5. if 16,000 units are produced, what is the average fixed manufacturing cost per unit produced?

The value of x will be 0 and x = 5. The correct option is A.

The x-intercept is the point at which a line intersects the x-axis, and the y-intercept is the point at which the line intersects the y-axis.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the x-intercept(s) of the function is the quantity of 5x² - 25x.

The value of the x-intercept will be calculated as,

5x² - 25x = 0

5x( x -25) = 0

5x = 0 and x - 5 = 0

x = 0  and x = 5

Therefore, the value of x will be 0 and x = 5. The correct option is A.

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Answer:

it's x = 5

Step-by-step explanation:

got it right on the test.

Answer:

y + 3 = 1/4(x -4)

Step-by-step explanation:

y - y = m (x - x)

y - -3 = 1/4 ( -4)

y + 3 = 1/4 ( x -4)

Step-by-step explanation:

x<-5 is the answer

1.

6x=-30

2.

x=-5

3.

x<-5

Answer:

A = 18 km^2

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

<2 and <6 are equal because of the corresponding angles thm so:

4x + 44 = 6x + 36

4x - 6x = 36 - 44

-2x = -8

x = 4

Q(√2, ∛2, ⁴√2, ...) is an algebraic extension of Q but not a finite extension of Q since every element in this extension is algebraic over Q.

To prove that the extension Q(√2, ∛2, ⁴√2, ...) is an algebraic extension of Q, we need to show that every element in this extension is algebraic over Q.

Let's consider an arbitrary element in the extension, say √2. We know that √2 is algebraic over Q because it is a root of the polynomial x² - 2 = 0. Similarly, for ∛2, it is a root of the polynomial x³ - 2 = 0. The same logic applies to ⁴√2 and other elements in the extension. Each of these elements is algebraic over Q because they satisfy polynomial equations with coefficients in Q.

Therefore, Q(√2, ∛2, ⁴√2, ...) is an algebraic extension of Q.

To prove that it is not a finite extension of Q, we need to show that there is an infinite number of elements in the extension. We can observe that for every positive integer n, there exists an element in the extension that is the nth root of 2. For example, √2 is the square root (n = 2), ∛2 is the cube root (n = 3), ⁴√2 is the fourth root (n = 4), and so on. Since there are infinitely many positive integers, there are infinitely many elements in the extension. Hence, Q(√2, ∛2, ⁴√2, ...) is not a finite extension of Q.

Therefore, we have proven that Q(√2, ∛2, ⁴√2, ...) is an algebraic extension of Q but not a finite extension of Q.

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Answer:

500000

Step-by-step explanation:

We need to find the value of the given expression :

\(5^{\dfrac{5}{2}}\times 20^{\dfrac{3}{2}}\div 10^{-2}\)

We can do it as per BODMAS rule.

\(5^{\dfrac{5}{2}}\times (\dfrac{20^{\dfrac{3}{2}}}{10^{-2}})\\\\=5^{\dfrac{5}{2}}\times {20^{\dfrac{3}{2}}}\times {10^{2}}\\\\=5^{\dfrac{5}{2}}\times {20^{\dfrac{3}{2}}}\times 100\\\\=5^{\dfrac{5}{2}}\times {(5\times 4)^{\dfrac{3}{2}}}\times 100\\\\=5^{\dfrac{5}{2}}\times {(5^{\dfrac{3}{2}})\times (4)^{\dfrac{3}{2}}}\times 100\\\\=5^{(\dfrac{5}{2}+\dfrac{3}{2})}\times 2^2^{\dfrac{3}{2}}\times 100\\\\=5^4\times 2^3\times 100\\\\=625\times 8\times 100\\\\=500000\)

So, the required answer is 500000.

the table shown is a relation between the side lengths of a regular octagon and its perimeter

so, the easiest way to find the ratio is.

Step 1

divide the perimeter by the length of the side

so, the factor is 8, it means that you need take the length and multiply by 8 to obtain the perimeter

Step 2

find the misssing values

so, the numbers in the table must be 72 and 96.

Answer:

16

Step-by-step explanation:

8 divided by 1/2 is 16 sites

Hope this helped!

In a right angled triangle, the angles are given by the fοrmula:

Angle A + Angle B + Angle C = 180°Therefοre, x° = 131°.

Angle is a geοmetrical figure fοrmed by twο rays with a cοmmοn endpοint. It is measured in degrees οr radians and is used tο describe the amοunt οf turn between twο lines. It can alsο be used tο measure the size οf an angle in a triangle, the amοunt οf rοtatiοn οf a 3D οbject, and mοre. Angles are impοrtant in bοth mathematics and science as they're used tο calculate the amοunt οf fοrce needed tο mοve an οbject οr the amοunt οf energy needed tο keep an οbject in mοtiοn.

In a right angled triangle, the angles are given by the fοrmula:

Angle A + Angle B + Angle C = 180°

Given that FHG = 49°, we can calculate the οther angles:

Angle A = 180° - 49° = 131°

Angle B = 180° - 131° - 49° = 0°

Angle C = 180° - 131° - 0° = 49°

Therefοre, x° = 131°.

In mοdel twο, the kinase is represented by a diamοnd shape.

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Answer:

20

Step-by-step explanation:

Thing to Remember :

Length of tangents from same external point is the same.

Solving :

If the target behavior is recorded whenever it occurs at any point within the scoring interval, the measurement procedure used is called continuous recording or event recording. This method involves observing and recording each instance of the behavior without considering its duration or intensity.

Continuous recording is typically used when the target behavior is discrete and occurs relatively infrequently or has a short duration. With this measurement procedure, each occurrence of the behavior is recorded as a separate event, regardless of when it starts or ends within the scoring interval. Examples of behaviors that can be measured using continuous recording include vocalizations, hand clapping, or instances of aggression.

Continuous recording provides a comprehensive account of the frequency or rate at which the behavior occurs, allowing for a detailed analysis of its occurrence patterns. This method is particularly useful when a precise count of behavior instances is needed and when the duration or intensity of the behavior is not a focus of measurement.

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The relationship between point Z and the triangle is that Z is called the incenter of the triangle.

The theorem associated with the incenter is called the Incenter Theorem.

We have,

The center inside a triangle is called the incenter.

The theorem associated with the incenter is called the Incenter Theorem.

The Incenter Theorem states that the incenter of a triangle is equidistant from the three sides of the triangle.

This means that the incenter is the center of the circle that can be inscribed inside the triangle, known as the incircle.

Thus,

The relationship between point Z and the triangle is that Z is called the incenter of the triangle.

The theorem associated with the incenter is called the Incenter Theorem.

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Answer:

what is this? ahdhdjxkdjjshsysusiiaiajsjjdyxc

Answer:

5=4x+13

4x+13=5

4x=5-13

4x= -8

x = -8÷4

x = -2

# be careful£

Hi!

q = 25 inches

r = 58 inches

s=37 inches

25 + 58 + 37 = 120

180 - 120 = 60

Answer: 60

I wish you success :)

Answer: 138

Step-by-step explanation:

137.777 = 138

The area of the region enclosed by y = ln(x) is e - 1.

The area of the region enclosed by y = ln(x), the x-axis, the y-axis, and y = 1.

(A) Using the method of horizontal slices (dx), we can integrate with respect to x:

The limits of integration are x = 1 (where the curves intersect) and x = e (where y = 1).

The height of the slice is y = 1 - ln(x)

Therefore, the area is given by:

A = ∫[1,e] (1 - ln(x)) dx

= x - x ln(x) |[1,e]

= e - e ln(e) - 1 + 1 ln(1)

= e - 1

Therefore, the area of the region is e - 1 square units.

(B) Using the method of vertical slices (dy), we can integrate with respect to y:

The limits of integration are y = 0 (where the curve intersects the x-axis) and y = 1.

The width of the slice is x = \(e^y\)

Therefore, the area is given by:

A = ∫[0,1] \(e^y\) dy

= \(e^y\) |[0,1]

= e - 1

Therefore, the area of the region is e - 1 square units, which is the same as the result obtained using horizontal slices.

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Answer:

Provided an attachment

Step-by-step explanation:

Answer:

y = 2x - 4

Step-by-step explanation:

To solve this problem, we must first calculate the slope of the line AB using the formula:

\(\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}\)

where:

m ⇒ slope of the line

(x₁, y₁), (x₂, y₂) ⇒ coordinates of two points on the line

Therefore, for line AB with points A = (2, 5) and B = (4, 4) :

\(m_{AB} = \frac{5 - 4}{2 - 4}\)

⇒ \(m_{AB} = \frac{1}{-2}\)

⇒ \(m_{AB} = -\frac{1}{2}\)

Next, we have to calculate the slope of the line BC.

We know that the product of the slopes of two perpendicular lines is -1.

Therefore:

\(m_{BC} \times m_{AB} = -1\)      [Since BC and AB are at right angles to each other]

⇒ \(m_{BC} \times -\frac{1}{2} = -1\)

⇒ \(m_{BC} = -1 \div -\frac{1}{2}\)      [Dividing both sides of the equation by -1/2]

⇒ \(m_{BC} = \bf 2\)

Next, we have to use the following formula to find the equation of line BC:

\(\boxed{y - y_1 = m(x - x_1)}\)

where (x₁, y₁) are the coordinates of a point on the line.

Point B = (4, 4) is on line BC, and its slope is 2. Therefore:

\(y - 4 =2 (x - 4)\)

⇒ \(y - 4 = 2x - 8\)         [Distributing 2 into the brackets]

⇒ \(y = 2x-4\)

Therefore, the equation of line BC is y = 2x - 4.

Answer:

Please see the attached picture for full solution.

In an assignment problem, each resource can perform only one task. The assignment problem is a linear programming problem that seeks to minimize the cost of assigning tasks to available resources.

An assignment problem is a combinatorial optimization problem in which a group of jobs must be assigned to a group of workers while minimizing the total cost of completing the jobs. This type of problem is solved using linear programming. In addition, there is a one-to-one matching between the set of jobs and the set of workers. The goal of an assignment problem is to find the optimal or best possible pairing of jobs to workers.To obtain the best possible solution, an optimal assignment algorithm can be utilized. There are four basic methods to solve the assignment problem: the Hungarian method, the matrix reduction method, the branch-and-bound method, and the Auction algorithm.

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A technique called simple random sampling involves choosing a random group of individuals from a predetermined population.

A selection of participants from a population is chosen at random by the researcher using simple random sampling, a sort of probability sampling.

Every person in the population has the same chance of being chosen.

Then, data are gathered from as much of this randomly selected subgroup as possible.

A straightforward random sample, where each participant has an equal chance of being selected, selects a small, random portion of the entire population to represent the entire data set.

Using techniques like lotteries or random draws, researchers can generate a straightforward random sample.

Therefore, a technique called simple random sampling involves choosing a random group of individuals from a predetermined population.

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Answer:

tan38 = 0.31

cos47 = -0.99

sin77 = 0.99

Step-by-step explanation:

There are several free online calculators that can help you do this! I recommend Desmos!

Answer:

here

Step-by-step explanation:

Step 1 : set the denominator equal to zero to find the number to put in the division box. Next, make sure the numerator is written in descending order.

Step 2 : Once the problem is set up correctly, bring the leading coefficient (first number) straight down.

Step 3 : Multiply the number in the division box with the number you brought down and put the result in the next column.

Step 4 : Add the two numbers together and write the result in the bottom of the row.

Step 5 : Repeat steps 3 and 4 until you reach the end of the problem.

Step 6 : Write the final answer. The final answer is made up of the numbers in the bottom row with the last number being the remainder and the remainder must be written as a fraction.

A quadratic equation is a polynomial equation of degree 2, which means the highest power of the variable is 2. It is generally written in the form: ax^2 + bx + c = 0. Option (d) x = -8, x = 8 is the correct answer.

The given equation is 15x^2 - 56 = 88 - 6x^2.

We need to find the values of x that are solutions to the given equation.

Solution: We are given an equation 15x² - 56 = 88 - 6x².

Rearrange the equation to form a quadratic equation in standard form as follows: 15x² + 6x² = 88 + 56  21x² = 144  

x² = 144/21 = 48/7

Therefore x = ±sqrt(48/7) = ±(4/7)*sqrt(21).

The values of x that are solutions to the given equation are x = -4/7 sqrt(21) and x = 4/7 sqrt(21).

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The given equation is 15x² - 56 = 88 - 6x². Values of x are solutions to the equation below 15x² - 56 = 88 - 6x² are x = -2.62, 2.62 or x ≈ -2.62, 2.62.

Firstly, let's add 6x² to both sides of the equation as shown below.

15x² - 56 + 6x² = 88

15x² + 6x² - 56 = 88

Simplify as shown below.

21x² = 88 + 56

21x² = 144

Now let's divide both sides by 21 as shown below.

x² = 144/21

x² = 6.86

Now we need to solve for x.

To solve for x we need to take the square root of both sides.

Therefore, x = ±√(6.86).

Therefore, the values of x are solutions to the equation below are x = -2.62, 2.62 or x ≈ -2.62, 2.62.

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