Answer:
Ok so we know it has to equal=180 right?
90+90=180
180/4
45
(02.05 MC)
The table represents the linear function f(x), and the equation represents the linear function g(x).
Compare the y-intercepts and slopes of the linear functions f(x) and g(x) and choose the answer that best describes them.
x f(x)
0 1
2 11
4 21
g(x) = 4x + 1
The slope of f(x) is less than the slope of g(x). The y-intercept of f(x) is equal to the y-intercept of g(x).
The slope of f(x) is less than the slope of g(x). The y-intercept of f(x) is greater than the y-intercept of g(x).
The slope of f(x) is greater than the slope of g(x). The y-intercept of f(x) is equal to the y-intercept of g(x).
The slope of f(x) is greater than the slope of g(x). The y-intercept of f(x) is greater than the y-intercept of g(x).
Table for f(x)
\(\begin{gathered}\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf f(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 9\\ \sf 4 &\sf 17\end{array}}\end{gathered}\)
Table for g(x)
\(\begin{gathered}\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf g(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 7\\ \sf 4 &\sf 13\end{array}}\end{gathered}\)
Option C is the correct answer
Answer:
c
Step-by-step explanation:
can somebody help me with my social studies cause if you do i will give you brainlist
Answer:
sure if it is about something i know
A car rental company charge $50 a day and 20 cents per mile for renting a car. Let y be the total rental charge (in dollar) for a car for one day and x be the miles driven. The equation for the relationship between x and y is y = 50 + 20x How much will a person pay who rents a car for one day and drives it 100miles
Answer:$2050.
Step-by-step explanation:
To find out how much a person will pay for renting a car for one day and driving it 100 miles using the given equation, you can substitute x = 100 into the equation y = 50 + 20x and solve for y:
y = 50 + 20x
y = 50 + 20(100)
y = 50 + 2000
y = 2050
Therefore, a person who rents a car for one day and drives it 100 miles will pay $2050.
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
The teacher's question, the student can provide a List of words including "sixty," "zesty," "skit," "site," "size," "exit," "yeti," "kits," "kite," and "ties."
Let unscramble the jumbled word "gzeysktqix" and find the possible words that can be formed.
Upon unscrambling, we can find several possible words:
1. Sixty
2. Zesty
3. Skit
4. Site
5. Size
6. Exit
7. Yeti
8. Kits
9. Kite
10. Ties
These are some of the words that can be formed from the jumbled letters "gzeysktqix." There may be additional words that can be created, depending on the specific rules or restrictions given by the teacher.
Unscrambling words can be a fun and challenging exercise that helps improve vocabulary, word recognition, and problem-solving skills. It allows students to enhance their language abilities and discover new words they might not have known before.
Remember, the key is to rearrange the given letters systematically and try different combinations until meaningful words are formed.
So, in response to the teacher's question, the student can provide a list of words including "sixty," "zesty," "skit," "site," "size," "exit," "yeti," "kits," "kite," and "ties."
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Which expression is equivalent to the given expression?
6y−12
Answer:
it is 6(y-2)
Step-by-step explanation:
Heeeelp please, Can be zero or not?
with all steps and explanay.
The value of integral is 3.
Let's evaluate the integral over the positive half of the interval:
∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx
Let u = 4 + 3sin(x), then du = 3cos(x) dx.
Substituting these expressions into the integral, we have:
∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du
Using the power rule of integration, the integral becomes:
∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]
Evaluating the definite integral at the limits of integration:
(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))
(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0
So, the value of integral is
= 3-0
= 3
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Answer:
\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)
Step-by-step explanation:
First, compute the indefinite integral:
\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)
To evaluate the indefinite integral, use the method of substitution.
\(\textsf{Let} \;\;u = 4 + 3 \sin x\)
Find du/dx and rewrite it so that dx is on its own:
\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)
Rewrite the original integral in terms of u and du, and evaluate:
\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)
Substitute back u = 4 + 3 sin x:
\(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)
Therefore:
\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)
To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.
Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.
\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)
Therefore, the curve of the function is:
Below the x-axis between -π and -π/2.Above the x-axis between -π/2 and π/2.Below the x-axis between π/2 and π.So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.
Integrate the function between -π and -π/2.
As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:
\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)
Integrate the function between -π/2 and π/2:
\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)
Integrate the function between π/2 and π.
As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:
\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)
To evaluate the definite integral, sum A₁, A₂ and A₃:
\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)
Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:
\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)
Therefore, the given expression cannot be zero.
Hi, please let me know if this is correct, please tell me if I’m wrong, thx (:
Answer:
It's correct!
Step-by-step explanation:
20.9/10000=0.00209
pls mark me as brainliest!
Total Cups in Boxes:
18
36
54
66
72
84
Total Numer of Boxes: 3
6
9
1.) How many boxes are needed for 66, 72, and 84 cups?
Answer:
Step-by-step explanation:
For 66 cups, 9 boxes are needed.
For 72 cups, 9 boxes are also needed.
For 84 cups, 9 boxes are also needed.
If
f(x) = 2x² + 3x - 6, determine the value of f(2).
Answer:
8
Step-by-step explanation:
2x² + 3x - 6
plug in x with 2
2(2)^2+3(2)-6
2(4)+6-6
8+6-6
14-6
8
Emma has been keeping an eye on an emerald ring she likes. Its original price was $3,000. After being marked down for a clearance sale, it is now $2,220. By what percent has the price of the ring gone down?
Answer:
26%
Step-by-step explanation:
Original price of the emerald ring
= $3000
Price after the sale
= $2220
Decrease in amount
= $(3000 - 2220)
= $780
Percentage decrease
\( \\ = (\: \frac{decrease \: in \: amount}{original \: amount} \times 100)\%\)
\( \\ = ( \frac{780}{3000} \times 100)\%\)
\( \\ = (26)\%\)
\( \\ = 26\%\)
Hence, by 26% has the price of the ring gone down.
whats equivalent to (4r+ 3) +(-2r+ 4)
Answer:
2r+7
Step-by-step explanation:
(4r+3)+(−2r+4)
Combine 4r and −2r to get 2r.
2r+3+4
Add 3 and 4 to get 7.
2r+7
:)
Find Term 20 for the sequence a= 4 6 8 10......
4,6,8,10 are in A.P
a=4d=2\(\\ \rm\Rrightarrow a_n=a+(n-1)d\)
\(\\ \rm\Rrightarrow a_20=4+(20-1)2\)
\(\\ \rm\Rrightarrow a_20=4+19(2)\)
\(\\ \rm\Rrightarrow a_20=4+38\)
\(\\ \rm\Rrightarrow a_20=42\)
What is the equation in slope-intercept form of the line that passes through the point (2, −2) and is perpendicular to the line represented by
Answer:
not enough information there's no equation
HELP!!!! Write an exponential function to describe the given sequence of numbers.
Answer:
y = 5^(x+1)
Step-by-step explanation:
y = 5^(x+1)
x = 1 for the initial step
2051
20
SINO-V3 COSO - 2
2
Answer:WHAT DOES THAT EVEN MEAN!?!?
Step-by-step explanation:
!!!!!!!!
Let x represent the average annual salary of college and university professors (in thousands of dollars) in the United States. For all colleges and universities in the United States, the population variance of x is approximately σ2
= 47.1. However, a random sample of 15 colleges and universities in Kansas showed that x has a sample variance σ2 = 83.2. Use a 5% level of significance to test the claim that the variance for colleges and universities in Kansas is greater than 47.1. Use the traditional method. Assume that a simple random sample is selected from a normally distributed population.
a. Check requirements.
b. Establish H0 and H1 and note the level of significance.
c. Find the sample test statistic.
d. Find Critical Value.
e. Conclude the test and interpret results.
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
The hypothesis :
H0 : σ²= 47.1
H1 : σ² > 47.1
α = 5% = 0.05
Population variance, σ² = 47.1
Sample variance, s² = 83.2
Sample size, n = 15
The test statistic = (n-1)*s²/σ²
Test statistic, T = [(15 - 1) * 83.2] ÷ 47.1
Test statistic = T = [(14 * 83.2)] * 47.1
Test statistic = 1164.8 / 47.1
Test statistic = 24.73
The degree of freedom, df = n - 1 ; 10 = 9
Critical value (0.05, 9) = 16.92 (Chisquare distribution table)
Reject H0 ; If Test statistic > Critical value
Since ; 24.73 > 16.92 ; Reject H0 and conclude that variance is greater.
Sam plays the violin and the guitar. There are 4 strings on a violin and 6 strings on a guitar. If he has 5 instruments with a total of 28 strings, how many of his 5 instruments are guitars?
Answer:
4 of them
here's why
\(6 * 4 = 24\\24 + 4v = 28\)
v means violin. it's an algebra variable I used to shorten the problem.
Please give brainliest when it shows up! the month is almost over and im on a time limit.
Find the vertical asymptote(s) of f of x equals quantity 2 x squared plus 3x plus 6 end quantity over quantity x squared minus 1.
a
x = −1, 1
b
x = 1, 2
c
x = −1, 2
d
x = −2, 2
The vertical asymptotes of the given rational function; f(x) = ( 2x² + 3x + 6 ) / (x² - 1) are represented in; Choice a; x = -1, 1.
What are the vertical asymptotes of the given rational function?It follows from the task content that the vertical asymptotes of the given rational function are to to be determined.
Since the given rational function is;
f(x) = ( 2x² + 3x + 6 ) / (x² - 1)
The vertical asymptotes of a rational function are the values of x which renders the function undefined.
This simply are values of x for which the denominator equals 0.
Therefore; x² - 1 = 0.
( x + 1 ) ( x - 1 ) = 0.
x = -1, 1.
On this note, the required vertical asymptotes of the rational function are represented by; Choice a; x = -1, 1.
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Put the quadratic into vertex form
The vertex form of the quadratic function f(x) = 2x^2 + 8x + 7 is f(x) = 2(x + 2)^2 - 25.
How to find the vertex formTake a look at the quadratic function:
f(x) = 2x^2 + 8x + 7
In this situation, a = 2 and b = 8, yielding:
f(x) = 2(x^2 + 4x) + 7
It shtbe noted that to determine the value to add and subtract, multiply (b/2a)2 by (8/2(2))2 = 42 = 16. Inside the parenthesis, we add and subtract 16:
f(x) = 2(x^2 + 4x + 16 - 16) + 7
The expression inside the parenthesis can now be written as a perfect square:
f(x) = 2((x + 2)^2 - 16) + 7
Finally, the phrase is simplified by spreading the 2:
f(x) = 2(x + 2)^2 - 32 + 7
f(x) = 2(x + 2)^2 - 25
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What is the vertex form of the quadratic function f(x) = 2x^2 + 8x + 7
HELP NEEDED ASAP
2. Consider the following transformed function
y = −2 Sin [2( − 45°)] + 1
a) Graph the five key points of Parent function on the provided grid. [1mark]
b) State the following for the transformed function [2marks]
Amplitude=
period=
Horizontal Phase shift =
Equation of axis=
c) Graph at least two cycles of the transformed function by transforming the key points of the parent function. (Don’t forget to label the x-axis and y -axis)
The five key points of the parent function are:
Domain: Set of all real numbersRange: Set of all real numbers from -1 to 1 (inclusive)No vertical asymptoteNo horizontal asymptoteMaximum: (π/2 + 2πn, 1)The five key points of the parent functionThe function is given as:
y = -2 sin[2(x - 45)] + 1
The above function is a sine function, and the parent function of a sine function is
y = sin(x)
The properties of the above function are:
Domain: Set of all real numbersRange: Set of all real numbers from -1 to 1 (inclusive)No vertical asymptoteNo horizontal asymptoteMaximum: (π/2 + 2πn, 1)The transformed functionThe transformed function is given as:
y = -2 sin[2(x - 45)] + 1
A sine function is represented as:
y = A sin[Bx + C] + D
Where:
A represents the amplitudePeriod = 2π/BC represents horizontal phase shiftUsing the above representations, we have:
Amplitude = -2Period = 2π/2 = πHorizontal phase shift, C = 2 * -45 = -90Equation of the axis, y = 1The graph of the functionSee attachment for the graph of the sine function y = -2 sin[2(x - 45)] + 1
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Bea T. Howen, a sophomore college student, lost her scholarship after receiving a D in her "Music Appreciation" course. She decided to buy a snow plow to supplement her income during the winter months. It cost her $6312.50. Fuel and standard maintenance will cost her an additional $8.75 for each hour of use. Find the cost function C(x) associated with operating the snow plow for x hours. C(x)= If she charges $34.00 per hour write the revenue function R(x) for the amount of revenue gained from x hours of use. R(x)= Find the profit function P(x) for the amount of profit gained from x hours of use. P(x)= How many hours will she need to work to break even? hours
Answer:
\((a)\ C(x) = 6312.50 + 8.75x\)
\((b)\ R(x) = 34x\)
\((c)\ P(x) = 6312.50 -25.25x\)
\((d)\ Break\ Even = 250\ hours\)
Step-by-step explanation:
Solving (a): The cost function.
Given
\(Cost = \$6312.50\) --- cost of saxophone
\(Additional = \$8.75\) per hour
The cost function is: sum of the cost of the saxophone and the extra cost per hour.
If an hour costs 8.75, then x hours will cost 8.75x
So, the cost function is:
\(C(x) = Cost + Additional\)
\(C(x) = 6312.50 + 8.75x\)
Solving (b): The revenue function
Given
\(Charges = \$34.00\) per hour
The revenue function is the product of the unit charge by the number of hours.
If in an hour, she charges $34.00, then in x hours, she will cost 34x
So, the revenue function is:
\(R(x) = Charges * Hours\)
\(R(x) = 34.00 * x\)
\(R(x) = 34x\)
Solving (c): The profit function
This is the difference between the cost function and the revenue function
i.e.
\(P(x) = C(x) - R(x)\)
So, we have:
\(P(x) = 6312.50 + 8.75x - 34x\)
\(P(x) = 6312.50 -25.25x\)
Solving (d): The break even hours.
To do this, we simply equate the cost function and the revenue function, then solve for x
i.e.
\(C(x) =R(x)\)
\(6312.50 + 8.75x = 34x\)
Collect like terms
\(6312.50 =- 8.75x + 34x\)
\(6312.50 = 25.25x\)
Solve for x
\(x = \frac{6312.50}{25.25}\)
\(x = 250\)
1.The annual salary of teachers in a certain state X has a mean of $54,000 and standard deviation of σ = $5,000. What is the probability that the mean annual salary of a random sample of 64 teachers from this state is less than $52,000?The mean of the sampling distribution of sample of means is $52,000 or $54,000 and the standard deviation is Select an answer $625 or $5000 . 2, The z-score for this problem is Select an answer .4 or -.4 or 3.2 or -3.2 . 3.What is the probability of that the mean annual salary of a random sample of 64 teachers from this state is less than $52,000?A) .0007B) .9993C) .3446D) .6554
Answer:
1
Step-by-step explanation:
The value of z-score will be –0.4. Then the correct option is B. The probability will be 0.34458. Then the correct option is C.
What is the z-score?The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x – μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The annual salary of teachers in a certain state X has a mean of $54,000 and standard deviation of σ = $5,000.
The probability that the mean annual salary of a random sample of 64 teachers from this state is less than $52,000 will be
The mean of the sampling distribution of sample of means is $54,000 and the standard deviation is select an answer $5000.
Then the z-score will be
z = (52000 – 54000) / 5000
z = –2000 / 5000
z = –0.4
Then the correct option is B.
Then the probability will be
P(x < 52000) = P(z < 0.-4)
P(x < 52000) = 0.34458
Then the correct option is C.
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Multiply.
6.39
× 0.42
6.39
x 0.42
-------------
We can multiply as if it's a normal number and ignore the decimals for now.
6.39
x 0.42
-------------
1278
+25560
--------------
26838
Now, we can count the number of places over the decimal is in each number. In 6.39, there are two numbers after the decimal. In 0.42, there are also two numbers. We add those together to get 4. This is how many places over you will put the decimal in 26838.
Therefore, our answer is 2.6838.
268.38
Step-by-step explanation:
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What is the meaning of "the notion of finiteness"?
The notion of finiteness refers to the idea that something has a definite limit or is not infinite. It is a concept that has been applied in various fields of study, such as mathematics, computer science, and philosophy.
In mathematics, finiteness is a fundamental concept used to define various mathematical objects and structures, such as sets, numbers, and sequences. It is also used to define the properties of functions and to study the properties of mathematical systems.
In computer science, the notion of finiteness is crucial for the design and analysis of algorithms and computer programs. Computer scientists use finite state machines, which are mathematical models that describe the behavior of a system that can be in one of a finite number of states.
This concept is essential to the development of computer programs that are efficient, reliable, and secure.
In philosophy, finiteness is a concept that is often used to reflect on the nature of human existence and the limits of human knowledge. It is also used to examine the concept of time and the nature of reality.
In general, the notion of finiteness is a fundamental concept that has many applications in various fields of study.
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anwers plzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
D. 13 1/2
Step-by-step explanation:
Answer: d
Step-by-step explanation:
Find the percent of decrease from 6 to 5.
Answer:
Use this
Step-by-step explanation:
Find the equation of the tangent at ( 0 , 2) to the circle with equation
(x + 2)^2 + (y + 1)^2 = 13
The equation of the tangent line at (0, 2) to the circle is 2x + 3y = 6.
We have,
To find the equation of the tangent at the point (0, 2) to the circle with equation (x + 2)² + (y + 1)² = 13,
We can use the following steps:
- Find the slope of the tangent line:
The slope of the tangent line at a point on the circle is equal to the negative reciprocal of the slope of the radius passing through that point. Since the center of the circle is at (-2, -1) and the point of tangency is
(0, 2), the slope of the radius passing through the point of tangency can be calculated as:
The slope of radius = \((y_2 - y_1) / (x_2 - x_1)\) = (2 - (-1)) / (0 - (-2)) = 3/2.
Using the point-slope form:
\(y - y_1 = m(x - x_1),\) where \((x_1, y_1)\) is the point of tangency and m is the slope, we can substitute the values of \((x_1, y_1)\) = (0, 2) and m = -2/3 into the equation:
y - 2 = (-2/3)(x - 0)
Simplifying the equation:
y - 2 = -2/3x
Multiplying both sides by 3 to eliminate the fraction:
3y - 6 = -2x
Rearranging the equation to the standard form:
2x + 3y = 6.
Therefore,
The equation of the tangent line at (0, 2) to the circle is 2x + 3y = 6.
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Label a ray with endpoint Y. Determine an appropriate name for a ray whose endpoint is Y. Choose the correct ray whose endpoint is Y. A. Y X B. X Y C. X Y D. Y x Choose an appropriate name for a ray whose endpoint is Y. A. XY B. XY C. YX
Label a ray with endpoint Y. An appropriate name for a ray whose endpoint is XY displays a ray with the endpoint Y.
A line with a single defined endpoint that continuously moves away from another is known as a ray (endpoint B in this case).
A segment of a line that lacks an endpoint but has a specified starting point. It can go on forever in a single direction. A ray cannot be measured since it has no end point.
In mathematics, a ray is a segment of a line with a definite starting point but no ending. It can go on forever in a single direction. A ray cannot be measured since it has no end point. Two rays with the same terminal are united to form an angle. The vertex of the angle is referred to as the common endpoint of the rays, while the sides of the angle are referred to as the rays themselves.
The ray in the hypothetical situation has one endpoint B and an endlessly extending endpoint A. (as shown by the arrowhead).
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For F(x)=x^2+8 and g(x)=x^2-8 , find
( f o g) (x)
(g o f) (x),
(f o g)(2)
thanks!!
The final answer is (f o g)(x) = x^4 - 16x^2 + 72
(g o f)(x) = x^4 + 16x^2 + 56
(f o g)(2) = 24
To find the composite functions (f o g)(x) and (g o f)(x), we need to substitute one function into the other.
(f o g)(x):
To find (f o g)(x), we substitute g(x) into f(x):
(f o g)(x) = f(g(x))
Let's substitute g(x) = x^2 - 8 into f(x) = x^2 + 8:
(f o g)(x) = f(g(x)) = f(x^2 - 8)
Now we replace x in f(x^2 - 8) with x^2 - 8:
(f o g)(x) = (x^2 - 8)^2 + 8
Simplifying further:
(f o g)(x) = x^4 - 16x^2 + 64 + 8
(f o g)(x) = x^4 - 16x^2 + 72
Therefore, (f o g)(x) = x^4 - 16x^2 + 72.
(g o f)(x):
To find (g o f)(x), we substitute f(x) into g(x):
(g o f)(x) = g(f(x))
Let's substitute f(x) = x^2 + 8 into g(x) = x^2 - 8:
(g o f)(x) = g(f(x)) = g(x^2 + 8)
Now we replace x in g(x^2 + 8) with x^2 + 8:
(g o f)(x) = (x^2 + 8)^2 - 8
Simplifying further:
(g o f)(x) = x^4 + 16x^2 + 64 - 8
(g o f)(x) = x^4 + 16x^2 + 56
Therefore, (g o f)(x) = x^4 + 16x^2 + 56.
(f o g)(2):
To find (f o g)(2), we substitute x = 2 into the expression (f o g)(x) = x^4 - 16x^2 + 72:
(f o g)(2) = 2^4 - 16(2)^2 + 72
(f o g)(2) = 16 - 64 + 72
(f o g)(2) = 24
Therefore, (f o g)(2) = 24.
In summary:
(f o g)(x) = x^4 - 16x^2 + 72
(g o f)(x) = x^4 + 16x^2 + 56
(f o g)(2) = 24
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A person places $48800 in an investment account earning an annual rate of 3.1%,
compounded continuously. Using the formula V = Pert, where Vis the value of the
account in t years, P is the principal initially invested, e is the base of a natural
logarithm, and r is the rate of interest, determine the amount of money, to the
nearest cent, in the account after 13 years.
When a person places $48,800 in an investment account at an annual rate of 3.1% compounded continuously, using the formula, V = \(Pe^rt\), the amount of money (future value) after 13 years is $73,019.78.
What is compounding?Compounding refers to the process or interest system that computes periodic or continuous interest on both the principal and accumulated interest.
We can solve for the future value of an investment under continuous compounding using an online finance calculator as follows:
Using the formula V = \(Pe^rt\)
Principal (P) = $48,800.00
Annual Rate (R) = 3.1%
Compound (n) = Compounding Continuously
Time (t in years) = 13 years
Result:
V = $73,019.78
V = P + I where
P (principal) = $48,800.00
I (interest) = $24,219.78
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 3.1/100
r = 0.031 rate per year,
Solving the equation for V:
V = \(Pe^rt\)
V = \(48,800.00(2.71828)^(0.031)(13)\)
V = $73,019.78
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