Which of the following materials commonly used in electronic devices is classified as a semiconductor

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

1/2

Explanation:

Given

c=distance

a= length

e= c/a

3/6

e= 1/2 or 0.5

These waves are traveling at the same speed.  The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."

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The statement that correctly defines an evolutionary stage of a star like the sun is that after leaving the main sequence, its core is stable due to electron degeneracy. That is option C.

The stages of the life cycle of a star include the following:

The evolutionary stage is also called the main sequence stage of the life cycle of the star.

In this stage, the core temperature reaches the point for the fusion to occur whereby the protons of hydrogen are converted into atoms of helium. This leads to the stability of the core of the newly formed start due to electron degeneracy.

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Answer:

true

Explanation:

because this is a favorite game i i think it us better

Answer:

Explanation:

W = Fd = 310(210) = 65,100 J

W = KE = ½mv²

v = √(2KE/m) = √(2(65100)/132) = 31.40642... = 31.4 m/s

W = PE = mgh = mgdsinθ

d = W/mgsinθ = 65100/(132(9.81)sin23) = 128.66488... = 129 m

Answer:

a. WD = 65100 J

b. v = 31.4 m/s

c. 129 m

Explanation:

WD = work done (Nm or J)

F = force (N) = 310

d = distance (m) = 210

P = power (W or J/s)

m = mass (kg) = 132

a = acceleration (m/s²)

v = final velocity (m/s)

u = initial velocity (m/s)

s = displacement (m) = 210

\(d_{i}\) = distance up incline (m)

Θ = angle of incline (°) = 23

g = gravity (m/s²) = 9.81

O = opposite

H = hypotenuse

Formulas:

WD = F.d

F (or net F) = ma

v² = u² + 2as

sin(Θ) = O/H

a.

WD = F.d

WD = 310 × 210

WD = 65100 J

b.

Ignoring friction and air resistance:

net F = 310

F = ma:

310 = 132a

a = 2.34848485

v² = u² + 2as:

v² = (0)² + 2(2.348...)(210)

v² = 986.363637

v = 31.4064267 → 31.4 m/s

c.

Coasting means no cycling by cyclist so no F produced up the incline

On incline:

F parallel to incline due to gravity = -132g.sin(23)

F parallel to incline due to gravity = -132(9.81)(0.390731128)

F parallel to incline due to gravity = -505.965552

F = ma:

net F parallel to incline = -505.965552

\(-505.965552 = 132a_{i}\)

\(a_{i} = -3.83307236\)

\((v_{i}) ^{2} = (u_{i})^{2} + 2(a_{i})(d_{i}):\)

\(u_{i} = 31.4064267\)

\(v_{i} = 0\)

\((0)^{2} = (31.4064267)^{2} + 2(-3.83307236)(d_{i}) \\\\ 0 = 986.363638 - 7.66614472(d_{i}) \\\\ 7.66614472(d_{i}) = 986.363638 \\\\ d_{i} = \frac{986.363638}{7.66614472} \\\\ d_{i} = 128.664886\) → 129 m

Answer:

\((75.0 \times 30) + (60.0 \times 6.0) = (75.0 \times V) + (60.0 \times 0) \\ 2250 + 360 = 75V \\ 75V = 2610 \\ V = 34.8 \: m {s}^{ - 1} \)

Answer:

Pressure =  5 x 10⁶ Pa

Explanation:

Given:

Height of building = 512 m

Find:

Pressure

Computation:

P2 = P1+dgh

P2 = 1 + (1000)(9.8)(512)

P2 = 51.2 atm

Pressure =  5 x 10⁶ Pa

Answer:

1.4 m/s to the left

Explanation:

just took it c:

Answer: 1968 cm3

Explanation: You first need to convert all of your dimensions to the same units.

240 mm = 24 cm

20.5 cm = 20.5 cm

0.04 m = 4 cm

Then volume is Length x width x height = 24 cm x 20.5 cm x 4 cm =

Answer:

Explanation:

Oh sorry I thought I knew this one I guess not but you can prob look it up on safari

The total power received by the antenna is 2.14 × 10^-14 W, and  a source at a distance of 17000 ly would need to emit a power of 1.35 × 10^-26 W to provide a signal that could be detected by the radio telescope.

A radio wave is a type of electromagnetic wave with a frequency between about 3 kHz and 300 GHz. Radio waves are used for a variety of purposes, including communication, broadcasting, and radar. They are produced by oscillating electrical charges, and can travel through air and other materials, including space.

Radio waves are characterized by their frequency and wavelength. The frequency of a radio wave is the number of cycles per second, measured in hertz (Hz). The wavelength is the distance between two adjacent peaks of the wave, and is inversely proportional to the frequency. Radio waves with lower frequencies have longer wavelengths, while those with higher frequencies have shorter wavelengths.

Radio waves can be generated by a variety of sources, including antennas, electrical circuits, and certain types of electronic devices. They are used for communication between devices, such as radios and cell phones, as well as for broadcasting television and radio signals. Radio waves are also used for remote sensing, including radar and satellite communication.

Here in the Question,

(a) The power per unit area received by the antenna is given by:

P/A = 0.95 pW / 6.1 × 10^17 m^2

The total power received by the antenna is equal to the power per unit area multiplied by the area of the antenna:

P = (P/A) × π(0.5d)^2

where d is the diameter of the antenna. Substituting d = 380 m, we get:

P = (0.95 pW / 6.1 × 10^17 m^2) × π(0.5 × 380)^2

P = 2.14 × 10^-14 W

Therefore, the total power received by the antenna is 2.14 × 10^-14 W.

(b) To find the power of a source at 17000 ly distance that could provide such a signal, we need to consider the power spreading over the surface of a sphere with a radius of 17000 ly. The power density of the signal decreases with the square of the distance from the source, so the power received by the antenna from a source at a distance of 17000 ly is:

P = P0 × (d0 / d)^2

where P0 is the power emitted by the source, d0 is the distance from the source to the antenna (i.e., 17000 ly), and d is the diameter of the antenna.

Substituting the values given, we get:

P = (0.95 pW / 6.1 × 10^17 m^2) × π(0.5 × 380)^2 × (17000 × 9.461 × 10^15 m / 380 m)^2

P = 1.35 × 10^-26 W

Therefore, a source at a distance of 17000 ly would need to emit a power of 1.35 × 10^-26 W to provide a signal that could be detected by the radio telescope.

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Answer:

Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.

Explanation:

Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.

When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.

(u should paraphrase it)

Answer:

a

Explanation:

Answer:

im pretty sure its intensity

Explanation:

The waves are traveling at 3.75 m/s considering the distance between two crests to be 7.5 m.

Identify the known variables. In this problem, we have the time between two wave crests (2.0 s) and the distance between two crests (7.5 m).

Calculate the wave speed. To calculate the wave speed, we need to divide the distance between two crests by the time between them. This gives us the equation v = d/t.

Plugging in our known values, we get v = 7.5 m / 2.0 s = 3.75 m/s.

The waves are traveling at 3.75 m/s.

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Answer:

A

Explanation:

1000ml = 1l

397ml = 0.397l

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:A: July

B: July and august

C:true

Explanation:

Answer:

About 6.26m/s

Explanation:

\(mgh=\dfrac{1}{2}mv^2\)

Divide both sides by mass:

\(gh=\dfrac{1}{2}v^2\)

Since the point of equality of kinetic and potential energy will be halfway down the cliff, height will be 4/2=2 meters.

\((9.8)(2)=\dfrac{1}{2}v^2 \\\\v^2=39.4 \\\\v\approx 6.26m/s\)

Hope this helps!

The gravitational potential energy (relative to the base of the cliff) be equal to its kinetic energy for speed of rock of 8.85 m/s.

Given data:

The height of vertical cliff is, h = 4.0 m.

Since, we are asked for speed by giving the condition for gravitational potential energy (relative to the base of the cliff) be equal to its kinetic energy. Then we can apply the conservation of energy as,

Kinetic energy = Gravitational potential energy

\(\dfrac{1}{2}mv^{2}=mgh\)

Here,

m is the mass of rock.

v is the speed of rock.

g is the gravitational acceleration.

Solving as,

\(v=\sqrt{2gh}\\\\v=\sqrt{2 \times 9.8 \times 4.0}\\\\v =8.85 \;\rm m/s\)

Thus, we can conclude that the gravitational potential energy (relative to the base of the cliff) be equal to its kinetic energy for speed of rock of 8.85 m/s.

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An athlete can jump a horizontal distance of 6.54 m in the broad jump. All else being equal (same launch speed, same launch angle), acceleration due to gravity has a value of 4.94 m/S² is = 32.3076 m.

To find the Height jumped by athlete on the planet, (y₂) the given data's are:

Height jumped by athlete on Earth (y₁) = 6.54 m

Acceleration on the planet = 4.94 m/s².

We know that, equation of motion can be defined as the displacement is directly proportional to the gravitational acceleration keeping the remaining quantities constant.

So, y ∝ g

Using the proportion equation for the planet and the Earth, then,

y₁ / gE = y₂ / gm

where as,

gm = gE × 4.94 m/s².

Substituting the values, we get,

y₂ = y₁ / gE ×  gm

y₂ = 6.54 ×  4.94

   = 32.3076 m.

Therefore, the height of the athlete can move is 32.3076 m.

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By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

The answer is C!

Explanation:

Answer:

C- the modern atomic theory contains over 200 years of research.

Explanation:

Answer:

104f

Explanation:

(40°C × 9/5) + 32 = 104°F

Answer:

Explanation:

Planetary Flyby:

The spacecraft does not go into orbit around the planet; instead, it uses the planet's gravity to change its speed and direction.

The spacecraft's closest approach to the planet is usually brief, ranging from a few minutes to a few hours.

The spacecraft is able to capture images and data during the brief encounter with the planet.

The spacecraft's trajectory can be adjusted to perform multiple flybys of different planets or moons.

The spacecraft does not require a large amount of fuel to perform a flyby, making it a cost-effective option for exploration.

Flybys are useful for studying a planet's atmosphere, magnetic field, and gravitational field.

Planetary Orbit Insertion:

The spacecraft goes into orbit around the planet, allowing for long-term study and data collection.

The spacecraft's orbit can be adjusted to achieve different scientific objectives, such as mapping the planet's surface or studying its atmosphere.

The spacecraft must have enough fuel to slow down and enter orbit, making it a more expensive option than a flyby.

The spacecraft's orbit can be stable or elliptical, depending on the scientific objectives and mission requirements.

The spacecraft may require several trajectory adjustments to achieve the desired orbit.

Orbit insertion allows for more detailed and comprehensive study of a planet's geology, climate, and magnetic field.

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Answer:

5.88 Nm

Explanation:

Applying,

Moment(M) = Force(F)×perpendicular distance(d)

M = F×d.................... Equation 1

But,

F = mg.................. Equation 2

Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

M = 3×0.2×9.8

M = 5.88 Nm

Answer:

e

Explanation:

the field points to the right

If loop is kept horizontally  and direction of current is clockwise , then according to Fleming’s Left Hand Rule the direction of magnetic field will be towards right .

Fleming’s Left Hand Rule states that if we arrange our thumb, forefinger and middle finger of the left-hand perpendicular to each other, then the thumb points towards the direction of the force experienced by the conductor, the forefinger points towards the direction of the magnetic field and the middle finger points towards the direction of the electric current.

If loop is kept horizontally  and direction of current is clockwise , then according to Fleming’s Left Hand Rule the direction of magnetic field will be towards right .

correct answer e) The field points to the right

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Newton's Second Law.

We have the following data, provided in the exercise:

Mass (m) = ?

Force (F) = 13607 N

Acceleration (a) = 2.9 m/s²

To calculate the mass, we solve the following formula:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}\)\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}\)

We substitute the data in the clear formula.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }\)

We break down the units of Newton = Kg * m/s².

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }\)