Your friend is trying to solve the equation. Is your friend correct? Does x = 15? How do you know?

Answer:

243

Step-by-step explanation:

3^5  in standard form

3*3*3*3*3

243

The longest poster that can fit in the box must have dimensions of 10 inches (height) by 20 inches (length) by 12 inches (width).

To find the longest poster that can fit in the box, we need to determine the longest dimension of the box itself. Since the box is 10 inches high, the longest poster that can fit in the box must have a height of no more than 10 inches.

Now, we need to consider the other two dimensions of the box. The box is 20 inches long and 12 inches wide, so the longest poster that can fit in the box must have a length of no more than 20 inches and a width of no more than 12 inches.

As for why we can only fit one maximum-length poster in the box but we can fit multiple 22-inch posters in the same box, it's because the length and width of the box are larger than the length and width of the 22-inch poster.

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Answer:

First boxes: 15,659  Second box: 22,370 Last box:38,029

Step-by-step explanation:

Answer:

Step-by-step explanation:

2nd one because if you use logic it works

btw this is a real answer

Answer: 180 = 10(2h), 180 = 20h, So 180 divided by 20 is 9. 9 = H - Dollars per hour. Hope this helps you

Step-by-step explanation:

To calculate the Value-at-Risk (VaR) for this investment at a 99% confidence level, we need to determine the loss amount that will be exceeded with a probability of only 1% (i.e., the worst-case loss that will occur with a 1% chance).

Given that there is a 0.5% chance of a loss of $10 million and a 99.5% chance of a loss of $1 million, we can express this as:

Loss Amount | Probability

$10 million | 0.5%

$1 million | 99.5%

To calculate the VaR, we need to find the loss amount that corresponds to the 1% probability threshold. Since the loss of $10 million has a probability of 0.5%, it is less likely to occur than the 1% threshold. Therefore, we can ignore the $10 million loss in this calculation.

The loss of $1 million has a probability of 99.5%, which is higher than the 1% threshold. This means that there is a 1% chance of the loss exceeding $1 million.

Therefore, the Value-at-Risk (VaR) for this investment at a 99% confidence level is $1 million.

The Value-at-Risk (VaR) for this investment at a 99% confidence level is $1,045,000.

To calculate the Value-at-Risk (VaR) for this investment at a 99% confidence level, we need to determine the loss amount that will be exceeded with only a 1% chance.

Given that the investment has a 0.5% chance of a loss of $10 million and a 99.5% chance of a loss of $1 million, we can calculate the VaR as follows:

VaR = (Probability of Loss of $10 million * Amount of Loss of $10 million) + (Probability of Loss of $1 million * Amount of Loss of $1 million)

VaR = (0.005 * $10,000,000) + (0.995 * $1,000,000)

VaR = $50,000 + $995,000

VaR = $1,045,000

Therefore, the Value-at-Risk (VaR) for this investment at a 99% confidence level is $1,045,000.

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Answer:

-8

Step-by-step explanation:

Answer:

y = 3/4x-3

Step-by-step explanation:

The equation of a line in slope intercept form is

y = mx+b where m is the slope and b is the y intercept

The y intercept is -3 ( where it crosses the y axis)

The slope is  change in y over change in x

We go up 3 and over to the right 4

The slope is 3/4

y = 3/4x-3

Answer:

\(x=0, \: -3, \: -4\)

Step-by-step explanation:

We can solve for the zeros of the function by factoring, then setting f(x) to 0 and solving for x.

First, we can factor out an x.

\(f(x) = 3x^3+21x^2+36x\)

\(f(x) = x(3x^2+21x+36)\)

We are left with a quadratic, from which we can factor out a 3.

\(f(x) = 3x(x^2+7x+12)\)

Next, we can factor the quadratic using the rule:

★ \(\text{if } x^2 + cx + d = (x + a)(x+b) \text{, then } a+ b = c \text{ and } a \cdot b = d\) ★

\(f(x) = 3x(x + 3)(x + 4)\)

The equation is now in a fully factored form. Therefore, we can find the zeros of the function by setting f(x) (the function's output) to 0 and solving for when each factor is equal to 0.

★ \(\text{if } AB = 0, \text{ then } A=0 \text{ or } B=0\) ★

\(0 = 3x(x + 3)(x + 4)\)

\(3x = 0\)

\(\boxed{x = 0}\)

OR

\(x+3=0\)

\(\boxed{x = -3}\)

OR

\(x+4 = 0\)

\(\boxed{x = -4}\)

The product of a rational and an irrational number can be either rational or irrational, depending on the specific numbers involved.

To illustrate this, let's consider an example:

Let's say we have the rational number 2/3 and the irrational number √2.

Their product would be (2/3) * √2.

In this case, the product is irrational.

The square root of 2 is an irrational number, and when multiplied by a rational number, the result remains irrational.

However, it's also possible to have a product of a rational and an irrational number that is rational. For example, if we consider the rational number 1/2 and the irrational number √4, their product would be (1/2) * 2, which equals 1. In this case, the product is a rational number.

Therefore, we cannot make a definitive statement that the product of a rational and an irrational number is always rational or always irrational. It depends on the specific numbers involved in the multiplication.

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The ellipse has semi-major axis length of 5/3, the semi-minor axis length of 5/8

To solve the equation 9\(x^2\) + 64\(y^2\) = 25, we can rearrange it to isolate one of the variables and solve for the other. Let's solve for y.

9\(x^2\) + 64\(y^2\) = 25

Divide both sides by 25:

(9\(x^2\) + 64\(y^2\)) / 25 = 1

Now, we can write the equation in standard form:

\(x^2\)/ \((5/3)^2\) + \(y^2 / (5/8)^2\) = 1

Comparing this equation with the standard form of an ellipse:

\((x - h)^2 / a^2 + (y - k)^2 / b^2\) = 1

We can see that the center of the ellipse is at the point (h, k) = (0, 0), and the semi-major axis length is a = 5/3, while the semi-minor axis length is b = 5/8.

Therefore, the equation represents an ellipse centered at the origin with the semi-major axis length of 5/3 and the semi-minor axis length of 5/8.

The graph of the ellipse will be elongated along the x-axis due to the larger value of a compared to b.

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S is a subring of R, we need to demonstrate that S satisfies the three conditions . Therefore, The set S = {x ∈ R | ax ≥ 0} is a subring of the ring R, where a belongs to R.

S is a subring of R, we need to demonstrate that S satisfies the three conditions of being a subring: closure under addition, closure under multiplication, and the existence of additive inverses.

1.Closure under addition: Let x, y ∈ S. This means ax ≥ 0 and ay ≥ 0. To show closure under addition,  to prove that (x + y) ∈ S. Since ax and ay are both non-negative, their sum (ax + ay) is also non-negative. Hence,   (x + y) satisfies the condition for being in S.

2.Closure under multiplication: Let x, y ∈ S. This means ax ≥ 0 and ay ≥ 0. To show closure under multiplication,  to prove that (xy) ∈ S. Multiplying two non-negative numbers results in a non-negative product, so (ax)(ay) = a(xy) ≥ 0. Therefore, xy satisfies the condition for being in S.

3.Existence of additive inverses: For any x ∈ S, we have ax ≥ 0. To show the existence of additive inverses, we need to demonstrate that (-x) ∈ S. Multiplying both sides of ax ≥ 0 by -1 gives -ax ≤ 0. Thus, (-x) satisfies the condition for being in S.

Since S satisfies all the conditions of a subring, namely closure under addition, closure under multiplication, and the existence of additive inverses, we can conclude that S is a subring of R.

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Answer:

18 cups

Step-by-step explanation:

Lem sold 27 cups and

27 ÷ 3 = 9

Lem sold 9 lots of 3 cups , then

Ada sells 9 × 2 = 18 cups

Answer:

27 cups

Step-by-step explanation:

See attached image.

Answer:

The average rate of change of the function is 22.

Step-by-step explanation:

The given function is :

\(f(x)=x^4-5x\)

We need to find the average rate of change of the function on the closed interval (0, 3).

The average rate of change of a function in interval (a,b) is given by :

\(R=\dfrac{f(b)-f(a)}{b-a}\)

Here, a = 0 and b = 3

\(R=\dfrac{(3^4-5(3))-(0^4-5(0))}{3-0}\\\\=\dfrac{66}{3}\\\\=22\)

So, the average rate of change of the function is 22.

Answer:

22

Step-by-step explanation:

(f(3)-f(0))/3

=66/3

=22

$35

He would need $35 to buy 7 pizzas because if you divide 25 and 5, you would get 5.

5+5+5+5+5+5+5=35

5x7=35

Answer:

$35

Step-by-step explanation:

So basically to find the unit price we need to craft an equation. Lets imagine one pizza is p.

We can craft this equation:

5p = 25

Divide both sides by 5

p = 5

How we just multiply that unit price by 7 to get 35, which is the answer

I put a lot of thought and effort into my answers, so I would really appreciate a Brainliest!

Answer:

since the decay rate constant of0.0 250 min.

hence the time required for the sample to decay to one forth of it's initial value is

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

quadrant 2 you're welcome :-)

Answer:

Quadrant 2

Step-by-step explanation:

Since the x coordinate is negative, it must in quadrant 2 or 3

Since the y coordinate is positive, it must in quadrant 1 or 2

It must be in quadrant 2

For this function, A is -2/3, B is 0 and C is 2/3.

To find the critical numbers of the function f(x) = 9x + 4\(x^{-1}\) , we need to find the values of x where the derivative of the function is equal to zero or undefined.

The derivative of f(x) is:

f'(x) = 9 - 4\(x^{-2}\) = 9 - 4/\(x^{2}\)

To find where the derivative is equal to zero, we set f'(x) = 0 and solve for x:

9 - 4/\(x^{2}\)  = 0

4/\(x^{2}\)  = 9

\(x^{2}\) = 4/9

x = ±2/3

Therefore, the critical numbers of f(x) are x = 2/3 and x = -2/3.

To find the intervals where the function is not defined, we need to look for values of x that make the denominator of the expression 4\(x^{-1}\)  equal to zero. In this case, the function is not defined at x = 0.

Now we need to determine the sign of the derivative in each of the intervals (−∞,A], [A,B), (B,C], and [C,∞).

For x < -2/3, f'(x) is negative because 4/\(x^{2}\)  is positive and 9 is greater than 4/\(x^{2}\) . Therefore, the function is decreasing on the interval (−∞,−2/3).

For −2/3 < x < 0, f'(x) is still negative because 4/\(x^{2}\)  is positive and 9 is still greater than 4/\(x^{2}\) . Therefore, the function is decreasing on the interval (−2/3,0).

For 0 < x < 2/3, f'(x) is positive because 4/\(x^{2}\)  is positive and 9 is less than 4/\(x^{2}\) . Therefore, the function is increasing on the interval (0,2/3).

For x > 2/3, f'(x) is still positive because 4/\(x^{2}\)  is positive and 9 is still less than 4/\(x^{2}\) . Therefore, the function is increasing on the interval (2/3,∞).

Finally, the function is not defined at x = 0, so the interval [A,B) is (−∞,0) and the interval (B,C] is (0,∞).

Therefore, we have:

A = -2/3

B = 0

C = 2/3

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Answer:

10

Step-by-step explanation:

given :

length WX ≅ (congruent means equal) length XY

therefore ,  WX = 3

WZ = WX + XZ

WZ = 3 + 7

WX = 10

The postfix expression of "7+5-3*2(6*7)/4" is "7 5 + 3 2 * 6 7 * 2 * - 4 /". Evaluating the postfix expression gives the result of the expression. The prefix expression for the given infix expression is "/ - + 7 5 * 3 * 2 ( * 6 7 ) 4".

To convert the infix expression "7+5-3*2(6*7)/4" into postfix expression, we follow the rules of operator precedence and associativity. The postfix expression is obtained by placing operators after their operands.

The postfix expression for the given infix expression is:

"7 5 + 3 2 * 6 7 * 2 * - 4 /"

To evaluate the postfix expression, we use a stack data structure. We scan the postfix expression from left to right and perform the corresponding operations.

Starting with an empty stack, we encounter the operands "7" and "5". We push them onto the stack. Then we encounter the operator "+", so we pop the last two operands from the stack (5 and 7), perform the addition operation (7 + 5 = 12), and push the result back onto the stack.

We continue this process for the remaining operators and operands in the postfix expression. Finally, after evaluating the entire expression, the result left on the stack is the final answer.

To convert the infix expression into prefix expression, we follow similar rules but scan the expression from right to left. The prefix expression is obtained by placing operators before their operands.

The prefix expression for the given infix expression is:

"/ - + 7 5 * 3 * 2 ( * 6 7 ) 4"

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Answer:

Answer:A)

Kiley bought a platter for $19 and several matching bowls that were $8 each. What is the total cost before tax

here x will be number of bowl which can only be dicrete value e.g 1 , 2 , 3 , 4 ...

Step-by-step explanation:

A discrete graph is a series of scatter plot points. It means point on graph aren't continuous manner.

A continuous function allows the x-values to be ANY points in the interval, including fractions, decimals, and irrational values. A discrete function allows the x-values to be only certain points in the interval, only integers or whole numbers.

Example

Number of student, x

x can only be integer

The number that will complete the square to solve equation is 1/36.

What is completing the square?

For some values of h and k, completing the square is an elementary algebraic method for changing a quadratic polynomial of the form

ax^2 + bx + c to the form a^2 + k. In other words, the quadratic expression is completed by inserting a perfect square trinomial.

Consider, the given polynomial

3w^2 - w - 24 = 0

Rewrite the polynomial in the form ax^2 + bx = c

Add 24 on both sides,

3w^2 - w - 24 + 24 = 24

⇒ 3w^2 - w = 24

Divide both sides by 3,

\(w^2-\frac{1}{3}w = 8\)

To complete the square x^2 + bx, we add \((\frac{b}{2} )^2\)

Here, b = -1/3

So, \((\frac{b}{2})^2 = (\frac{-1/3}{2})^2 = (-\frac{1}{6})^2 = \frac{1}{36}\)

Adding to both sides of the equation, we have

\(w^2-\frac{1}{3}w+\frac{1}{36} = 8+\frac{1}{36}\)

Hence, the number that will complete the square to solve an equation is 1/36.

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Answer: there is a 53.24 percent chance.

Step-by-step explanation: Add all of the candies and get 139. Then add 32 and 42 to get 74. Then subtract 74 from 139 and get 65. Finally, you find the percentage of 74/139 and get 53.24.

Using the rational zero test, the rational zeroes of the given functions are (A) ± 1, 2, 3, 6, 1/2, 3/2.

So, use the rational zero tests as follows:

Now, evaluate as follows:

Then, the rational zeroes will be:

Therefore, using the rational zero test, the rational zeroes of the given functions are (A) ± 1, 2, 3, 6, 1/2, 3/2.

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\(Angles\) \(that\) \(form\) \(a\) \(linear\) \(pair\) \(add\) \(up\) \(to\) \(180 degrees\).

If the measure of angle 1 is 113, then all we must do is subtract:

180-113=67 \(degrees\)

And we're done!

Good luck! :)

Hope it helps you!

\(GraceRosalia\) ✺                    ✺                      ✺          ✺              ✺             ✺          ✺

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below

\((\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{24}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{24}-\stackrel{y1}{8}}}{\underset{\textit{\large run}} {\underset{x_2}{3}-\underset{x_1}{1}}} \implies \cfrac{ 16 }{ 2 } \implies 8\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{ 8}(x-\stackrel{x_1}{1}) \\\\\\ y-8=8x-8\implies {\Large \begin{array}{llll} y=8x \end{array}}\)

Answer:

\(y=8x\)

Step-by-step explanation:

We can see that this line has a constant of proportionality. That is — x is proportional to y and vice versa. This means that the equation for the line's equation will be in the form:

\(y = mx\)

where \(m\) is the ratio of x to y.

This ratio is also known as the line's slope. We can solve for the slope using the equation:

slope = rise / run

slope = \(\Delta\)y / \(\Delta\)x

slope = 8 / 1

slope = 8

\(m=8\)

So, the equation of the line is:

\(y=mx\)

\(\boxed{y=8x}\)

Lines f and g look to be parallel to each other.

Answer:

Lines G and F

Step-by-step explanation:

Parallel means never touching, and they usually run alongside eachother, that's why G and F look parallel.

Please mark brainliest!

Answer:

1) 8x³ - x² + 1

2) 5a - 3b - 10c

3 17x²y - 7xy²

Step-by-step explanation:

Just combine like terms, since everything is adding, all you have to do is add everything with the same symbol. Make sure you watch for negatives so you know when to add or subtract you numbers!

Hope this helps!

The probability that the mean weight of the 17 fruits will be between 489 grams and 500 grams is approximately 0.0322 - 0.0322 = 0.0000 (rounded to four decimal places).

The probability that the mean weight of 17 randomly picked fruits falls between 489 grams and 500 grams can be calculated using the Central Limit Theorem.

The mean weight of the 17 fruits will follow a normal distribution with a mean equal to the population mean (494 grams) and a standard deviation equal to the population standard deviation divided by the square root of the sample size (√17).

First, we calculate the z-scores for the lower and upper bounds:

Lower z-score:

z_lower = (489 - 494) / (8 / √17)

Upper z-score:

z_upper = (500 - 494) / (8 / √17)

Then, we use a standard normal distribution table or a calculator to find the probabilities associated with these z-scores. The probability that the mean weight falls between 489 grams and 500 grams is equal to the difference between these two probabilities.

Let's calculate the probabilities:

z_lower = (489 - 494) / (8 / √17) ≈ -1.8409

z_upper = (500 - 494) / (8 / √17) ≈ 1.8409

Using a standard normal distribution table or a calculator, we find that the probability corresponding to z_lower is approximately 0.0322 and the probability corresponding to z_upper is also approximately 0.0322.

The problem presents a normal distribution of fruit weights, with a given mean of 494 grams and a standard deviation of 8 grams. When we randomly select a sample of 17 fruits, the mean weight of this sample will also follow a normal distribution. According to the Central Limit Theorem, as the sample size increases, the distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.

In this case, since the range is relatively narrow and the sample size is moderate, the probability of the mean weight falling between 489 grams and 500 grams is quite low, approximately 0.0000.

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