Answer: - Galaxies are composed of billions of stars.
- Earth and most of the other planets orbit the sun in nearly circular elliptical orbits.
- The sun is a star.
-The Milky Way is a spiral galaxy.
Explanation:
:)
The Milky Way is a spiral galaxy, the sun is a star, and Earth and most of the other planets orbit the sun in nearly circular elliptical orbits.
From the given options, the correct statements are:
The Milky Way is a spiral galaxy.The sun is a star.Earth and most of the other planets orbit the sun in nearly circular elliptical orbits.Clouds, filaments, and walls are structures within galaxies.Earth rotates around the sun, which is the reason we see the sun rise and set.Galaxies are composed of billions of stars.Therefore, the incorrect statements are: The sun is not part of the Milky Way.
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5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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Select the correct answer. What is the electron configuration of an element with atomic number 15? A. B. O C. O D. OE. 15² 25² 2p6 1s² 2s² 2p 3s² 3p5 1s² 25² 2p 3s² 3p³ 1s² 25² 2p 3s² 1s² 2s² 2p 3p³ 3s² 3p¹
The electron configuration of an element with atomic number 15 is 3s² 3p⁵.
What is electronic configuration?The electron configuration of an element with atomic number 15 (which corresponds to the element phosphorus) can be determined by following the Aufbau principle and the Pauli exclusion principle. The Aufbau principle states that electrons occupy the lowest energy levels available, while the Pauli exclusion principle states that each orbital can hold at most two electrons with opposite spins.
What is energy level of phosphorus?Starting with the first energy level, we fill in the electrons for each subsequent energy level until we reach the 15 electrons of phosphorus: 1s² 2s² 2p⁶ 3s² 3p⁵
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What is malleability and brittleness? How do they affect the physical changes in solid materials? 20 pts please!!!!!!!!!!!!!!!!!
Explanation:
malleability is the property of a material that has the ability to deform under compressive stress.
brittleness is when a material is subjected to stress and it fractures with little elastic deformation and without significant plastic deformation.
explain why sound wave travel faster in liquid than gas
Answer:
Because gas contains free molecules but not liquid.
Please mark as brainliast
3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).
The radii of the first five Fresnel zones is 3.6 mm.
Distance from the light source to the wave surface, d₁ = 1 m
Distance from the wave surface to the observation point, d₂ = 1 m.
Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm
The expression for the radius of the Fresnel zones is given by,
rₙ = √[nλd₁d₂/(d₁ + d₂)]
Therefore, the radii of the first five Fresnel zones is,
r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]
r₅ = √(25 x 10⁻⁶/2)
r₅ = 3.6 x 10⁻³m
r₅ = 3.6 mm
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I don’t understand what it’s asking me to do
Because the mass and displacement are already given in Kg and m, respectively, in the first part of your question, there is no need to convert them. However, in the second part of your question, you must use the given equation to calculate the spring constant.
if the table data is given in grams and cm you have to convert it using the following conversion,
1. To convert grams to kilograms, we divide the mass values by 1000.
2. To convert centimeters to meters, we divide the displacement values by 100.
But here in the given table it's already given the mass in kg and the displacement in meters (m). so no need to convert it.
Now comes the second part of your question,
To calculate the spring constants for the given data, we can use the equation:
k = -mg/Δx
where:
k is the spring constant (in N/m),
m is the mass (in kg), and
Δx is the displacement of the spring (in m).
Let's calculate the spring constants using the provided data:
Mass (kg): 0.05 0.1 0.2 0.3 0.4 0.5 0.6
Displacement of Spring (m): 0.012 0.027 0.065 0.1 0.135 0.17 0.199
Using the equation
k = -mg/Δx,
we can calculate the spring constant for each data point:
For the first data point (m = 0.05 kg, Δx = 0.012 m):
k = -0.05 kg * 9.8 m/s² / 0.012 m
k ≈ -40.833 N/m
Similarly, we can calculate the spring constants for the other data points:
For the mass of 0.05 kg, the spring constant is approximately -40.833 N/m.
For the mass of 0.1 kg, the spring constant is approximately -18.519 N/m.
For the mass of 0.2 kg, the spring constant is approximately -6.154 N/m.
For the mass of 0.3 kg, the spring constant is approximately -3.267 N/m.
For the mass of 0.4 kg, the spring constant is approximately -2.222 N/m.
For the mass of 0.5 kg, the spring constant is approximately -1.716 N/m.
For the mass of 0.6 kg, the spring constant is approximately -1.449 N/m.
Therefore, In the first part of the question, there is no need to convert the mass into kg and the displacement cm into m because it is already given in kg and m respectively, and in the second part question you have to calculate the spring constant using the given equation.
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A 75 kg person stands on a metric bathroom scale that reads in Newtons while in an elevator. The
elevator accelerates upward at 3 m/s/s. Determine the person's actual weight and the reading of the
scale under these conditions.
Answer: 735 N (actual), 960 N (accelerating up)
Explanation:
Actual weight = W = mg = (75 kg)(9.8 m/s²) = 735 N
Scale reading = N (normal force acting on the person by the elevator) = mg + ma = 735 N + (75 kg)(3.0 m/s²) = 735 N + 225 N = 960 N
That's why you feel heavier when you are accelerating up in an elevator
A 310 000 kg meteor is heading directly towards a space shuttle at 35 m/s. It is pushed for a period of 45 seconds after which its velocity is 27 m/s and it has veered 22° from its original course. a) Find the impulse given to the meteor (magnitude and direction). b) Find the magnitude of the force applied
( a ) The magnitude of the impulse given to the meteor is 2,480,000 kg.m/s at 22⁰ from original position.
( b ) The magnitude of the force applied to the meteor is 55,111.1 N.
What is the magnitude of the impulse?
The magnitude of the impulse given to the meteor is calculated from the change in momentum of the meteor.
Mathematically, the formula for Impulse is given as;
J = ΔP
J = m (vf - vi )
where;
m is the mass of the meteorvf is the final velocity of the meteorvi is the initial velocity of the meteorThe magnitude of the impulse given to the meteor is calculated as follows;
J = ( 310, 000 kg ) ( 27 m/s - 35 m/s )
J = ( 310, 000 kg ) ( -8 m/s )
J = -2,480,000 kg.m/s
| J | = 2,480,000 kg.m/s
The magnitude of the force applied to the meteor is calculated as follows;
F = ma = J / t
where;
J is the impulse experiencedt is the time of motionF = ( 2,480,000 kg.m/s ) / ( 45 s )
F = 55,111.1 N
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Magnets are usually made up of which material
A. plastic
B. iron ore
C. copper
D. gold
Answer:
B. iron ore
Explanation:
Hope this helps
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from the following properties, select the properties that are not classified as an intensive property. (check all that apply.)
Temperature, density, color, electric current, heating value, as well as other characteristics are all intense attributes since they are unaffected by changes in the size or quantity of the substance.
What intense property examples are there?A property of that is intensive depends solely on the type of matter in a sample and not on the quantity. Examples of intense qualities include color, temperature, and solubility.
Which of the aforementioned traits are intense traits?intense qualities. The rate of electron passage in a conductor is known as electric current. Intensive qualities are those that exist regardless of the quantity of a substance or substances in the system.
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Which location on Earth receives the most solar radiation in any given year?
The location on Earth that receives the most solar radiation in any given year is typically the Sahara Desert in Africa.
What location of the Earth receives most solar radiation?
The Sahara receives the highest levels of solar radiation due to its location near the equator and its clear, cloudless skies. The combination of these two factors allows for maximum exposure to the sun's rays, leading to high levels of solar radiation throughout the year.
However, it's worth noting that other areas near the equator, such as the regions in South America, also receive a high amount of solar radiation.
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Find weather X^N plus Y^N is divisible by X - Y (y not equal to 0) or not
The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).
To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.
The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.
Let's substitute X = Y into the expression:
\(Y^{N} + Y^{N}\)
Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:
2(\(Y^{N}\))
We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.
In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.
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A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs.
time t.
What is the instantaneous velocity of the crow at t = 9 s ?
A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.
What is the instantaneous velocity of the crow at t = 9 s?
Answer: -0.50 m/s
A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
From the figure, it shows that from t = 8sec to t = 12 sec the displacement is decreasing, so velocity will be the slope of the straight line.
The velocity is given by:
velocity = -Δx ÷ Δt
velocity = (-2) ÷ (12-8)
velocity = -2 ÷ 4
velocity = -0.5 m/s
Therefore, A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
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An automobile driver increasing the speed at a constant rate from 20 km/h to 46 km/h in 0.90 min. A bicycle rider speeds up at a
constant rate from rest to 26 km/h in 0.90 min. What are the magnitudes of (a) the driver's acceleration and (b) the rider's
acceleration?
(a) ?
(b) ?
a) The acceleration for an automobile driver is 22.23 m / s².
b) The acceleration for a bicycle rider will be zero.
What is acceleration?Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.
Given that An automobile driver increases the speed at a constant rate from 20 km/h to 46 km/h in 0.90 min. A bicycle rider speeds up at a constant rate from rest to 26 km/h in 0.90 min.
The acceleration for an automobile driver,
a = change in velocity / Time
a = ( 40 - 20 ) / 0.90
a = 22.23 m / s²
The acceleration of bicycle rider:-
a = change in velocity/time
a = ( 26 - 26 ) / 0.90
a = 0 m/s²
Hence, the acceleration for an automobile driver is 22.23 m / s² and he acceleration for a bicycle rider will be zero.
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Which of the following is a scientific question that can be answered through experimentation?
a. When looking at a map, you ask,c. When sitting with friends in class, you ask, "How
"How are the borders of
many protons does an atom of iron have?"
Germany determined?"
b. When talking to your teacher, d. When looking at a building, you ask, "Will the materials used
you ask, "What is the definition in this building withstand acid rain?"
of matter?"
\(\bold{Hello}\)~
\(\color{purple}\huge\bold\star \underline\mathcal{ \: Answer \: }\star \)
The answer should be B.)\(\bold\purple{Hopeithelps}\)
\(\bold{Study}\) \(\bold{Well}\) ~
What happens to the mechanical advantage of a machine if the output force is less than the input force? What must happen to output distance? Give an example of a machine that does this?
how many pennies can 4 folds of a paper hold?
Microwaves of wavelength 9.33 cm are incident on a narrow window that is 34.55 cm wide. If the far wall is 5.73 m away from the window, what is the distance from the central maximum to the first order minimum?
Given:
The wavelength of the microwave is
\(\begin{gathered} \lambda=9.33\text{ cm} \\ =9.33\times10^{-2}\text{ m} \end{gathered}\)The width of the window is,
\(\begin{gathered} a=34.55\text{ cm} \\ =34.55\times10^{-2}\text{ m} \end{gathered}\)The distance between the wall from the window is,
\(d=5.73\text{ m}\)To find:
the distance from the central maximum to the first order minimum
Explanation:
For destructive interference,
\(sin\theta=n\frac{\lambda}{a}\)Here, for the first order, minima n=1.
\(\begin{gathered} sin\theta=\frac{9.33\times10^{-2}}{34.55\times10^{-2}} \\ \theta=15.67\degree \end{gathered}\)The distance from the central maximum to the first order minimum is
\(\begin{gathered} y=dtan\theta \\ =5.73\times tan15.67\degree \\ =1.61\text{ m} \end{gathered}\)Hence, the required distance is 1.61 m.
An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward
with the horizontal.
What is the magnitude of the velocity when it hits the ground?
Answer:
Explanation:
Angle:
β = - 23°
( From the symmetry condition)
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
A. The average speed you can use to pull the safe is 1.02 m/s
B. The time needed to pull the safe up is 17.65 s
A. How do i determine the velocity?First, we shall obtain the force. This is shown below:
Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?F = mg
F = 60 × 9.8
F = 588 N
Finally, we shall obtain the average speed. Details below:
Power = 600 WForce = 588 NAverage speed =?Power = force × average speed
600 = 588 × average speed
Divide both sides by 588
Average speed = 600 / 588
Average speed = 1.02 m/s
B. How do i determine the time?The time needed to pull the safe up can be obtained as follow:
Average speed = 1.02 m/sTotal distance = 18 mTime = ?Time = Total distance / average speed
Time = 18 / 1.02
Time = 17.65 s
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Complete question:
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
Part B
What is the time needed to pull the safe up?
Calculate the energy changes corresponding to the transitions of the hydrogen atom. From n = 3 to n = ∞.
Answer: ΔE = -2.42 × 10^-19 J
Explanation:
The energy of an electron in the nth energy level of a hydrogen atom is given by the following formula:
E = (-2.18 × 10^-18 J) × (Z^2 / n^2)
where Z is the atomic number (1 for hydrogen) and n is the principal quantum number.
The energy change corresponding to a transition from energy level n1 to energy level n2 is given by the formula:
ΔE = E2 - E1 = (-2.18 × 10^-18 J) × Z^2 (1/n2^2 - 1/n1^2)
Given that the electron transitions from n = 3 to n = ∞, we can substitute n1 = 3 and n2 = ∞ in the above formula to obtain:
ΔE = (-2.18 × 10^-18 J) × 1^2 (1/∞^2 - 1/3^2)
ΔE = (-2.18 × 10^-18 J) × (1/9)
ΔE = -2.42 × 10^-19 J
Therefore, the energy change corresponding to the transition of the hydrogen atom from n = 3 to n = ∞ is -2.42 × 10^-19 J.
The energy change for the transition of a hydrogen atom from n = 3 to n = ∞ is 1.511 eV. This transition represents the electron moving to an energy level where it is essentially unbound from the nucleus, resulting in an energy increase.
The energy changes corresponding to the transitions of a hydrogen atom can be calculated using the formula for energy levels in hydrogen:
E = -13.6 eV * (Z² / n²)
Where:
E is the energy of the electron in electronvolts (eV).
Z is the atomic number, which is 1 for hydrogen.
n is the principal quantum number, representing the energy level.
Given the transition from n = 3 to n = ∞, we can calculate the energy change:
Calculate the initial energy (n = 3):
Einitial = -13.6 eV * (1² / 3²) = -13.6 eV * (1/9) = -1.511 eV
Calculate the final energy (n = ∞):
Efinal = -13.6 eV * (1² / ∞²)
In the final state, as n approaches infinity, the energy becomes zero.
Calculate the energy change (ΔE):
ΔE = Efinal - Einitial = 0 - (-1.511 eV) = 1.511 eV
So, the energy change corresponding to the transition of a hydrogen atom from n = 3 to n = ∞ is 1.511 electronvolts (eV).
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Write 3 paragraphs explaining conduction, convection, and radiation. The paragraph must include examples of each and explain the type of energy. It also must include conductors and insulators and various examples of each.
Answer:
Eeeeeeeeeeeeeeeeeeeeeeeeeee
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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PLS HELP!! This question was never fully solved!
An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg
To find the mass of the object, we can use the formula for kinetic energy:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:
mass = (2 * KE) / (velocity^2)
Substituting the given values:
mass = (2 * 426 J) / (13 m/s)^2
mass = (2 * 426 J) / (169 m^2/s^2)
mass = 852 J / 169 m^2/s^2
mass = 5.04 kg
Therefore, the mass of the object is 5.04 kg.
A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
Look at this model of an atom. Where are the protons located and how many are there?
Answer:
protons are in the nucleus .
Explanation:
there are 6 protons
A rigid body with a cylindrical cross-section is released from the top of a 26 deg incline. It rolls 10.9 m to the bottom in 3.06 s. Find the moment of inertia of the body in terms of its mass m and radius r. (Assume I is in kq * m ^ 2 , m is in kilograms, and r is in meters. Do not include units in your answer.)
The moment of inertia of a rigid body with a cylindrical cross-section is (m*\(r^2\))/2.5, where m is mass and r is radius.
Given data:
Inclination angle, θ = 26 degrees
Distance traveled, s = 10.9 m
Time taken, t = 3.06 s
The acceleration of the body can be found by analyzing its motion down the incline.
Since the body is rolling, we need to consider both translational and rotational motion.
The net force acting on the body is the component of its weight parallel to the incline. Therefore:
Fnet = mgsinθ
The force causes both translational and rotational acceleration. The translational acceleration can be found using Newton's second law:
Fnet = ma
Therefore,
a = Fnet/m = gsinθ
The rotational acceleration can be found using the torque equation:
τ = Iα
where τ is the torque, I is the moment of inertia, and α is the angular acceleration. The torque is provided by the force of friction acting on the body, and it is given by:
τ = Fr
where r is the radius of the body.
The force of friction can be found using the relationship between the translational and rotational acceleration:
a = αr
Therefore
Fr = ma = mgsinθ
Substituting α = a/r and τ = Fr, we get:
I(a/r) = mgsinθ
Substituting a = gsinθ, we get:
I = (m*\(r^2\))/2.5
Therefore, the moment of inertia of the body in terms of its mass m and radius r is I = (m*\(r^2\))/2.5.
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Find Density of a cylinder with diameter of 5.0 cm and height of 12.0cm and mass of 600.0g
Answer: 2.55 g/cm^3
Explanation:
density is defined as:
Density = mass/volume
Now, the mass of the cylinder is 600g
and the volume of a cylinder is:
V = pi*r^2*h
where r is the radius (half of the diameter), here r = (5/2)cm and h is the height, here 12 cm
So the volume is:
V = 3.14*(2.5cm)^2*12cm = 235.5cm^3
then the density is:
D = 600g/235.5cm^3 = 2.55 g/cm^3
please help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.
Row 1: Plate Boundary (Movement)
Write the type of plate boundary: convergent, divergent, transform.
Write the correct description for each in parentheses below the name: sliding, separating, or colliding.
Row 2: Diagram
Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.
Row 3: Lithosphere (Created or Destroyed)
Identify whether the Earth's crust is created or destroyed at this type of plate boundary.
Row 4: Geologic Process
Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.
Row 5: Real World Example
Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.
Row 6: References
This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.
Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.
Here are the steps to be followed:
Step 1: Understanding the Assignment Requirements
Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.
Step 2: Research
Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.
Step 3: Worksheet Setup
Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.
Step 4: Fill in Row 1 - Plate Boundary (Movement)
In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.
Step 5: Fill in Row 2 - Diagram
In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.
Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)
In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.
Step 7: Fill in Row 4 - Geologic Process
In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.
Step 8: Fill in Row 5 - Real World Example
In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.
Step 9: Fill in Row 6 - References
In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.
Step 10: Review and Proofread
Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.
Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.
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