, can be calculated as follows:

moles of benzene = mass of benzene / molar mass of benzene

moles of benzene = 187.8 g / 78.11 g/mol = 2.404 mol

moles of cholesterol = mass of cholesterol / molar mass of cholesterol

moles of cholesterol = 7.462 g / 386.6 g/mol = 0.0193 mol

The total number of moles in the solution is the sum of the moles of benzene and cholesterol:

total moles = 2.404 mol + 0.0193 mol = 2.423 mol

The mole fraction of benzene is:

Xbenzene = moles of benzene / total moles

Xbenzene = 2.404 mol / 2.423 mol = 0.9921

The vapor pressure of the solution can be calculated as follows:

Pbenzene-solution = Xbenzene x Pbenzene-pure

Pbenzene-solution = 0.9921 x 73.03 mmHg = 72.46 mmHg

Therefore, the vapor pressure of the solution at 25°C is 72.46 mmHg.

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Given data:

- mass % = 3.5%

- mass of solution = 50g

- mass of solute (sodium bicarbonate) = ?

In order to find the mass of solute we must use the next formula

Since we need the mass of solute, we must solve the equation for mas of solute

Now, we must replace the values in the equation

Finally, we must simplify

ANSWER:

The mass of the sodium bicarbonate is 1.75 g

Answer:

59.46 g

Explanation:

To answer this question, the molecular weight of ammonium sulfate must be computed.  To accomplish this, the weights of the individual elements must be noted.
N=14.01\(\frac{g}{mol}\)

H=1.01\(\frac{g}{mol}\)

S=32.07\(\frac{g}{mol}\)

O=16.00\(\frac{g}{mol}\)

To compute the molecular weight:

\(2[14.01\frac{g}{mol}+4(1.01\frac{g}{mol})]+32.07\frac{g}{mol}+4(16.00\frac{g}{mol})=132.14\frac{g}{mol}\)

To calculate the mass:

\(0.45 mol(\frac{132.14g}{1mol})=59.463g\)

Answer:

ok so basicalkly he lloked at how the subdiction zone formed and where previus conintal drift occured

Explanation:

Considering the Dalton's partial pressure, the partial pressure of CO₂ is 2.465 atm and the partial pressure of H₂O is 0.035 atm.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

\(P_{T} =P_{1} +P_{2} +...+P_{n}\)

where n is the amount of gases in the mixture.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

\(P_{A} =x_{A} P_{T}\)

In this case, you know:

Then:

Replacing in the Dalton's law:

\(P_{CO_{2} } =x_{CO_{2}} P_{T}\)

\(P_{CO_{2} } =\) 0.986× 2.50 atm

\(P_{CO_{2} } =\) 2.465 atm

\(P_{H_{2}O } =x_{H_{2}O} P_{T}\)

\(P_{H_{2}O } =\) 0.014× 2.50 atm

\(P_{H_{2}O } =\) 0.035 atm

Finally, the partial pressure of CO₂ is 2.465 atm and the partial pressure of H₂O is 0.035 atm.

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Answer:

Sublimation is a phenomenon by which Solids directly get converted into Gas without conversion into Liquid State.

Explanation:

Eg. Naphthalene balls get converted from solid to gaseous state without being converted into Liquid state.

The true statements are;

A gas's pressure, volume, temperature, and mole count are all related by the ideal gas law. This method treats the vapor of the unidentified liquid as an ideal gas.

The molar mass of the unidentified liquid is calculated using the vapor's density. By rearranging the ideal gas equation, the molar mass can be obtained from the ideal gas law equation.

From the question, we can see that the statements that are true are;

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Answer:

The correct answer is option D

Explanation:

The enzyme enolase is categorized as a metalloenzyme that carries out the catalytic reaction of 2-phosphoglycerate to phosphoenolpyruvate conversion. Several kinetic and spectroscopic methods have been applied to study the role of the divalent metal ions Mg+2 (magnesium ions) involved in the reaction. Both the ions have been shown to coordinate with the carboxylic group of the substrate and product. The coordination provides stability to the intermediate steps in the general base catalysis of enolase (proton abstraction by a base), thereby providing maximum activity to the dimeric molecule.

The enzyme is a molecule that acts as a catalyst while the ions are supposed to facilitate the action of the enzyme. So, option a and b are incorrect. In the reaction, the proton abstraction takes place by a base, not an acid and so, option C is incorrect. The transition state and the intermediate steps are stabilized which facilitates the base catalysis and so, option E is incorrect.

Answer: To facilitate  general base catalysis. Thus option D is correct.

Explanation:

Enolase enzyme is classified as a metalloenzyme that performs the catalytic reaction of converting 2-phosphoglycerate to phosphoenolpyruvate. Various kinetic and spectroscopic methods were used to investigate the role of the divalent Mg+2 metal ions (magnesium ions) involved in the reaction. Both ions were shown to coordinate to the carboxyl group of the substrate and the product. The coordination ensures the stability of the intermediate steps in the general base catalysis of enolase(extraction of the proton by the base) and thus the maximum activity of the dimeric molecule.

An enzyme is a molecule that acts as a catalyst, while ions are believed to facilitate the action of the enzyme .Therefore, options a and b are invalid. The reaction involves the extraction of the proton from the base, not the acid, so option C is incorrect. The transition state and intermediate phases are stabilized, facilitating base catalysis, so option E is wrong.

Answer:

c. element

Explanation:

Because gold is its own element, a gold bar is only made of one element.

The smallest unit found in a bar of gold is the nucleus of its atom.  The core of an atom is called its nucleus which contains the nucleons protons and neutrons.

An atom is composed of  nucleons and electrons. The core of an atom is called its nucleus. Protons and neutrons are located inside the nucleus. They are called the nucleons.

The electrons are revolving around the nucleus through circular trajectories of fixed energies. Every elements are composed of their atoms. Atoms of different elements combine together to form compounds.

Gold is 79th element in periodic table. It is a transition metal in d-block. As every other elements the smallest unit are atoms where the atomic nuclei are even smaller units.

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Answer:

blue curve on edge :)

Explanation:

The 95% margin of error for the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment is ±1.98 (rounded off to two decimal places).

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment can be estimated by using the formula;μ = x ± z(\(a^{2}\)) * σ/√n

Where;μ is the population mean increase.x is the sample mean increase.z(\(a^{2}\)) is the z-scoreα is the level of significanceσ is the population standard deviationn is the sample size.

Substituting the given values into the formula;μ = 9.1 ± 1.96 * 5.5/√37= 9.1 ± 1.98

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment lies between 7.12 to 11.08.

Hence, the estimated mean increase is between 7.12 to 11.08 millimeters of mercury.

The 95% margin of error can be calculated using the formula;

Margin of error (E) = z(\(a^{2}\)) * σ/√n

Margin of error (E) = 1.96 * 5.5/√37

Margin of error (E) = 1.98 (approximated to two decimal places).

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The molarity of the calcium hydroxide solution is 0.0696 M

These are essentially 4-step problems.

1. Write and balance the equation. If we call potassium hydrogen phthalate just KHP, then

Ca(OH)2 + 2KHP ==> 2H2O + CaP + K2P

2. Convert grams to moles. moles KHP = 0.990/molar mass KHC8H4O4 = 0.990/179 = approximately 0.0055

3. Using the coefficients in the balanced equation, convert moles KHP to moles Ca(OH)2

0.0055moles KHP x (1 mole Ca(OH)2/2 moles KHP) = 0.0055 x (1/2) = 0.00275 moles Ca(OH)2.

4. M Ca(OH)2 = moles Ca(OH)2/L Ca(OH)2

 M Ca(OH)2 = 0.00275/0.0395 = approximately 0.0696 M

Part B is done the same way. Now that you have the Ca(OH)2 standardized, use that, with the same process, to determine the molarity of the HI.

Remember that moles = M x L.

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In this question, we have:

31.1 grams of O2

84.3 grams of F2

94.9 L of total volume

55.77°C of temperature which is equal to 328.92 K

Now, to find the pressure of this container, we can find the number of moles of each gas, and add both values together making it one value of moles and then we will use the Ideal gas law to find the pressure, so let's start with O2

The molar mass of O2 is 32g/mol and we have 31.1 grams

32g = 1 mol

31.1g = x moles

x = 0.972 moles of O2

Now for F2, the molar mass is 38g/mol, and we have 84.3 grams

38g = 1 mol

84.3g = x moles

x = 2.22 moles of F2

Now we add these values, 0.972 + 2.22 = 3.192 moles

And now we can use the ideal gas law formula:

PV = nRT

Remember that R is the gas constant, 0.082

P * 94.9 L = 3.192 * 0.082 * 328.92

94.9P = 86.1

P = 0.91 atm

In a solution of magnesium ions and sulfate ions, if the reaction quotient is less than the solubility product, all ions remain solvated.

When the reaction quotient (Q) is less than the solubility product (Ksp), it indicates that the concentrations of the dissolved ions in the solution are below the equilibrium concentrations. In this case, the solution is not saturated and there is no excess of ions to form a precipitate. Instead, the ions continue to stay in their solvated state, meaning they are surrounded by water molecules and are dispersed evenly throughout the solution. Therefore, in the given scenario, when the reaction quotient is less than the solubility product, there is no precipitation or formation of an emulsion. All ions remain solvated in the solution.

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Answer:

i dk how ur school works, but you'll most likely have to take that science again to get the credits u need to graduate

Explanation:

The tests suggest that the original solution contains Group 2 cations (Zn²⁺, Cd²⁺, Pb²⁺), Group 3 cations (Fe³⁺), and possibly Group 4 cations (Ni²⁺, Co²⁺), but does not contain Group 1 cations, Group 2 cations (Mg²⁺), Group 3 cations (Al³⁺), Group 4 cations (Mn²⁺), or Group 5 cations (Cu²⁺).

No precipitate formed when dilute HCl was added, indicating the absence of Group 2 cations (Ca²⁺, Sr²⁺, Ba²⁺) and Group 3 cations (Al³⁺). When H₂S was bubbled through the acidic solution, a precipitate formed and was filtered off. This indicates the presence of Group 2 cations (Zn²⁺, Cd²⁺, Pb²⁺), Group 3 cations (Fe³⁺, Al³⁺), and Group 4 cations (Ni²⁺, Co²⁺, Mn²⁺).

The pH was raised to about 9 and H₂S was bubbled through the solution again. Another precipitate formed and was filtered off. This indicates the presence of Group 4 cations (Ni²⁺, Co²⁺) and Group 5 cations (Cu²⁺). Finally, sodium carbonate was added to the filtered solution and no precipitate formed, indicating the absence of Group 1 cations (Li⁺, Na⁺, K⁺), Group 2 cations (Mg²⁺, Ca²⁺, Sr²⁺, Ba²⁺), Group 3 cations (Al³⁺), Group 4 cations (Ni²⁺, Co²⁺, Mn²⁺), and Group 5 cations (Cu²⁺).

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Answer:

That's correct! Photosynthesis is the process by which plants, algae, and some bacteria convert light energy into chemical energy in the form of glucose. Water is a crucial component of photosynthesis. Here's a breakdown of the process you mentioned:

Water Absorption: Plants absorb water from the soil through their roots. Water is transported from the roots to the leaves through specialized tissues called xylem.

Photosynthesis in Leaves: Within the leaves, specialized structures called chloroplasts contain a pigment called chlorophyll, which captures light energy from the sun.

Carbon Dioxide Uptake: Carbon dioxide (CO2) from the atmosphere enters the leaves through tiny pores called stomata. These openings also allow water vapour to exit the plant in a process known as transpiration.

Photosynthetic Reactions: In the presence of light energy, water molecules in the chloroplasts undergo a process called photolysis. This means they are broken apart into hydrogen ions (H+), electrons (e-), and oxygen (O2). The released oxygen is a byproduct of photosynthesis and is released into the atmosphere.

Formation of Glucose: The hydrogen ions and electrons produced during photolysis are used in a series of chemical reactions known as the Calvin cycle. Within the chloroplasts, carbon dioxide (CO2) combines with the hydrogen ions and electrons to form glucose (C6H12O6).

Other Uses of Glucose: Glucose serves as the primary source of energy for the plant. It is used for various metabolic processes, growth, and the production of other organic compounds needed by the plant.

Overall, photosynthesis is a vital process for plants as it allows them to convert light energy, water, and carbon dioxide into oxygen and glucose, which are essential for their survival and growth.

hey hope that helps, have a great rest of the day :D

3.08*10^23 ions of Na+ and Cl- will be present in 30g of NaCl.

Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.

Mathematically, it can be represented as -

1 mol (Na) + 1 mol (Cl)

= 23.0+ 35.5

= 58.5 g/mol

In 58.5  gram of NaCl, there is one mole of Na or 6.02*10^23 ions

In one gram of NaCl, there will be

  =6.02*10^23/58.5 sodium ions

In 30 grams of  NaCl, the number of sodium ions will be -

(6.02*10^23*30)/ 58.5

=3.08*10^23 ions

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To deploy configuration profiles for computers from Jamf Pro, the Apple Push Notification service (APNs) must be available.

APNs is a cloud-based service provided by Apple that enables the secure transfer of data between Apple devices and servers. It is essential for communication between Jamf Pro and Apple devices during the deployment of configuration profiles.

APNs is used to initiate the connection between the devices and Jamf Pro, allowing for the transfer of the configuration profiles. Without APNs, it would be impossible to deploy configuration profiles to Apple devices using Jamf Pro.

Therefore, it is critical to ensure that APNs is available and functioning correctly before attempting to deploy configuration profiles using Jamf Pro.

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The heat lost by 18.0 g of ethanol during cooling from 63.5 °C to -47.0 °C is approximately -4,193.76 J (or 4.19 kJ, rounded to two decimal places).

The temperature change and the mass of the substance are given. To calculate the heat lost by ethanol during cooling, we can use the formula:

q = mcΔT

where:

q = heat lost or gained (in joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/g·°C)

ΔT = change in temperature (in °C)

First, we need to determine the specific heat capacity of ethanol. The specific heat capacity of ethanol is approximately 2.44 J/g·°C.

Next, let's calculate the heat lost by the given mass of ethanol during cooling.

Step 1: Convert the mass of ethanol to grams.

The given mass is already in grams, so no conversion is needed.

Step 2: Calculate the change in temperature.

ΔT = final temperature - initial temperature

ΔT = (-47.0 °C) - (63.5 °C)

ΔT = -110.5 °C

Step 3: Plug the values into the formula and solve for q.

q = (18.0 g) × (2.44 J/g·°C) × (-110.5 °C)

q ≈ -4,193.76 J

Therefore, the heat lost by 18.0 g of ethanol during cooling from 63.5 °C to -47.0 °C is approximately -4,193.76 J (or 4.19 kJ, rounded to two decimal places). Note that the negative sign indicates heat loss.

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If a flexible hot air balloon has a volume of 350,000 L of air at 40 degrees C and 1 atm, 13636 moles of air are in the balloon . This is taken out by ideal gas law.

The ideal gas law, also known as the general gas equation, is the state equation for a hypothetical ideal gas. Although it has several limitations, it is a good approximation of the behavior of many gases under many conditions. Benoît Paul Émile Clapeyron proposed it in 1834 as a combination of empirical Boyle's law, Charles' law, Avogadro's law, and Gay Lussac's law.

using the equation P × V= n × R × T

P = Pressure = 1 atm

V = Volume = 350000 L

n = moles

R = 0.082 L.atm.K⁻¹.mol⁻¹

solving for n ,

moles n =   13636 moles

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The entropy of the universe increases because energy is continuously dissipating in the form of heat.

The term entropy makes reference to the levels of the randomness (state of disorder) of the matter and energy.

In conclusion, the entropy of the universe increases because energy is continuously dissipating in the form of heat.

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Answer:

\(M_{base}=0.0311M\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

\(n_{acid}=n_{base}\)

Which in terms of molarities and volumes is:

\(M_{acid}V_{acid}=M_{base}V_{base}\)

Thus, we solve for the molarity of the base (KOH) to obtain:

\(M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M\)

Regards!