As an object's depth below the surface of a body of salt water increases, so does the pressure acting on the object due to atmospheric and water conditions. the rate at which pressure increases is approximately 111111 pounds per square inch (\text{psi})(psi)left parenthesis, start text, p, s, i, end text, right parenthesis for every increase in depth of 252525 feet (\text{ft})(ft)left parenthesis, start text, f, t, end text, right parenthesis. the pressure at the surface of the water is 15\ \text{psi}15 psi15, space, start text, p, s, i, end text. rounded to the nearest foot, at what depth will the pressure acting on the object be 50\ \text{psi}50 psi50, space, start text, p, s, i, end text?
Answers
The pressure acting on an object below the surface of a body of salt water increases as the depth below the surface increases. The rate at which the pressure increases is approximately 111,111 pounds per square inch (psi) for every increase in depth of 25,525 feet (ft).
To find the depth at which the pressure acting on the object is 50 psi, we can set up a proportion:
Pressure increase / Depth increase = Pressure at surface / Depth at desired pressure
Using the given values:
111,111 psi / 25,525 ft = 15 psi / Depth at desired pressure
Now we can solve for the Depth at desired pressure:
Depth at desired pressure = (25,525 ft * 15 psi) / 111,111 psi
Simplifying the equation:
Depth at desired pressure = 383,625 ft / 111,111 psi
To round to the nearest foot, we divide the numerator by the denominator and round the result to the nearest whole number:
Depth at desired pressure ≈ 3.45 ft
Therefore, at a depth of approximately 3.45 feet below the surface of the body of salt water, the pressure acting on the object will be 50 psi.
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Related Questions
A newspaper for a large city launches a new advertising campaign focusing on the number of digital subscriptions. The equation S(t)=31,500(1.034)^t approximates the number of digital subscriptions S as a function of t months after the launch of the advertising campaign. Determine the statements that interpret the parameters of the function S(t).
A. The newspaper had 31,500 digital subscriptions when the advertising campaign was launched.
B. The number of digital subscriptions increases by 3.4% each month.
C. The number of digital subscriptions increases by 103.4% each month.
D. The number of digital subscriptions increases by 3.4% each year.
E. The newspaper had 32,571 digital subscriptions when the advertising campaign was launched.
Answers
Answer: D. The number of digital subscriptions increases by 3.4% each year
C. the number of digital subscriptions increases by 103.4% each month.
Find the greatest possible error for each measurement. 1 1/4
Answers
Answer:
12 should be 1 as in 1 foot. 1' 1/4"
Step-by-step explanation:
Solve 5x - 2.5 = 17.5
X =
Answers
X=4…………….
A car travels along the highway to Denver at a steady speed. When it begins, it is 300 miles from Denver. After 3 hours, it is 180 miles from Denver. Which function describes the car's distance from Denver?
Answers
Answer:
A, y = -40x+300
Step-by-step explanation:
y=180
x=3
180=-40(3)+300
180=300-120
what is equivalent to 5 x a
1. 5a
2. a^5
3. a x a x a x a x a
4. 5^a
Answers
The multiplication sign isn’t always used in algebra, you can put the two things being multiplied together
For example 8x or 2xy
Answer:
5a
Step-by-step explanation:
\(5\cdot \:a\\\\\)
5 multiply a
5a
Select the two values of x that are roots of
this equation.
3x - 5 =-2x2
D A. X=-3
0 B. x=-3
. C. x=2
. D. x= 1
Answers
Answer: B is the answer
Step-by-step explanation:
Fill in the missing fraction: Do not reduce your answer. What is 10/12 plus blank equals 16/12
Answers
Answer:
The missing fraction is 6/12
(you can further simplify this but the question requires that you don't do that)
Step-by-step explanation:
To add fractions easily, their denominators should have the same value, so the denominator should be 12,
Then, to get 16 in the numerator, we need to find a number that on adding to 10, gives 16, or,
10 + x = 16
x = 16 - 10
x = 6
So, the numerator should be 6
so we get the fraction, 6/12
We can also solve it in an alternate way,
\(10/12 + x = 16/12\\x = 16/12 - 10/12\\x = (16-10)/12\\x = 6/12\)
Please help me with the correct answers
Answers
Answer:
13 ft
Step-by-step explanation:
we need to find the square root of 169
√169 = 13
What is the 7th term of the geometric sequence below? 7, -14,28, -56, А -448 b b -896 с 448 D 896
Answers
Given the sequence:
7, -14, 28, -56,
To find the 7th term of the geometric sequence, use the formula below:
\(a_n=ar^{(n-1)}\)where,
a is the first term = 7
n is the number of terms = 7
r = common ratio =
\(r\text{ = }\frac{\sec ond\text{ term}}{\text{first term}}\text{ = }\frac{-14}{7}=\text{ -2}\)Thus, we have:
\(\begin{gathered} a_7=\text{ 7(}-2^{(7-1)}) \\ \\ \text{ = 7 }(-2^6) \\ \\ \text{ = }7(-64) \\ \\ \text{ = }-448 \end{gathered}\)The 7th term is -448
ANSWER:
A) -448
Can somebody help me please
Answers
The area of figure is 272.52 square units.
The given figure consist:
A parallelogram of,
length = 12
width = 18
Since we know that,
Area of parallelogram = length x width
= 12 x 18
= 216 square units
And it consist of a semicircle of,
radius = 12/2
= 6
Since we know that,
Area of semicircle is = πr²/2
= 3.14 x 6 x 6/2
= 56.52 square units
Thus,
The area of figure is sum of both areas,
⇒ 216 + 56.52
Hence, area is
⇒ 272.52 square units
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5 - 2 (4а + 1) - За - 13 I need help
Answers
Answer:
-11a - 10
Step-by-step explanation:
simplify in order of terms: -2(4a + 1) - 3a - 13 + 5
simplify: -8a - 2 - 3a - 8
simplify again: -11a - 10
5 -8a -2 - 3a - 13
3 - 11a - 13
-10 - 11a
and if you want to solve for a:
-10 - 11a = 0
-11a = 10
a = -10/11
Mr. Anders and Ms. Rich each drove home form a business meeting. Mr. Anders traveled east at 100 kilometers per hour and Ms. Rich traveled west at 80 kilometers per hour. In how many hours were they 3600 kilometers apart?
Answers
Answer:
180 hours
Step-by-step explanation:
Hope this helps
Complete the steps to solve for X
please say sloving steps
Answers
Answer:
see below
Step-by-step explanation:
2/5x - 1/4x = 3
Get a common denominator of 20
2/5x *4/4 - 1/4x *5/5 =3
8/20 x - 5/20x =3
3/20x = 3
Multiply by 20/3 to isolate x
20/3 * 3/20 x = 20/3 * 3
x = 20
100 1/4 in simplest radical form.
Answers
Answer:
\(\sqrt[4]{100}\)
Step-by-step explanation: Hope this helped
basaltic clasts within a conglomerate have been radiometrically dated to 50 million years ago. is this a reliable age for the conglomerate?
Answers
Yes, the radiometrically dated basaltic clasts within the conglomerate can be considered a reliable age for the conglomerate.
The reliable age of conglomerate basaltic clasts radiometrically dated to 50 million years ago is the Eocene era.
The sedimentary rock called conglomerate has basaltic clasts embedded in it that have been radiometrically dated to 50 million years ago. Therefore, this is a reliable age for the conglomerate because the basaltic clasts would have been derived from the volcanoes that were active at the time, which would have deposited ash and pyroclastic material in the surrounding area. This means that the conglomerate itself must have been formed sometime later after the volcanic activity, during the Eocene era.
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VERY MUCH HELP ME PLEASE!!! (10 pts)
Answers
720-320= 400 for the deck
Look carefully at the completed Punnett Squares A, B, and C. Use these letters to answer the questions below. Answers may be used more than once. Which Punnett Square shows: 2. 25% wrinkled offspring? Fill in the blank text field 1 Enter Text Here 3. 50% wrinkled offspring? Fill in the blank text field 2 Enter Text Here 4. 75% round offspring? Fill in the blank text field 3 Enter Text Here 5. 100% round offspring? Fill in the blank text field 4 Enter Text Here Check Answer Three Punnett squares.
Answers
Answer: A C A B
Step-by-step explanation:
a coffee shop owner sells brazilian coffee for $10 per pound and colombian coffee for $14 per pound. if the store decides to make a 150-pound blend of the two coffee types and sell it for $11 per pound, how much of each type of coffee should be used?
Answers
The coffee shop owner should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian coffee to make the 150-pound blend.
To solve this problem, we can use a system of equations. Let x be the number of pounds of Brazilian coffee and y be the number of pounds of Colombian coffee. We can set up the following equations:
x + y = 150 (the total amount of coffee is 150 pounds)
10x + 14y = 11(150) (the total cost of the coffee is $11 per pound)
Now we can use the first equation to solve for one of the variables. Let's solve for y:
y = 150 - x
Now we can substitute this into the second equation:
10x + 14(150 - x) = 11(150)
Distribute the 14:
10x + 2100 - 14x = 1650
Combine like terms:
-4x = -450
Divide by -4:
x = 112.5
Now we can substitute this back into the first equation to solve for y:
112.5 + y = 150
y = 37.5
So the coffee shop owner should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian coffee to make the 150-pound blend.
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A -10 nC charge is located at (x, y) = (1.2 cm , 0 cm).
What is the x-component of the electric field at the position (x, y) = (−4.1cm, 0 cm)?Express your answer to two significant figures and include the appropriate units.
Answers
We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:
E = k * Q / r^2
where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.
In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).
To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.
So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:
E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)
where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.
Substituting the given values, we get:
E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2
E_x ≈ -30,566.04 N/C
Rounding this to two significant figures and including the appropriate units, we get:
The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).
Which of the following statement is NOT correct about hypothesis testing? If the outcome we observed could have occurred just by chance, then we say the effect is statistically significant. We cannot eliminate both type l error and type Il error at the same time. Null hypothesis and Alternative hypothesis should be mutually exclusive. It is a statement about the value of a population parameter.
Answers
The statement that is NOT correct about hypothesis testing is: "We cannot eliminate both type l error and type II error at the same time."
In hypothesis testing, we aim to make a decision about a population parameter based on sample data. Type I error refers to rejecting a true null hypothesis, while Type II error refers to failing to reject a false null hypothesis. While it is not possible to completely eliminate both types of errors simultaneously, we can minimize the chances of committing either of them by choosing an appropriate significance level and conducting a power analysis.
Therefore, the statement that we cannot eliminate both Type I and Type II errors at the same time is incorrect.
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Statistics when mode is best measure of central tendency.
Answers
Answer:
The mode is the least used of the measures of central tendency
Step-by-step explanation:
BN Rao Suits B N Rao suits is a 146-year old firm that has branches at 3 places in Bangalore - Domlur, Kaly Nagar and Vijay Nagar. They have plans to open another branch at Electronic City. Though B Rao suits specialize in suits, they also have a good collection of formal shirts, trousers and Shirts. Needless to add, their apparels are priced at a premium. But they have been doing go business because of their services and brand reputation. They have been very few qua complaints and even if there were some, the in-house tailors whom they had ensured that problem was rectified in a matter of minutes. Dr. Amarkant Tripathi who works in a top notch IT firm in Bangalore decided to explore B N R suits for the first time. He was scheduled to attend a meeting in Chennai on Friday 15
∗
May 20 and he decided to visit B N Rao suits on 1" May itself. But as it was Labor Day, he visited the sh at Vijay Nagar the next day. The measurements were taken and he was assured that the delive would be given on 13
t
May-two days before his scheduled departure to Chennai. On 13
an
May. Dr Tripathi got the delivery but to his dismay the trouser was fight. To add to woes, the store manager politely informed him that the in-house tailor was scheduled to ret from his native place in the evening and that he can be rest assured that his trousers will delivered to him in the evening. There were 4 tailors in the Vijay Nagar branch but three of the had been diverted to the Domlur branch because of a large order there. As there were not ma orders in the Vijay Nagar branch, the store manager was confident that they could manage witt in-house tailor. Unfortunately, after stitching the suit of Dr Tripathi, the tailor had to rush to native place at Kolar on an emergency. When Dr Tripathi called up B N Rao on 13th, he was asked to come on 14
an
and the sto manager profusely apologized to him for the delay saying that the tailor was delayed. T deadlines for the large order in the Domlur branch were tight. so no tailor could be spared fro that branch, The Kalyan Nagar branch was a recent branch and there was only one tailor the who was busy with the present order. On 14n moming. when Dr Tripathi called up the store manager the alteration was not yet dor Livid about the delay, Dr Tripathi blew his fuse. The store manager listened to him patiently a asked him if Dr Tripathi could share details of his programme. Dr Tripathi was in no mood to obli and said that he would come back from Chennai and then collect his suit the next week. decided to wear one of his older suits for the meeting. Dr Tripathi left for Chennai on 14
th
evening. On 15
th
May, 2-hours before the scheduled meeting the hotel where Dr Tripathi was put up. he received a package. When he opened it, he found trouser neatly packed along with a bunch of handkerchieves and an apology note from the st manager. The trouser fitted him well. But Dr Tripathi was perplexed. How did B N Rao suits co. to know of his plan? He got his answers when he returned to Bangalore on 17
∘
May 2012 . T store manager had called up Dr Tripathi's home. had spoken to his daughter and had explain the problem to her. He had arranged for the suit to be taken to the Domlur branch personally a got it mended. He then arranged for the suit to be delivered by Express Delivery on 14
th
even so that it could reach Chennai the next day. Explain: Service Recovery Paradox in the above context.
Answers
The scenario described above illustrates the Service Recovery Paradox, where a customer's satisfaction can actually increase after experiencing a service failure and receiving effective recovery efforts.
Dr. Amarkant Tripathi faced a delay and inconvenience with his suit order from B N Rao suits, but the store manager went above and beyond to rectify the situation, ultimately leading to Dr. Tripathi's increased satisfaction and loyalty.
The Service Recovery Paradox occurs when a customer's satisfaction and loyalty increase even after encountering a service failure. In the given context, Dr. Tripathi experienced a delay and fitting issue with his suit order. However, the store manager took prompt action to resolve the problem and ensure Dr. Tripathi's satisfaction.
Despite initial setbacks, the store manager exhibited proactive service recovery efforts. He communicated with Dr. Tripathi, apologized sincerely, and made efforts to rectify the situation promptly. The manager's willingness to listen, understand, and address the customer's concerns played a crucial role.
Furthermore, the store manager's personal involvement, contacting Dr. Tripathi's home, explaining the situation to his daughter, and arranging for the suit to be taken to the Domlur branch for repairs and express delivery showcased a high level of customer service and dedication to resolving the issue.
These service recovery efforts exceeded Dr. Tripathi's expectations and demonstrated B N Rao suits' commitment to customer satisfaction. As a result, when Dr. Tripathi received the suit, along with the apology note and additional handkerchiefs, he felt not only satisfied with the resolution but also impressed by the store's efforts to understand his needs and deliver a superior service experience.
The Service Recovery Paradox, in this case, highlights the importance of effective service recovery in building customer loyalty and turning a potentially negative experience into a positive one. B N Rao suits' commitment to resolving the issue and going the extra mile to deliver a satisfactory outcome ultimately strengthened the customer's trust and loyalty in the brand.
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A sequence is defined recursively using the equation . If f(1)=100, what is f(6)?
52
60
68
92
Answers
Step-by-step explanation:
A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100, what is f(6) ?
Since, A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100,we have to find the value of f(6).
Consider
f(n+1) = f(n)-8
Let n =1, we get
f(1+1) = f(2) = f(1) - 8 = 100-8 = 92
Let n =2, we get
f(2+1) = f(3) = f(2) - 8 = 92-8 = 84
Let n =3, we get
f(3+1) = f(4) = f(3)-8 = 84 - 8 = 76
Let n =4, we get
f(4+1) = f(5) = f(4)-8 = 76 - 8 = 68
Let n =5, we get
f(5+1) = f(6) = f(5) - 8 = 68-8 = 60
Therefore, the value of f(6) is 60.
Answer: C, 60
Step-by-step explanation: Just took the quiz :)
Suppose y, ... Yn ~ N(u,02), with y known. Use the non-informative prior p(02) « 1/02. Obtain the sampling distribution (likelihood) and the posterior distribution.
Answers
To obtain the sampling distribution (likelihood) and the posterior distribution for this scenario, we can use Bayesian inference.
The sampling distribution (likelihood) can be represented as:
p(y|u,02) = (1/sqrt(2*pi*02)^n) * exp(-(1/(2*02)) * sum((yi-u)^2))
where y is the observed data, u is the mean of the normal distribution, and 02 is the variance of the normal distribution.
The non-informative prior for 02 can be represented as:
p(02) « 1/02
Using Bayes' theorem, we can obtain the posterior distribution:
p(u,02|y) = p(y|u,02) * p(02) / p(y)
where p(y) is the marginal likelihood. To simplify the calculation, we can integrate out u from the joint distribution:
p(02|y) = (p(y|02) * p(02)) / p(y)
where p(y|02) is the marginal likelihood for 02:
p(y|02) = (1/sqrt(2*pi*02)^n) * exp(-(n-1)/2)
We can then obtain the posterior distribution for 02:
p(02|y) « 1/02 * exp(-(n-1)/2)
This is a gamma distribution with shape parameter (n-1)/2 and scale parameter 1/2. Therefore, the posterior distribution for 02 is:
02|y ~ Gamma((n-1)/2, 1/2)
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solve: 2x+3y=12 6x-y=4
Answers
Answer:
this is what I got. I'm not sure if it's right
PLEASE ANSWERS FAST
how do you find the perimeter of the base?
A. Multiply the side lengths
B. Divide the side lengths
C. Add all sides of the base shape
D. Take the square root after multiplying the side lengths
Answers
Answer:
C. Add all sides of the base shape
Step-by-step explanation:
perimeter = sum of length of sides of a polygon
Answer: C. Add all sides of the base shape
The formula a = m – n represents the actual cost, a, of an item with original price m after a coupon for n dollars off is applied. Solve the formula for the amount of the coupon n. A. n = a + m B. n = m – a C. n = a – m D. n = – m – a
Answers
Answer:
n = m - a
Step-by-step explanation:
Given that:
The expression of the formula a = m - n
where;
a = actual cost of an item
m = original price
n = amount of coupon in dollars
The objective is to solve for the amount of the coupon.
In order to determine the amount of the coupon, we need to make n which is the amount of coupons in dollars the subject of the formula from the given expression.
So if a = m - n
a + n = m
n = m - a
Scores on an endurance test for cardiac patients are normally distributed with mean of 185 and standard deviation of 30 . a. What is the probability a patient will score above 192? (10 points) b. What score does a patient at the 80th percentile receive? (10 points)
Answers
The probability of a patient scoring above 192 on the endurance test is approximately 40.90%. A patient at the 80th percentile receives a score of approximately 208.2.
a. To find the probability that a patient will score above 192, we need to use the Z-score formula. The Z-score measures the number of standard deviations a data point is from the mean. In this case, the formula is Z = (X - μ) / σ, where X is the score, μ is the mean, and σ is the standard deviation.
First, calculate the Z-score: Z = (192 - 185) / 30 = 7/30 ≈ 0.23.
Next, we need to find the probability of scoring above this Z-score. Using a Z-table or a calculator, we find that the probability is approximately 0.4090, or 40.90%.
b. To find the score that corresponds to the 80th percentile, we need to find the Z-score that has an area of 0.80 to the left. Using the Z-table or a calculator, we find that the Z-score is approximately 0.84.
Now, we can use the Z-score formula to find the corresponding score: X = Z * σ + μ. Plugging in the values, we get X = 0.84 * 30 + 185 = 208.2.
Therefore, a patient at the 80th percentile receives a score of approximately 208.2.
a. To find the probability of a patient scoring above 192 on the endurance test, we first calculate the Z-score. This allows us to standardize the score by measuring how many standard deviations it is from the mean. We then use a Z-table or calculator to find the probability corresponding to this Z-score, which is approximately 0.4090 or 40.90%.
b. To find the score at the 80th percentile, we first need to find the Z-score that corresponds to an area of 0.80 to the left. Using a Z-table or calculator, we find this Z-score to be approximately 0.84. We then use the Z-score formula to find the corresponding score, which is approximately 208.2.
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A single die is rolled twice. Find the probability of rolling an odd number the first time and a number greater than 3 the second time. THE Find the probability of rolling an odd number the first time and a number greater than 3 the second time. (Type an integer or a simplified fraction.)
Answers
The probability of rolling an odd number the first time and a number greater than 3 the second time is 1/4
Calculating the probabilityThe probability of rolling an odd number on a single die is 3/6 or 1/2, since there are three odd numbers (1, 3, and 5) out of six possible outcomes.
The probability of rolling a number greater than 3 on a single die is 3/6 or 1/2, since there are three numbers greater than 3 (4, 5, and 6) out of six possible outcomes.
To find the probability of both events happening together (rolling an odd number first and a number greater than 3 second), we need to multiply their individual probabilities:
P(odd number first and number > 3 second) = P(odd number first) * P(number > 3 second)
P(odd number first and number > 3 second) = (1/2) * (1/2) = 1/4
Therefore, the probability is 1/4.
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Harry and Olivia are planning to buy a bedroom furniture set that costs $4,100 plus 6% taxes. They would like to apply for a 0% APR store credit card on purchases for 10 months. How much money do they need to pay in equal installments monthly for the next 10 months such that they will be able to pay off the bedroom furniture set before the 0% APR offer expires?
Answers
Answer:
434.60
Step-by-step explanation: