Answer:
It is the total distance traveled over the total time .
Answer:
D
Explanation:
2. (01.01 HC)
Describe the role of consumers in a food web. Are consumers heterotrophs? Justify your answer. (7 points)
Yes the all types of the consumers are the heterotrophs.
What role play the consumers in a food web? Are consumers heterotrophs?
The consumers play a very important role in the ecosystem of the earth by maintaining the population and growth to the organism of the ecosystem. If we remove the consumer or either the producer then the whole system of the ecosystem will be destabilize, and thus the ecosystem can survive from the overpopulation problem and lack of food problem. The other organism can transfer energy to the consumer.
Both the primary (herbivores) and as well as the secondary (carnivores and omnivores) consumers are heterotrophs.
So we can conclude that yes the all types of the consumers are the heterotrophs.
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how many atoms are in 12.0g of carbon
12 grams of carbon contains 6.022 x 10^23 atoms.
What is the Avogadro's number?
Avogadro's number gives the number of particles in one mole (or moles) of a substance. These particles can be electrons or molecules or atoms. The value of Avogadro's number is approximately 6.022140857 × 10^23 mol−1.
12 grams of carbon contains 6.022 x 10^23 atoms, which corresponds to 1 mole of atoms.
This means that the same number of atoms can be found in other substances of the same weight. Avogadro's number expresses the number of atoms in gram atoms of an element, or the number of molecules in gram moles of a compound.Dividing the atomic mass of an element by the actual mass of that atom gives the value 6.022 xx 10^(23).For example, a carbon molecule contains the same number of atoms as 12 grams of carbon, so 12 grams of carbon equals 6.022 x 10^23 atoms.Therefore, 12 grams of carbon contains 6.022 x 10^23 atoms.
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Rain soaks into the soil or runs off into oceans, rivers, and lakes. ___________ which process is this
Answer:
The water falls to the earth as precipitation, such as rain, hail, sleet, and snow. When precipitation reaches the earth's surface, some of it will flow along the surface of the land and enter surface water like lakes, streams, and rivers, as runoff. The rest of it soaks or percolates into the soil, called
A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 35°C is 42.2 torr, what is the volume of the gas sample at standard pressure?
Answer:
The volume of the gas sample at standard pressure is 819.5ml
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.
\( V_1=250ml\)
\( V_2=?\)
\( P_{total}=735 mmhg\)
1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,
\( P_{water}=42.2mmhg\)
\( T_1=35°C=35+273=308 K\)
Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.
\( P_{gas}=P_{total}-P_{water} \)
=735-42.2=692.8 mmhg
Now
By using combined gas law equation:
\(\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}\)
\(V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1\)
\(V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1\)
Here \(P_2 \:and\: T_2\) are standard pressure and temperature respectively.
we have
\(P_2=750mmhg \:and\: T_2=273K\)
Substituting value, we get
\(V_2=\frac{692.8}{750}*\frac{273}{308} *250\)
\(V_2= 819.51 ml\)
how many moles are in 22 grams of argon
Answer:
0.551 moles
Explanation:
To calculate the number of moles in 22 grams of argon, divide the mass by the molar mass:
Number of moles = Mass / Molar mass
Number of moles = 22 g / 39.95 g/mol
Number of moles ≈ 0.551 moles
Therefore, there are approximately 0.551 moles of argon in 22 grams of argon.
What are the details of the chemical structure of methylisothiazolinone (MIT)?
If there is direct variation and y=75 when x=25, find x when y=48.
A. x=16
B. x=10
C. x=12
D. x=14
If there is direct variation and y=75 when x=25,when y=48 X = 16. Therefore, option A is correct.
What is direct variation ?link between two variables that can be described mathematically by an equation where one variable equals a constant multiplied by the other. For instance, the constant of variation is k = = 3 if y varies straight as x and y = 6 when x = 2. Consequently, y = 3x is the equation that describes this direct variation.
When x is not equal to zero, an equation of the form y = kx describes the linear function known as direct variation. When x is not equal to zero and k is a nonzero real number constant, the equation of the form xy = k describes the nonlinear function known as inverse variation.
x = ky
where k is constant
25 = k × 75
25 / 75 = k
k = 1 / 3
now when y = 48 then substitute the values
x = ky
x = 1 ÷ 3 × 48
x = 16
Thus, option A is correct.
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How many molecules of ammonia are produced from the reaction of
9.5 * 10^{23} molecules of nitrogen are reacted with excess hydrogen gas?
Answer:
9.5X10^23 molecules N2 X (2 molecules NH3 / 1 molecule N2) = 1.9X10^24 molecules NH3
Explanation:
.
12. 5.6g of solid copper was heated with 476.2 J at room temperature (25°C). Given that
copper has a C of 0.38 J/g°C, what would its final temperature be?
Answer:
The final temperature of the copper would be 311.3°C.
I hope this helps you
7. Describe the propert 1 lies of hard and soft materials
The properties of hard and soft materials refer to their physical characteristics and behaviors.
These properties are related to factors such as the arrangement of molecules, bonding strength, and response to external forces. Here, we will discuss the general properties of hard and soft materials.
Hard materials:
Rigidity: Hard materials exhibit high stiffness and resist deformation under applied forces. They tend to maintain their shape and structure.
High strength: Hard materials have strong intermolecular or intramolecular forces, allowing them to withstand high stress and pressure without breaking or deforming.
High melting and boiling points: Hard materials often have high melting and boiling points due to the strong bonds between their atoms or molecules.
Brittle: Hard materials are often brittle, meaning they have low tolerance to tensile or bending forces and are prone to fracturing or shattering instead of deforming.
Low compressibility: Hard materials have low compressibility, meaning they do not easily compress or change volume under pressure.
Soft materials:
Flexibility: Soft materials are pliable and easily deformable under applied forces. They can be bent, stretched, or compressed without breaking.
Low strength: Soft materials have weak intermolecular or intramolecular forces, making them more susceptible to deformation or damage under stress.
Low melting and boiling points: Soft materials generally have lower melting and boiling points compared to hard materials.
Ductile: Soft materials are often ductile, meaning they can be drawn into thin wires or stretched into thin sheets without fracturing.
High compressibility: Soft materials can be easily compressed or change volume under pressure due to their loosely packed molecular structures.
It's important to note that these properties are generalizations, and there can be variations within each category. Some materials may exhibit properties that fall between hard and soft, or they may have unique combinations of properties. Materials' properties play a crucial role in various applications, as they determine their suitability for specific uses such as construction, manufacturing, and design.
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CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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how many grams of Fe are produced from 92.5g of FeO given the following reaction
The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams
How do i determine the mass of Fe produced?The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:
2FeO → 2Fe + O₂
Molar mass of FeO = 71.85 g/molMass of NH₃ from the balanced equation = 2 × 71.85 = 143.7 g Molar mass of Fe = 55.85 g/molMass of Fe from the balanced equation = 2 × 55.85 = 111.7 gFrom the balanced equation above,
143.7 g of FeO reacted to produce 111.7 g of Fe
Therefore,
92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe
Thus, the mass of Fe produced from the reaction is 71.9 grams
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Complete question:
How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂
Aqueous hydrobromic acid (HBr) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H₂O). If 2.69 g
of water is produced from the reaction of 17.0 g of hydrobromic acid and 13.9 g of sodium hydroxide, calculate the percent yield of water.
Round your answer to 3 significant figures.
Answer:
70.95%
Explanation:
To calculate the percent yield of water in this reaction, we need to compare the actual amount of water produced to the theoretical amount of water that could be produced based on the amount of hydrobromic acid and sodium hydroxide used.
First, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed in the reaction, limiting the amount of product that can be formed.
To find the limiting reactant, we can use stoichiometry to calculate the amount of water that could be produced from each reactant, assuming they react completely. The balanced chemical equation for the reaction is:
HBr + NaOH → NaBr + H2O
From the equation, we can see that the mole ratio of HBr to H2O is 1:1, and the mole ratio of NaOH to H2O is 1:1. Therefore, the amount of water produced depends on the amount of HBr and NaOH present, and the reactant that produces less water is the limiting reactant.
Using the molar masses of the compounds, we can convert the masses of HBr and NaOH to moles:
moles of HBr = 17.0 g / 80.91 g/mol = 0.210 moles
moles of NaOH = 13.9 g / 40.00 g/mol = 0.348 moles
Based on the balanced chemical equation, the theoretical amount of water that could be produced from 0.210 moles of HBr is also 0.210 moles. The theoretical amount of water that could be produced from 0.348 moles of NaOH is also 0.348 moles.
However, since the amount of water produced is given as 2.69 g, we need to convert this to moles:
moles of H2O produced = 2.69 g / 18.02 g/mol = 0.149 moles
To calculate the percent yield of water, we can use the formula:
percent yield = (actual yield / theoretical yield) x 100%
where actual yield is the amount of water produced (0.149 moles) and theoretical yield is the amount of water that could be produced based on the limiting reactant.
Since the reactant that produces less water is the limiting reactant, we need to compare the theoretical yield of water from both reactants, and the lower value will be the theoretical yield based on the limiting reactant.
The theoretical yield of water from HBr is:
0.210 moles of HBr x (1 mole of H2O / 1 mole of HBr) = 0.210 moles of H2O
The theoretical yield of water from NaOH is:
0.348 moles of NaOH x (1 mole of H2O / 1 mole of NaOH) = 0.348 moles of H2O
Since the theoretical yield of water from HBr is lower, it is the limiting reactant. Therefore, the theoretical yield of water is 0.210 moles.
Now we can calculate the percent yield of water:
percent yield = (actual yield / theoretical yield) x 100%
percent yield = (0.149 moles / 0.210 moles) x 100%
percent yield = 70.95%
Therefore, the percent yield of water is 70.95%.
amobarbital sodium react with ethanolic sodium hyrooxide
Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.
What is the mechanism of amobarbital?Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.
Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.
So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.
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Someone help me do each piece of evidence in 2-4 sentences
No definitions
No go*gle
Claim 1: The Moon’s appearance changes because Earth casts a shadow on the Moon.
Claim 2: The Moon’s appearance changes because the position of the Moon changes.
Claim 1: occurs during full moon phase
Claim 2: the orbital function of the moon to cast full moon, new moon and crescent moon phases.
How are the moon appearances described?Claim 1: The Moon's appearance changes due to Earth casting a shadow on it during a lunar eclipse. During this event, the Earth is positioned between the Moon and the Sun, and the Earth's shadow falls on the Moon, creating a reddish-brown hue. This phenomenon can only occur during a full moon phase.
Claim 2: The Moon's appearance changes due to its position relative to the Earth and the Sun. As the Moon orbits around the Earth, the amount of sunlight that reflects off of it changes, causing different phases, such as full moon, new moon, and crescent moon. Additionally, the Moon's position in the sky changes over time, which can affect its visibility and apparent size.
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A balloon full of air has a volume of 1.00L at a temperature of 23 °C. What is the balloon's volume at 33°C?
Answer:1.03L
How do I solve this?
Answer:
V2= 1.03L
Explanation:
Start off with what you are given.
V^1: 1.00L
T^1: 23°C
V^2?
T^2: 33°C
If you know your gas laws, you have to utilise a certain gas law called Charles' Law:
V^1/T^1 = V^2/T^2
Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.
(23+273 = 296) (33+273 = 306)
Multiply crisscross
1.00/296= V^2/306
296V^2 = 306
Dividing both sides by 296 to isolate V2, we get
306/296 = 1.0337837837837837837837837837838
V2= 1.03L
Element Z consists of 3 isotopes,
Z-28 with a mass of 27.977 amu
Z-29 with a mass of 28.976 amu
Z-30, whose atomic masses is 29.974 amu.
The most abundant isotope is Z-28 which accounts for 92.23% of the atoms.
Given that the observed atomic mass of element Z is 28.0855 amu; calculate the percentages of Z-29 and Z-30 in nature.
Considering the definition of isotopes and atomic mass of an element, the percentages of Z-29 and Z-30 in nature are 4.66% and 3.11% respectively.
Definition of isotopeThe same chemical element can be made up of different atoms with different numbers of neutrons. These atoms are called isotopes of the element.
Definition of atomic massThe atomic mass of an element is the weighted average mass of its natural isotopes, considering the relative abundance of each of them.
Atomic mass of the element in this caseIn this case, you know:
Z-28 with a mass of 27.977 amu and a percent natural abundance of 92.23 %.Z-29 with a mass of 28.976 amu and a percent natural abundance of x%.Z-30 with a mass of 29.974 amu and a percent natural abundance of y%.The atomic mass of element Z is 28.0855 amu.Being the total percent natural abundance equal to 92.23% + x% + y%= 100%, then:
y%= 100% - 92.23% - x%
y%= 7.77% - x% or y=0.0777 - x
Then, the average mass of Z can be calculated as:
27.977 amu×0.9223 + 28.976 amu× x +29.974 amu× y= 28.0855 amu
Replacing the expression of y:
27.977 amu×0.9223 + 28.976 amu× x +29.974 amu× (0.0777 - x)= 28.0855 amu
Solving:
27.977 amu×0.9223 + 28.976 amu× x +29.974 amu× 0.0777 - 29.974 amu× x= 28.0855 amu
28.132 amu - 0.998 amu× x= 28.0855 amu
- 0.998 amu× x= 28.0855 amu - 28.132 amu
- 0.998 amu× x= -0.0465 amu
x= (-0.0465 amu)÷ (-0.998 amu)
x= 0.0466= 4.66%
Remembering that y%= 7.77% - x%, you get:
y%= 7.77% - 4.66%
y%= 3.11%
Finally, the percentage of Z-29 is 4.66% and the percentage of Z-30 is 3.11%.
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An atomic cation with a charge of +1 has the following electron configuration:
1s 2s 2p 3s 3p 3d ¹4s¹
What is the chemical symbol for the ion?
How many electrons does the ion have?
How many 3p electrons are in the ion?
A) The chemical symbol for the ion is Fe+
B) It has 20 electrons in total, and there are 6 3p electrons in the ion.
C) There are 6 electrons present in the 3p orbital.
The atomic cation with the given electron configuration is represented by the chemical symbol Fe+.
To determine the number of electrons in the ion, we need to count the electrons present in the electron configuration. In the given configuration, we can see that the 1s orbital has 2 electrons, the 2s orbital has 2 electrons, the 2p orbital has 6 electrons, the 3s orbital has 2 electrons, the 3p orbital has 6 electrons, the 3d orbital has 1 electron, and the 4s orbital has 1 electron. Adding up these numbers, we have:
2 + 2 + 6 + 2 + 6 + 1 + 1 = 20
Therefore, the ion has 20 electrons.
To determine the number of 3p electrons in the ion, we look at the 3p orbital. In this case, there are 6 electrons present in the 3p orbital.
In summary, the chemical symbol for the ion is Fe+, it has 20 electrons in total, and there are 6 3p electrons in the ion.
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7. What is the volume of the
composite
solid?
4 in.
3 in.
3 in.
Answer:
The volume of Component 1 is 36 cubic inches.
Explanation:
To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.
In this case, the composite solid consists of multiple components with the following dimensions:
Component 1:
Length: 4 inches
Width: 3 inches
Height: 3 inches
To find the volume of Component 1, we multiply the length, width, and height together:
Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches
Therefore, the volume of Component 1 is 36 cubic inches.
Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.
Chemistry
Definition in your own words
Will check if you got it from online.
Word: Phase change
How many joules of heat are needed to melt 50 g of ice at 0°C and then warm the liquid to 65°C? heat of fusion of ice = 334 J/g specific heat of water = 4.184 J/g°C specific heat of ice = 2.03 J/g°C heat of vaporization of water = 2260J/g
Answer:
\(Q=30298J\)
Explanation:
Hello,
In this case, in this heating process, we should consider two steps which have their own associated enthalpy for the same mass of water:
1) Melting of ice at 0 °C.
\(H_1=m_{ice}\Delta _{fusion}H=50g*334\frac{J}{g} =16700J\)
2) Heating of liquid water from 0 °C to 65 °C.
\(H_2=mCp(T_2-T_1)=50g*4.184\frac{J}{g\°C}(65-0)\°C =13598J\)
Therefore, the total needed heat turns out:
\(Q=H_1+H_2=16700J+13598J\\\\Q=30298J\)
Regards.
Answer:
30,298 joules of heat are needed to melt 50 g of ice at 0°C and then warm the liquid to 65°C
Explanation:
To analyze the heat that must be supplied to the ice, two phases are analyzed: one in which a part of heat will be required to melt the ice, that is, convert 0 ° C of ice to 0 ° C in a liquid state, and another part of heat that will raise the temperature of the melted ice to 65 ° C. So:
Total heat required = Heat required to melt ice + Heat required to raise the temperature of the ice in liquid state
Being fusion, the process that a substance undergoes to go from a solid state to a liquid, then the heat required to convert 0 ° C of ice to 0 ° C in a liquid state is calculated as:
Heat required to melt ice=mass*heat of fusion of ice= 50 g* 334 \(\frac{J}{g}\)= 16,700 J
On the other hand, the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous) is calculated by the expression:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (Tfinal-Tinitial).
Then, the heat required to go from water at 0 ° C to water at 65 ° C is calculated by:
q=specific heat of water*m*ΔT= 4.184 \(\frac{J}{g*C}\) *50 g* (65 °C - 0°C)= 13,598 J
So:
Total heat required = 16,700 J + 13,598 J
Total heat required = 30,298 J
30,298 joules of heat are needed to melt 50 g of ice at 0°C and then warm the liquid to 65°C
Solve 21 and 22 please
Answer:
try youre best to succsess
Calculate the work done when a force of 4 N pulls a box along the floor for a distance of 0.3 m.
Answer:
1.2 Joulesolution,
Force=4 N
Distance=0.3 m
Now,
\(work = f \times d \\ \: \: \: \: \: \: \: \: \: \: \: = 4 \times 0.3 \\ \: \: \: \: \: \: \: \: \: \: \: = 1.2 \: joule\)
hope this helps...
Good luck on your assignment....
Two asteroids are 75,000 m apart one has a mass of 8 x 10^7 N what is the mass of the other asteroid
The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg
To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:
F = (G * m1 * m2) / \(r^{2}\)
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.
Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):
1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)
Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.
The question was incomplete. find the full content below:
Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid
A. 3.4 x \(10^{11}\) kg
B. 8.3 x \(10^{12}\) kg
C. 1.2 x \(10^{12}\) kg
D. 1.2 x \(10^{10}\) kg
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What is The relationship between the electromotive force and the free enthalpy of reaction in a redox reaction?
Answer:
The EMF and free enthalpy (or Gibbs Free Energy) of a reaction are directly related.
If the free enthalpy of a redox reaction is negative, then the EMF will be negative, indicating that the reaction is spontaneous and will occur without the need for an external source of energy.
If the free enthalpy of the reaction is positive, then the EMF will be positive, indicating that the reaction is not spontaneous and will not occur without the input of energy.
The relationship between free enthalpy and EMF is shown in the following equation:
∆G = -nFE°(cell), where n is the number of electrons transferred, F is the Faraday constant, and E° is the EMF of a cell under standard conditions.
You are given 3 liquid samples – A, B, C and told that one is water, one is ethanol, and one is ether (d=0.700 g/mL). Each sample is 10.0 mL. the masses are as follows: A = 10.0 g, B= 7.00 g, C = 8.00 g. Identify each of the substances using density problems.
Answer:
im just trying to get work done i will help u if i knew it
Question 5 of 5What happens to the particles in a substance as it boils?aA. The particles slow down and move closer together.B. The particles slow down and become fixed in place.C. The particles move more quickly and spread far apart.D. The particles move more quickly but stay close together.SUBMIT
For a substance to begin to boil, it must have an increase in kinetic energy, either due to an increase in temperature or a decrease in pressure. Now, by having greater kinetic energy, the average speed of the molecules will be greater, there will also be greater collisions between the molecules and they will begin to move away. Therefore, the correct option will be: The particles move more quickly and spread far apart.
Answer: C. The particles move more quickly and spread far apart.
Which best illustrates the way in which radiation transfers thermal energy
Warm
Warm
Cool
3
( Warm
Cool
Warm
Cool
Warm
Cooi
the answer is:
b. warm ~~> cool
What can we measure with the
SI unit, the mole?
A. temperature
B. mass
C. amount of substance
D. length
The amount of substance is measured with the SI unit, the mole.
What is Mole?Mole is the ratio of the given mass of substance to the molar mass of that substance.
Or it is the ratio of the number of molecules of substance to the Avogadro number.
Mathematically, it can be written as
Mole = given mass / molar mass
Or Mole = number of molecules / Avogadro number.
For first case,
Temperature is measured with the SI unit, the celsius. So, this is incorrect option.
For second case,
As we know that, mass is measured with the SI unit, the gram. So, this is also incorrect option.
For fourth case,
Length is measured with the SI unit, the metre. So, this is also incorrect option.
Therefore, option C is the correct option.
Thus, we concluded that the amount of substance is measured with the SI unit, the mole.
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The radius of a potassium
atom is 0.227 nm. Express this
radius in the unit centimeters.
Answer:
0.227 nm can also be written as
0.227 * \(10^{-9}\)m
and we know that 1 cm = 1m * 100
so we will multiply by with 100:
0.227 * \(10^{-7}\) cm
2.27 * \(10^{-8}\) cm
The radius of a potassium atom is 0.227 nm. In centimeters, the radius of potassium is 2.27 × 10⁻⁸ cm
Potassium is an element on the periodic table with the atomic number 19. It has white, lustrous, and shiny color. They exhibit a low melting point and are a great conductor of electricity.
Given that:
The radius of a potassium atom is 0.227 nm
Using the standard conversion analysis:
Since 1 nanometer (nm) = 1.0 × 10⁻⁷ centimeters (cm)
Then, 0.227 nm is:
= \(\dfrac{(0.227 \ nm \times 1.0 \times 10^{-7} (cm))}{1 \ nm}\)
= 2.27 × 10⁻⁸ cm
Therefore, we can conclude that the radius of a potassium atom in centimeters is 2.27 × 10⁻⁸ cm
Learn more about conversion rates here:
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