A 1.50 g sample of hydrocarbon (containing C & H only) undergoes complete combustion to produce 4.40 g of CO2 and 2.70 g of H2O. Calculate the empirical formula of the compound.

Answer:

a. is the correct answer

Explanation:

The response is 320000 as a result. Volume is a physical term that describes how much space an object or substance takes up.

By multiplying the box's length, breadth, and height, one can get the capacity of the container: Volume is equal to 125 cm, 37 cm, and 68 cm, or 320,500 cm3. The result of rounding to the proper significant digits is: 320,000 cm3 is the volume. The response is 320000 as a result. Liters, cubic metres, and cubic centimetres are frequently used as units of measurement. In several disciplines, including physics, chemistry, and engineering, the idea of volume is crucial. For example, in physics, volume is a crucial metric when examining the behaviour of gases and liquids under various conditions. In chemistry, the volume of a material can be used to calculate its concentration in a solution. Volume is a concept that is used frequently in daily life, such as when measuring components for meals or figuring out how much something can hold.

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Answer:

55.56 amu

Explanation:

Let A, B, C and D represent the four isotopes of iron.

The following data were obtained from the question:

Isotope A (Fe-54):

Mass of A = 53.940 amu

Abundance (A%) = 5.82%

Isotope B (Fe-56):

Mass of B = 55.935 amu

Abundance (B%) = 91.66%

Isotope C (Fe-57):

Mass of C = 56.935 amu

Abundance (C%) = 2.19%

Isotope D (Fe-58):

Mass of D = 57.933 amu

Abundance (D%) = 0.33%

Average atomic mass =.?

The average atomic mass of the iron can obtained as follow:

Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100] + [(mass of D × D%)/100]

Average atomic mass = [(53.940 × 5.82)/100] + [(55.935 × 91.66 )/100] + [(56.935 × 2.19)/100] + [(57.933 × 0.33)/100]

= 2.848 + 51.270 + 1.247 + 0.191

= 55.56 amu

Therefore, the average atomic mass of the iron is 55.56 amu

The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.

This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).

In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).

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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.

We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.

In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.

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Answer:

B

Explanation:

Write the dissociation reaction of solid CoS:
\(\displaystyle \text{CoS}_\text{(s)} \rightleftharpoons \text{Co}_\text{(aq)}^{2+} + \text{S}_\text{(aq)}^{2-}\)

The Ksp expression is hence:
\(\displaystyle K_{sp} = [\text{Co}^{2+}][\text{S}^{2-}]\)

If the molar solubility of CoS is 5.0 × 10⁻²² mol L⁻¹ (M), then 5.0 × 10⁻²² M of Co²⁺ and S²⁻ also forms. Hence, the value of Ksp is:
\(\displaystyle \begin{aligned} K_{sp} & = [\text{Co}^{2+}][\text{S}^{2-}] \\ \\ & = (5.0\times 10^{-22})^2 \\ \\ & = 2.5\times 10^{-43}\end{aligned}\)

In conclusion, the answer is B.

The two which she should use to check whether the sublimation of camphor would reduce if pepper seeds are placed along with it are P and S and is denoted as option C.

This is referred to as the transition of a substance directly from the solid to the gas state, without passing through the liquid state and an example is iodine crystal.

Options P and S are both open boxes and one contains only camphor while the other contains camphor and pepper seeds which is used to compare their rate of sublimation to know if the addition of the seeds caused a reduction.

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Answer:

7351.179999999 this may help u more.

The  equation for the base dissociation constant, Kp, of NH3 is given as; Kp = [ NH4^+] [OH-]/[NH3]

The term base dissociation constant refers to the number that shows the extent to which a base dissociates in water. A high value of the dissociation constant implies that the base is completely dissociated in water.

Having said that, we can see that the equation for the base dissociation of NH3 is obtained as; NH3(aq) ⇄ NH4^+(aq) + OH-(aq). We also know that water is in large extent hence it does not come into the dissociation equation.

Thus the  equation for the base dissociation constant, Kp, of NH3 is given as; Kp = [ NH4^+] [OH-]/[NH3]

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To determine the number of moles in each substance, we need to divide the mass of the substance by its molar mass.

67.42 g Si:

The molar mass of Si is 28.0855 g/mol (rounded to 4 decimal places). Therefore, the number of moles of Si is:

67.42 g / 28.0855 g/mol = 2.3992 mol (rounded to 4 decimal places).

11.82 g gold:

The molar mass of gold is 196.9665 g/mol (rounded to 4 decimal places). Therefore, the number of moles of gold is:

11.82 g / 196.9665 g/mol = 0.060 mol (rounded to 3 decimal places).

28.8 g Br₂:

The molar mass of Br₂ is 159.808 g/mol (rounded to 3 decimal places). Therefore, the number of moles of Br₂ is:

28.8 g / 159.808 g/mol = 0.1803 mol (rounded to 4 decimal places).

Therefore, the number of moles in each substance is:

2.3992 mol Si

0.060 mol gold

0.1803 mol Br₂.

Answer:

WILL GIVE BRAINLYEST!!! impressions of leaves can be classified as what A. animals B. plants. C. both animals and plants D. neither plants nor animals

Explanation:

The most complete list of the parts of the experiment presented in this scenario include:

This refers to the procedures which are performed in other to support or refute a hypothesis. It is also used to ascertain the authenticity of the claim by other people such as scientists etc who review it.

In the scenario given, we were told that the group of identical mice is given the supplement and the other group is not given any thing which means that the control group is the one which wasn't given anything while the ones who were given something is the experimental group.

The dependent variable is the supplement which was given to the mice and is therefore the reason why option B was chosen as the correct choice.

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Answer:

Ca3(PO4)2

Explanation:

Ca3(PO4)2 or calcium phosphate is insoluble in water.

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

(B. Plants and meat)

Explanation:

To identify the limiting reactant, excess reactant, and theoretical yield, we first need to determine the amount of each reactant in moles.

Using the molar masses of Ca and P:

Number of moles of Ca = 17.0 g / 40.08 g/mol = 0.424 mol

Number of moles of P = 18.0 g / 30.97 g/mol = 0.581 mol

Next, we need to determine the stoichiometric ratio of the reactants. From the balanced chemical equation, we see that the ratio of Ca to P is 3:2.

3 Ca + 2 P → Ca3P2

To use the stoichiometric ratio to determine the limiting reactant, we need to compare the actual ratio of the reactants to the stoichiometric ratio.

Actual ratio of Ca to P = (0.424 mol Ca) / (0.581 mol P) ≈ 0.73

Stoichiometric ratio of Ca to P = 3/2 = 1.5

Since the actual ratio is greater than the stoichiometric ratio, Ca is the excess reactant and P is the limiting reactant.

To find the theoretical yield of Ca3P2, we need to use the stoichiometric ratio to determine how many moles of Ca3P2 can be produced from the limiting reactant (P).

From the balanced chemical equation, we see that 2 moles of P react with 3 moles of Ca to produce 1 mole of Ca3P2.

So, the number of moles of Ca3P2 that can be produced from 0.581 mol of P is:

(0.581 mol P) × (1 mol Ca3P2 / 2 mol P) = 0.2905 mol Ca3P2

Therefore, the theoretical yield of Ca3P2 is 0.2905 mol.

We have a gas that we will assume behaves like an ideal gas. So we can apply the ideal gas law. The ideal gas law tells us:

Where,

P is the pressure of the gas

V is the volume of the gas

n is the moles of the gas

R is a constant

T is the temperature of the gas

We have two states of the gas. One initial and one final, for both states it is assumed that the moles remain constant. The conditions for each state are.

Initial state:

V1=2.3mL

P1=5.3atm

T1=45°C =318.15K

Final state:

V2=1.2L

P2=2.5atm

T2=?

For each state the ideal gas law will be:

Now, as the moles remain constant, the term nR will be constant and we can equate the two equations, we will then have that:

Now, we clear T2 and replace the known data:

The temperature of the gas will be 78.3K

Answer:

\(d=2600m\)

Explanation:

Hello,

In this case, since the velocity is computed via the distance divided by the elapsed time:

\(v=\frac{d}{t}\)

We can easily compute the how far it will travel as shown below:

\(d=v*t=1m/s*2600s\\\\d=2600m\)

Best regards.

Answer:

The answer is B(scale)

Explanation:

Since the question asked about a range, the scale would be the most logical answer since scales are used to measure.

Answer:

the answer is C.

Explanation:

The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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The chemical formula for copper(II) sulfate is CuSO4.

Copper(II) sulfate is a chemical compound that is made up of copper, sulfur, and oxygen. It has the chemical formula CuSO4 and is commonly referred to as "blue vitriol" or "bluestone." Copper(II) sulfate can be prepared by reacting copper oxide or copper metal with sulfuric acid. It is a blue-colored crystalline solid that dissolves easily in water.

Copper(II) sulfate has many uses in industry and can be used as a fungicide, herbicide, pesticide, and in the manufacture of other chemicals. It is also commonly used in schools and laboratories as a reagent in chemical reactions and experiments.

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Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition  for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

Answer:

The term “flat bone” is somewhat of a misnomer because, although a flat bone is typically thin, it is also often curved. Examples include the cranial (skull) bones, the scapulae (shoulder blades), the sternum (breastbone), and the ribs. Flat bones serve as points of attachment for muscles and often protect internal organs.

HOPE THIS HELPS!!! :D

Answer:

its b

Explanation:

Answer:

which property is least helpful in identifying a sample of matter is (B) VOLUME

Explanation:

volume depend on the amount of substance present and are not useful in the identification of a sample of matter. volume is an extensive property so it is not useful identifying the sample of matter.

The equilibrium constant, Kc, for the response is 0. This approach that at equilibrium, the attention of merchandise is correctly 0 in comparison to the attention of reactants.

The equilibrium constant, Kc, may be calculated the use of the concentrations of the reactants and merchandise at equilibrium, consistent with the regulation of mass action. The balanced chemical equation for the response is:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

At equilibrium, the attention of CO2 is given as 0.seventy three M. The preliminary attention of CO is 2.00 M, and the preliminary attention of H2O is likewise 2.00 M. Let x be the alternate in attention of CO and H2O, and y be the alternate in attention of CO2 and H2, then the equilibrium concentrations may be expressed as:

[CO] = 2.00 M - x

[H2O] = 2.00 M - x

[CO2] = 0.seventy three M + y

[H2] = y

The equilibrium expression for the response is:

Kc = ([CO2][H2])/([CO][H2O])

Substituting the equilibrium concentrations into the expression gives:

Kc = ([0.73 + y][y])/([(2.00 - x)][(2.00 - x)])

Assuming that x and y are small in comparison to the preliminary concentrations, we will approximate the equilibrium concentrations as:

[CO] ≈ 2.00 M

[H2O] ≈ 2.00 M

[CO2] ≈ 0.seventy three M

[H2] ≈ 0.00 M

Substituting those values into the equilibrium expression gives:

Kc = (0.730)/(2.002.00) = 0

This suggests that the response does now no longer continue to a enormous quantity withinside the ahead route and is in all likelihood to be an instance of a reversible response with a low equilibrium constant.

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Answer:

The experimental value in the ideal gas lab is the value obtained through actual measurement and observation of the properties of gases under specific conditions.

Two ways in which scientists can exhibit ethical behavior are

Science can simply be defined as an intellectual and proven practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

So therefore, two ways in which scientists can exhibit ethical behavior are

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Answer:

The number of energy levels increases as you move down a group as the number of electrons increases. Each subsequent energy level is further from the nucleus than the last. Therefore, the atomic radius increases as the group and energy levels increase.

Explanation:

Dose this help? Tell me if it dose.

Answer:

The modern periodic table has a lot to say about the chemical elements, besides the atomic number, atomic weight, and symbol of the identified elements. For example, chemical elements falling in the same group share common properties, which are different from other groups. Also, go through the periodic table trends and you will come to know a regular pattern in the alteration of physical and chemical properties of elements, as you go from left to right, from top to down direction, and vice versa.

Explanation:

I hope this gives an idea to your question - Good luck ^w

Answer:

12 valence electrons

Explanation:

Number of valence electrons: 2 carbons (2 x 4 valence electrons= 8e-) and 4 hydrogens (4 x 1 valence electron = 4 e-) added up gives us 12 valence electrons to work with: Counting the bonds we have made shows that we have used up 10 of the 12 valence electrons leaving us with 2 to complete the octets.

Answer: 44.8 L

Explanation:

To find the volume, we would need to use the ideal gas law.

Ideal Gas Law: PV=nRT

We take the given information and plug it into the equation, but first, we have to manipulate the equation so that we are finding volume.

\(V=\frac{nRT}{P}\)

P= 1.00 atm (STP)

T= 273.15 K (STP)

R= 0.08206 Latm/Kmol

n= \(64g*\frac{1mol}{31.998 g O_{2} }=2 mol\)

\(V=\frac{(2 mol)(0.08206Latm/Kmol)(273.15 K)}{1.00atm} =44.8 L\)