Write a compound inequality that is represented by the graph.



A compound inequality using the variable x is

The prediction we can make is that there were about 169 principals in attendance at the conference. The answer is D.

A type of ratio known as proportions describes the size of one segment of a group in relation to the size of the group as a whole, or population.

If 80 people represent a certain percentage of the total attendance, then we can use that same percentage to estimate the number of principals in attendance. Specifically:

percentage of principals in exhibit room = 15/80 = 0.1875

percentage of total attendance in exhibit room = 80/900 = 0.0889

If we assume that the percentage of principals in the exhibit room is similar to the percentage of principals in the entire conference, then we can set up the following proportion:

0.1875 / x = 0.0889 / 900

where x represents the total number of principals in attendance.

here, Solve for x, then:

x = 169

Therefore, the prediction we can make is that there were about 169 principals in attendance at the conference. The answer is D.

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Answer:

23

Step-by-step explanation:

put the numbers in numerical order and then cross off on both sides until there is only one number left (look at the process below!)

9,14,16,18,23,25,26,26,30

14,16,18,23,25,26,26

16,18,23,25,26

18,23,25

23

True. When y is a vector in Rn that is a linear combination of nonzero vectors u1, u2,..., up from an orthogonal set in Rn, the coefficients cj can indeed be computed without using systems of linear equations or row operations on a matrix.

You can compute the coefficients cj using the dot product and the fact that orthogonal vectors have a dot product of zero.

Step-by-step solution:

1. You have the orthogonal vectors u1, u2,..., up in Rn.

2. You also have the linear combination y = c1u1 + c2u2 + ... + cpup.

3. To find the coefficients cj, you can use the dot product of the vectors. For each j (1 ≤ j ≤ p), follow these steps:

a. Calculate the dot product of y and uj: (y • uj).

b. Calculate the dot product of uj with itself: (uj • uj).

c. Divide the result of step a by the result of step b: cj = (y • uj) / (uj • uj).

By using the properties of the dot product and orthogonal vectors, you can compute the coefficients cj without solving systems of linear equations or performing row operations on a matrix.

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This is the solution to the given initial value problem using the Laplace transform method.

To solve the given IVP using the Laplace transform method, we first apply the Laplace transform to the differential equation y'' - y = t - 2 with the initial conditions y(2) = 3 and y'(2) = 0.

Taking the Laplace transform of the given equation, we get:

L{y''}(s) - L{y}(s) = L{t - 2}(s)

Now, we apply the Laplace transform properties for derivatives:

s^2Y(s) - sy(2) - y'(2) - Y(s) = (1/s^2) - (2/s)

Given the initial conditions y(2) = 3 and y'(2) = 0, we can plug them into the equation:

s^2Y(s) - 3s - Y(s) = (1/s^2) - (2/s)

Now, solve for Y(s):

Y(s) = (1/s^2) - (2/s) + 3s/(s^2 + 1) + 1/(s^2 + 1)

Next, perform the inverse Laplace transform to find y(t):

y(t) = L^{-1}{Y(s)}

y(t) = t - 2 + 3(sin(t) - 2cos(t)) + cos(t)

This is the solution to the given initial value problem using the Laplace transform method.

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Answer:

-3(x - 3) (x + 1)

Step-by-step explanation:

Let's check

-3(x - 3) (x + 1)

(-3x + 9) (x + 1)

-3\(x^{2}\) -3x + 9x + 9

-3\(x^{2}\) + 6x + 9

Answer:

-3(x-3)(x+1)

Step-by-step explanation:

A common factor that all three numbers share is that they are divisible by 3, so we can factor 3 out. Typically, I take out the negative first:

-3(\(x^2-2x-3\)) (always remember to change signs!)

Now, we are left with \(x^2-2x-3\), and to factor that out, we need to find two numbers that add up to -2 and multiply to -3. These two numbers will be 1 and -3, so we can write our factor like this:

(x-3)(x+1)

Let's add back in the -3 from earlier to complete our factoring:

-3(x-3)(x+1)

Answer:

If i am correct the area should 337inches..........

Step-by-step explanation:

my reason is becuase if you multiply these numbers

13* 6 = 78       and   8 * 8 = 64     and   10 * 17 + 170   and  last 5 * 5 = 25

they you add    170+ 78 + 64 + 25 =  337inches          so means the answer is 337 Your Welcome :D

Answer:

5/100 x 300=15

300-15=285

The lengths 6, 8 and 15 cannot represent the sides of the triangle. The solution has been obtained by using the triangle inequality theorem.

What is the triangle inequality theorem?

The triangle inequality theorem outlines the relationships between a triangle's three sides. According to this theorem, the lengths of any triangle's two shorter sides add up to be longer than the triangle's third side. In other terms, this theorem states that the shortest path between any two places is always a straight line.

We are given the lengths to be 6, 8 and 15.

Using the triangle inequality theorem,

⇒ 6 + 15 > 8

⇒ 21 > 8

Also,

⇒ 8 + 15 > 6

⇒ 23 > 8

Also,

⇒ 6 + 8 > 15

But,

⇒ 14 < 15

Hence, the lengths 6, 8 and 15 cannot represent the sides of the triangle.

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Answer:

Step 3.

Step-by-step explanation:

Step 3

She  wrote that a4 - 12a3 = -11a.

a4 and 12a3 are unlike terms so they cannot be added.

Answer:

24.95-6.95= 18

18 divided by 8 = 2.25

So each tube of paint cost 2.25 dollars

Step-by-step explanation:

for the first equation we are subtracting the cost of the canvas from the total cost to find the cost of 8 tubes of paint and we get that 8 tubes of paint cost 18 dollars. Next we divide 18 by 8 to get the cost of a single tube of paint and we get 2.25.

Answer:

see below

Step-by-step explanation:

this is difference of the squares a² -b² =(a-b)(a +b)

a² =1/9 x² → a = √1/9x² =1/3 x

b² =25 → b = √25 = 5

finally 0 = -1 (1/3x -5)(1/3x5) or

\(0 = -1 (\frac{x}{3} -5)(\frac{x}{3} +5)\)

Answer:

(3)(2x) + 3 (-4) + - 1n

6x + -12 + - n

Answer -n + 6x - 12

The degrees of freedom for a one-sample t-test with an alpha level of .05 and a sample size of 88 students is 87.

The degrees of freedom are calculated by subtracting 1 from the sample size, which in this case is 88 - 1 = 87. The degrees of freedom represent the number of independent pieces of information available for estimating the population parameter.

In this context, it reflects the number of students in the sample whose scores can vary freely while still being able to estimate the population mean. The t-distribution is used in the t-test to determine the critical value for hypothesis testing and to calculate the p-value.

In a one-sample t-test, the researcher is comparing the mean of a single sample to a known or hypothesized population mean. The degrees of freedom are a crucial parameter in determining the critical value from the t-distribution. The formula to calculate the degrees of freedom is simply the sample size minus 1. In this case, the sample size is 88, so the degrees of freedom would be 87.

Having 87 degrees of freedom means that the sample data has 87 independent pieces of information that contribute to estimating the population mean. With this information, the researcher can use the t-distribution table or statistical software to find the critical t-value for a one-sided test with an alpha level of .05.

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Question 3: True

Question 4: False

Question 5: True

If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c.

This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.

Question 3: If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c.

True

When the derivative of a function, f'(x), is negative at a point c, it indicates that the function is decreasing at that point. Additionally, if the second derivative, f''(x), exists and is negative at x = c, it implies that the graph of f(x) is concave down at that point.

Question 4: A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0.

False

A local extreme point of a polynomial function can occur when f'(x) = 0, but it is not the only condition. A local extreme point can also occur when f'(x) does not exist (such as at a sharp corner or cusp) or when f'(x) is undefined. Therefore, f'(x) being equal to zero is not the sole requirement for a local extreme point to exist.

Question 5: If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = c.

True

If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c. This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.

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When comparing two sample means, we can safely reject the null hypothesis if the calculated test statistic exceeds the critical value corresponding to the chosen significance level.

In hypothesis testing, when comparing two sample means, we typically perform a t-test or z-test depending on the characteristics of the data and assumptions. The null hypothesis assumes that there is no significant difference between the means of the two samples.

To determine whether we can reject the null hypothesis and conclude that there is a significant difference, we calculate a test statistic. The specific test statistic (t or z) depends on factors such as sample size and whether population parameters are known.

Next, we compare the calculated test statistic to the critical value. The critical value is determined based on the chosen significance level (commonly denoted as α). If the calculated test statistic exceeds the critical value, we reject the null hypothesis, indicating that there is evidence to support a significant difference between the two sample means.

The significance level determines the threshold for rejecting the null hypothesis and is typically set at 0.05 (5%) or lower, depending on the desired level of confidence.

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The equation that represents the function shown on the graph is (d) y = 4x

The graph that completes the question is added as an attachment

On the graph, we have the following ordered pairs

Line starts at (0. 0) and through (2, 8), (4, 16), then end at (5, 20)

These ordered pairs are

(x, y) = (0. 0), (2, 8), (4, 16), (5, 20)

The ordered pair (0, 0) implies that the line passes through the origin

This means that the equation can be represented as

y = Y/X * x

Where

(X, Y) = any of (2, 8), (4, 16), (5, 20)

So, we have

y = 8/2 * x

Evaluate the quotient

y = 4 * x

This gives

y = 4x

Hence, the equation is (d) y = 4x

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Answer: d

Step-by-step explanation:

yw

Answer:

J (-5,2)

Hope this helps!

Answer:

x=35

Step-by-step explanation:

The fourth step of the risk assessment process is to determine current level of preparedness/mitigation.

The correct option is C.

A risk assessment is a procedure for identifying potential dangers and analyzing what might happen if one happens. A business impact analysis (BIA) is a procedure that determines the probable consequences of interrupting time-sensitive or important business processes. There are various potential hazards to be mindful of.

The ultimate goal of risk assessments is to improve workplace safety and health. However, to order to accomplish this, your risk assessment process must identify occupational hazards and eliminate or reduce the risks they represent.

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The vertex of the given quadratic equation is located at the point (2, -12).

ax²+bx+c=0, with a not, equals 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

Given a quadratic equation 3x² = 12,

2. My quadratic equation in standard form is: 3x²-12x=0

3. My quadratic equation opens up because the coefficient of x² is Positive.

4. My quadratic has a Min because it opens Upward.

5. The vertex of my quadratic is located at

x = -b/2a

Once you find the x-value of the vertex, you can substitute it back into the original equation to find the y-value.

In your case, the quadratic equation is 3x^2 = 12x, which can be rewritten as:

3x^2 - 12x = 0

Factoring out 3x, we get:

3x(x - 4) = 0

So the solutions are:

x = 0 or x = 4

Using the formula for the vertex, we have:

x = -b/2a = -(-12)/(2*3) = 2

To find the y-value, we can substitute x = 2 into the original equation:

3(2)^2 - 12(2) = -12

So the vertex is located at the point (2, -12).

6. The axis of symmetry of my quadratic is x = 2

7. The y-intercept of my quadratic is 0.

8. My quadratic equation has 2 roots which are (0, 12).

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This problem implies more cases to solve as well as the use of other formulas that we can use in the subject of free fall, if we read our exercise again, we will realize that we only have a height of 150 meters from where it is dropped freely a ball. To proceed to resolve, we collect the data.

Data:

h = 150 m

g = 9.8 m/s²

In order to obtain the distance traveled in 4 seconds, we can use the following formula:

\(\bf{\displaystyle h={{v}_{0}}t+\frac{g{{t}^{2}}}{2} }\)

Remember, that as it is a free fall, the initial speed is null, that is, zero. So the formula reduces:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2} }\)

We are going to place the 4 seconds in the “t” of time. Thus:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2}=\frac{\left( 9.8\frac{m}{{{s}^{2}}} \right){{\left( 4s \right)}^{2}}}{2} }\)

Carrying out the indicated operations:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2}=\frac{\left( 9.8\frac{m}{{{s}^{2}}} \right)16{{s}^{2}}}{2}=\frac{156.8m}{2}=78.4m }\)

That is to say that the height at 4 seconds is 78.4 meters.

For the velocity at 4 seconds, we use the following formula:

\(\bf{\displaystyle {{v}_{f}}={{v}_{0}}+gt}\)

Remember, that since there is no initial speed because it is free fall, then the formula is reduced:

\(\bf{\displaystyle {{V}_{f}}=gt }\)

Substituting our data and calculating:

\(\bf{\displaystyle {{v}_{f}}=gt=\left( 9.8\frac{m}{{{s}^{2}}} \right)\left( 4s \right)=39.2\frac{m}{s} }\)

So the speed at 4 seconds is 39.2 m/s.

Although it seems difficult to solve this section, it is not. It's very easy, let's remember that after 4 seconds it has traveled 78.4 meters and that the height from where the ball was dropped is 150 meters, so the difference is the amount that remains to reach the ground, that is:

\(\bf{\displaystyle {{h}_{T}}={{h}_{1}}+{{h}_{2}}}\)

It is as if we had:

\(\bf{\displaystyle 150=78.4+{{h}_{2}} }\)

Clearing "h2" what would be the distance to reach the ground.

\(\bf{\displaystyle {{h}_{2}}=150-78.4=71.6m }\)

In other words, we need to travel 71.6 meters to reach the ground.

The length of HE is 3 units, which is tangent on the circle.

Tangents to circles are lines that cross the circle at such a single point.

For the stated question-

HE = GE = 3 units.

Thus, the length of HE is 3 units, which is tangent on the circle.

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Answer:

x(x+2) is the answer

Step-by-step explanation:

x²+2x

x(x+2)

Hideki should use coupon 2 to get a better deal.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, Hideki buys 2 sweaters for $18 each.

Coupon 1: Buy one, get one 40% off

Here, 40% of 18

= 40/100 ×18

= 0.4×18

= $7.2

So, cost of entire purchase 2(18)-7.2

= 36-7.2

= $28.8

Coupon 2: 25% off entire purchase

25% of 2(18)

= 25/100 ×36

= 0.25×36

= $9

Now, 36-9 =$27

Therefore, Hideki should use coupon 2 to get a better deal.

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