Which of the following quantities is NOT needed to calculate wavelength from a double-slit experiment when using the small angle simplification?(A) the distance between the slits(B) the distance from the slits to the screen(C) the distance between the center bright band and the first bright band(D) the angle formed by the paths from the slits to the center band and the first bright band

Answer:

It is importants because it facilitates the monitoring and analysis of global earthquakes and other sources of seismic activity.

Explanation:

ANSWER:

40.17 kg

STEP-BY-STEP EXPLANATION:

Given:

m1 = 3548 kg

V1 = -0.03 m/s

V2 = 2.65 m/s

We apply law of conservation of linear momentum:

We replace and calculate the mass as follows:

Therefore the mass is equal to 40.17 kg

(a) Let the base of the cliff be the origin, so that the rock's height y at time t is

y = h + (8.19 m/s) t - 1/2 gt²

where h is the height of the cliff. The rock hits the ground when y = 0. Solve for h when t = 2.37 s :

0 = h + (8.19 m/s) (2.37 s) - 1/2 (9.80 m/s²) (2.37 s)²

⇒   h ≈ 8.11 m

(b) If the rock is thrown straight down with the same speed, its height at time t would be

y = 8.11 m - (8.19 m/s) t - 1/2 gt²

Solve for t when y = 0 (use the quadratic formula and ignore the negative solution) :

t ≈ 0.699 s

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

Given that a steel beam is winched up to the top floor of a new buiding, let's determine the new foem of energy.

Mechanical energy is the sum of kinetic energy and potential energy.

The steel beam currently has a mechanical energy. Since the steel beam is now at the top of a new building, the mechanical energy is being converted to potential energy.

Potential energy is the energy held by an object due to its position relative to other objects. It is the energy stored from an object.

Since the steel beam is now at the top of the building, it has the potential to fall.

Therefore, the mechanical energy is now being converted to potential energy.

ANSWER:

Potential energy

Answer:

the answer is A The potential energy in the system is greatest at X.

Explanation:

i know things

The derivation of the  total energy Kinetic energy plus potential energy in rolling motion is shown in the image attached.

In rolling motion, the total energy is the sum of the kinetic energy and the potential energy. Rolling motion is a combination of rotational and translational motion, and the energy of rolling can be expressed as follows:

Total energy = Kinetic energy + Potential energy

The derivation has been done and shown in the image attached here.

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Answer:

A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes

Explanation:

Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.

The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.

As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.

The potential energy is the energy due to the position of a body.

Answer: Patsy is eager to learn how to bake a cake but does not know how to do it.

Explanation: i picked this and it is correct, you’re welcome:)

Answer:

hindi ko maintindihan teh

The Correct choice is C. pebbles

Answer:

pebbles

Explanation:

because it is not soluble in water

The pressure exerted when a force of 1000 N acts on an area of 0.25 cm² is 40,000,000 Pa or 40,000,000 N/m².

To calculate the pressure exerted, we can use the formula:

Pressure = Force / Area

Given that the force is 1000 N and the area is 0.25 cm², we need to convert the area to square meters to match the unit of force (Newtons per square meter or Pascal).

1 cm² = 0.0001 m² (conversion factor)

0.25 cm² = 0.25 * 0.0001 m² = 0.000025 m²

Now we can calculate the pressure:

Pressure = 1000 N / 0.000025 m²

Pressure = 40,000,000 N/m² or 40,000,000 Pascal (Pa)

Therefore, the pressure exerted when a force of 1000 N acts on an area of 0.25 cm² is 40,000,000 Pa or 40,000,000 N/m².

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The variables that Madison will deal with in her experiment are as follows:

An experiment is a test under controlled conditions made to either demonstrate a known truth or examine the validity of a hypothesis.

According to this question, Madison wants to conduct an experiment to validate her hypothesis that states: increased concentrations of salt in the air speeds the corrosion of certain metals.

To do this, Madison will deal with the following variables;

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Answer:

C) Momentum

Explanation:

Refers to an objects mass in motion.

Answer:

the three possible movements by the change in electric potential energy (Ue) of the object are NORTH EAST SOUTH

Explanation:

This is because When the object moves south, the force is in the direction of the displacement, and positive work is done with decreasing electric potential energy.

The opposite is true if the particle moves north—that is, negative work is done with increasing electric potential energy.

No work is done and the electric potential energy is constant if the motion is perpendicular to the electric field.

The bike is travelling at 22.5 m/s after 2.5 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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Answer:

The concentrations of the reactants and the products. The temperature of the system. The partial pressures of the gases involved (if any)

Explanation:

Answer:

As frequency increases, wavelength decreases

Explanation:

Both quantities are inversely proportional

Answer:

meter

Explanation:

please mark as brainlist answer

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. The magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².

To determine the magnitude of the angular acceleration of the wheel, we need to first calculate the change in angular velocity and the time taken to come to rest. Then we can use these values to find the angular acceleration.

Calculate the initial angular velocity:

The initial linear velocity of the bicycle wheel is given by the formula v = ω * r, where v is the linear velocity, ω is the angular velocity, and r is the radius of the wheel.

The radius of the wheel is half the diameter, so r = 0.68 m / 2 = 0.34 m.

Given the initial linear velocity vi = 8.40 m/s, we can calculate the initial angular velocity ωi:

vi = ωi * r

ωi = vi / r

Calculate the final angular velocity:

The final angular velocity of the wheel is 0 rad/s since it comes to rest.

ωf = 0 rad/s

Calculate the change in angular velocity:

The change in angular velocity (Δω) is given by the formula Δω = ωf - ωi.

Δω = 0 - ωi

Calculate the time taken to come to rest:

To calculate the time taken to come to rest, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given the initial velocity vi = 8.40 m/s, final velocity vf = 0 m/s, and distance d = 115 m, we can calculate the acceleration a:

vf = vi + at

0 = 8.40 + a * t

We also know that the distance traveled d is related to the initial and final velocities and the time by the formula d = (vi + vf) / 2 * t:

d = (vi + vf) / 2 * t

115 = (8.40 + 0) / 2 * t

From the two equations above, we can solve for the acceleration a and the time t.

Calculate the angular acceleration:

The angular acceleration (α) is given by the formula α = Δω / t.

α = Δω / t

Substitute the values for Δω and t and calculate the angular acceleration.

Therefore, the magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².

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Answer:

Explanation:

15 km(1000 m / km) / (20 min(60 s/min)) = 12.5 m/s

Answer:

Explanation:

Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.

To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:

1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.

2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.

3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.

4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.

By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.

Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.

The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.

In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.

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Answer:

-0.704 m/s

Explanation:

The conservation of momentum demands that since the child + boat + box system is isolated, the initial momentum must equal the final momentum.

Now since initially, everything is at rest, the initial momentum of the system is zero.

The final momentum of the system is

where

m_c = mass of the child

m_b = mass of the boat

m_box mass of the boat

v1 = belcity of child + boat

v2 = veloctiy of the box.

Equating the initial momentum to the final momentum gives

Now in our case

m_c = 37 kg

m_b = 67 kg

v1 = unknown

m_box = 5.9 kg

v2 = 12.4

Therefore, the above equation gives

solving for v1 gives

which evaluates to give (rounded to the nearest hundredth)

which is our answer!

The given statement '' the four principal types of space our text names are: deep space, flat space, split space, and ambiguous space'' is false as the four principal types of space our text names are: atmospheric space, void space, domestic space, and liminal space.

Atmospheric space is the space between objects, where the environment can affect the objects in it. Void space is the empty space that can be found in a room or an area, but can also be found in one’s mind.

Domestic space is the space we create at home, and it is a space that reflects our identity and emotions. Finally, liminal space is a space between two states, where something is neither this nor that and can be seen as a threshold.

All of these spaces are integral to understanding how humans interact with the world, and they all contribute to the overall experience of living.

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Answer:

a. 1.5 m/s

Explanation:

We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:

\(m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\\)

where,

m₁ = mass of ball = 1.6 kg

m₂= mass of block = 0.8 kg

u₁ = initial speed of ball = 0 m/s

u₂ = initial speed of block = 0 m/s

v₁ = final speed of ball = ?

v₂ = final speed of block = 3 m/s

Therefore,

\((1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\\)

v₁ = 1.5 m/s

Therefore, the correct option is:

a. 1.5 m/s

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the quick check

Answer:

A

Explanation:

hope this helps