Which statement is true of the following function?
f(x) = (x-7)^2 + 9

a. The vertex is in quadrant IV and the graph opens down.
b. The vertex is in quadrant IV and the graph opens up.
c. The vertex is in quadrant II and the graph opens up.
d. The vertex is in quadrant I and the graph opens up.

Answer:

4x - 3y = 0

Step-by-step explanation:

The angle between the radius and the tangent at P is right

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 4y + 3x = 25 into this form

Subtract 3x from both sides

4y = - 3x + 25 ( divide all terms by 4 )

y = - \(\frac{3}{4}\) x + \(\frac{25}{4}\) ← in slope- intercept form

with slope m = - \(\frac{3}{4}\)

Given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{-\frac{3}{4} }\) = \(\frac{4}{3}\) , thus

y = \(\frac{4}{3}\) x + c ← is the partial equation

To find c substitute P(3, 4) into the partial equation

4 = 4 + c ⇒ c = 4 - 4 = 0

y = \(\frac{4}{3}\) x ← equation of radius in slope- intercept form

Multiply through by 3

3y = 4x ( subtract 3y from both sides )

4x - 3y = 0 ← equation of radius in standard form

So the frequency of individuals with red hair in population b after 10 generations of migration is approximately 0.02%.

We need to use the Hardy-Weinberg equation, which describes how the frequencies of alleles in a population will change over time.
The equation is:
p^2 + 2pq + q^2 = 1
Where:
p = frequency of one allele
q = frequency of the other allele
p^2 = frequency of homozygous dominant individuals
2pq = frequency of heterozygous individuals
q^2 = frequency of homozygous recessive individuals
In this case, the recessive trait is red hair, so we'll use q to represent the frequency of the recessive allele.
In population a, q = 0.49, so p (the frequency of the dominant allele) = 1 - q = 0.51.
In population b, q = 0.25, so p = 0.75.
After the emigrants from population a migrate to population b, the new frequency of the recessive allele in population b will be:
q' = (0.1 x 0.49) + (0.9 x 0.25) = 0.286
This is the new value of q after one generation of migration. To calculate the frequency of red-haired individuals after 10 generations, we need to use the equation:
q^10 = (0.286)^10 = 0.0002
So the frequency of individuals with red hair in population b after 10 generations of migration is approximately 0.02%.
The frequency of individuals with red hair in population b after 10 generations of migration is approximately 0.02%. This is based on the assumption that the emigrants from population a mate randomly with members of population b and that the population sizes remain constant over time.
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In circle s TQ = 92°. The value of x is approximately 4.0 to the nearest tenth.

In circle s, TQ = 92°. Solve for x if m TRQ = (11x - 40)°.We are required to find the value of x. To solve for x, we need to use the following formula of the angle in a semi-circle. Since we know that TQ is equal to 92°, we can find the value of the angle TRQ. We know that the angle TRQ is a vertical angle to the angle TQ. Therefore, the angle TRQ is also equal to 92°.

Since we know that angle TRQ is a straight angle, which means the sum of angle TPQ and angle PQR would equal 180°. Hence,

m TRQ + m PQR = 180°92 + m PQR = 180°m PQR = 180° - 92° = 88°

Now we know that the angle PQR is equal to 88°, and the angle TRQ is equal to 92°, we can find the value of the angle TPQ.

m TPQ = 180° - m TRQ - m PQRm TPQ = 180° - 92° - 88°m TPQ = 0°

Since m TPQ is equal to zero degrees, this means that TPQ is tangent to the circle, and TR is the radius of the circle. Therefore, angle TRQ is equal to half of the angle TQ. So, we can use the following formula to find x:

(11x - 40)° = (92°) / 2(11x - 40)° = 46°11x - 40 = 4.18181818181818211x = 44.18181818181818x

= 4.017828981821653.

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When comparing variables x and y that are in the list '(AB), the comparison function we use is EQ.

Here's an explanation:

In Lisp, the EQ operator compares whether the two arguments are the same memory location.

EQV, on the other hand, checks whether the two values being compared are equivalent to each other.

For example, EQV will return true for two identical strings, while EQ will not.

The comparison function that should be used to compare variables x and y, which are both in the list '(AB), is EQ.

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Answer:

A -12x+212

B 14x+30

C

Mikaela

0 212

1- 200

2- 188

3- 176

4- 164

5- 152

6- 140

7- 128

8- 116

Matthew

0- 30

1- 44

2- 58

3- 72

4- 86

5- 100

6- 114

7- 128

8- 142

D In 7 months

The consumer surplus is $5.

Consumer surplus is defined as the amount saved based on the estimated value and actual paid price. It is the difference between the amount that customer wants to pay and the amount that customer has to pay based on the final price.

Leon is willing to pay $10. The discount offered of $10 item is 50%. Hence, the final price will be -

Final price = 10 - 50%×10

Final price = 10 - 5

Final price = 5

Surplus amount = 10 - 5

Surplus amount = $5

Thus, the surplus amount for Leon is $5.

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The complete question is -

Determine the amount of consumer surplus generated: Leon goes to the clothing store to buy a new T-shirt, for which he is willing to pay up to $10. He picks out one he likes with a price tag of exactly $10. When he is paying for it he learns that the T-shirt has been discounted by 50%

So to find any last digit of 3^2011 divide 2011 by 4 which comes to have 3 as remainder. Hence the number in units place is same as digit in units place of number 3^3. Hence answer is 7.

Answer:

22 bags like i said before! there is an explanation on that one as well if you wanna go and see

Step-by-step explanation:

Answer:

You can use option (D) to find the area of rectangle

(D) y = - x²+32x

Step-by-step explanation:

If you can substitute your values you can find your answer

THANK YOU....

PLZZ GIVE ME A BRAINLIEST TAG

The expression for the given rectangle with width x and area y is\(y = -x^{2} +32\)

it is given that

area of the rectangle = y

width of the rectangle = x

so the length of the rectangle will be = area/width = \(\frac{y}{x}\)

perimeter = 64

Perimeter is the sum of all four sides of the rectangle.

we can say that,

2(length + breadth) = 64

\(2( \frac{y}{x} + x)=64\\\\\)

\(\frac{y}{x} + x= 32\)

\(\frac{y + x^{2} }{x} = 32\)

\(y+x^{2} = 32x\)

\(y = -x^{2} +32\)

therefore, the expression for the area of the rectangle,

\(y = -x^{2} +32\)

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Yes, the sample size would be large enough if the population is school-aged children and young adults in the United States as this is a simple random sampling.

Simple random sampling is used for randomly selecting the sample size for research. No member in the population has a higher chance in comparison to others for selection in sampling. Every individual has an equal chance to be a part of the sample for the study. This is a type of probability sampling method.

The probability sampling method states that every individual has a fair and equal chance to be selected as a research sample. It includes simple random sampling, stratified sampling, systematic sampling, and cluster sampling. Here the researchers have picked around 150 students and young adults which is an appropriate amount of simple random sample for the study.

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The graph of f(x) = x^3 -6x^2 + 4x +1 hits 3 times to the x-axis

Hence, option (D) is the correct choice.

We have the function:

f(x) = x^3-6x^2+4x+1

The values of the variable in a function that cause the function to equal zero are known as the zeros of the function. The places on the x-axis where the graph crosses the x-axis are known as a function's zeros graphically. In other words, we may say that a function's zeros are the graph's x-intercepts.

The zeros of the function will be:

x^3-6x^2+4x+1 = 0

Since the last term is positive, so (x-1) will be the factor of the above equation.

Factorising, we will get,

(x-1)(x^2-5x-1)=x^3-6x^2+4x+1

So, one factor will be x = 1

Now solving the quadratic equation,

The roots will be: \(x^2 = \frac{( 5 \pm \sqrt 29)}{2}\)

So, the value of both roots will be: (x-5.19)(x+0.192)

Therefore, the graph will hit x-axis at these three points.

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Answer:

To make 3 glasses of orange squash you need 825 ml of water and 75 ml of orange cordial

Step-by-step explanation:

Answer:17

Step-by-step explanation:

The speed of the object is 12121 m per week.

What does it mean to do speed?

The object is moving at a speed of 2 centimeters every 7 seconds.

We need to find the speed in m per week.

2 cm = 0.02 m

1 week = 604800 s

7 s =  \(1.65 * 10^{-6} week\)

Speed = distance/time

So,

\(v = \frac{0.02 m}{1.65 * 10^{-6 } week}\)

\(v = 12121.21 m/ week\)

or v = 12121 m/ week

So, the speed of the object is 12121 m per week.

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The set of points that can be the other x-intercepts of the graph of f(x) is (-6, 0)

The x-intercept is given as:

x-intercept = (6, 0)

A function is said to be an even function, if the following is true

f(x) = f(-x)

This means that

If the x-intercept of the even function is (6, 0), then (-6, 0) is another x-intercept of the function

This is so because:

f(x) = f(-x) implies that f(6) = 0 and f(-6) = 0

Hence, the set of points that can be the other x-intercepts of the graph of f(x) is (-6, 0)

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Answer:

12a. Addition = 7y⁵ + 7y³ – 6y – 5

12b. Subtraction = – y⁵ – 3y³ + 8y + 11

13a. Addition = 5x⁴ + x³ – 6x² + 8x + 17

13b. Subtraction = – x⁴ – 9x³ –6x² + 8x + 3

14a. Addition = – 2b⁴ + b³ – 11b² – 1

14b. Subtraction = 4b⁴ + 7b³ – b² + 8b – 1

15a. Addition = m⁵ + m⁴ + m³ + m²

15b. Subtraction = m⁵ – m⁴ – m³ – m² – 10

16a. Addition = 4x⁴ + 12x³ + 18x² + 16x + 4

16b. Subtraction = 4x⁴ – 4x³ + 14x² – 16x + 4

Step-by-step explanation:

12a. Addition

.. 3y⁵ + 2y³ + y + 3

+ (4y⁵ + 5y³– 7y – 8)

————————————

= 7y⁵ + 7y³ – 6y – 5

12b. Subtraction

.. 3y⁵ + 2y³ + y + 3

– (4y⁵ + 5y³– 7y – 8)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – y⁵ – 3y³ + 8y + 11

13a. Addition

.. 2x⁴ – 4x³ – 6x² + 8x + 10

+ (3x⁴ + 5x³ +...................+ 7)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 5x⁴ + x³ – 6x² + 8x + 17

13b. Subtraction

.. 2x⁴ – 4x³ – 6x² + 8x + 10

– (3x⁴ + 5x³ +...................+ 7)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – x⁴ – 9x³ – 6x² + 8x + 3

14a. Addition

...... b⁴ + 4b³ – 6b² + 4b – 1

+ (– 3b⁴ – 3b³ – 5b² – 4b)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – 2b⁴ + b³ – 11b² – 1

14b. Subtraction

...... b⁴ + 4b³ – 6b² + 4b – 1

– (– 3b⁴ – 3b³ – 5b² – 4b)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4b⁴ + 7b³ – b² + 8b – 1

15a. Addition

... m⁵ + m³ – 5

+ (m⁴ + m² + 5)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= m⁵ + m⁴ + m³ + m²

15b. Subtraction

... m⁵ + m³ – 5

– (m⁴ + m² + 5)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= m⁵ – m⁴ – m³ – m² – 10

16a. Addition

.... 4x⁴ + 8x³ + 16x² + 4

+ (4x³ + 2x² + 16x)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4x⁴ + 12x³ + 18x² + 16x + 4

16b. Subtraction

.... 4x⁴ + 8x³ + 16x² + 4

– (4x³ + 2x² + 16x)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4x⁴ – 4x³ + 14x² – 16x + 4

Answer:

It's a 1/6 chance.

Step-by-step explanation:

Answer:

Each term in pattern B is 9 less than the corresponding term in pattern A.

Answer:

Step-by-step explanation:

See attached worksheet

Square - a rectangle (4 sided shape) whose sides are equal length

Rectangle - a polygon that has 4 sides and 4 right angles - two pairs of parallel lines

Triangle: a polygon with 3 sides and 3 angles. The angles add up to a total of 180 degrees. There are 3 kinds of triangles

Parallelogram - a polygon with 4 sides, 2 pair of parallel lines, 2 obtuse angles and 2 acute angles.  

Trapezoid - a polygon with 4 sides and only 1 pair of parallel lines

Circle: a shape with no sides, angles, or parallel lines. Any point in the circumference to the center of the circle is the same length.

Happy to help!

Answer:

1). Triangle - Has 3 equal sides and angles of 60°.

2). Square - A quadrilateral with 4 equal sides and angles (all the angles are right angles).

3). Rectangle - A quadrilateral with 2 equal parallel sides horizontal and vertical. All the angles are equal because they are right angles.

4). Pentagon - It has 5 equal sides with equal angles of 108°.

5). Hexagon - It has 6 equal sides with equal angles of 120°.

PROPERTIES OF A CIRCLE:

It has no sides with no angles. The radius in any direction from the point are of the same length.

Answer:

1) FAP=70

2)DAB=90

The compound inequality for the given situation is $2.75x + $4.25y ≥ $65 and $2.75x + $4.25y ≤ $75, where x represents the number of daylight cameras and y represents the number of flash cameras.

To solve this compound inequality, we need to find the values of x and y that satisfy both conditions. The inequality $2.75x + $4.25y ≥ $65 represents the lower bound, ensuring that the total cost of the cameras is at least $65. The inequality $2.75x + $4.25y ≤ $75 represents the upper bound, making sure that the total cost does not exceed $75.

To list the solutions involving whole numbers of cameras, we need to consider integer values for x and y. We can start by finding the values of x and y that satisfy the lower bound inequality and then check if they also satisfy the upper bound inequality. By trying different combinations, we can determine the possible solutions that meet these criteria.

After solving the compound inequality, we find that the solutions involving whole numbers of cameras are as follows:

(x, y) = (10, 10), (11, 8), (12, 6), (13, 4), (14, 2), (15, 0), (16, 0), (17, 0), (18, 0), (19, 0), (20, 0).

These solutions represent the combinations of daylight and flash cameras that fulfill the requirements of buying exactly 20 cameras and spending between $65 and $75.

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Answer:

I don't know but I will advise you to use microsoft maths solver

Answer:

x+-3/4

Step-by-step explanation:

-2/3(2)+x+7/3/4

=-4/3+(4/3+7/12)

x+-3/4

ARCH (Autoregressive Conditional Heteroscedasticity) models are estimated using Maximum Likelihood (ML) estimation. Regarding Question 7, if the model has the given conditional variance function, it corresponds to an ARCH(3) model.

In the case of ARCH models, the ML estimation process involves the following steps:

1. Specify the ARCH model: Determine the appropriate order of the ARCH model by analyzing the autocorrelation and partial autocorrelation functions of the squared residuals (or other suitable diagnostic tests). For example, an ARCH(3) model implies that the conditional variance at time t depends on the squared residuals at time t-1, t-2, and t-3.

2. Formulate the likelihood function: The likelihood function specifies the probability of observing the given data under the assumed ARCH model. In ARCH models, the likelihood function is constructed based on the assumption that the errors follow a normal distribution with mean zero and a time-varying conditional variance.

3. Maximize the likelihood function: The goal is to find the parameter values that maximize the likelihood function. This is typically achieved using numerical optimization techniques, such as the Newton-Raphson algorithm or the BFGS algorithm.

4. Estimate the parameters: Once the likelihood function is maximized, the estimated parameter values are obtained. These estimates represent the best-fitting values that maximize the likelihood of observing the given data.

Therefore, the answer to Question 7 is: ARCH(3).

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Answer:

what is the question?

Step-by-step explanation:

i don't see a problem or answer choices

Answer:

It is Option D. 120 x^3 y^7

Option D is correct i.e. the eighth term of the given expansion is \(120x^{3} y^{7}\).

The Binomial Theorem is the method of expanding an expression that has been raised to any finite power.

A binomial expression is an algebraic expression that contains two dissimilar terms .

\(T_{r+1} =nC_{r} x^{n-r} y^{r}\)

According to the given question

We have,

The binomial expansion \((x+y)^{10}\)

Therefore,

The eighth term of the given binomial expansion is given by

\(T_{7+1} = 10C_7x^{10-7} y^{7} \\T_{8} = \frac{10!}{7!3!} x^{3} y^{7}\)

\(T_{8} = \frac{(10)(9)(8)(7!)}{7!(3)(2)(1)} x^{3} y^{7}\)

\(T_{8} = 120x^{3} y^{7}\)

Hence, option D is correct. i.e. the eighth term of the given expansion is \(120x^{3}y^{7}\).

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Answer:

I believe it's $130

Step-by-step explanation:

Well first I subtracted the amount paid from the total cost and I got $390. to pay the rest in 3 equal payments I just divided it by 3 and got $130 I'm not completely sure but this is just how I solved it

Answer:

£130

Step-by-step explanation:

Assuming I understood your question correctly, you have a television which costs in full, £1290 including all applicable VAT and tax. You paid £900 up front, which lowers your overall cost to pay it back down to £390. The rest you pay over the course of an unknown time period in equal payments.

In a real-world scenario, we would take interest into account but you provided none so lets assume this is a utopia where credit needs no interest.

In which case we do simple division, of 390/3 which is a nice round 130.

Simple! You pay £130 per payment.