31 15 X What is the value of x in this triangle? Enter your answer as a decimal in the blank. Round only your final answer to the nearest hundredth. ​

Answer:

the answer is one solution

Answer:

x=0

This means that there is a solution.

Step-by-step explanation:

Step 1- Distribute into the parenthesis

-14-8x= (-2)-3x+(-2)7

Step 2- Multiply

-14-8x= 6x-14

Step 3- Add 8x to both sides.

-14x-8x= 6x-14

     +8x +8x

Step 4- Add 14 to both sides.

-14= 14x-14

+14       +14

Step 5- Divide both sides by 14.

0 = 14x

14    14

x=0

Answer:

The chain is around 11 feet in length.

Step-by-step explanation:

Area of a circle = π × r²

380 ft² = π × r²

121 ft² = r²

11 ft = r

The solution to the equation one-third (x + 9) = negative 12 is  x = -45

The equation is given as:

one-third (x + 9) = negative 12

Rewrite properly as:

1/3 (x + 9) = -12

Multiply both sides by 3

x + 9 = -36

Subtract 9 from both sides

x = -45

Hence, the solution to the equation one-third (x + 9) = negative 12 is  x = -45

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Answerrrrrrrrrrr -

:0

Answer:

OmGgggg so true tho- XDDD

Step-by-step explanation:

I’m losing so many brain cells just thinking about that xD

Given :

To Find :

Solution :

We know that,

\( \purple{ \boxed{\quad \bf Length \times Width = Area_{(rectangle)}}}\)

Now, Putting the values in the formula :

\({ \qquad \sf { \dashrightarrow{ x(x + 2)= 168 {cm}^{2} }}}\)

\({ \qquad \sf { \dashrightarrow{ {x}^{2} + 2x= 168 }}}\)

\({ \qquad \sf { \dashrightarrow{ {x}^{2} + 2x - 168=0 }}}\)

\({ \qquad \sf { \dashrightarrow{ {x}^{2} - 12x + 14x - 168 = 0 }}}\)

\({ \qquad \sf { \dashrightarrow{ {x}(x - 12) + 14(x - 12) = 0 }}}\)

\({ \qquad \sf { \dashrightarrow{ ({x}+ 14)(x - 12) = 0 }}}\)

\({ \qquad \sf { \dashrightarrow{ ({x}+ 14) = 0 }}}\)

\({ \qquad \sf { \dashrightarrow{ {x}= - 14 }}}\)

\({ \qquad \sf { \dashrightarrow{ ({x} - 12) = 0 }}}\)

\({ \qquad \sf { \dashrightarrow{ {x} = 12 }}}\)

The length of the rectangle can never be negative so the length must be 12 cm .

Therefore, Width = (12 + 2) = 14 cm .

(1,2,4)

Range describes the y-values of a graph.

Range

Range is the y-values that a graph covers. Remember that the y-values are found on the vertical axis. If the graph is not continuous, then the values between the points are not included in the range. Similar to the range, the domain of a graph is the x-values that a graph covers. If there is a coordinate point with a y-value, then that y-value should be included in the range.

Finding Range

In order to find the range, we need to find all the unique y-values of the graph. Additionally, the range is given in numerical order. This means starting from the least value and going up to the greatest. The lowest y-value is 1, then 2, and finally 4. Even though there are two points where y = 2, we are only looking for unique values. This means that the range is (1,2,4).

The another equivalent expression of total liquid is (x+2)/4.

Expressions that perform similarly but differ in appearance are said to be equivalent expressions. When the same value for the variable is entered, two algebraic expressions that are equivalent will have the same result.

x quarts liquid in the container 3/4 part of liquid is removed

Then remaining liquid in container = X - \(\frac{3}{4}X\)

Then remaining liquid in container = x/4quarts

Another 1/2 quart is poured into container

Then total liquid = \(X-\frac{3}{4}X+\frac{1}{2}\) quarts

total liquid = \(\frac{X+2}{4}\) quarts

So, then the another equivalent expression of total liquid is (x+2)/4.

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Class A and Class C sell 187.5 altogether

Represent the classes with their initials

So, we have

B = 2A

C = 3/4 * B = 3/4 * 2A

C = 3/2A

The total number of bars they had initially was

A + B + C = Total

A + 2A + 3/2A = Total

Total = 4.5A

The average number of bars the 3 classes had initially was 225,

So

4.5A = 225

A = 75

For Class A and Class C together, we have

Class A and C = A + 3/2A

Class A and C = 75 + 3/2 * 75

Class A and C = 187.5

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By using  the sum or difference formula of cosine to solve cos(525°) we get cos(525°) = -0.465

The formula to find the value of cos(A ± B) is given as,

cos(A + B) = cosA cosB − sinA sinBcos(A − B) = cosA cosB + sinA sinB

Here, A = 450° and B = 75°

We can write 525° as the sum of 450° and 75°.

Therefore,cos(525°) = cos(450° + 75°)

Now, we can apply the formula for cos(A + B) and solve it.

cos(A + B) = cosA cosB − sinA sinBcos(450° + 75°) = cos450° cos75° − sin450° sin75°= 0.707 × 0.259 − 0.707 × 0.966= -0.465

Substituting the values in the above equation, we get

cos(525°) = 0.707 × 0.259 − 0.707 × 0.966= -0.465

Thus, cos(525°) = -0.465.

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For the  entire operation of positioning and attaching a randomly selected part, there are no changes in the shape and variability of the total time distribution of the entire operation whereas the center of the normal distribution enlarges each operation performed.

We know that -

A time and motion study is used to determine the time needed by an assembly line worker to carry out different repetitive tasks.

For such an operation of positioning and attaching a randomly selected part, we can define shape, center, and variability as below -

(a) Shape -

For a randomly selected part of different repetitive tasks, there exists a normal distribution function.

So, if there are several repetitive task such as positioning and attaching are added up one after another, there is a certain constant being added up to every particular operation.

We know that, in a normal distribution function, any addition of constant doesn't affect the shape of the total time distribution. So, there won't be any change in the shape of the total time required for the entire operation.

(b) Center

We have already determined that the entire operation of positioning and attaching represents a normal distribution function where certain repetitive tasks equal to the addition of constant to this function.

So, for this type of normal distribution function, addition of constant to a specific operation (or, data value) will lead to increase in the center of normal distribution.

Thus, the center of the total time distribution will be magnified for the entire operation.

(c) Variability

For the normal distribution function that represents the entire operation of positioning and attaching a randomly selected part, there is always a constant being added to the distribution.

For each of the constant added to the operations (or, data value), there won't be any change in the variability of the normal distribution.

Therefore, for the  entire operation of positioning and attaching a randomly selected part, there are no changes in the shape and variability of the total time distribution of the entire operation whereas the center the distribution enlarges each operation performed.

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Answer:

14400

Step-by-step explanation:

(105-15)²

We will solve it with Identity:

(a-b)² = a²+2ab-b²

So,

Answer:

28

Step-by-step explanation:

If he has himself plus 6 friends that is 7 people then you take 7x4=28  so he needs 28 cookies

Answer:

24 or 28

Step-by-step explanation:

if the cookies are just for friends its 24 since 6x4 equals 24

if its his friends AND him then it would be 28 since 7x4 equals 28

The number of such lists that have the property that the d occurs before the a is 120.

In order to obtain a solution to this problem, we will use the principle of permutations with restrictions. We can solve the problem by first finding the total number of permutations of length 6 made from the letters a,b,c,d,e,f.

This is given by 6!, or 720, since we are not allowing repetition.

Then, we need to find the number of permutations of length 6 made from the letters a,b,c,d,e,f where d appears before a.

We can solve this by fixing the position of d and a in the list.

The position of d can be any of the first five positions, since we want d to appear before a. Once d is fixed, the position of a can be any of the remaining four positions.

Finally, the remaining four letters can be arranged in any order, which gives us 4! permutations of those letters.

Therefore, the number of such lists that have the property that the d occurs before the a is equal to the product of the number of ways to choose the position of d (5), the number of ways to choose the position of a (4), and the number of ways to arrange the remaining four letters (4!), which is equal to 5×4×4!=120.

Therefore, the number of such lists that have the property that the d occurs before the a is 120.

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Answer:

it does

Step-by-step explanation:

Answer: 2.2

Step-by-step explanation: twenty percent of 11 is 2.2

The amount of sales tax on Finnegan's purchase is $5.94

The first step is to calculate the total amount of purchase

Sweater- $29.50

Jeans- $42.50

Total amount

29.50 + 42.50

= 72

The sales tax rate is 8.25%

The amount of sales tax on the purchase can be calculated as follows

8.25/100 × 72

= 0.0825 × 72

= 5.94

Hence the sales tax on the total purchase is $5.94

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C. It may be especially useful in circumstances in which the combination of inherent and control risk is at the maximum level.

Nonstatistical sampling is a sampling technique used in substantive tests, which involves selecting items based on auditors' judgment rather than using statistical methods. The correct statement from the given options is C, as nonstatistical sampling may be particularly useful when both inherent risk and control risk is assessed as being at the maximum level.

Nonstatistical sampling does not require populations with an immaterial book value (Option A is incorrect). It also does not necessarily require the use of structured sample size selection techniques (Option B is incorrect). Nonstatistical sampling allows auditors to select items based on their judgment, which can be useful in situations where inherent and control risks are high.

By focusing on areas of maximum risk, auditors can efficiently identify potential misstatements or errors in the population (Option C is correct).

Regarding Option D, nonstatistical sampling does not involve projecting the results to the entire population. Instead, auditors make conclusions based on the sampled items and use professional judgment to assess the overall population (Option D is incorrect).

In summary, option C is correct because nonstatistical sampling may be particularly useful when inherent and control risks are assessed at their maximum level, allowing auditors to focus their efforts on areas of highest risk.

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Answer:

C. Squares always have four interior right angles; rhombi do not.

Answer:

the unit rate of pesos to dollars is 1 MXN = 0.04960 USD

Step-by-step explanation:

Quick Conversions from Mexican Peso to United States Dollar : 1 MXN = 0.04960 USD

$ or MEX$ 10 $, US$ 0.50

$ or MEX$ 50 $, US$ 2.48

$ or MEX$ 100 $, US$ 4.96

$ or MEX$ 250 $, US$ 12.40

Answer:

x = 13

Step-by-step explanation:

The angle of a straight line = 180

180-74=106

(8x+2)=106

106-2=104

8x=104

104/8=13

x=13

Without specific data on the number of students who prefer each option, we cannot calculate the probability.

To determine the probability that a student prefers the zoo or the water park, we need to know the total number of students and the number of students who prefer each option. Without this information, it is not possible to calculate the probability accurately.

To calculate the probability, we would need to divide the number of students who prefer the zoo or the water park by the total number of students. For example, if there are 50 students in total and 30 prefer the zoo and 20 prefer the water park, the probability would be:

P(prefer zoo or water park) = (30 + 20) / 50 = 50 / 50 = 1

However, without specific data on the number of students who prefer each option, we cannot calculate the probability.

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The null hypothesis is formulated as a statement of equality to represent the assumption of no effect, no difference, or no relationship between variables in hypothesis testing.

The null hypothesis is typically formulated as a statement of equality because it represents the assumption or claim of no effect, no difference, or no relationship between variables in the context of statistical hypothesis testing.

When conducting hypothesis tests, we start with the assumption that there is no significant difference or relationship between variables, and any observed differences or relationships are merely due to random chance or sampling variability. The null hypothesis serves as a benchmark or reference point against which we compare the observed data.

Formulating the null hypothesis as a statement of equality allows for a clear and specific claim to be tested statistically. It sets the baseline or default position that is assumed to be true unless there is sufficient evidence to reject it in favor of an alternative hypothesis.

For example, in a study comparing the mean scores of two groups, the null hypothesis might state that the population means are equal (μ1 = μ2). This implies that any observed difference in sample means is due to chance, rather than a true difference in the population means.

By specifying the null hypothesis as a statement of equality, statistical tests provide a framework to assess the likelihood of observing the obtained data under the assumption of no effect or no difference, allowing us to make inference and draw conclusions about the population parameters based on the evidence from the sample.

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The Confidence interval for the population standard deviation σ  is 0.25  <  \(\sigma\)  < 0.47 oz.

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. In statistics, confidence is another word for probability.

Given:

n = 22

x = 1.37

s= 0.33

So, Confidence Interval

= √(n-1)s² / \(\chi^2_{(0.05/2, 21)}\) <  \(\sigma\)  < √(n-1)s² / \(\chi^2_{(1-0.05/2, 21)}\)

=  √(21)(0.33)² / 35.4789 <  \(\sigma\)  < √(21)(0.33)² / 10.2829

= 0.2539  <  \(\sigma\)  < 0.4716

= 0.25  <  \(\sigma\)  < 0.47 oz

Hence, the Confidence Interval is  0.25  <  \(\sigma\)  < 0.47 oz

.

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The range of the given function y = 3 | x - 1 | +3 for the domain 0 ≤ x ≤ 3 will be [3,9].

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

The given function has been drawn below.

The minimum value of the function in interval 0 ≤ x ≤ 3 is 3 while the maximum value is 9.

The range will be [3,9].

Hence "For the domain 0 x 3, the provided function, y = 3 | x - 1 | +3, will have a range of [3,9].".

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Answer:

$100-5(15) aka $25 still owed

Answer: CB, DA, IJ, HG

Step-by-step explanation:

As long as the lines never intersect, they are parallel

Answer:

DONT CHEAT

Step-by-step explanation:

Answer:

160 for each

Step-by-step explanation:

A normal distribution means that mean = median = mode. Furthermore, in a normal distribution, 68% of values are within 1 standard deviation of the mean, 95% of values are within 2 standard deviations, and 99.7% are within 3 standard deviation.

The mean is 150 and the standard deviation is 15. 165 and 135 1 standard deviation away from the mean, so 68% of values are between 135 and 165. This means that 32% of values are not between those values. A normal distributuion is symmetric, so 16% of values are greater than 1 standard distribution and 16% are less. Therefore, 16% of values (160) are less than 135 and 16% of values (160) are greater than 165

Answer:

Step-by-step explanation:

140

Answer:

19° = m∠B

73° = m∠T

88° = m∠R

Step-by-step explanation:

Let x = measure of angle B

then 4x - 3 = measure of angle T

 and 31 + 3x = measure of angle R

x + 4x - 3 + 31 + 3x = 180

8x + 28 = 180

8x = 152

x = 19° = m∠B

4(19) - 3 = 73° = m∠T

31 + 3(19) = 88° = m∠R

Answer:

Step-by-step explanation:

7x+4=10x-11

4=3x-11

15=3x

x=5