The primary source of chemical energy in the body is
ADP
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O DNA
O AMP
Identify the correct chemical formula. Select one: O a. K₂C₂H₂O2 0 b. K2(OH)2 O c. KCIO3 O d. 504 MATU 20 A www. wowow
Answer:
B.K2(OH)2 i think that is the answer
This particle determines what element you have - the element's identity.
Answer:
protons
These particles do not vary in quality from one element to another; rather, what gives an element its distinctive identification is the quantity of its protons, called its atomic number. Protons and neutrons contribute nearly all of an atom's mass; the number of protons and neutrons is an element's mass number
Explanation:
How does mass of an object affects velocity?
Answer: The amount of matter in a particle or object.
Which of the following equations has been balanced correctly?
O a. 2ZnS + 302 -> 2ZnO + 2SO2
O b. ZnS + 02 --> ZnO + SO2
O c. ZnS + 02 -> 2ZnO + SO2
O d. All of the above
O e. None of the above
The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal.
The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. To determine whether an equation is balanced, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's analyze each option:
(a) 2ZnS + 302 -> 2ZnO + 2SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (7 on the left side and 4 on the right side) compared to the amount of sulphur atoms (2 on each side).
(b) ZnS + 02 --> ZnO + SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (2 on the left side and 3 on the right side) compared to the sulphur atoms (1 on each side).
(c) ZnS + 02 -> 2ZnO + SO2: This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal. Therefore, option (c) is the only equation that has been balanced correctly.
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A 100.0g sample of Fe2S3 was to produce Fe2O3 and SO2 according to 2Fe2S3+9O2=2 Fe2O3+6SO2. if 57.8g of Fe2O3 was collected what is the percent yeild
The percent yield of \(Fe_2O_3\) if 57.8g was collected is 75.1%.
To calculate the percent yield, we need to compare the actual yield (the amount of\(Fe_2O_3\) collected) to the theoretical yield (the amount of \(Fe_2O_3\)that would be obtained if the reaction went to completion).
First, we need to determine the molar mass of \(Fe_2O_3\) and \(Fe_2S_3\):
Molar mass of \(Fe_2O_3\):
2(55.85 g/mol) + 3(16.00 g/mol) = 159.69 g/mol
Molar mass of\(Fe_2S_3\):
2(55.85 g/mol) + 3(32.07 g/mol) = 207.67 g/mol
Next, we can calculate the theoretical yield of\(Fe_2O_3\) using stoichiometry:
2 moles of \(Fe_2S_3\) produce 2 moles of \(Fe_2O_3\)(according to the balanced equation).
So, the molar ratio of \(Fe_2O_3\)to Fe2S3 is 2:2.
The molar mass ratio of \(Fe_2O_3\) to Fe2S3 is:
159.69 g/mol : 207.67 g/mol
To calculate the theoretical yield, we can use the following equation:
Theoretical yield of\(Fe_2O_3\) = (mass of \(Fe_2S_3\)) * (molar mass of \(Fe_2O_3\) / molar mass of \(Fe_2S_3\))
Theoretical yield of \(Fe_2O_3\) = (100.0 g) * (159.69 g/mol / 207.67 g/mol)
Theoretical yield of \(Fe_2O_3\) = 76.46 g
Now we can calculate the percent yield using the formula:
Percent yield = (actual yield / theoretical yield) * 100
Percent yield = (57.8 g / 76.46 g) * 100
Percent yield = 75.1%
Therefore, the percent yield of \(Fe_2O_3\) is 75.1%.
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3/5 of 1 1/9 + 3 1/2
Answer: 4 1/6
Explanation: 3/5x1 1/9=2/3. 2/3+3 1/2=4 1/6.
A chemist adds 255.0mL of a 1.27M sodium carbonate Na2CO3 solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask.
Answer: The mass in grams of sodium carbonate is 34.3 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
\(Molarity=\frac{n\times 1000}{V_s}\)
where,
n = moles of solute
\(V_s\) = volume of solution in ml
moles of \(Na_2CO_3\) = \(\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{106g/mol}\)
Now put all the given values in the formula of molarity, we get
\(1.27=\frac{xg\times 1000}{106g/mol\times 255.0 ml}\)
\(x=34.3g\)
Therefore, the mass in grams of sodium carbonate is 34.3 g
The glacier given in this picture is an example of which type?
Answer:
arctic glacier
Explanation:
Answer:
Explanation:
are there any choices to choose from?
if not a glacier is a type of frozen water compacted together...
if it doesnt have choices ill word it differently...
can u also tell me what is your unit about?
I need help please:(
Diatomic: Composed of two atoms. Polar: A bond with a negative end and a positive end. Nonpolar: A bond in which neither atom takes more than its share of electrons. Metallic: A type of bond that allows valence electrons to move freely among ions. Electronegativity: Determines what type of bond will form.
The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry.
Diatomic molecules consist only of two atoms, whether they are from the same or distinct chemical elements.
Since charges fluctuate, a momentary dipole moment occurs in a so-called nonpolar molecule at any given time if the charge arrangement is spherically symmetric when averaged across time.
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How many liters of O2(g) at STP are evolved when 3.25 g of KNO3 decompose to KNO2 (s) and O2(g)?
2 KNO 3 (s) <=> 2KNO2 (s) + 02 (g)
Answer:
0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP
Explanation:
The balanced chemical equation for the decomposition of KNO3 is:
2 KNO3 (s) → 2 KNO2 (s) + O2 (g)
From this equation, we can see that 2 moles of KNO3 produce 1 mole of O2. Therefore, we need to calculate the number of moles of KNO3 we have and use the mole ratio to find the number of moles of O2 produced.
First, we need to convert the mass of KNO3 given to moles:
moles of KNO3 = mass of KNO3 / molar mass of KNO3
The molar mass of KNO3 is 101.1 g/mol (39.1 g/mol for K, 14.0 g/mol for N, and 3 x 16.0 g/mol for 3 O atoms), so we have:
moles of KNO3 = 3.25 g / 101.1 g/mol = 0.0321 mol
Now we can use the mole ratio from the balanced equation to find the number of moles of O2 produced:
moles of O2 = 0.5 x moles of KNO3
moles of O2 = 0.5 x 0.0321 mol = 0.01605 mol
Finally, we can convert the number of moles of O2 to volume at STP using the ideal gas law:
V(O2) = n x RT/P = (0.01605 mol)(0.0821 L·atm/(mol·K) x 273.15 K)/(1 atm) = 0.359 L
Therefore, 0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP.
calculate the number of carbon hydrogen and oxygen atoms in 1.5 gram of glucose
The number of atoms :
C = 6 x 5 x 10²¹ = 3 x 10²²
H = 12 x 5 x 10²¹ = 6 x 10²²
O = 6 x 5 x 10²¹ = 3 x 10²²
Further explanationGiven
1.5 g glucose(C₆H₁₂O₆)
Required
The number of atoms
Solution
mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :
mol = mass : MW
mol = 1.5 : 180
mol = 0.0083
Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹
There are 6 C, 12 H and 6 O, so number or atoms :
C = 6 x 5 x 10²¹ = 3 x 10²²
H = 12 x 5 x 10²¹ = 6 x 10²²
O = 6 x 5 x 10²¹ = 3 x 10²²
Read the following statement:
The amount of force acting on an object is equal to its mass times its acceleration.
Does the statement describe a scientific law?
No, because it is applicable to all cases in the natural world
Yes, because it is applicable to just a few cases in the natural world
No, because it describes the relationship between force and acceleration
Yes, because it describes how mass and acceleration affect force
Answer:
D
Explanation:
the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of an object
Which one of the following substances is a liquid fuel used in rocket engines? A) Potassium perchlorate B) Sodium nitrate C) Ammonia D)
• The engineers uses ,Hydrogen-fueled engines ,, that uses ,ammonia as the carrier ,or as the as a propellent .
• Ammonia constitutes of a ,large hydrogen weight ,, this helps in providing a ,source of hydrogen for fuel cells,.
apply chemical models to demonstrate the organization of the elements in the periodic table
Answer:
apply chemical models to demonstrate the organization of the elements in the periodic table
Explanation:
Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.
Objective(s): In your own words, what was the purpose of this lab?
Hypothesis: In this section, please include the if/then statements you developed during your lab activity.
These statements reflect your predicted outcomes for the experiment.
Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of
For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2
What are the phenotype ratios from the test crosses?For Test One:
Parent 1: FF (homozygous dominant for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff = 1 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 2 : 0 or 100% short fur
For Test Two:
Parent 1: Ff (heterozygous for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff : ff = 1 : 2 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur
For Test Three:
Parent 1: ff (homozygous recessive for long fur)
Parent 2: ff (homozygous recessive for long fur)
The Punnett square for this cross will give the following genotype ratios:
ff : ff = 1 : 0
And the corresponding phenotype ratios will be:
Short fur : Long fur = 0 : 2 or 100% long fur
For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.
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what energy is stored
Answer: potential energy is stored
Explanation:
Enter your answer in the provided box. An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 121.00 u and 123.00 u, with natural abundances of 90% and 10%, respectively. Calculate its average atomic mass. Report your answer to 2 decimal places.
Answer:
Kk I got it now but I think it to be great
7.5 L of a gas at 2 ATM and a temperature of 75°C is changed and volume to 3.4 L and a pressure of .5 ATM what is the new temperature
Answer:
Explanation:
Combined Gas Law
T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C
List five general properties of organic
Compound
Answer:
Five general properties of organic compounds:
Organic compounds include complex structures and high molecular weights.Organic compounds have low melting points and boiling points. They are volatile in nature. They are generally insoluble in water but soluble in organic solvents. They are poor bad conductors of electricity.Balance this chemical equation?
?Fe2+ ?Na3PO4 = ?Fe3(PO4)2 + ?Na+
The balanced chemical equation for the reaction between Fe2+ and Na3PO4 is:
\(3Fe2+ + 2Na3PO4\) → \(Fe3(PO4)2 + 6Na+\)
First, we need to determine the chemical formula of the products based on the charges of the reactants. Fe2+ has a charge of +2, while PO43- has a charge of -3. To balance the charges, we need two Fe2+ ions for every three PO43- ions. This gives us the formula Fe3(PO4)2 for the product.
Next, we need to balance the equation by making sure that the same number of atoms of each element are present on both sides of the equation. To do this, we can start by balancing the phosphorus atoms. There are two phosphorus atoms on the left side (2x PO43-), so we need two Fe3(PO4)2 molecules on the right side to balance this. This gives us:
3Fe2+ + 2Na3PO4 → 2Fe3(PO4)2 + ?
Next, we can balance the sodium atoms by adding six Na+ ions to the right side:
3Fe2+ + 2Na3PO4 → 2Fe3(PO4)2 + 6Na+
Finally, we can check that the equation is balanced by counting the number of atoms of each element on both sides of the equation. The equation is now balanced with respect to the number of atoms of Fe, P, Na, and O.
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What has a higher boiling point C2H4O or CH3OH
Answer:
Explanation:
i wish i can help
Notice
10 January 2018
Gift A Tree
This is to inform students of Class XII to assemble in the ground on Saturday, 31 January
2018 at 8:00 in the morning to participate in a Tree Plantation Ceremony being organised
by the Environment Club as a part of the Farewell Programme.
Amita/Amit
Secretary, Environment Club)
Exercises
As the Head Boy/ Head Girl, Central Public School, draft a notice informing all students about
a wrist watch that was found near the school canteen.answar
Answer:
gahwidsuacsgsuacayau1joagavahiq8wtw8quavakiafabajozyavqhaigavayquata
Explanation:
vahaiqgahiavavqugafayqigqvsbjsiagwyeiwvvs
What are the possible values of 1 and m for
n=4 ?
Answer:
If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?
In the laboratory, a general chemistry student measured the pH of a 0.313 M aqueous solution of acetylsalicylic acid (aspirin), HC9H7O4 to be 2.031. Use the information she obtained to determine the Ka for this acid.
Answer: \(K_a\) for the acid is \(2.7\times 10^{-4}\)
Explanation:
\(C_9H_7O_4H\rightarrow H^+C_9H_7O_4^-\)
c 0 0
\(c-c\alpha\) \(c\alpha\) \(c\alpha\)
So dissociation constant will be:
\(K_a=\frac{(c\alpha)^{2}}{c-c\alpha}\)
Give c= 0.313 M and \(pH\) = 2.031
\((\alpha)=0.030\)
\([H^+]=c\times \alpha\)
\([H^+]=0.500\times 0.030=0.015\)
Also \(pH=-log[H^+]\)
\(2.031=-log[H^+]\)
\([H^+]=0.009\)
[ \([H^+]=c\alpha\)
\(c\alpha=0.009\)
Putting in the values we get:
\(K_a=\frac{(0.009)^2}{(0.313-0.009)}\)
\(K_a=\frac{(0.009)^2}{(0.304)}=2.7\times 10^{-4}\)
\(K_a\) for the acid is \(2.7\times 10^{-4}\)
Name the following compounds
Answer:
What are the compounds
Explanation:
Answer:
Where is the picture?
Explanation:
14. What type of materials are spun together to make yarns?
Answer:
cotton
Explanation:
which is typically spun into fine yarn for mechanical weaving or knitting into cloth.
How do you calculate the number of protons, neutrons, and electrons in an element?
Answer:
The first thing you will need to do is find some information about your element. Go to the Periodic Table of Elements and click on your element. If it makes things easier, you can select your element from an alphabetical listing.
Number of Protons = Atomic Number
Number of Electrons = Number of Protons = Atomic Number
Number of Neutrons = Mass Number - Atomic Number
For krypton:
Number of Protons = Atomic Number = 36
Number of Electrons = Number of Protons = Atomic Number = 36
Number of Neutrons = Mass Number - Atomic Number = 84 - 36 = 48
Explanation:
hope this helps, have a good day :-)
The ages of rocks that contain fossils can be determined using the isotope 87Rb. This isotope of rubidium undergoes beta decay with a half‑life of 4.75×1010y. Ancient samples contain a ratio of 87Sr to Rb87 of 0.0205. Given that 87Sr is a stable product of the beta decay of 87Rb, and assuming there was originally no 87Sr present in the rocks, calculate the age of the rock sample. Assume that the decay rate is constant over the relatively short lifetime of the rock compared to the half-life of 87Rb.
The calculate the age of the rock sample values, the age of the rock sample can be determined.
we can use the concept of radioactive decay and the ratio of 87Sr to 87Rb. Since 87Sr is a stable product of the beta decay of 87Rb, the increase in the ratio of 87Sr to 87Rb over time reflects the decay of 87Rb.
The ratio of 87Sr to 87Rb in ancient samples is given as 0.0205. This means that for every 0.0205 moles of 87Rb, there is one mole of 87Sr.
Since the half-life of 87Rb is 4.75×10^10 years, after each half-life, half of the 87Rb would have decayed into 87Sr. Therefore, the ratio of 87Sr to 87Rb increases by a factor of 2.
To determine the age of the rock sample, we can calculate the number of half-lives that have occurred based on the change in the ratio. The ratio of 0.0205 corresponds to 1 half-life, 0.041 corresponds to 2 half-lives, 0.082 corresponds to 3 half-lives, and so on.
By taking the logarithm of the ratio change and dividing it by the logarithm of 2 (since the ratio doubles with each half-life), we can find the number of half-lives.
Using this information, the age of the rock sample can be calculated as follows:
Age (in years) = number of half-lives × half-life of 87Rb
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The sound of a bus passing by is an example of an (open, efficient) system because some chemical energy is transformed to sound and other energy is transformed to (thermal, electric) energy and mechanical energy. Which two is it. Need ASAP
Answer:
Explanation:
I hope it helps you.