You hang from a tree branch, then let go and fall toward the Earth. As you fall, the y component of your momentum, which was originally zero, becomes large and negative. (a) Choose yourself as the system. There must be an object in the surroundings whose y momentum must become equally large, and positive. What object is this? (b) Choose yourself and the Earth as the system. The y component of your momentum is changing. Does the total momentum of the system change? Why or why not?

The magnitude of the rocket's acceleration is 12.5 m/s².To find the magnitude of the rocket's acceleration, we can use the equation of motion: \(v^2 = u^2 + 2as\)

The above equation has  v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Rearranging the equation, we have \(a = (v^2 - u^2) / (2s)\).Given that the initial velocity (u) is 20.0 m/s, the final velocity (v) is 30.0 m/s, and the distance traveled (s) is 40.0 m, we can substitute these values into the equation:

a = (30.0² - 20.0²) / (2 * 40.0)

= (900 - 400) / 80

= 500 / 80

= 6.25 m/s².

Therefore, the magnitude of the rocket's acceleration is 6.25 m/s².

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Answer:

5v

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

A trumpet creates a sound intensity level of 1.14 102 db at a distance of 2 m, the sound intensity of a trumpet at this distance is 4.89×10^-4 W/m2.

The sound intensity of a trumpet at a distance of 2m is 4.89×10^-4 W/m2. Sound intensity, which is the sound energy produced per unit time and per unit area, is measured in watts per square meter (W/m2). The formula for sound intensity is I = P/A, where I is sound intensity, P is sound power, and A is area. Sound intensity level (SIL) is another metric used to describe sound.

The formula for SIL is SIL = 10 log(I/I₀), where I₀ is the threshold of hearing, which is 1.00×10^-12 W/m2.

The sound intensity level produced by the trumpet at a distance of 2m is 102 dB.

Therefore, we can use the following formula to determine the sound intensity of the trumpet at this distance: I = I₀ 10^(SIL/10).

Substituting the values, we get:I = (1.00×10^-12 W/m2) 10^(102/10)I = 4.89×10^-4 W/m2

Therefore, the sound intensity of the trumpet at a distance of 2m is 4.89×10^-4 W/m2.

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Answer:

Metal

Explanation:

Just answered on Apex

Metal is the material will heat up the most quickly if placed near a heat source. Option D is correct.

The movement of energy from a hot to a cold item is characterized as heat. Heat energy flows from a hot material to a cold one.

This occurs because faster-vibrating molecules transmit their energy to slower-vibrating ones. Heat content is another name for vibrational energy.

It is hot or chilly depending on how much heat is there in the body. The body will be hotter as the heat content increases. The movement of energy from a hot to a cold item is characterized as heat.

The heat flow in the material is due to the free electrons. In the metal, no of free electron is highest. Metal is the material will heat up the most quickly if placed near a heat source.

Hence, option D is correct.

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The new frequency of rotation of the neutron star would be approximately 7 x 10^8 revolutions per day.

The conservation of angular momentum states that the product of the moment of inertia and angular velocity remains constant as long as there are no external torques acting on the system.

In this case, the star's collapse does not involve any external torques, so we can assume that the star's angular momentum is conserved.

The moment of inertia of a rotating object depends on its mass distribution and radius. The moment of inertia for a solid sphere is (2/5) * m * r^2, where m is the mass and r is the radius.

Initially, the star has a radius of 7 x 10^5 km and rotates once every 100 days. The new radius of the neutron star is 10 km. Therefore, the moment of inertia of the neutron star can be approximated as (2/5) * m * (10 km)^2, where m is the mass of the neutron star.

To find the new frequency of rotation, we can use the conservation of angular momentum. The initial angular momentum L1 of the star is equal to the final angular momentum L2 of the neutron star:

L1 = L2

The initial angular momentum is given by:

L1 = I1 * w1

where I1 is the moment of inertia of the original star and w1 is its initial angular velocity.

The final angular momentum is given by:

L2 = I2 * w2

where I2 is the moment of inertia of the neutron star and w2 is its final angular velocity.

Since angular momentum is conserved, we can set these two expressions equal to each other:

I1 * w1 = I2 * w2

Substituting the expressions for I1 and I2, we get:

(2/5) * m * (7 x 10^5 km)^2 * w1 = (2/5) * m * (10 km)^2 * w2

Simplifying and solving for w2, we get:

w2 = w1 * (7 x 10^5 km)^2 / (10 km)^2

w2 = w1 * (7 x 10^10)

Substituting the values given in the problem, we get:

w2 = (1 revolution / 100 days) * (7 x 10^10)

w2 = 7 x 10^8 revolutions per day

Therefore, the new frequency of rotation of the neutron star would be approximately 7 x 10^8 revolutions per day.

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At the lowest point of her swing, she can withstand a maximum speed of 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body,

F = mv²/r = (61.7× v²)/11.5 = 5.37 v²

Gravitational force acting on her is

F = m × g = 61.7 × 9.81 = 605.28 N

By summing up gravitational and centripetal forces to get the total available force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Hence, the maximum speed at the low point of her swing is 10.78 m/s.

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Hello!

a = 3 m/s²

Use the equation F = m · a (Newton's Second Law) to solve.

We are given the force and mass, so plug these values into the equation:

60 = 20 · a

60 = 20a

Divide both sides by 20:

60/20 = 20a/20

a = 3 m/s²

Then the separation between the two pennies will be O.354m.

To find the correct answer, we need to know about the electrostatic force of attraction.

                 \(m=3*10^{-3}kg\\n=4*10^{12}\\\)

                 \(Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1\)

                    \(F_e=\frac{kQ_1Q_2}{r^2} =mg\\\) , here given that the electrostatic force equal to the weight of the system.

                  \(r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m\)

Thus, we can conclude that the separation between the pennies is 0.354m.

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0.354m will be the separation between the two pennies.

We must understand the electrostatic force of attraction in order to arrive at the correct solution.

                  \(Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1\)

                      \(F=\frac{kQ_1Q_2}{R^2}=mg\)

Given that the electrostatic force in this instance is equal to the system's weight.

                    \(R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m\)

As a result, we may say that the distance between the pennies is 0.354m.

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The cart's increased speed is the same as when it first took off.

Rate is the speed from which an object travels along a path over time, whereas velocity is the speed and orientation of an item's motion.

At first, the cart is at rest.

So, u = 0 m/s.

A brief period of time is spent with a constant force applied.

The final speed that the force gives the cart is what we'll call v.

Newton's first equation of motion yields the following results:

v = u + at

Where;

The ultimate speed =v.

The starting speed =u.

Acceleration = a.

Time = t

u = 0 m/s, therefore we now have;

v = 0 + at

v = at

Let's now use Newton's second rule of motion to construct a formula to introduce force;

F = ma

Where;

Force = f.

Mass = m.

Acceleration = a.

So,

= a = F/m.

Substituting in v = at,

= v = (F/m)t

The final speed, v, is evidently exactly related to the force. So, if the force is constant, the end speed will also stay constant.

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The complete question is -

A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the cart a certain final speed. Suppose we repeat the experiment but, instead of starting from rest, the cart is already moving with constant speed in the direction of the force at the moment we begin to apply the force.

After we exert the same constant force for the same short time interval, the increase in the cart's speed:

A. is equal to two times its initial speed.

B. is equal to the square of its initial speed.

C. is equal to four times its initial speed.

D. is the same as when it started from rest.

E. cannot be determined from the information provided.

Answer:

Find two boxes just a bit smaller than the other. The long sides of the box should be less than twice as long as the short side of the boxes. The smaller box should fit inside the larger box with about 1 inch in each direction to spare. The boxes can be cut down so that they fit together properly. Leave the flaps on the boxes. Buy a small sheet of Plexiglas (tm) a little bit smaller than the width and length of the top of the box. You will also need four pieces of cardboard to use for reflectors.

Explanation:

Answer:

You build up kinetic energy and you get shocked this happens because static has built up from the socks and the rug. This also happens when you rub a balloon on your head or shuffle across a trampoline with socks on.

Explanation:

brainliest plz

The noise level is I=1029 I=log2 times over the threshold of human hearing.

Logarithmic scales are used to measure decibels. This is a method of accounting for or measuring an exponentially growing quantity. For instance, every 10 dB increase in decibels corresponds to a 10-fold increase in sound pressure level (SPL).

The formula for sound speed is vw=f, where f is sound frequency and is sound wavelength. The distance between adjacent, identical wave components, such as between adjacent compressions, determines a sound's wavelength.

The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.

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a) The charge on the capacitor at time t is given by:

\(Q(t) = Q0 * e^( -t/RC)\)

b) Q(t) is the charge on the capacitor and C is the capacitance of the capacitor.

(a) If the initial charge on the capacitor is Q0 and the initial current is Q0, then the charge on the capacitor at time t is given by:

\(Q(t) = Q0 * e^( -t/RC)\)

where e is the base of the natural logarithm, t is time, R is the resistance of the circuit, and C is the capacitance.

Since the resistance of the circuit is zero, the charge on the capacitor and the current in the circuit satisfy the differential equation at t = 0:

\(dQ/dt = Q0 * e^( -t/RC)\)

Substituting t = 0 into this equation gives:

\(dQ/dt = Q0 * e^( -0/RC) = Q0\)

Therefore, the charge on the capacitor at time t is given by:

\(Q(t) = Q0 * e^( -t/RC)\)

(b) If the capacitor is initially charged to Q0 and the current is initially Q0, then the charge on the capacitor at time t is given by:

\(Q(t) = Q0 * e^( -t/RC)\)

where e is the base of the natural logarithm, t is time, R is the resistance of the circuit, and C is the capacitance.

Since the resistance of the circuit is zero, the charge on the capacitor and the current in the circuit satisfy the differential equation at t = 0:

\(dQ/dt = Q0 * e^( -t/RC)\)

Substituting t = 0 into this equation gives:

\(dQ/dt = Q0 * e^( -0/RC) = Q0\)

Therefore, the charge on the capacitor at time t is given by:

\(Q(t) = Q0 * e^( -t/RC)\)

Since the current in the circuit is given by the charge on the capacitor, the current in the circuit at time t is given by:

I(t) = Q(t)/C

where C is the capacitance of the capacitor.

Therefore, the current in the circuit at time t is given by:

I(t) = Q(t)/C

where Q(t) is the charge on the capacitor and C is the capacitance of the capacitor.  

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Full Question: oblem concerns the electric circuit shown in the figure below. pt) T his p Capacitor Resistor Inductor A charged capacitor connected to an inductor causes a current to flow through the inductor until the capacitor is fully discharged. The current in the inductor, in turn, charges up the capacitor until the capacitor is fully charged again. Q(t) is the charge on the capacitor at me t and 11 is the current, then dQ dt If the circuit resistance is zero, then the charge Q and the cument in the circuit satisfy the differential equation at C where Cis the capacitance and Ll is the inductance, so Then, just as as a spring can have a damping force which affects its motion, so can a circuit; his is introduced by the resistor, so that if the resistance of the resistor is R, d Q dQ dt C IfL 1 henry, R ohm and C 25 farads. d a formula for the charge when (a) Q(0) and Q (0) Q(t) b) Q(0) and Q (0) Q(t)

An important safety measure when we go out on a wild life encounter is to stay away from food and water sources of the wild animals.

Wild life encounters simply means times when we go into the wild to see wild animals and to understand the wild life ecosystem. This of course poses a lot of risk.

While on a wild life encounter, one of the safety measures is to stay away from food and water sources.

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Answer:

C

Explanation:

Stay away from food and water sources

Answer:

Y

Explanation:

the net force on y is 45 +35 = 75 N [right]

When atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.

Atoms can combine with each other through sharing of the electrons, donating the electrons etc. to make molecules.

When atoms combine by forming covalent bonds, the resulting collection of atoms is called a molecule. We can therefore say that a molecule is the simplest unit of a covalent compound.

Thus, when atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.

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The orbital radius is 2.7 au for an asteroid orbiting the Sun had an orbital period of 7.5 years. Option e is the correct answer.

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

\(\sqrt{\dfrac{4 \pi^2 r^3}{Gm}}\)

Where,

π = 3.14

G is the gravitational constant = \(6.67 \times 10^{-11}\ m^3/(kgs^2)\)

M is the mass of the sun = \(1.989 \times 10^{30}\ kg\)

r is the radius, which we want to find.

T is given to be 7.5 years,

Rewriting the equation for the radius we get,

\(r = \sqrt[3]{\dfrac{(2.3655 \times 10^8)^2 \times 6.67 \times 10^{-11} \times 1.989 \times 10^{30}}{4 \pi^2}}\)

So the orbital radius is,

\(4.29 \times 10^{11}\ m\)

= 2.7 AU

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Answer:

35/9 m/s

Explanation:

21 km = 21000 m

90 min = 90*60 s = 5400 s

21000/5400 = 35/9 m/s

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

Answer:

a low protein diet helps you lose weight because lack of protein can make you lose muscle mass

Explanation:

It cuts your strength it makes it harder to keep your balance and slows your metabolism and later you get tired easily it leads to muscle wasting overtime and sheds your fat

Answer:

Work is calculated as the force multiplied by the displacement in the force's direction. Work is defined as force times a displacement in the force's direction.

Answer:

W i think but i think it's W

Explanation:

The car can take this curve without skidding to the outside of the curve with a speed of 23.47 m/s.

Given that,

Radius of the track r = 44 m

Inclination θ = 16°

Mass of car m = 1563 kg

Coefficient of kinetic friction μ = 0.72

By analysing the free body diagram, we get,

N cos θ - fr - m g = 0  ----(1)

where, N is normal reaction

fr is friction

N cos θ + fr cos θ = mv²/r  ----(2)

fr = μ N ----(3)

From (1), (2) and (3) we get maximum velocity without skidding as,

v = √(g r ) × √( tanθ +μ )/(1 - μ tanθ) = √(9.8× 44 ) ×√( tan 16°+ 0.72)/(1 - 0.72 tan 16°) = 20.77 × √1.007/0.79 = 20.77 × 1.13 = 23.47 m/s

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Kepler's laws demonstrate how gravity affects orbits. They pertain to any orbiting object, such as planets around the Sun and moons.

Our planet is subject to incredibly significant impacts from the sun: By photosynthesis, it supports seasons, climate, ocean currents, weather, and plant life. Life on Earth just wouldn't live without the heat and light provided by the sun. The solar system's centre is where the sun is located. The sun is a sizable ball of hot gases that spins and glows.

A liquid will expand in order to fill a closed container while inside of it. The air you inhale is an example of a gas. When applied to matter, the word "gas" can also refer to the state.

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The man's resultant velocity is

8.5 m/s up .

The rate at which the radius increases when the radius is 6 cm is approximately 0.056 cm/s.

To determine how fast the radius increases, we can use the given information about the volume of a cylinder and its rate of change. The volume of a cylinder is given by the formula v = πR²H, where R represents the radius and H represents the height.

Given that the radius is three times the height, we can express the height as H = R/3. Substituting this value into the volume equation, we have v = πR²(R/3). Simplifying further, the volume equation becomes v = (π/3)R³.

Now, we are given that the volume increases at a rate of 10 cm/s. By taking the derivative of the volume equation with respect to time, we can determine how the radius changes over time. The derivative, dv/dt, is equal to (π/3)(3R²)(dR/dt), where dR/dt represents the rate of change of the radius.

Simplifying the equation, we have dv/dt = πR²(dR/dt). Substituting the given values, we have 10 cm/s = π(6²)(dR/dt).

Solving for dR/dt, we find that the rate at which the radius increases when the radius is 6 cm is approximately 0.056 cm/s.

Calculus and related concepts to explore the relationships between variables and their rates of change. Understanding these mathematical principles is essential for analyzing dynamic systems and their behaviors.

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The experiment involves comparing the temperatures of two thermometers placed in different atmospheric compositions and exposed to radiant energy. The goal is to track the amount of radiant energy absorbed by each atmosphere over a period of 30 minutes.

Part B of the experiment involves performing the actual experiment by following the given directions.:

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This motion of the balloon is an example of buoyancy, which is the upward force exerted by a fluid on an object immersed in it.

When the balloon is neutrally buoyant, it means that the weight of the balloon and the weights attached to it is equal to the weight of the water displaced by the balloon.

If you push the balloon down to a greater depth and then release it, the balloon will rise back up to its original position.

This is because the balloon is still partially inflated and contains air, which is less dense than water. When you push the balloon down, the water pressure compresses the air in the balloon, causing it to become smaller in size.

When you release the balloon, the compressed air expands and pushes the balloon upwards towards the surface of the water.

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