X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequency. Suppose an X-ray camera uses X-rays with a wavelength of 8.38nm . Calculate the frequency of the X-rays. Round your answer to 3 significant digits.

Answer: B

Explanation: Anything that has mass and takes up space

Answer:

Explanation:

We can use the formula:

q = mcΔT

where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Given:
specific heat of iron (c) = 0.449 J/g°C
initial temperature (T1) = 24.0°C
final temperature (T2) = 82.1°C
heat absorbed (q) = 948.0 J

Substituting the given values into the formula, we get:

q = mcΔT
948.0 J = m(0.449 J/g°C)(82.1°C - 24.0°C)
948.0 J = m(0.449 J/g°C)(58.1°C)
m = 948.0 J ÷ (0.449 J/g°C × 58.1°C)
m = 33.1 g

Therefore, the mass of the iron piece is 33.1 g (to three significant figures)

The tests that can be used to determine the kinds of solids that have been listed are shown below.

Here are some tests that can be used to show that a solid is:

Ionic (NaCl):

Solubility test: NaCl is highly soluble in water, and a high degree of solubility can confirm the ionic nature of NaCl.

Conductivity test: In its molten or dissolved state, NaCl conducts electricity due to the presence of charged ions.

Metallic (Ca):

Conductivity test: Metals such as Ca conduct electricity due to the presence of free electrons in their crystal structure.

Ductility and malleability test: Metals are ductile and malleable, and can be easily deformed under pressure.

Covalent Network (Quartz, SiO2):

Hardness test: Covalent network solids such as quartz are extremely hard due to the strong covalent bonds between atoms.

Melting point test: Covalent network solids often have high melting and boiling points due to the strong intermolecular forces between atoms.

Polar Molecular (sugar, C6H12O6):

Solubility test: Polar molecules such as sugar are soluble in polar solvents such as water but insoluble in nonpolar solvents.

Melting and boiling point test: Polar molecular solids have lower melting and boiling points compared to ionic or covalent network solids due to weaker intermolecular forces.

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Answer:

get it back to me by tomorrow

Explanation:

I am currently in life generally but will be perfect

The element is in 2nd group, 3rd period and s block.

How to check the group, period and block of the elements by looking at the electronic configuration?

The total number of valence electron gives us the group, the total number of shells gives us the period and the shell which the valence electron is entering tells us about the block it belongs to.

In [Ne]3s2, the valence electron is 2, the number of shells is 3 that is 1,2 and 3. the valence electron is entering the the s subshell.

Therefore, in [Ne]3s2, the group is 2nd, the period is 3 and it belongs to s block.

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Answer:

a. pH = 2.52

b. pH = 8.67

c. pH = 12.83

Explanation:

The equation of the titration between the benzoic acid and NaOH is:

C₆H₅CO₂H + OH⁻ ⇄ C₆H₅CO₂⁻ + H₂O    (1)

a. To find the pH after the addition of 20.0 mL of NaOH we need to find the number of moles of C₆H₅CO₂H and NaOH:

\( \eta_{NaOH} = C*V = 0.250 M*0.020 L = 5.00 \cdot 10^{-3} moles \)

\( \eta_{C_{6}H_{5}CO_{2}H}i = C*V = 0.300 M*0.050 L = 0.015 moles \)  

From the reaction between the benzoic acid and NaOH we have the following number of moles of benzoic acid remaining:

\(\eta_{C_{6}H_{5}CO_{2}H} = \eta_{C_{6}H_{5}CO_{2}H}i - \eta_{NaOH} = 0.015 moles - 5.00 \cdot 10^{-3} moles = 0.01 moles\)

The concentration of benzoic acid is:

\( C = \frac{\eta}{V} = \frac{0.01 moles}{(0.020 + 0.050) L} = 0.14 M \)

Now, from the dissociation equilibrium of benzoic acid we have:

C₆H₅CO₂H + H₂O ⇄ C₆H₅CO₂⁻ + H₃O⁺  

0.14 - x                            x                x

\( Ka = \frac{[C_{6}H_{5}CO_{2}^{-}][H_{3}O^{+}]}{[C_{6}H_{5}CO_{2}H]} \)

\( Ka = \frac{x*x}{0.14 - x} \)

\( 6.5 \cdot 10^{-5}*(0.14 - x) - x^{2} = 0 \)   (2)  

By solving equation (2) for x we have:          

x = 0.0030 = [C₆H₅CO₂⁻] = [H₃O⁺]

Finally, the pH is:

\( pH = -log([H_{3}O^{+}]) = -log (0.0030) = 2.52 \)

b. At the equivalence point, the benzoic acid has been converted to its conjugate base for the reaction with NaOH so, the equilibrium equation is:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻     (3)

The number of moles of C₆H₅CO₂⁻ is:

\( \eta_{C_{6}H_{5}CO_{2}^{-}} = \eta_{C_{6}H_{5}CO_{2}H}i = 0.015 moles \)

The volume of NaOH added is:

\( V = \frac{\eta}{C} = \frac{0.015 moles}{0.250 M} = 0.060 L \)

The concentration of C₆H₅CO₂⁻ is:

\( C = \frac{\eta}{V} = \frac{0.015 moles}{(0.060 L + 0.050 L)} = 0.14 M \)

From the equilibrium of equation (3) we have:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻  

0.14 - x                              x               x

\(Kb = \frac{[C_{6}H_{5}CO_{2}H][OH^{-}]}{[C_{6}H_{5}CO_{2}^{-}]}\)

\( (\frac{Kw}{Ka})*(0.14 - x) - x^{2} = 0 \)

\( (\frac{1.00 \cdot 10^{-14}}{6.5 \cdot 10^{-5}})*(0.14 - x) - x^{2} = 0 \)

By solving the equation above for x, we have:

x = 4.64x10⁻⁶ = [C₆H₅CO₂H] = [OH⁻]

The pH is:

\( pOH = -log[OH^{-}] = -log(4.64 \cdot 10^{-6}) = 5.33 \)

\( pH = 14 - pOH = 14 - 5.33 = 8.67 \)

c. To find the pH after the addition of 100 mL of NaOH we need to find the number of moles of NaOH:

\( \eta_{NaOH}i = C*V = 0.250 M*0.100 L = 0.025 moles \)

From the reaction between the benzoic acid and NaOH we have the following number of moles remaining:                              

\( \eta_{NaOH} = \eta_{NaOH}i - \eta_{C_{6}H_{5}CO_{2}H} = 0.025 moles - 0.015 moles = 0.010 moles \)                          

The concentration of NaOH is:

\( C = \frac{\eta}{V} = \frac{0.010 moles}{0.100 L + 0.050 L} = 0.067 M \)

Therefore, the pH is given by this excess of NaOH:         

\( pOH = -log([OH^{-}]) = -log(0.067) = 1.17 \)

\( pH = 14 - pOH = 12.83 \)

I hope it helps you!    

Answer:

A) bring the magnet close to the plastic ball and note any motion of the ball toward the magnet

Explanation:

Answer:

There are fewer oxygen atoms in the equation than hydrogen or carbon.

Explanation:

PLATO

Cylinder will expand to 6.08 Lit by assuming that all the energy released is converted to work used to push the piston.

Concept of work :If we  apply force on an object and if the object moves and changes it's position, then product of the force and the displacement of an object in the direction of applied force is called work.

Given,

Pressure= P= 738.52 mm Hg = 0.97 atm. (∵ 760 mm Hg = 1 atm)

Initial volume =V1= 1.7 L

Work done = W = 439.6 J

As we need our answer in litters ..

let's convert the work done into suitable units

∴work done = W = 4.26 L-atm (∵ 1 J = 101.3 L-atm)

As given all the energy is assumed to converted into work so we need not to worry About heat loss or entropy.

work done = pressure * difference in volume

W = PΔV

ΔV = 4.26÷ 0.97

∴ΔV = 4.38 LIt

There for, the volume expanded = 4.38 Lit

So, total volume = 4.38+ 1.7 = 6.08 Lit.

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Answer:

Any atom with six protons, regardless of how much other stuff it has, is a carbon atom. Having 7 neutrons, this would be an atom of Carbon 13 (C-13), a stable isotope of carbon making up 1.1% of natural carbon in the atmosphere and near the Earth's surface. As for the electrons, Carbon has six, but atoms may temporarily pick up or lose electrons in the hurly burly of chemical reactions, solar radiation and so forth. This is a negative ion of C13, which will soon pass on its extra election to an atom which needs it (a positive ion).

Explanation:

https://www.quora.com/What-element-has-6-protons-7-neutrons-and-7-electrons

The amount of heat transferred to the sample of sodium is 332,699.149.

The amount of heat absorbed or released by a substance can be calculated using the following formula;

Q = mc∆T

Where;

According to this question, 898.3g sample of sodium experiences a temperature change of +301.11 K. The specific heat capacity of sodium is 1.23 J/(g-K).

Q = 898.3 × 1.23 × 301.11

Q = 332,699.149 J

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Answer: 7.032

Explanation:
The pH of an aqueous solution can be calculated using the formula:

pH = -log[H+]

Given [H+] = 9.3×10⁻⁸ M, we can plug this value into the formula:

pH = -log(9.3×10⁻⁸)

pH = 7.032

Therefore, the pH of the aqueous solution with a hydrogen ion concentration of [H+]=9.3×10−8 M is approximately 7.032.

Answer:

A.

Explanation:

Answer:

HCN+CuSO4->H2SO4+Cu(CN)2

2,1,1,1

1.Add 2 to HCN it then becomes (H=2, C=2, N=2,) (had to add 2 cz on right side you had H2 in H2SO4)

2.1(nothing) cz on both sides we got 1Cu and 1SO4

3.1 cz again we have H2 on both sides and 1SO4 on both sides

4.1 cz we got 1Cu on both sides and 2C 2N on both sides (1st step)

Answer:

B) Energy will be added

Explanation:

I just took the test...

Explanation:

The atomic number of Uranium is 92. The electron configuration is: [U] = [Rn] 5f3; 7s4 where Radon Rn has 86 electrons and a complete period. This result is respecting the Madelung. BUT … U is an exception !!!

On the period 7 are only 6 electron left for Uranium (92–86). The first 2 electrons are on the principal energy level 7 and occupy the 7s-orbital block. The 3rd electron is placed in the 5f-orbital block. The next 3 electrons are place here as well. The last electron has the unique quantum label (n; l; ml; s) = (5; 3; 0; 0)

To understand this: The first electron of the 5f-orbital block has the label (5; 3, -3; 0). The following electrons have the labels (5; 3; -2, 0), (5; 3; -1; 0), (5; 2; 0; 0). You notice, that the HUND’S RULE is satisfied. ( I always use head 0 before tail 1 to represent the spin.) The f-orbital block is made up of 7 orbitals and therefore can be filled up by at most 14 electrons. When the first electron has the spin 0 then the next 6 electrons must also have the spin 0. With the electron 8 you get the label (5; 3; -3, 1) which tells us, that the spin is opposite to 0. It must be 1. The next 6 electrons also will have spin 1 but are placed in the orbitals -2; -1; 0; 1; 2; 3. Their labels are: (5; 3; -2; 1), (5; 3; -1; 1), (5; 3; 0; 1), (5; 3; 1; 1), (5; 3; 2; 1) and (5; 3; 3; 1) Now the f-block is full !!!

ANSWER: The last electron of U has the label (5; 3; 0; 0). BUT … !!!!!

I hope that you can verify now the correctness of the answer by yourself according to the Madelung.

Please, apply the definitions of the 4 quantum numbers correctly by also respecting the MANDELUNG’S RULE, the OCTET RULLE, the HUND’S RULE.

NOTICE: The Madelung has 21 exceptions. (Wikipedia lists only 20 and treats Ni not as an exception)

Cr, Ni, Cu, Nb, Mo, Ru, Rh, (Pd), Ag, Pt, Au and

La, Ce, Gd, Ac, (Th), Pa, U, Np, Cm, Lr.

In the first group listed: 1 electron moves inwards. In the second group listed: 1 electron moves outwards. Pd and Th have 2 moving electron each. YOU CAN SEE, THAT U IS AN EXCEPTION !!!

CORRECT ANSWER: The last electron of U has the label (6; 2; 0; 0). Can you see the moving electron ??? ❮❮(5; 3; 0; 0) becomes (6; 2; 0; 0)❯❯ Can you see the moving outwards ???

The 21 exception were discovered with spectral analysis. The MADELUNG is not a principle !!! It is only a very simple rule to memorise the electron configurations. By respecting the exceptions, you can correct you Madelung answer !!! Learn the 21 exceptions by heart !

Did you get it ??? (6; 2; 0; 0) is the label of the last electron of U.

Answer:

No. of H atoms in 0.51 moles of H+ = 3.0713 * 10^23 atom

Explanation:

according to the definition of mole which states that the mole is the unit of amount of substance that equals Avogadro's number"Na = 6.022 * 10^23" (i.e. one mole of O2 contains 1Na of molecules, one mole of Ca = 1Na of atoms )

So

the number of atoms in 0.51 moles of H = 0.51 * 6.022 * 10^23 = 3.0713 * 10^23 atom

Answer:

In the Fertile Crescent in the Middle East, cereal crops were first domesticated about 11,000 years ago. Generally, the first domesticated crops were annuals with big seeds or fruits. ... Humans began to transition from a hunter-gatherer culture to a settled farming society as domestication took place.

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Answer:

47900 cm

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

0.479 km

Step 2: Identify Conversions

1 km = 1000 m

1 m = 100 cm

Step 3: Convert

\(0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} )\) = 47900. cm

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

47900. cm ≈ 47900 cm

By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Answer:

I would expect ig to be polar

Explanation:

because it can not be nonpolor.

Answer:

Attached below diagram of the eight diastereomers

The Isomer that reacts so slowly is DIASTEREOMER 8

Explanation:

The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination

attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )

The number of moles that is present is 1 mole.

Molar volume is the volume occupied by one mole of any gas at a specific temperature and pressure. It is represented by the symbol Vm and is expressed in units of cubic meters per mole (m³/mol) or liters per mole (L/mol).

The molar volume of an ideal gas at standard temperature and pressure (STP), which is defined as 0°C (273.15 K) and 1 atmosphere (1 atm) of pressure, is approximately 22.4 L/mol. This means that one mole of an ideal gas occupies a volume of 22.4 liters at STP.

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The 107 moles of electrons are needed to produce 53.5 mol of solid zinc.

The electron is a subatomic particle that contains a negative elementary charge. The electron's mass is approximate 1/1836th that of the proton and has an intrinsic angular momentum of a half-integer value. No two electrons can have the same quantum state.

An electron is bounded to the nucleus of an atom by the attractive Coulomb force. If the number of electrons differs from the nucleus's electrical charge is known as an ion. Each orbital has a unique set of quantum numbers that exist around the nucleus of an atom.

Solid zinc can be formed by chemical reactions:

Zn²⁺  +  2e⁻   →  Zn (s)

One mole of zinc is produced when two moles of electrons are accepted by one mole of zinc ions

One mole of solid zinc is produced from electrons = 2 moles

The 53.5 mol of zinc will be produced from electrons = 2 × 53.5 = 107 mol

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