you have a 10.g sample of c-13 atoms and another 10. g sample of c-12 atoms. which 10. g sample of carbon atoms contains more atoms?

Answer:

Explanation:

Insulin is an hormone used to regulate blood glucose, as it helps to maintain a balance. It allows for transport of glucose to organs such as liver.

The process of glucose regulation is a complex process. When food is eating glucose is absorbed into the bloodstream this happen from the gut and it raises the blood glucose level this causes insulin(hormone) to be released from the pancreas so glucose can move inside the cells and be used.

As glucose moves inside the cells, the glucose level inside the bloodstream returns to normal and insulin release slows down.

Glucose which is the main energy source used by cells is allowed to be taken up by muscles, liver and fat (adipose tissue) and use as a source of energy so they can function properly.

Answer:

c is the answer........

Answer:To calculate the concentration of the Fe(NO3)3 solution after dilution, we can use the formula:

Explanation:

C1V1 = C2V2

C1 = Initial concentration of the solution

V1 = Initial volume of the solution

C2 = Final concentration of the solution

V2 = Final volume of the solution

Initial concentration (C1) = 3.0 M

Initial volume (V1) = 80 mL

Final volume (V2) = 1500 mL

Using the formula, we can solve for C2:

C1V1 = C2V2

(3.0 M)(80 mL) = C2(1500 mL)

Rearranging the equation to solve for C2:

C2 = (C1V1) / V2

C2 = (3.0 M)(80 mL) / 1500 mL

C2 ≈ 0.16 M

Therefore, the concentration of the Fe(NO3)3 solution after dilution is approximately 0.16 M.

we have an initial solution of Fe(NO3)3 with a concentration of 3.0 M and a volume of 80 mL. The goal is to dilute this solution to a final volume of 1500 mL and determine the concentration of the diluted solution.

To do this, we can use the dilution formula: C1V1 = C2V2, where C1 and V1 represent the initial concentration and volume, and C2 and V2 represent the final concentration and volume.

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Answer:

The clear liquid is less dense than the black liquid, which is why it floats on top. If the volume were different, you would visually see more clear liquid than black and vice versa.

The clear liquid is less dense than the black liquid

Answer:

A. The clear liquid is less dense than the black liquid

Explanation:

Since the clear liquid since on top of the black one it's density is less. Whatever liquid has a higher density will sink to the bottom of the flask.

Answer:

539.3mmHg of H₂

179.7mmHg of N₂

Explanation:

Ammonia, NH₃, reacts completely producing N₂ and H₂ thus:

2 NH₃ → N₂ + 3H₂

That means there are produced 4 moles of gases and 3 are of H₂ and 1 of N₂

Total pressure (Sum of pressures of N₂ and H₂) is 719mmHg. 3 parts are of H₂ and 1 of H₂

Thus, partial pressures of the products after reaction are:

719mmHg ₓ (3 H₂ / 4) = 539.3mmHg of H₂

719mmHg ₓ (1 N₂ / 4) = 179.7mmHg of N₂

Answer:

we make water dirty

Explanation:

The cycloalkanes with a molecular formula C6H12 that have a 4-membered ring and one substituent are cyclobutane and its derivatives.

Cyclobutane is a cyclic hydrocarbon with a 4-membered ring. It consists of four carbon atoms and has the molecular formula C4H8. By adding two additional hydrogen atoms to each carbon atom, we can obtain cyclobutane with a molecular formula of C6H12. Cyclobutane can have various substituents attached to the carbon atoms of the ring, resulting in different derivatives of cyclobutane. These derivatives can include different functional groups or other hydrocarbon chains or groups.

The presence of a 4-membered ring in cyclobutane makes it a unique cycloalkane, and when one substituent is added to this ring, it forms a cyclobutane derivative. The specific nature of the substituent can vary, resulting in different compounds with diverse properties and reactivity.

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Answer:

Addition polymers are formed when monomer units join each other in a process that involves the rearranging of electrons in double or triple bonds in the monomer. The polymer is the ONLY product formed.

EX:C=C + C=C + C=C - ·C-C-C-C-C-C·

Ethene(ethylene) monomers -> part of polyethene

Explanation:

Answer:

2Al +3Fe(NO3)2 --------> 3Fe + 2Al(NO3)3

In the above reaction Aluminum and iron nitrate reacts to produce iron metal and aluminum nitrate so aluminum is replace by iron

Answer:

Iron is oxidized to form rust.

Explanation:

Consider the reaction; 4Fe + 302------>2Fe2O3, we can see that iron is being oxidized to iron III oxide. Rust is the common name of iron III oxide.

Rusting is an electrochemical process, iron rusts when it comes into contact with air and water because electrochemical cells are set up at the surface of contact.

Iron usually functions as the anode in the electrochemical process. This process leads to the formation of iron III oxide. Rust is soft and breaks off easily thereby exposing the metal below the surface to further rusting.

Answer:

Iron is oxidized to form rust.

Explanation:

edge

The half-life T1/2 of the isotope is approximately 1.87 days.

The half-life T1/2 of the isotope in question, with a decay rate that decreases from 8335 decays per minute to 3105 decays per minute over 5.00 days, can be determined using the formula

T1/2 = tln(2) / ln(N₀/N),  where

t represents the elapsed time,

N₀ is the initial number of undecayed nuclei, and

N is the final number of undecayed nuclei.

Given:

t = 5.00 days

N₀ = 8335 decays per minute

N = 3105 decays per minute

Substituting the given values into the formula, we obtain:

T1/2 = 5.00ln(2) / ln(8335/3105)

Evaluating the equation, we find:

T1/2 ≈ 1.87 days (rounded to three significant figures)

Hence, the half-life T1/2 of the isotope is approximately 1.87 days.


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The minimum volume of 0.2M sodium sulfide that will precipitate out aluminum from 50.0 mL, 0.25 M aluminum nitrate would be 0.094 L or 94 mL

From the equation of the reaction:

\(2Al(NO_3)_3 + 3Na_2S ---> Al_2S_3 + 6NaNO_3\)

Mole ratio of Na2S and Al(NO3)3 = 3:2

Mole of 50.0 mL, 0.25 M Al(NO3)3 = 50/1000 x 0.25

                                                         = 0.0125 mole

Equivalent mole of Na2S = 3/2 x 0.0125

                                         = 0.0188 mole

Volume of 0.2M, 0.0188 mole Na2S = 0.0188/0.2

                                                          = 0.094 L or 94 mL

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Equilibrium constant K for the reaction can be written as,

   K = [C]c  [D]d / [A]a  [B]b

In the absence of oxygen, cells cannot carry out their biochemical responsibilities. Oxygen moves to the cells attached to hemoglobin. Equilibrium constant is the value of its reaction quotient. The equilibrium constant, K, expresses the relationship between products and reactants of a reaction at equilibrium with respect to a specific unit. The equilibrium constant K is the ratio of the mathematical product of the concentrations of the products of a reaction to the mathematical product of the concentrations of the reactants of the reaction. protein hemoglobin which binds oxygen in your lungs and carries it to other tissues of your body. hemoglobin bind oxygen tightly so that a large fraction of the hemoglobin will pick up an oxygen before cycling back through the other tissues. However, in the other tissues, one wants hemoglobin to bind oxygen loosely so that it can be easily relinquished for use in respiration. Each concentration is raised to the power of its coefficient in the balanced chemical equation.

suppose a general reaction written,

              aA + bB--->  cC + dD

For the reaction equilibrium constant can be written as,

             Keq = [C]c  [D]d / [A]a  [B]b

The reaction of equilibrium of hemoglobin is,

    Hb(CO)4 + 4O2  ⇌  Hb(O2)4 + 4CO

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Answer:

107.5 amu

Explanation:

isotopes:                                                                     fractional      Wt Avg

           isotopes: isotopic mass   %Abundance      abundance      (amu)    

              X110              110                          60                0.60            66.0

             X105              105                         30                0.30             31.5

             X100              100                         10                 0.10             10.0

                                                      ∑ atm mass contributions      =    107.5 amu*

*amu = atomic mass units

There are approximately 3.04 moles of nitrogen gas (N2) contained in the airbag.

To calculate the number of moles of nitrogen gas (N2) in the airbag, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure of the gas (in atm)

V = volume of the gas (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature of the gas (in Kelvin)

First, we need to convert the given temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 25°C + 273.15

T(K) = 298.15 K

Now, we can rearrange the ideal gas law equation to solve for n:

n = PV / (RT)

Substituting the given values:

P = 1.09 atm

V = 65 L

R = 0.0821 L·atm/(mol·K)

T = 298.15 K

n = (1.09 atm)(65 L) / ((0.0821 L·atm/(mol·K))(298.15 K))

n ≈ 3.04 moles

Therefore, there are approximately 3.04 moles of nitrogen gas (N2) contained in the airbag.

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Answer:

1. 254 milli

2. 5.3 centi

Explanation:

254 milli = 25.4 centi

53 milli = 5.3 centi

Answer:

a

Explanation:

The heat capacity of a substance is the heat energy required to rise its temperature per one degree Celsius. Hence its unit is J/°C.

Heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius or 1 Kelvin. It is expressed in the following units:

Joules per degree Celsius (J/°C)

Joules per Kelvin (J/K)

Calories per degree Celsius (cal/°C)

Calories per Kelvin (cal/K)

Joules per gram per degree Celsius (J/(g·°C))

Joules per gram per Kelvin (J/(g·K)) etc.

If in terms of simply the energy, then, The following units are used.

Joules (J) , Calories (cal) , Degrees Celsius (°C), Kelvin (K)

The choice of unit depends on the specific application and the system of units being used. The SI unit for heat capacity is J/K, while the traditional unit is cal/°C.

The use of per gram units is common in the context of specific heat capacity, which is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius or 1 Kelvin.

Therefore, here, the unit of heat capacity is J/°C.

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The third quantum number (m_l) of a 3s² electron in phosphorus is 0.

The third quantum number, denoted as m_l, represents the magnetic quantum number and describes the orientation of an orbital within a subshell. It can have integer values ranging from -l to +l, where l is the azimuthal quantum number.

In the electron configuration of phosphorus, we see that the 3s subshell is being filled. The azimuthal quantum number (l) for the 3s subshell is 0. Since the electron is in the 3s² subshell, there are two electrons present in the 3s orbital.

For the two electrons in the 3s orbital, they will have opposite spins due to the Pauli exclusion principle. However, the magnetic quantum number (m_l) for both electrons in the 3s orbital will be the same, which is 0.

Therefore, the third quantum number (m_l) of a 3s² electron in phosphorus is 0. This means that both electrons in the 3s orbital have the same orientation within the subshell.

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A lunar eclipse can be photographed sometimes when Earth is in between the sun and the Moon.

A lunar eclipse occurs when the Sun, Earth, and Moon align in the same line in which the Moon passes into Earth's shadow. In a total lunar eclipse, the entire Moon falls within the darkest part of Earth's shadow, called the umbra so we can conclude that claim 2  is the right answer about lunar eclipse.

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In 1867, Otto von Bismarck created the Northern Confederation, a combination of the northernmost German states beneath Prussian rule.

The "Iron Chancellor," Otto von Bismarck (1815–1898), oversaw the unification and modernization of Germany. He virtually ruled Prussia and then all of Germany between 1862 until 1890. To unify the 39 autonomous German states under Prussian control, great strategist Bismarck launched decisive wars with France, Austria, & Denmark.

In 1864, Bismarck began the series of wars that'd make Prussia the most powerful country in Europe. He invaded Denmark to seize control of the German-speaking province of Schleswig-Holstein, and two years later he persuaded Emperor Franz-Josef I to start the Austria- War (1866), which brought about an immediate defeat for the faltering Austrian empire.

Thus, on 1867, Otto von Bismarck created the Northern Confederation, a combination of the northernmost German states beneath Prussian rule.

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For a mineral that contains 50% of its original K-40, the statements which are true are option (a) Mineral Age = 50% of 1.25 b.y. - 0.625 b.y. and option (d) The percentage of Ar-40 atoms inside the mineral is reduced with time.

Potassium-40 (K-40) decays to Argon-40 (Ar-40) with a half-life of 1.25 billion years. For a mineral that contains 50% of its original K-40, the statements which are true :

a) Mineral Age = 50% of 1.25 b.y. - 0.625 b.y. - This statement is true. The age of the mineral is half the half-life of K-40 which equals 0.625 billion years.

b) Mineral Age = 1.25 by. X 1 elapsed half-life = 1.25 by. - This statement is false because the mineral contains only 50% of the original K-40.

c) The percentage of K-40 atoms inside the mineral increases with time. This statement is false because K-40 decays to Ar-40 with time.

d) The percentage of Ar-40 atoms inside the mineral is reduced with time. This statement is true because K-40 decays to Ar-40 with time. As K-40 decays, the percentage of Ar-40 atoms inside the mineral increases.

Thus, the statements which are true are option (a) Mineral Age = 50% of 1.25 b.y. - 0.625 b.y. and option (d) The percentage of Ar-40 atoms inside the mineral is reduced with time.

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Answer: I learned that almost every technology has radio waves that spread out from their sources.

Explanation:

Answer:

Acids react with most metals.

When an acid reacts with a metal, the products are a salt and hydrogen.

This is the general word equation for the reaction: metal + acid → salt + hydrogen

Explanation:

Decreasing the TBCl concentration will not affect the rate constant in this experiment. The rate constant is determined by the specific reaction and temperature conditions and is independent of the reactant concentrations.

The rate constant (k) is a proportionality constant that relates the rate of a reaction to the concentrations of the reactants. However, the rate constant itself is not affected by the concentrations of the reactants. It is determined by the specific reaction and temperature conditions.

The rate of a chemical reaction can be expressed using the rate equation, which typically includes the concentration terms for the reactants raised to certain powers.

These powers, known as reaction orders, can be determined experimentally. However, the rate constant is a separate factor in the rate equation and is not dependent on the reactant concentrations.

By decreasing the TBCl concentration, the rate of the reaction may be affected, as the rate is directly proportional to the reactant concentrations.

However, the rate constant itself remains unchanged. The rate constant is influenced by factors such as temperature, presence of catalysts, and the nature of the reacting species, but not by the concentrations of the reactants.

Therefore, decreasing the TBCl concentration will not affect the rate constant in this experiment.

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The oxidation half-reaction is Cl_{2} → 2Cl- + 2e- and the reduction half-reaction is 2K+ + 2e- → 2K. These two half-reactions can be combined to give the balanced redox reaction.

In this redox reaction, chlorine gas (Cl_{2}) is reacting with potassium (K) to form potassium chloride (KCl). To balance the reaction, we need to identify the oxidation and reduction half-reactions.
The oxidation half-reaction involves the loss of electrons, and in this case, chlorine is being oxidized. The equation for this half-reaction is:
Cl_{2} → 2Cl- + 2e-
Here, each chlorine molecule (Cl_{2}) is being reduced to two chloride ions (Cl-) by losing two electrons (2e-).
The reduction half-reaction involves the gain of electrons, and in this case, potassium is being reduced. The equation for this half-reaction is:
2K+ + 2e- → 2K
Here, each potassium ion (K+) is being reduced by gaining two electrons (2e-) to form a neutral potassium atom (K).
By adding these two half-reactions together, we get the balanced redox reaction:
Cl_{2} + 2K → 2KCl
In summary, the oxidation half-reaction is Cl_{2} → 2Cl- + 2e- and the reduction half-reaction is 2K+ + 2e- → 2K. These two half-reactions can be combined to give the balanced redox reaction.

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complete question: Separate this redox reaction into its balanced component half‑reactions. Use the symbol e− for an electron. Cl_{2}+2K⟶2KCl

oxidation half-reaction:

reduction half-reaction:

The pH of the solution is determined by the amount of acid or base present in the solution. pH is a measure of the acidity or alkalinity of a solution, with a range of values from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydrogen ion concentration (H+) in the solution

The pH of a solution of 0.080 m trimethylamine and 0.13 m trimethylammonium chloride can be calculated using the following equation:

Kb = [CH3)3N][H2O] / [(CH3)3NH+][OH-]

where Kb is the base dissociation constant of trimethylamine, (CH3)3N. Using the relationship that Kw = Ka × Kb, where Ka is the acid dissociation constant of water (1.0 × 10-14 at 25 °C), the OH- ion concentration of the solution can be found to be 1.23 × 10-5 M. Then, since Kw = [H+][OH-], the H+ ion concentration is found to be 8.12 × 10-10 M. Finally, taking the negative logarithm of the H+ ion concentration gives a pH of 9.09. When a solution is introduced to water, it can either react with the water to form acid or base.

The pH of the solution is determined by the amount of acid or base present in the solution. pH is a measure of the acidity or alkalinity of a solution, with a range of values from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydrogen ion concentration (H+) in the solution. The pH of the solution can be calculated using the pH formula, which is: pH = -log [H+], where [H+] is the concentration of hydrogen ions in the solution. The given solution is composed of 0.080 m trimethylamine and 0.13 m trimethylammonium chloride. Trimethylamine is a weak base and trimethylammonium chloride is its corresponding conjugate acid. When a weak base is added to water, it undergoes a reaction with water to produce hydroxide ions and a conjugate acid.

The base dissociation constant of trimethylamine, Kb is used to find the OH- ion concentration of the solution. The relationship between Kb and Ka is given by Kw = Ka × Kb, where Ka is the acid dissociation constant of water (1.0 × 10-14 at 25 °C).The OH- ion concentration of the solution can be found to be 1.23 × 10-5 M. Then, since Kw = [H+][OH-], the H+ ion concentration is found to be 8.12 × 10-10 M. Finally, taking the negative logarithm of the H+ ion concentration gives a pH of 9.09.

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The volume of the gas is 1.27 L at a temperature is 47°C and the pressure is 5.0 atm. Therefore, option (B) is correct.

The ideal gas equation is described as the equation of the state of a perfect gas. The ideal gas equation is the product of the pressure and volume of one-mole gas is equal to the multiplication of the absolute temperature and gas constant.

The mathematical equation for a perfect gas is as follows:

PV = nRT

where n is the moles of an ideal gas, P is the pressure of the gas,  V is the volume, and R is the universal gas constant.

Given, the initial volume of the gas, V₁ = 2.0 L

The initial temperature of the gas, T₁ =  27° C = 300.15 K

The initial pressure of the gas, P₁ = 3.0 atm

The final temperature of the gas, T₂ =  47° C = 320.15 K

The initial pressure of the gas, P₂ = 5.0 atm

We know that for an ideal gas:

\(\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}\)

\(V_2=\frac{P_1V_1T_2}{T_1P_2}\)

\(V_2= \frac{3.0\times2.0\times320.15}{5.0\times 300.15}\)

\(V_2= 1.27 L\)

Therefore, the volume of the gas in its final state is equal to 1.27 L when the gas is heated to 47ºC and compressed to 5.0 atm.

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The approximate bond angle for the H-C-H bond in CH3OH is approximately 109.5 degrees. In CH3OH, the central atom is carbon and it is surrounded by four other atoms - three hydrogens and one oxygen.

The molecular shape of CH3OH is tetrahedral, with the carbon atom at the center and the three hydrogens and one oxygen atom bonded to it. The H-C-H bond angles in CH3OH are approximately 109.5 degrees, which is the ideal bond angle for a tetrahedral shape. This is because the four electron pairs around the central carbon atom repel each other, and the molecule takes a shape that minimizes this repulsion. However, the H-O-H bond angle in CH3OH is slightly less than 109.5 degrees, at around 104.5 degrees. This is due to the lone pairs of electrons on the oxygen atom, which repel the bonding pairs of electrons and cause the H-O-H bond angle to deviate from the ideal tetrahedral angle. The bond angles in CH3OH are determined by the molecular shape and the repulsion between electron pairs. The H-C-H bond angles are approximately 109.5 degrees.

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