i. What is the elasticity at point \( g \) ? ii. What is the elasticity at point \( h \) ? (As a first step, determine what the quantity is equal to at \( h \) )

Answer:

100 ml de una disolucion 05 M de sulfate de vivre

The intensity of a sound decreases as the distance from the source increases.

This is because the energy from the sound wave spreads out over a larger area, resulting in a lower energy per unit area.

In this case, we can use the inverse square law to calculate the intensity at a distance of 30 meters. The inverse square law states that the intensity of a sound is inversely proportional to the square of the distance from the source.

Therefore, if the intensity at 10 meters is 0.00009 watts/m2, the intensity at 30 meters would be 0.00001 watts/m2.

This is because the distance from the source has increased by a factor of 3, so the intensity is reduced by a factor of 9 (3 squared).

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Answer:

2700

Explanation:

1m/s=3.6km/hr

Explanation:

a) i) Calculation of the friction force:

The friction force can be determined using the equation:

friction force = coefficient of friction * normal force

The normal force is equal to the weight of the object, which can be calculated as:

normal force = mass * gravitational acceleration

where the gravitational acceleration is approximately 9.8 m/s².

normal force = 75 kg * 9.8 m/s² = 735 N

friction force = 0.4 * 735 N = 294 N

ii) Calculation of the acceleration of the body:

Now, we can calculate the acceleration using Newton's second law:

net force = mass * acceleration

Since the applied force and the friction force act in opposite directions, the net force can be calculated as:

net force = applied force - friction force

net force = 300 N - 294 N = 6 N

mass = 75 kg

6 N = 75 kg * acceleration

acceleration = 6 N / 75 kg = 0.08 m/s²

b) Explanation:

In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.

The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.

The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.

Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.

Type I supernovae are substantially better than type II supernovae at measuring distances to galaxies. The distances between the stars in our Milky Way Galaxy are growing as the universe expands.

Given that they all have the same luminosity, Type Ia supernovae are helpful tools for studying the structure of the cosmos. One can gauge the universe's expansion pace and how that rate changes over time by analyzing the apparent brightness of these objects.

A Type II Supernova produces a supernova remnant as well as neutron stars or black holes, as discussed below. A supernova remnant's bulk and energy are dispersed.

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Answer:

Explanation:

Answer D. Interaction between a pen and paper while you write

Answer:

D.  interaction between a pen and paper while you write

Explanation:

plato

Answer:

A

Explanation:

Because of the convectional currents

13.02 meters

Explanation

the work done by the brakes makes the car stops, so the change in energy equals the work done

hence

also, the work done by a force is given by

then, let

replace

therefore, the answer is

13.02 meters

I hope this helps you

Answer:

First, as you may know, the light travels at a given velocity.

In vaccum, this velocity is c = 3x10^8 m/s.

And we know that:

distance = velocity*time

Now, if some object (like a star ) is really far away, the light that comes from that star may take years to reach the Earth.

This means that the images that the astronomers see today, actually happened years and years ago (So the night sky is like a picture of the "past" of the universe)

Also, for example, if an astronomer sees some particular thing, he can apply a model (a "simplification" of some phenomena that is used to simplify it an explain it) and with the model, the scientist can infer the information of the given thing some time before it was seen.

The astronomers could know what was happening inside galaxies way back then by the fact that;

they examine the spectra of galaxies (or the overall colors of galaxies) with the highest redshifts they can find

Astronomers Measure the wavelength of the light that is stretched, so the light is seen as 'shifted' towards the red part of the spectrum by using spectroscopy. This measure is also called redshift.

This invokes a ray of light through a triangular prism that splits the light into various components known as spectrum.

The way the astronomers could use this concept to know what was happening in the galaxies before is by examining the spectra of galaxies that have the highest redshifts.

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Bill and Jennifer throw a ball at the same speed of 15 m/s from two different heights. The height where the two balls meet is around 71.51068 m. The velocity for Bill's ball and for Jennifer's ball is -4.012 m/s.

(a) To determine how high above the ground the two balls will meet, we can find the time it takes for each ball to reach its highest point and then calculate the total distance traveled by each ball.

For Bill's ball:

Using the equation for vertical displacement, we can calculate the time it takes for the ball to reach its highest point:

y = y₀ + v₀t - (1/2)gt²

0 = 60 + 15t - (1/2)(9.8)t²

Solving this quadratic equation, we find t ≈ 1.94 seconds.

Substituting this time back into the equation for vertical displacement, we can determine the height above the ground where the balls meet:

y = 60 + 15(1.94) - (1/2)(9.8)(1.94)²

with 15(1.94) = 29.1

(1/2)(9.8)(3.7636) = 17.58932

Substituting these values back into the expression for y:

y = 60 + 29.1 - 17.58932

y = 60 + 29.1 - 17.58932

= 89.1 - 17.58932

= 71.51068

Therefore, the height above the ground where the two balls meet is approximately 71.51068 meters.

For Jennifer's ball:

Since Jennifer throws the ball upward with the same initial speed, the time it takes for the ball to reach its highest point is also approximately 1.94 seconds. Therefore, the height above the ground where the balls meet is the same.

(b) The velocities of the balls at the point of meeting can be found using the equation:

v = v₀ - gt

For Bill's ball:

v = 15 - 9.8(1.94)

9.8 * 1.94 = 19.012

v = 15 - 19.012

v = 15 - 19.012

= -4.012 m/s (negative sign indicates the upward direction)

Therefore, the velocity of the ball thrown by Bill at the point of meeting is approximately -4.012 m/s

For Jennifer's ball:

v = -15 - 9.8(1.94)

v = -4.2 m/s  

(c) To determine which ball hits the ground first, we need to compare their total flight times. Since the height above the ground where the balls meet is the same, the ball thrown by Jennifer will take longer to reach the ground because it has to cover the additional distance from the meeting point to the ground.

d) The graph in image below shows that initially, the ball is at the top of the 60-meter building. As time progresses, the ball moves downward, crossing the meeting point, and continues to fall towards the ground.

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Answer:

0.1667Hz

Explanation:

by explanation frequency is given by 1/time

after carrying out the calculation of time we can easily get frequency.

time=speed/distance

=18/3

=6s

but frequency=1/time

hence=1/6

=0.1667hertz

i) The velocity of the particle at 17 sec is 17m/s.

ii) The total distance travelled is 190 m.

iii) The total displacement is -10m.

Distance is the length of any path connecting any two places. As measured along the shortest path between any two points, displacement is the direct distance between them.

The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.

Since it solely depends on magnitude and not direction, distance is a scalar number. Since displacement varies on both magnitude and direction, it is a vector quantity.

Distance provides specific directions that must be taken when moving from one location to another. Displacement only provides a partial description of the route because it pertains to the quickest way.

Velocity of particle = Slope of the object =Δ \(\frac{y}{x}\)

Velocity = \(\frac{95-10}{20-15}\) = 17m/s

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Answer:

Your education back ground

Among the answer choices provided, correct option is (A) which means smallest charge is \(1.6 * 10^(-19)\) coulombs.

Charge is a fundamental property of matter and is quantized, which means it can only exist in discrete amounts, rather than being continuous. The smallest unit of charge is the charge of an electron, which has a magnitude of \(1.602 * 10^(-19)\) coulombs. This value is given in option (A).

Option (B) \(6.63 * 10^(-34)\) coulombs is not a valid value for charge since it is in the range of Planck's constant, which is a fundamental constant in quantum mechanics.

Option (C) \(1.38 * 10^(-23)\) coulombs is the value of the Boltzmann constant, which is related to the average kinetic energy of particles in a gas.

Option (D) \(5.34 * 10^(-20)\) coulombs and option

(E) \(8.85 * 10^(-12)\)coulombs are not valid values for the smallest unit of charge, as they are not within the range of any known physical constant or value.

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The cross-sectional area of a circle is given by:

A = π * r^2

A = π * (0.79 × 10^-3 m)^2 = 4.91 × 10^-7 m^2

σ = 6.0 × 10^7 Ω^-1m^-1

I = 4.5 A

Therefore,

E = 4.5 A / (6.0 × 10^7 Ω^-1m^-1 * 4.91 × 10^-7 m^2) = 1.84 × 10^-2 V/m

If we replace the copper wire with a gold wire of the same size, the electric field inside the wire will change.

σ = 4.1 × 10^7 Ω^-1m^-1

E = 4.5 A / (4.1 × 10^7 Ω^-1m^-1 * 4.91 × 10^-7 m^2) = 2.17 × 10^-2 V/m

Therefore, the electric field in the gold wire will be higher than in the copper wire.

The conductivity of gold (4.1 × 10^7 Ω^-1m^-1) is lower than that of copper (6.0 × 10^7 Ω^-1m^-1). Therefore, to maintain the same current of 4.5 A, the electric field inside the gold wire must be higher than that in the copper wire. This means more energy is required to maintain the same current in the gold wire.

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a metaphor for generosity and joy and joy and joy and joy organised a large wedding guests had to choose their meal from beef chicken tikka and a kind young women in the streets of St

The number of excess electrons needed to be distributed uniformly in the sphere to produce the given electric field is 1.69*10^(10).

What is an electric field?

The electric force exerted on a unit charge is called the electric field.

For a sphere of uniform charge density, the magnitude of the electric field on its surface is given by,

E=k*q/r^2

where E is the magnitude of the electric field, k is the coulomb's constant which has a value of 9*10^9 N m^(2) C^(-2), and q is the total charge of the sphere, and r is the radius of the sphere.

The radius of the sphere is half of the diameter. Given the diameter of the sphere is 26.0 m, the radius of the sphere r=26.0/2 cm or r=13.0 cm.

It is given that E=1440 N/C, r=13.0 cm, and the value of k is 9*10^9 N m^(2) C^(-2). Substitute these values in the formula of the electric field and solve it to get the value of the total charge on the sphere.

Note: 1 cm = 0.01 m.

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13 cm)^2

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13*0.01 m)^2

1440 ( N/C)= (532.54*10^(9) N C^(-2))*q

q=1440/(532.54*10^(9)) C

q=2.704*10^(-9) C

Since the charge is quantized, the total charge inside the sphere is the integral multiple of an elementary charge. In the given case, the value of that elementary charge is 1.6*10^(-19) C. The total charge is then given by,

q=ne

where q is the total charge, n is the number of elementary charges and e is the value of the elementary charge.

The value of q is 2.704*10^(-9) C and the value of e is 1.6*10^(-19) C.

Substitute these values in the formula of total charge and solve it to get the number of elementary charges.

2.704*10^(-9) C =n*1.6*10^(-19) C

n=2.704*10^(-9)/ 1.6*10^(-19)

n=1.69*10^(10)

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To find the Thevenin equivalent voltage with respect to terminals a and b in the given circuit, follow these steps:

1. Disconnect any sources (in this case, the 8.2V source) from the circuit.
2. Calculate the equivalent resistance between terminals a and b. This can be done using various methods such as series and parallel combinations of resistors.
3. Reconnect the sources, and measure the voltage across the terminals a and b. This voltage will be the Thevenin equivalent voltage.
Without a diagram or specific information about the circuit, it is not possible to provide an exact calculation. However, I can guide you through the general process. If you provide more details or a circuit diagram, I can provide a more specific answer.

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Answer:

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

Potential and kinetic energy are at play when we talk about Newton's second law of motion through the various positions in relation to the bodies involved.

This law states that force is equal to the rate of change of momentum and is denoted as F = mv where m is mass and v is velocity.

Potential energy is the energy is possessed by a body by virtue of its position while kinetic energy is possessed by a body by virtue of its motion. Both forms of energy are influenced by forces and are equal to the total momentum.

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After the collision, block A will be moving to the left at 1.56 m/s and block B will be moving to the left at 0.50 m/s. In this type of collision, the momentum of the system is conserved.

We can use the law of conservation of momentum to determine the velocities of the blocks after the collision. The total momentum of the system before the collision is the momentum of block A plus the momentum of block B, and the total momentum after the collision must also be the same.

The momentum of each block before the collision is given by the mass of the block multiplied by its velocity

p_A = m_A * v_A = 8.00 kg * 2.00 m/s = 16.00 kg m/s (to the right)

p_B = m_B * v_B = 15.00 kg * -0.500 m/s = -7.50 kg m/s (to the left)

p_initial = p_A + p_B = 16.00 kg m/s + (-7.50 kg m/s) = 8.50 kg m/s (to the right)

After the collision, we can use the law of conservation of momentum to find the final velocities of the blocks.

p_final = p_A' + p_B' = m_A * v_A' + m_B * v_B' = 8.00 kg * v_A' + 15.00 kg * v_B' = 8.00 kg * v_A' - 7.50 kg m/s

we know that p_final = p_initial = 8.50 kg m/s, so we can set the two equations equal to each other.

8.50 kg m/s = 8.00 kg * v_A' - 7.50 kg m/s

so

v_A' = (8.50 kg m/s + 7.50 kg m/s) / 8.00 kg = 1.56 m/s (to the left)

and

v_B' = -0.500 m/s (to the left)

Therefore, after the collision, block A will be moving to the left at 1.56 m/s and block B will be moving to the left at 0.50 m/s. In this type of collision, the momentum of the system is conserved, and both blocks reverse their directions of motion.

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The correct answer is(b). There is a physical change from the solid state to a gas state where energy between the molecules increases.

During sublimation, carbon dioxide transitions directly from the solid state (dry ice) to the gas state without passing through the liquid phase. In this process, individual molecules of carbon dioxide gain energy from the surroundings, leading to an increase in their kinetic energy and molecular movement.

As a result, the carbon dioxide molecules separate from each other and form a gas. This phase change is considered a physical change rather than a chemical change since the chemical composition of carbon dioxide remains the same throughout the process.

Therefore, the sublimation of carbon dioxide results in a physical change where the molecules transition from the solid state to the gas state, gaining energy and increasing their molecular movement.

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Answer:

q = 0.384 C

Explanation:

The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:

\(q = ne\)

where,

q = total charge on head = ?

n = total no. of electrons on the head = 2.4 x 10¹⁸

e = charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)

q = 0.384 C

When the air resistance equals 100 pounds, the acceleration of the sack will be: zero.

So, the correct answer is C.

When a 100-pound sack of potatoes falls from an airplane, it experiences gravitational force and air resistance.

The gravitational force acts downward, while air resistance acts upward.

As the velocity of the falling sack increases, the air resistance also increases. When the air resistance equals 100 pounds, it balances the gravitational force acting on the sack.

At this point, the net force acting on the sack is zero (100 pounds - 100 pounds = 0), as the air resistance and gravitational force cancel each other out.

According to Newton's second law of motion, F = ma, when the net force (F) is zero, the acceleration (a) is also zero.

Therefore, the correct answer is c. zero.

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Answer:

550N

Explanation:

Force=Mass ×Acceleration

= 55kg×10m/s²

=550N

The resultant

vector

R-A-B-C-D is approximately 2.3638 cm at an angle of arctan(Ry/Rx): ≈ 8.5157 cm

To find the

resultant

vector R-A-B-C-D using the analytical method, we need to calculate the x and y

components

of each vector and then sum them up.

Let's start with vector A:

A = 7 cm at 35°

The x component of A can be calculated using the formula:

Ax = A * cos(θ)

Ax = 7 cm * cos(35°)

Ax = 7 cm * 0.8192

Ax ≈ 5.7344 cm

The y component of A can be calculated using the formula:

Ay = A * sin(θ)

Ay = 7 cm * sin(35°)

Ay = 7 cm * 0.5736

Ay ≈ 4.0152 cm

Next, let's move on to vector B:

B = 8 cm at 120°

The x component of B can be calculated using the formula:

Bx = B * cos(θ)

Bx = 8 cm * cos(120°)

Bx = 8 cm * (-0.5)

Bx = -4 cm

The y component of B can be calculated using the formula:

By = B * sin(θ)

By = 8 cm * sin(120°)

By = 8 cm * 0.8660

By ≈ 6.928 cm

Now, let's calculate the vector Ĉ:

Ĉ = 2.5 cm at 240°

The x component of Ĉ can be calculated using the formula:

Ĉx = Ĉ * cos(θ)

Ĉx = 2.5 cm * cos(240°)

Ĉx = 2.5 cm * (-0.5)

Ĉx = -1.25 cm

The y component of Ĉ can be calculated using the formula:

Ĉy = Ĉ * sin(θ)

Ĉy = 2.5 cm * sin(240°)

Ĉy = 2.5 cm * (-0.8660)

Ĉy ≈ -2.165 cm

Lastly, let's calculate the vector D:

D = 2 cm at 320°

The x component of D can be calculated using the formula:

Dx = D * cos(θ)

Dx = 2 cm * cos(320°)

Dx = 2 cm * 0.9397

Dx ≈ 1.8794 cm

The y component of D can be calculated using the formula:

Dy = D * sin(θ)

Dy = 2 cm * sin(320°)

Dy = 2 cm * (-0.3420)

Dy ≈ -0.684 cm

By the

analytical

method:

Now we can sum up the x and y components of all the vectors:

Rx = Ax + Bx + Ĉx + Dx

Rx = 5.7344 cm + (-4 cm) + (-1.25 cm) + 1.8794 cm

Rx ≈ 2.3638 cm

Ry = Ay + By + Ĉy + Dy

Ry = 4.0152 cm + 6.928 cm + (-2.165 cm) + (-0.684 cm)

Ry ≈ 8.0942 cm

Therefore, the resultant vector R-A-B-C-D is approximately 2.3638 cm at an

angle

of arctan(Ry/Rx):

R = sqrt(Rx^2 + Ry^2)

R = sqrt((2.3638 cm)^2 + (8.0942 cm)^2)

R ≈ 8.5157 cm

θ = arctan(Ry/Rx)

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Answer: B is DEFINITELY the answer no doubt about it!