Write a word problem below that describes an object ,vith a distance greater than zero, but a final displacement that is equal to zero. Draw a diagram that illustrates the word problem. Make sure you have the correct units for displacement and distance.

The moment of inertia of the boxer's forearm that has an angular acceleration of 125.0 rad / s² is 0.25 kg m²

τ = F * ⊥d

τ = Torque

F = Force

⊥d = Perpendicular distance

F = 1495 N

⊥d = 2.1 cm = 0.021 m

τ = 1495 * 0.021

τ = 31.395 N m

τ = I α

I = Moment of inertia

α = Angular acceleration

α = 125 rad / s²

I = τ / α

I = 31.395 / 125

I = 0.25 kg m²

Therefore, the moment of inertia of the boxer's forearm is 0.25 kg m²

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Answer:

is that rm in you profile pic

The stresses acting on the surfaces of haulage excavated in an orthotropic rock mass is obtained.

Major and minor stresses act on the surfaces of excavations. Let's calculate the stresses acting on the surfaces of haulage excavated in an orthotropic rock mass given the following parameters acting at a point around the peripheral of the excavation. Major and minor stresses acting on the surfaces of excavations are given by the following equation:

σ1 = ½ [(σxx + σyy) + √[(σxx – σyy)² + 4σxy²]]σ2 = ½ [(σxx + σyy) – √[(σxx – σyy)² + 4σxy²]]σ3 = σzz

Here,

σ1 is the major stress,

σ2 is the minor stress,

σ3 is the axial stress,

σxx is the stress along the x-axis,

σyy is the stress along the y-axis,

σzz is the stress along the z-axis,

σxy is the shear stress in the xy plane,

σyz is the shear stress in the yz plane,

σzx is the shear stress in the zx plane,

and ε is the strain tensor acting at a point.

We have,E1 = 2.5E2 = 2E3 = 2.5V21 = 0.2V31 = 0.15V32 = 0.125G12 = 0.15G23 = 0.26G31 = 0.2εxx = ?εyy = ?εzz = ?εxy = ?εyz = ?εzx = ?

The calculation of stress is carried out as follows:

σxx = E1εxx + V21E2εyy + V31E3εzzσyy = V21E1εxx + E2εyy + V32E3εzzσzz = V31E1εxx + V32E2εyy + E3εzzσxy = G12εxy + G23εyz + G31εzxNow substituting the values:σxx = (2.5)(2.5)εxx + (0.2)(2)(2)εyy + (0.15)(2.5)(2.5)εzzσyy = (0.2)(2.5)(εxx) + (2)(2)εyy + (0.125)(2.5)εzzσzz = (0.15)(2.5)(εxx) + (0.26)(2)(εyy) + (2.5)εzzσxy = (0.15)εxy + (0.26)εyz + (0.2)εzx

Thus, the stresses acting on the surfaces of haulage excavated in an orthotropic rock mass given the following parameters acting at a point around the peripheral of the excavation are as follows:σxx = 6.25εxx + 0.8εyy + 1.875εzzσyy = 0.5εxx + 4εyy + 0.3125εzzσzz = 0.375εxx + 0.52εyy + 2.5εzzσxy = 0.15εxy + 0.26εyz + 0.2εzx

Thus the stresses acting on the surfaces of haulage excavated in an orthotropic rock mass is obtained.

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The acceleration of the tanker aircraft will remain the same, since the thrust of the engine is kept constant.

option C is the correct answer.

Thrust is the power or force that is required to make a vehicle or aircraft move in a particular direction.

According to Newton's second law of motion, the force applied on an object is directly proportional to the product of mass and acceleration of the object.

Mathematically, Newton's second law of motion is given as;

F = ma

where;

a = F/m

When the thrust of the engine is kept constant, then the force applied by the engine is constant.

a = F1/m = F2/m

F1 = F2, since the thrust of the engine kept constant.

Hence, the acceleration of the tanker aircraft will be constant.

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Geoffrey can use various sources to avoid losing total battery power for his camera during a long shoot. Some options include: Geoffrey can carry spare batteries with him to swap them out when the current battery runs low.

This ensures that he always has a fully charged battery available. Battery grip: A battery grip is an accessory that can be attached to the camera and holds extra batteries. This allows Geoffrey to switch between batteries without interrupting the shoot.

Portable power bank: Geoffrey can use a portable power bank to charge his camera battery on the go. These power banks are easy to carry and can provide multiple charges, extending the camera's battery life. AC power adapter: If there is access to a power outlet nearby, Geoffrey can connect his camera to it using an AC power adapter. This way, he can shoot without worrying about battery drain. By utilizing these sources, Geoffrey can prolong his camera's battery life and ensure he doesn't lose total power during his long shoot.

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Sara walked north at 100 m/s. Han had a different velocity but the same speed. He could have walked. The answer is option D: Han could have walked north at 100 m/s.

Velocity is a vector quantity that includes both speed and direction. In this scenario, Sara walked north at a speed of 100 m/s. Now, for Han to have the same speed but a different velocity, he would also need to be moving at 100 m/s. However, the direction of his movement can vary. Option A states that Han could have walked south at 50 m/s. This would result in a different speed than Sara, so it doesn’t meet the given conditions. Option B suggests that Han could have walked north at 200 m/s. This violates the condition of having the same speed as Sara, as Han’s speed would be twice as fast.

Option C suggests that Han could have walked west at 100 m/s. Again, this violates the condition of having the same speed as Sara, as Han’s direction is different. Option D states that Han could have walked north at 100 m/s. This satisfies the condition of having the same speed as Sara and allows for a different direction of movement, making it the correct option. In summary, only option D, where Han walks north at 100 m/s, meets the requirement of having the same speed as Sara while allowing for a different direction of motion.

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The function of sleep theory supported by the illustration is sleep conserves and protects.

From the first sentence, bats sleep a lot because they face little danger from predators and as such, they have a high-calorie diet of insects.

From the second sentence, cows sleep less, because they face more danger from predators and as such, they have a low-calorie diet of insects.

We can conclude that sleep helps to keep animal safe. Therefore, the correct option will be, "Sleep conserves and protects".

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Answer:

5,760

Explanation:

1 minute is equal to 60 seconds. so you will multiply 60 times 96. and that equals 5,760

The rocket launched vertically is being tracked by a radar station on the ground 8 miles from the launch site to calculate the vertical speed of rocket is as follow:

To find: The vertical speed of the rocket when its distance from the radar station is exactly 10 miles

Let's take t be the time in minutes from the launch of the rocket.

At time t, let d be the distance in miles between the rocket and the radar station.

The distance between the rocket and the radar station is given by:

d² = 8² + h² ------(1)

Differentiating both sides of equation (1) w.r.t time, we get,

2dd/dt = 0 + 2h (dh/dt)------(2)

h = √(d² - 64)------(3)

Differentiating both sides of equation

(3) w.r.t time, we get,

h(dh/dt) = d (dd/dt)

=> (dh/dt) = (d/dd) * [√(d² - 64)] * (dd/dt)

=> (dh/dt) = d/{2√(d² - 64)} * (dd/dt)

Put the value of h and (dh/dt) in equation (2),

2dd/dt = 2h (dh/dt)

=> dd/dt = h (dh/dt)

=> dd/dt = d/{2√(d² - 64)} * (dd/dt) * √(d² - 64)

Put the value of d, dd/dt and substitute h = √(d² - 64) in above equation.

dd/dt = 5√191

The vertical speed of the rocket when its distance from the radar station is exactly 10 miles is 5√191 miles per minute.

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Answer:

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. While waves can move over long distances, the movement of the medium of transmission—the material—is limited. Therefore, the oscillating material does not move far fro

Explanation:

The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

                                 \(N=mg\\F_t=ma\\F_t=F-f\)

where, N is the normal reaction, mg is the weight of the box, \(F_t\) is the net force, f is the kinetic friction.

                      \(f=kN=kmg=0.267*1.75*9.8= 4.58N\)

                        \(F_t= 8.35-4.58=3.77N\)

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

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The net force acting on the box is 3.77 N.

We need to learn more about the fundamental forces affecting a body in order to locate the solution.

                             \(N=mg\\F_n=F-f\)

where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.

                            \(f=kN=kmg=4.58N\)

                                     \(F_n=3.77N\)

Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.

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Please find attached photograph for your answer. Please do comment whether it is helpful or not.

The frequency of the siren perceived by the observer is 2,566 Hz.

Calculation:

F = fo(Vsound +V)/(Vsound⁻V source) 2000*(345+24)/345 = 2,566 Hz.

Frequency describes the number of waves passing through a particular location at a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.

The term frequency refers to the number of waves passing through a fixed point in a unit of time. It also describes the number of cycles or vibrations an object undergoes in periodic motion in a unit of time. The frequency of a particular data is the frequency with which the data value occurs. Denote the frequency of the data values ​​by f.

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Answer:

Amount of mold

Explanation:

the dependent variable depends on the independent variable. the amount of mold changes if the bread is opened or not. the independent variable is what can change.

From the above information provided, the blood type of the individual is O- (O negative) which is found   by the reactions of the blood sample with the different antibodies:

Anti-A serum: No reaction

Anti-B serum: No reaction

Anti-Rh serum: No reaction

The individual do not have the A, B, or Rh antigens on their red blood cells, that is corresponding  to blood type O-.

Rh antigens, also called Rhesus antigens, are  described as transmembrane proteins expressed at the surface of erythrocytes and they appear to be used for the transport of CO2 and/or ammonia across the plasma membrane.

In conclusion, the main Rh antigens on red cells – C, c, D, E, e of which the  most important of these is the Rh D.

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Answer:

(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Explanation:

Given;

potential difference, V = 3.00 volts

charge of electron, q = 1.6 x 10⁻¹⁹ C

The work required to move an electron is calculated as;

W = Vq

where;

W is the work done in Joules

Substitute the given values and solve for W;

W = (3.00)(1.6 x 10⁻¹⁹)

W = 4.8 x 10⁻¹⁹ J.

Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Supermassive black holes are believed to be located at the centre of many galaxies because the orbital motion of material near the centre is very fast and indicates a very massive core.

Supermassive black holes are believed to be at the centre of every galaxy as they have such gravitational power and strength so that they can pull the rest of the dust, planets, asteroids closer to it.

Dark matter, which makes up 90% of the milky way's mass, is found in the galaxy's halo.

A plot of orbital motion of the star S2 around the centre of the milky way is a direct evidence for a supermassive black hole.

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Answer:

1. direction of propagation of sound

2.medium through which sound trsnsmitted

(a)1.1 m is the minimum depth of snow that would have stopped him safely. (b)The magnitude of the impulse on him from the snow\(|\Delta \overrightarrow{\mathrm{p}}|\) -4.8 * 10³ kg. m/s.

A key concept in science is magnitude, which is employed in physics. Magnitude describes a general amount or a distance. We can relate magnitude to size and speed of the object is motion while considering the aspects of movement. The magnitude of the an object is defined by it's own size or quantity.

We choose +y upward, which implies a>0  (the acceleration is upward since it represents a deceleration of his downward motion through the snow).

a) The maximum deceleration a\(_m_a_x\) of the paratrooper (of mass m and initial speed ν=56m/s ) is found from Newton’s second law

F\(_s_n_o_w\)−mg=ma\(_m_a_x\)

where we require F\(_s_n_o_w\) =1.2×10⁵N . Using Eq. 2 −15ν² =2a max​ d , we find the minimum depth of snow for the man to survive :

\(\mathrm{d}=\frac{v^2}{2 \mathrm{a}_{\text {max }}}=\frac{\mathrm{m} v^2}{2\left(\mathrm{~F}_{\text {snow }}-\mathrm{mg}\right)} \approx \frac{(85 \mathrm{~kg})(56 \mathrm{~m} / \mathrm{s})^2}{2\left(1.2 \times 10^5 \mathrm{~N}\right)}=\)1.1 m.

(a) He experiences a change in momentum during his brief journey through the snow.

\(\Delta \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{p}}_{\mathrm{f}}-\overrightarrow{\mathrm{p}}_{\mathrm{i}}\) = 0 - (85 kg)(-56m/s)= -4.8 * 10³ kg. m/s.

or\(|\Delta \overrightarrow{\mathrm{p}}|\) = -4.8 * 10³ kg. m/s.

Because downward is the negative direction, the starting velocity has a negative value. This equals the impulse caused by the net force F\(_s_n_o_w\)−mg according to the impulse-momentum theorem, but since F\(_s_n_o_w\) ≫mg we can approximate this as the impulse on him just from the snow.

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The complete question is -

In February 1955, a paratrooper fell 370m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 56m/s (terminal speed), that his mass (including gear) was 85kg, and that the magnitude of the force on him from the snow was at the survivable limit of 1.2×10⁵ N. What are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?

Answer:

B

Explanation:

in comparison, the sun is a soccer ball, and the earth is a head of a needle, and the moon is a speck of salt

The electric bill for the household for the month of June is ₹ 504.72

We'll begin by obtaining the energy consumed. This is shown below:

For fridge:

Energy = power × time

Energy for fridge = 400 × 10

Energy for fridge = 4000 Wh

Divide by 1000 to express in KWh

Energy for fridge = 4000 / 1000

Energy for fridge = 4 kWh

For fan:

Energy = power × time

Energy for fan = 80 × 6

Energy for fan = 480 Wh

Divide by 1000 to express in KWh

Energy for fan = 480 / 1000

Energy for fan = 0.48 kWh

Energy for 2 fans = 2 × 0.48 = 0.96 kWh

For tube:

Energy = power × time

Energy for tube = 18 × 6

Energy for tube = 108 Wh

Divide by 1000 to express in KWh

Energy for tube = 108 / 1000

Energy for tube = 0.108 kWh

Energy for 6 tubes = 6 × 0.108 = 0.648 kWh

Total energy consumed per day = 4 + 0.96 + 0.648 = 5.608 kWh

Total energy consumed per month = 30 × 5.608 = 168.24 kWh

Finally, we shall determine the electric bill for the month of june. Details below:

Electric bill = energy × Cost per KWh

Electric bill for June= 168.24 × 3

Electric bill for June = ₹ 504.72

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Answer:

Women are now allowed to participate in the Olympics. The original Olympic Games were open only to men.

Modern Olympic Games include many more events. The first Olympics included only a running event. Today, there are more than 20 different sports and almost 300 events.

The Olympics are held every two years, alternating between summer and winter. The ancient Olympics were originally held every four years in Olympia.

Athletes from countries around the world participate in the modern Olympics. The ancient Olympics consisted of athletes only from ancient Greece.

Explanation:

plato

Answer:

Choose how long the object is falling. In this example, we will use the time of 8 seconds. Calculate the final free-fall speed

The following are true:

The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.

The net electric field inside a block of metal is zero under all circumstances.

The electric field from an external charge cannot penetrate to the center of a block of iron.

Equilibrium in a conductor refers to a state where the electric field is zero inside the conductor and there is no net flow of mobile charged particles. The electric field from an external charge cannot penetrate to the center of a block of iron, meaning that the electric field is confined to the surface of the metal. The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium, meaning that the electric field is uniform and balanced throughout the conductor. The net electric field inside a block of metal is zero under all circumstances, regardless of the presence of an external electric field. This is because the electric field inside a metal is always balanced and uniform, due to the movement of mobile charged particles within the conductor.

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SWOT Analysis: Apple Inc. has a strong brand image and innovative product portfolio, but faces challenges such as high product prices and intense competition.

PESTEL Analysis: Apple Inc. is influenced by global political stability, economic conditions, changing consumer preferences, rapid technological advancements, environmental sustainability practices, and legal regulations.

Porter's Five Forces Analysis: Apple Inc. faces moderate threats of new entrants and supplier bargaining power, high buyer bargaining power and threats of substitute products, and intense competitive rivalry.

Value Chain Analysis: Apple Inc.'s value chain includes primary activities like logistics, operations, marketing, and support activities such as procurement, technology development, and human resource management.

SWOT Analysis of Apple Inc.:

PESTEL Analysis of Apple Inc.:

Porter's Five Forces Analysis of Apple Inc.:

Value Chain Analysis of Apple Inc.:

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Planetesimals' orbits were disturbed by orbital resonance with Jupiter, which prevented them from accreting into planets.

Orbital resonance happens when the gravitational forces of celestial bodies that are periodically orbiting one another interact, and this interaction is sometimes expressed as a ratio of tiny integers.

Jupiter has the ability to influence the asteroid belt since it is so large and is located very close to the asteroid belt compared to other planets. Asteroids are literally pushed out of the orbital resonances with Jupiter at the locations where they exist, leaving empty space in their wake.

Since Daniel Kirkwood, an American astronomer, was able to foresee and characterise such occurrences in the middle of the 1800s, the region has been virtually free of asteroids. Kirkwood gaps were later used to describe this paucity of asteroids in the region of Jupiter's orbital resonances.

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The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.

Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.

If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.

The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.

F2 = 45 cos 30 = 38.9 N.

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Explanation: White light is all colors of light in one, so when white light passes through a prism, the light gets refracted and breaks apart into all of the colors on the visible light spectrum.

The time it takes the motorboat to cross the river is approximately 73.40 seconds.

The velocity of the motorboat with respect to the river is v_b = 4.00 m/s at an angle of 30° north of east with the north direction. The river flows south with velocity v_r = 1.90 m/s. The width of the river is d = 700 m. We need to find the time t it takes the motorboat to cross the river.

Step 1: Find the velocity of the motorboat with respect to the ground - The velocity of the motorboat with respect to the ground can be found using the velocity addition formula:

v_bg = v_b + v_r

where v_bg is the velocity of the motorboat with respect to the ground.

v_bg = (4.00 m/s)² + (1.90 m/s)² + 2(4.00 m/s)(1.90 m/s cos 30°)

v_bg = sqrt(22.76) m/s

v_bg ≈ 4.78 m/s

Step 2: Find the time to cross the river - The time to cross the river is given by the distance across the river divided by the component of the velocity of the motorboat with respect to the ground perpendicular to the river, which is v_bg sin 30°.

t = d / (v_bg sin 30°)

t = 700 m / (4.78 m/s)(0.5)

t ≈ 73.40 s

Therefore, the time it takes the motorboat to cross the river is approximately 73.40 seconds.

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