Which of the following is an indirect, as opposed to a direct, value of biodiversity?medical usefoodconsumptive useecotourismagricultural useEcotourism is a type of indirect value of biodiversity. Everything else is a direct value of biodiversity.

The mitochondria are organelles found in animal cells that are responsible for generating energy in the form of ATP through the process of cellular respiration.

Mitochondria are composed of an outer membrane and an inner membrane, which together create two compartments: the intermembrane space and the mitochondrial matrix. The mitochondrial matrix contains enzymes that are involved in the citric-acid cycle, also known as the Krebs cycle, which breaks down nutrients like glucose into carbon-dioxide and water, releasing energy in the process.

This energy is then used by the electron transport chain, located in the inner mitochondrial membrane, to generate ATP molecules. In addition to their role in energy production, mitochondria are also involved in other cellular processes.

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Answer:

high temperatures

Explanation:

hope that helped. and I like your pfp

Answer:

hard minerals

Explanation:

rocks made from very strong minerals keep colder and resist longer to weathering than rocks with soft minerals

I think that's right bro goodluck

Answer:

invasive species threaten biodiversity

Explanation:

they can take up an inoordinate amount of resources that affect people and animals. they are different from reintroducing a species. invasive species are bad for biodiveristy.

The answer to this is 6600 Hz to 19,800 Hz. When sound waves or longitudinal air vibrations enter the ear canal and impact the ear drum, the brain interprets the sound.

The range of low frequencies between 2,000 and 5,000 Hertz is where people are most sensitive. The human ear degenerates with age and is expected to become less sensitive to high frequencies.

The shape of the human ear is analogous to a closed ended pipe hence

we have λ = 4L or wavelength = 4 * length of the child ear

The frequency  c/λ  where c = speed of sound = 343 m/s

hence the child's audible range is multiples of 343/(4*0.13) =6600Hz

or 13200 Hz or 19,800 Hz

The generally quoted range of human hearing is 20 Hz to 20 kHz.

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Full Question: A child has an ear canal that is 1.3cm  long. At what sound frequencies in the audible range will the child have increased hearing sensitivity?

Answer:

To provide an experimental foundation for the theoretical concepts introduced in the lectures. It is important that students have an opportunity to verify some of the ideas for themselves.

2. To familiarize students with experimental apparatus, the scientific method, and methods of data analysis so that they will have some idea of the inductive process by which the ideas were originated. To teach how to make careful experimental observations and how to think about and draw conclusions from such data.

3. To introduce the methods used for estimating and dealing with experimental uncertainties, including simple ideas in probability theory and the distinctions between random (statistical) and systematic "errors." This is essential in understanding what valid conclusions can be deduced from experimental data and that, properly obtained, these conclusions are valid, notwithstanding the uncertainty of the data.

4. To learn how to write a technical report which communicates scientific information in a clear and concise manner.

5. To introduce new concepts and techniques which have a wide application in experimental science, but have not been introduced in the standard courses. These may require that the student consult additional textbooks.

Explanation:

Answer:

1. To provide an experimental foundation for the theoretical concepts introduced in the lectures. It is important that students have an opportunity to verify some of the ideas for themselves.

2. To familiarize students with experimental apparatus, the scientific method, and methods of data analysis so that they will have some idea of the inductive process by which the ideas were originated. To teach how to make careful experimental observations and how to think about and draw conclusions from such data.

3. To introduce the methods used for estimating and dealing with experimental uncertainties, including simple ideas in probability theory and the distinctions between random (statistical) and systematic "errors." This is essential in understanding what valid conclusions can be deduced from experimental data and that, properly obtained, these conclusions are valid, notwithstanding the uncertainty of the data.

4. To learn how to write a technical report which communicates scientific information in a clear and concise manner.

5. To introduce new concepts and techniques which have a wide application in experimental science, but have not been introduced in the standard courses. These may require that the student consult additional textbooks.

Answer:

RNA instruct dna to make protien

The statement (A) best summarizes the process of protein synthesis.

Protein synthesis is the process in which cells make proteins. It occurs in two stages: transcription and translation. Transcription is the transfer of genetic instructions in DNA to mRNA in the nucleus.

Moreover, protein biosynthesis (or protein synthesis) is a core biological process, occurring inside cells, balancing the loss of cellular proteins (via degradation or export) through the production of new proteins. Proteins perform a number of critical functions as enzymes, structural proteins or hormones.

Therefore, ribosomes are the sites in a cell in which protein synthesis takes place. Cells have many ribosomes, and the exact number depends on how active a particular cell is in synthesizing proteins.

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Answer:

Sex linked genes is a trait in which a gene is found on a sex chromosome, males are the one that carry most/ more of the mutation.

Explanation:

Hope it helps.

Answer:

D. The plant will produce less glucose.

Explanation:

CO2 i. needed for glucose to be produced. However if there isn't enough co2 then glucose production is reduced,

Answer:  The correct answer is D. The plant will produce less glucose.

Explanation:  Carbon dioxide (CO2) is an essential component of photosynthesis (also called carbon assimilation). Photosynthesis is a chemical process that uses light energy to convert CO2 and water into sugars (glucose). When the CO2 is lowered, so is the glucose output.

Answer:

A Population is group of organisms of the SAME species living in the same area at the same time and sharing a common gene pool. ... In ecology, the term Community refers to the populations of animals and plants that live within a specific region under similar environmental conditions.

Answer:

The answer is : A

Their genotype can be NP (Carrier Parent) NN if one of their parents has PKU but it is dormant (Normal Parent). This will result in a genotypic ratio of 0 NN, 0 PP, and 4 NP when done in a punnet square.

However, if both parents do have PKU recessive disorder in their DNA, their genotype will be NP (Carrier parent) NP (Carrier parent). In this case, it is conceivable for one kid to have PKU, one child to be a PKU carrier, and two children to be PKU carriers. Therefore, the percentage will be as follows if we base the final results on the second setup: 25% Normal 25% with illness, PKU carrier at 50%.

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The energy present in the ecosystem is being conveyed from producers to each level of the ecosystem. Photosynthesis is the process involve in the conversion of the energy from the sun to chemical energy. The number of trophic levels in an ecosystem is confines to 4-5 only. Only 10 % of energy is being conveyed from one level to the next. If this will be the case, each level will have a decrease of energy. If a sixth level will be present, there will be not enough energy to provide the species on such level.

Answer is Option 1 - Not enough energy is available to be transferred from the fifth trophic level to the sixth trophic level to support organisms.

Dialkyl phosphonates (diesters of phosphonic acids) act as nucleophiles in this reaction.

Dialkyl phosphonates are a class of organic compounds which have the general formula (RO)2P(O)H, where R is a short-chain alkyl group (usually methyl or ethyl). Dialkyl phosphonates act as nucleophiles in reactions, meaning they have a high affinity for positively charged atoms (in this case, the carbonyl carbon of an aldehyde or ketone).

This reactivity is due to the electron-withdrawing properties of the phosphonate group, which makes the carbon more susceptible to attack by the nucleophile. The use of dialkyl phosphonates as nucleophiles is particularly useful in the Horner-Wadsworth-Emmons (HWE) reaction, a type of olefination reaction that allows for the formation of carbon-carbon double bonds between aldehydes or ketones and phosphonate esters.

The reaction is catalyzed by a strong base (usually triethylamine), which deprotonates the phosphonate ester to form a reactive ylide intermediate that can then undergo nucleophilic addition to the carbonyl group of the aldehyde or ketone.

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The human body is a complex organism and understanding its structure and functions requires a thorough knowledge of directional terminology, body planes, and body movements. In this image, we can see a person performing a side plank exercise which is an effective core-strengthening exercise.

We can also use directional terminology to describe the person's movements. The person is performing a lateral flexion to the side while maintaining an isometric contraction of the core muscles. The movement involves the transverse axis of the body, which runs from front to back, perpendicular to the frontal plane.

In conclusion, this picture shows a person performing a side plank exercise, positioned on the frontal plane and performing a lateral flexion movement. The person is using their core muscles to maintain the position while one arm is supporting their weight and the other arm is extended towards the ceiling.

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Answer:fact 2

Explanation:

Answer:

Fact #2

Explanation:

Mammals, birds, and reptiles usually have different body coverings. Mammals usually have fur or hair, birds usually have feathers, and reptiles usually have scales.

When Todd is classifying (sorting) his three animals into groups based on body covering, he will probably find fact #2 the most useful.

6 ways of expressing standard atmospheric pressure include: millimetres (or inches) of mercury, pounds per square inch (psi), dynes per square centimetre, millibars (mb), standard atmospheres, and kilopascals.

The false statement about epigenetic modifications is:
c. Only non-DNA components of chromatin are modified with epigenetic markers.

Epigenetic modifications refer to changes in gene expression that do not involve changes to the underlying DNA sequence. These modifications can be inherited and can influence how genes are turned on or off in different cells or at different stages of development.

a. The tails of the nucleosome octamer components can be modified with methylation: This statement is true. Methylation of the tails of nucleosome octamer components, which are made up of histone proteins, can affect gene expression by either activating or repressing the associated genes.

b. The tails of the nucleosome octamer components can be modified with acetylation: This statement is also true. Acetylation of histone tails is another type of epigenetic modification that can influence gene expression. Acetylation generally leads to gene activation by relaxing the chromatin structure and allowing transcription factors to access the DNA.

d. Epigenetic modifications control whether a region is euchromatin or heterochromatin: This statement is true. Epigenetic modifications play a crucial role in determining whether a region of DNA is in a euchromatin state, which is more accessible for gene expression, or a heterochromatin state, which is more condensed and less accessible for gene expression.

In summary, the false statement is c. Only non-DNA components of chromatin are modified with epigenetic markers. Epigenetic modifications can occur on both DNA and non-DNA components of chromatin, such as histone proteins. These modifications can have significant impacts on gene expression and are essential for cellular development and function.

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Post-synaptic inhibitory potentials (IPSPs) group of answer choices(a) are formed when postsynaptic membrane permeability increases for k (b) are a type of graded potential(c) are formed when the postsynaptic permeability for cl- ions increases. The correct answer is (e) all of the above.

Post-synaptic inhibitory potentials (IPSPs) are the hyperpolarizations of postsynaptic potentials. They result from the binding of neurotransmitters to receptors on the postsynaptic membrane. The permeability of the postsynaptic membrane increases for chloride (Cl−) or potassium (K+) ions, which results in the hyperpolarization of the membrane potential. As a result, the membrane potential is more negative than the resting potential and more difficult to depolarize. The postsynaptic potential is proportional to the quantity of neurotransmitter that was released and the number of receptors on the postsynaptic membrane. The postsynaptic inhibitory potentials (IPSPs) are a kind of graded potential, which means they can have varying amplitudes and durations, depending on the quantity of neurotransmitter released.

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Answer:    Membrane transport proteins are specific and selective for the molecules they move, and they often use energy to catalyze passage. Also, these proteins transport some nutrients against the concentration gradient, which requires additional energy.

Explanation:

Membrane transport proteins play a crucial role in the movement of solutes across biological membranes, including ions, nutrients, neurotransmitters, and a wide range of medications.

What function do transport proteins provide in living membranes?

The cell membrane contains transport proteins that enable the selective transit of particular molecules from the surrounding environment. Each transport protein recognizes a certain chemical only (indicated by matching colors)

The two main kinds of membrane transport proteins are carrier proteins and channel proteins. The specific solute to be transported is bound by carrier proteins (also known as carriers, permeases, or transporters), which then go through a series of conformational changes to move the bound solute across the membrane.

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DNA nucleotides come in four different varieties since there are four naturally occurring nitrogenous bases : adenine (A), thymine (T), guanine (G), and cytosine (C)  =  −15

A single, continuous molecule of nucleic acid or protein makes up a biological sequence.

The basic structure of a biological macromolecule, also known as the sequence, is the covalently connected, one-dimensional ordering of monomers inside a biopolymer. The phrase "sequence" can apply to a variety of substances, although it is most frequently used to describe a DNA sequence.

It can be compared to a class hierarchy with multiple inheritance. The underlying molecule type, such as DNA, RNA, or protein, is one hierarchy.

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Answer:

the answer is the last option 75% brown and 25% green.

Climate and soil type are the two factors that have the biggest impact on the type of agriculture produced in a local area. The correct option is D.

Climate refers to the long-term patterns of temperature, humidity, wind, and precipitation in an area, which can influence what crops can be grown and how they are grown. For example, certain crops may require specific temperature ranges, amount of sunlight, or amount of water to thrive.

Soil type refers to the physical and chemical properties of the soil in an area, which can also influence what crops can be grown. For example, some crops may require well-draining soil, while others may require soil with a high nutrient content. Soil type can also affect the types of fertilizers and pesticides that may be needed to support crop growth.

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Answer:

2 elements chemically joined together. An emample is Ironoxie

Explanation:

Answer:

A compound is a mixture of elements.

Explanation:

examples:

Calcium carbonate

Potassium nitrate

Hydrogen peroxide

Water

To determine the amount of insert DNA Vrinda needs to add for setting up ligation, she needs to use the given protocol and molar ratio. Vrinda needs to add 99.33 ng of insert DNA to set up the ligation.

The ligation reaction involves the 4kb plasmid and 500bp PCR product. The molar ratio needed for the ligation reaction is 1 plasmid: 2 insert. 1 plasmid refers to 4kb while 2 inserts refer to 500bp.

Therefore, the total number of bp is

4kb + 1 kb = 5 kb or 5000bp.

Since the molar ratio is 1:2, the 500bp insert will be in excess.

Hence, the amount of insert DNA that needs to be added will depend on the amount of plasmid DNA required. The protocol specifies the use of 100ng plasmid DNA.

To determine how much insert DNA to add, first, calculate the mass of 1 mole of 5 kb DNA.

Mass of 1 mole of 5 kb DNA = (5kb x 660 gm/mole)/ Avogadro's number

= 3.3 x 10^-18g/molecule

Now, calculate the number of molecules of 4kb plasmid that will be present in 100 ng of plasmid DNA.

Number of molecules of 4 kb plasmid = (100 ng / 4kb) x Avogadro's number

= (100 x 10^-9g / 4 x 10^3bp) x 6.022 x 10^23 molecules/mole

= 1.505 x 10^13 molecules

Now, calculate the number of insert molecules that are needed:

Number of insert molecules = 2 x Number of plasmid molecules

= 2 x 1.505 x 10^13 molecules

= 3.01 x 10^13 molecules

Finally, calculate the mass of insert DNA required.

Mass of insert DNA required = (Number of insert molecules x 3.3 x 10^-18g/molecule)

= (3.01 x 10^13 molecules x 3.3 x 10^-18g/molecule)= 99.33 ng

Therefore, Vrinda needs to add 99.33 ng of insert DNA to set up the ligation.

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Answer:

c. The current changes are happening much faster than past changes.

Explanation:

This is correct because the earth's atmosphere is warming at an exceedingly high rate. This is due to the rise in amounts of carbon dioxide in the atmosphere among other factors. If the current trends were a representation of Earth's natural climate cycle then they would not be as high as they are now.

Have a great day. I assure you this is the correct answer. Let me know if you have any questions on this topic.

Scanning electron microscope (SEM) can be used to study the details of protein molecules present on the surface of a cell. These give a three-dimensional structure of the molecules. Thus, the correct option is A.

Scanning electron microscope (SEM) is a type of electron microscope, designed to directly study the surfaces of solid objects, that utilizes a beam of focused electrons of relatively low energy is scanned in a regular manner over the specimen to be observed.

Scanning electron microscopes use an electron beam to study samples with a resolution. The electrons are emitted from a filament and collect into a beam in the electron source. The beam is focused on the sample by a set of lenses in the column.

Therefore, the correct option is A.

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Your question is incomplete, most probably the complete question will be:

To study the details of protein molecules on the surface of a cell a biologist would most likely use a:

a. scanning electron microscope

b. transmission electron microscope

c. compound light microscope

d. dissecting microscope

Explanation:

multicellular means it's forms tissue