which of the following are true about css? select two that apply.
a. CSS can be easily read by humans
b. CSS is open source
c. The CSS standard can be freely used by anyone
d. Anyone can download the CSS sorce code and change the CSS standard

To achieve 100% statement coverage, additional tests are needed to cover different combinations of drink preferences (milk and sugar). For 100% decision coverage, tests should cover both the selection of drink type and the decisions related to adding milk and sugar.

a. Control Flow Diagram:

Start

|

V

Choose Drink Type (Hot or Cold)

|

V

IF Hot Drink

|   |

|   V

|   Ask for Milk Preference

|   |

|   V

|   IF Milk Required

|   |   |

|   |   V

|   |   Add Milk

|   |   |

|   |   V

|   |   Ask for Sugar Preference

|   |   |

|   |   V

|   |   IF Sugar Required

|   |   |   |

|   |   |   V

|   |   |   Add Sugar

|   |   |   |

|   |   |   V

|   |   V

|   V

|   Dispense Hot Drink

|

V

ELSE (Cold Drink)

   |

   V

   Dispense Cold Drink

|

V

End

b. Given the tests:

Test 1: Cold drink

Test 2: Hot drink with milk and sugar

Statement Coverage achieved: The statement coverage achieved would be 10 out of 15 statements (66.7%).

Decision Coverage achieved: The decision coverage achieved would be 2 out of 3 decisions (66.7%).

c. Additional tests for 100% statement coverage:

Test 3: Hot drink without milk and sugar

Test 4: Hot drink with milk only

Test 5: Hot drink with sugar only

Test 6: Hot drink without milk and without sugar

Additional tests for 100% decision coverage:

Test 7: Cold drink

Test 8: Hot drink with milk and sugar

Test 9: Hot drink without milk and sugar

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Enterprise License  is a software license that allows 100 or more activations

The correct answer is "Enterprise License." An enterprise license is a type of software license that allows for a specified number of activations or installations, typically intended for large organizations or businesses. This license grants the organization the right to install and use the software on multiple devices or for multiple users, often without a specific limit on the number of activations. It provides flexibility and scalability for organizations that require a larger number of software installations to accommodate their needs. With an enterprise license, organizations can deploy the software across their infrastructure, ensuring widespread access and usage within the defined licensing terms.

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Answer:

When a system is produced using the evolutionary development model, features tend to be added without regard to an overriding design. With each modification, the software becomes increasingly disorganized. System maintenance hampered by these problems, as it is harder identifying the source of bugs in poorly designed systems. Also, keeping the documentation up to date over successive "evolution" is uncommon. Poor documentation also makes maintenance more difficult.

Explanation:

・It leads to implementing and then repairing way of building systems.

・Practically, this methodology may increase the complexity of the system as scope of the system may expand beyond original plans.

・Incomplete application may cause application not to be used as the full system was designed.

・Their results have incomplete or inadequate problem analysis.

Answer:

d

Explanation:

yea

Answer:

D

Explanation:

Answer:

Q ≅ 1.53 m³/s

Explanation:

From the given information:

The flow rate of the orifice is:

\(v = c_v \sqrt{2gh}\)

\(v = 0.90 \times \sqrt{2*9.81 * 10}\)

where;

\(Q = c_d \times \sqrt{2gh} \times A\); &

\(c_d = c_c \times c_v\)

∴

\(Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2\)

\(Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2\)

\(Q = 0.558 \times 14.00714104 \times 0.1963495408\)

Q ≅ 1.53 m³/s

Answer:

True

Explanation:

Mechanical Advantage Of A Wedge

It is the ratio of the output force to the input force. A wedge applies more force to the object (output force) than the user applies to the wedge (input force), so the mechanical advantage of a wedge is greater than 1

The reason an engineer may choose to use a prefabricated  building component is because: D. She wants the construction to move quickly.

A prefabricated  building component is also referred to as prefabs and it can be defined as a component that is fully manufactured to standard in a manufacturing plant or factory and then transported to a construction site, for partial assemblage and usage by an engineer. Some examples of prefabricated  building components are:

Generally, the two (2) main reasons why an engineer may choose to use a prefabricated  building component are:

I. To minimize negative environmental impacts by using standard materials from the manufacturing plant or factory.

II. To make the construction process move quickly.

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Answer:

The first five terms of the given geometric sequence are

8,40,200,1000,5000

Explanation:

:)

The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

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Answer:

Explained below

Explanation:

Perfect Elastic Plastic in steel design is simply a method whereby the structural members are selected using the criteria of the overall ultimate capacity of the system. However, when safety is considered, the applied loads are usually increased by factors of safety as prescribed in the relevant steel design codes. Therefore, this model of design is just based on the yield capacity of the steel.

Answer:

See the image for solution

The three methods used to find the real roots of the function are,

graphically, the quadratic formula, and by iteration.

The correct vales are;

(a) Graphically, the roots obtained are; x ≈ -1.629, and 5.629

(b) Using the quadratic formula, the real roots of the given function are; x ≈ -1.62589, x ≈ 5.62859

(c) Using three iterations, we have; the bracket is \(x_l\) = 5.625, and \(x_u\) = 6.25

Reasons:

The given function is presented as follows;

f(x) = -0.6·x² + 2.4·x + 5.5

(a) The graph of the function is plotted on MS Excel, with increments in the

x-values of 0.01, to obtain the approximation of the x-intercepts which are

the real roots as follows;

\(\begin{array}{|c|cc|}x&&f(x)\\-1.63&&-0.00614\\-1.62&&0.03736\\5.62&&0.03736 \\5.63&&-0.00614\end{array}\right]\)

Checking for the approximation of x-value of the intercept, we have;

\(x = -1.63 + \dfrac{0 - (-0.00614)}{0.0376 - (-0.00614)} \times (-1.62-(-1.63)) \approx -1.629\)

Therefore, based on the similarity of the values at the intercepts, the x-

values (real roots of the function) at the x-intercepts (y = 0) are;

x ≈ -1.629, and 5.629

(b) The real roots of the quadratic equation are found using the quadratic

formula as follows;

The quadratic formula for finding the roots of the quadratic equation

presented in the form f(x) = a·x² + b·x + c, is given as follows;

\(x = \mathbf{ \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}}\)

Comparison to the given function, f(x) = -0.6·x² + 2.4·x + 5.5, gives;

a = -0.6, b = 2.4, and c = 5.5

Therefore, we get;

\(x = \dfrac{-2.4\pm \sqrt{2.4^{2}-4\times (-0.6)\times 5.5}}{2\times (-0.6)} = \dfrac{-2.4\pm\sqrt{18.96} }{-1.2} = \dfrac{12 \pm\sqrt{474} }{6}\)

Which gives

The real roots are; x ≈ -1.62859, and x ≈ 5.62859

(c) The initial guesses are;

\(x_l\) = 5, and \(x_u\) = 10

The first iteration is therefore;

\(x_r = \dfrac{5 + 10}{2} = 7.5\)

\(Estimated \ error , \ \epsilon _a = \left|\dfrac{10- 5}{10 + 5} \right | \times 100\% = 33.33\%\)

\(True \ error, \ \epsilon _t = \left|\dfrac{5.62859 - 7.5}{5.62859} \right | \times 100\% = 33.25\%\)

f(5) × f(7.5) = 2.5 × (-10.25) = -25.625

The bracket is therefore; \(x_l\) = 5, and \(x_u\) = 7.5

Second iteration:

\(x_r = \dfrac{5 + 7.5}{2} = 6.25\)

\(Estimated \ error , \ \epsilon _a = \left|\dfrac{7.5- 5}{7.5+ 5} \right | \times 100\% = 20\%\)

\(True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 6.25}{5.62859} \right | \times 100\%} \approx 11.04\%\)

f(5) × f(6.25) = 2.5 × (-2.9375) = -7.34375

The bracket is therefore; \(x_l\) = 5, and \(x_u\) = 6.25

Third iteration

\(x_r = \dfrac{5 + 6.25}{2} = 5.625\)

\(Estimated \ error , \ \epsilon _a = \left|\dfrac{5.625- 5}{5.625+ 5} \right | \times 100\% = 5.88\%\)

\(True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 5.625}{5.62859} \right | \times 100\%} \approx 6.378 \times 10^{-2}\%\)

f(5) × f(5.625) = 2.5 × (0.015625) = 0.015625

Therefore, the bracket is \(x_l\) = 5.625, and \(x_u\) = 6.25

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1. Yes, there would still be a need for a rigorous study of ethics. Even if everyone agreed to take the ethical point of view, there would still be difficult ethical dilemmas and decisions to make.

Ethics is a set of moral principles or values that guide an individual or a group in determining what is right and wrong. It is a set of values that help dictate how people should behave in various situations. Ethics can be used to refer to a system of moral principles or values, or to the study of such principles or values.

2. I would choose the utilitarianism theory for my personal ethical decision making. Utilitarianism is a consequentialist theory, which means it assesses the consequences of a particular action in order to determine the ethicality of the action.

3. Businesses and governments often use utilitarian thinking to determine the proper course of action because it is an effective way to maximize the benefits to the greatest number of people. Utilitarianism can help businesses and governments make decisions that will benefit the most people in the most effective way.

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Answer:

the J and K inputs are tied to Vcc.

Explanation:

A J-K flip-flop can be defined as a gated set-reset (SR) flip-flop with an additional clock input circuit that is being used as a feedback to prevent any invalid or illegal output condition that may arise, when the set (S) and reset (R) inputs are equal to logic level 1.

Basically, in a set-reset (SR) flip-flop the set (S) should have a logic level output that is equal to 1 while the reset (R) has 0; these two levels as the name implies, are used to set and reset the device respectively.

A J-K flip-flop is being used as a divide-by-2 circuit when the J and K inputs are tied to Vcc i.e the ground voltage. Thus, the set and reset pins are not being used but are rather tied to Vcc in a divide-by-2 circuit.

The J and K inputs are tied with Vcc. Thus the option B is correct.

The J-K flip-flop can be said as the gated set-reset with the additional clock input circuits that are used as feedback to prevent any invalid or illegal output condition that may arise, when the set (S) and reset (R) inputs are equal to logic level 1.

The flip-flop is being used as a divide by 2 circuits when the inputs are tied to the Vcc by the ground voltage. Thus, the set and then reset the pins that are not used but are rather tied to Vcc.

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Answer:

Explanation:

From the information given;

The velocity of the wind blow V = 7 m/s

The diameter of the blades  (d) = 80 m

Percentage of the overall efficiency \(\eta_{overall} = 30\%\)

The density of air \(\rho = 1.25 kg/km^3\)

Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:

\(e_{mechanic} = \dfrac{mV^2}{2}\)

here;

m = \(\rho AV\)

= \(1.25 \times \dfrac{\pi}{4}(80)^2 \times 7\)

= 43982.29 kg/s

∴

\(W = e_{mechanic} = \dfrac{mV^2}{2}\)

\(= \dfrac{43982.29 \times 7^2}{2}\)

\(= 1077566.105 \ W\)

\(\mathbf{ =1077.566 \ kW}\)

The actual electric power is:

\(W_{electric} = \eta_{overall} \times W\)

\(W_{electric} = 0.3 \times 1077.566\)

\(\mathbf{W_{electric} =323.26 \ kW}\)

Answer:

Overflow and underflow are both errors resulting from a shortage of space. On the most basic level, they manifest in data types like integers and floating points. Unlike the physical world, the number stored in a computer exists in a discrete number of digits.

Explanation:

The reason for the `ConcurrentModificationException` error to occur in Java programming is due to the modification of the list that is in use. The solution to resolve the `ConcurrentModificationException` error on the BOLD part of the code is to use an Iterator on the ArrayList in Java programming.

The following is the solution to resolve the `ConcurrentModificationException` error on the BOLD part of the code:``` Iterator isRentedOutIterator = isRentedOut.iterator(); while(isRentedOutIterator.hasNext()){ String media = isRentedOutIterator.next(); customer.removeQueue(media); } ```

The aforementioned code will help to solve the `ConcurrentModificationException` error. It is because the `ConcurrentModificationException` occurs due to the modification of the list that is in use by the loop.

Using the `Iterator`, one can solve the `ConcurrentModificationException` error.To avoid the `ConcurrentModificationException` error, one must not modify the `ArrayList` while it is being iterated. So, using the `Iterator` can help to avoid the `ConcurrentModificationException` error.

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Fault location techniques are used in power systems for accurate pinpointing of the fault position.

This paper presents a comparative study between two fault location methods in distribution network with Distributed Generation (DG). Both methods are based on computing the impedance using fundamental voltage and current signals. The first method uses one-end information and the second uses both ends

Answer:

1. make any last minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Explanation:

Given that the role or functions of maintenance and operations crews in building construction are to ensure that the building is maintained to the required standard of use.

This involves making sure that all repairs in a building are done. The equipment is properly installed and solved any form of equipment that malfunctions.

Hence, in this case, the correct answer is:

1. make any last-minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Answer:

1. make any last minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Explanation:

When the inverter clock frequency becomes larger, the dynamic energy dissipated due to charging or discharging in a single clock cycle will increase.

In an inverter, if the clock frequency becomes larger, the dynamic energy dissipated due to charging or discharging in a single clock cycle will increase. This is because dynamic energy is directly proportional to the frequency.

Dynamic energy is given by the formula: E = 0.5 * C * V² * f, where E is the dynamic energy, C is the capacitance, V is the voltage, and f is the frequency. When the inverter clock frequency (f) becomes larger, the overall dynamic energy (E) increases according to the formula. The increase in frequency means that the inverter is switching between charging and discharging more rapidly in a given time period. As a result, more energy is consumed due to the higher rate of charging and discharging.

In conclusion, when the inverter clock frequency becomes larger, the dynamic energy dissipated due to charging or discharging in a single clock cycle will increase.

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To determine the correct measurement for the size of a penny using a ruler, we need to consider the scale or unit of measurement used on the ruler. Without knowing the specific scale or unit mentioned on the ruler, it is difficult to provide an exact measurement. However, I can provide a general explanation of how to measure the size of a penny using a ruler.

Most rulers typically use inches or centimeters as the unit of measurement. An inch ruler is divided into smaller increments, usually 1/16th or 1/32nd of an inch, while a centimeter ruler is divided into smaller increments, usually millimeters.

To measure the size of a penny accurately, place the ruler on a flat surface and position the penny next to it. Ensure that the edge of the penny lines up with one of the ruler's markings. Identify the nearest marking on the ruler that aligns with the opposite edge of the penny. This marking will give you the measurement of the penny's size.

For example, if you are using an inch ruler and the edge of the penny aligns with the 1-inch marking, the measurement would be 1 inch. If the edge aligns with the 3/4th inch marking, the measurement would be 3/4th of an inch.

Similarly, if you are using a centimeter ruler and the edge of the penny aligns with the 2-centimeter marking, the measurement would be 2 centimeters. If the edge aligns with the 2.5-centimeter marking, the measurement would be 2.5 centimeters.

Remember to read the ruler carefully and use the appropriate unit of measurement based on the ruler's scale to accurately determine the size of the penny.

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Answer:

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

Explanation:

The complete statement of this question is "Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P = 450 kN"

Each bolt is subjected to shear forces. In this case, safety factor is the ratio of the ultimate shear strength to maximum allowable shear stress. That is to say:

\(n = \frac{S_{uts}}{\tau_{max}}\)

Where:

\(n\) - Safety factor, dimensionless.

\(S_{uts}\) - Ultimate shear strength, measured in pascals.

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

The maximum allowable shear stress is consequently cleared and computed: (\(n = 4.2\), \(S_{uts} = 320\times 10^{6}\,Pa\))

\(\tau_{max} = \frac{S_{uts}}{n}\)

\(\tau_{max} = \frac{320\times 10^{6}\,Pa}{4.2}\)

\(\tau_{max} = 76.190\times 10^{6}\,Pa\)

Since each bolt has a circular cross section area and assuming the shear stress is not distributed uniformly, shear stress is calculated by:

\(\tau_{max} = \frac{4}{3} \cdot \frac{V}{A}\)

Where:

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

\(V\) - Shear force, measured in kilonewtons.

\(A\) - Cross section area, measured in square meters.

As connection consist on five bolts, shear force is equal to a fifth of the applied load. That is:

\(V = \frac{P}{5}\)

\(V = \frac{450\,kN}{5}\)

\(V = 90\,kN\)

The minimum allowable cross section area is cleared in the shearing stress equation:

\(A = \frac{4}{3}\cdot \frac{V}{\tau_{max}}\)

If \(V = 90\,kN\) and \(\tau_{max} = 76.190\times 10^{3}\,kPa\), the minimum allowable cross section area is:

\(A = \frac{4}{3} \cdot \frac{90\,kN}{76.190\times 10^{3}\,kPa}\)

\(A = 1.640\times 10^{-3}\,m^{2}\)

The minimum allowable cross section area can be determined in terms of minimum allowable bolt diameter by means of this expression:

\(A = \frac{\pi}{4}\cdot D^{2}\)

The diameter is now cleared and computed:

\(D = \sqrt{\frac{4}{\pi}\cdot A}\)

\(D =\sqrt{\frac{4}{\pi}\cdot (1.640\times 10^{-3}\,m^{2})\)

\(D = 0.0457\,m\)

\(D = 45.7\,mm\)

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

We have that the minimum allowable bolt diameter is mathematically given as

From the question we are told

Generally the equation for the stress   is mathematically given as

\(\mu= 320/4.2 \\\\\mu= 76.190 N/mm^2\)

Therefore

Force = Stress * area

Force = P/2

F= 425,000 N / 2 = 212,500 N

Hence area of each bolt is given as

212,500 = 76.190*( 5* area of each bolt)

area of each bolt = 557.815

Since

area of each bolt=\pi*d^2/4

\pi*d^2/4 = 557.815

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yes it will

Explanation:

Answer:

a). 5 cylinders

b). 3 cylinders

Explanation:

To develop a gasoline engine that produces

Power, P = 300 hp

               = 300 x 746 = 223710 watt

at speed, N = 600 rpm = 100 rps

and stroke volume \($V_s=0.5$\) L

                                   = \($0.5 \times 10^{-3}\ m^3$\)

a). A naturally aspirated engine

BMEP at peak power = 10 bar

                                    = \($10 \times 10^5\ N/m^2$\)

Suction volume, V = \($V_s \times N$\)

                           = \($0.5 \times 10^{-3} \times 100 = 0.05\ m^3/s$\)

Power produced in one engine cylinder , p = BMEP x V

                                                                        = \($10 \times 10^5 \times 0.05$\)

                                                                        = 50000 watts

No. of cylinders required, n = \($\frac{P}{p}$\)

                                              = \($\frac{223710}{50000}$\)    

                                             = 4.47

So number of cylinders ≈ 5 nos.

b). A turbo charged engine

   BMEP = 20 bar = \($20 \times 10^5\ N/m^2$\)

   and Volume V = \($0.05\ m^3 /s$\)

Power produced in one engine cylinder, p = BMEP x V

                                                                       = \($20\times 10^5 \times 0.05$\)

                                                                       = 100000 watts

Therefore, number of cylinders, n = \($\frac{P}{p}$\)

                                                        = \($\frac{223710}{100000}$\)

                                                        = 2.23

So number of cylinders ≈ 3 nos.

Answer:

The Mechanical Properties include Elasticity, Plasticity, Ductility, Malleability, Hardness, Toughness, Brittleness, Tenacity, Fatigue, Fatigue resistance, Impact Resistance property, Machineability, Strength, Strain Energy, Resilience, Proof Resilience, Modulus of Resilience, Creep, Rupture, and Modulus of Toughness.

The ER diagram for the Temporary Employment Corporation (TEC) based on the business rules given is given below: Attributes for Entities:

(One-to-Many)One candidate can have many job histories. (One-to-Many)One job history can belong to only one candidate. (One-to-One)One placement can belong to only one candidate. (One-to-One)One job opening can be placed by many placements. (One-to-Many)One candidate can have many placements.

In the given diagram below, all the relationships and primary keys are labeled correctly and the ER diagram is resolved for all M:N relationships and 1:N relationships. If you want to add more attributes to each entity, you can do it accordingly:

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Given values are as follows:
Mass of the crate, m = 200 kg
Coefficient of static friction, μs = 0.3
Formula used: The force of friction, f = μs N
Here, f = maximum force of friction
N = Normal force = mg

Let's determine the maximum force of friction first.N = mg = 200 kg × 9.8 m/s² = 1960 Nμs = 0.3f = μs N = 0.3 × 1960 N = 588 N. The maximum force that can be applied to the crate without it moving is 588 N. To determine whether we can move the crate, we need to apply a force greater than this.

If we want to move the crate, we will need to apply a force greater than 588 N. Therefore, we cannot move the crate.

Thus, we have determined that we cannot move the crate as we have to apply a force greater than 588 N and the maximum force that can be applied without moving the crate is 588 N.

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The amount of total current draw that will occur if the strip heat comes on while the compressor is operating is 53.778 A.

We have the following details

Pe = 10 Kw

compressor current = 34A

Power factor = 70%

The voltage applied = 240 V

frequency f = 60 Hz

P = ER² / R

= 240² / 10 x 10

= 57600 / 10000

= 5.76Ω

We have El = Lr = Et

El = Lr = 240

The true power P

10 x 10³ / 240

= 41.667 A

The total current is solved by

√41.667² + 34³

= √1736.138 + 1156

= √2892.138

= 53.778 A

Hence the amount of total current draw that will occur if the strip heat comes on while the compressor is operating is 53.778 A.

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