a car travel 30 miles for 30 minutes. the car then stops at a service station for 10 minutes. the car continues for another 20 minutes at a constant speed of 45 mph. draw the distance-time graph for the car.

Answer:

283.15

Explanation:

looked it up

there's a handy calculator

Answer: C.

283 K

Explanation: edmentum

Answer:

2.4 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'.................... Equation 1

Where m = mass of the moving puck, m' = mass of the stationary puck, u = initial velocity of the moving puck, u' = initial velocity of the stationary puck, v = final velocity of the moving puck, v' = final velocity of the stationary puck.

make v' the subject of the equation

v' = (mu+m'u'-mv)/m'................ Equation 2

From the question,

Given; m = 3 kg, m' = 2 kg, u = 2 m/s, u' = 0 m/s (stationary), v = 0.4 m/s

Substitute these values into equation 2

v' = [(3×2)+(2×0)-(3×0.4)]/2

v' = (6-1.2)/2

v' = 4.8/2

v' = 2.4 m/s

The driver will not collide with deer, given that the reaction time is 0.50 seconds.

To determine if the driver will collide with deer or not, we shall determine the distance travelled by the car during the given time. Details below

s = ut + 1/2at²

s = (28 × 0.50) + (1/2 × 6 × 0.50²)

s = 14 + (3 × 0.25)

s = 14 + 0.75

s = 14.75 m

From the calculation made above, we can see that the distance travelled by the driver during the given time is 14.75 m.

Thus, we can conclude that the driver will not collide with the deer since the raection time only move the driver 14.75 m and the deer is 80 m away.

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The period and frequency of the pendulum are equal to 2 sec and 0.5 Hz.

A simple pendulum can be defined as a mechanical arrangement that possesses periodic motion. The simple pendulum is made of a bob having mass suspended by a thin string hung at its upper end of the length.

The simple pendulum moves freely back and forth in an oscillatory motion and the motion of the pendulum occurs in a vertical plane which is operated by the gravitational force.

The relationship between the time period and length of the pendulum is given by:

T = 2π√(L/g)

Where 'g' is the acceleration due to gravity  and  'L' is the length of the pendulum.

T = 1/f     where is the frequency of the pendulum.

Given, the length of a pendulum,  L = 1 m

Then the period of the pendulum can be calculated as:

\(T = 2\times 3.14 \sqrt{\frac{1}{9.8} }\)

T = 2 s

The frequency of the pendulum, f = 1/T = 1/2 = 0.5 Hz

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\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)

\(\\ \bull\tt\dashrightarrow 534\times 10^1\)

\(\\ \bull\tt\dashrightarrow 534\times 10\)

\(\\ \bull\tt\dashrightarrow 5340\)

Answer:

  D.  The current is the same across all resistors in the circuit.

Explanation:

In a series circuit, all circuit elements are connected so that there is exactly one current path. That path goes through each of the elements of the circuit.

The current is the same through all resistors in a series circuit.

Answer:

the radius of curvature of the track for this instant is 266 m

Explanation:

Given that;

The Initial Velocity u = 100 km/h = 100 × \(\frac{5}{18}\) = 27.77 m/s

velocity of the train at t=12 s is;

\(V_{t=12}\) = 50 km/h = 50 × \(\frac{5}{18}\) = 13.89 m/s

now, we calculate the deceleration of the train

\(V_{t=12}\)  = u + at

13.89 = 27.77 + \(a_{t}\)12

\(a_{t}\) = (13.89 - 27.77) / 12

\(a_{t}\) = -13.88 / 12

\(a_{t}\) = - 1.1566 m/s²

Now, the velocity of the train at 6 seconds is;

\(V_{t=6}\)  = u + at

\(V_{t=6}\)  = 27.77 + ( - 1.1566 m/s²)6

\(V_{t=6}\)  = 27.77 - 6.9396

\(V_{t=6}\)  = 20.83 m/s

The acceleration at t=6 s is;

a = √[ (\(a_{t}\) )² + (\(a_{n}\))²]

a = √[ (\(a_{t}\) )² + (\(a_{n}\))²]

we substitute

2m/s² = √[ (- 1.15 )² + (\(a_{n}\))²]

4 = (- 1.1566 )² + (\(a_{n}\))²

4 = 1.3377 +  (\(a_{n}\))²

(\(a_{n}\))² = 4 - 1.3377

(\(a_{n}\))² = 2.6623

\(a_{n}\) = √2.6623

\(a_{n}\)  = 1.6316 m/s²

Now the radius of curve is;

a = V² / p

\(p_{t=6}\) = ( \(V_{t=6}\) )² /  \(a_{n}\)

\(p_{t=6}\) = ( 20.83 m/s )² /  1.6316 m/s²

\(p_{t=6}\) = 433.8889 / 1.6316

\(p_{t=6}\) = 265.9 m ≈ 266 m

Therefore;  the radius of curvature of the track for this instant is 266 m

Answer:

record is information created, received and maintained as evidence and information by an organization or person.in simpler terms it's a collection of of fields probably of different data types.

sound is however something loud or soft.which can be defined as vibrations that travel through the air or another medium.

I hope this helps

Answer:

8m/s^2

Explanation:

hope it helps........

Explanation:

you're supposed to know the formula of acceleration which is velocity of a time then you can solve the question

A type of research which would be most appropriate for a research looking to see how drinking coffee impacts college students' grade point averages (GPAs) is a survey.

In Science, a research method can be defined as the scientific methods or techniques that are adopted by a researcher for the collection and analysis of data.

Generally speaking, there are different types of research method that are used for the collection of data and these include the following:

In Science, a survey simply refers to a type of research method that uses various data collection methods such as questionnaires and interviews, which favors it in revealing correlations between two data variables such as the relationship between coffee and college students' grade point averages (GPAs).

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Answer:

8760 N

Explanation:

think this is the right answer :)

Explanation:

The mechanical energy can be expressed as kinetic and potential energy, given by the equation;

ME=KE+PE

but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0

ME=KE

The equation of KE=0.5mv²

ME=0.5mv²

32 000=0.5(1600)v²

\(v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} \)

\(v {}^{2} = \frac{32 \: 000}{800} \)

\( {v}^{2} = 40\)

\(v = \sqrt{40} = 6.324\)

v=6.324 m/s :)

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

\(a=2.14\ m/s^2\)

Explanation:

Force in upward direction = 45 N

Force in right side = 60 N

Mass of the object, m = 35 kg

Net force on the object is given by :

\(F=\sqrt{45^2+60^2} \\F=75\ N\)

We know that,

F = ma

Where

a is acceleration of the object

\(a=\dfrac{F}{m}\\\\a=\dfrac{75\ N}{35\ kg}\\\\a=2.14\ m/s^2\)

So, the acceleration of the object is \(2.14\ m/s^2\).

Pressure in pa = (total force) x (area)

10⁸ pa = (1000 N) x (area)

Divide each side of the equation by 1000N.

10⁸ pa/1000N = area

area = 10⁵ square meters

ANSWER:

b) and f)

STEP-BY-STEP EXPLANATION:

To determine the answer we analyze option by option as follows:

a) Because the speed is constant, the acceleration is zero:

Acceleration happens when there is a change in velocity. Since the direction of the velocity vector is changing, there is an acceleration, an inward acceleration.

Therefore this is false.

b) If the net force acting upon the object is suddenly reduced to zero, then the object would suddenly depart from its circular path and travel tangent to the circle.

We have that if the net force is 0 N, then the moving object will maintain its state of motion and at the instant, the net force becomes 0 N, the object is moving tangent to the circle.

So this option is true

c) The object experiences a force which has a component directed parallel to the direction of motion.

We have that if the movement is circular at a constant speed, the net force is perpendicular to the direction of movement and this means that there is no component parallel or antiparallel to the direction of movement.

Therefore, this option is false.

d) Inertia causes objects to move in a circle.

The centripetal force that causes circular motion.

So this option is false

e) The acceleration and the net force vector are directed perpendicular to each other.

Acceleration and net force are always directed in the same direction. But in this case, they are directed inwards; this happens to be perpendicular to the tangential velocity vector.

So this option is false

f) There can be a force pushing outwards on the object as long as the net force in inwards.

An object moving in a circle must have a net internal force. And it may be the case where individual external forces are overcome by an individual internal force.

That is to say that this option is true

g) The acceleration of the object is directed tangent to the circle. We have that the acceleration is directed inwards; only the velocity is directed tangent to the circle.

So this option is false.

This means that the only true options are b) and f)

Answer:

i cant see it

Explanation:

sorry maybe try to show us a different way?

Answer:

Below

Explanation:

K.E. = 1/2 * m * v^2

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

im sorry i would help but thats too much

Answer:

Explanation:

A leaf appears green becuase of photosyithesis

Milk appears white because all the corols are being aborseb

words on the page are black because all colors are being refcted.

The spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

The angular speed of the ball is calculated as follows;

ω = 2π/T

ω = (2π) / (0.13)

ω = 48.33 rad/s

The spring constant is calculated as follows;

ω = √(k/m)

ω² = k/m

ω²m = k

(48.33² x 0.232) = k

542 N/m

v = ωL

v = 48.33 x 0.56 m

v = 27.1 m/s

h = v²/2g

h = (27.1²) / (2 x 9.8)

h = 37.5 m

Thus, the spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

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The initial temperature of the forging is approximately 1,090.42°C.

To determine the initial temperature of the forging, we can use the principle of conservation of energy. The heat lost by the forging is equal to the heat gained by the oil during the quenching process.

The heat lost by the forging can be calculated using the formula:

Q_lost = m_forging * c_forging * (T_forging_initial - T_equilibrium)

where:

- Q_lost is the heat lost by the forging

- m_forging is the mass of the forging (90.8 kg)

- c_forging is the specific heat capacity of the forging (434 J/(kg C°))

- T_forging_initial is the initial temperature of the forging (unknown)

- T_equilibrium is the final temperature of the oil and forging at thermal equilibrium (58.9°C)

The heat gained by the oil can be calculated using the formula:

Q_gained = m_oil * c_oil * (T_equilibrium - T_oil_initial)

where:

- Q_gained is the heat gained by the oil

- m_oil is the mass of the oil (689 kg)

- c_oil is the specific heat capacity of the oil (2680 J/(kg C°))

- T_oil_initial is the initial temperature of the oil (38.3°C)

Since the heat lost by the forging is equal to the heat gained by the oil, we can set up the following equation:

m_forging * c_forging * (T_forging_initial - T_equilibrium) = m_oil * c_oil * (T_equilibrium - T_oil_initial)

Plugging in the given values, we can solve for T_forging_initial:

90.8 kg * 434 J/(kg C°) * (T_forging_initial - 58.9°C) = 689 kg * 2680 J/(kg C°) * (58.9°C - 38.3°C)

Simplifying the equation:

90.8 * 434 * (T_forging_initial - 58.9) = 689 * 2680 * (58.9 - 38.3)

Solving for T_forging_initial:

T_forging_initial - 58.9 = (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)

T_forging_initial = 58.9 + (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)

Calculating the value:

T_forging_initial ≈ 1,090.42°C

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Answer:

William Gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

Answer:

william gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 5

We have the final answer as

Hope this helps you