why don't planets crash into each other?​

Answer: A thermal camera could protect the school during the pandemic because you could detect when students may have a fever or even if the student is hot. Being hot or having a fever is a symptom that doesn't always mean you have Co/vid, however, it does mean you are not keeping the school safe. If anyone in the school has a virus and you have a cold or fever this automatically makes the risk of you getting a cold, or even worse like Cov/id-19 higher.

Explanation: please make me brainliest

Explanation:

Given that,

The wavelength of light = 580 nm

Slit separation, d = 0.000125 m

We need to find the angle of the third dark interference. For the dark fringe,

\(d\sin\theta=(m+\dfrac{1}{2})\lambda\)

Put m = 3 and other values also.

\(d\sin\theta=(3+\dfrac{1}{2})\lambda\\\\d\sin\theta=\dfrac{7\lambda}{2}\\\\\sin\theta=\dfrac{7\lambda}{2d}\\\\\theta=\sin^{-1}(\dfrac{7\lambda}{2d})\\\\\theta=\sin^{-1}(\dfrac{7\times 580\times 10^{-9}}{2\times 0.000125 })\\\\\theta=0.93^\circ}\)

So, the angle is 0.93°.

Answer: 0.665 deg

Explanation:

m=3

lambda= 580

d (converted to nanometers)= 125000

Using the equation of angle=arcsine of m-1/2 times lambda divided by d, filled in it would be arcsine of 3-1/2 times 580 over 125000.

To find the maximum speed of the photoelectrons emitted from the nickel surface, we can use the equation for the kinetic energy of a photoelectron:

K.E. = E - W

λ = 237 nm = 237 × 10^(-9) m

W = 5.10 eV

Where K.E. is the kinetic energy of the photoelectron, E is the energy of the incident photon, and W is the work function of the material.

Wavelength of light, λ = 237 nm = 237 × 10^(-9) m

Work function of nickel, W = 5.10 eV

First, we need to find the energy of the incident photon using the equation: E = hc/λ

Where h is Planck's constant (6.626 × 10^(-34) J·s) and c is the speed of light (3.00 × 10^8 m/s).

Substituting the values, we can calculate E.

Next, we can calculate the maximum kinetic energy of the photoelectron by subtracting the work function from the energy of the incident photon.

K.E. = E - W

Finally, we can find the maximum speed of the photoelectron using the equation:

K.E. = (1/2)mv^2

Where m is the mass of the electron and v is its velocity. The mass of an electron is approximately 9.10938356 × 10^(-31) kg.

By rearranging the equation and substituting the calculated kinetic energy, we can solve for v.

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Explanation:

In scientific notation the Sun's mass is: =1.989 x 10 ^30 kg

Answer:

I think in scientific notation the Sun's mass becomes: M Sun = 1.989 x 10 30 kg. The number above the ten, called the power of ten or exponent, stands for the number of decimal places. If it is positive, as in the mass of the Sun, the decimal places are in front of the decimal point.

I hope this help you!:)

Answer:

Vector Quantities:

Vector quantities refer to the physical quantities characterized by the presence of both magnitude as well as direction. For example, displacement, force, torque, momentum, acceleration, velocity, etc.

Hi there!

We can use a summation of torques to solve.

Recall the following:
\(\Sigma \tau = r \times F\\\\\)

For a system to be static:
\(\Sigma \tau = 0 \\\\\Sigma F = 0\)

In this case, the counterclockwise torques must sum up to the clockwise torques. We can use the pivot as our fulcrum.

Clockwise torques:
1. Weight of man (F = Mg = 70 · 9.8 = 686 N)

2. Weight of beam (F = Mg = 20 · 9.8 = 196 N)

Counterclockwise torque:
3. VERTICAL comp. of tension (F = Ty = Tsin(φ))

Do a summation of torques. The 'r' value is the distance from the force's line of action to the pivot.

Ex: For the beam, its center of mass (assuming uniform density) is at 1.5 m, or its center.

\(\tau_{cc} = \tau_{ccw}\\\\rF_1 + rF_2 = rF_3\\\\(1)(686) + 1.5(196) = 3(Tsin(30))}}\\\\686 + 294 = 3T(0.5)\\\\980 = 1.5T\\\\T = \boxed{653.33 N}\)

Now, we can use a summation of forces to determine the vertical and horizontal components of the pivot's force.

\(\Sigma F_y = 0\)

Sum the forces in the vertical direction. Let 'V' represent the pivot's vertical force.

\(0 = T_y + V - W_m - W_b\\\\0 = Tsin(30) + V - 686 - 196\\\\882 = 326.67 + V\\\\V = 555.34 N\)

Now, sum the horizontal forces. 'H' is the pivot's horizontal force.

\(\Sigma F_x = 0 \\\\0 = T_x - H \\\\H = Tcos(30)\\\\H = 653.33cos(30) = 565.80 N\)

These are the components, so use Pythagorean Theorem to find the total pivot force.

\(F_p = \sqrt{V^2 + H^2} = \boxed{792.80 N}\)

The force will point towards the UPPER LEFT (diagonal). We can solve for the exact angle:

\(tan\theta = V/H \\\\tan{-1}(555.34/565.80) = \boxed{44.47^o}\)

Answer:

When two objects collide, the forces that are exerted on each other are determined by their masses and speeds. If the mass of one of the objects is increased, the force that it exerts on the other object during the collision will also increase. Similarly, if the speed of one of the objects is increased, the force that it exerts on the other object during the collision will also increase. In general, the greater the mass and speed of an object, the greater the force that it will exert on another object during a collision. However, it is important to note that the direction of the forces will remain the same, regardless of the masses or speeds of the objects involved.

Using this formula m=W/g, the mass of an object if its weight on earth is 1150N is 117.347 kg

Let mass of an object be m, weight be W and acceleration due to gravity is g.

From the formula m=W/g

mass m =?

weight w = 1150N

g=9.8 m/\(s^{2}\)

So,  the mass of an object if its weight on earth is 1150N will be calculated as:

m=1150/9.8

m=117.347 kg

Hence using the formula m=W/g, the mass of an object if its weight on earth is 1150N will be 117.347 kg.

This is in acceptance with Newton's laws of motion as well and thus calculated according to given formula.

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Answer:

1. Attacking the person

2. Stress fractures

Explanation:

If this helps this is on my opinion and I need do my best to help you:)

The gravitational acceleration on the surface of the exoplanet is 0.188 m/s².

Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.

From the question above, we know that

h = 18 m

vo = 2.6 m/s

In this case, the final velocity should be zero. Hence,

vt² = vo² + 2a . s

vt² = vo² - 2g . h

0² = 2.6² - 2.g . 18

36g = 6.76

g = 0.188 m/s²

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Explanation:

The force on the passenger will be F = ma

Here, m does not change, but a is the variable.

If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.

If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.

This question can be solved by using equations of motion.

A. The grapefruit dropped by "3.1 m".

B. The speed of the grapefruit, when it hit the ground was "7.8 m/s".

A.

We will use the second equation of motion here to find out the distance dropped by the grapefruit:

\(h = v_it+\frac{1}{2}gt^2\)

where,

h = height dropped = ?

vi = initial speed = 0 m/s

t = time period = 0.8 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

\(h = (0\ m/s)(0.8\ s)+\frac{1}{2}(9.81\ m/s^2)(0.8\ s)^2\)

h = 3.1 m

B.

Now, we will use the first equation of motion to find out the final speed:

\(v_f = v_i +gt\)

vf = 0 m/s + (9.81 m/s²)(0.8 s)

vf = 7.8 m/s

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The attached picture shows the equations of motion in the horizontal and vertical directions.

Answer:

negative at first.

Explanation:

It's important to disconnect the negative side at first, otherwise you can cause an electrical short if positive is removed first.

Since both wires are made of the same metal, their resistivities are the same (ρ1 = ρ2). Thus, the ratio of their resistivities is:

ρ2/ρ1 = ρ1/ρ1 = 1

The ratio of the resistivities of the two wires is 1.

Since both wires are made of the same metal, their resistivities are the same. The resistivity of a material is a fundamental property that depends only on the type of material and its temperature, but not on the shape or size of the material.

Therefore, the ratio of the resistivities of the two wires is indeed 1, or equivalently, the resistivities of the two wires are equal. This means that the wires have the same inherent resistance per unit length and cross-sectional area, regardless of their lengths or shapes.

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Answer:

Its not getting as hot because water and soap can act as a lubricant and it would not heat up easily because of the soapy water.

Answer:

there is less friction when your hands are soapy

Explanation:

The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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Answer:

5.26 m/s

Explanation:

Given that,

The frequency of mosquito's wings, f = 1050 Hz

The observed frequency = 1034 Hz

We need to find the velocity of the mosquito travelling with respect to you. We have a formula to find it such that,

\(v=\dfrac{v}{\dfrac{f'}{f}}-v\)

Where

v is the speed of sound

So,

\(v=\dfrac{340}{\dfrac{1034}{1050}}-340\\\\v=5.26\ m/s\)

So, the required velocity is equal to 5.26 m/s/

The maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm can be calculated using the difference between the energy of the incident photon and the work function of silver.

To find the maximum kinetic energy of electrons ejected from a silver surface, we can use the equation:

K_max = hν - φ

where K_max is the maximum kinetic energy of the ejected electrons, h is Planck's constant, ν is the frequency of the incident light, and φ is the work function of silver.

First, we need to find the frequency of the incident light using the equation:

c = νλ

where c is the speed of light and λ is the wavelength of the incident light.

ν = c/λ = (3.00 x 10^8 m/s)/(254 x 10^-9 m) = 1.18 x 10^15 Hz

Next, we can use the cutoff frequency to find the work function of silver using the equation:

φ = hν_c/λ_c

where ν_c is the cutoff frequency and λ_c is the cutoff wavelength.

φ = (6.63 x 10^-34 J s)(3.00 x 10^8 m/s)/(325 x 10^-9 m) = 6.08 x 10^-19 J

Finally, we can substitute these values into the first equation to find the maximum kinetic energy of the ejected electrons:

K_max = hν - φ = (6.63 x 10^-34 J s)(1.18 x 10^15 Hz) - 6.08 x 10^-19 J = 1.10 x 10^-18 J

Therefore, the maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm is 1.10 x 10^-18 J.

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Answer:

T sin30 = 30N and T cos 30= W as they're in equilibrium

I hope this makes sense I am not the best at this subject

Explanation:

have a great day

Answer:

f =-20 cm

Explanation:

Given that,

The magnification of a spherical mirror, m = -1

The image distance, v = 40 cm (for negative magnification)

The magnification of a concave mirror is negative. The mirror showing -1 magnification is a concave mirror.

Let f be the focal length of the mirror. We know that,

\(m=\dfrac{-v}{u}\\\\-1=\dfrac{-v}{u}\\\\v=u\)

Object distance, u = -40 cm

Using mirror's formula i.e.

\(\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}\\\\f=\dfrac{1}{\dfrac{1}{-40}+\dfrac{1}{-40}}\\\\f=-20\ cm\)

So, the focal length of the mirror is 20 cm.

Answer the answer is A please tell me if this is correct

Explanation:

The point at which the Fahrenheit and Celsius scales have the same numerical value is -40°C. The point at which the Fahrenheit and Kelvin scales have the same numerical value is 459.67°F the expansion gap that should be left between the steel railroad rails is 0.0045 m or 4.5 mm.

(a) The point at which the Fahrenheit and Celsius scales have the same numerical value is -40°C. This is because this temperature is equivalent to -40°F.  At this temperature, both scales intersect and meet the same numerical value.
(b) The point at which the Fahrenheit and Kelvin scales have the same numerical value is 459.67°F. At this temperature, both scales intersect and meet the same numerical value.
For the second part of the question:
Given that the original length of the steel railroad rails is 12.5m, the maximum temperature rise is 30℃, and the coefficient of linear expansion (a) is 1.2×10⁻⁵/℃.
Therefore, the expansion ΔL can be calculated as:
ΔL = L×a×ΔT
Where L is the original length of the steel railroad rails, a is the coefficient of linear expansion, and ΔT is the temperature rise.
Substituting the given values, we have:
ΔL = 12.5×1.2×10⁻⁵×30
ΔL = 0.0045 m
Therefore, the expansion gap that should be left between the steel railroad rails is 0.0045 m or 4.5 mm. This gap allows the rails to expand without buckling or bending.

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Intrinsic attributes refer to the inherent characteristics or qualities of an object, concept, or entity. These attributes are essential in defining and understanding the nature of something.

The use of intrinsic attributes can vary depending on the context, but here are a few common applications:

1. Classification and categorization: Intrinsic attributes help in categorizing and classifying objects or entities based on their inherent properties. For example, in a product catalog, intrinsic attributes such as size, color, and material are used to classify items into different categories.

2. Descriptive analysis: Intrinsic attributes analyze and describe objects by detailing their characteristics and features. Product reviews use attributes like performance, durability, and design for comprehensive evaluations.

3. Search and retrieval: Intrinsic attributes aid information retrieval by enabling efficient search and filtering. Attributes like author, title, and genre in a book database facilitate specific book searches.

4. Decision making: Intrinsic attributes are often used as factors in decision-making processes. By considering the intrinsic attributes of various options, individuals or systems can make informed choices. For example, when purchasing a car, attributes such as fuel efficiency, safety features, and price are considered to make a decision.

5. Personalization and customization: Intrinsic attributes personalize experiences by tailoring offerings to individual preferences. E-commerce websites utilize attributes like purchase history and preferences for personalized recommendations. Customization based on intrinsic attributes enhances user satisfaction and engagement.

Overall, the use of intrinsic attributes helps in understanding, organizing, and making informed decisions about objects, concepts, or entities by considering their inherent qualities and characteristics.

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Option C is the correct answer that indicates the direction of the electric field at point P. The electric field is in the -y direction because electric fields point away from the positive charge and toward the negative charge.

In this scenario, point P is closer to the positively charged plate, so it experiences a stronger electric field towards the negatively charged plate. Since the electric field is a vector quantity, it has both magnitude and direction. The electric field direction is determined by the direction of the force that a positive test charge would experience when placed at that point.
Option A is incorrect because the equal and opposite charges cancel out the electric field at the midpoint, but it does not determine the direction of the electric field at point P.
Option B is incorrect because the distance from the positively charged plate does not determine the direction of the electric field. The electric field direction is determined by the charge distribution around point P.
Option D is incorrect because it assumes that there is a negative charge present near point P, which is not mentioned in the question.

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The pressure will be greater in the cylinder with the piston of smaller area.

In the cylinders with different piston areas, the pressure will be greater in the cylinder with the piston of smaller area.

The pressure in a fluid is directly proportional to the force applied per unit area. This relationship is expressed by Pascal's principle, which states that the pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container.

When the same force is applied to the two cylinders, the cylinder with the smaller piston area will have a smaller total force acting on it compared to the cylinder with the larger piston area. Since pressure is force divided by area, a smaller force applied over a smaller area results in a higher pressure.

Therefore, the cylinder with the piston of smaller area will have a greater pressure compared to the cylinder with the piston of larger area.

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the length of the screen is 70.8 cm.

Width of the central bright band of the diffraction pattern,

δy = λD/d

Where,λ = wavelength of light= 500 nm= 500 × 10⁻⁹ m

Substituting the given values,

δy = (500 × 10⁻⁹ × 1)/4 × 10⁻³= 1.25 × 10⁻⁴ m = 0.125 mm

Thus, the width of the bright patch is 0.12 cm < 0.125 mm. Hence, the entire bright patch would not have formed.b) Making the aperture larger would cause a larger patch of light to appear on the screen.

c) Given,Distance of aperture from the point source, d = 4 mm

Distance of the screen from the aperture, D = 1 m

Distance of the observer from the aperture, x = 2.1 m

Distance of the observer from the screen, L = 2.1 + 1= 3.1 m

Length of the screen, l = 1 m

Let y be the length of the bright patch at x = 2.1 m

Length of the bright patch at x = 2.1 m is given by,

δy' = λL/x = λ(2.1 + 1)/2.1 = 1.476λ

Length of the bright patch on the screen,

δy = λD/d = λ(1)/(4 × 10⁻³) = 0.25λ

Therefore, we get,l/y = δy'/δy= (1.476λ)/(0.25λ)= 5.904Length of the screen, l = y × 5.904= 12 × 5.904= 70.848 ≈ 70.8 cm

Thus, the length of the screen is 70.8 cm.

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Blunt force injuries are caused by non-sharpened objects such as bats or pipes. These types of injuries occur when a blunt object strikes the body, resulting in damage to the underlying tissues and organs.

Unlike sharp force injuries that penetrate or cut the skin, blunt force injuries typically cause a wider area of impact and can result in contusions, bruising, fractures, and internal organ damage.

The force applied by the object can cause compression, shearing, or crushing of tissues, leading to various degrees of injury. Blunt force injuries can range from minor bruises to severe trauma, depending on the intensity and location of the impact.

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The intensity of the sound waves at a distance of 2.50 m from the point source is 11.94.The intensity at a distance of 2.50 m from the point source, we can use the inverse square law for sound intensity. The inverse square law states that the intensity of a sound wave decreases as the square of the distance from the source increases.

First, let's calculate the intensity at the source. Since the source emits sound waves isotropically, the intensity at the source will be the same in all directions. Therefore, the intensity at the source is also 1.91.
Next, we can use the inverse square law to find the intensity at 2.50 m from the source. The formula for the inverse square law is:
I2 = I1 * (d1 / d2)^2
where I2 is the intensity at the second distance, I1 is the intensity at the first distance, d1 is the first distance, and d2 is the second distance.
Plugging in the values, we have:
I2 = 1.91 * (2.50 / 0)^2
I2 = 1.91 * (2.50^2)
I2 = 1.91 * 6.25
I2 = 11.94
Therefore, the intensity of the sound waves at a distance of 2.50 m from the point source is 11.94.

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To calculate the required values, we can use the following formulas:

i. Sampling frequency (Fs) = 1 / τ

ii. Total duration (T) = N * τ

iii. Maximum frequency without aliasing (Fmax) = Fs / 2

Given the values:

N = 1000 samples

τ = 2 ms

Let's calculate each value:

i. Sampling frequency (Fs) = 1 / τ

Fs = 1 / (2 * 10^-3) = 500 Hz

ii. Total duration (T) = N * τ

T = 1000 * (2 * 10^-3) = 2 seconds

iii. Maximum frequency without aliasing (Fmax) = Fs / 2

Fmax = 500 Hz / 2 = 250 Hz

Therefore, the calculated values are:

i. Sampling frequency (Fs) = 500 Hz

ii. Total duration (T) = 2 seconds

iii. Maximum frequency without aliasing (Fmax) = 250 Hz

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