x-4 in word form
Please help!

Answer:

a.

\( \frac{64}{80} \times 100 = 80\%\)

b.

2 hours = 120 minutes

\( \frac{25}{120} \times 100 = 20\%\)

Answer:

a.

b.

2 hours = 120 minutes

Step-by-step explanation:

\(\\ \sf\longmapsto 2(5m-4)-3(m-5)^2\)

\(\\ \sf\longmapsto 10m-8-3(m^2-10m+5^2)\)

\(\\ \sf\longmapsto 10m-8-3(m^2-10m+25)\)

\(\\ \sf\longmapsto 10m-8-3m^2+30m-75\)

\(\\ \sf\longmapsto -3m^2+30m+10m-75-8\)

\(\\ \sf\longmapsto -3m^2+40m-83\)

Answer:

Uhh Like 50 different outfits using the same paints and shirts just put differently

Step-by-step explanation:

Answer:

Natural Number: 1, 2, 3

Whole number: 7, 19, 24

Integer: 12

Rational Number: 8, 1.5

Irrational Number: π

Step-by-step explanation:

8th grade k-12 xx

Answer:

Step-by-step explanation:

In an organization, two popular training methodologies that can be utilized are on-the-job training and off-the-job training.

Let's examine each methodology along with their popular methods:

1. On-the-Job Training:

On-the-job training refers to the process of acquiring knowledge and skills while performing tasks and responsibilities directly related to one's job. It takes place within the actual work environment and provides hands-on experience. Some popular methods of on-the-job training include:

a. Job Shadowing: This method involves a new employee observing and working closely with an experienced employee, learning from their day-to-day activities and tasks.

b. Mentoring: In this method, a more experienced employee (mentor) guides and supports a less experienced employee (mentee) by providing advice, feedback, and sharing their expertise.

c. Coaching: Similar to mentoring, coaching involves a more experienced employee providing guidance and support to enhance the skills and performance of the employee being coached.

d. Apprenticeships: This method combines on-the-job training with classroom instruction. It allows individuals to learn a trade or skill through practical experience while working alongside skilled professionals.

2. Off-the-Job Training:

Off-the-job training refers to the process of learning and acquiring skills outside of the regular work environment. It usually takes place in a separate training facility or classroom setting. Some popular methods of off-the-job training include:

a. Workshops and Seminars: These are interactive sessions where participants learn new skills, gain knowledge, and exchange ideas on specific topics facilitated by subject-matter experts.

b. Conferences and Conventions: These events bring together professionals from a particular industry or field to attend presentations, panel discussions, and networking opportunities to learn about new trends and developments.

c. E-Learning and Online Courses: With advancements in technology, online platforms offer various courses and training programs that individuals can access remotely at their own pace and convenience.

d. Simulations and Role-Playing: These methods involve creating artificial scenarios or situations that closely resemble real work situations, allowing participants to practice and develop skills in a controlled environment.

e. Case Studies and Group Discussions: Participants analyze real-life scenarios and engage in group discussions to understand problem-solving techniques, decision-making processes, and best practices.

It's important to note that the selection of the training methodology and methods depends on the specific needs, goals, and resources of the organization, as well as the desired learning outcomes for the employees. A combination of both on-the-job and off-the-job training can often be beneficial for comprehensive skill development and knowledge acquisition.

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The evolution of the function call (things '(11 -2 31)) is as follows:

(things '(11 -2 31)) -> (things '(-2 31)) -> (things '(31)) -> (things '()) -> '() the final result of the given call is '().

The given function is a recursive function called "things" that takes a list as input. It checks if the list is empty (null), and if so, it returns an empty list. Otherwise, it checks if the first element of the list (car x) is greater than 10. If it is, it adds 1 to the first element and recursively calls the "things" function on the rest of the list (cdr x). If the first element is not greater than 10, it subtracts 1 from the first element and recursively calls the "things" function on the rest of the list. The function then returns the result.

Now, let's see the evolution resulting from the call (things '(11 -2 31)):

1. (things '(11 -2 31))

  Since the list is not empty, we move to the next if statement.

  The first element (car x) is 11, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(-2 31)).

2. (things '(-2 31))

  Again, the list is not empty.

  The first element (car x) is -2, which is not greater than 10, so we subtract 1 from it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(31)).

3. (things '(31))

  The list is still not empty.

  The first element (car x) is 31, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '()).

4. (things '())

  The list is now empty, so the function returns an empty list.

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By proportion formulas, the variable x associated to the two similar triangles is equal to 6.

Two triangles are similar, when their internal angles are congruent but their sides are not congruent though proportion formulas. Similar triangles can be understood by proportion formulas. In this problem we find this proportion formula:

(3 · x - 5) / r = (5 · x - 4) / (2 · r)

2 · (3 · x - 5) = 5 · x - 4

6 · x - 10 = 5 · x - 4

x = 6

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Answer:

um with what plz tell for I can help you

Answer:

distributive property of multiplication!

please mark me as brainliest!!!

Step-by-step explanation:

6¹⁰/6⁴ = 6⁶

(basically you subtract 4 from 10 so you have 6)

Answer:

1) Please find attached the graph sowing the line of symmetry

The symmetry line is a vertical line passing through (2, -9)

2) The x-intercept are (5, 0) and (-1, 0)

The y-intercept is (0, -5)

The vertex is (2, -9)

Step-by-step explanation:

The given function is;

f(x) = x² - 4·x - 5

The data values are generated as follows;

x,          f(x)

-1,         0

-0.8,    -1.16

-0.6,    -2.24

-0.4,    -3.24

-0.2,    -4.16

0,         -5

0.2,      -5.76

0.4,      -6.44

0.6,     -7.04

0.8,     -7.56

1,         -8

1.2,      -8.36

1.4,      -8.64

1.6,      -8.84

1.8,      -8.96

2,        -9

2.2,     -8.96

2.4,      -8.84

2.6,     -8.64

2.8,     -8.36

3,        -8

3.2,     -7.56

3.4,     -7.04

3.6,     6.44

3.8,     -5.76

4,        -5

4.2,      -4.16

4.4,     -3.24

4.6,     -2.24

4.8,      -1.16

5,           0

The minimum is found from differentiating the function, f(x), with respect to x and looking for the zeros of the result  as follows;

f'(x) = 2·x -4

f'(x) = 0 = 2·x -4

x = 2

The y-coordinate gives; f(2) = 2² - 4×2 - 5 = -9

Therefore, the symmetry line is a vertical line passing through (2, -9)

The x-intercept is the point at which y = 0, therefore, from f(x) = x² - 4·x - 5, we have;

0 = x² - 4·x - 5 = (x - 5)·(x + 1)  

Therefore, the x-intercept are x = 5 or -1

The x-intercept are (5, 0) and (-1, 0)

The y-intercept occur at the point where the x value = 0, therefore, we have;

The y-intercept occur at y = f(0) = 0² - 4·0 - 5 = -5

The y-intercept is (0, -5)

Re-writing the  equation in vertex form y = a(x - h)² + k gives;

f(x) = x² - 4·x - 5 = 1·(x - 2)² - 9

Therefore, the vertex is (2, -9)

Answer:

see attached graph

The x-intercept are (5, 0) and (-1, 0)

The y-intercept is (0, -5)

The vertex is (2, -9)

Step-by-step explanation:

Answer:

26.87877

Step-by-step explanation:

Answer:

C=-3t+30

Step-by-step explanation:

Answer:

The value that completes the square is: c=8

Step-by-step explanation:

Find the value of c that completes the square  \(x^2-16x+c\)

The formula used is: \(a^2-2ab+b^2=(a-b)^2\)

In the question given the value c can be found by breaking the middle term. we are given -16x while the general formula is 2ab for middle term so,

2(x)(8) = 16x

so, c= 8

Solving:

\(x^2-16x+c\\=x^2-2(x)(8)+(8)^2-(8)^2\\=(x-8)^2-64\)

So, the value that completes the square is: c=8

Answer:

Mohan lent 3600 to Ram and 3000 to Shyam.

Step-by-step explanation:

Given that Mohan lent altogether 6,600 to Ram and Shyam for 2 years.

Let Mohan lent x to Ram and y to Shyam

x+y=6600

Or, x=6600-y ...(i)

As Ram  pays simple interest at 15 %=0.15 p.a, so, the interest paid by Ram in 2 years:

\(I=x\times 0.15 \times 2 \\\\\Rightarrow I=0.3x \\\\\)

\(\Rightarrow I=0.3(6600-y) \\\\\) [by using (i)]

\(\Rightarrow I=1980-0.3y \cdots(ii)\)

As Shyam  pays compound interest at 15 %=0.15 p.a,

so, the interest paid by Shyam in 2 years, C.I.= Final amount - Initial principal amount

\(C.I. = y(1+0.15)^2-y \\\\\Rightarrow C.I. = y(1.15^2-1) \\\\\Rightarrow C.I. = y(1.3225-1) \\\\\Rightarrow C.I. = 0.3225y \cdots(iii)\)

As Ram paid Rs 112.50 more than Shyam as the interest, so by using equations (ii) and (iii),

\((1980-0.3y)-0.3225y=112.5 \\\\\Rightarrow 1980-0.3y-0.3225y=112.5 \\\\\Rightarrow 0.6225y=1980-112.5 \\\\\Rightarrow  y = 1867.5/0.6225=3000\)

From equations (i),

\(x=6600-3000=3600\)

Hence, Mohan lent 3600 to Ram and 3000 to Shyam.

Answer:

the fisrst cup has a volume of 100.53

Step-by-step explanation:

As x approaches positive infinity, the function m approaches 0.

To determine this:

In both cases, as x becomes very large in either the positive or negative direction, the value of the function m approaches 0. This is because the function m has been transformed in such a way that it approaches 0 as x becomes very large. This could be due to factors such as the presence of a constant or a coefficient that causes the function to approach 0 as x becomes very large, or due to the presence of a term in the function that cancels out other terms as x becomes very large. Regardless of the specific reason, the result is that the function m approaches 0 as x approaches both positive and negative infinity.

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The upper bound of the 95% confidence interval for the average age in the U.S. is 48.29 years.

To determine the upper bound of the 95% confidence interval for the average age in the U.S., we can use the sample data from the survey. The sample size is 1072 people, randomly selected from the U.S. population, with a minimum age of 12. By calculating the average age of the respondents, we can estimate the average age of the entire U.S. population.

Using the given information that the average age of the respondents is 43.56 years, and assuming that the sample is representative of the population, we can calculate the standard error. The standard error measures the variability of the sample mean and indicates how much the sample mean might deviate from the population mean.

Using statistical methods, we can calculate the standard error and construct a confidence interval around the sample mean. The upper bound of the 95% confidence interval represents the highest plausible value for the population average age based on the sample data.

Therefore, based on the provided information and calculations, the upper bound of the 95% confidence interval for the average age in the U.S. is 48.29 years.

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a. The PMF (Probability Mass Function) for X is:

PMF(X) = {}

0.1, for X = 0

0.2, for X = 1

0.25, for X = 2

0.2, for X = 3

0.15, for X = 4

0.06, for X = 5

0.03, for X = 6

0.01, for X = 7

b. The mean (μ) is 2.54; the Variance (σ²) is 1.6484

c. The CDF is a valid CDF because it is a non-decreasing function and it approaches 1 as x approaches infinity.

a) The PMF (Probability Mass Function) for X, the number of goals scored in a World Cup soccer match, is given by the following:

PMF(X) = {}

0.1, for X = 0

0.2, for X = 1

0.25, for X = 2

0.2, for X = 3

0.15, for X = 4

0.06, for X = 5

0.03, for X = 6

0.01, for X = 7

This PMF is valid because it assigns probabilities to each possible value of X (0 to 7) and the probabilities sum up to 1. The probabilities are non-negative, and for any value of X outside the range of 0 to 7, the probability is zero.

b) To compute the mean and variance of X, we can use the following formulas:

Mean (μ) = Σ(X * PMF(X))

Variance (σ^2) = Σ((X - μ)² * PMF(X))

Using the PMF values given above, we can calculate:

Mean (μ) = (0 * 0.1) + (1 * 0.2) + (2 * 0.25) + (3 * 0.2) + (4 * 0.15) + (5 * 0.06) + (6 * 0.03) + (7 * 0.01) = 2.54

Variance (σ²) = [(0 - 2.54)² * 0.1] + [(1 - 2.54)² * 0.2] + [(2 - 2.54)² * 0.25] + [(3 - 2.54)² * 0.2] + [(4 - 2.54)² * 0.15] + [(5 - 2.54)² * 0.06] + [(6 - 2.54)² * 0.03] + [(7 - 2.54)² * 0.01] ≈ 1.6484

c) The CDF (Cumulative Distribution Function) of X is a function that gives the probability that X takes on a value less than or equal to a given value x.

The CDF can be obtained by summing up the probabilities of X for all values less than or equal to x.

CDF(x) = Σ(PMF(X)), for all values of X ≤ x

For example, the CDF for x = 3 would be:

CDF(3) = PMF(0) + PMF(1) + PMF(2) + PMF(3)

CDF(3) = 0.1 + 0.2 + 0.25 + 0.2

CDF(3) = 0.75

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a) The PMF for X is valid because it assigns non-negative probabilities to each possible value of X and the sum of all probabilities is equal to 1.

b) The mean of X is 2.55 and the variance is 2.1925.

c) The CDF of X is a valid cumulative distribution function as it is a non-decreasing function ranging from 0 to 1, inclusive.

a) The PMF (Probability Mass Function) for X, the number of goals scored in a randomly selected World Cup soccer match, can be represented as follows,

PMF(X) = {

 0.1, if X = 0,

 0.2, if X = 1,

 0.25, if X = 2,

 0.2, if X = 3,

 0.15, if X = 4,

 0.06, if X = 5,

 0.03, if X = 6,

 0.01, if X = 7,

 0, otherwise

}

This PMF is valid because it satisfies the properties of a valid probability distribution. The probabilities assigned to each value of X are non-negative, and the sum of all probabilities is equal to 1. Additionally, the PMF assigns a probability to every possible value of X within the given distribution.

b) To compute the mean (expected value) and variance of X, we can use the formulas,

Mean (μ) = Σ (x * p(x)), where x represents the possible values of X and p(x) represents the corresponding probabilities.

Variance (σ^2) = Σ [(x - μ)^2 * p(x)]

Calculating the mean,

μ = (0 * 0.1) + (1 * 0.2) + (2 * 0.25) + (3 * 0.2) + (4 * 0.15) + (5 * 0.06) + (6 * 0.03) + (7 * 0.01)

  = 0 + 0.2 + 0.5 + 0.6 + 0.6 + 0.3 + 0.18 + 0.07

  = 2.55

The mean number of goals scored in a World Cup soccer match is 2.55.

Calculating the variance,

σ^2 = [(0 - 2.55)^2 * 0.1] + [(1 - 2.55)^2 * 0.2] + [(2 - 2.55)^2 * 0.25] + [(3 - 2.55)^2 * 0.2]

      + [(4 - 2.55)^2 * 0.15] + [(5 - 2.55)^2 * 0.06] + [(6 - 2.55)^2 * 0.03] + [(7 - 2.55)^2 * 0.01]

    = [(-2.55)^2 * 0.1] + [(-1.55)^2 * 0.2] + [(-0.55)^2 * 0.25] + [(-0.55)^2 * 0.2]

      + [(-1.55)^2 * 0.15] + [(2.45)^2 * 0.06] + [(3.45)^2 * 0.03] + [(4.45)^2 * 0.01]

    = 3.0025 * 0.1 + 2.4025 * 0.2 + 0.3025 * 0.25 + 0.3025 * 0.2

      + 2.4025 * 0.15 + 6.0025 * 0.06 + 11.9025 * 0.03 + 19.8025 * 0.01

    = 0.30025 + 0.4805 + 0.075625 + 0.0605 + 0.360375 + 0.36015 +          0.357075 + 0.198025

    = 2.1925

The variance of the number of goals scored in a World Cup soccer match is 2.1925.

c) The CDF (Cumulative Distribution Function) of X can be calculated by summing up the probabilities of X for all values less than or equal to a given x,

CDF(X) = {

 0, if x < 0,

 0.1, if 0 ≤ x < 1,

 0.3, if 1 ≤ x < 2,

 0.55, if 2 ≤ x < 3,

 0.75, if 3 ≤ x < 4,

 0.9, if 4 ≤ x < 5,

 0.96, if 5 ≤ x < 6,

 0.99, if 6 ≤ x < 7,

 1, if x ≥ 7

}

The CDF is valid because it satisfies the properties of a valid cumulative distribution function. It is a non-decreasing function with a range between 0 and 1, inclusive. At x = 0, the CDF is 0, and at x = 7, the CDF is 1. The CDF is right-continuous, meaning that the probability assigned to a specific value of x is the probability of x being less than or equal to that value.

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The probability is given by -0.004 , that the mean of the sample would differ from the population mean by less than 0.9 watts.

Normal distribution also known as the Gaussian probability, is a probability distribution that is symmetric about the mean, showing that data bear the mean are more frequent in occurrence than data far from the mean.

In a set with mean μ and standard deviation (which is the square root of the variance) σ , the z score of a measure X is given by:

Z =X-μ/σ

we have given μ = 495

σ =root(100),   n = 85

This is the p-value of Z when X = 495 +1.7 =496.7 subtracted by the p-value of Z when X = 495 - 1.7 = 493.3

When X = 496.7

Z =X-μ/10

Z = 496.7 -495/10

Z = 0.447 p-value = 0.447

When X = 493.3

Z =X-μ/σ

Z = 493.3- 495/10

=- 0.443 p-value

0.443 - 0.447= -0.004

Hence the probability is -0.004.

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Answer:

5°F

Step-by-step explanation:

-7+12 = 5

Answer:

5 degrees farenheit

Step-by-step explanation:

A scatter diagram is a preliminary or initial step in exploring a relationship between two variables.

A scatter diagram is a graphical tool used to investigate the relationship between two variables. The first step in exploring a relationship between two variables is to create a scatter diagram.

This diagram shows the relationship between two variables as a set of ordered pairs of data points, where one variable is plotted on the horizontal axis and the other variable is plotted on the vertical axis.

The pattern or trend in the plotted points on the scatter diagram can provide useful information about the relationship between the variables. For example, if the points form a roughly linear pattern, it suggests a positive or negative correlation between the variables, while a scatterplot with no clear pattern suggests no correlation.

Therefore, creating a scatter diagram is an essential first step in exploring a relationship between two variables.

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Answer:

If you follow c²=a²+b² you can find your solution or you can do it with the cosinus rule/ sinus rule. But i don't see the side a remarked in your picture so i don't know which one you want to calculate.

Step-by-step explanation:

The surface area of cylinder is  132\(\pi in^2\).

What is surface area ?

A two-dimensional flat surface's area is the space it takes up in space. It has a square unit of measurement. A three-dimensional object's surface area is the space it takes up when viewed from the outside. Square units are used to measure it as well.

Here in given cylinder Radius= 6 in and height = 5 in

Now using surface area formula for cylinder,

Surface Area = 2\(\pi\)r(r+h) square unit.

=> Surface area = \(2\times\pi\times6(6+5)\)

=> Surface area = 132\(\pi in^2\)

Hence the surface area of cylinder is  132\(\pi in^2\).

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Answer:

slope(m)=6

Step-by-step explanation:

(2 , -1)=(x1 , y1)

(3 , 5)=(x2 , y2)

use formula : y2 - y1/x2 - x1

=5-(-1)/3-2

=5+1/1

=6/1

=6

therefore slope of a line is 6.

Answer:

t is a: Transversal

<1 and <7 are: Exterior Angles

<2 and<6 are: Corresponding Angles

<4 and <5 are: Alternate Interior Angles

a and b are: Parallel Lines

<4 and <6 are: Consecutive Interior Angles

<2 and <7 are: Alternate Exterior Angles

<5 and <6 are: Interior Angles

I hope this helps!