which number s below belong to the solution set of the inequality check all that apply 4 times less than 112 pls help me

Answer:

5. Rational

6. 4.27 Rational, 0.375 Rational,

0.232342345 Rational, √62 Not rational, 13/1 Rational

Step-by-step explanation:

A rational number is an integer, fraction, terminating decimal, or repeating decimal.

An irrational number  is a number that cannot be expressed as the ratio of two integers.

Hope this helps :)

Number of 5-letter passwords that start with or finish with H = 2 * 26^4 - 26^3. To determine the number of 5-letter passwords that either start with or finish with the letter H, we can use the principle of inclusion-exclusion.

1. Starting with H: In this case, the first letter is fixed as H, and the remaining 4 letters can be any of the 26 letters of the alphabet. Therefore, the number of passwords starting with H is 26^4.

2. Finishing with H: Similarly, in this case, the last letter is fixed as H, and the remaining 4 letters can again be any of the 26 letters of the alphabet. So, the number of passwords finishing with H is also 26^4.

Now, we need to consider the intersection of the two cases, i.e., passwords that both start with and finish with H. Since the first and last letters are fixed as H, we have 1 option for each of these positions. The remaining 3 letters can be any of the 26 letters of the alphabet, so there are 26^3 possibilities for these letters. Therefore, the number of passwords that both start with and finish with H is 1 * 1 * 26^3 = 26^3.

Using the inclusion-exclusion principle, we can find the total number of passwords that either start with or finish with H by summing the number of passwords in each case and subtracting the intersection:

Total = (Number starting with H) + (Number finishing with H) - (Number starting with H and finishing with H)

     = 26^4 + 26^4 - 26^3

Number of 5-letter passwords that start with or finish with H = 2 * 26^4 - 26^3.

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Answer:

The dilation factor of the width is 3/4

The dilation factor of the length is 10/13

The standard court and the modified court are not similar

Step-by-step explanation:

The given dimension of a tennis courts are given as follows;

The width of the standard tennis court = 36 ft.

The length of the standard tennis court = 78 ft.

The height of the  net of the standard tennis court = 3 ft.

The width of the modified tennis court = 27 ft.

The length of the modified tennis court = 60 ft.

The height of the  net of the standard tennis court = 3 ft.

The dilation factor of the width = (Modified court width)/(Standard court width)

∴ The dilation factor of the width = (27 ft.)/(36 ft.) = 3/4

Therefore, the width of the modified court = 3/4 × The width of the standard court

∴ The dilation factor of the length = (60 ft.)/(78 ft.) = 10/13

Therefore, the length of the modified court = 10/13 × The length of the standard court

The dilation factor for the width is different from the dilation factor for the length and the net of both courts are of equal dimension, therefore, based on similarity theorem, both courts are not similar.

Answer:

He's definitely on the right track on saving money for his retirement. As the years move along, he can continue to save money in his savings account.

Step-by-step explanation:

Answer:

dfadfadsadas

Step-by-step explanation:

Answer:

x = 45 ft

Step-by-step explanation:

\( x = \sqrt{ {36}^{2} + {27}^{2} } \\ = \sqrt{1296 + 729} \\ \sqrt{2025 } \\ = 45\)

Check the picture below.

so the surface area is really just the area of four triangles with a base of 6 and a height of 8, and a 6x6 square.

\(\stackrel{ \textit{\LARGE Areas} }{\stackrel{ square }{(6)(6)}~~ + ~~\stackrel{ \textit{four triangles} }{4\left[\cfrac{1}{2}(6)(8) \right]}}\implies 36+96\implies \text{\LARGE 132}~yd^2\)

Answer:

B

Step-by-step explanation:

The answer inequality of the given line will be -4<n<5.

A number line is an image of numbers plotted on a straight line, either horizontally or vertically. We can compare numbers and execute simple arithmetic operations on them easily by writing the numbers down on a number line. The starting point of a number line is often regarded as zero (0).

These numbers to the left of zero are all negative while the numbers just on right of zero are all positive. As a result, we can argue that on a number line, the value of numbers grows as we approach the right. The numbers on the right are therefore larger than the ones on the left, according to this statement.

The endpoints of the given line are -4 and +5.

So the value of inequality should lie between these two lines only.

The inequality can be written as n< 5 and n>-4

or -4<n<5

Hence the answer inequality of the given line will be -4<n<5.

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Answer:

1) 906

Step-by-step explanation:

It's in the ones value making it represent the value of 6

The net cash provided by operating activities is $266400.

To calculate the net cash provided by operating activities, we need to start with net income and adjust for non-cash items and changes in working capital. We don't have the net income given in this problem, so we need to calculate it by adjusting for the other items given in the problem. We start with the cash received from customers, which is $592000, and subtract the cash paid for wages, which is $88800, and the cash paid for inventory, which is $236800. This gives us cash provided by operating activities of $266400.

There are no non-cash items given in the problem, so we don't need to make any adjustments for those. Additionally, there are no changes in working capital given in the problem, so we don't need to make any adjustments for those either. Therefore, our final answer for the net cash provided by operating activities is $266400.

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2.25 km on the ground is represented by 9cm on the map.

What is the actual distance?

Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. The distance can refer to a physical length in physics or to an estimate based on other factors in common usage.

Here, we have

Given: The scale on the map is 1:25000

We have to find the actual distance of 9 cm on the map.

First, we have to find the actual distance of 1 cm on the map:

1cm = 25000cm

1cm = 250m

1cm = 0.25km

Now Find the actual distance of 9 cm on the map:

1cm = 0.25km

9cm = 9(0.25) = 2.25km

Hence, 2.25 km on the ground is represented by 9cm on the map.

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Answer:

NLO or OLN

Step-by-step explanation:

I'm not exactly sure but this is my guess

Answer:

The shorter piece would beStep-by-step explanation:

a) The null hypothesis (H0) would be that the variance of the nicotine content in cigarettes is equal to 0.723 milligram squared.

The alternative hypothesis (Ha) would be that the variance is not equal to 0.723 milligram squared.

b) There is enough evidence to accept the statistician's claim that the variance of the nicotine content in cigarettes is 0.723.

a) The null hypothesis (H0) would be that the variance of the nicotine content in cigarettes is equal to 0.723 milligram squared.

The alternative hypothesis (Ha) would be that the variance is not equal to 0.723 milligram squared.

b) In this case, we can use the chi-square distribution to test the hypothesis since we are dealing with the variance and the sample size is relatively small (n = 24).

c) For the critical value approach, we need to calculate the chi-square test statistic and compare it to the critical value from the chi-square distribution at a significance level of 0.01.

The test statistic (chi-square) can be calculated using the formula:

chi-square = (n - 1) sample variance / population variance

In this case:

n = 24 (sample size)

sample variance  = 1.3225

population variance = 0.723

So, chi-square = (24 - 1) 1.3225 / 0.723 = 42.0712

degrees of freedom (df) equal to (n - 1) = 23.

So, the critical value for a significance level of 0.01 and 23 degrees of freedom is 41.6383.

Since the calculated chi-square value (42.0712) is greater than the critical value (41.6383), we can reject the null hypothesis.

Therefore, at a 0.01 level of significance, there is enough evidence to accept the statistician's claim that the variance of the nicotine content in cigarettes is 0.723.

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Answer: A 550g box for $10.89

Step-by-step explanation:

Represent each option as grams per dollar

225g / $5.77 = 38.99g / $1.00

550g / $10.89 = 50.51g / $1.00

725g / $16.89 = 42.92g / $1.00

The second option gives the most grams per dollar

Bonnie bought approximately 4 bags of chips and 14 cans of pop for a total cost of $17.50.

Let's assume the number of bags of chips Bonnie bought is x.

According to the given information, Bonnie bought ten more cans of pop than bags of chips. Therefore, the number of cans of pop Bonnie bought is x + 10.

We are also given that Bonnie spent $17.50 on these purchases.

Now, let's calculate the total cost of the bags of chips and cans of pop:

Cost of x bags of chips = x dollars

Cost of (x + 10) cans of pop = (x + 10) dollars

The total cost is the sum of the cost of bags of chips and cans of pop:

Total cost = x + (x + 10) = 2x + 10

According to the given information, the total cost is $17.50:

2x + 10 = 17.50

Subtracting 10 from both sides of the equation:

2x = 17.50 - 10

2x = 7.50

Dividing both sides by 2:

x = 7.50 / 2

x = 3.75

Therefore, Bonnie bought 3.75 bags of chips (which we'll assume is 4 bags since we can't have a fraction of a bag) and (3.75 + 10) = 13.75 (which we'll assume is 14 cans since we can't have a fraction of a can) cans of pop.

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Answer:

1: 6:10,9:15,12:20 2: 4:8, 6:12, and 8:16

Step-by-step explanation: To make an equivalent ratio you multiply each number by the same number (ex: 2:4 2*2= 4 and 4*2=8 so 2:8)

Answer:

Step-by-step explanation:

               Salt-Water

Class A         3/5=y/x      y=3/5x

Class B         2/4=y/x     1/2=y/x      y=1/2 x

Answer:

Step-by-step explanation:

1.

by using Pythagoras law

h²=p²+b²

17²=6²+x²

x=√{17²-6²)=√253=15.9=16approx

2.

by using Pythagoras law

h²=p²+b²

x²=9²+15²

x=√306=17.49=17.5approx

Answer:

1 is 16.                    2 is 17.49 or 17.5 or 17          depends on how you're rounding.

Step-by-step explanation:

a. To derive the bias of p(hat)2, we need to calculate the expected value (mean) of p(hat)2 and subtract the true value of p.

Bias(p(hat)2) = E(p(hat)2) - p

Now, p(hat)2 = (Y+1)/(n+2), and Y has a binomial distribution with parameters n and p. Therefore, the expected value of Y is E(Y) = np.

E(p(hat)2) = E((Y+1)/(n+2))

          = (E(Y) + 1)/(n+2)

          = (np + 1)/(n+2)

The bias of p(hat)2 is given by:

Bias(p(hat)2) = (np + 1)/(n+2) - p

b. To derive the mean squared error (MSE) for both p(hat)1 and p(hat)2, we need to calculate the variance and bias components.

For p(hat)1:

Bias(p(hat)1) = E(p(hat)1) - p = E(Y/n) - p = (1/n)E(Y) - p = (1/n)(np) - p = p - p = 0

Variance(p(hat)1) = Var(Y/n) = (1/n^2)Var(Y) = (1/n^2)(np(1-p))

MSE(p(hat)1) = Variance(p(hat)1) + [Bias(p(hat)1)]^2 = (1/n^2)(np(1-p))

For p(hat)2:

Bias(p(hat)2) = (np + 1)/(n+2) - p (as derived in part a)

Variance(p(hat)2) = Var((Y+1)/(n+2)) = Var(Y/(n+2)) = (1/(n+2)^2)Var(Y) = (1/(n+2)^2)(np(1-p))

MSE(p(hat)2) = Variance(p(hat)2) + [Bias(p(hat)2)]^2 = (1/(n+2)^2)(np(1-p)) + [(np + 1)/(n+2) - p]^2

c. To find the values of p where MSE(p(hat)1) < MSE(p(hat)2), we can compare the expressions for the mean squared errors derived in part b.

(1/n^2)(np(1-p)) < (1/(n+2)^2)(np(1-p)) + [(np + 1)/(n+2) - p]^2

Simplifying this inequality requires a specific value for n. Without the value of n, we cannot determine the exact values of p where MSE(p(hat)1) < MSE(p(hat)2). However, we can observe that the inequality will hold true for certain values of p, n, and the difference between n and n+2.

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In the given scenario, we have two estimators for the parameter p of a binomial distribution: p(hat)1 = Y/n and p(hat)2 = (Y+1)/(n+2). The objective is to analyze the bias and mean squared error (MSE) of these estimators.

The bias of p(hat)2 is derived as (n+1)/(n(n+2)), while the MSE of p(hat)1 is p(1-p)/n, and the MSE of p(hat)2 is (n+1)(n+3)p(1-p)/(n+2)^2. For values of p where MSE(p(hat)1) is less than MSE(p(hat)2), we need to compare the expressions of these MSEs.

(a) To derive the bias of p(hat)2, we compute the expected value of p(hat)2 and subtract the true value of p. Taking the expectation:

E(p(hat)2) = E[(Y+1)/(n+2)]

          = (1/(n+2)) * E(Y+1)

          = (1/(n+2)) * (E(Y) + 1)

          = (1/(n+2)) * (np + 1)

          = (np + 1)/(n+2)

Subtracting p, the true value of p, we find the bias:

Bias(p(hat)2) = E(p(hat)2) - p

             = (np + 1)/(n+2) - p

             = (np + 1 - p(n+2))/(n+2)

             = (n+1)/(n(n+2))

(b) To derive the MSE of p(hat)1, we use the definition of MSE:

MSE(p(hat)1) = Var(p(hat)1) + [Bias(p(hat)1)]^2

Given that p(hat)1 = Y/n, its variance is:

Var(p(hat)1) = Var(Y/n)

            = (1/n^2) * Var(Y)

            = (1/n^2) * np(1-p)

            = p(1-p)/n

Substituting the bias derived earlier:

MSE(p(hat)1) = p(1-p)/n + [0]^2

            = p(1-p)/n

To derive the MSE of p(hat)2, we follow the same process. The variance of p(hat)2 is:

Var(p(hat)2) = Var((Y+1)/(n+2))

            = (1/(n+2)^2) * Var(Y)

            = (1/(n+2)^2) * np(1-p)

            = (np(1-p))/(n+2)^2

Adding the squared bias:

MSE(p(hat)2) = (np(1-p))/(n+2)^2 + [(n+1)/(n(n+2))]^2

            = (n+1)(n+3)p(1-p)/(n+2)^2

(c) To compare the MSEs, we need to determine when MSE(p(hat)1) < MSE(p(hat)2). Comparing the expressions:

p(1-p)/n < (n+1)(n+3)p(1-p)/(n+2)^2

Simplifying:

(n+2)^2 < n(n+1)(n+3)

Expanding:

n^2 + 4n + 4 < n^3 + 4n^2 + 3n^2

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The probability of not drawing a blue marble in the first trial is given by the ratio of the number of yellow marbles to the total number of marbles: 8/10. After removing one yellow marble, the probability of not drawing a blue marble in the second trial becomes 7/9. Similarly, for the third trial, the probability is 6/8, and for the fourth trial, it is 5/7. To find the probability of not drawing a blue marble in all four trials, we multiply these individual probabilities together: (8/10) * (7/9) * (6/8) * (5/7) = 0.2.

To calculate the probability of not drawing a blue marble in the first four trials, we use the concept of conditional probability. We assume that each marble is drawn without replacement, meaning that once a marble is selected, it is not put back into the pocket. Since the marbles are drawn randomly, the probability of choosing a specific marble on any given trial depends on the composition of the remaining marbles. In this case, we multiply the probabilities of each trial together because we want to find the probability of multiple independent events occurring consecutively.

2. The probability of having exactly one blue marble within the first four trials can be calculated using a combination of probabilities. There are four possible positions for the blue marble within the four trials: first trial, second trial, third trial, or fourth trial. We can calculate the probability of having the blue marble in each of these positions and sum them up.

The probability of the blue marble being in the first trial is (2/10) * (8/9) * (7/8) * (6/7) = 0.1333.

The probability of the blue marble being in the second trial is (8/10) * (2/9) * (7/8) * (6/7) = 0.1333.

The probability of the blue marble being in the third trial is (8/10) * (7/9) * (2/8) * (6/7) = 0.1333.

The probability of the blue marble being in the fourth trial is (8/10) * (7/9) * (6/8) * (2/7) = 0.1333.

Adding these probabilities together gives a total probability of 0.1333 + 0.1333 + 0.1333 + 0.1333 = 0.5333.

We use the concept of conditional probability and calculate the individual probabilities for each position where the blue marble can be found. In each calculation, we multiply the probability of selecting a blue marble in the given position with the probabilities of selecting yellow marbles in the other positions. Then, we add up these individual probabilities to find the overall probability of having exactly one blue marble within the first four trials.

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Answer:

x = 96 degrees

Step-by-step explanation:

49 + 35 + x = 180

84 + x = 180

x = 180 - 84

x = 96 degrees

Answer:

a. To find the margin of error and interval estimate for the number of eligible people under 20 years old who had a driver's license in 1995, we can use the formula for a confidence interval for a proportion:

margin of error = zsqrt(p(1-p)/n)

where z is the z-score corresponding to the desired level of confidence (95% confidence corresponds to a z-score of 1.96), p is the sample proportion (0.639), and n is the sample size (1200).

Plugging in the values, we get:

margin of error = 1.96sqrt(0.639(1-0.639)/1200) = 0.0261 (rounded to four decimal places)

To find the interval estimate, we can use the formula:

interval estimate = p ± margin of error

Plugging in the values, we get:

interval estimate = 0.639 ± 0.0261 = (0.6129, 0.6651) (rounded to four decimal places)

b. To find the margin of error and interval estimate for the number of eligible people under 20 years old who had a driver's license in 2016, we can use the same formulas with p = 0.417 (the sample proportion for 2016) and n = 1200:

margin of error = 1.96sqrt(0.417(1-0.417)/1200) = 0.0294 (rounded to four decimal places)

interval estimate = 0.417 ± 0.0294 = (0.3876, 0.4464) (rounded to four decimal places)

c. The margin of error is not the same in parts (a) and (b) because the sample proportion for 2016 (0.417) is smaller than the sample proportion for 1995 (0.639). As a result, the standard error (which is the square root of p*(1-p)/n) is larger for the 2016 sample than for the 1995 sample, which leads to a larger margin of error for the 2016 estimate.

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The given function f(x) = 16^x is an exponential function.

An exponential function is a mathematical function in which an independent variable appears in the exponent. In this case, the base of the function is 16, and the variable x is the exponent.

In the given function f(x) = 16^x, the variable x represents the exponent to which 16 is raised. As x increases, the function value grows rapidly, indicating exponential growth. The base of 16 signifies that the function is being multiplied by 16 for each unit increase in the exponent.

In contrast, a linear function has a constant rate of change, and a quadratic function has a squared term. The given function does not involve a linear relationship or a squared term, which confirms that it is not a linear or quadratic function.

Therefore, based on the given form f(x) = 16^x and the exponential growth nature of the function, we can classify it as an exponential function.

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Answer:

58

Step-by-step explanation:

x= points in 2nd game

x+8= points in 1st game

42= points in third game

x+x+8+42>150

2x+50>150

2x>100

Therefore x must be greater than 50.

50+8=58, which is the least amount of points in the second game.

Answer:

in which class's u are in

Answer:

-6>12

Step-by-step explanation:

i am pretty sure you can handle the 1,2,

about a and b

-3a>12  a=2

-3(2)>12

-6>12

negative can't be compared to positive numbers

i would agree with David because, i don't think we can have more solutions.

also if this advice was wrong, i am sorry, i don't remembered this stuff so well, so i am sorry.

The theorem that proves that the triangles are congruent is the Side-Side-Side (SSS) Congruence Theorem.

The Side-Side-Side (SSS) Congruence Theorem states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent. This theorem is useful for proving that two triangles are congruent without having to use angles. The SSS Congruence Theorem is a useful tool for solving geometry problems involving triangles. It can be used to find the unknown side length of a triangle given the lengths of the other two sides, or in more complicated proofs involving multiple triangles. This theorem is also helpful in determining the area of a triangle, as the area is proportional to the product of the lengths of the sides.

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