Who is able to solve this problem for me please!!!!!!!!!!
Brainiest will be marked!!!!

No link i can’t open it!!!

Let's simplify the expression step by step: Expand the squared term:

(x - 3y)² = (x - 3y)(x - 3y) = x² - 6xy + 9y²

Expand the second term:

3(x + y)(x − 4y) = 3(x² - 4xy + xy - 4y²) = 3(x² - 3xy - 4y²)

Expand the third term:

x(3x + 4y + 3) = 3x² + 4xy + 3x

Now, let's combine all the expanded terms:

(x - 3y)² + 3(x + y)(x − 4y) + x(3x + 4y + 3)

= x² - 6xy + 9y² + 3(x² - 3xy - 4y²) + 3x² + 4xy + 3x

Combining like terms:

= x² + 3x² + 3x² - 6xy - 3xy + 4xy + 9y² - 4y² + 3x

= 7x² - 5xy + 5y² + 3x

The simplified form of the expression is 7x² - 5xy + 5y² + 3x.

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Answer:

30 plus 20 is 50

30 minus 20 is 10

Answer:Each interior angle of a regular polygon with n sides is given by the formula:

Interior angle = (n - 2) x 180 degrees / n

Exterior angle = 180 degrees - Interior angle

Step-by-step explanation: The angle that is formed between one of the polygon's sides and a line that is drawn from the side next to it is called the polygon's exterior angle. The outside point and the inside point at every vertex of a polygon are beneficial, meaning they amount to 180 degrees.

The vector u is a unit vector or not, we can determine its magnitude. ||u|| = √[(-9/√97)^2 + (-4/√97)^2] = √[81/97 + 16/97] = √97/97 = 1. Therefore, the vector u is a unit vector.

Unit vector: A unit vector is a vector that has a magnitude of 1 and points in a particular direction. By dividing a vector by its magnitude, we obtain a unit vector.

The magnitude of a vector v is denoted by ||v||.To obtain a unit vector u in the direction of vector v (-9, -4), we will use the formula, u = v/||v||.

The magnitude of v can be determined using the Pythagorean Theorem,||v|| = √((-9)^2 + (-4)^2) = √(81 + 16) = √97Now we can find u by dividing v by its magnitude, u = (-9/√97, -4/√97)

To check whether the vector u is a unit vector or not, we can determine its magnitude.||u|| = √[(-9/√97)^2 + (-4/√97)^2] = √[81/97 + 16/97] = √97/97 = 1. Therefore, the vector u is a unit vector.

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Answer: y and x

Step-by-step explanation:

Answer:

stop posting this question multiple times

Answer:

Step-by-step explanation:

I haven't got time to do all these by I'll give you the method in each case.

You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.

A . Multiply  equation 2 by 2 and subtract (to eliminate x)

- don't forget to multiply EACH TERM by 2.

B. Multiply  equation 2 by -2 and add.

C.  Multiply  equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so  you then add to eliminate y.

D.  Multiply equation 1 by 13 and equation  and equation 2 by 2 to eliminate x then add.

Answer:

The maximum weight of the second box is 125 pounds. (The box can weight  less than 125 pounds, but no more than 125 pounds since the total weight of the boxes cannot be more than 300 pounds.)

Step-by-step explanation:

x+y ≤ 300

175+y ≤ 300

Substract 175 on both sides:

y ≤ 125

The inequality that describes the weight limitation in terms of x and y is -

x + y ≤ 300 and the maximum weight of second box can be 125 pounds.

We have a conveyor belt such that there can only be two boxes moving at a time. The total weight of the boxes cannot be more than 300 pounds.

It is given in the question to assume let x and y represent the weights of the two boxes on the conveyer belt.

We have to find -

a) - inequality that describes the weight limitation in terms of x and y.

b) - If two boxes are to be placed on the conveyor belt and first box weighs 175 pounds then what is the maximum weight of the second box?

Inequality in mathematics is a relation that is used to compare two or more algebraic expressions.

According to the part 'a' of the question -

The inequality that describes the weight limitation in terms of x and y is -

x + y ≤ 300

According to part 'b' of the question -

x = 175 pounds

The maximum weight of second box can be found out by substituting the value of 'x' in inequality in part a.

175 + y ≤ 300

y ≤ 125

Hence, the maximum weight of second box can be 125 pounds.

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Answer:

The mass of cocoa in chocolate candy is 3 g.

Step-by-step explanation:

30gr chocolate candy, mark on its packaging that it contains 10% cocoa, how many grams of cocoa does this represent?

mass of chocolate candy = 30 g

cocoa contains = 10 %

Now the mass of cocoa = 10 % of 30 g = 0.1 x 30 = 3 g

Mass of cocoa in the candy is 3 g.

Answer: 8

4: 1, 4, 8

8: 1, 8

Answer:

Step-by-step explanation:

Find the factors of 8 and 4.

8 = 2 * 2 * 2 = 2³

4 = 2 * 2 = 2²

LCM = 2 * 2 * 2 = 8

Or

Write the multiples of 8 and 4

8 = 8,16,24,32,40,....

4 = 4,8,.....

LCM = 8

Haven't answered an inequality question in a while so this
might be complete bullhonkey.

Answer:

154 minutes of talktime.

Step-by-step explanation:

To find out how many minutes of talktime John can have per month, we need to set up an equation using the information given.

Let x be the number of minutes of talktime John can have per month.

The equation for John's monthly phone bill is:

26.50 + 0.35x = 80

To find the value of x, we can solve for x by subtracting 26.50 from both sides:

0.35x = 53.50

To find the number of minutes, we can divide both sides by 0.35:

x = 153.57

To the nearest whole number, John can have 154 minutes of talktime per month.

In this Triangle, ΔUVW, UW is extended through point w to point x

∠ WUV = (3x - 4)°

∠ VWX = (6x + 6)°

∠ UVW = (x + 20)°,  

the value of x is 5

According to the question, given that

∠ WUV = (3x - 4)°

∠ VWX = (6x + 6)°

∠ UVW = (x + 20)°

because ∠ VWX = ∠ WUV + ∠ UVW

             ⇒  (6x + 6) = (3x - 4) + (x + 20)

             ⇒  (6x + 6) = 4x + 16

             ⇒ 2x = 10

             ⇒ x = 5

{The sum of triangle's interior angles is 100°}

{The sum of supplementary angles is 180°}

Therefore, In ΔUVW, UW is extended through point w to point x, then the value of x is 5.

The interior angles of a triangle always add up to 180° while the exterior angles of a triangle are equal to the sum of the two interior angles that are not adjacent to it. By deducting the angle of the target vertex from 180°, one can also determine a triangle's exterior angle.

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The terms minimum and infimum are both related to the concept of lower bounds in mathematics. A minimum is the smallest value in a set of numbers, whereas an infimum is the greatest lower bound of a set.

A minimum is a value that is less than or equal to all other values in the set, while an infimum is a value that is less than or equal to all other values in the set, but not necessarily the smallest value.

For example, if we consider the set {2, 4, 6}, the minimum is 2 and the infimum is also 2. However, if we consider the set {2, 4, 6, 8}, the minimum is 2 and the infimum is 4. In the latter set, 4 is the greatest lower bound, meaning that all other values in the set are greater than or equal to 4.

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Answer:

Step-by-step explanation:

Area of 19 by 29 rectangle = 551 sq ft

White space:

Area of large triangle = 0.5*15^2 = 112.5 sq ft

Area of 15 by 14 rectangle = 210 sq ft

Area of small triangle = 0.5*4^2 = 8 sq ft

Shaded area = 551 - 112.5 - 210 - 8 = 220.5 sq ft

Answer: 551

Step-by-step explanation:

I took the test its correct.

Answer: 2304

Step-by-step explanation: 64 x 36 = 2304

Answer:

2,304 in.

Step-by-step explanation:

I attached a pic of my work.

Answer:

36 back

Step-by-step explanation:

100 - 64 = 36

Answer:

36¢

Step-by-step explanation:

1.00-0.64=0.36

Answer: 112.5

Step-by-step explanation: When line AB and CD intersect at point E, angle AEC equals BED so you set them equal to each other and find what x is. 5x -20 = x + 50, solving for x, which gives you 17.5. Finding x will tell you what AEC and BED by plugging it in which is 67.5. Angle BED and BEC are supplementary angles which adds up to 180 degrees. So to find angle CEB, subtract 67.5 from 180 and you get 112.5 degrees.

Given that the probability of rolling a 1 on a standard die is 1 over 6 or 1/6, then the odds in favor of getting a 1 upon rolling a die is d.) 1 : 5.

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating that the event will not occur and 1 indicating that the event will definitely occur.

Since the probability of rolling a 1 on a standard die is 1 over 6 or 1/6, this means that there is 1 chance out of 6 possibilities that the die will be 1 and 5 chances that the die will not be a 1.

odds = p / 1 - p

where p = probability that the outcome will occur

1 - p = probability that the outcome will not occur

odds = 1/6 / (1 - 1/6) = 1/6 / 5/6 = 1 / 5

Hence, the odds in favor of getting a 1 upon rolling a die is 1 : 5.

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Answer:

1/6

Step-by-step explanation:

Answer:

(2, 2 )

Step-by-step explanation:

Given the 2 equations

3x + 6y = 18 → (1)

- 3x + 4y = 2 → (2)

Adding the 2 equations term by term will eliminate the x- term, that is

0 + 10y = 20

10y = 20 ( divide both sides by 10 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for x

Substituting into (1)

3x + 6(2) = 18

3x + 12 = 18 ( subtract 12 from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

solution is (2, 2 )

Therefore, the integral ∫ (3cos(8x) - 2sin(4x) + 2sec(tan(x))) dx cannot be expressed in terms of elementary functions.

To evaluate the integral ∫ (3cos(8x) - 2sin(4x) + 2sec(tan(x))) dx, we can simplify each term and then integrate term by term.

Let's start by simplifying each term:

∫ 3cos(8x) dx - ∫ 2sin(4x) dx + ∫ 2sec(tan(x)) dx

To integrate each term, we can use standard integration formulas:

∫ cos(ax) dx = (1/a) sin(ax) + C

∫ sin(ax) dx = -(1/a) cos(ax) + C

∫ sec²(u) du = tan(u) + C

Applying these formulas, we have:

(3/8) ∫ cos(8x) dx - (2/4) ∫ sin(4x) dx + 2 ∫ sec(tan(x)) dx

= (3/8) (1/8) sin(8x) - (1/2) (-1/4) cos(4x) + 2 ∫ sec(tan(x)) dx

= (3/64) sin(8x) + (1/8) cos(4x) + 2 ∫ sec(tan(x)) dx

Now, we need to evaluate the integral of sec(tan(x)) dx. This integral does not have a simple closed-form expression, so we cannot integrate it directly. It is often denoted as "non-elementary" or "special" integral.

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Answer:

1/40

Step-by-step explanation:

the chance of getting a multiple of 8 in June:

there are 3 multiples of 8 in June so that makes the chance 3/30 or 1/10

the chance of getting an S in Superstar:

there are 2 's' in Superstar and 8 letters total so the chances are 2/8 or 1/4

to get the chance we just need to multiply 1/10 by 1/4 and we get 1/40

hope this helps!

Answer:

D

Step-by-step explanation:

Answer:

4 8/15

Step-by-step explanation:

The rule is subtract 1 2/6 from the number (n):

(in equation)   x = n - 1 2/6

Answer:

x = 28*

Step-by-step explanation:

We know that Line M is parrallel to line N , so angle x = 28 degrees because the Alternate interior angles of a transversal are equal.

Hope it helps.

True, Reinforcement Learning (RL) with linear function approximation may not work effectively on environments having a continuous state space.

The reason behind this is the complexity and high dimensionality of continuous state spaces, which often makes it difficult for a linear function to capture the underlying structure of the environment accurately.
Linear function approximation involves using a linear combination of features to estimate the value function or the optimal policy in RL. While this approach works well for discrete state spaces and simple problems, it struggles to handle continuous state spaces where the relationships between states and actions are more complex and nonlinear.
In such environments, a more sophisticated function approximation technique, such as neural networks or kernel-based methods, might be required to learn and generalize from continuous state spaces effectively. These methods can capture nonlinear relationships, enabling better performance in challenging environments.
In summary, although RL with linear function approximation can work in some cases, it might not be effective in environments with continuous state spaces due to the complexity and high dimensionality involved. More advanced function approximation techniques are typically necessary for successful learning in such situations.

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