You are testing that the mean speed of your cable Internet connection is more than one hundred Megabits per second. What is the random variable? Describe in words.

Answer:

$200 : $40

(i divided 240 by 6 because there are six parts in the ratio, and got 40. 40*5=200 and the other 40 makes it 240 in the ratio of 5:1)

Step-by-step explanation:

Answer:

Alex : Burton

    5 : 1

5+1=6

240/6=40

5 times 40=200

1 times 40 =40

= 200:40                                                                                                                                                                                     this means alex gets $200 and burton gets $40

Answer:

All real numbers

The dimensions that minimize the cost are x ≈ 13.42 ft and y ≈ 33.58 ft.

We are given that;

Brick wall costing= $30

Area= 450ft^2

Now,

To find the critical points, we take the derivative of C and set it equal to zero:

C’ = 50 - 9000/x2 C’ = 0 50 - 9000/x2 = 0 9000/x2 = 50 x2 = 9000/50 x2 = 180 x = ±√180 x ≈ ±13.42

Since x must be positive, we only consider x ≈ 13.42 as a critical point. To check if this is a minimum or maximum, we can use the first derivative test or the second derivative test. Using the second derivative test, we find:

C’’ = 18000/x3

Since x ≈ 13.42 is positive, C’’ > 0 at this point, which means C has a local minimum at x ≈ 13.42.

To find the absolute minimum, we also need to evaluate C at the endpoints of its domain:

C(0) = undefined C(450) = 50(450) + 20(1) = 22520

So, C has an absolute minimum at x ≈ 13.42 with a value of:

C(13.42) ≈ 50(13.42) + 20(33.58) ≈ $1,337

To find the dimensions of the garden that minimize the cost, we use y = 450/x and plug in x ≈ 13.42:

y ≈ 450/13.42 y ≈ 33.58

Therefore, by area the answer will be x ≈ 13.42 ft and y ≈ 33.58 ft.

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The answers are (a) 1.5 orders (b) 0.5  (c)-1

a. Probability that a faxed order will arrive within the next 9 minutes:

Since there are 24 hours in a day, and we receive an average of 20 orders every two hours, this means we receive an average of 10 orders per hour. We can assume that orders arrive uniformly throughout the hour. To find the probability that a faxed order will arrive within the next 9 minutes, we can convert the time to hours. 9 minutes is \(\frac{9}{60} = 0.15\) hours. The probability of an order arriving within the next 9 minutes is equal to the average rate of orders per hour multiplied by the time interval:

Probability = (10 orders/hour) * (0.15 hours) = 1.5 orders.

b. Probability that the time between two faxed orders will be between 3 and 6 minutes. Again, we need to convert the time interval to hours. 3 minutes is \(\frac{3}{60}=0.05\) hours, and 6 minutes is \(\frac{6}{60} = 0.1\).

The probability of the time between two orders being between 3 and 6 minutes can be calculated as the difference between the probabilities of an order arriving within the next 3 minutes and an order arriving within the next 6 minutes:

Probability = (10 orders/hour)  (0.1 hours) - (10 orders/hour) (0.05 hours)

= 1 - 0.5

= 0.5.

c. Probability that 12 or more minutes will elapse between faxed orders:

Similar to the previous calculations, we convert the time to hours. 12 minutes is \(\frac{12}{60} = 0.2\) hours.

The probability that 12 or more minutes will elapse between faxed orders can be calculated as the probability of no orders arriving within the next 12 minutes:

Probability = 1 - (10 orders/hour) (0.2 hours)

= 1 - 2

= -1.

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Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{(5.5 \: , \: - 9.5)}}}}}\)

Step-by-step explanation:

Let the points be A and B

Let A ( 9 , -9 ) be ( x₁ , y₁ ) and B ( 2 , - 10 ) be ( x₂ , y₂ )

Finding the midpoint

\( \boxed{ \sf{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} }}\)

\( \longrightarrow{ \sf{midpoint = ( \frac{9 + 2}{2} , \: \frac{ - 9 + ( - 10)}{2}}} )\)

\( \longrightarrow{ \sf {midpoint = ( \frac{11}{2} \: , \: \frac{ - 9 - 10}{2}})} \)

\( \longrightarrow{ \sf{midpoint = (5.5 \: , \: \frac{ - 19}{2}}} )\)

\( \longrightarrow{ \sf{midpoint = (5.5 \: , - 9.5}})\)

Hope I helped!

Best regards! :D

To calculate the monthly principal + interest payments for a house with a down payment and a mortgage using an Excel formula, you can use the PMT function. Here's how:

Calculate the loan amount by subtracting the down payment from the house cost. In this case, the down payment is 25% of $300,000, so it would be $75,000.
  Loan Amount = $300,000 - $75,000 = $225,000    

Determine the monthly interest rate by dividing the annual interest rate by 12. In this case, the annual interest rate is 2.75%, so the monthly interest rate would be 2.75% / 12 = 0.00229.

Determine the loan term in months. Since it's a 30-year mortgage, the loan term would be 30 * 12 = 360 months.

Use the PMT function in Excel to calculate the monthly principal + interest payment.
  Monthly Payment = -PMT(0.00229, 360, 225000)

The negative sign is used because the payment is an outgoing cash flow.

By using this formula in Excel, you can find the monthly principal + interest payments for your mortgage. Remember to adjust the interest rate, loan amount, and loan term if they differ from the example provided.

To calculate the monthly principal + interest payments using an Excel formula, you can use the PMT function by inputting the appropriate parameters: the monthly interest rate, loan term in months, and loan amount.

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The given statement is false because In programming, the break and continue statements serve different purposes and can be used independently or together within nested loops.

The break statement is used to exit the current loop prematurely. When encountered, it terminates the loop and continues with the next statement after the loop. This can be useful when a specific condition is met, and you want to stop the execution of the loop immediately.

The continue statement, on the other hand, is used to skip the current iteration of a loop and move on to the next iteration. It allows you to skip certain iterations based on a specific condition without terminating the entire loop.

Both break and continue statements can be used within nested loops. In such cases, the break statement will exit only the innermost loop it is placed in, while the continue statement will skip to the next iteration of the innermost loop.

By using break and continue strategically within nested loops, you can control the flow of execution based on specific conditions. This flexibility allows you to fine-tune the behavior of your program and optimize its efficiency.

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Note : This is a computer science question

Answer:

A set of all positive integers between 7 and 43.

Step-by-step explanation:

If a triangle is given with the sides a, b, c, triangle is possible when,

a + b > c

a + c > b

b + c > a

Following the same rule in a triangle having side lengths 18, 25 and l unit.

18 + 25 > l    ⇒ l < 43

18 + l > 25    ⇒ l > 7

25 + l > 18    ⇒ l > -7

Therefore, length of the third side of the triangle will be,

7 < l < 43  (A set of positive integers between 7 and 43)

Answer:

500

Step-by-step explanation:

It is hard to expain.

Hope its correct and helps:)

Answer:

y2=3

Step-by-step explanation:

4y2+7=19

Subtract 7 from both sides.

4y  2 =19−7

Subtract 7 from 19 to get 12.

4y2=12

Divide both sides by 4.

y2= 12/4

Divide 12 by 4 to get 3.

y2=3

​  

Answer:

4y2 + 7 = 19

Step-by-step explanation:

4y2 =19-7

4y2=12

4yx2=12

8y=12

dbs by 8

y=1.5 or 2

Answer:

-7/6 is the answer hope it helped

The values of x, y and z for the right triangle are: x = √6, y = 3, and z = √10 respectively.

The perpendicular height of the right triangle divides the triangle in two triangles with the same proportions as the original triangle.

√15/(y + 2) = y/√15 {opposite/adjacent}

y(y + 2) = (√15)² {cross multiplication}

y² + 2y = 15

y² + 2y - 15 = 0

by factorization;

(y - 3)(y + 5) = 0

y = 3 or y = -5

by Pythagoras rule:

(√15)² = x² + y²

15 = x² + 3²

x = √(15 - 9)

x = √6

z² = (√6)² + 2²

z = √(6 + 4)

z = √10

Therefore, the values of x, y and z for the right triangle are: x = √6, y = 3, and z = √10 respectively.

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Answer:

Step-by-step explanation:

Midpoint theorem : The line joining midpoint of  any two side of a triangle is parallel to third side and is half of it.

1) AI = 10.5

MC = 2*AI = 2*10.5

MC = 21

I solved for MC using midpoint theorem.

2) MC = 32

AI = \(\frac{1}{2}*32\)

AI = 16

I solved for AI using midpoint theorem.

Answer:

AI is 16

Step-by-step explanation:

Answer:

what image u talking about can u so me the image so I can right the answer. plis

Answer:

No

Step-by-step explanation:

This is a ray (Image Below)

The image you have is a line segment.

Answer:

x=5

Step-by-step explanation:

     May I have brainiest I'm trying to level up!

                 </3 PureBeauty

Answer:

x=5

Step-by-step explanation:

6x-3 = 3x +12

+3            +3

6x = 3x +15

-3x   -3x

3x = 15

divided both sides by 3 to get your answer

Answer:

15,600 Gallons

Step-by-step explanation:

The 30% of 12000 is 3600 thus, Jessica's family used 15600 gallons of water.

The percentage is defined as a given amount in every hundred. It is a fraction with 100 as the denominator percentage is represented by the one symbol %.

The percentage is also called the indicating hundredths. Thus, 2% is two-hundredth, which means 2%=2/100=0.02.

As per the given,

Last used of water = 12000

30% of 12000 = (30/100)12000 = 3600

Water used in the current year = 12000 + 3600 = 15600 gallons.

Hence "The 30% of 12000 is 3600 thus, Jessica's family used 15600 gallons of water".

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Out of the next 99 seed packets, the expected number of pumpkin seed packets is given as follows:

27.

First we must obtain the proportion of the number of pumpkin seed packets, which is given by the division of the number of pumpkin seed packets by the total number of packets.

The total number of packets is obtained as follows:

40 + 21 + 16 = 77.

Hence the proportion of pumpkin seed packets is given as follows:

21/77.

Out of 99 packets, the expected number of pumpkin seed packets is given as follows:

99 x 21/77 = 9 x 21/7 = 27.

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An equation that could represent a linear combination of the system with  no solution is: B) 0 = 26.

In Mathematics, no solution is sometimes referred to as zero solution. Additionally, an equation is considered as having no solution when the right hand side and left hand side of the equation are not the same or equal.

From the information provided above, we have this system of equations:

2x/3 + 5y/2 = 15     ........equation 1

4x + 15y = 12           ........equation 2

Multiplying equation 1 by 6, we have:

6 × (2x/3 + 5y/2 = 15)

4x + 15y = 90      ......equation 3

Subtracting the equation 3 from equation 2, we have:

(4x - 4x) + (15y - 15y) = (12 - 90)

0 + 0 = -78

0 = -78  ≡ 0 = 26.

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Complete question:

The system of equations below has no solution.

2x/3 + 5y/2 = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?

A) 4/3x=42

B) 0 = 26

C) 15/2y=33

D) 0=0

To accurately represent the shoe sizes for men and women separately, it would be better to compute the mean or median shoe size for each group separately and compare them.

The problem with either the mean or the median as a measure of center in this case is that the data is not separated by gender, and the shoe size distributions for men and women are likely to be different. Therefore, computing the mean or median shoe size across all students may not accurately represent the typical shoe size for men or women separately.

For example, if the men in the sample have, on average, larger shoe sizes than the women, then the mean shoe size across all students may be biased towards the larger sizes, even though the majority of the students are women. On the other hand, if there are a few male students with very large shoe sizes, then the median shoe size across all students may be biased towards the larger sizes as well, even if most of the students are women with smaller shoe sizes.

To accurately represent the shoe sizes for men and women separately, it would be better to compute the mean or median shoe size for each group separately and compare them. Alternatively, a better measure of center might be to report the mode, which represents the most common shoe size in the data.

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Answer:

t= 52 seconds

A= 7,903 ft

Step-by-step explanation:

So start by writing each plane as an expression.

Plane A

3687+65.5*t is an expression for the ascent

Plane B

5000+40.25*t is an expression for the ascent

to find the time when they are at the same altitude set them equal to each other

3687+65.5*t = 5000+40.25*t

25.25*t = 1313

t= 52 seconds

to find the altitude solve one of the expressions with t=52

A =3687+65.5*52= 7093 ft

Answer:10:05

Step-by-step explanation:

subtract 45 from 50!

Answer:

She started the test at 10:05 am

Step-by-step explanation:

Take the end time and subtract the time of the test

10:50-45 = 10:05

She started the test at 10:05 am

Answer:

Step-by-step explanation:

The loop will run an infinite number of times

Answer:

x = 19.425

Step-by-step explanation:

x = (asin(B)) / (sin(B))

x = (21sin(61∘)) / (sin(71∘))

x = 19.425 cm

Answer:

you would have 10 apples I'm pretty sure lollll

Answer:

ok

Step-by-step explanation:

let me do it for you lol

Answer:

ok?!?!?!?!?!?!?!?!?!?!?!?

It is not necessarily true that either [a] = [0] or [b] = [0] when [a],[b] ∈ z6 and [a]·[b] = [0].

This is because in z6, there are other pairs of elements that multiply to [0] besides [0] and any other element. For example, [2]·[3] = [6] = [0] in z6, but neither [2] nor [3] are equal to [0].

However, if [a],[b] ∈ z7 and [a]·[b] = [0], then it is necessarily true that either [a] = [0] or [b] = [0]. This is because z7 is a field, meaning that it has no zero divisors (elements that multiply to [0] besides [0] itself). Therefore, the only way for [a]·[b] = [0] in z7 is if either [a] or [b] are equal to [0].

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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