25 g sample of a compound that contains only C and H was burned in separately and weighed. It was found that 3.007 g of CO₂ and 1.845 H₂O were formed in this reaction. What is the empirical formula of the compound?​

The statement "the reaction between R and P appeared to stop when no further changes were observed" suggests that the observable changes in the reaction have ceased. However, chemical reactions may not actually "stop" completely even when no further changes are visibly observed.

Chemical reactions occur at the molecular level, where individual molecules collide and undergo chemical transformations. Even if the macroscopic changes or observable properties appear to have reached a steady state, the molecular-level reactions can continue at an equilibrium. In other words, while the overall concentrations or properties of the reactants and products may remain constant, the individual molecules are still undergoing constant microscopic fluctuations and interconversions.

In such cases, the reaction is considered to be in a dynamic equilibrium, where the forward and reverse reactions occur at equal rates, resulting in no net change in the macroscopic observable properties. This state of equilibrium does not imply that the reaction has completely stopped but rather that the rates of the forward and reverse reactions have balanced out.

Therefore, even when no further changes are observed at the macroscopic level, chemical reactions can continue at the molecular level in a dynamic equilibrium state.

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Answer:

B: Magma

Explanation:

technically magma is the name for the hot molten rock (mixed with gases and mineral crystals) that collects in chambers beneath the Earth's crust.

The crust has been the upper layer of the earth's geosphere. It has been characterized by the presence of melted rocks and minerals that are called magma. Thus, option A is correct.

Magma has been defined as the hot semi-liquid president beneath the earth's surface in the crust layer. It has a very high temperature and is known to have many metals and minerals dissolved in it. The magma comprises metals minerals, dissolved gases, etc.

When the magma from the magma chambers flows outwards on the earth's surface then it is called lava. This lava on cooling produces igneous rocks. This event of magma explosion and lava formation along with other gases from a mountainous surface is called volcanic eruption.

Therefore, option A. melted rock and minerals in Earth's crust is called magma.

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Answer:

Ver explicacion

Explanation:

La gravedad es una fuerza que actúa a distancia. La fuerza que actúa entre la tierra y los cuerpos en ella es la fuerza gravitacional.

Es un ejemplo típico de una fuerza de acción a distancia.

Por lo tanto, la fuerza tat que existe entre la tierra y los cuerpos que se encuentran en ella es una fuerza de distancia.

To calculate the work that an object does when it moves covering a distance of 3000 meters when it is propelled by a force of 65 Newton, one of the principles of mechanics must be considered.

A force does work when there is a displacement of the center of mass of the body on which the force is applied, in the direction of said force.

The work of the force on that body will be equivalent to the energy necessary to displace it, so that:

W = F.d

Substituting the corresponding values in said formula:

F = 65N

d = 3000m

W = 65 N. 3000 m

W = 195000 W

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To determine the mass percent of chloride in the original sample, we need to first calculate the amount of chloride present in the sample. We can do this by using the balanced equation for the reaction between chloride and silver nitrate:

AgNO3 + Cl- → AgCl + NO3-

First, we need to calculate the number of moles of silver nitrate used in the titration:

moles of AgNO3 = volume (L) x molarity (M) = 0.03083 L x 0.7890 M = 0.02439 moles

Next, we can use the balanced equation to find the number of moles of chloride:

moles of Cl- = moles of AgNO3 = 0.02439 moles

Finally, we can use the number of moles of chloride to calculate the mass of chloride in the sample:

mass of Cl- = moles of Cl- x molar mass of Cl- = 0.02439 moles x 35.5 g/mol = 0.868 g

To find the mass percent of chloride in the original sample, we divide the mass of chloride by the total mass of the sample and multiply by 100%.

mass percent of Cl- = (mass of Cl- / total mass of sample) x 100%

Since we don't know the total mass of the sample, we can use the mass of chloride we just calculated and the formula above to find the mass percent of chloride in the original sample.

mass percent of Cl- = (0.868 g / 0.1599 g) x 100% = 54.3%

So, the mass percent of chloride in the original sample is 54.3%.

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Answer:

432 grams of Ag

Explanation:

First, we need to determine the limiting reagent between Mg and AgNO3.Using the stoichiometry of the balanced chemical equation, we can see that 1 mole of Mg reacts with 2 moles of AgNO3 to produce 2 moles of Ag.

The number of moles of Mg present in 48 grams can be calculated as:

48 g / 24 g/mol = 2 moles Mg

Now, let's calculate the number of moles of Ag that can be produced from 2 moles of Mg:

2 moles Mg x (2 moles Ag / 1 mole Mg) = 4 moles Ag

Finally, we can calculate the mass of Ag produced by multiplying the number of moles of Ag by its molar mass:

4 moles Ag x 108 g/mol = 432 grams Ag

Therefore, 48 grams of Mg will produce 432 grams of Ag in this reaction.

This is a stoichiometry question, and will be answered in two steps, but the first thing for every stoichiometry question is to have the reaction properly balanced, which the question already provided us:

S8 + 8 O2 -> 8 SO2

First step is to find the limiting and excess reactant, this will tell us which element is in excess and by how much, let's gather the data for the reactants first:

30.14 grams of S8, molar mass of S8 is 256.5g/mol

287.43 grams of O2, molar mass of O2 is 32g/mol

Now we will focus on S8, and see how many moles we have of it in this reaction:

256.5 g = 1 mol

30.14 g = x moles

x = 0.12 moles of S8 in this reaction

According to the molar ratio, 1:8, we need 1 mol of S8 and 8 moles of O2 in order to have the reaction to proceed

1 S8 = 8 O2

0.12 S8 = x O2

x = 0.96 moles of O2 if we have 0.12 moles of S8

We only need 0.96, if we have more than that, is excess, if we have less than that, this means that O2 is the limiting and S8 is in excess, so let's check how much of O2 we do have

32g = 1 mol

287.43 g = x moles

x = 8.98 moles of O2, we have a big excess of O2, we only need 0.96 moles and we have almost 9 times more

Now that we know which element is the limiting, we can use this information to find the theoretical yield of SO2

The molar ratio will also be 1:8, and since we have 0.12 moles of S8, we will have 8 times that, which is 0.96 moles of SO2, using its molar mass, 64.1g/mol, we will have the theoretical yield

64.1g = 1 mol

x grams = 0.96

x = 61.5 grams is the theoretical yield

55.59 grams is the actual yield

Now we use these two values in the percent yield formula:

%yield = actual yield/theoretical yield

%yield = 55.59/61.5

%yield = 0.90

Limiting reactant = S8

Excess reactant = O2

Percent yield = 90%

When cooking in the same pan and on the same burner setting, 250 ml (about 1 cup) of water will start to boil more quickly than 1 l (about 4 cups) of water. This is because 1 cup of water has a lower heat capacity than 4 cups.

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If one part of a system fails, this affects the rest of the system.

\(4.8 M = \frac{4 mol}{x}\)

x = 0.83 L

Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

The reaction is spontaneous at 298K room temperature with the Gibb's free energy of -50.76KJ/Mol.

How to calculate Gibb's free energy?

The maximum amount of reversible work that a system may perform under constant temperature and pressure circumstances is determined using the thermodynamic function known as Gibbs free energy (G).

The change in Gibbs free energy is zero when a system is in equilibrium. The formula: can be used to assess the overall spontaneity of a response or bodily change.

ΔG= Δ H − T Δ S

When the specified values are substituted, the reaction's change in Gibbs free energy is:

ΔG = \(\frac{-74.85KJ/Mol*-298K}{-8.084 *10^{-2}KJ/Mol*K }\)

ΔG = -50.76 KJ/mol

At 298K, the reaction has a negative G value. Because it is exergonic, the reaction will happen on its own.

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Answer:

C. an entirely new substance with new properties forms as a result of the change

Answer:

. an entirely new substance with new properties forms as a result of the change

Explanation:

The mass of 0.5 mole of the element is approximately 6.025 grams.

To calculate the mass of 0.5 mole of the element, we need to know the molar mass of the element.

Given that the mass of 2 x 10^21 atoms of the element is 0.4 grams, we can use this information to find the molar mass.

The number of atoms in 1 mole of any substance is given by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.

First, we calculate the molar mass of the element using the given information:

Molar mass = Mass of 2 x 10^21 atoms / Number of moles of 2 x 10^21 atoms

Molar mass = 0.4 g / (2 x 10^21 atoms / (6.022 x 10^23 atoms/mol))

Molar mass ≈ 0.4 g / (3.32 x 10^-2 mol)

Molar mass ≈ 12.05 g/mol

Now that we know the molar mass of the element is approximately 12.05 g/mol, we can calculate the mass of 0.5 mole of the element:

Mass = Molar mass x Number of moles

Mass = 12.05 g/mol x 0.5 mol

Mass = 6.025 grams

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DNA is made up of genes that carry hereditary information

The molecule inside cells that contains the genetic information responsible for the development and function of an organism and DNA molecules allow this information to be passed from one generation to the next generation and a molecule that contains the biological instructions that make each species unique

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Answer:

2 C4H10     +  13  O2    ====>   8  CO2      + 10 H2O

Explanation:

It is a very good oxidizing agent, so hypochlorite is used.

What is an oxidizing agent?

In a redox chemical process, an oxidizing agent is a material that obtains or "accepts" or "receives" an electron from a reducing agent (also known as an oxidant, oxidizer, electron recipient, or electron acceptor) (called the reductant, reducer, or electron donor). So every substance that oxidizes another material is an oxidant. By saying that oxidizers "undergo reduction" and "are reduced" while reducers "undergo oxidation" and "are oxidized," it may be indicated that the oxidizer's oxidation state, which characterizes the degree of electron loss, falls while the reductant's increases. Oxygen, hydrogen peroxide, and halogens are frequently used oxidizing agents.

It is a very good oxidizing agent, so hypochlorite is used.

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Yes, nonpolar molecules generally diffuse more readily through the plasma membrane than polar molecules of the same size.

This is because the plasma membrane is composed of a lipid bilayer which has a hydrophobic interior, making it easier for nonpolar molecules to pass through.

The plasma membrane is a selectively permeable barrier that separates the cell from its external environment. It is composed of a lipid bilayer made up of phospholipids, cholesterol, and proteins.

The hydrophobic tails of the phospholipids form the interior of the membrane while the hydrophilic heads face outward, interacting with the surrounding aqueous environment.

Nonpolar molecules, such as oxygen and carbon dioxide, are able to pass through the lipid bilayer more easily than polar molecules like glucose and ions. This is because the hydrophobic interior of the membrane repels polar molecules while allowing nonpolar molecules to pass through.

When a molecule comes in contact with the plasma membrane, it will diffuse across the membrane if it is able to pass through the hydrophobic interior. The rate of diffusion is influenced by the size, polarity, and concentration gradient of the molecule.

Small nonpolar molecules, such as oxygen, diffuse rapidly through the membrane, while larger nonpolar molecules diffuse more slowly. Polar molecules, such as glucose, diffuse even more slowly, and ions require transport proteins to pass through the membrane.

Overall, nonpolar molecules diffuse more readily through the plasma membrane than polar molecules of the same size due to the hydrophobic interior of the lipid bilayer.

This property of the membrane plays an important role in regulating the movement of molecules into and out of the cell.

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The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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From the given information each sphere of aluminium contian 13 electrons in it.The sphere of aluminium is made of aluminium or of different alloys of aluminium. Aluminium alloy balls, malleable, ductile and non-magnetic, are preferred where lightweight materials are needed that have good surface finishing or wear resistance.

The number of electrons in a sphere of aluminum can be determined by knowing the atomic number of aluminum, which is 13. The atomic number represents the number of protons in the nucleus of an atom and is also equal to the number of electrons in a neutral atom.

When an aluminium sphere is dipped in water and the temperature of water is increased, the aluminium will start expanding leading to increase in its volume.

So, each sphere of aluminum would contain 13 electrons.

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The boiling temperature of bromine is 331.29 K

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

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Lithium=li

Iron=Fe

Helium=He

I don't say u must have to mark my ans as brainliest but if u think it has really helped u plz don't forget to thank me....

Answer:

lithium symbol=li helium= he and iron =i

Answer: Van't Hoff factor, i is less than expected from the formula of the compound and this decreases the effective concentration of particles.

Explanation:

Strong electrolytes are defined as the solutions which completely dissociate into their ions.

But, most of the strong electrolytes do not dissociate completely (act ideally) but remain partially undissociated into the ions. Thus, giving a lesser number of ions in the solution than expected.

This means that the Van't Hoff factor, i which denotes the number of ions is less than expected.

As fewer ions are released in the solution, the concentration of the solution is expected to decrease.

Hence, van't Hoff factor, i is less than expected from the formula of the compound and this decreases the effective concentration of particles.

In the external circuit, electrons migrate from the Cd|Cd2+ electrode to the I-|I2 electrode. In the salt bridge, anions migrate from the Cd|Cd2+ compartment to the I-|I2 compartment.

The anode reaction is Cd(s) → Cd2+(aq) + 2e-

The cathode reaction is I2(s) + 2e- → 2I-(aq)

In a voltaic cell, oxidation occurs at the anode (negative electrode), and reduction occurs at the cathode (positive electrode). The anode reaction involves the loss of electrons (oxidation), while the cathode reaction involves the gain of electrons (reduction).

Given the cell reaction: I2(s) + Cd(s) → 2I-(aq) + Cd2+(aq)

The anode reaction occurs at the Cd|Cd2+ electrode:

Cd(s) → Cd2+(aq) + 2e-

The cathode reaction occurs at the I-|I2 electrode:

I2(s) + 2e- → 2I-(aq)

In the external circuit, electrons always flow from the anode to the cathode. Therefore, electrons migrate from the Cd|Cd2+ electrode (anode) to the I-|I2 electrode (cathode).

In the salt bridge, the purpose is to maintain charge neutrality in the half-cell compartments. Anions migrate from the compartment with higher anion concentration (Cd|Cd2+ compartment) to the compartment with lower anion concentration (I-|I2 compartment). This helps balance the charges and maintain electrical neutrality.

In summary, the anode reaction in the voltaic cell is Cd(s) → Cd2+(aq) + 2e-, and the cathode reaction is I2(s) + 2e- → 2I-(aq). Electrons migrate from the Cd|Cd2+ electrode (anode) to the I-|I2 electrode (cathode) in the external circuit. In the salt bridge, anions migrate from the Cd|Cd2+ compartment to the I-|I2 compartment to maintain charge neutrality.

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Answer:

A

Explanation:

The standard free-energy change at 25 ∘C for the given reaction, Mg(s)+Fe₂+(aq)→Mg₂+(aq)+Fe(s) can be calculated using the equation:ΔG∘ = ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)where ΔGf∘ is the standard free energy of formation of the compound, n is the stoichiometric coefficient of each compound in the reaction.

The values of ΔGf∘ for the given reaction are:

Mg₂+ (aq):−467.2 kJ/mol Fe(s): 0 kJ/mol Fe₂+(aq): −237.2 kJ/mol Mg(s): 0 kJ/molΔG∘ =

ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)ΔG∘ =

[ΔGf∘ (Mg₂+ (aq)) + ΔGf∘ (Fe(s))] - [ΔGf∘ (Mg(s)) + ΔGf∘ (Fe₂+(aq))]ΔG∘ =

[−467.2 kJ/mol + 0 kJ/mol] - [0 kJ/mol + (−237.2 kJ/mol)]ΔG∘ =

−230.0 kJ/mol At 25 ∘C, the standard free-energy change for the given reaction is −230.0 kJ/mol. The units of ΔG∘ are kilojoules per mole (kJ/mol). Hence, the answer is -230.0 kJ/mol.

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Using the ideal gas law equation PV = nRT, with n = 0.18 mol, R = 8.314 J K^(-1) mol^(-1), T = 300.15 K, and P = 102,300 Pa, the volume of the balloon can be calculated.

To find the volume of the balloon, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Step 1: Convert the temperature from Celsius to Kelvin.

Given that the temperature is 27 degrees Celsius, we need to add 273.15 to convert it to Kelvin.

T = 27°C + 273.15 = 300.15 K

Step 2: Determine the gas constant to use.

We are given two options for the gas constant: R = 8.314 J K^(-1) mol^(-1) or R = 0.082 L atm K^(-1) mol^(-1). Choose the appropriate gas constant based on the desired units for the volume.

Step 3: Substitute the values into the ideal gas law equation.

Using the selected gas constant, we can rearrange the equation to solve for the volume:

V = (nRT) / P

Substitute the given values:

V = (0.18 mol * R * 300.15 K) / 102,300 Pa

Step 4: Calculate the volume.

Evaluate the expression to find the volume of the balloon in the desired units, whether it be in cubic meters (m³) using the first gas constant or in liters (L) using the second gas constant.

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Explanation:

D mole is a power. .......

[NOBr]2/[NO]2[Br2] is the equilibrium expression for 2NO+Br2⇌2NOBr. Therefore, the correct option is option D.

When the observable qualities, such as colour, pressure, temperature, concentration, etc. do not vary, the process is said to be in equilibrium. As "balance" is the definition of the word "equilibrium," it follows because a chemical reaction reflects a balance among the substances and outcomes involved in the reaction.

In some physical processes, such as the melting of ice at 0°C, where both the two substances are present at equilibrium, the equilibrium state can also be observed. Physical equilibrium refers to the equilibrium that results from physical processes like the melting of solids.  [NOBr]2/[NO]2[Br2] is the equilibrium expression for 2NO+Br2⇌2NOBr.

Therefore, the correct option is option D.

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The change in entropy of the surroundings (ΔSsurr) for the given reaction at 48 °C is -0.178 kJ/K.

To calculate the change in entropy of the surroundings (ΔSsurr) for a reaction, we need to use the equation:

ΔSsurr = -ΔHrxn / T

where ΔHrxn is the enthalpy change for the reaction and T is the temperature in Kelvin.

Given:

ΔHrxn = 57.24 kJ

Temperature, T = 48 °C = 321 K (convert Celsius to Kelvin)

Using the given values in the equation, we get:

ΔSsurr = -ΔHrxn / T

ΔSsurr = -(57.24 kJ) / (321 K)

ΔSsurr = -0.178 kJ/K

Therefore, the change in entropy of the surroundings (ΔSsurr) for the given reaction at 48 °C is -0.178 kJ/K.

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