while discussing pfi systems, technician a says the pcm provides the proper air/fuel ratio by controlling the fuel pressure. technician b says the pcm provides the proper air/fuel ratio by controlling the injector pulse width. who is correct? group of answer choices a only b only both a and b neither a nor b

Answer:

I don't know

Explanation:

sorry I am answering this for points

please follow and mark as brainliest for me I will also do same

Answer:

Adapting this case to a work environment, especifically an industry, there should be a security and health brigade in charge of response against emergencies within the organization. Said brigade has the duty of giving direction to all people that could be hurt in any way by a negative event caused by the emergency These directions are given orally in the case of emergencies. Also, emergency services personnel, such as police, firefighters, and paramedics, are certified professionals who have the responsibility of protecting people against harm, and this includes giving guidance during emergencies.

Waves in the electric and magnetic fields are known as electromagnetic waves. You must first understand what a field is, which is just a technique of giving each square inch of space a numerical value. You may see that as a temperature field, for instance, when you look at the weather predictions and they mention the temperature in several locations. Every location on Earth has a unique temperature that can be quantified. Everywhere on Earth has its own wind velocity, which is another form of field. This field differs somewhat from the temperature field in that the wind velocity has both a direction and a magnitude, whereas the temperature just has a magnitude (how hot it is). A vector is a quantity that has both magnitude and direction, hence a field that contains vectors at every location is referred to as a vector field. Vector fields include the magnetic and electric fields. We may examine what would happen if we placed a charged particle at any given position in space. If the charged particle were to accelerate, we would state that the electric field there is the direction in which the particle is moving. In general, positively charged particles will move in the electric field's direction, whereas negatively charged particles will move in the opposite way. Because it is a vector field, the magnetic field exhibits comparable behavior. We discovered in the 19th century that the same interaction, electromagnetism, really produces both electric and magnetic fields. Like an electromagnet, a changing electric field will produce a magnetic field, and a changing magnetic field will induce an electric field (like in a generator). If your system is configured properly, you may have an electric field that fluctuates, which in turn produces a magnetic field, which in turn induces another electric field, which in turn generates another magnetic field, and so on indefinitely. At the speed of light, this oscillation between a strong magnetic field and strong electric field spreads out indefinitely. In reality, light is an electromagnetic wave—an oscillation in the electromagnetic fields. An electric or magnetic field may exist without a medium since they exist in a vacuum, which implies that waves in these fields don't require a medium like sound to flow through.

Local codes can impact blowdown water by specifying the allowable concentration of impurities and discharge standards, which can affect the treatment and disposal of blowdown water.

Local codes and regulations play an important role in determining the quality of water that can be discharged into the environment. Blowdown water, which is generated from cooling systems, can contain high levels of impurities such as dissolved solids, minerals, and organic matter.

Local codes can specify the maximum allowable concentration of these impurities, which can impact the treatment and disposal of blowdown water. For example, some codes may require blowdown water to be treated before being discharged into the environment, while others may require it to be hauled off-site for disposal.

It is important for businesses to be aware of these regulations and ensure compliance to avoid potential penalties or environmental harm.

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Answer:

14.5° ; THD % = 3.873 × 100 = 387.3%.

Explanation:

Okay, in this question we are given the following parameters or data or information which is going to assist us in solving the question efficiently and they are;

(1). "500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor".

(2). Consideration of up to 12th harmonic.

So, let us delve right into the solution to the question above;

Step one: Calculate the Irms and Irms(12th) by using the formula for the equation below;

Irms = reactive power /Vrms = 500/230 = 2.174 A.

Irms(12th) = 1.5 × 10^3/ 12 × 230 = 0.543 A.

Step two: Calculate the THD.

Before the Calculation of the THD, there is the need to determine the value for the dissociation factor, h.

h = Irms(12th)/Irms = 0.543/ 2.174 = 0.25.

Thus, THD = [1/ (h)^2 - 1 ] ^1/2. = 3.873.

THD % = 3.873 × 100 = 387.3%.

Step four: angle AC - Ac converter

theta = sin^-1 (1.5 × 10^3/ 12 × 500) = 14.5°.

"The next higher octane aviation gas" can be substituted for an aircraft if the recommended octane is not available. The answer is (a).

When an aircraft requires fuel, the recommended octane rating must be used to avoid engine knock and other safety issues. If the recommended fuel is not available, it is essential to use the next higher octane aviation gas, which is considered safe for the engine. However, the next lower octane aviation gas or unleaded automotive gas of the same octane rating must not be used, as it can lead to engine damage and compromise safety.

Therefore, it is important for pilots and aviation personnel to ensure that the correct fuel is used to maintain the safety and reliability of aircraft operations. Option (a) is the correct answer.

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yes it will

Explanation:

Answer:

Clay bricks are manufactured by mining and clay moulded blocks. There are 20,000 brick klins in Pakistan.

Explanation:

In Pakistan, the clay bricks are manufactured by mining and baking the clay moulded blocks in brick kilns. According to an estimate, the baking process emits about  1.4 pounds of carbon per brick made, but in Pakistan, because the systems are outdated, brick kilns are used, which is producing more than the average amount of the pollution.

There are about 20,000 brick kilns in Pakistan. The traditional brick production in Pakistan is consists of hand-made bricks which are first baked in Fixed Chimney Bull's Trench Kilns (FCBTK), this is the most widely used brick firing technology in South Asia.

The speed of water in a pipe can vary depending on the shape and size of the pipe and the rate of flow of water.

Generally, the speed of water is highest at the narrowest point of the pipe and lowest at the widest point.

In a pipe with a constant diameter, the speed of water is fastest at the center of the pipe and slowest at the edges. This is because the water experiences the least amount of friction and resistance at the center, where it is farthest away from the walls of the pipe.

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When water is run through a pipe that is narrow is flows faster than when the pipe is wider. This is called the Bernoulli's principle.

Bernoulli's principle asserts that in a horizontal flow of fluid, places with faster fluid speed will have less pressure than points of slower fluid speed.

When a vehicle goes quickly, it creates a low pressure area, and dusts are drawn along in the low pressure area. When we stand very close to the railway track on the platform and a fast train passes us, we are dragged towards the track due to the low pressure region created by the train's high speed.

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Answer:

B

Explanation:

Fingerprint 6 is the one associated with Mr. Kurtz.The correct answer is c.

Fingerprinting is an important security measure used to identify individuals and verify their identity. It involves taking an impression of the ridges and patterns on a person's fingers, which are then used to create a unique digital record that can be used to identify and verify an individual's identity.

The process involves taking an impression of the ridges and patterns on a person's fingers with a special scanner, which is then used to create a unique digital record. This record is then used to identify and verify the individual's identity. Fingerprinting has become increasingly popular in recent times, due to its accuracy and reliability as a form of biometric identification.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

The final velocity of the rocket is 450 m/s.

Explanation:

Given;

initial velocity of the rocket, u = 0

constant upward acceleration of the rocket, a = 18 m/s²

time of motion of the rocket, t = 25 s

The final velocity of the rocket is calculated with the following kinematic equation;

v = u + at

where;

v is the final velocity of the rocket after 25 s

Substitute the given values in the equation above;

v = 0 + 18 x 25

v = 450 m/s

Therefore, the final velocity of the rocket is 450 m/s.

a. 25 b. accelerated by 7

Answer:

a. 25 b. accelerated by 7

Answer:

See explanation

Explanation:

See the document for the complete FBD and the introductory part of the solution.

Static Balance ( Sum of Forces = 0 ) in all three directions

                 ∑\(F_G_X = W - G_x = 0\)

                 \(G_X = W = 1500 lb\)

                 ∑\(F_G_Y = P - G_Y = 0\)

                 \(G_Y = P = -10,800 lb\)

                ∑\(F_G_Z = - G_Z = 0\)

Where, ( \(G_X, G_Y, G_Z\) ) are internal forces at section ( G ) along the defined coordinate axes.

Static Balance ( Sum of Moments about G = 0 ) in all three directions

              \(M_G = r_O_G x F_O\)

Where,

              r_OG: The vector from point O to point G

              F_OG: The force vector at point O

- The vector ( r_OG ) and ( F_OG ) can be written as follows:

              \(r_O_G = [ -( 3 + \frac{H}{2} ) i + (\frac{r_o}{12})j - ( \frac{r_o}{12} + \frac{L}{2})k ] \\\\r_O_G = [ -( 6 ) i + (0.25)j - (6)k ] \\\)

              \(F_O_G = [ ( W ) i + ( P ) k ]\\\\F_O_G = [ (1500) i - ( 10,800 ) k ] lb\)

- Then perform the cross product of the two vectors ( r_OG ) and ( F_OG ):

     \(( M_G_X )i + (M_G_Y)j+ (M_G_Z)k = \left[\begin{array}{ccc}i&j&k\\-6&0.25&-6\\1500&-10,800&0\end{array}\right] \\\\\\( M_G_X )i + (M_G_Y)j+ (M_G_Z)k = -( 6*10,800 ) i - ( 6*1500 ) j + [ ( 10,800*6) - ( 0.25*1500) ] k\\\\( M_G_X )i + (M_G_Y)j+ (M_G_Z)k = - (64,800)i - (9,000)j + (64,425)k\)

- The internal torque ( T ) and shear force ( V ) that act on slice ( G ) are due to pressure force ( P ) as follows:

             \(T = P*[\frac{L}{2}] = (10,800)*(6) = 64,800 lb.ft\)

             \(V = P = -10,800 lb\)

- For the state of stress at point "C" we need to determine the the normal stress along x direction ( σ_x ) and planar stress ( τ_xy ) as follows:-

             σ_x = \(-\frac{G_x}{A} - \frac{M_G_Y. z*}{I_Y_Y} + \frac{M_G_Z. y*}{I_Z_Z}\)

Where,

          A: The area of pipe cross section

          \(A = \pi * [ ( \frac{r_o}{12})^2 - ( \frac{r_i}{12})^2 ] = \pi * [ ( \frac{3}{12})^2 - ( \frac{2.75}{12})^2 ] = 0.03136 ft^2\)

          z*: The distance of point "C" along z-direction from central axis ( x )

          \(z*= [\frac{r_i}{12} ] = [\frac{2.75}{12} ] = 0.22916 ft\)

         I_YY: The second area moment of pipe along and about "y" axis:

         \(I_Y_Y = \frac{\pi }{4} * [ (\frac{r_o}{12})^4 - (\frac{r_i}{12})^4 ]=\frac{\pi }{4} * [ (\frac{3}{12})^4 - (\frac{2.75}{12})^4 ] \\\\I_Y_Y = 0.00090 ft^4\)

         y*: The distance of point "C" along y-direction from central axis ( x )

         \(y* = 0\)

- The normal stress ( σ_x ) becomes:

          σ_x = \([-\frac{1500}{0.03136} - \frac{-9,000*0.22916}{0.00090} + \frac{64,425*0}{0.00090} ] * (\frac{1}{12})^2 = 15.5 ksi\)

- The planar stress is ( τ_xy ) is a contribution of torsion ( T ) and shear force ( V ):

           τ_xy = \(- \frac{T.c}{J} + \frac{V.Q}{I.t}\)

Where,

           c: The radial distance from central axis ( x ) and point "C".

           \(c = \frac{r_i}{12} = \frac{2.75}{12} = 0.22916 ft\)

          J: The polar moment of inertia of the annular cross section of pipe:

          \(J = \frac{\pi }{2}* [ ( \frac{r_o}{12})^4 - ( \frac{r_i}{12})^4 ] = \frac{\pi }{2}* [ ( \frac{3}{12})^4 - ( \frac{2.75}{12})^4 ] = 0.00180 ft^4\)

          Q: The first moment of area for point "C" = semi-circle

          \(Q = Y_c*A_c = \frac{4*( r_m)}{3\pi } * \frac{\pi*( r_m)^2 }{2} = \frac{2. ( r_m)^3}{3} \\\\Q = \frac{2. [ ( \frac{r_o}{12})^3 - ( \frac{r_i}{12})^3] }{3} = \frac{2. [ ( \frac{3}{12})^3 - ( \frac{2.75}{12})^3] }{3} = 0.00239ft^3\)

          I: The second area moment of pipe along and about "y" axis:

         \(I_Y_Y = \frac{\pi }{4} * [ (\frac{r_o}{12})^4 - (\frac{r_i}{12})^4 ]=\frac{\pi }{4} * [ (\frac{3}{12})^4 - (\frac{2.75}{12})^4 ] \\\\I_Y_Y = 0.00090 ft^4\)    

         t: The effective thickness of thin walled pipe:

         \(t = 2* [ \frac{r_o}{12} - \frac{r_i}{12} ] = 2* [ \frac{3}{12} - \frac{2.75}{12} ] = 0.04166 ft\)

- The planar stress is ( τ_xy ) becomes:

        τ_xy =  \([ - \frac{-64,800*0.22916}{0.0018} + \frac{-10,800*0.00239}{0.0009*0.04166} ] * [ \frac{1}{12}]^2 = 52.4 ksi\)

- The principal stresses at point "C" can be determined from the following formula:-

       σ_x = 15.55 ksi,  σ_y = 0 ksi , τ_xy = 52.4 ksi

       σ_1 =\(\frac{sigma_x+sigma_y}{2} + \sqrt{(\frac{sigma_x+sigma_y}{2})^2 + (tow_x_y)^2 }\)

       σ_2 = \(\frac{sigma_x+sigma_y}{2} - \sqrt{(\frac{sigma_x+sigma_y}{2})^2 + (tow_x_y)^2 }\)

        σ_1 = \(\frac{15.55+0}{2} + \sqrt{(\frac{15.55+0}{2})^2 + (52.4)^2 } = 60.75 ksi\)

        σ_2 =\(-\sqrt{\left(\frac{15.55+0}{2}\right)^2\:+\:\left(52.4\right)^2\:}+\frac{15.55+0}{2} = -45.20 ksi\)

- The angle of maximum plane stress ( θ ):

       θ = \(0.5*arctan ( \frac{tow_x_y}{\frac{sigma_x-sigma_y}{2} } )= 0.5*arctan*( \frac{52.4}{7.8} ) = 40.8 deg\)

Note: The plane stresses at point D are evaluated using the following procedure given above. Due to 5,000 character limit at Brainly, i'm unable to post here.

Answer:

Step 1: Define the Problem.  

Step 2: Do Background Research. .

Step 3: Specify Requirements. .

Step 4: Brainstorm, Evaluate and Choose Solution.  

Step 5: Develop and Prototype Solution.  

Step 6: Test Solution.

Step 7: Does Your Solution Meet the Requirements?  

Step 8: Communicate Results.

can u tell me the definition tho?

palled correctly as “though” which is an alternate form of “although”) at the end is informal usage. It's better placed before “she seems better today

The technician in A is right.

A 4×4 transfer case is a portion of your differential system that allows your truck to go into four-wheel drive when travelling on paved roadways. In times of necessity, it also disengages. Though they all share certain commonalities in terms of form and functionality, there are many differences.

Transfer cases of an all-wheel drive car actually let the front and rear driveshafts turn at various rates. This will make steering simpler and help the car drive more safely on any surface.

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Answer:

Used to recall the direction a standard screw

Answer:

True

Explanation:

The development of empires in Mesopotamia had a significant impact on the region and the world as a whole. Mesopotamia was the cradle of civilization and the place where the first empires emerged. These empires were characterized by their highly organized and centralized systems of government, sophisticated legal codes, and complex economies.

The development of empires in Mesopotamia had several important impacts, including the spread of civilization, the advancement of technology, and the growth of trade and commerce. Mesopotamia was a melting pot of cultures, and the empires that emerged there played a vital role in the spread of civilization. They established trade routes that spanned the ancient world, and their technological innovations, such as the wheel and irrigation systems, had a lasting impact on human history. The development of empires in Mesopotamia also had a profound impact on the way we think about government and society.
These empires were characterized by strong central authority, and their legal codes and administrative systems set the standard for the rest of the world. In conclusion, the development of empires in Mesopotamia was a significant turning point in human history. It played a crucial role in the spread of civilization, the advancement of technology, and the growth of trade and commerce.

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Answer:

Exit temperature = 32 °C

Explanation:

We are given;

Initial Pressure;P1 = 100 KPa

Cp =1000 J/kg.K = 1 KJ/kg.k

R = 500 J/kg.K = 0.5 Kj/Kg.k

Initial temperature;T1 = 27°C = 273 + 27K = 300 K

volume flow rate;V' = 15 m³/s

W = 130 Kw

Q = 80 Kw

Using ideal gas equation,

PV' = m'RT

Where m' is mass flow rate.

Thus;making m' the subject, we have;

m' = PV'/RT

So at inlet,

m' = P1•V1'/(R•T1)

m' = (100 × 15)/(0.5 × 300)

m' = 10 kg/s

From steady flow energy equation, we know that;

m'•h1 + Q = m'h2 + W

Dividing through by m', we have;

h1 + Q/m' = h2 + W/m'

h = Cp•T

Thus,

Cp•T1 + Q/m' = Cp•T2 + W/m'

Plugging in the relevant values, we have;

(1*300) - (80/10) = (1*T2) - (130/10)

Q and M negative because heat is being lost.

300 - 8 + 13 = T2

T2 = 305 K = 305 - 273 °C = 32 °C

13000 + 300 - 8000 = T2

Answer:

4

Explanation:

The resultant force will be F = 6i-j-14k , Therefore f1 and f2 are in cartesian form.

The coordinates of the Free-body diagram points are given as

0=(0,0,0) m

A=(0.15,0,0.3) m

B=(0,-0.25,0.3) m

Therefore the position vector of OA will be.

roa = (0.15-0)i +(0-0)j +(0.3–0)k

= 0.15i +0j +0.3k

Then the position vector of OB,

rob =(0-0)i +(-0.25 - 0); +(0.3–0)k

= 0i -0.25j +0.3K

So,

The equivalent resultant force can be expressed as,

F = F1+ F2

By substituting,

6i - 3j -10k for  F1, and 2j -4K for F2.

F =6i -3j -10k +2j - 4k

= 6i - 1j -14k

Hence the resultant force is F = 6i-j-14k , which is cartesian form.

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Answer:

B....................

Answer:

Explanation:

In this geometry, the force in each string is proportional to the cosine of the angle the opposite string makes with the horizontal, and is inversely proportional to the sine of the sum of the angles.

  AC = (15 N)cos(45°)/sin(60° +45°) = (15 N)cos(45°)/sin(105°) ≈ 10.98 N

  BC = (15 N)cos(60°)/sin(105°) ≈ 7.76 N

_____

The relation described above derives from the fact that the sum of vertical forces and the sum of horizontal forces are both zero when the system is in equilibrium.

Maximum quantization error is calculated using the formula Maximum quantization error = (VH - VL)/2(2n), where n is the ADC's resolution in bits.

The largest inaccuracy that can occur corresponds to a voltage that is (1/2) of an LSB. This quantization would be the sole cause of error in the recorded samples for a perfect digital recorder. This mistake establishes the absolute upper bound on the readings' accuracy for a real digital recorder. The difference between the analog signal and the nearest available digital value at each sampling instant from the A/D converter is known as the quantization error. Quantization error also introduces noise to the sample signal known as quantization noise.

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Answer: a heathen

Explanation:

The term for a person who does not share the belief of the dominant religion of a society is "a heathen". The correct option is A.

A society is a group of people who interact with one another on a regular basis, or a large social group that shares the same spatial or social territory and is typically subject to the same political authority and dominant cultural expectations.

"A heathen" is a person who does not share the beliefs of a society's dominant religion.

The term is frequently used to describe someone who is considered uncivilized or primitive because of their religious beliefs, especially in societies where the dominant religion wields significant power and influence.

However, it is important to note that the term can be considered derogatory and offensive, and it is generally more respectful to refer to people of different religious beliefs using neutral or positive terms.

Thus, the correct option is A.

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