Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin. Use the polygon tool to graph the triangle.

Answer:

...

Step-by-step explanation:

2. 5.25, because the radius is half the diameter

3. 3 in because the diameter is 2x the radius

4. i.dk this one sorry

Answer:

2. 5.25in

3. 3 in

4. 81.68 or 82

Step-by-step explanation:

The first two are basically multiplication and division. radius is half the diameter, and diameter is the whole of radius.  the circumference is 3.14 or \(\pi\) x diameter

so you need to add the radius (13) by itself (13+13) to get the diameter (or 13*2) then multiply by 3.14159. (26*3.14159 = 81.68) and if you need to round its 82.

~R3V0

Hey there! I'm happy to help!

To find the volume of a rectangular prism, you simply multiply each of the three different sides!

18×9×17=2754

Therefore, the volume of this rectangular prism is c. 2754 units cubed.

Now you can find the volume of a rectangular prism! Have a wonderful day!

The inference procedure for each is give below-

A. The inference procedure: Confidence Interval - One mean, μ.

C. The inference procedure: Hypothesis test - Difference in proportions from two samples, P1-P2.

E. The inference procedure: Confidence Interval - One proportion, p.

G. The inference procedure: Confidence Interval - Difference in proportions from two separate samples, M1-M2

I. The Inference procedure: Hypothesis test - Difference in means from two independent samples.

K. The Inference procedure: Hypothesis test - Paired means, HD.

B. The Inference procedure: Hypothesis test - Difference in proportions from two samples, P1-P2.

D. The Inference procedure: Hypothesis test - One mean, μ.

F. Inference procedure: Confidence Interval - Paired means, HD.

H. Inference procedure: Hypothesis test - One proportion, p.

J. Inference procedure: Confidence Interval - Difference in means from two independent samples.

L. It doesn't directly involve inference.

Now we have-

A. What's the average number of free throws for the Warriors to attempt during a game?

Distribution type: z

C. Do the Warriors make more free throws (on average) during games at home than on the road?

Simulation type: BT (bootstrap)

Distribution type: z

E. What proportion of free throw attempts do the Warrior players make?

Simulation type: BT (bootstrap)

Distribution type: z

G. How much better (or worse) are the Warriors at making free throw attempts compared to their opponents?

Simulation type: BT (bootstrap)

Distribution type: z

I. Is the mean number of free throw attempts awarded to the Warriors during their games different from the mean number attempted by their opponents?

Distribution type: z

K. (Challenge) On average, is the point spread when GSWarriors win larger than the point spread when they lose?

Simulation type: BT (bootstrap)

Distribution type: z

B. Is the proportion of free throws made by the Warriors different between games they play at home and those they play on the road?

Simulation type: BT (bootstrap)

Distribution type: z

D. Over the past 10 years, NBA teams have averaged close to 25 free throw attempts per game. Treating this as the population mean, is the mean number of free throw attempts by the Warriors much different?

Simulation type: BT (bootstrap)

Distribution type: z

F. How many more (or fewer) free throw attempts do the Warriors take on average for home games compared to road games?

Simulation type: BT (bootstrap)

Distribution type: z

H. Players in the NBA as a whole make about 75.6% of their free throws. Is the proportion made by the Warriors different from this?

Simulation type: BT (bootstrap)

Distribution type: z

J. How does the average number of free throws made (per game) by the Warriors compare to their opponents?

Distribution type: z

L. (Extra) On average, what is the point spread in GS Warrior games? (where "+" means they won; "-"means they lost)

This case doesn't directly involve inference.  As it requires calculating the average point spread, but it doesn't involve making statistical inferences about a population parameter.

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Answer:

So your answer for X all of them equals 2

To find the growth rate per year, we need to use the formula y = Ce^kt, where y is the number of internet users, t is the number of years, C is the initial number of internet users, and k is the growth rate. the predicted approximate month and year when there will be 5 billion internet users is 13.5 years after 2000,

In 2000, there were 300 million internet users, so C = 300 million. In 2005, there were 1 billion internet users, so y = 1 billion and t = 5 (since 2005 is 5 years after 2000).

Substituting these values into the formula, we get:

1 billion = 300 million e^(5k)

To solve for k, we can divide both sides by 300 million and then take the natural logarithm of both sides:

ln(1 billion/300 million) = 5k

ln(3.33) = 5k

k = ln(3.33)/5 = 0.239

So the growth rate per year is approximately 0.239.

To predict when there will be 5 billion internet users, we can use the same formula and solve for t:

5 billion = 300 million e^(0.239t)

Dividing both sides by 300 million, we get:

16.67 = e^(0.239t)

Taking the natural logarithm of both sides, we get:

ln(16.67) = 0.239t

t = ln(16.67)/0.239 = 13.5

So the predicted approximate month and year when there will be 5 billion internet users is 13.5 years after 2000, which is June/July 2013.

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Answer:

m'n' equals 13

Step-by-step explanation:

39 divided by 1/3 equals 13

Answer:

x = 4

Step-by-step explanation:

5x + 2 and 4x + 6 are alternate angles and are congruent, thus

5x + 2 = 4x + 6 ( subtract 4x from both sides )

x + 2 = 6 ( subtract 2 from both sides )

x = 4

The relation R is not transitive because the statement ∀x∀y∀z.R(x, y) is not sufficient to establish transitivity. Transitivity requires that if R(x, y) and R(y, z) are true, then R(x, z) must also be true for all x, y, and z. However, the given statement only asserts the existence of a relation between x and y, without specifying any relationship between y and z. Therefore, we cannot conclude that R is transitive based on the given condition.

Transitivity is a property of relations that states if there is a relation between two elements and another relation between the second element and a third element, then there must be a relation between the first and third elements. In the case of relation A(x, y) defined in the question, A is true if and only if the sets x and y have the same size (denoted by |x| = |y|).

To check transitivity, we need to examine whether the given condition ∀x∀y∀z.R(x, y) implies transitivity. However, the statement ∀x∀y∀z.R(x, y) simply asserts the existence of a relation between any elements x and y, without specifying any relationship between y and z. In other words, it does not guarantee that if there is a relation between x and y, and a relation between y and z, there will be a relation between x and z.

To illustrate this, consider the following counterexample: Let x = {1, 2}, y = {3, 4}, and z = {5, 6}. Here, |x| = |y| and |y| = |z|, satisfying the condition of relation A. However, there is no relation between x and z since |x| ≠ |z|. Therefore, the given condition does not establish transitivity for relation A.

In conclusion, the relation A(x, y) defined in the question is not transitive based on the given condition. Additional conditions or constraints would be required to ensure transitivity.

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ANSWER :

9/41

EXPLANATION :

Using Pythagorean Theorem to find the other side of the triangle :

Recall that cos angle is adjacent over hypotenuse

The adjacent side to angle R is QR and the hypotenuse is RP

That will be :

The population of Americans over age 100 was changing at a rate of 0.0378 million people/decade at the beginning of 2000.

To find how fast the population of Americans over age 100 was changing at the beginning of 2000, we need to take the derivative of the function P(t) with respect to t. The derivative of P(t) with respect to t is given by:

P'(t) = 0.54*0.07e0.54t

At the beginning of 2000, t = 0. So, we need to plug in t = 0 into the derivative to find how fast the population was changing at that time:

P'(0) = 0.54*0.07e0.54*0 = 0.0378

Therefore, the answer will be 0.0378.

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using methods taught in this course, the following identity. Your work should be legible, and all your logic should be clear and justifiecos^(-1) (x) = phi - sin^(-1) - [(1-x^(2))^(1/2)], where x<0,We have proven the identity cos⁽⁻¹⁾(x) = φ - sin.

to prove the identity cos⁽⁻¹⁾(x) = φ - sin⁽⁻¹⁾(√(1-x²)), where x < 0, we will use the following definitions:cos⁽⁻¹⁾(x) = φ, where φ is the angle in the interval [0, π] whose cosine is x.sin⁽⁻¹⁾(x) = θ, where θ is the angle in the interval [-π/2, π/2] whose sine is x.first, we note that if x < 0, then √(1 - x²) > 0, so sin⁽⁻¹⁾(√(1 - x²)) is in the interval [0, π/2]. thus, to get an angle in the interval [0, π], we need to subtract this angle from φ.

we begin by using the pythagorean identity for sine and cosine:sin²(θ) + cos²(θ) = 1solving for sin²(θ), we get:sin²(θ) = 1 - cos²(θ)

taking the square root of both sides, we get:sin(θ) = ±√(1 - cos²(θ))since sin⁽⁻¹⁾(x) is the angle in the interval [-π/2, π/2] whose sine is x, we take the negative square root to get:sin⁽⁻¹⁾(x) = -cos⁽⁻¹⁾(√(1 - x²))

substituting this expression into the original identity, we get:cos⁽⁻¹⁾(x) = φ - (-cos⁽⁻¹⁾(√(1 - x²)))simplifying, we get:

cos⁽⁻¹⁾(x) = φ + cos⁽⁻¹⁾(√(1 - x²))taking the cosine of both sides, we get:cos(cos⁽⁻¹⁾(x)) = cos(φ + cos⁽⁻¹⁾(√(1 - x²)))using the identity cos(α + β) = cos(α)cos(β) - sin(α)sin(β), we get:

x = cos(φ)cos(cos⁽⁻¹⁾(√(1 - x²))) - sin(φ)sin(cos⁽⁻¹⁾(√(1 - x²)))using the definition of cos⁽⁻¹⁾(x) as φ, we have:x = x√(1 - (cos(φ))²) - sin(φ)sin(cos⁽⁻¹⁾(√(1 - x²)))using the pythagorean identity again, we have:

x = x√(sin²(φ)) - sin(φ)sin(cos⁽⁻¹⁾(√(1 - x²)))simplifying, we get:x = xsin(φ) - sin(φ)sin(cos⁽⁻¹⁾(√(1 - x²)))factoring out sin(φ), we get:

x = sin(φ)(x - sin(cos⁽⁻¹⁾(√(1 - x²))))dividing both sides by (x - sin(cos⁽⁻¹⁾(√(1 - x²)))), we get:sin⁽⁻¹⁾(√(1 - x²)) = φ - cos⁽⁻¹⁾(x)substituting this expression into the original identity, we get:

cos⁽⁻¹⁾(x) = φ - sin⁽⁻¹⁾(√(1 - x²))

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If the poles are located at A(7, 7), B(16, 7), C(2, 2), and D(16, 2), then the number of foot of fencing that he need to fence in the garden is 48.16 foot

The poles are located at A(7, 7), B(16, 7), C(2, 2), and D(16, 2)

The distance between two points = \(\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }\)

The distance between A and B = \(\sqrt{(16-7)^{2}+(7-7)^{2} }\)

= 9 foot

The distance between B and C = \(\sqrt{(2-16)^{2}+(2-7)^{2} }\)

=\(\sqrt{196+25}\)

= 14.86 foot

The distance between C and D = \(\sqrt{(16-2)^{2}+(2-2)^{2} }\)

= 14 foot

The distance between D and A = \(\sqrt{(7-16)^{2}+(7-2)^{2} }\)

=\(\sqrt{81+25}\)

= 10.30 foot

The number of foot of fencing that he need to fence in the garden = The perimeter of the garden

= 9+14.86+14+10.30

=48.16 foot

Hence, if the poles are located at A(7, 7), B(16, 7), C(2, 2), and D(16, 2), then the number of foot of fencing that he need to fence in the garden is 48.16 foot

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To find the rate at which the temperature is rising on the bug's path after 2 seconds, we need to use the chain rule of differentiation.

Let T denote the temperature function. Then, the rate of change of temperature with respect to time t is given by dT/dt = (dT/dx)(dx/dt) + (dT/dy)(dy/dt). Substituting the given values, we have dT/dt = (2/sqrt(2+t)) + 9/2. Evaluating this expression at t = 2, we get dT/dt ≈ 6.72 degrees Celsius per second.

To find the equation of the tangent plane to the given surface z = 4(x -1)^2 + 3(y + 3)^2 + 6 at the point (2, -2, 13), we need to find the partial derivatives of the surface with respect to x and y. These are given by ∂z/∂x = 8(x-1) and ∂z/∂y = 6(y+3).

Evaluating these at the given point, we get ∂z/∂x = 8 and ∂z/∂y = 0. Thus, the normal vector to the tangent plane is given by (8, 0, -1). Using the point-normal form of the equation of a plane, we get the equation of the tangent plane as 8(x-2) - z + 13 = 0.

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The length of -EF is approximately 31.8 cm. the closest choice to the calculated length is C) 21.8 cm.

To find the length of -EF, we can use the tangent-secant theorem, which states that when a tangent and a secant intersect at a point outside the circle, the product of the lengths of the secant's external segment and the entire secant is equal.

Given that -ED is tangent to the circle at point D and ED = 24 cm, we need to find the length of -EF.

Let's label the point where -ED intersects the circle as A. We can form a right triangle with -ED as the hypotenuse, with legs -EA and AD.

Since -ED is tangent to the circle, angle EDA is a right angle. Thus, we have a right triangle △EDA.

Thus, the length of -EF is approximately 31.8 cm.

Among the given options, the closest choice to the calculated length is C) 21.8 cm.

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We can arrange the 2023 squares to cover the unit square, with overlaps allowed.

We can prove that a collection of 2023 closed squares of total area 4 can be arranged to cover a unit square by using the pigeonhole principle. Since the total area of the squares is 4, the average area of each square is 4/2023. Let's take a unit square and divide it into 2023 smaller squares of area (1/2023) each. By the pigeonhole principle, we can assign one of the 2023 squares to each of the smaller squares. Since the average area of each square is 4/2023, each of the assigned squares will overlap with at most 4 other squares. Therefore, we can arrange the 2023 squares to cover the unit square, with overlaps allowed.

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Write out the expression

Write out the formula to obtain the term that would be added to make it a perfect square trinomial

Write out the data given to obtain "C"

Obtaining for the value of "c"

The term that would be added to make it a perfect square trinomial is 121.

The correct answer is the numbers are statistics because the numbers were calculated from a sample of city University of New York students and are estimates.

The study of statistics focuses on gathering, organising, analysing, interpreting, and presenting data. It is customary to initiate with a statistical population or a statistical model to be researched when applying statistics to a scientific, industrial, or social problem.

Populations which can refer to a variety of groupings of individuals or things, such as "every individual living in a nation" or "each atom making up a crystal."

Every facet of data which includes the planning of data collecting in terms of the layout of surveys and experiments, is covered by statistics.

When census data cannot be gathered, statisticians devise specialised experiment designs and survey samples to get data. A representative sample ensures that generalisations and inferences from the sample to the entire population are reasonable.

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Answer:

0cm

i think the the area doesn't exist

Step-by-step explanation:

soln:

given:

a=8cm

b=16cm

area of triangle ABC(A)=?

here,

A=b/4√4a^2-b^2

or,A=16/4√4(8)^2-(16)^2

or,A=4√4*64-256

or,A=4√256-256

or,A=4√0

or,A=4*0

•°•A=0cm

Answer:

x = 261.50 ft

Step-by-step explanation:

From the question, we want to calculate the distance from the tugboat given the height of the hose above the ocean

This means y is 3 and we want to find x

Substitute value for y

3 = -0.0045x^2 + 1.15x + 10

3 + 0.0045x^2 - 1.15x - 10 = 0

That will be;

0.0045x^2 - 1.15x - 7 = 0

we can use the quadratic formula here;

a = 0.0045

b = -1.15

c = -7

Mathematically;

x = -b ± √b^2 - 4ac/2a

Thus we have;

x = 1.15 ± √(-1.15)^2 - 4(0.0045)(-7)/2(0.0045)

We have;

x = 1.15 ± 1.2035/0.009

x = (1.15+ 1.2035)/0.009

we ignore the negative since distance cannot be negative

x = 261.50 ft

Answer:

the third one (I don’t know if you put it as b on purpose or not that’s why I’m calling it the third one)

Step-by-step explanation:

it’s says the puppy gained 2 pound for x weeks so you know that the variable (x) will be associated with the 2 and it already weighed 10 pounds so your adding from there.

Answer:

B (2x + 10 = 16)

Step-by-step explanation:

initial weight = 10 pounds

2 pounds per week for x weeks, so

2 multiplied by the number of weeks

= 2x

It now weighs 16 pounds in total

so, 10 added to it's weight per week

= 10 + 2x

= 16

so

2x + 10 = 16

Therefore, the top of the ladder is sliding down the wall at a rate of 3.75 ft/sec (negative rate) when the bottom is 15 feet from the wall.

To solve this problem, we can use related rates and the Pythagorean theorem.

Let's denote the distance between the bottom of the ladder and the wall as x, and the height of the ladder (distance from the ground to the top of the ladder) as y. We are given that dx/dt = -2 ft/sec (negative because the bottom is sliding away from the wall).

According to the Pythagorean theorem, x^2 + y^2 = 17^2.

Differentiating both sides of the equation with respect to time t, we get:

2x(dx/dt) + 2y(dy/dt) = 0.

Substituting the given values, x = 15 ft and dx/dt = -2 ft/sec, we can solve for dy/dt:

2(15)(-2) + 2y(dy/dt) = 0,

-60 + 2y(dy/dt) = 0,

2y(dy/dt) = 60,

dy/dt = 60 / (2y).

To find the value of y, we can use the Pythagorean theorem:

x^2 + y^2 = 17^2,

15^2 + y^2 = 289,

y^2 = 289 - 225,

y^2 = 64,

y = 8 ft.

Now we can substitute y = 8 ft into the equation to find dy/dt:

dy/dt = 60 / (2 * 8) = 60 / 16 = 3.75 ft/sec.

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Answer:

4 years

Step-by-step explanation:

The simple interest = $6,500 - $5,000 = $1500

From the formula for simple interest;

I=PRT/100

T= 100 I/PR

T= 100 × 1500/5000 × 7.5

T= 150000/37500

T= 4 years

\(\\ \tt\hookrightarrow \sqrt{\dfrac{1}{64}}=\dfrac{\sqrt{1}}{\sqrt{64}}=\dfrac{1}{8}=0.125\)

\(\\ \tt\hookrightarrow \dfrac{1}{5}=0.2\)

\(\\ \tt\hookrightarrow 0.2222\approx 0.3\)

So the order is

\(\\ \tt\hookrightarrow 0.125<0.2<0.222\)

The cost of one computer is £600 and the cost of one printer is £800.

Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.

Let the cost of a computer be x and the cost of a printer be y.

Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)

4x + 5y = 6000 ---------------------- (2)

Solving equations (1) and (2) simultaneously:x = 600y = 800

Therefore, the cost of a computer is £600 and the cost of a printer is £800..

:Therefore, the cost of one computer is £600 and the cost of one printer is £800.

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\(\(\frac{{\partial z}}{{\partial x}} = ye^{xy}\)\), \(\(\frac{{\partial z}}{{\partial y}} = xe^{xy}\)\), To find the first partial derivatives of the function \(z = e^{xy}\) with respect to \(x\) and \(y\), we need to differentiate the function with respect to each variable while treating the other variable as a constant.

Let's find \(\(\frac{{\partial z}}{{\partial x}}\)\) first:

To differentiate \(\(e^{xy}\)\) with respect to \(x\), we can use the chain rule. Let \(u = xy\). Then \(\(\frac{{\partial z}}{{\partial x}} = \frac{{\partial z}}{{\partial u}} \cdot \frac{{\partial u}}{{\partial x}}\)\).

Differentiating \(e^u\) with respect to \(u\) gives us \(\(\frac{{\partial z}}{{\partial u}} = e^u\)\).

To differentiate \(u = xy\) with respect to \(x\), we treat \(y\) as a constant. So \(\(\frac{{\partial u}}{{\partial x}} = y\)\).

Putting it all together, we have:

\(\(\frac{{\partial z}}{{\partial x}} = \frac{{\partial z}}{{\partial u}} \cdot \frac{{\partial u}}{{\partial x}} = e^u \cdot y\)\).

Since \(u = xy\), we substitute it back in: \(\(\frac{{\partial z}}{{\partial x}} = e^{xy} \cdot y\)\).

Therefore, \(\(\frac{{\partial z}}{{\partial x}} = ye^{xy}\)\).

Now let's find \(\(\frac{{\partial z}}{{\partial y}}\)\):

To differentiate \(\(e^{xy}\)\) with respect to \(y\), we again use the chain rule. Let \(v = xy\). Then \(\(\frac{{\partial z}}{{\partial y}} = \frac{{\partial z}}{{\partial v}} \cdot \frac{{\partial v}}{{\partial y}}\)\).

Differentiating \(e^v\) with respect to \(v\) gives us  \(\(\frac{{\partial z}}{{\partial v}} = e^v\)\\\).

To differentiate \(v = xy\) with respect to \(y\), we treat \(x\) as a constant. So \(\(\frac{{\partial v}}{{\partial y}} = x\)\).

Combining these results, we get: \(\(\frac{{\partial z}}{{\partial y}} = \frac{{\partial z}}{{\partial v}} \cdot \frac{{\partial v}}{{\partial y}} = e^v \cdot x\)\).

Substituting \(v = xy\), we have: \(\(\frac{{\partial z}}{{\partial y}} = e^{xy} \cdot x\)\).

Therefore, \(\(\frac{{\partial z}}{{\partial y}} = xe^{xy}\)\).

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Options:

(–3, 5) and (–2, 5)         (–3, 5) and (–9, 3)

(5, 3) and (9, 3)             (5, –9) and (3, –5)

(2, 3) and (7, 3)

Answer:

(–3, 5) and (–2, 5)

(5, 3) and (9, 3)

(2, 3) and (7, 3)

Step-by-step explanation:

To do this, have to compare the both x and both y coordinates of the points.

If the x coordinates are equal or the y coordinates are equal, then that option is true

For (a): (-3,5) and (-2,5)

The y coordinates are the same:

i.e.

\(y_1 = y_2 = 5\)

This option is true

For (b): (-3, 5) and (-9, 3)

None of the coordinates are the same;

i.e.

\(x_1 \ne x_2\)

\(y_1 \ne y_2\)

Hence, this option is false.

For (c): (5, 3) and (9, 3)

The y coordinates are the same:

i.e.

\(y_1 = y_2 = 3\)

This option is true

For (d): (5, -9) and (3, -5)

None of the coordinates are the same;

i.e.

\(x_1 \ne x_2\)

\(y_1 \ne y_2\)

Hence, this option is false.

(2, 3) and (7, 3)

The y coordinates are the same:

i.e.

\(y_1 = y_2 = 3\)

This option is true

Answer:

(-3,5) & (-2,5)

(5,3) & (9,3)

(2,3) & (7,3)

Step-by-step explanation:

The hour hand that goes through 3 right angles and starts from 7 will stop at 4.

We can assume that the numbers in a clock are positioned in a circle. The angle in a circle is 360⁰, while the numbers in a clock is 12.

Hence, from each clock number to its consecutive number, the hour hand must travel 30⁰ as shown in the attached picture.

A right angle is equal to 90⁰. This is equal to 3 ⨉ 30⁰. In other words, to travel  90⁰ means to travel 3 hours.

3 right angles =  3 ⨉ 90⁰

                      = 3 ⨉ 3 hours

                      = 9 hours.

Thus, the hour hand will go to:

7 + 9 = 16

16 is equal to number 4 in a clock number.

Conclusion: If the hour hand start from 7, it will stop at clock number 4.

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The value of the given expression  5x²⁵ - 3x³² + 2x - 12 at x = 1 is -8.

The given expression is:

5x²⁵ - 3x³² + 2x - 12

To evaluate the value at x=1.

Substitute x = 1 in the given expression.

= 5(1)²⁵ - 3(1)³² + 2(1) - 12

Simplify:

= 5 - 3 + 2 - 12

= -8

Therefore, the value of the given expression at x = 1 is -8.

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The correct question is-

What is the value of 5x²⁵ - 3x³² + 2x - 12 at x=1?